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• Detect if class has overloaded function fails on Comeau compiler

  - by Frank

  Hi Everyone, I'm trying to use SFINAE to detect if a class has an overloaded member function that takes a certain type. The code I have seems to work correctly in Visual Studio and GCC, but does not compile using the Comeau online compiler. Here is the code I'm using: #include <stdio.h> //Comeau doesnt' have boost, so define our own enable_if_c template<bool value> struct enable_if_c { typedef void type; }; template<> struct enable_if_c< false > {}; //Class that has the overloaded member function class TestClass { public: void Func(float value) { printf( "%f\n", value ); } void Func(int value) { printf( "%i\n", value ); } }; //Struct to detect if TestClass has an overloaded member function for type T template<typename T> struct HasFunc { template<typename U, void (TestClass::*)( U )> struct SFINAE {}; template<typename U> static char Test(SFINAE<U, &TestClass::Func>*); template<typename U> static int Test(...); static const bool Has = sizeof(Test<T>(0)) == sizeof(char); }; //Use enable_if_c to only allow the function call if TestClass has a valid overload for T template<typename T> typename enable_if_c<HasFunc<T>::Has>::type CallFunc(TestClass &test, T value) { test.Func( value ); } int main() { float value1 = 0.0f; int value2 = 0; TestClass testClass; CallFunc( testClass, value1 ); //Should call TestClass::Func( float ) CallFunc( testClass, value2 ); //Should call TestClass::Func( int ) } The error message is: no instance of function template "CallFunc" matches the argument list. It seems that HasFunc::Has is false for int and float when it should be true. Is this a bug in the Comeau compiler? Am I doing something that's not standard? And if so, what do I need to do to fix it?

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• Indexing with pointer C/C++

  - by Leavenotrace

  Hey I'm trying to write a program to carry out newtons method and find the roots of the equation exp(-x)-(x^2)+3. It works in so far as finding the root, but I also want it to print out the root after each iteration but I can't get it to work, Could anyone point out my mistake I think its something to do with my indexing? Thanks a million :) #include <stdio.h> #include <math.h> #include <malloc.h> //Define Functions: double evalf(double x) { double answer=exp(-x)-(x*x)+3; return(answer); } double evalfprime(double x) { double answer=-exp(-x)-2*x; return(answer); } double *newton(double initialrt,double accuracy,double *data) { double root[102]; data=root; int maxit = 0; root[0] = initialrt; for (int i=1;i<102;i++) { *(data+i)=*(data+i-1)-evalf(*(data+i-1))/evalfprime(*(data+i-1)); if(fabs(*(data+i)-*(data+i-1))<accuracy) { maxit=i; break; } maxit=i; } if((maxit+1==102)&&(fabs(*(data+maxit)-*(data+maxit-1))>accuracy)) { printf("\nMax iteration reached, method terminated"); } else { printf("\nMethod successful"); printf("\nNumber of iterations: %d\nRoot Estimate: %lf\n",maxit+1,*(data+maxit)); } return(data); } int main() { double root,accuracy; double *data=(double*)malloc(sizeof(double)*102); printf("NEWTONS METHOD PROGRAMME:\nEquation: f(x)=exp(-x)-x^2+3=0\nMax No iterations=100\n\nEnter initial root estimate\n>> "); scanf("%lf",&root); _flushall(); printf("\nEnter accuracy required:\n>>"); scanf("%lf",&accuracy); *data= *newton(root,accuracy,data); printf("Iteration Root Error\n "); printf("%d %lf \n", 0,*(data)); for(int i=1;i<102;i++) { printf("%d %5.5lf %5.5lf\n", i,*(data+i),*(data+i)-*(data+i-1)); if(*(data+i*sizeof(double))-*(data+i*sizeof(double)-1)==0) { break; } } getchar(); getchar(); free(data); return(0); }

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• Why Swift is 100 times slower than C in this image processing test?

  - by xiaobai

  Like many other developers I have been very excited at the new Swift language from Apple. Apple has boasted its speed is faster than Objective C and can be used to write operating system. And from what I learned so far, it's a very type-safe language and able to have precisely control over the exact data type (like integer length). So it does look like having good potential handling performance critical tasks, like image processing, right? That's what I thought before I carried out a quick test. The result really surprised me. Here is a much simplified image alpha blending code snippet in C: test.c: #include <stdio.h> #include <stdint.h> #include <string.h> uint8_t pixels[640*480]; uint8_t alpha[640*480]; uint8_t blended[640*480]; void blend(uint8_t* px, uint8_t* al, uint8_t* result, int size) { for(int i=0; i<size; i++) { result[i] = (uint8_t)(((uint16_t)px[i]) *al[i] /255); } } int main(void) { memset(pixels, 128, 640*480); memset(alpha, 128, 640*480); memset(blended, 255, 640*480); // Test 10 frames for(int i=0; i<10; i++) { blend(pixels, alpha, blended, 640*480); } return 0; } I compiled it on my Macbook Air 2011 with the following command: gcc -O3 test.c -o test The 10 frame processing time is about 0.01s. In other words, it takes the C code 1ms to process one frame: $ time ./test real 0m0.010s user 0m0.006s sys 0m0.003s Then I have a Swift version of the same code: test.swift: let pixels = UInt8[](count: 640*480, repeatedValue: 128) let alpha = UInt8[](count: 640*480, repeatedValue: 128) let blended = UInt8[](count: 640*480, repeatedValue: 255) func blend(px: UInt8[], al: UInt8[], result: UInt8[], size: Int) { for(var i=0; i<size; i++) { var b = (UInt16)(px[i]) * (UInt16)(al[i]) result[i] = (UInt8)(b/255) } } for i in 0..10 { blend(pixels, alpha, blended, 640*480) } The build command line is: xcrun swift -O3 test.swift -o test Here I use the same O3 level optimization flag to make the comparison hopefully fair. However, the resulting speed is 100 time slower: $ time ./test real 0m1.172s user 0m1.146s sys 0m0.006s In other words, it takes Swift ~120ms to processing one frame which takes C just 1 ms. I also verified the memory initialization time in both test code are very small compared to the blend processing function time. What happened?

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• can't connect Java client to C server.

  - by nexes

  I have a very simple server written in C and an equally simple client written in Java. When I run them both on the same computer everything works, but when I try to run the server on computer A and the client on computer B, I get the error IOException connection refused from the java client. I can't seem to find out whats happening, any thoughts? I've even turned off the firewalls but the problem still persists. server. #include <stdio.h> #include <unistd.h> #include <string.h> #include <sys/types.h> #include <sys/socket.h> #include <netinet/in.h> #define PORT 3557 #define BUF 256 int main(int argc, char *argv[]) { struct sockaddr_in host, remote; int host_fd, remote_fd; int size = sizeof(struct sockaddr);; char data[BUF]; host.sin_family = AF_INET; host.sin_addr.s_addr = htonl(INADDR_ANY); host.sin_port = htons(PORT); memset(&host.sin_zero, 0, sizeof(host.sin_zero)); host_fd = socket(AF_INET, SOCK_STREAM, 0); if(host_fd == -1) { printf("socket error %d\n", host_fd); return 1; } if(bind(host_fd, (struct sockaddr *)&host, size)) { printf("bind error\n"); return 1; } if(listen(host_fd, 5)) { printf("listen error"); return 1; } printf("Server setup, waiting for connection...\n"); remote_fd = accept(host_fd, (struct sockaddr *)&remote, &size); printf("connection made\n"); int read = recv(remote_fd, data, BUF, 0); data[read] = '\0'; printf("read = %d, data = %s\n", read, data); shutdown(remote_fd, SHUT_RDWR); close(remote_fd); return 0; } client. import java.net.*; import java.io.*; public class socket { public static void main(String[] argv) { DataOutputStream os = null; try { Socket socket = new Socket("192.168.1.103", 3557); os = new DataOutputStream(socket.getOutputStream()); os.writeBytes("phone 12"); os.close(); socket.close(); } catch (UnknownHostException e) { System.out.println("Unkonw exception " + e.getMessage()); } catch (IOException e) { System.out.println("IOException caught " + e.getMessage()); } } }

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• Telephone Directory

  - by Mizukage of Meron 5

  I need your help. We are ask to make a telephone directory program that asks your name, address, and telephone number. If the name you entered already exists, it will display that it already exists. This is what i have so far... #include<stdio.h> #include<conio.h> struct file { char name[25],address[25]; double telno; }; char tempname[25],tempadd[25]; double tempnum; int x; int choice; FILE *fp; main() { struct file rec; clrscr(); fp=fopen("TelDir.txt","a+"); while(!feof(fp)) { fscanf(fp,"%s %s %.0lf,&tempname,&tempadd,&tempnum); printf("\n%s\t\t%s\t\t\t%.0lf",tempname,tempadd,tempnum); printf("\nEnter Name: "); gets(rec.name); if(strcmp(rec.name,tempname)==1) { printf("\n\nALREADY EXIST!"); printf("\n%s\t\t%s\t\t\t%.0lf",tempname,tempadd,tempnum); getch(); } else { printf("Enter Address: "); scanf("%s",&rec.address); printf("Enter your Telephone No.: "); scanf("%lf",&rec.telno); printf("%s\t\t%s\t\t%\t\t0lf",rec.name,rec.address,rec.telno); fprintf(fp,"%s %s %.0lf\n",rec.name,rec.address,rec.telno); } } fclose(fp); getch(); } But this thing doesn't work. I don't know where the error is. Can someone help me on this? I would really appreciate if you could help me somehow.

