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  • How to use double buffering inside a thread and applet

    - by russell
    I have a question about when paint and update method is called?? i have game applet where i want to use double buffering.But i cant use it.the problem is In my game there is a ball which is moving inside run() method.I want to know how to use double buffering to swap the offscreen image and current image.Someone plz help. And when there is both update() and paint() method.which are called first,when and why ???

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  • Problem in converting ToDictionary<Datetime,double>() using LINQ(C#3.0)

    - by Newbie
    I have written the below return (from p in returnObject.Portfolios.ToList() from childData in p.ChildData.ToList() from retuns in p.Returns.ToList() select new Dictionary<DateTime, double> () { p.EndDate, retuns.Value } ).ToDictionary<DateTime,double>(); Getting error No overload for method 'Add' takes '1' arguments Where I am making the mistake I am using C#3.0 Thanks

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  • roundoff double values in Java

    - by S.PRATHIBA
    Hi all, I have a matrix.I found the 10th power of matrix using Java.After finding the 10th power,I need to round off the double values to 3 decimal places.Please help me to round off the double values in the matrix to 3 decimal places.

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  • Python: inserting double or single quotes around a string

    - by Jessy
    Im using python to access a MySQL database and im getting a unknown column in field due to quotes not being around the variable. code below: cur = x.cnx.cursor() cur.execute('insert into tempPDBcode (PDBcode) values (%s);' % (s)) rows = cur.fetchall() How do i manually insert double or single quotes around the value of s? I've trying using str() and manually concatenating quotes around s but it still doesn't work. The sql statement works fine iv double and triple check my sql query.

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  • strange parsing Double behaviour...

    - by Cristian Boariu
    Hi, I have this line of code: return (this.pretWithoutDiscount / Double.Parse(UtilsStatic.getEuroValue())).ToString("N2") + "€"; In debug mode i've tested and the values are: UtilsStatic.getEuroValue() = "4.1878" this.pretWithoutDiscount = 111.0 Can anyone explaing WHY: Double.Parse(UtilsStatic.getEuroValue()) = 41878.0 when it should be 4.1878 ?? Thanks... PS: UtilsStatic.getEuroValue returns a string.

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  • Math.min.apply(0, x) - why?

    - by Trevor Burnham
    I was just digging through some JavaScript code (Raphaël.js) and came across the following line (translated slightly): Math.min.apply(0, x) where x is an array. Why on earth would you do this? The behavior seems to be "take the min from the array x."

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  • double border with no space in between

    - by user330239
    Hi guys, i wanted to make a double border but with no space in between and the double border should be of different color. I tried using image instead but i thought css could probably perform this job for me, i searched the net but hardly find anything close. What i wanted is total of 2px dotted border with top color of #a4a4a4 and bottom color of #474747. Any idea how i can do this instead of creating 2 divs?

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  • client generated double submit cookie, cross site request forgery prevention

    - by james
    in a double-submitted cookie csrf prevention scheme, is it necessary for the server to provide the cookie? it seems i could have javascript on the clients page generate and set a cookie "anti_csrf", then double submit that (once as a cookie, done by the browser, and once in the body of the request). a foreign domain would not be able to read or write the "anti_csrf" cookie to include it in the body of a request. is this secure, or am i overlooking something?

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  • template; Point<2, double>; Point<3, double>

    - by Oops
    Hi, I want to create my own Point struct it is only for purposes of learning C++. I have the following code: template <int dims, typename T> struct Point { T X[dims]; Point(){} Point( T X0, T X1 ) { X[0] = X0; X[1] = X1; } Point( T X0, T X1, T X2 ) { X[0] = X0; X[1] = X1; X[2] = X2; } Point<dims, int> toint() { //how to distinguish between 2D and 3D ??? Point<dims, int> ret = Point<dims, int>( (int)X[0], (int)X[1]); return ret; } std::string str(){ //how to distinguish between 2D and 3D ??? std::stringstream s; s << "{ X0: " << X[0] << " | X1: " << X[1] << " }"; return s.str(); } }; int main(void) { Point<2, double> p2d = Point<2, double>( 12.3, 45.6 ); Point<3, double> p3d = Point<3, double>( 12.3, 45.6, 78.9 ); Point<2, int> p2i = p2d.toint(); //OK Point<3, int> p3i = p3d.toint(); //m??? std::cout << p2d.str() << std::endl; //OK std::cout << p3d.str() << std::endl; //m??? std::cout << p2i.str() << std::endl; //m??? std::cout << p3i.str() << std::endl; //m??? char c; std::cin >> c; return 0; } of couse until now the output is not what I want. my questions is: how to take care of the dimensions of the Point (2D or 3D) in member functions of the Point? many thanks in advance Oops

