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  • Basic data alignment question

    - by Broken Logic
    I've been playing around to see how my computer works under the hood. What I'm interested in is seeing is what happens on the stack inside a function. To do this I've written the following toy program: #include <stdio.h> void __cdecl Test1(char a, unsigned long long b, char c) { char c1; unsigned long long b1; char a1; c1 = 'b'; b1 = 4; a1 = 'r'; printf("%d %d - %d - %d %d Total: %d\n", (long)&b1 - (long)&a1, (long)&c1 - (long)&b1, (long)&a - (long)&c1, (long)&b - (long)&a, (long)&c - (long)&b, (long)&c - (long)&a1 ); }; struct TestStruct { char a; unsigned long long b; char c; }; void __cdecl Test2(char a, unsigned long long b, char c) { TestStruct locals; locals.a = 'b'; locals.b = 4; locals.c = 'r'; printf("%d %d - %d - %d %d Total: %d\n", (long)&locals.b - (long)&locals.a, (long)&locals.c - (long)&locals.b, (long)&a - (long)&locals.c, (long)&b - (long)&a, (long)&c - (long)&b, (long)&c - (long)&locals.a ); }; int main() { Test1('f', 0, 'o'); Test2('f', 0, 'o'); return 0; } And this spits out the following: 9 19 - 13 - 4 8 Total: 53 8 8 - 24 - 4 8 Total: 52 The function args are well behaved but as the calling convention is specified, I'd expect this. But the local variables are a bit wonky. My question is, why wouldn't these be the same? The second call seems to produce a more compact and better aligned stack. Looking at the ASM is unenlightening (at least to me), as the variable addresses are still aliased there. So I guess this is really a question about the assembler itself allocates the stack to local variables. I realise that any specific answer is likely to be platform specific. I'm more interested in a general explanation unless this quirk really is platform specific. For the record though, I'm compiling with VS2010 on a 64bit Intel machine.

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  • "Use of uninitialised value" despite of memset

    - by Framester
    Hi there, I allocate a 2d array and use memset to fill it with zeros. #include<stdio.h> #include<string.h> #include<stdlib.h> void main() { int m=10; int n =10; int **array_2d; array_2d = (int**) malloc(m*sizeof(int*)); if(array_2d==NULL) { printf("\n Could not malloc 2d array \n"); exit(1); } for(int i=0;i<m;i++) { ((array_2d)[i])=malloc(n*sizeof(int)); memset(((array_2d)[i]),0,sizeof(n*sizeof(int))); } for(int i=0; i<10;i++){ for(int j=0; j<10;j++){ printf("(%i,%i)=",i,j); fflush(stdout); printf("%i ", array_2d[i][j]); } printf("\n"); } } Afterwards I use valgrind [1] to check for memory errors. I get following error: Conditional jump or move depends on uninitialised value(s) for line 24 (printf("%i ", array_2d[i][j]);). I always thought memset is the function to initialize arrays. How can I get rid off this error? Thanks! Valgrind output: ==3485== Memcheck, a memory error detector ==3485== Copyright (C) 2002-2009, and GNU GPL'd, by Julian Seward et al. ==3485== Using Valgrind-3.5.0-Debian and LibVEX; rerun with -h for copyright info ==3485== Command: ./a.out ==3485== (0,0)=0 (0,1)===3485== Use of uninitialised value of size 4 ==3485== at 0x409E186: _itoa_word (_itoa.c:195) ==3485== by 0x40A1AD1: vfprintf (vfprintf.c:1613) ==3485== by 0x40A8FFF: printf (printf.c:35) ==3485== by 0x8048724: main (playing_with_valgrind.c:39) ==3485== ==3485== ==3485== ---- Attach to debugger ? --- [Return/N/n/Y/y/C/c] ---- ==3485== Conditional jump or move depends on uninitialised value(s) ==3485== at 0x409E18E: _itoa_word (_itoa.c:195) ==3485== by 0x40A1AD1: vfprintf (vfprintf.c:1613) ==3485== by 0x40A8FFF: printf (printf.c:35) ==3485== by 0x8048724: main (playing_with_valgrind.c:39) [1] valgrind --tool=memcheck --leak-check=yes --show-reachable=yes --num-callers=20 --track-fds=yes --db-attach=yes ./a.out [gcc-cmd] gcc -std=c99 -lm -Wall -g3 playing_with_valgrind.c

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  • passing a class method as opposed to a function in std::sort

    - by memC
    hi, Within a class, I am trying to sort a vector, by passing a method of the same class. But it gives errors at the time of compilation. Can anyone tell what the problem is? Thank you! it gives the following error: argument of type bool (Sorter::)(D&, D&)' does not matchbool (Sorter::*)(D&, D&)' I have also tried using sortBynumber(D const& d1, D const& d2) #include<vector> #include<stdio.h> #include<iostream> #include<algorithm> class D { public: int getNumber(); D(int val); ~D(){}; private: int num; }; D::D(int val){ num = val; }; int D::getNumber(){ return num; }; class Sorter { public: void doSorting(); bool sortByNumber(D& d1, D& d2); std::vector<D> vec_D; Sorter(); ~Sorter(){}; private: int num; }; Sorter::Sorter(){ int i; for ( i = 0; i < 10; i++){ vec_D.push_back(D(i)); } }; bool Sorter::sortByNumber(D& d1, D& d2){ return d1.getNumber() < d2.getNumber(); }; void Sorter::doSorting(){ std::sort(vec_D.begin(), vec_D.end(), this->sortByNumber); }; int main(){ Sorter s; s.doSorting(); std::cout << "\nPress RETURN to continue..."; std::cin.get(); return 0; }

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  • Implications of trying to double free memory space in C