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• Unexpected output while using Microsoft Visual Studio 2008 (Express Edition) C++ Command Line Tool

  - by Sujith S Pillai

  One of my friends sent this code to me, saying it doesn't work as expected: #include<stdio.h> void main() { int a [10] ={23, 100, 20, 30, 25, 45, 40, 55, 43, 42}; int sizeOfInput = sizeof(a)/sizeof(int); int b, outer, inner, c; printf("Size is : %d \n", sizeOfInput); printf("Values before bubble sort are : \n"); for ( b = 0; b < sizeOfInput; b++) printf("%d\n", a[b]); printf("End of values before bubble sort... \n"); for ( outer = sizeOfInput; outer > 0; outer-- ) { for ( inner = 0 ; inner < outer ; inner++) { printf ( "Comparing positions: %d and %d\n",inner,inner+1); if ( a[inner] > a[inner + 1] ) { int tmp = a[inner]; a[inner] = a [inner+1]; a[inner+1] = tmp; } } printf ( "Bubble sort total array size after inner loop is %d :\n",sizeOfInput); printf ( "Bubble sort sizeOfInput after inner loop is %d :\n",sizeOfInput); } printf ( "Bubble sort total array size at the end is %d :\n",sizeOfInput); for ( c = 0 ; c < sizeOfInput; c++) printf("Element: %d\n", a[c]); } I am using Micosoft Visual Studio Command Line Tool for compiling this on a Windows XP machine. cl /EHsc bubblesort01.c My friend gets the correct output on a dinosaur machine (code is compiled using TCC there). My output is unexpected. The array mysteriously grows in size, in between. If you change the code so that the variable sizeOfInput is changed to sizeOfInputt, it gives the expected results! A search done at Microsoft Visual C++ Developer Center doesn't give any results for "sizeOfInput". I am not a C/C++ expert, and am curious to find out why this happens - any C/C++ experts who can "shed some light" on this? Unrelated note: I seriously thought of rewriting the whole code to use quicksort or merge sort before posting it here. But, after all, it is not Stooge sort...

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• Sending a file from memory (rather than disk) over HTTP using libcurl

  - by cinek1lol

  Hi! I would like to send pictures via a program written in C + +. - OK WinExec("C:\\curl\\curl.exe -H Expect: -F \"fileupload=@C:\\curl\\ok.jpg\" -F \"xml=yes\" -# \"http://www.imageshack.us/index.php\" -o data.txt -A \"Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.1) Gecko/20061204 Firefox/2.0.0.1\" -e \"http://www.imageshack.us\"", NULL); It works, but I would like to send the pictures from pre-loaded carrier to a variable char (you know what I mean? First off, I load the pictures into a variable and then send the variable), cause now I have to specify the path of the picture on a disk. I wanted to write this program in c++ by using the curl library, not through exe. extension. I have also found such a program (which has been modified by me a bit) #include <stdio.h> #include <string.h> #include <iostream> #include <curl/curl.h> #include <curl/types.h> #include <curl/easy.h> int main(int argc, char *argv[]) { CURL *curl; CURLcode res; struct curl_httppost *formpost=NULL; struct curl_httppost *lastptr=NULL; struct curl_slist *headerlist=NULL; static const char buf[] = "Expect:"; curl_global_init(CURL_GLOBAL_ALL); /* Fill in the file upload field */ curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "send", CURLFORM_FILE, "nowy.jpg", CURLFORM_END); curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "nowy.jpg", CURLFORM_COPYCONTENTS, "nowy.jpg", CURLFORM_END); curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "submit", CURLFORM_COPYCONTENTS, "send", CURLFORM_END); curl = curl_easy_init(); headerlist = curl_slist_append(headerlist, buf); if(curl) { curl_easy_setopt(curl, CURLOPT_URL, "http://www.imageshack.us/index.php"); if ( (argc == 2) && (!strcmp(argv[1], "xml=yes")) ) curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headerlist); curl_easy_setopt(curl, CURLOPT_HTTPPOST, formpost); res = curl_easy_perform(curl); curl_easy_cleanup(curl); curl_formfree(formpost); curl_slist_free_all (headerlist); } system("pause"); return 0; }

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• how can I create macro definitions for the lines commented in the code.

  - by yaprak

  #include <stdio.h> //Here use a macro definition that assigns a value to SIZE (for example 5) int main() { int i; int array[SIZE]; int sum=0; for(i=0; i<SIZE; i++) { //Here use a macro definition named as CALCSUM to make the //following addition operation for the array printf("Enter a[%d] = ",i); scanf("%d", &array[i]); sum+=array[i]; //Here use a macro definition named as VERBOSE to print //what program does to the screen printf("The user entered %d\n", array[i]); // // //If the macro definition CALCSUM is not used, the program //should assign 0 to the i-th element of the array array[i]=0; //Here, again use VERBOSE to print what program does to the screen printf("a[%d] is assigned to zero\n", i); // // } //If CALCSUM is defined, print the summation of the array elements to the screen printf("Summation of the array is %d\n",sum); // //If CALCSUM is not defined, but VERBOSE mode is used, print the following printf("All the elements in the array are assigned to zero\n"); // printf("Program terminated\n"); return 0; } When CALCSUM is defined, the program will sum up the values of each element in the given array. If CALCSUM is not defined, each array element will be assigned to zero. Besides, when VERBOSE mode is defined, the program will make print statements pointed out active. [root@linux55]# gcc code.c [root@linux55]# ./a.out Program terminated [root@linux55]# gcc code.c -D CALCSUM [root@linux55]# ./a.out Enter a[0] = 3 Enter a[1] = 0 Enter a[2] = 2 Enter a[3] = 5 Enter a[4] = 9 Summation of the array is 19 Program terminated [root@linux55]# gcc code.c -D CALCSUM -D VERBOSE [root@linux55]# ./a.out Enter a[0] = 2 The user entered 2 Enter a[1] = 10 The user entered 10 Enter a[2] = 3 The user entered 3 Enter a[3] = 8 The user entered 8 Enter a[4] = 1 The user entered 1 Summation of the array is 24 Program terminated [root@linux55]# gcc code.c -D VERBOSE [root@linux55]# ./a.out a[0] is assigned to 0 a[1] is assigned to 0 a[2] is assigned to 0 a[3] is assigned to 0 a[4] is assigned to 0 All the elements in the array is assigned to zero Program terminated

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• Command prompt in debug mode for Eclipse? (OpenCV + Eclipse + Win7)

  - by Tony

  I am a beginner for Eclipse. I now have Eclipse C/C++ IDE with OpenCV library running on Windows 7. So far it works after spending hours trying to get it running. But then I realize that Eclipse does not pop up a command prompt as VS2010 does while debugging. And moreover Eclipse's debug mode is just stuck in there and refuse to output anything. But if the code doesn't involve the OpenCV things it works again. Below is the code I use for testing. It captures images from webcam and output it to the screen. The infinite loop (until you press 'q') makes sure it constantly grabs new inputs from the camera. I browsed through the workspace and run the exe just compiled and it worked flawlessly. So I don't think there's anything wrong in the code (it's an example code anyway In brief, can I just pop up a command prompt window in debug mode? And why is Eclipse console stuck when the code involves some OpenCV functions? #include <stdio.h> #include <stdlib.h> #include <tchar.h> #include <cv.h> #include <cxcore.h> #include <highgui.h> #include <iostream> int _tmain(int argc, _TCHAR* argv[]) { CvCapture *capture = 0; IplImage *frame = 0; int key = 0; /* initialize camera */ capture = cvCaptureFromCAM( 0 ); /* always check */ if ( !capture ) { printf("Cannot open initialize webcam!\n"); return 1; } /* create a window for the video */ cvNamedWindow( "result", CV_WINDOW_AUTOSIZE ); while( key != 'q' ) { /* get a frame */ frame = cvQueryFrame( capture ); /* always check */ if( !frame ) break; /* display current frame */ cvShowImage( "result", frame ); /* exit if user press 'q' */ key = cvWaitKey( 1 ); } /* free memory */ cvDestroyWindow( "result" ); cvReleaseCapture( &capture ); return 0; }

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• c permutation of a number

  - by Pkp

  I am writing a program for magic box. As the only way around it is brute force, I wrote a program to compute permutations of a given array using bells algorithm. I wrote in the lines similar to http://programminggeeks.com/c-code-for-permutation/. It does work for array of 3 and 4. It does not work for an arryay of 8 numbers (1,2,3,4,5,6,7,8). I see that the combination 1 2 3 4 5 6 7 8 gets repeated couple of times. Also there are other combinations that gets repeated. I see that certain combinations don't get displayed even. So could someone tell me what is wrong in the program below. Code: include<stdio.h> int len,numperm=1,count=0; display(int a[]){ int i; for(i=0;i<len;i++) printf("%d ",a[i]); printf("\n"); count++; } swap(int *a,int *b){ int temp; temp=*a; *a=*b; *b=temp; } no_of_perm(){ int x; for(x=1;x<=len;x++) numperm=numperm*x; } perm(int a[]){ int x,y; while(count < numperm){ for(x=0;x<len-1;x++){ swap(&a[x],&a[x+1]); display(a); } swap(&a[0],&a[1]); display(a); for(y=len-1;y>0;y--){ swap(&a[y],&a[y-1]); display(a); } swap(&a[len-1],&a[len-2]); display(a); } } main(int argc, char *argv[]){ if(argc<2){ printf("Error\n"); exit(0); } int i,*a=malloc(sizeof(int)*atoi(argv[1])); len=atoi(argv[1]); for(i=0;i<len;i++) a[i]=i+1; no_of_perm(); perm(a); }

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• CUDA memory transfer issue