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  • Problem in converting ToDictionary<Datetime,double>() usinh LINQ(C#3.0)

    - by Newbie
    I have written the below return (from p in returnObject.Portfolios.ToList() from childData in p.ChildData.ToList() from retuns in p.Returns.ToList() select new Dictionary<DateTime, double> () {p.EndDate, retuns.Value }).ToDictionary<DateTime,double>(); Getting error No overload for method 'Add' takes '1' arguments Where I am making the mistake I am using C#3.0 Thanks

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  • C# Int and math not returning full value.

    - by Mike
    Int64 c1 = Convert.ToInt64(csvdeep[1]); Int64 division = 1024; string results = Math.Abs(c1 / division / division / division).ToString(); My c1 is 10201841664 and results is "9". I'd perfer to get the 2nd two decimal places so my real result would be 9.50. Any tips on how I could get the 2 decimal places?

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  • toFixed(2) - math round ?

    - by adrien334
    Hi, I would like to find a function that will return this kind of formatted values : 1.5555 => 1.55 1.5556 => 1.56 1.5554 => 1.55 1.5651 => 1.56 toFixed() and math round return this value : 1.5651.fixedTo(2) => 1.57 This will be usefull for money rounding.

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  • Python and C++ Sockets converting packet data

    - by yeus
    First of all, to clarify my goal: There exist two programs written in C in our laboratory. I am working on a Proxy Server (bidirectional) for them (which will also mainpulate the data). And I want to write that proxy server in Python. It is important to know that I know close to nothing about these two programs, I only know the definition file of the packets. Now: assuming a packet definition in one of the C++ programs reads like this: unsigned char Packet[0x32]; // Packet[Length] int z=0; Packet[0]=0x00; // Spare Packet[1]=0x32; // Length Packet[2]=0x01; // Source Packet[3]=0x02; // Destination Packet[4]=0x01; // ID Packet[5]=0x00; // Spare for(z=0;z<=24;z+=8) { Packet[9-z/8]=((int)(720000+armcontrolpacket->dof0_rot*1000)/(int)pow((double)2,(double)z)); Packet[13-z/8]=((int)(720000+armcontrolpacket->dof0_speed*1000)/(int)pow((double)2,(double)z)); Packet[17-z/8]=((int)(720000+armcontrolpacket->dof1_rot*1000)/(int)pow((double)2,(double)z)); Packet[21-z/8]=((int)(720000+armcontrolpacket->dof1_speed*1000)/(int)pow((double)2,(double)z)); Packet[25-z/8]=((int)(720000+armcontrolpacket->dof2_rot*1000)/(int)pow((double)2,(double)z)); Packet[29-z/8]=((int)(720000+armcontrolpacket->dof2_speed*1000)/(int)pow((double)2,(double)z)); Packet[33-z/8]=((int)(720000+armcontrolpacket->dof3_rot*1000)/(int)pow((double)2,(double)z)); Packet[37-z/8]=((int)(720000+armcontrolpacket->dof3_speed*1000)/(int)pow((double)2,(double)z)); Packet[41-z/8]=((int)(720000+armcontrolpacket->dof4_rot*1000)/(int)pow((double)2,(double)z)); Packet[45-z/8]=((int)(720000+armcontrolpacket->dof4_speed*1000)/(int)pow((double)2,(double)z)); Packet[49-z/8]=((int)armcontrolpacket->timestamp/(int)pow(2.0,(double)z)); } if(SendPacket(sock,(char*)&Packet,sizeof(Packet))) return 1; return 0; What would be the easiest way to receive that data, convert it into a readable python format, manipulate them and send them forward to the receiver?

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  • Windows 2008 R2 remote desktop - Double Login

    - by Zulgrib
    After an Active Directory fail RDP connection started to ask for credentials twice (once on local RDP program, second time on remote's logon screen) I already looked at Windows 2008 R2 RDS - Double Login Solution provided there doesn't work for me. The server is alone, without AD/DNS services, RDP service isn't installed I tried every security settings on RDP-Tcp (RDP, Negotiate, SLL) Logon option is set to "Use credentials from the client" Both windows client and server use RDP 7.1 fPromptForPassword regitries are set to 0 Local Computer Policy\Administrative Templates\Windows Components\Remote Desktop Services\Remote Desktop Session Host\Security\Always prompt for password upon connection is set to "Disabled" Why i am sure the problem comes from the server and not the client ? This problem affected a 3rd RDP program on Android too (it was directly showing "preparing desktop previously, on both MS RDP and the 3rd program) No bakcup are available (Else the Active Directory wouldn't be a fail, but just a lose of time) I am wondering if a rule linked to RDP got changed after the AD install+unistall, but i'm unable to find where. While this is not a critic problem, this is very annoying. I don't know if more information are needed, if it's the case and if you are patient enough, please tell me what is missing and i'll edit this post to add the missing informations.