    - by SidNoob
    Here' my piece of code: #include <stdio.h> #include<stdlib.h> struct student{ char *name; }; int main() { struct student s; s.name = malloc(sizeof(char *)); // I hope this is the right way... printf("Name: "); scanf("%[^\n]", s.name); printf("You Entered: \n\n"); printf("%s\n", s.name); free(s.name); // This will cause my code to break } All I know is that dynamic allocation on the 'heap' needs to be freed. My question is, when I run the program, sometimes the code runs successfully. i.e. ./struct Name: Thisis Myname You Entered: Thisis Myname I tried reading this I've concluded that I'm trying to double-free a piece of memory i.e. I'm trying to free a piece of memory that is already free? (hope I'm correct here. If Yes, what could be the Security Implications of a double-free?) While it fails sometimes as its supposed to: ./struct Name: CrazyFishMotorhead Rider You Entered: CrazyFishMotorhead Rider *** glibc detected *** ./struct: free(): invalid next size (fast): 0x08adb008 *** ======= Backtrace: ========= /lib/tls/i686/cmov/libc.so.6(+0x6b161)[0xb7612161] /lib/tls/i686/cmov/libc.so.6(+0x6c9b8)[0xb76139b8] /lib/tls/i686/cmov/libc.so.6(cfree+0x6d)[0xb7616a9d] ./struct[0x8048533] /lib/tls/i686/cmov/libc.so.6(__libc_start_main+0xe6)[0xb75bdbd6] ./struct[0x8048441] ======= Memory map: ======== 08048000-08049000 r-xp 00000000 08:01 288098 /root/struct 08049000-0804a000 r--p 00000000 08:01 288098 /root/struct 0804a000-0804b000 rw-p 00001000 08:01 288098 /root/struct 08adb000-08afc000 rw-p 00000000 00:00 0 [heap] b7400000-b7421000 rw-p 00000000 00:00 0 b7421000-b7500000 ---p 00000000 00:00 0 b7575000-b7592000 r-xp 00000000 08:01 788956 /lib/libgcc_s.so.1 b7592000-b7593000 r--p 0001c000 08:01 788956 /lib/libgcc_s.so.1 b7593000-b7594000 rw-p 0001d000 08:01 788956 /lib/libgcc_s.so.1 b75a6000-b75a7000 rw-p 00000000 00:00 0 b75a7000-b76fa000 r-xp 00000000 08:01 920678 /lib/tls/i686/cmov/libc-2.11.1.so b76fa000-b76fc000 r--p 00153000 08:01 920678 /lib/tls/i686/cmov/libc-2.11.1.so b76fc000-b76fd000 rw-p 00155000 08:01 920678 /lib/tls/i686/cmov/libc-2.11.1.so b76fd000-b7700000 rw-p 00000000 00:00 0 b7710000-b7714000 rw-p 00000000 00:00 0 b7714000-b7715000 r-xp 00000000 00:00 0 [vdso] b7715000-b7730000 r-xp 00000000 08:01 788898 /lib/ld-2.11.1.so b7730000-b7731000 r--p 0001a000 08:01 788898 /lib/ld-2.11.1.so b7731000-b7732000 rw-p 0001b000 08:01 788898 /lib/ld-2.11.1.so bffd5000-bfff6000 rw-p 00000000 00:00 0 [stack] Aborted So why is it that my code does work sometimes? i.e. the compiler is not able to detect at times that I'm trying to free an already freed memory. Has it got to do something with my stack/heap size?

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  • Multi-threaded random_r is slower than single threaded version.

    - by Nixuz
    The following program is essentially the same the one described here. When I run and compile the program using two threads (NTHREADS == 2), I get the following run times: real 0m14.120s user 0m25.570s sys 0m0.050s When it is run with just one thread (NTHREADS == 1), I get run times significantly better even though it is only using one core. real 0m4.705s user 0m4.660s sys 0m0.010s My system is dual core, and I know random_r is thread safe and I am pretty sure it is non-blocking. When the same program is run without random_r and a calculation of cosines and sines is used as a replacement, the dual-threaded version runs in about 1/2 the time as expected. #include <pthread.h> #include <stdlib.h> #include <stdio.h> #define NTHREADS 2 #define PRNG_BUFSZ 8 #define ITERATIONS 1000000000 void* thread_run(void* arg) { int r1, i, totalIterations = ITERATIONS / NTHREADS; for (i = 0; i < totalIterations; i++){ random_r((struct random_data*)arg, &r1); } printf("%i\n", r1); } int main(int argc, char** argv) { struct random_data* rand_states = (struct random_data*)calloc(NTHREADS, sizeof(struct random_data)); char* rand_statebufs = (char*)calloc(NTHREADS, PRNG_BUFSZ); pthread_t* thread_ids; int t = 0; thread_ids = (pthread_t*)calloc(NTHREADS, sizeof(pthread_t)); /* create threads */ for (t = 0; t < NTHREADS; t++) { initstate_r(random(), &rand_statebufs[t], PRNG_BUFSZ, &rand_states[t]); pthread_create(&thread_ids[t], NULL, &thread_run, &rand_states[t]); } for (t = 0; t < NTHREADS; t++) { pthread_join(thread_ids[t], NULL); } free(thread_ids); free(rand_states); free(rand_statebufs); } I am confused why when generating random numbers the two threaded version performs much worse than the single threaded version, considering random_r is meant to be used in multi-threaded applications.

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  • what is the wrong with this code"length indicator implementation" ?

    - by cj
    Hello, this is an implementation of length indicator field but it hang and i think stuck at a loop and don't show any thing. // readx22.cpp : Defines the entry point for the console application. // #include "stdafx.h" #include "iostream" #include "fstream" #include "stdio.h" using namespace std; class Student { public: string id; size_t id_len; string first_name; size_t first_len; string last_name; size_t last_len; string phone; size_t phone_len; string grade; size_t grade_len; void read(fstream &ven); void print(); }; void Student::read(fstream &ven) { size_t cnt; ven >> cnt; id_len=cnt; id.reserve( cnt ); while ( -- cnt ) { id.push_back( ven.get() ); } ven >> cnt; first_len=cnt; first_name.reserve( cnt ); while ( -- cnt ) { first_name.push_back( ven.get() ); } ven >> cnt; last_len=cnt; last_name.reserve( cnt ); while ( -- cnt ) { last_name.push_back( ven.get() ); } ven >> cnt; phone_len=cnt; phone.reserve( cnt ); while ( -- cnt ) { phone.push_back( ven.get() ); } ven >> cnt; grade_len=cnt; grade.reserve( cnt ); while ( -- cnt ) { grade.push_back( ven.get() ); } } void Student::print() { // string::iterator it; for ( int i=0 ; i<id_len; i++) cout << id[i]; } int main() { fstream in; in.open ("fee.txt", fstream::in); Student x; x.read(in); x.print(); return 0; } thanks