  - by Vaibhav Sundriyal

  I am trying to execute a code which first transfers data from CPU to GPU memory and vice-versa. In spite of increasing the volume of data, the data transfer time remains the same as if no data transfer is actually taking place. I am posting the code. #include <stdio.h> /* Core input/output operations */ #include <stdlib.h> /* Conversions, random numbers, memory allocation, etc. */ #include <math.h> /* Common mathematical functions */ #include <time.h> /* Converting between various date/time formats */ #include <cuda.h> /* CUDA related stuff */ #include <sys/time.h> __global__ void device_volume(float *x_d,float *y_d) { int index = blockIdx.x * blockDim.x + threadIdx.x; } int main(void) { float *x_h,*y_h,*x_d,*y_d,*z_h,*z_d; long long size=9999999; long long nbytes=size*sizeof(float); timeval t1,t2; double et; x_h=(float*)malloc(nbytes); y_h=(float*)malloc(nbytes); z_h=(float*)malloc(nbytes); cudaMalloc((void **)&x_d,size*sizeof(float)); cudaMalloc((void **)&y_d,size*sizeof(float)); cudaMalloc((void **)&z_d,size*sizeof(float)); gettimeofday(&t1,NULL); cudaMemcpy(x_d, x_h, nbytes, cudaMemcpyHostToDevice); cudaMemcpy(y_d, y_h, nbytes, cudaMemcpyHostToDevice); cudaMemcpy(z_d, z_h, nbytes, cudaMemcpyHostToDevice); gettimeofday(&t2,NULL); et = (t2.tv_sec - t1.tv_sec) * 1000.0; // sec to ms et += (t2.tv_usec - t1.tv_usec) / 1000.0; // us to ms printf("\n %ld\t\t%f\t\t",nbytes,et); et=0.0; //printf("%f %d\n",seconds,CLOCKS_PER_SEC); // launch a kernel with a single thread to greet from the device //device_volume<<<1,1>>>(x_d,y_d); gettimeofday(&t1,NULL); cudaMemcpy(x_h, x_d, nbytes, cudaMemcpyDeviceToHost); cudaMemcpy(y_h, y_d, nbytes, cudaMemcpyDeviceToHost); cudaMemcpy(z_h, z_d, nbytes, cudaMemcpyDeviceToHost); gettimeofday(&t2,NULL); et = (t2.tv_sec - t1.tv_sec) * 1000.0; // sec to ms et += (t2.tv_usec - t1.tv_usec) / 1000.0; // us to ms printf("%f\n",et); cudaFree(x_d); cudaFree(y_d); cudaFree(z_d); return 0; } Can anybody help me with this issue? Thanks

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• making a queue program

  - by seventhief

  Hi can someone help me making a queue program. i want to set the array[0] to be array[1] just in display but in real i am adding value at array[0]. i got how to run the add function to it. but i can't do the view and delete command that will view from ex. array[0] to array[4], when displayed array[1] to array[5] with the value inserted. #include <stdio.h> #include <stdlib.h> #define p printf #define s scanf int rear = 0; int front = 0; int *q_array = NULL; int size = 0; main() { int num, opt; char cont[] = { 'y' }; clrscr(); p("Queue Program\n\n"); p("Queue size: "); s("%d", &size); p("\n"); if(size > 0) { q_array = malloc(size * sizeof(int)); if(q_array == NULL) { p("ERROR: malloc() failed\n"); exit(2); } } else { p("ERROR: size should be positive integer\n"); exit(1); } while((cont[0] == 'y') || (cont[0] == 'Y')) { clrscr(); p("Queue Program"); p("\n\nQueue size: %d\n\n", size); p("MAIN MENU\n1. Add\n2. Delete\n3. View"); p("\n\nYour choice: "); s("%d", &opt); p("\n"); switch(opt) { case 1: if(rear==size) { p("You can't add more data"); } else { p("Enter data for Queue[%d]: ", rear+1); s("%d", &num); add(num); } break; case 2: delt(); break; case 3: view(); break; } p("\n\nDo you want to continue? (Y\/N)"); s("%s", &cont[0]); } } add(int a) { q_array[rear]=a; rear++; } delt() { if(front==rear) { p("Queue Empty"); } else { p("Queue[%d] = %d removed.", front, q_array[front]); front++; } } view() { int i; for(i=front;i<=rear;i++) p("\nQueue[%d] = %d", i, q_array[i]); }

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• How to copy the memeory allocated in device function back to main memory

  - by xhe8

  I have a CUDA program containing a host function and a device function Execute(). In the host function, I allocate a global memory output which will then be passed to the device function and used to store the address of the global memory allocated within the device function. I want to access the in-kernel allocated memory in the host function. The following is the code: #include <stdio.h> typedef struct { int * p; int num; } Structure_A; \__global__ void Execute(Structure_A *output); int main(){ Structure_A *output; cudaMalloc((void***)&output,sizeof(Structure_A)*1); dim3 dimBlockExecute(1,1); dim3 dimGridExecute(1,1); Execute<<<dimGridExecute,dimBlockExecute>>>(output); Structure_A * output_cpu; int * p_cpu; cudaError_t err; output_cpu= (Structure_A*)malloc(1); err=cudaMemcpy(output_cpu,output,sizeof(Structure_A),cudaMemcpyDeviceToHost); if( err != cudaSuccess) { printf("CUDA error a: %s\n", cudaGetErrorString(err)); exit(-1); } p_cpu=(int *)malloc(1); err=cudaMemcpy(p_cpu,output_cpu[0].p,sizeof(int),cudaMemcpyDeviceToHost); if( err != cudaSuccess) { printf("CUDA error b: %s\n", cudaGetErrorString(err)); exit(-1); } printf("output=(%d,%d)\n",output_cpu[0].num,p_cpu[0]); return 0; } \__global__ void Execute(Structure_A *output){ int thid=threadIdx.x; output[thid].p= (int*)malloc(thid+1); output[thid].num=(thid+1); output[thid].p[0]=5; } I can compile the program. But when I run it, I got a error showing that there is a invalid argument in the following memory copy function. "err=cudaMemcpy(p_cpu,output_cpu[0].p,sizeof(int),cudaMemcpyDeviceToHost);" CUDA version is 4.2. CUDA card: Tesla C2075 OS: x86_64 GNU/Linux

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• having an issue about the output in c programming ..

  - by user2985811

  i'm having a problem on running the output after putting the input.. the output doesn't show after i put the variables and i don't know how to set the code .. so if you guys could help me with this, that would be grateful.. #include <stdio.h> #include <conio.h> int read_temps (float temps[]); int hot_days (int numOfTemp, float temps[]); int printf_temps (int numOfTemp, float temps[], int numOfHotDays); int main (void) { int index = 0; float tempVal; float temps[31]; int numOfTemp, numOfHotDays; do { printf ("Enter the temperature:"); scanf ("%f", &tempVal); if (tempVal!=-500.0) { temps[index] = tempVal; index++; } } while (tempVal != -500.0); return ; { int i; int count = 0; for (i = 0; i < numOfTemp; i++) { if (temps[i] > 32.0) count++; } return count; } { float sum = 0.0; int i; printf ("\nInput Temperatures:"); printf ("\n-------------------------"); for (i = 0;i < numOfTemp; i++) { printf ("\nDay %d : %.2fF", i+1, temps[i]); sum = sum + temps[i]; } printf ("\nNumber of Hot Days : %d", numOfHotDays); printf ("\nAverage Temperature: %.2f", sum/numOfTemp); } { clrscr (); numOfTemp = read_temps (temps); numOfHotDays = hot_days (numOfTemp, temps); clrscr (); printf_temps (numOfTemp, temps, numOfHotDays); getch (); } }

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• How do i change the BIOS boot splash screen?

  - by YumYumYum

  I have a Dell PC which has very ugly and bad luck looking Alien face on every boot. I want to change it or disable it forever, but in Bios they do not have any options. How can i change this from my linux Fedora or ArchLinux which is running now? Tried following does not work. ( http://www.pixelbeat.org/docs/bios/ ) ./flashrom -r firmware.old #save current flash ROM just in case ./flashrom -wv firmware.new #write and verify new flash ROM image Also tried: $ cat c.c #include <stdio.h> #include <inttypes.h> #include <netinet/in.h> #include <stdlib.h> #include <string.h> #include <sys/types.h> #include <sys/stat.h> #include <fcntl.h> #include <unistd.h> #define lengthof(x) (sizeof(x)/sizeof(x[0])) uint16_t checksum(const uint8_t* data, int len) { uint16_t sum = 0; int i; for (i=0; i<len; i++) sum+=*(data+i); return htons(sum); } void usage(void) { fprintf(stderr,"Usage: therm_limit [0,50,53,56,60,63,66,70]\n"); fprintf(stderr,"Report therm limit of terminal in BIOS\n"); fprintf(stderr,"If temp specifed, it is changed if required.\n"); exit(EXIT_FAILURE); } #define CHKSUM_START 51 #define CHKSUM_END 109 #define THERM_OFFSET 67 #define THERM_SHIFT 0 #define THERM_MASK (0x7 << THERM_SHIFT) #define THERM_OFF 0 uint8_t thermal_limits[]={0,50,53,56,60,63,66,70}; #define THERM_MAX (lengthof(thermal_limits)-1) #define DEV_NVRAM "/dev/nvram" #define NVRAM_MAX 114 uint8_t nvram[NVRAM_MAX]; int main(int argc, char* argv[]) { int therm_request = -1; if (argc>2) usage(); if (argc==2) { if (*argv[1]=='-') usage(); therm_request=atoi(argv[1]); int i; for (i=0; i<lengthof(thermal_limits); i++) if (thermal_limits[i]==therm_request) break; if (i==lengthof(thermal_limits)) usage(); else therm_request=i; } int fd_nvram=open(DEV_NVRAM, O_RDWR); if (fd_nvram < 0) { fprintf(stderr,"Error opening %s [%m]\n", DEV_NVRAM); exit(EXIT_FAILURE); } if (read(fd_nvram, nvram, sizeof(nvram))==-1) { fprintf(stderr,"Error reading %s [%m]\n", DEV_NVRAM); close(fd_nvram); exit(EXIT_FAILURE); } uint16_t chksum = *(uint16_t*)(nvram+CHKSUM_END); printf("%04X\n",chksum); exit(0); if (chksum == checksum(nvram+CHKSUM_START, CHKSUM_END-CHKSUM_START)) { uint8_t therm_byte = *(uint16_t*)(nvram+THERM_OFFSET); uint8_t therm_status=(therm_byte & THERM_MASK) >> THERM_SHIFT; printf("Current thermal limit: %d°C\n", thermal_limits[therm_status]); if ( (therm_status == therm_request) ) therm_request=-1; if (therm_request != -1) { if (therm_status != therm_request) printf("Setting thermal limit to %d°C\n", thermal_limits[therm_request]); uint8_t new_therm_byte = (therm_byte & ~THERM_MASK) | (therm_request << THERM_SHIFT); *(uint8_t*)(nvram+THERM_OFFSET) = new_therm_byte; *(uint16_t*)(nvram+CHKSUM_END) = checksum(nvram+CHKSUM_START, CHKSUM_END-CHKSUM_START); (void) lseek(fd_nvram,0,SEEK_SET); if (write(fd_nvram, nvram, sizeof(nvram))!=sizeof(nvram)) { fprintf(stderr,"Error writing %s [%m]\n", DEV_NVRAM); close(fd_nvram); exit(EXIT_FAILURE); } } } else { fprintf(stderr,"checksum failed. Aborting\n"); close(fd_nvram); exit(EXIT_FAILURE); } return EXIT_SUCCESS; } $ gcc c.c -o bios # ./bios 16DB

