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  • how to prevent white spaces in a regular expression regex validation

    - by Rees
    i am completely new to regular expressions and am trying to create a regular expression in flex for a validation. using a regular expression, i am going to validate that the user input does NOT contain any white-space and consists of only characters and digits... starting with digit. so far i have: expression="[A-Za-z][A-Za-z0-9]*" this correctly checks for user input to start with a character followed by a possible digit, but this does not check if there is white space...(in my tests if user input has a space this input will pass through validation - this is not desired) can someone tell me how i can modify this expression to ensure that user input with whitespace is flagged as invalid?

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  • Regex: Matching a space-joined list of words, excluding last whitespace

    - by Jesper
    How would I match a space separated list of words followed by whitespace and some optional numbers? I have this: >>> import re >>> m = re.match('(?P<words>(\w+\s+)+)(?P<num>\d+)?\r\n', 'Foo Bar 12345\r\n') >>> m.groupdict() {'num': '12345', 'words': 'Foo Bar '} I'd like the words group to not include the last whitespace(s) but I can't figure this one out. I could do a .strip() on the result but that's not as much fun :) Some strings to test and wanted result: 'Foo & Bar 555\r\n' => {'num': '555', 'words': 'Foo & Bar'} 'Hello World\r\n' => {'num': None, 'words': 'Hello World'} 'Spam 99\r\n' => {'num': 99, 'words': 'Spam'} 'Number 1 666\r\n' => {'num': 666, 'words': 'Number 1'}

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  • Ignoring Whitespace with Regex(perl)

    - by Zerobu
    Hello, I am using Perl Regular expressions. How would i go about ignoring white space and still perform a test to see if a string match. For example. $var = " hello "; #I want var to igonore whitespace and still match if($var =~ m/hello/) { }

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  • regex php: find everything in div

    - by Fifth-Edition
    I'm trying to find eveything inside a div using regexp. I'm aware that there probably is a smarter way to do this - but I've chosen regexp. so currently my regexp pattern looks like this: $gallery_pattern = '/([\s\S]*)<\/div/'; And it does the trick - somewhat. the problem is if i have two divs after each other - like this. <div class="gallery">text to extract here</div> <div class="gallery">text to extract from here as well</div> I want to extract the information from both divs, but my problem, when testing, is that im not getting the text in between as a result but instead: "text to extract here text to extract from here as well" So . to sum up. It skips the first end of the div. and continues on to the next. The text inside the div can contain "<", "/" and linebreaks. just so you know! Does anyone have a simple solution to this problem? Im still a regexp novice.

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  • jQuery: select all inputs with unique id (Regex/Wildcard Selectors)

    - by d3020
    I have some textboxes on a webform that have ids like this: txtFinalDeadline_1 txtFinalDeadline_2 txtFinalDeadline_3 txtFinalDeadline_4 In my jQuery how do I find all of those in order to assign a value to them. Before I had the underscore and they were all named txtFinalDeadline I could do this and it worked. $(this).find("#txtFinalDeadline").val(formatDate); However, that was when they were all named the same thing. Now I have the _x after the name and I'm not sure how to go about assigning that same value as before to them. Thanks.

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  • initial caps in actionScript using Regex

    - by Deyon
    I'm trying to do initial caps in actionScript with no loops but now i'm stuck. I wanted to select the first letter or every word then apply uppercase on that letter. Well I got the selection part right, but at a dead end right now, any ideas? I was trying to do this with out loops and cutting up strings. //replaces with x cant figure out how to replace with the found result as uppercase public function initialcaps():void { var pattern:RegExp=/\b[a-z]/g; var myString:String="yes that is my dog dancing on the stage"; var nuString:String=myString.replace(pattern,"x"); trace(nuString); }

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  • jQuery Validate plugin - password check - minimum requirements - Regex