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  • Storing a NTFS Security Descriptor in C

    - by Doori Bar
    My goal is to store a NTFS Security Descriptor in its identical native state. The purpose is to restore it on-demand. I managed to write the code for that purpose, I was wondering if anybody mind to validate a sample of it? (The for loop represents the way I store the native descriptor) This sample only contains the flag for "OWNER", but my intention is to apply the same method for all of the security descriptor flags. I'm just a beginner, would appreciate the heads up. Thanks, Doori Bar #define _WIN32_WINNT 0x0501 #define WINVER 0x0501 #include <stdio.h> #include <windows.h> #include "accctrl.h" #include "aclapi.h" #include "sddl.h" int main (void) { DWORD lasterror; PSECURITY_DESCRIPTOR PSecurityD1, PSecurityD2; HANDLE hFile; PSID owner; LPTSTR ownerstr; BOOL ownerdefault; int ret = 0; unsigned int i; hFile = CreateFile("c:\\boot.ini", GENERIC_READ | ACCESS_SYSTEM_SECURITY, FILE_SHARE_READ, NULL, OPEN_EXISTING, FILE_FLAG_BACKUP_SEMANTICS, NULL); if (hFile == INVALID_HANDLE_VALUE) { fprintf(stderr,"CreateFile() failed. Error: INVALID_HANDLE_VALUE\n"); return 1; } lasterror = GetSecurityInfo(hFile, SE_FILE_OBJECT, OWNER_SECURITY_INFORMATION , &owner, NULL, NULL, NULL, &PSecurityD1); if (lasterror != ERROR_SUCCESS) { fprintf(stderr,"GetSecurityInfo() failed. Error: %lu;\n", lasterror); ret = 1; goto ret1; } ConvertSidToStringSid(owner,&ownerstr); printf("ownerstr of PSecurityD1: %s\n", ownerstr); /* The for loop represents the way I store the native descriptor */ PSecurityD2 = malloc( GetSecurityDescriptorLength(PSecurityD1) * sizeof(unsigned char) ); for (i=0; i < GetSecurityDescriptorLength(PSecurityD1); i++) ((unsigned char *) PSecurityD2)[i] = ((unsigned char *) PSecurityD1)[i]; if (IsValidSecurityDescriptor(PSecurityD2) == 0) { fprintf(stderr,"IsValidSecurityDescriptor(PSecurityD2) failed.\n"); ret = 2; goto ret2; } if (GetSecurityDescriptorOwner(PSecurityD2,&owner,&ownerdefault) == 0) { fprintf(stderr,"GetSecurityDescriptorOwner() failed."); ret = 2; goto ret2; } ConvertSidToStringSid(owner,&ownerstr); printf("ownerstr of PSecurityD2: %s\n", ownerstr); ret2: free(owner); free(ownerstr); free(PSecurityD1); free(PSecurityD2); ret1: CloseHandle(hFile); return ret; }

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  • Thread feeding other MultiThreading

    - by alaamh
    I see it's easy to open pipe between two process using fork, but how we can passing open pipe to threads. Assume we need to pass out of PROGRAM A to PROGRAM B "may by more than one thread", PROGRAM B send his output to PROGRAM C #include <stdio.h> #include <stdlib.h> #include <pthread.h> struct targ_s { char* reader; }; void *thread1(void *arg) { struct targ_s *targ = (struct targ_s*) arg; int status, fd[2]; pid_t pid; pipe(fd); pid = fork(); if (pid == 0) { int fd = fileno( targ->fd_reader ); dup2(STDIN_FILENO, fd); close(fd[0]); dup2(fd[1], STDOUT_FILENO); close(fd[1]); execvp ("PROGRAM B", NULL); exit(1); } else { close(fd[1]); dup2(fd[0], STDIN_FILENO); close(fd[0]); execl("PROGRAM C", NULL); wait(&status); return NULL; } } int main(void) { FILE *fpipe; char *command = "PROGRAM A"; char buffer[1024]; if (!(fpipe = (FILE*) popen(command, "r"))) { perror("Problems with pipe"); exit(1); } char* outfile = "out.dat"; FILE* f = fopen (outfile, "wb"); int fd = fileno( f ); struct targ_s targ; targ.fd_reader = outfile; pthread_t thid; if (pthread_create(&thid, NULL, thread1, &targ) != 0) { perror("pthread_create() error"); exit(1); } int len; while (read(fpipe, buffer, sizeof (buffer)) != 0) { len = strlen(buffer); write(fd, buffer, len); } pclose(fpipe); return (0); }

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  • mysql timeout - c/C++

    - by user1262876
    Guys i'm facing a problem with this code, the problem is the timeout by timeout i mean the time it takes the program to tell me if the server is connected or not. If i use my localhost i get the answer fast, but when i connect to outside my localhost it takes 50sc - 1.5 min to response and the program frezz until it done. HOw can i fix the frezzing, or make my own timeout, like if still waiting after 50sc, tell me connection failed and stop? please use codes as help, becouse i would understand it better, thanks for any help i get PS: USING MAC #include "mysql.h" #include <stdio.h> #include <stdlib.h> // Other Linker Flags: -lmysqlclient -lm -lz // just going to input the general details and not the port numbers struct connection_details { char *server; char *user; char *password; char *database; }; MYSQL* mysql_connection_setup(struct connection_details mysql_details) { // first of all create a mysql instance and initialize the variables within MYSQL *connection = mysql_init(NULL); // connect to the database with the details attached. if (!mysql_real_connect(connection,mysql_details.server, mysql_details.user, mysql_details.password, mysql_details.database, 0, NULL, 0)) { printf("Conection error : %s\n", mysql_error(connection)); exit(1); } return connection; } MYSQL_RES* mysql_perform_query(MYSQL *connection, char *sql_query) { // send the query to the database if (mysql_query(connection, sql_query)) { printf("MySQL query error : %s\n", mysql_error(connection)); exit(1); } return mysql_use_result(connection); } int main() { MYSQL *conn; // the connection MYSQL_RES *res; // the results MYSQL_ROW row; // the results row (line by line) struct connection_details mysqlD; mysqlD.server = (char*)"Localhost"; // where the mysql database is mysqlD.user = (char*)"root"; // the root user of mysql mysqlD.password = (char*)"123456"; // the password of the root user in mysql mysqlD.database = (char*)"test"; // the databse to pick // connect to the mysql database conn = mysql_connection_setup(mysqlD); // assign the results return to the MYSQL_RES pointer res = mysql_perform_query(conn, (char*) "SELECT * FROM me"); printf("MySQL Tables in mysql database:\n"); while ((row = mysql_fetch_row(res)) !=NULL) printf("%s - %s\n", row[0], row[1], row[2]); // <-- Rows /* clean up the database result set */ mysql_free_result(res); /* clean up the database link */ mysql_close(conn); return 0; }