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• Why is syslog so much slower than file IO?

  - by ceving

  I wrote a simple test program to measure the performance of the syslog function. This are the results of my test system: (Debian 6.0.2 with Linux 2.6.32-5-amd64) Test Case Calls Payload Duration Thoughput [] [MB] [s] [MB/s] -------------------- ---------- ---------- ---------- ---------- syslog 200000 10.00 7.81 1.28 syslog %s 200000 10.00 9.94 1.01 write /dev/null 200000 10.00 0.03 343.93 printf %s 200000 10.00 0.13 76.29 The test program did 200000 system calls writing 50 Bytes of data during each call. Why is Syslog more than ten times slower than file IO? This is the program I used to perform the test: #include <fcntl.h> #include <stdio.h> #include <string.h> #include <sys/stat.h> #include <sys/time.h> #include <sys/types.h> #include <syslog.h> #include <unistd.h> const int iter = 200000; const char msg[] = "123456789 123456789 123456789 123456789 123456789"; struct timeval t0; struct timeval t1; void start () { gettimeofday (&t0, (void*)0); } void stop () { gettimeofday (&t1, (void*)0); } void report (char *action) { double dt = (double)t1.tv_sec - (double)t0.tv_sec + 1e-6 * ((double)t1.tv_usec - (double)t0.tv_usec); double mb = 1e-6 * sizeof (msg) * iter; if (action == NULL) printf ("Test Case Calls Payload Duration Thoughput \n" " [] [MB] [s] [MB/s] \n" "-------------------- ---------- ---------- ---------- ----------\n"); else { if (strlen (action) > 20) action[20] = 0; printf ("%-20s %-10d %-10.2f %-10.2f %-10.2f\n", action, iter, mb, dt, mb / dt); } } void test_syslog () { int i; openlog ("test_syslog", LOG_PID | LOG_NDELAY, LOG_LOCAL0); start (); for (i = 0; i < iter; i++) syslog (LOG_DEBUG, msg); stop (); closelog (); report ("syslog"); } void test_syslog_format () { int i; openlog ("test_syslog", LOG_PID | LOG_NDELAY, LOG_LOCAL0); start (); for (i = 0; i < iter; i++) syslog (LOG_DEBUG, "%s", msg); stop (); closelog (); report ("syslog %s"); } void test_write_devnull () { int i, fd; fd = open ("/dev/null", O_WRONLY); start (); for (i = 0; i < iter; i++) write (fd, msg, sizeof(msg)); stop (); close (fd); report ("write /dev/null"); } void test_printf () { int i; FILE *fp; fp = fopen ("/tmp/test_printf", "w"); start (); for (i = 0; i < iter; i++) fprintf (fp, "%s", msg); stop (); fclose (fp); report ("printf %s"); } int main (int argc, char **argv) { report (NULL); test_syslog (); test_syslog_format (); test_write_devnull (); test_printf (); }

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• The code works but when using printf it gives me a weird answer. Help please [closed]

  - by user71458

  //Programmer-William Chen //Seventh Period Computer Science II //Problem Statement - First get the elapsed times and the program will find the //split times for the user to see. // //Algorithm- First the programmer makes the prototype and calls them in the //main function. The programmer then asks the user to input lap time data. //Secondly, you convert the splits into seconds and subtract them so you can //find the splits. Then the average is all the lap time's in seconds. Finally, //the programmer printf all the results for the user to see. #include <iostream> #include <stdlib.h> #include <math.h> #include <conio.h> #include <stdio.h> using namespace std; void thisgetsElapsedTimes( int &m1, int &m2, int &m3, int &m4, int &m5, int &s1, int &s2, int &s3, int &s4, int &s5); //this is prototype void thisconvertstoseconds ( int &m1, int &m2, int &m3, int &m4, int &m5, int &s1, int &s2, int &s3, int &s4, int &s5, int &split1, int &split2, int &split3, int &split4, int &split5);//this too void thisfindsSplits(int &m1, int &m2, int &m3, int &m4, int &m5, int &split1, int &split2, int &split3, int &split4, int &split5, int &split6, int &split7, int &split8, int &split9, int &split10);// this is part of prototype void thisisthesecondconversation (int &split1M, int &split2M, int &split3M, int &split4M, int &split5M, int &split1S,int &split2S, int &split3S, int &split4S, int &split5S, int &split1, int &split2, int &split3, int &split4, int &split5);//this gets a value void thisfindstheaverage(double &average, int &split1, int &split2, int &split3, int &split4, int &split5);//and this void thisprintsstuff( int &split1M, int &split2M, int &split3M, int &split4M, int &split5M, int &split1S, int &split2S, int &split3S, int &split4S, int &split5S, double &average); //this prints int main(int argc, char *argv[]) { int m1, m2, m3, m4, m5, s1, s2, s3, s4, s5, split1, split2, split3, split4, split5, split1M, split2M, split3M, split4M, split5M, split1S, split2S, split3S, split4S, split5S; int split6, split7, split8, split9, split10; double average; char thistakescolon; thisgetsElapsedTimes ( m1, m2, m3, m4, m5, s1, s2, s3, s4, s5); thisconvertstoseconds ( m1, m2, m3, m4, m5, s1, s2, s3, s4, s5, split1, split2, split3, split4, split5); thisfindsSplits ( m1, m2, m3, m4, m5, split1, split2, split3, split4, split5, split6, split7, split8, split9, split10); thisisthesecondconversation ( split1M, split2M, split3M, split4M, split5M, split1S, split2S, split3S, split4S, split5S, split1, split2, split3, split4, split5); thisfindstheaverage ( average, split1, split2, split3, split4, split5); thisprintsstuff ( split1M, split2M, split3M, split4M, split5M, split1S, split2S, split3S, split4S, split5S, average); // these are calling statements and they call from the main function to the other functions. system("PAUSE"); return 0; } void thisgetsElapsedTimes(int &m1, int &m2, int &m3, int &m4, int &m5, int &s1, int &s2, int &s3, int &s4, int &s5) { char thistakescolon; cout << "Enter the elapsed time:" << endl; cout << " Kilometer 1 "; cin m1 thistakescolon s1; cout << " Kilometer 2 "; cin m2 thistakescolon s2; cout << " Kilometer 3 " ; cin m3 thistakescolon s3; cout << " Kilometer 4 "; cin m4 thistakescolon s4; cout << " Kilometer 5 "; cin m5 thistakescolon s5; // this gets the data required to get the results needed for the user to see // . } void thisconvertstoseconds (int &m1, int &m2, int &m3, int &m4, int &m5, int &s1, int &s2, int &s3, int &s4, int &s5, int &split1, int &split2, int &split3, int &split4, int &split5) { split1 = (m1 * 60) + s1;//this converts for minutes to seconds for m1 split2 = (m2 * 60) + s2;//this converts for minutes to seconds for m2 split3 = (m3 * 60) + s3;//this converts for minutes to seconds for m3 split4 = (m4 * 60) + s4;//this converts for minutes to seconds for m4 split5 = (m5 * 60) + s5;//this converts for minutes to seconds for m5 } void thisfindsSplits (int &m1, int &m2, int &m3, int &m4, int &m5,int &split1, int &split2, int &split3, int &split4, int &split5, int &split6, int &split7, int &split8, int &split9, int &split10)//this is function heading { split6 = split1; //this is split for the first lap. split7 = split2 - split1;//this is split for the second lap. split8 = split3 - split2;//this is split for the third lap. split9 = split4 - split3;//this is split for the fourth lap. split10 = split5 - split4;//this is split for the fifth lap. } void thisfindstheaverage(double &average, int &split1, int &split2, int &split3, int &split4, int &split5) { average = (split1 + split2 + split3 + split4 + split5)/5; // this finds the average from all the splits in seconds } void thisisthesecondconversation (int &split1M, int &split2M, int &split3M, int &split4M, int &split5M, int &split1S,int &split2S, int &split3S, int &split4S, int &split5S, int &split1, int &split2, int &split3, int &split4, int &split5) { split1M = split1 * 60; //this finds the split times split1S = split1M - split1 * 60; //then this finds split2M = split2 * 60; //and all of this split2S = split2M - split2 * 60; //does basically split3M = split3 * 60; //the same thing split3S = split3M - split3 * 60; //all of it split4M = split4 * 60; //it's also a split4S = split4M - split4 * 60; //function split5M = split5 * 60; //and it finds the splits split5S = split5M - split5 * 60; //for each lap. } void thisprintsstuff (int &split1M, int &split2M, int &split3M, int &split4M, int &split5M, int &split1S, int &split2S, int &split3S, int &split4S, int &split5S, double &average)// this is function heading { printf("\n kilometer 1 %d" , ":02%d",'split1M','split1S'); printf("\n kilometer 2 %d" , ":02%d",'split2M','split2S'); printf("\n kilometer 3 %d" , ":02%d",'split3M','split3S'); printf("\n kilometer 4 %d" , ":02%d",'split4M','split4S'); printf("\n kilometer 5 %d" , ":02%d",'split5M','split5S'); printf("\n your average pace is ",'average',"per kilometer \n", "William Chen\n"); // this printf so the programmer // can allow the user to see // the results from the data gathered. }

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• How does gluLookAt work?