    - by QviXx
    I've got a little problem with my password-checker. There's got a registration form with some fields. I use jQuery Validate plugin to validate user-inputs. It all works except the password-validation: The password should meet some minimum requirements: minimum length: 8 - I just use 'minlength: 8' at least one lower-case character at least one digit Allowed Characters: A-Z a-z 0-9 @ * _ - . ! At the moment I use this code to validate the password: $.validator.addMethod("pwcheck", function(value, element) { return /^[A-Za-z0-9\d=!\-@._*]+$/.test(value); }); This Code works for the allowed characters but not for minimum requirements. I know that you can use for example (?=.*[a-z]) for a lower-case-requirement. But I just don't get it to work. If I add (?=.*[a-z]) the whole code doesn't work anymore. I need to know how to properly add the code to the existing one. Thank you for your answers! This is the complete code <script> $(function() { $("#regform").validate({ rules: { forename: { required: true }, surname: { required: true }, username: { required: true }, password: { required: true, pwcheck: true, minlength: 8 }, password2: { required: true, equalTo: "#password" }, mail1: { required: true, email: true }, mail2: { required: true, equalTo: "#mail1" } }, messages: { forename: { required: "Vornamen angeben" }, surname: { required: "Nachnamen angeben" }, username: { required: "Usernamen angeben" }, password: { required: "Passwort angeben", pwcheck: "Das Passwort entspricht nicht den Kriterien!", minlength: "Das Passwort entspricht nicht den Kriterien!" }, password2: { required: "Passwort wiederholen", equalTo: "Die Passwörter stimmen nicht überein" }, mail1: { required: "Mail-Adresse angeben", email: "ungültiges Mail-Format" }, mail2: { required: "Mail-Adresse wiederholen", equalTo: "Die Mail-Adressen stimmen nicht überein" } } }); $.validator.addMethod("pwcheck", function(value, element) { return /^[A-Za-z0-9\d=!\-@._*]+$/.test(value); }); }); </script>

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  • String format or REGEX.

    - by ThePower
    I need an simple way to check whether a string that is sent to my function is of the form: (x + n)(x + m) //the +'s can be minus' //n and m represent a double //x represents the char 'x' Is there a simple string format that I can use to check that this is the form. As opposed to checking each character singularly. The whitespace will be removed to save any confusion. Regards Lloyd

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  • Java String.replaceAll regex

    - by atomsfat
    I want to replace the first context of web/style/clients.html with the java String.replaceFirst method so I can get: ${pageContext.request.contextPath}/style/clients.html I tried String test = "web/style/clients.html".replaceFirst("^.*?/", "hello/"); And this give me: hello/style/clients.html but when I do String test = "web/style/clients.html".replaceFirst("^.*?/", "${pageContext.request.contextPath}/"); gives me java.lang.IllegalArgumentException: Illegal group reference

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  • Need Flex Regex Validation Expression for password that allows for only alphanumeric values and requ

    - by BlueDude
    Hi I'm trying to setup a RegexpValidator that only accepts a string of alphanumeric characters between 6-30 characters long and requires one number. I'm new to Regular Expressions and everything I've tried seems to keep returning an invalid ValidationRsultEvent. Here's a chunk of code: <mx:RegExpValidator id="regexValidator" source="{passwordInput}" property="text" triggerEvent="" valid="onPasswordValidate(event)" invalid="onPasswordValidate(event)" /> private function validateRegister():void { regexValidator.expression = "^(?=.*(\d|\W)).{6,30}$"; regexValidator.validate(); }

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  • StackOverflowError occured as using java.util.regex.Matcher

    - by Captain Kidd
    Hi guys I try to catch text by Regular Expression. I list codes as follows. Pattern p=Pattern.compile("<@a>(?:.|\\s)+?</@a>"); Matcher m = p.matcher(fileContents.toString()); while(m.find()) { //Error will be thrown at this point System.out.println(m.group()); } If the length of text I want to catch is too long, system will throw me a StackOverflowError. Otherwise, the codes work well. Please help me how to solve this problem.

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  • Regex - Modifying strings except in specified enclosures - PHP

    - by Kovo
    I have found similar answers to my current needs on SO, however I am still trying to grasp modifying strings based on a rule, except in certain enclosures within those strings. Example of what Im trying to accomplish now: preg_replace("/\s*,\s*/", ",", $text) I found the above in many places. It will remove spaces before and after all commas in a string. That works great. However, if I want to exclude modifying commas found within " ", I am not sure how that rule has to be modified. Any help? Thanks! EDIT: I want to clarify my question: I would like all whitespace before and after the commas in the following sentence removed, except commas found in double or single quotes: a, b , c "d, e f g , " , h i j ,k lm,nop Expected result: a,b,c "d, e f g , ",h i j,k lm,nop

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  • What is proper RegEx expession for SWIFT codes?