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  • C Named pipe (fifo). Parent process gets stuck

    - by Blitzkr1eg
    I want to make a simple program, that fork, and the child writes into the named pipe and the parent reads and displays from the named pipe. The problem is that it enters the parent, does the first printf and then it gets weird, it doesn't do anything else, does not get to the second printf, it just ways for input in the console. #include <string.h> #include <stdlib.h> #include <stdio.h> #include <unistd.h> #include <sys/types.h> #include <sys/stat.h> #include <fcntl.h> void main() { char t[100]; mkfifo("myfifo",777); pid_t pid; pid = fork(); if (pid==0) { //execl("fifo2","fifo2",(char*)0); char r[100]; printf("scrie2->"); scanf("%s",r); int fp; fp = open("myfifo",O_WRONLY); write(fp,r,99); close(fp); printf("exit kid \n"); exit(0); } else { wait(0); printf("entered parent \n"); // <- this it prints // whats below this line apparently its not being executed int fz; printf("1"); fz = open("myfifo",O_RDONLY); printf("2"); printf("fd: %d",fz); char p[100]; int size; printf("------"); //struct stat *info; //stat("myfifo",info); printf("%d",(*info).st_size); read(fz,p,99); close(fz); printf("%s",p); printf("exit"); exit(0); } }

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  • Illegal Instruction When Programming C++ on Linux

    - by remagen
    Heyo, My program, which does exactly the same thing every time it runs (moves a point sprite into the distance) will randomly fail with the text on the terminal 'Illegal Instruction'. My googling has found people encountering this when writing assembly which makes sense because assembly throws those kinds of errors. But why would g++ be generating an illegal instruction like this? It's not like I'm compiling for Windows then running on Linux (which even then, as long as both are on x86 shouldn't AFAIK cause an Illegal Instruction). I'll post the main file below. I can't reliably reproduce the error. Although, if I make random changes (add a space here, change a constant there) that force a recompile I can get a binary which will fail with Illegal Instruction every time it is run, until I try setting a break point, which makes the illegal instruction 'dissapear'. :( #include <stdio.h> #include <stdlib.h> #include <GL/gl.h> #include <GL/glu.h> #include <SDL/SDL.h> #include "Screen.h" //Simple SDL wrapper #include "Textures.h" //Simple OpenGL texture wrapper #include "PointSprites.h" //Simple point sprites wrapper double counter = 0; /* Here goes our drawing code */ int drawGLScene() { /* These are to calculate our fps */ static GLint T0 = 0; static GLint Frames = 0; /* Move Left 1.5 Units And Into The Screen 6.0 */ glLoadIdentity(); glTranslatef(0.0f, 0.0f, -6); glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT | GL_STENCIL_BUFFER_BIT); glEnable(GL_POINT_SPRITE_ARB); glTexEnvi(GL_POINT_SPRITE, GL_COORD_REPLACE, GL_TRUE); glBegin( GL_POINTS ); /* Drawing Using Triangles */ glVertex3d(0.0,0.0, 0); glVertex3d(1.0,0.0, 0); glVertex3d(1.0,1.0, counter); glVertex3d(0.0,1.0, 0); glEnd( ); /* Finished Drawing The Triangle */ /* Move Right 3 Units */ /* Draw it to the screen */ SDL_GL_SwapBuffers( ); /* Gather our frames per second */ Frames++; { GLint t = SDL_GetTicks(); if (t - T0 >= 50) { GLfloat seconds = (t - T0) / 1000.0; GLfloat fps = Frames / seconds; printf("%d frames in %g seconds = %g FPS\n", Frames, seconds, fps); T0 = t; Frames = 0; counter -= .1; } } return 1; } GLuint objectID; int main( int argc, char **argv ) { Screen screen; screen.init(); screen.resize(800,600); LoadBMP("./dist/Debug/GNU-Linux-x86/particle.bmp"); InitPointSprites(); while(true){drawGLScene();} }

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  • please help me to find Bug in my Code (segmentation fault)

    - by Vikramaditya Battina
    i am tring to solve this http://www.spoj.com/problems/LEXISORT/ question it working fine in visual studio compiler and IDEone also but when i running in SPOJ compiler it is getting SEGSIGV error Here my code goes #include<stdio.h> #include<stdlib.h> #include<string.h> char *getString(); void lexisort(char **str,int num); void countsort(char **str,int i,int num); int main() { int num_test; int num_strings; char **str; int i,j; scanf("%d",&num_test); for(i=0;i<num_test;i++) { scanf("%d",&num_strings); str=(char **)malloc(sizeof(char *)*num_strings); for(j=0;j<num_strings;j++) { str[j]=(char *)malloc(sizeof(char)*11); scanf("%s",str[j]); } lexisort(str,num_strings); for(j=0;j<num_strings;j++) { printf("%s\n",str[j]); free(str[j]); } free(str); } return 0; } void lexisort(char **str,int num) { int i; for(i=9;i>=0;i--) { countsort(str,i,num); } } void countsort(char **str,int i,int num) { int buff[52]={0,0},k,x; char **temp=(char **)malloc(sizeof(char *)*num); for(k=0;k<52;k++) { buff[k]=0; } for(k=0;k<num;k++) { if(str[k][i]>='A' && str[k][i]<='Z') { buff[(str[k][i]-'A')]++; } else { buff[26+(str[k][i]-'a')]++; } } for(k=1;k<52;k++) { buff[k]=buff[k]+buff[k-1]; } for(k=num-1;k>=0;k--) { if(str[k][i]>='A' && str[k][i]<='Z') { x=buff[(str[k][i]-'A')]; temp[x-1]=str[k]; buff[(str[k][i]-'A')]--; } else { x=buff[26+(str[k][i]-'a')]; temp[x-1]=str[k]; buff[26+(str[k][i]-'a')]--; } } for(k=0;k<num;k++) { str[k]=temp[k]; } free(temp); }