  - by Chan

  From my understanding, gluLookAt( eye_x, eye_y, eye_z, center_x, center_y, center_z, up_x, up_y, up_z ); is equivalent to: glRotatef(B, 0.0, 0.0, 1.0); glRotatef(A, wx, wy, wz); glTranslatef(-eye_x, -eye_y, -eye_z); But when I print out the ModelView matrix, the call to glTranslatef() doesn't seem to work properly. Here is the code snippet: #include <stdlib.h> #include <stdio.h> #include <GL/glut.h> #include <iomanip> #include <iostream> #include <string> using namespace std; static const int Rx = 0; static const int Ry = 1; static const int Rz = 2; static const int Ux = 4; static const int Uy = 5; static const int Uz = 6; static const int Ax = 8; static const int Ay = 9; static const int Az = 10; static const int Tx = 12; static const int Ty = 13; static const int Tz = 14; void init() { glClearColor(0.0, 0.0, 0.0, 0.0); glEnable(GL_DEPTH_TEST); glShadeModel(GL_SMOOTH); glEnable(GL_LIGHTING); glEnable(GL_LIGHT0); GLfloat lmodel_ambient[] = { 0.8, 0.0, 0.0, 0.0 }; glLightModelfv(GL_LIGHT_MODEL_AMBIENT, lmodel_ambient); } void displayModelviewMatrix(float MV[16]) { int SPACING = 12; cout << left; cout << "\tMODELVIEW MATRIX\n"; cout << "--------------------------------------------------" << endl; cout << setw(SPACING) << "R" << setw(SPACING) << "U" << setw(SPACING) << "A" << setw(SPACING) << "T" << endl; cout << "--------------------------------------------------" << endl; cout << setw(SPACING) << MV[Rx] << setw(SPACING) << MV[Ux] << setw(SPACING) << MV[Ax] << setw(SPACING) << MV[Tx] << endl; cout << setw(SPACING) << MV[Ry] << setw(SPACING) << MV[Uy] << setw(SPACING) << MV[Ay] << setw(SPACING) << MV[Ty] << endl; cout << setw(SPACING) << MV[Rz] << setw(SPACING) << MV[Uz] << setw(SPACING) << MV[Az] << setw(SPACING) << MV[Tz] << endl; cout << setw(SPACING) << MV[3] << setw(SPACING) << MV[7] << setw(SPACING) << MV[11] << setw(SPACING) << MV[15] << endl; cout << "--------------------------------------------------" << endl; cout << endl; } void reshape(int w, int h) { float ratio = static_cast<float>(w)/h; glViewport(0, 0, w, h); glMatrixMode(GL_PROJECTION); glLoadIdentity(); gluPerspective(45.0, ratio, 1.0, 425.0); } void draw() { float m[16]; glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT); glMatrixMode(GL_MODELVIEW); glLoadIdentity(); glGetFloatv(GL_MODELVIEW_MATRIX, m); gluLookAt( 300.0f, 0.0f, 0.0f, 0.0f, 0.0f, 0.0f, 0.0f, 1.0f, 0.0f ); glColor3f(1.0, 0.0, 0.0); glutSolidCube(100.0); glGetFloatv(GL_MODELVIEW_MATRIX, m); displayModelviewMatrix(m); glutSwapBuffers(); } int main(int argc, char** argv) { glutInit(&argc, argv); glutInitDisplayMode(GLUT_DOUBLE | GLUT_RGB | GLUT_DEPTH); glutInitWindowSize(400, 400); glutInitWindowPosition(100, 100); glutCreateWindow("Demo"); glutReshapeFunc(reshape); glutDisplayFunc(draw); init(); glutMainLoop(); return 0; } No matter what value I use for the eye vector: 300, 0, 0 or 0, 300, 0 or 0, 0, 300 the translation vector is the same, which doesn't make any sense because the order of code is in backward order so glTranslatef should run first, then the 2 rotations. Plus, the rotation matrix, is completely independent of the translation column (in the ModelView matrix), then what would cause this weird behavior? Here is the output with the eye vector is (0.0f, 300.0f, 0.0f) MODELVIEW MATRIX -------------------------------------------------- R U A T -------------------------------------------------- 0 0 0 0 0 0 0 0 0 1 0 -300 0 0 0 1 -------------------------------------------------- I would expect the T column to be (0, -300, 0)! So could anyone help me explain this? The implementation of gluLookAt from http://www.mesa3d.org void GLAPIENTRY gluLookAt(GLdouble eyex, GLdouble eyey, GLdouble eyez, GLdouble centerx, GLdouble centery, GLdouble centerz, GLdouble upx, GLdouble upy, GLdouble upz) { float forward[3], side[3], up[3]; GLfloat m[4][4]; forward[0] = centerx - eyex; forward[1] = centery - eyey; forward[2] = centerz - eyez; up[0] = upx; up[1] = upy; up[2] = upz; normalize(forward); /* Side = forward x up */ cross(forward, up, side); normalize(side); /* Recompute up as: up = side x forward */ cross(side, forward, up); __gluMakeIdentityf(&m[0][0]); m[0][0] = side[0]; m[1][0] = side[1]; m[2][0] = side[2]; m[0][1] = up[0]; m[1][1] = up[1]; m[2][1] = up[2]; m[0][2] = -forward[0]; m[1][2] = -forward[1]; m[2][2] = -forward[2]; glMultMatrixf(&m[0][0]); glTranslated(-eyex, -eyey, -eyez); }

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• What's the best/most efficent way to create a semi-intelligent AI for a tic tac toe game?

  - by Link

  basically I am attempting to make a a efficient/smallish C game of Tic-Tac-Toe. I have implemented everything other then the AI for the computer so far. my squares are basically structs in an array with an assigned value based on the square. For example s[1].value = 1; therefore it's a x, and then a value of 3 would be a o. My question is whats the best way to create a semi-decent game playing AI for my tic-tac-toe game? I don't really want to use minimax, since It's not what I need. So how do I avoid a a lot of if statments and make it more efficient. Here is the rest of my code: #include <stdio.h> #include <stdlib.h> #include <string.h> #include <time.h> struct state{ // defined int state; // 0 is tie, 1 is user loss, 2 is user win, 3 is ongoing game int moves; }; struct square{ // one square of the board int value; // 1 is x, 3 is o char sign; // no space used }; struct square s[9]; //set up the struct struct state gamestate = {0,0}; //nothing void setUpGame(){ // setup the game int i = 0; for(i = 0; i < 9; i++){ s[i].value = 0; s[i].sign = ' '; } gamestate.moves=0; printf("\nHi user! You're \"x\"! I'm \"o\"! Good Luck :)\n"); } void displayBoard(){// displays the game board printf("\n %c | %c | %c\n", s[6].sign, s[7].sign, s[8].sign); printf("-----------\n"); printf(" %c | %c | %c\n", s[3].sign, s[4].sign, s[5].sign); printf("-----------\n"); printf(" %c | %c | %c\n\n", s[0].sign, s[1].sign, s[2].sign); } void getHumanMove(){ // get move from human int i; while(1){ printf(">>:"); char line[255]; // input the move to play fgets(line, sizeof(line), stdin); while(sscanf(line, "%d", &i) != 1) { //1 match of defined specifier on input line printf("Sorry, that's not a valid move!\n"); fgets(line, sizeof(line), stdin); } if(s[i-1].value != 0){printf("Sorry, That moves already been taken!\n\n");continue;} break; } s[i-1].value = 1; s[i-1].sign = 'x'; gamestate.moves++; } int sum(int x, int y, int z){return(x*y*z);} void getCompMove(){ // get the move from the computer } void checkWinner(){ // check the winner int i; for(i = 6; i < 9; i++){ // check cols if((sum(s[i].value,s[i-3].value,s[i-6].value)) == 8){printf("The Winner is o!\n");gamestate.state=1;} if((sum(s[i].value,s[i-3].value,s[i-6].value)) == 1){printf("The Winner is x!\n");gamestate.state=2;} } for(i = 0; i < 7; i+=3){ // check rows if((sum(s[i].value,s[i+1].value,s[i+2].value)) == 8){printf("The Winner is o!\n");gamestate.state=1;} if((sum(s[i].value,s[i+1].value,s[i+2].value)) == 1){printf("The Winner is x!\n");gamestate.state=2;} } if((sum(s[0].value,s[4].value,s[8].value)) == 8){printf("The Winner is o!\n");gamestate.state=1;} if((sum(s[0].value,s[4].value,s[8].value)) == 1){printf("The Winner is x!\n");gamestate.state=2;} if((sum(s[2].value,s[4].value,s[6].value)) == 8){printf("The Winner is o!\n");gamestate.state=1;} if((sum(s[2].value,s[4].value,s[6].value)) == 1){printf("The Winner is x!\n");gamestate.state=2;} } void playGame(){ // start playing the game gamestate.state = 3; //set-up the gamestate srand(time(NULL)); int temp = (rand()%2) + 1; if(temp == 2){ // if two comp goes first temp = (rand()%2) + 1; if(temp == 2){ s[4].value = 2; s[4].sign = 'o'; gamestate.moves++; }else{ s[2].value = 2; s[2].sign = 'o'; gamestate.moves++; } } displayBoard(); while(gamestate.state == 3){ if(gamestate.moves<10); getHumanMove(); if(gamestate.moves<10); getCompMove(); checkWinner(); if(gamestate.state == 3 && gamestate.moves==9){ printf("The game is a tie :p\n"); break; } displayBoard(); } } int main(int argc, const char *argv[]){ printf("Welcome to Tic Tac Toe\nby The Elite Noob\nEnter 1-9 To play a move, standard numpad\n1 is bottom-left, 9 is top-right\n"); while(1){ // while game is being played printf("\nPress 1 to play a new game, or any other number to exit;\n>>:"); char line[255]; // input whether or not to play the game fgets(line, sizeof(line), stdin); int choice; // user's choice about playing or not while(sscanf(line, "%d", &choice) != 1) { //1 match of defined specifier on input line printf("Sorry, that's not a valid option!\n"); fgets(line, sizeof(line), stdin); } if(choice == 1){ setUpGame(); // set's up the game playGame(); // Play a Game }else {break;} // exit the application } printf("\nThank's For playing!\nHave a good Day!\n"); return 0; }