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  • Windows Displays Double the Actual Installed Physical Memory

    - by Andrew Barber
    I have a server I've installed Windows Web 2008 R2 on, which is reporting that I have double the physical memory installed as is actually the case. In msinfo32 "Installed Physical Memory" shows as 2x what ever the actual installed amount is, though "Total Physical Memory" shows the correct amount. The "System" info window shows installed memory as 2x, with the correct amount in parenthesis listed as the "usable" amount). This server mistakenly had Windows Web 2008 (32-bit) installed on it just previously, and that OS also reported the same faulty information as Win2K8R2 is reporting. BIOS reports the correct amount, memtest was run on this server before installation, and a previous Windows 2000 instance installed on this system also reported the correct amount, as I recall. Server operation seems to be fine as well (it's only trying to use the correct amount of memory). The server is a generic pizzabox running on a SuperMicro X6DVL-EG with dual Xeon-3.2's. Memory installed are 4 matching mt18vddf12872g-335c3 sticks (1GB pc2700 DDR ECC REG cl2.5) This behavior occurs whether two or all four are installed. So, has anyone seen something like this before? Have any idea about what's causing it, and how I should be concerned about it? Everything else seems good so far, and I'll be upgrading the memory before putting the server into service, but I don't want to spend too much time/money/effort on the server if it's got something odd going wrong here. UPDATE: There was a question I ran into regarding memory sparing in the BIOS and a possible (buggy) effect thereof; however, flipping that bit back and forth in the BIOS revealed that isn't the issue. Still flummoxed a bit about this one, though I still have seen no negative impacts. Post-Answer Update (January 13, 2011): Upgrading the system with new, larger memory has fixed this issue.

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  • Raphael JS image animation performance.

    - by michael
    Hi, I'm trying to create an image animation using Raphael JS. I want the effect of a bee moving randomly across the page, I've got a working example but it's a bit "jittery", and I'm getting this warning in the console: "Resource interpreted as image but transferred with MIME type text/html" I'm not sure if the warning is causing the "jittery" movement or its just the way I approached it using maths. If anyone has a better way to create the effect, or improvements please let me know. I have a demo online here and heres my javascript code: function random(min, max) { return Math.floor(Math.random() * (max - min + 1)) + min; } function BEE(x, y, scale) { this.x = x; this.y = y; this.s = scale; this.paper = Raphael("head", 915, 250); this.draw = function() { this.paper.clear(); this.paper.image("bee.png", this.x, this.y, 159*this.s, 217*this.s); } this.update = function() { var deg = random(-25, 25); var newX = Math.cos(Raphael.rad(deg)) * 2; var newY = Math.sin(Raphael.rad(deg)) * 2; this.x += newX; this.y += newY; if( this.x > 915) { this.x = 0; } if( this.y > 250 || this.y < 0 ) { this.y = 125; } } } $(document).ready(function() { var bee = new BEE(100, 150, 0.4); var timer = setInterval(function(){ bee.draw(); bee.update(); }, 15); }

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  • What is the name of this geometrical function?

    - by Spike
    In a two dimentional integer space, you have two points, A and B. This function returns an enumeration of the points in the quadrilateral subset bounded by A and B. A = {1,1} B = {2,3} Fn(A,B) = {{1,1},{1,2},{1,3},{2,1},{2,2},{2,3}} I can implement it in a few lines of LINQ. private void UnknownFunction(Point to, Point from, List<Point> list) { var vectorX = Enumerable.Range(Math.Min(to.X, from.X), Math.Abs(to.X - from.Y) + 1); var vectorY = Enumerable.Range(Math.Min(to.Y, from.Y), Math.Abs(to.Y - from.Y) + 1); foreach (var x in vectorX) foreach (var y in vectorY) list.Add(new Point(x, y)); } I'm fairly sure that this is a standard mathematical operation, but I can't think what it is. Feel free to tell me that it's one line of code in your language of choice. Or to give me a cunning implementation with lambdas or some such. But mostly I just want to know what it's called. It's driving me nuts. It feels a little like a convolution, but it's been too long since I was at school for me to be sure.