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  • Counting number of searches

    - by shinjuo
    I am trying to figure out how to get the total number of tests each search makes in this algorithm. I am not sure how I can pass that information back from this algorithm though. I need to count how many times while runs and then pass that number back into an array to be added together and determine the average number of test. main.c #include <stdio.h> #include <stdlib.h> #include <time.h> #include <stdbool.h> #include "percentage.h" #include "sequentialSearch.h" #define searchAmount 100 int main(int argc, char *argv[]) { int numbers[100]; int searches[searchAmount]; int i; int where; int searchSuccess; int searchUnsuccess; int percent; srand(time(NULL)); for (i = 0; i < 100; i++){ numbers[i] = rand() % 200; } for (i = 0; i < searchAmount; i++){ searches[i] = rand() % 200; } searchUnsuccess = 0; searchSuccess = 0; for(i = 0; i < searchAmount; i++){ if(seqSearch(numbers, 100, searches[i], &where)){ searchSuccess++; }else{ searchUnsuccess++; } } percent = percentRate(searchSuccess, searchAmount); printf("Total number of searches: %d\n", searchAmount); printf("Total successful searches: %d\n", searchSuccess); printf("Success Rate: %d%%\n", percent); system("PAUSE"); return 0; } sequentialSearch.h bool seqSearch (int list[], int last, int target, int* locn){ int looker; looker = 0; while(looker < last && target != list[looker]){ looker++; } *locn = looker; return(target == list[looker]); }

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  • [c++] upload image to imageshack

    - by cinek1lol
    Hi. I would like to send pictures via a program written in C + + I wrote such a thing using curl.exe WinExec("C:\\curl\\curl.exe -H Expect: -F \"fileupload=@C:\\curl\\ok.jpg\" -F \"xml=yes\" -# \"http://www.imageshack.us/index.php\" -o data.txt -A \"Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.1) Gecko/20061204 Firefox/2.0.0.1\" -e \"http://www.imageshack.us\"", NULL); This only works that I would like to send pictures to a variable pre-loaded char (you know what I mean? first reads the pictures into a variable and then send that variable), because now I have to specify the path to the images on disk I wanted to make this program was written in C + + using the curl library, and not the exe. I found it such a program (which some have modified) #include <stdio.h> #include <string.h> #include <iostream> #include <curl/curl.h> #include <curl/types.h> #include <curl/easy.h> int main(int argc, char *argv[]) { CURL *curl; CURLcode res; struct curl_httppost *formpost=NULL; struct curl_httppost *lastptr=NULL; struct curl_slist *headerlist=NULL; static const char buf[] = "Expect:"; curl_global_init(CURL_GLOBAL_ALL); /* Fill in the file upload field */ curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "send", CURLFORM_FILE, "nowy.jpg", CURLFORM_END); curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "nowy.jpg", CURLFORM_COPYCONTENTS, "nowy.jpg", CURLFORM_END); curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "submit", CURLFORM_COPYCONTENTS, "send", CURLFORM_END); curl = curl_easy_init(); headerlist = curl_slist_append(headerlist, buf); if(curl) { curl_easy_setopt(curl, CURLOPT_URL, "http://www.imageshack.us/index.php"); if ( (argc == 2) && (!strcmp(argv[1], "xml=yes")) ) curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headerlist); curl_easy_setopt(curl, CURLOPT_HTTPPOST, formpost); res = curl_easy_perform(curl); curl_easy_cleanup(curl); curl_formfree(formpost); curl_slist_free_all (headerlist); } system("pause"); return 0; } I will be grateful for any help

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  • What is user gcc's purpose in requesting code possibly like this?

    - by James Morris
    In the question between syntax, are there any equal function the user gcc is requesting only what I can imagine to be the following code: #include <stdio.h> #include <string.h> /* estimated magic values */ #define MAXFUNCS 8 #define MAXFUNCLEN 3 int the_mainp_compare_func(char** mainp) { char mainp0[MAXFUNCS][MAXFUNCLEN] = { 0 }; char mainp1[MAXFUNCS][MAXFUNCLEN] = { 0 }; char* psrc, *pdst; int i = 0; int func = 0; psrc = mainp[0]; printf("scanning mainp[0] for functions...\n"); while(*psrc) { if (*psrc == '\0') break; else if (*psrc == ',') ++psrc; else { mainp0[func][0] = *psrc++; if (*psrc == ',') { mainp0[func][1] = '\0'; psrc++; } else if (*psrc !='\0') { mainp0[func][1] = *psrc++; mainp0[func][2] = '\0'; } printf("function: '%s'\n", mainp0[func]); } ++func; } printf("\nscanning mainp[1] for functions...\n"); psrc = mainp[1]; func = 0; while(*psrc) { if (*psrc == '\0') break; else if (*psrc == ',') ++psrc; else { mainp1[func][0] = *psrc++; if (*psrc == ',') { mainp1[func][1] = '\0'; psrc++; } else if (*psrc !='\0') { mainp1[func][1] = *psrc++; mainp1[func][2] = '\0'; } printf("function: '%s'\n", mainp1[func]); } ++func; } printf("\ncomparing functions in '%s' with those in '%s'\n", mainp[0], mainp[1] ); int func2; func = 0; while (*mainp0[func] != '\0') { func2 = 0; while(*mainp1[func2] != '\0') { printf("comparing %s with %s\n", mainp0[func], mainp1[func2]); if (strcmp(mainp0[func], mainp1[func2++]) == 0) return 1; /* not sure what to return here */ } ++func; } /* no matches == failure */ return -1; /* not sure what to return on failure */ } int main(int argc, char** argv) { char* mainp[] = { "P,-Q,Q,-R", "R,A,P,B,F" }; if (the_mainp_compare_func(mainp) == 1) printf("a match was found, but I don't know what to do with it!\n"); else printf("no match found, and I'm none the wiser!\n"); return 0; } My question is, what is it's purpose?