    - by abatishchev
    I have to filter user input to on my web ASP.NET page: <asp:TextBox runat="server" ID="recipientBankIDTextBox" MaxLength="11" /> <asp:RegularExpressionValidator runat="server" ValidationExpression="?" ControlToValidate="recipientBankIDTextBox" ErrorMessage="*" /> As far is I know SWIFT code must contain 5 or 6 letters and other symbols up to total length 11 are alphanumeric. How to implement such rule properly? TIO

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  • Need to add underscore to my regex

    - by TaMeR
    I suck at regular expression and just can't seem to figure this out. '/^[A-Za-z0-9](?:.[A-Za-z0-9]+)*$/' As it's right now it allows dots anytime after the first char and I like to add _ so that it allows both. Thanks

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  • Ruby RegEx not matching valid expression

    - by Matthew Carriere
    I have the following expression: ^\w(\s(+|-|\/|*)\s\w)*$ This simply looks to match a mathematical expression, where a user is prompted for terms separated by basic operators (ex: price + tax) The user may enter more than just 2 terms and one operator (ex: price + tax + moretax) I tested this expression in Rubular http://rubular.com/ With the terms: a + a (MATCH) a + a + a (MATCH) a + a + a + a a a + a a Everything works, but when I use it in Ruby it does not work! expression =~ /^\w(\s(+|-|\/|*)\s\w)*$/ I started picking the expression apart and noticed that if I remove the start of line caret it finds matches but isn't correct. a + a (MATCH) a a (MATCH) <-- this is not correct Why is this expression not working in Ruby code? (I am using Ruby 1.8.7 p174)

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  • What is proper RegEx expression for SWIFT codes?

    - by abatishchev
    I have to filter user input to on my web ASP.NET page: <asp:TextBox runat="server" ID="recipientBankIDTextBox" MaxLength="11" /> <asp:RegularExpressionValidator runat="server" ValidationExpression="?" ControlToValidate="recipientBankIDTextBox" ErrorMessage="*" /> As far is I know SWIFT code must contain 5 or 6 letters and other symbols up to total length 11 are alphanumeric. How to implement such rule properly? TIO

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  • Javascript how many characters replaced in a regex?

    - by macca1
    I am sanitizing an input field and manually getting and setting the caret position in the process. With some abstraction, here's the basic idea: <input type="text" onkeyup"check(this)"> And javascript... function check(element) { var charPosition = getCaretPosition(element); $(element).val( sanitize( $(element).val() ) ); setCaretPosition(element, charPosition); } function sanitize(s) { return s.replace(/[^a-zA-Z0-9\s]/g, ''); } This is working fine except when a character does actually get sanitized, my caret position is off by one. Basically I'd like a way to see if the sanitize function has actually replaced a character (and at what index) so then I can adjust the charPosition if necessary. Any ideas?

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  • bash: assign grep regex results to array

    - by Ryan
    Hello everyone, I am trying to assign a regular expression result to an array inside of a bash script but I am unsure whether that's possible, or if I'm doing it entirely wrong. The below is what I want to happen, however I know my syntax is incorrect: indexes[4]=$(echo b5f1e7bfc2439c621353d1ce0629fb8b | grep -o '[a-f0-9]\{8\}') such that: index[1]=b5f1e7bf index[2]=c2439c62 index[3]=1353d1ce index[4]=0629fb8b Any links, or advice, would be wonderful :)

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  • Java Regex for matching quoted string with escaped quotes

    - by kayahr
    I know there are already many questions like mine but I found no answer which works in Java. So I write a new question. I have text files with content like this: key1 = "This is a \"test\" text with escapes using '\\' characters"; key2 = 'It must work with \'single\' quotes and "double" quotes'; I need a regular expression which matches the values in the double-quotes (or single-quotes). This regular expression must support the escaped quotes and escaped backslashes. The regular expression must work with Java standard Pattern/Matcher classes.

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  • Regex optional match in python fails

    - by AaronG
    tickettypepat = (r'MIS Notes:.**(//p//)?.**') retype = re.search(tickettypepat,line) if retype: print retype.group(0) print retype.group(1) Given the input. MIS Notes: //p// Can anyone tell me why group(0) is MIS Notes: //p// and group(1) is returning as None?

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