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  • How to check if a number is a power of 2

    - by configurator
    Today I needed a simple algorithm for checking if a number is a power of 2. The algorithm needs to be: Simple Correct for any ulong value. I came up with this simple algorithm: private bool IsPowerOfTwo(ulong number) { if (number == 0) return false; for (ulong power = 1; power > 0; power = power << 1) { // this for loop used shifting for powers of 2, meaning // that the value will become 0 after the last shift // (from binary 1000...0000 to 0000...0000) then, the for // loop will break out if (power == number) return true; if (power > number) return false; } return false; } But then I thought, how about checking if log2x is an exactly round number? But when I checked for 2^63+1, Math.Log returned exactly 63 because of rounding. So I checked if 2 to the power 63 is equal to the original number - and it is, because the calculation is done in doubles and not in exact numbers: private bool IsPowerOfTwo_2(ulong number) { double log = Math.Log(number, 2); double pow = Math.Pow(2, Math.Round(log)); return pow == number; } This returned true for the given wrong value: 9223372036854775809. Does anyone have any suggestion for a better algorithm?

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  • How to revert to Eclipse's old behavior when double-clicking on frames or windows, in Juno?

    - by mattquiros
    I find Eclipse Juno very counter-intuitive. In my workspace, I used to just have the package view at the left, my code on the right, and whenever I'm printing something in the console, that's only when the console frame shows up from the bottom right. When you double click on a particular window, it either only goes fullscreen within Eclipse, or back to its original size together with the size of the other frames. In Juno, however, it seems that frames are put on layers on top of each other. When I print something to the console, the output frame only shows up as a small, useless square to my right. When I double-click, it goes full screen. When I double-click again, it occupies the full right frame, hiding my code. I double-click again and it goes full screen, then it double-clicks before it shares the right frame with my code on top of it. Then when I minimize it, it goes to the side. Any way to go back to the good old days of Eclipse? Thanks.

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  • Floating Point Arithmetic - Modulo Operator on Double Type

    - by CrimsonX
    So I'm trying to figure out why the modulo operator is returning such a large unusual value. If I have the code: double result = 1.0d % 0.1d; it will give a result of 0.09999999999999995. I would expect a value of 0 Note this problem doesn't exist using the dividing operator - double result = 1.0d / 0.1d; will give a result of 10.0, meaning that the remainder should be 0. Let me be clear: I'm not surprised that an error exists, I'm surprised that the error is so darn large compared to the numbers at play. 0.0999 ~= 0.1 and 0.1 is on the same order of magnitude as 0.1d and only one order of magnitude away from 1.0d. Its not like you can compare it to a double.epsilon, or say "its equal if its < 0.00001 difference". I've read up on this topic on StackOverflow, in the following posts one two three, amongst others. Can anyone suggest explain why this error is so large? Any any suggestions to avoid running into the problems in the future (I know I could use decimal instead but I'm concerned about the performance of that).

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  • Double null-terminated string

    - by wengseng
    I need to format a string to be double null-terminated string in order to use SHFileOperation. Interesting part is i found one of the following working, but not both: // Example 1 CString szDir(_T("D:\\Test")); szDir = szDir + _T('\0') + _T('\0'); // Example 2 CString szDir(_T("D:\\Test")); szDir = szDir + _T("\0\0"); //Delete folder SHFILEOPSTRUCT fileop; fileop.hwnd = NULL; // no status display fileop.wFunc = FO_DELETE; // delete operation fileop.pFrom = szDir; // source file name as double null terminated string fileop.pTo = NULL; // no destination needed fileop.fFlags = FOF_NOCONFIRMATION|FOF_SILENT; // do not prompt the user fileop.fAnyOperationsAborted = FALSE; fileop.lpszProgressTitle = NULL; fileop.hNameMappings = NULL; int ret = SHFileOperation(&fileop); Does anyone has idea on this? Is there other way to append double-terminated string?