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• C to C++ Conversion [closed]

  - by Annalyne

  Can someone convert this code to C++, pretty please? :( #include <stdio.h> #include <stdlib.h> #include <time.h> #define WEAPON_ROPE 10 #define WEAPON_REVOLVER 20 #define WEAPON_LEADPIPE 30 #define WEAPON_CANDLESTICK 40 #define WEAPON_KNIFE 50 #define WEAPON_WRENCH 60 #define PEOPLE_MRGREEN 100 #define PEOPLE_MSSCARLET 200 #define PEOPLE_CONLMUSTARD 300 #define PEOPLE_PROFPLUM 400 #define PEOPLE_MISPEACOCK 500 #define PEOPLE_MISWHITE 600 #define PLACE_KITCHEN 1 #define PLACE_HALL 2 #define PLACE_POOLROOM 3 #define PLACE_STUDY 4 #define PLACE_LOUNG 5 #define PLACE_LIBRARY 6 #define PLACE_CONSERVATORY 7 #define PLACE_DINING 8 #define PLACE_BILLIARDS 9 int main() { int die = 0; int players[6][9] = {{0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0}}; int allCards[] = {WEAPON_ROPE, WEAPON_REVOLVER, WEAPON_LEADPIPE, WEAPON_CANDLESTICK, WEAPON_CANDLESTICK, WEAPON_KNIFE, WEAPON_WRENCH, PEOPLE_MRGREEN, PEOPLE_MSSCARLET, PEOPLE_CONLMUSTARD, PEOPLE_CONLMUSTARD, PEOPLE_PROFPLUM, PEOPLE_MISPEACOCK, PEOPLE_MISWHITE, PLACE_KITCHEN, PLACE_HALL, PLACE_POOLROOM, PLACE_STUDY, PLACE_LOUNG, PLACE_LIBRARY, PLACE_CONSERVATORY, PLACE_DINING, PLACE_BILLIARDS}; int deckSize = 23; // number of cards in allCards array int count; for (count = 0; count < deckSize; ++count) { printf(", %d", allCards[count]); } // End for // These three array's are so you can put a card back, if need be... int weaponCards[] = {WEAPON_ROPE, WEAPON_REVOLVER, WEAPON_LEADPIPE, WEAPON_CANDLESTICK, WEAPON_CANDLESTICK, WEAPON_KNIFE, WEAPON_WRENCH}; int weaponDeckSize = 7; int peopleCards[] = {PEOPLE_MRGREEN, PEOPLE_MSSCARLET, PEOPLE_CONLMUSTARD, PEOPLE_CONLMUSTARD, PEOPLE_PROFPLUM, PEOPLE_MISPEACOCK, PEOPLE_MISWHITE}; int peopleDeckSize = 7; int placeCards[] = {PLACE_KITCHEN, PLACE_HALL, PLACE_POOLROOM, PLACE_STUDY, PLACE_LOUNG, PLACE_LIBRARY, PLACE_CONSERVATORY, PLACE_DINING, PLACE_BILLIARDS}; int placeDeckSize = 9; srand(clock()); // seed rand() using clock() which gives // the current tick your processor is at... int killer[3]; // no need to initialize yet. killer[0-2] will initialize int deckShuffle = rand() % weaponDeckSize; // picks one number out of the deck killer[0] = weaponCards[deckShuffle]; allCards[deckShuffle] = 0; // Card drawn. No longer exists in deck deckShuffle = rand() % peopleDeckSize; // picks another random card out of the deck killer[1] = peopleCards[deckShuffle]; allCards[deckShuffle + weaponDeckSize] = 0; // Card drawn. No longer exists in deck deckShuffle = rand() % placeDeckSize; // randomly picks the last card needed killer[2] = placeCards[deckShuffle]; allCards[deckShuffle + weaponDeckSize + peopleDeckSize] = 0; // Card drawn. No longer exists in deck int numberOfCards = 0; printf("CLUE\n"); printf("written by John Schintone\n"); printf("Origonal game delvoped by Hasbro\n"); int numberOfPlayers = 0; while ((numberOfPlayers < 3) || (numberOfPlayers > 6)) { printf("How many players are Going to play :\n"); printf("[number] > "); scanf("%d",&numberOfPlayers); // A very fast if statement which only uses integers/char's switch(numberOfPlayers) { case 6: { numberOfCards = 3; } break; case 5: { numberOfCards = 4; } break; case 4: { numberOfCards = 5; } break; case 3: { numberOfCards = 6; } break; default: { printf("You must enter a number between 3 and 6...\n"); } // End default } // End switch } // End while int index1, index2; // Note: ++index1; is faster than index1++; and will almost always // produce better code (index1++ happens after this statement line. // ++index1 increments index1 before this statement line) for (index1 = 0; index1 < numberOfPlayers; ++index1) { printf("Player %d", index1); for (index2 = 0; index2 < numberOfCards; ++index2) { // Remember that allCards[deckShuffle] == 0 because we removed that // card ages ago... works out well, just don't forget you did that : ) while (allCards[deckShuffle] == 0) { deckShuffle = rand() % deckSize; } // End while players[index1][index2] = allCards[deckShuffle]; allCards[deckShuffle] = 0; // Card removed for after loop... printf(", %d", players[index1][index2]); switch(players[index1][index2]) { case WEAPON_ROPE: { } break; // Add more... case PEOPLE_MRGREEN: { } break; // Add more... case PLACE_KITCHEN: { } break; // Add more... default: { printf("Program has caught player %d cheating...", index1); } // End default } // End switch } // End for printf("\n"); } // End for printf("The killer is %d, with the %d, and in the %d \n\n", killer[0], killer[1], killer[2]); printf("Type h for this help... \n"); printf("Type e to escape... \n"); printf("Type r to roll the die... \n"); char command = '\0'; // \0 represents zero, or the null character while (command != 'e') { printf("[one character] > "); scanf("%c", &command); if (command == 'r') { die = rand() % 6 + 1; printf("Your number is: %d \n", die); } // end while if (command == 'h') { printf("Type h for this help... \n"); printf("Type e to escape... \n"); printf("Type r to roll the die... \n"); } // End if printf("\n"); } // End while return(0); // Success. Program worked ok } // End main() Function

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• Informaton of pendriver with libudv on linux