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  • execl doesn't work in a while(1) cicle, server side; C script

    - by Possa
    Hi guys, I have a problem with a little C script who should run as a server and launch a popup for every message arriving. The execl syntax is correct because if I try a little script with main() { execl(...); } it works. When I put it in a while(1) cicle it doesn't work. Everything else is working, like printf or string operation, but not the execl. Even if I fork it doesn't work. I really don't know what I can do ... can anyone help me? Thanks in advice for your help and sorry for my bad english. Here's the complete server C code. #include <arpa/inet.h> #include <netinet/in.h> #include <stdio.h> #include <stdlib.h> #include <sys/types.h> #include <sys/socket.h> #include <unistd.h> #include <string.h> #define BUFLEN 512 #define PORT 9930 void diep(char *s) { perror(s); exit(1); } int main() { struct sockaddr_in si_me, si_other; int s, i, slen=sizeof(si_other), broadcastPermission; char buf[100], zeni[BUFLEN]; if ((s=socket(AF_INET, SOCK_DGRAM, IPPROTO_UDP))==-1) diep("socket"); broadcastPermission = 1; if (setsockopt(s, SOL_SOCKET, SO_BROADCAST, (void *) &broadcastPermission, sizeof(broadcastPermission)) < 0) diep("setsockopt() failed"); memset((char *) &si_me, 0, sizeof(si_me)); si_me.sin_family = AF_INET; si_me.sin_port = htons(PORT); si_me.sin_addr.s_addr = htonl(INADDR_ANY); if (bind(s, &si_me, sizeof(si_me))==-1) diep("bind"); while (1) { if (recvfrom(s, buf, BUFLEN, 0, &si_other, &slen)==-1) diep("recvfrom()"); //printf("Received packet from %s:%d\nData: %s\n", inet_ntoa(si_other.sin_addr), ntohs(si_other.sin_port), buf); strcpy(zeni, ""); strcat(zeni, "zenity --warning --title Hack!! --text "); strcat(zeni, buf); printf("cmd: %s\n", zeni); //system (zeni); execl("/usr/bin/zenity", "/usr/bin/zenity", "--warning", "--title", "Warn!", "--text", buf, (char *) NULL); } close(s); return 0; }

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  • get return value from 2 threads in C

    - by polslinux
    #include <stdio.h> #include <stdlib.h> #include <pthread.h> #include <stdint.h> #include <inttypes.h> typedef struct tmp_num{ int tmp_1; int tmp_2; }t_num; t_num t_nums; void *num_mezzo_1(void *num_orig); void *num_mezzo_2(void *num_orig); int main(int argc, char *argv[]){ pthread_t thread1, thread2; int tmp=0,rc1,rc2,num; num=atoi(argv[1]); if(num <= 3){ printf("Questo è un numero primo: %d\n", num); exit(0); } if( (rc1=pthread_create( &thread1, NULL, &num_mezzo_1, (void *)&num)) ){ printf("Creazione del thread fallita: %d\n", rc1); exit(1); } if( (rc2=pthread_create( &thread2, NULL, &num_mezzo_2, (void *)&num)) ){ printf("Creazione del thread fallita: %d\n", rc2); exit(1); } t_nums.tmp_1 = 0; t_nums.tmp_2 = 0; pthread_join(thread1, (void **)(&t_nums.tmp_1)); pthread_join(thread2, (void **)(&t_nums.tmp_2)); tmp=t_nums.tmp_1+t_nums.tmp_2; printf("%d %d %d\n", tmp, t_nums.tmp_1, t_nums.tmp_2); if(tmp>2){ printf("Questo NON è un numero primo: %d\n", num); } else{ printf("Questo è un numero primo: %d\n", num); } exit(0); } void *num_mezzo_1(void *num_orig){ int cont_1; int *n_orig=(int *)num_orig; t_nums.tmp_1 = 0; for(cont_1=1; cont_1<=(*n_orig/2); cont_1++){ if((*n_orig % cont_1) == 0){ (t_nums.tmp_1)++; } } pthread_exit((void *)(&t_nums.tmp_1)); return NULL; } void *num_mezzo_2(void *num_orig){ int cont_2; int *n_orig=(int *)num_orig; t_nums.tmp_2 = 0; for(cont_2=((*n_orig/2)+1); cont_2<=*n_orig; cont_2++){ if((*n_orig % cont_2) == 0){ (t_nums.tmp_2)++; } } pthread_exit((void *)(&t_nums.tmp_2)); return NULL; } How this program works: i have to input a number and this program will calculate if it is a prime number or not (i know that it is a bad algorithm but i only need to learn pthread). The problem is that the returned values are too much big.For example if i write "12" the value of tmp tmp_1 tmp_2 into the main are 12590412 6295204 6295208.Why i got those numbers??

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  • Learning C, would appreciate input on why this solution works.

    - by Keifer
    This is literally the first thing I've ever written in C, so please feel free to point out all it's flaws. :) My issue, however is this: if I write the program the way I feel is cleanest, I get a broken program: #include <sys/queue.h> #include <stdlib.h> #include <stdio.h> #include <string.h> /* Removed prototypes and non related code for brevity */ int main() { char *cmd = NULL; unsigned int acct = 0; int amount = 0; int done = 0; while (done==0) { scanf ("%s %u %i", cmd, &acct, &amount); if (strcmp (cmd, "exit") == 0) done = 1; else if ((strcmp (cmd, "dep") == 0) || (strcmp (cmd, "deb") == 0)) debit (acct, amount); else if ((strcmp (cmd, "wd") == 0) || (strcmp (cmd, "cred") == 0)) credit (acct, amount); else if (strcmp (cmd, "fee") == 0) service_fee(acct, amount); else printf("Invalid input!\n"); } return(0); } void credit(unsigned int acct, int amount) { } void debit(unsigned int acct, int amount) { } void service_fee(unsigned int acct, int amount) { } As it stands, the above generates no errors at compile, but gives me a segfault when ran. I can fix this by changing the program to pass cmd by reference when calling scanf and strcmp. The segfault goes away and is replaced by warnings for each use of strcmp at compile time. Despite the warnings, the affected code works. warning: passing arg 1 of 'strcmp' from incompatible pointer type As an added bonus, modifying the scanf and strcmp calls allows the program to progress far enough to execute return(0), at which point the thing crashes with an Abort trap. If I swap out return(0) for exit(0) then everything works as expected. This leaves me with two questions: why was the original program wrong? How can I fix it better than I have? The bit about needing to use exit instead of return has me especially baffled.