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  • Logic error for Gauss elimination

    - by iwanttoprogram
    Logic error problem with the Gaussian Elimination code...This code was from my Numerical Methods text in 1990's. The code is typed in from the book- not producing correct output... Sample Run: SOLUTION OF SIMULTANEOUS LINEAR EQUATIONS USING GAUSSIAN ELIMINATION This program uses Gaussian Elimination to solve the system Ax = B, where A is the matrix of known coefficients, B is the vector of known constants and x is the column matrix of the unknowns. Number of equations: 3 Enter elements of matrix [A] A(1,1) = 0 A(1,2) = -6 A(1,3) = 9 A(2,1) = 7 A(2,2) = 0 A(2,3) = -5 A(3,1) = 5 A(3,2) = -8 A(3,3) = 6 Enter elements of [b] vector B(1) = -3 B(2) = 3 B(3) = -4 SOLUTION OF SIMULTANEOUS LINEAR EQUATIONS The solution is x(1) = 0.000000 x(2) = -1.#IND00 x(3) = -1.#IND00 Determinant = -1.#IND00 Press any key to continue . . . The code as copied from the text... //Modified Code from C Numerical Methods Text- June 2009 #include <stdio.h> #include <math.h> #define MAXSIZE 20 //function prototype int gauss (double a[][MAXSIZE], double b[], int n, double *det); int main(void) { double a[MAXSIZE][MAXSIZE], b[MAXSIZE], det; int i, j, n, retval; printf("\n \t SOLUTION OF SIMULTANEOUS LINEAR EQUATIONS"); printf("\n \t USING GAUSSIAN ELIMINATION \n"); printf("\n This program uses Gaussian Elimination to solve the"); printf("\n system Ax = B, where A is the matrix of known"); printf("\n coefficients, B is the vector of known constants"); printf("\n and x is the column matrix of the unknowns."); //get number of equations n = 0; while(n <= 0 || n > MAXSIZE) { printf("\n Number of equations: "); scanf ("%d", &n); } //read matrix A printf("\n Enter elements of matrix [A]\n"); for (i = 0; i < n; i++) for (j = 0; j < n; j++) { printf(" A(%d,%d) = ", i + 1, j + 1); scanf("%lf", &a[i][j]); } //read {B} vector printf("\n Enter elements of [b] vector\n"); for (i = 0; i < n; i++) { printf(" B(%d) = ", i + 1); scanf("%lf", &b[i]); } //call Gauss elimination function retval = gauss(a, b, n, &det); //print results if (retval == 0) { printf("\n\t SOLUTION OF SIMULTANEOUS LINEAR EQUATIONS\n"); printf("\n\t The solution is"); for (i = 0; i < n; i++) printf("\n \t x(%d) = %lf", i + 1, b[i]); printf("\n \t Determinant = %lf \n", det); } else printf("\n \t SINGULAR MATRIX \n"); return 0; } /* Solves the system of equations [A]{x} = {B} using */ /* the Gaussian elimination method with partial pivoting. */ /* Parameters: */ /* n - number of equations */ /* a[n][n] - coefficient matrix */ /* b[n] - right-hand side vector */ /* *det - determinant of [A] */ int gauss (double a[][MAXSIZE], double b[], int n, double *det) { double tol, temp, mult; int npivot, i, j, l, k, flag; //initialization *det = 1.0; tol = 1e-30; //initial tolerance value npivot = 0; //mult = 0; //forward elimination for (k = 0; k < n; k++) { //search for max coefficient in pivot row- a[k][k] pivot element for (i = k + 1; i < n; i++) { if (fabs(a[i][k]) > fabs(a[k][k])) { //interchange row with maxium element with pivot row npivot++; for (l = 0; l < n; l++) { temp = a[i][l]; a[i][l] = a[k][l]; a[k][l] = temp; } temp = b[i]; b[i] = b[k]; b[k] = temp; } } //test for singularity if (fabs(a[k][k]) < tol) { //matrix is singular- terminate flag = 1; return flag; } //compute determinant- the product of the pivot elements *det = *det * a[k][k]; //eliminate the coefficients of X(I) for (i = k; i < n; i++) { mult = a[i][k] / a[k][k]; b[i] = b[i] - b[k] * mult; //compute constants for (j = k; j < n; j++) //compute coefficients a[i][j] = a[i][j] - a[k][j] * mult; } } //adjust the sign of the determinant if(npivot % 2 == 1) *det = *det * (-1.0); //backsubstitution b[n] = b[n] / a[n][n]; for(i = n - 1; i > 1; i--) { for(j = n; j > i + 1; j--) b[i] = b[i] - a[i][j] * b[j]; b[i] = b[i] / a[i - 1][i]; } flag = 0; return flag; } The solution should be: 1.058824, 1.823529, 0.882353 with det as -102.000000 Any insight is appreciated...

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