  - by Catanzaro

  I'm doing a little app in C that read the driver information of my pendrive: Plugged it and typed dmesg: [ 7676.243994] scsi 7:0:0:0: Direct-Access Lexar USB Flash Drive 1100 PQ: 0 ANSI: 0 CCS [ 7676.248359] sd 7:0:0:0: Attached scsi generic sg2 type 0 [ 7676.256733] sd 7:0:0:0: [sdb] 7831552 512-byte logical blocks: (4.00 GB/3.73 GiB) [ 7676.266559] sd 7:0:0:0: [sdb] Write Protect is off [ 7676.266566] sd 7:0:0:0: [sdb] Mode Sense: 43 00 00 00 [ 7676.266569] sd 7:0:0:0: [sdb] Assuming drive cache: write through [ 7676.285373] sd 7:0:0:0: [sdb] Assuming drive cache: write through [ 7676.285383] sdb: sdb1 [ 7676.298661] sd 7:0:0:0: [sdb] Assuming drive cache: write through [ 7676.298667] sd 7:0:0:0: [sdb] Attached SCSI removable disk with "udevadm info -q all -n /dev/sdb" P: /devices/pci0000:00/0000:00:11.0/0000:02:03.0/usb1/1-1/1-1:1.0/host7/target7:0:0/7:0:0:0/block/sdb N: sdb W: 36 S: block/8:16 S: disk/by-id/usb-Lexar_USB_Flash_Drive_AA5OCYQII8PSQXBB-0:0 S: disk/by-path/pci-0000:02:03.0-usb-0:1:1.0-scsi-0:0:0:0 E: UDEV_LOG=3 E: DEVPATH=/devices/pci0000:00/0000:00:11.0/0000:02:03.0/usb1/1-1/1-1:1.0/host7/target7:0:0/7:0:0:0/block/sdb E: MAJOR=8 E: MINOR=16 E: DEVNAME=/dev/sdb E: DEVTYPE=disk E: SUBSYSTEM=block E: ID_VENDOR=Lexar E: ID_VENDOR_ENC=Lexar\x20\x20\x20 E: ID_VENDOR_ID=05dc E: ID_MODEL=USB_Flash_Drive E: ID_MODEL_ENC=USB\x20Flash\x20Drive\x20 E: ID_MODEL_ID=a813 E: ID_REVISION=1100 E: ID_SERIAL=Lexar_USB_Flash_Drive_AA5OCYQII8PSQXBB-0:0 E: ID_SERIAL_SHORT=AA5OCYQII8PSQXBB E: ID_TYPE=disk E: ID_INSTANCE=0:0 E: ID_BUS=usb E: ID_USB_INTERFACES=:080650: E: ID_USB_INTERFACE_NUM=00 E: ID_USB_DRIVER=usb-storage E: ID_PATH=pci-0000:02:03.0-usb-0:1:1.0-scsi-0:0:0:0 E: ID_PART_TABLE_TYPE=dos E: UDISKS_PRESENTATION_NOPOLICY=0 E: UDISKS_PARTITION_TABLE=1 E: UDISKS_PARTITION_TABLE_SCHEME=mbr E: UDISKS_PARTITION_TABLE_COUNT=1 E: DEVLINKS=/dev/block/8:16 /dev/disk/by-id/usb-Lexar_USB_Flash_Drive_AA5OCYQII8PSQXBB-0:0 /dev/disk/by-path/pci-0000:02:03.0-usb-0:1:1.0-scsi-0:0:0:0 and my software is: Codice: Seleziona tutto #include <stdio.h> #include <libudev.h> #include <stdlib.h> #include <locale.h> #include <unistd.h> int main(void) { struct udev_enumerate *enumerate; struct udev_list_entry *devices, *dev_list_entry; struct udev_device *dev; /* Create the udev object */ struct udev *udev = udev_new(); if (!udev) { printf("Can't create udev\n"); exit(0); } enumerate = udev_enumerate_new(udev); udev_enumerate_add_match_subsystem(enumerate, "scsi_generic"); udev_enumerate_scan_devices(enumerate); devices = udev_enumerate_get_list_entry(enumerate); udev_list_entry_foreach(dev_list_entry, devices) { const char *path; /* Get the filename of the /sys entry for the device and create a udev_device object (dev) representing it */ path = udev_list_entry_get_name(dev_list_entry); dev = udev_device_new_from_syspath(udev, path); /* usb_device_get_devnode() returns the path to the device node itself in /dev. */ printf("Device Node Path: %s\n", udev_device_get_devnode(dev)); /* The device pointed to by dev contains information about the hidraw device. In order to get information about the USB device, get the parent device with the subsystem/devtype pair of "usb"/"usb_device". This will be several levels up the tree, but the function will find it.*/ dev = udev_device_get_parent_with_subsystem_devtype( dev, "block", "disk"); if (!dev) { printf("Errore\n"); exit(1); } /* From here, we can call get_sysattr_value() for each file in the device's /sys entry. The strings passed into these functions (idProduct, idVendor, serial, etc.) correspond directly to the files in the directory which represents the USB device. Note that USB strings are Unicode, UCS2 encoded, but the strings returned from udev_device_get_sysattr_value() are UTF-8 encoded. */ printf(" VID/PID: %s %s\n", udev_device_get_sysattr_value(dev,"idVendor"), udev_device_get_sysattr_value(dev, "idProduct")); printf(" %s\n %s\n", udev_device_get_sysattr_value(dev,"manufacturer"), udev_device_get_sysattr_value(dev,"product")); printf(" serial: %s\n", udev_device_get_sysattr_value(dev, "serial")); udev_device_unref(dev); } /* Free the enumerator object */ udev_enumerate_unref(enumerate); udev_unref(udev); return 0; } the problem is that i obtain in output: Device Node Path: /dev/sg0 Errore and dont view information. subsystem and the devtype i think that are inserted well : "block" and "disk". thanks for help. Bye

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• Making an asynchronous Client with boost::asio

  - by tag

  Hello, i'm trying to make an asynchronous Client with boost::asio, i use the daytime asynchronous Server(in the tutorial). However sometimes the Client don't receive the Message, sometimes it do :O I'm sorry if this is too much Code, but i don't know what's wrong :/ Client: #include <iostream> #include <stdio.h> #include <ostream> #include <boost/thread.hpp> #include <boost/bind.hpp> #include <boost/array.hpp> #include <boost/asio.hpp> using namespace std; using boost::asio::ip::tcp; class TCPClient { public: TCPClient(boost::asio::io_service& IO_Service, tcp::resolver::iterator EndPointIter); void Write(); void Close(); private: boost::asio::io_service& m_IOService; tcp::socket m_Socket; boost::array<char, 128> m_Buffer; size_t m_BufLen; private: void OnConnect(const boost::system::error_code& ErrorCode, tcp::resolver::iterator EndPointIter); void OnReceive(const boost::system::error_code& ErrorCode); void DoClose(); }; TCPClient::TCPClient(boost::asio::io_service& IO_Service, tcp::resolver::iterator EndPointIter) : m_IOService(IO_Service), m_Socket(IO_Service) { tcp::endpoint EndPoint = *EndPointIter; m_Socket.async_connect(EndPoint, boost::bind(&TCPClient::OnConnect, this, boost::asio::placeholders::error, ++EndPointIter)); } void TCPClient::Close() { m_IOService.post( boost::bind(&TCPClient::DoClose, this)); } void TCPClient::OnConnect(const boost::system::error_code& ErrorCode, tcp::resolver::iterator EndPointIter) { if (ErrorCode == 0) // Successful connected { m_Socket.async_receive(boost::asio::buffer(m_Buffer.data(), m_BufLen), boost::bind(&TCPClient::OnReceive, this, boost::asio::placeholders::error)); } else if (EndPointIter != tcp::resolver::iterator()) { m_Socket.close(); tcp::endpoint EndPoint = *EndPointIter; m_Socket.async_connect(EndPoint, boost::bind(&TCPClient::OnConnect, this, boost::asio::placeholders::error, ++EndPointIter)); } } void TCPClient::OnReceive(const boost::system::error_code& ErrorCode) { if (ErrorCode == 0) { std::cout << m_Buffer.data() << std::endl; m_Socket.async_receive(boost::asio::buffer(m_Buffer.data(), m_BufLen), boost::bind(&TCPClient::OnReceive, this, boost::asio::placeholders::error)); } else { DoClose(); } } void TCPClient::DoClose() { m_Socket.close(); } int main() { try { boost::asio::io_service IO_Service; tcp::resolver Resolver(IO_Service); tcp::resolver::query Query("127.0.0.1", "daytime"); tcp::resolver::iterator EndPointIterator = Resolver.resolve(Query); TCPClient Client(IO_Service, EndPointIterator); boost::thread ClientThread( boost::bind(&boost::asio::io_service::run, &IO_Service)); std::cout << "Client started." << std::endl; std::string Input; while (Input != "exit") { std::cin >> Input; } Client.Close(); ClientThread.join(); } catch (std::exception& e) { std::cerr << e.what() << std::endl; } } Server: http://www.boost.org/doc/libs/1_39_0/doc/html/boost_asio/tutorial/tutdaytime3/src.html Regards :)

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• Write a signal handler to catch SIGSEGV

  - by Adi

  Hi all, I want to write a signal handler to catch SIGSEGV. First , I would protect a block of memory for read or writes using char *buffer; char *p; char a; int pagesize = 4096; " mprotect(buffer,pagesize,PROT_NONE) " What this will do is , it will protect the memory starting from buffer till pagesize for any reads or writes. Second , I will try to read the memory by doing something like p = buffer; a = *p This will generate a SIGSEGV and i have initialized a handler for this. The handler will be called . So far so good. Now the problem I am facing is , once the handler is called, I want to change the access write of the memory by doing mprotect(buffer, pagesize,PROT_READ); and continue my normal functioning of the code. I do not want to exit the function. On future writes to the same memory, I want again catch the signal and modify the write rights and then take account of that event. Here is the code I am trying : #include <signal.h> #include <stdio.h> #include <malloc.h> #include <stdlib.h> #include <errno.h> #include <sys/mman.h> #define handle_error(msg) \ do { perror(msg); exit(EXIT_FAILURE); } while (0) char *buffer; int flag=0; static void handler(int sig, siginfo_t *si, void *unused) { printf("Got SIGSEGV at address: 0x%lx\n",(long) si->si_addr); printf("Implements the handler only\n"); flag=1; //exit(EXIT_FAILURE); } int main(int argc, char *argv[]) { char *p; char a; int pagesize; struct sigaction sa; sa.sa_flags = SA_SIGINFO; sigemptyset(&sa.sa_mask); sa.sa_sigaction = handler; if (sigaction(SIGSEGV, &sa, NULL) == -1) handle_error("sigaction"); pagesize=4096; /* Allocate a buffer aligned on a page boundary; initial protection is PROT_READ | PROT_WRITE */ buffer = memalign(pagesize, 4 * pagesize); if (buffer == NULL) handle_error("memalign"); printf("Start of region: 0x%lx\n", (long) buffer); printf("Start of region: 0x%lx\n", (long) buffer+pagesize); printf("Start of region: 0x%lx\n", (long) buffer+2*pagesize); printf("Start of region: 0x%lx\n", (long) buffer+3*pagesize); //if (mprotect(buffer + pagesize * 0, pagesize,PROT_NONE) == -1) if (mprotect(buffer + pagesize * 0, pagesize,PROT_NONE) == -1) handle_error("mprotect"); //for (p = buffer ; ; ) if(flag==0) { p = buffer+pagesize/2; printf("It comes here before reading memory\n"); a = *p; //trying to read the memory printf("It comes here after reading memory\n"); } else { if (mprotect(buffer + pagesize * 0, pagesize,PROT_READ) == -1) handle_error("mprotect"); a = *p; printf("Now i can read the memory\n"); } /* for (p = buffer;p<=buffer+4*pagesize ;p++ ) { //a = *(p); *(p) = 'a'; printf("Writing at address %p\n",p); }*/ printf("Loop completed\n"); /* Should never happen */ exit(EXIT_SUCCESS); } The problem I am facing with this is ,only the signal handler is running and I am not able to return to the main function after catching the signal.. Any help in this will be greatly appreciated. Thanks in advance Aditya