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  • Returning and printing string array index in C

    - by user1781966
    I've got a function that searches through a list of names and I'm trying to get the search function to return the index of the array back to the main function and print out the starting location of the name found. Everything I've tried up to this point either crashes the program or results in strange output. Here is my search function: #include<stdio.h> #include<conio.h> #include<string.h> #define MAX_NAMELENGTH 10 #define MAX_NAMES 5 void initialize(char names[MAX_NAMES][MAX_NAMELENGTH], int Number_entrys, int i); int search(char names[MAX_NAMES][MAX_NAMELENGTH], int Number_entrys); int main() { char names[MAX_NAMES][MAX_NAMELENGTH]; int i, Number_entrys,search_result,x; printf("How many names would you like to enter to the list?\n"); scanf("%d",&Number_entrys); initialize(names,Number_entrys,i); search_result= search(names,Number_entrys); if (search_result==-1){ printf("Found no names.\n"); }else { printf("%s",search_result); } getch(); return 0; } void initialize(char names[MAX_NAMES][MAX_NAMELENGTH],int Number_entrys,int i) { if(Number_entrys>MAX_NAMES){ printf("Please choose a smaller entry\n"); }else{ for (i=0; i<Number_entrys;i++){ scanf("%s",names[i]); } } } int search(char names[MAX_NAMES][MAX_NAMELENGTH],int Number_entrys) { int x; char new_name[MAX_NAMELENGTH]; printf("Now enter a name in which you would like to search the list for\n"); scanf("%s",new_name); for(x = 0; x < Number_entrys; x++) { if ( strcmp( new_name, names[x] ) == 0 ) { return x; } } return -1; } Like I mentioned before I have tried a lot of different ways to try and fix this issue, but I cant seem to get them to work. Printing X like what I have above is just the last thing I tried, and therefor know that it doesn't work. Any suggestions on the simplest way to do this?

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  • Can a process have two pid's?

    - by limp_chimp
    I'm studying computer systems and I've made this very simple function which uses fork() to create a child process. fork() returns a pid_t that is 0 if it's a child process. But calling the getpid() function within this child process returns a different, nonzero pid. In the code I have below, is newPid only meaningful in the context of the program, and not to the operating system? Is it possibly only a relative value, measured against the pid of the parent? #include <stdio.h> #include <unistd.h> #include <sys/types.h> #include <string.h> #include <errno.h> #include <stdlib.h> void unixError(char* msg) { printf("%s: %s\n", msg, strerror(errno)); exit(0); } pid_t Fork() { pid_t pid; if ((pid = fork()) < 0) unixError("Fork error"); return pid; } int main(int argc, const char * argv[]) { pid_t thisPid, parentPid, newPid; int count = 0; thisPid = getpid(); parentPid = getppid(); printf("thisPid = %d, parent pid = %d\n", thisPid, parentPid); if ((newPid = Fork()) == 0) { count++; printf("I am teh child. My pid is %d, my other pid is %d\n", getpid(), newPid); exit(0); } printf("I am the parent. My pid is %d\n", thisPid); return 0; } Output: thisPid = 30050, parent pid = 30049 I am the parent. My pid is 30050 I am teh child. My pid is 30052, my other pid is 0 Lastly, why is the child's pid 2 higher than the parent's, and not 1? The difference between the main function's pid and its parent is 1, but when we create a child it increments the pid by 2. Why is that?

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  • How do you return a string from a function correctly in Dynamic C?

    - by aquanar
    I have a program I am trying to debug, but Dynamic C apparently treats strings differently than normal C does (well, character arrays, anyway). I have a function that I made to make an 8 character long (well, 10 to include the \0 ) string of 0s and 1s to show me the contents of an 8-bit char variable. (IE, I give it the number 13, it returns the string "0001101\0" ) When I use the code below, it prints out !{happy face] 6 times (well, the second one is the happy face alone for some reason), each return comes back as 0xDEAE or "!\x02. I thought it would dereference it and return the appropriate string, but it appears to just be sending the pointer and attempting to parse it. This may seem silly, but my experience was actually in C++ and Java, so going back to C brings up a few issues that were dealt with in later programming languages that I'm not entirely sure how to deal with (like the lack of string variables). How could I fix this code, or how would be a better way to do what I am trying to do (I thought maybe sending in a pointer to a character array and working on it from the function might work, but I thought I should ask to see if maybe I'm just trying to reinvent the wheel). Currently I have it set up like this: this is an excerpt from the main() display[0] = '\0'; for(i=0;i<6;i++) { sprintf(s, "%s ", *char_to_bits(buffer[i])); strcat(display, s); } DispStr(8,5, display); and this is the offending function: char *char_to_bits(char x) { char bits[16]; strcpy(bits,"00000000\0"); if (x & 0x01) bits[7]='1'; if (x & 0x02) bits[6]='1'; if (x & 0x04) bits[5]='1'; if (x & 0x08) bits[4]='1'; if (x & 0x10) bits[3]='1'; if (x & 0x20) bits[2]='1'; if (x & 0x40) bits[1]='1'; if (x & 0x80) bits[0]='1'; return bits; } and just for the sake of completion, the other function is used to output to the stdio window at a specific location: void DispStr(int x, int y, char *s) { x += 0x20; y += 0x20; printf ("\x1B=%c%c%s", x, y, s); }

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  • Flex, continuous scanning stream (from socket). Did I miss something using yywrap()?