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• 5x5 matrix multiplication in C

  - by Rick

  I am stuck on this problem in my homework. I've made it this far and am sure the problem is in my three for loops. The question directly says to use 3 for loops so I know this is probably just a logic error. #include<stdio.h> void matMult(int A[][5],int B[][5],int C[][5]); int printMat_5x5(int A[5][5]); int main() { int A[5][5] = {{1,2,3,4,6}, {6,1,5,3,8}, {2,6,4,9,9}, {1,3,8,3,4}, {5,7,8,2,5}}; int B[5][5] = {{3,5,0,8,7}, {2,2,4,8,3}, {0,2,5,1,2}, {1,4,0,5,1}, {3,4,8,2,3}}; int C[5][5] = {0}; matMult(A,B,C); printMat_5x5(A); printf("\n"); printMat_5x5(B); printf("\n"); printMat_5x5(C); return 0; } void matMult(int A[][5], int B[][5], int C[][5]) { int i; int j; int k; for(i = 0; i <= 2; i++) { for(j = 0; j <= 4; j++) { for(k = 0; k <= 3; k++) { C[i][j] += A[i][k] * B[k][j]; } } } } int printMat_5x5(int A[5][5]){ int i; int j; for (i = 0;i < 5;i++) { for(j = 0;j < 5;j++) { printf("%2d",A[i][j]); } printf("\n"); } } EDIT: Here is the question, sorry for not posting it the first time. (2) Write a C function to multiply two five by five matrices. The prototype should read void matMult(int a[][5],int b[][5],int c[][5]); The resulting matrix product (a times b) is returned in the two dimensional array c (the third parameter of the function). Program your solution using three nested for loops (each generating the counter values 0, 1, 2, 3, 4) That is, DO NOT code specific formulas for the 5 by 5 case in the problem, but make your code general so it can be easily changed to compute the product of larger square matrices. Write a main program to test your function using the arrays a: 1 2 3 4 6 6 1 5 3 8 2 6 4 9 9 1 3 8 3 4 5 7 8 2 5 b: 3 5 0 8 7 2 2 4 8 3 0 2 5 1 2 1 4 0 5 1 3 4 8 2 3 Print your matrices in a neat format using a C function created for printing five by five matrices. Print all three matrices. Generate your test arrays in your main program using the C array initialization feature. enter code here

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• Bundler doesn't want to install hpricot on Windows XP with Ruby 1.8.7

  - by Nick Gorbikoff

  Hello I develop on a Windows machine but deploy to Debian. Trying to use hpricot with Rails 3 app. I can get the gem to install using : gem install hpricot --platform=mswin32 But when I do this in the bundle file - it keeps throwing an error (I think it's trying to install the wrong version of hpricot (not windows specific) group :production do gem "hpricot", "0.8.3" end group :development, :test do gem "hpricot", "0.8.3", :platforms => [:mswin, :mingw] end This is from another question here on stackoverflow - but it's not working for me. Any ideas? P.S.: Windows XP sp3 with Ruby 1.8.7 with Rails 3.0.3 with bundler 1.0.7 EDIT Forgot to paste my error: bundle install Fetching source index for http://rubygems.org/ which: no sudo in (.;C:\Program Files\ImageMagick-6.6.5-Q16;C:\ruby\Ruby187\bin;C:\Program Files\ActiveState Komodo Edit 6\;C:\WINDOWS\system32;C:\WINDOWS;C:\WINDOWS\System32\Wbem;C:\Program Files\e\cmd;C:\Program Files\MySQL\MySQL Server 5.1\bin;C:\WINDOWS\system32\WindowsPowerShell\v1.0;c:\tools;C:\gnuwin32\bin;C:\tools\wkhtmltopdf;C:\Python31;C:\Program Files\TortoiseHg\;C:\Program Files\TortoiseGit\bin; c:\program files\videolan\vlc;C:\Program Files\SMPlayer\mplayer;C:\Program Files\Git\cmd;C:\Program Files\QuickTime\QTSystem\;C:\Program Files\Calibre2\;c:\ruby\jruby-1.5.5\bin;C:\Program Files\Common Files\Shoes\0.r1514\..) Using rake (0.8.7) Using abstract (1.0.0) Using activesupport (3.0.3) Using builder (2.1.2) Using i18n (0.4.2) Using activemodel (3.0.3) Using erubis (2.6.6) Using rack (1.2.1) Using rack-mount (0.6.13) Using rack-test (0.5.6) Using tzinfo (0.3.23) Using actionpack (3.0.3) Using mime-types (1.16) Using polyglot (0.3.1) Using treetop (1.4.9) Using mail (2.2.10) Using actionmailer (3.0.3) Using arel (2.0.4) Using activerecord (3.0.3) Using activeresource (3.0.3) Using bcrypt-ruby (2.1.4) Using bundler (1.0.7) Using cancan (1.5.0) Using haml (3.0.24) Using compass (0.10.6) Using warden (1.0.3) Using devise (1.1.5) Installing hpricot (0.8.3) Temporarily enhancing PATH to include DevKit... with native extensions C:/ruby/Ruby187/lib/ruby/site_ruby/1.8/rubygems/installer.rb:483:in `build_extensions': ERROR: Failed to build gem native extension. (Gem::Installer::ExtensionBuildError) C:/ruby/Ruby187/bin/ruby.exe extconf.rb checking for stdio.h... no *** extconf.rb failed *** Could not create Makefile due to some reason, probably lack of necessary libraries and/or headers. Check the mkmf.log file for more details. You may need configuration options. Provided configuration options: --with-opt-dir --without-opt-dir --with-opt-include --without-opt-include=${opt-dir}/include --with-opt-lib --without-opt-lib=${opt-dir}/lib --with-make-prog --without-make-prog --srcdir=. --curdir --ruby=C:/ruby/Ruby187/bin/ruby Gem files will remain installed in C:/ruby/Ruby187/lib/ruby/gems/1.8/gems/hpricot-0.8.3 for inspection. Results logged to C:/ruby/Ruby187/lib/ruby/gems/1.8/gems/hpricot-0.8.3/ext/fast_xs/gem_make.out from C:/ruby/Ruby187/lib/ruby/site_ruby/1.8/rubygems/installer.rb:446:in `each' from C:/ruby/Ruby187/lib/ruby/site_ruby/1.8/rubygems/installer.rb:446:in `build_extensions' from C:/ruby/Ruby187/lib/ruby/site_ruby/1.8/rubygems/installer.rb:198:in `install' from C:/ruby/Ruby187/lib/ruby/gems/1.8/gems/bundler-1.0.7/lib/bundler/source.rb:95:in `install' from C:/ruby/Ruby187/lib/ruby/gems/1.8/gems/bundler-1.0.7/lib/bundler/installer.rb:55:in `run' from C:/ruby/Ruby187/lib/ruby/gems/1.8/gems/bundler-1.0.7/lib/bundler/spec_set.rb:12:in `each' from C:/ruby/Ruby187/lib/ruby/gems/1.8/gems/bundler-1.0.7/lib/bundler/spec_set.rb:12:in `each' from C:/ruby/Ruby187/lib/ruby/gems/1.8/gems/bundler-1.0.7/lib/bundler/installer.rb:44:in `run' from C:/ruby/Ruby187/lib/ruby/gems/1.8/gems/bundler-1.0.7/lib/bundler/installer.rb:8:in `install' from C:/ruby/Ruby187/lib/ruby/gems/1.8/gems/bundler-1.0.7/lib/bundler/cli.rb:225:in `install' from C:/ruby/Ruby187/lib/ruby/gems/1.8/gems/bundler-1.0.7/lib/bundler/vendor/thor/task.rb:22:in `send' from C:/ruby/Ruby187/lib/ruby/gems/1.8/gems/bundler-1.0.7/lib/bundler/vendor/thor/task.rb:22:in `run' from C:/ruby/Ruby187/lib/ruby/gems/1.8/gems/bundler-1.0.7/lib/bundler/vendor/thor/invocation.rb:118:in `invoke_task' from C:/ruby/Ruby187/lib/ruby/gems/1.8/gems/bundler-1.0.7/lib/bundler/vendor/thor.rb:246:in `dispatch' from C:/ruby/Ruby187/lib/ruby/gems/1.8/gems/bundler-1.0.7/lib/bundler/vendor/thor/base.rb:389:in `start' from C:/ruby/Ruby187/lib/ruby/gems/1.8/gems/bundler-1.0.7/bin/bundle:13 from C:/ruby/Ruby187/bin/bundle:19:in `load' from C:/ruby/Ruby187/bin/bundle:19

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