    - by Diederich Kroeske
    Working on a socketbased scanner (continuous stream) using Flex for pattern recognition. Flex doesn't find a match that overlaps 'array bounderies'. So I implemented yywrap() to setup new array content as soon yylex() detects < (it will call yywrap). No success so far. Basically (for pin-pointing my problem) this is my code: %{ #include <stdio.h> #include <string.h> #include <stdlib.h> #define BUFFERSIZE 26 /* 0123456789012345678901234 */ char cbuf1[BUFFERSIZE] = "Hello everybody, lex is su"; // Warning, no '\0' char cbuf2[BUFFERSIZE] = "per cool. Thanks! "; char recvBuffer[BUFFERSIZE]; int packetCnt = 0; YY_BUFFER_STATE bufferState1, bufferState2; %} %option nounput %option noinput %% "super" { ECHO; } . { printf( "%c", yytext[0] );} %% int yywrap() { int retval = 1; printf(">> yywrap()\n"); if( packetCnt <= 0 ) // Stop after 2 { // Copy cbuf2 into recvBuffer memcpy(recvBuffer, cbuf2, BUFFERSIZE); // yyrestart(NULL); // ?? has no effect // Feed new data to flex bufferState2 = yy_scan_bytes(recvBuffer, BUFFERSIZE); // packetCnt++; // Tell flex to resume scanning retval = 0; } return(retval); } int main(void) { printf("Lenght: %d\n", (int)sizeof(recvBuffer)) ; // Copy cbuf1 into recvBuffer memcpy(recvBuffer, cbuf1, BUFFERSIZE); // packetCnt = 0; // bufferState1 = yy_scan_bytes(recvBuffer, BUFFERSIZE); // yylex(); yy_delete_buffer(bufferState1); yy_delete_buffer(bufferState2); return 0; } This is my output: dkmbpro:test dkroeske$ ./text Lenght: 26 Hello everybody, lex is su>> yywrap() per cool. Thanks! >> yywrap() So no match on 'super'. According to the doc the lexxer is not 'reset' between yywrap's. What do I miss? Thanks.

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  • if non zero elements in same column count only once

    - by George
    I want to check the elements above the main diagonal and if I found non zero values , count one. If the non zero values are found in the same column ,then count just one ,not the number of the non zero values. For example , it should be count = 2 and not 3 in this example because 12 and 6 are in the same column. A= 1 11 12 4 5 6 0 7 0 #include <stdio.h> #include <stdlib.h> #include <math.h> int main( int argc, const char* argv[] ){ int Rows = 3 , Cols = 3; float *A = (float *) malloc ( Rows * Cols * sizeof (float) ); A[0] = 1.0; A[1] = 11.0; A[2] = 12.0; A[3] = 4.0; A[4] = 5.0; A[5] = 6.0; A[6] = 0.0; A[7] = 7.0; A[8] = 0.0; // print input matrix printf("\n Input matrix \n\n"); for ( int i = 0; i < Rows; i++ ) for ( int j = 0; j < Cols; j++ ) { printf("%f\t",A[ i * Cols + j ]); if( j == Cols-1 ) printf("\n"); } printf("\n"); int count = 0; for ( int j = 0 ; j < Cols; j++ ) { for ( int i = ( Rows - 1 ); i >= 0; i-- ) { // check the diagonal elements above the main diagonal if ( j > i ) { if ( ( A[ i * Cols + j ] != 0 ) ) { printf("\n Above nonzero Elmts = %f\n",( A[i * Cols + j] ) ); count++; } } } } printf("\ncount = %d\n",count ); return 0; }

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  • can't read from stream until child exits?

    - by BobTurbo
    OK I have a program that creates two pipes - forks - the child's stdin and stdout are redirected to one end of each pipe - the parent is connected to the other ends of the pipes and tries to read the stream associated with the child's output and print it to the screen (and I will also make it write to the input of the child eventually). The problem is, when the parent tries to fgets the child's output stream, it just stalls and waits until the child dies to fgets and then print the output. If the child doesn't exit, it just waits forever. What is going on? I thought that maybe fgets would block until SOMETHING was in the stream, but not block all the way until the child gives up its file descriptors. Here is the code: #include <stdlib.h> #include <stdio.h> #include <string.h> #include <sys/types.h> #include <unistd.h> int main(int argc, char *argv[]) { FILE* fpin; FILE* fpout; int input_fd[2]; int output_fd[2]; pid_t pid; int status; char input[100]; char output[100]; char *args[] = {"/somepath/someprogram", NULL}; fgets(input, 100, stdin); // the user inputs the program name to exec pipe(input_fd); pipe(output_fd); pid = fork(); if (pid == 0) { close(input_fd[1]); close(output_fd[0]); dup2(input_fd[0], 0); dup2(output_fd[1], 1); input[strlen(input)-1] = '\0'; execvp(input, args); } else { close(input_fd[0]); close(output_fd[1]); fpin = fdopen(input_fd[1], "w"); fpout = fdopen(output_fd[0], "r"); while(!feof(fpout)) { fgets(output, 100, fpout); printf("output: %s\n", output); } } return 0; }

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  • C++ STL make_heap and pop_heap not working.

    - by Henrique
    I need to use a Heap, so i've searched about the STL one, but it doesn't seem to work, i wrote some code to explain what i mean: #include <stdio.h> #include <stdlib.h> #include <vector> #include <algorithm> struct data { int indice; int tamanho; }; bool comparator2(const data* a, const data* b) { return (a->tamanho < b->tamanho); } int main() { std::vector<data*> mesas; data x1, x2, x3, x4, x5; x1.indice = 1; x1.tamanho = 3; x2.indice = 2; x2.tamanho = 5; x3.indice = 3; x3.tamanho = 2; x4.indice = 4; x4.tamanho = 6; x5.indice = 5; x5.tamanho = 4; mesas.push_back(&x1); mesas.push_back(&x2); mesas.push_back(&x3); mesas.push_back(&x4); mesas.push_back(&x5); make_heap(mesas.begin(), mesas.end(), comparator2); for(int i = 0 ; i < 5 ; i++) { data* mesa = mesas.front(); pop_heap(mesas.begin(),mesas.end()); mesas.pop_back(); printf("%d, %d\n", mesa->indice, mesa->tamanho); } return 0; }; and this is what i get: 4, 6 2, 5 1, 3 3, 2 5, 4 So it's not working as a heap, as the maximum element on the vector is not being returned right. Or am i doing something wrong?

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