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  • Reversed Latitude/Longitude US Tiger/Line Shape File to MySQL w/ OGR2OGRP

    - by Dave LeJeune
    Hi - I've downloaded the latest set (2010) of TIGER edge shape files (ESRI shapefile format) from the US Census website and am loading them into MySQL using the GDAL ogr2ogr utility. A new table (geotest) does get created with a SHAPE column that has the geometry defined as a LINESTRING. However, I am seeing reversed latitude and longitude values that get reversed when running the following command: ogr2ogr -f "MySQL" MySQL:"geo,user=lejeuned,host=localhost,password=cnickl234" -nln geotest -nlt LINESTRING -append -a_srs "EPSG:4326" -lco engine=MYISAM tl_2010_01021_edges.shp Mapping the latitude/longitude (after reversing them of course) they appear to be spot on so I suspect there is just something I am doing wrong or flag I am missing which is causing the latitude and longitudes to be transposed. When I select the SHAPE column using astext() I get the following result: LINESTRING(-86.69863 32.973164,-86.69853 32.97302,-86.69856 32.97287,-86.698613 32.972825,-86.6988 32.972825,-86.6989 32.972892,-86.6989 32.973002,-86.69874 32.97316,-86.69864 32.97318,-86.69863 32.973164) Any ideas what I am doing wrong?

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  • RoR Devise: Sign in with username OR email

    - by Patrick Oscity
    Whats the best way to enable users to log in with their email address OR their username? I am using warden + devise for authentication. I think it probably won't be too hard to do it but i guess i need some advice here on where to put all the stuff that is needed. Perhaps devise devise already provides this feature? like in the config/initializers/devise.rb you would write: config.authentication_keys = [ :email, :username ] To require both username AND email for signing in. But i really want to have only one field for both username and email and require only one of them. I'll just visualize that with some ASCII art, it should look something like this in the view: Username or Email: [____________________] Password: [____________________] [Sign In]

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  • Amazon AWS s3fs mount problem on Fedora 14

    - by Alex
    I successfully compiled and installed s3fs (http://code.google.com/p/s3fs/) on my Fedora 14 machine. I included the password credentials in /etc/ as specified in the guide. When I run: sudo /usr/bin/s3fs bucket_name /mnt/bucket_name/ it runs successfully. (note: the bucket name is the same as the folder name in /mnt/). When I run ls in /mnt/ I get the error "ls: cannot access bucket_name: Permission denied". When I run sudo chmod 640 /mnt/bucket_name I get "chmod: changing permissions of `bucket_name': Input/output error". When I reboot the machine I can access the folder /mnt/bucket_name normally but it is not mapped to the s3 bucket. So, basically I have two questions. 1) How do I access the folder (/mnt/bucket_name) as usual after I mount it to the s3 bucket and 2) How can I keep it mounted even after machine restart. Regards

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  • Adding LDAP OU using Net::LDAP

    - by lupindeterd
    What is the correct syntax of adding an OU using Net::LDAP, I tried the following: #!/usr/bin/perl -w use 5.10.1; use strict; use Net::LDAP; use Data::Dumper; my $ldap = Net::LDAP->new("192.168.183.2") or die "$@"; my $mesg = $ldap->bind( "cn=admin,dc=lab,dc=net", password => 'xxx' ); $mesg = $ldap->add( "ou=Users,dc=lab,dc=net", attrs => [ 'ou' => 'dc=Users', 'objectClass' => [ 'top', 'organizationalUnit' ] ] ); say $mesg->error; say $mesg->code; And got the following error: value of naming attribute 'ou' is not present in entry 64 However using the ldapmodify command line, and using this following ldif, works: dn: ou=Users,dc=lab,dc=net changetype: add objectclass: top objectclass: organizationalUnit ou: Users

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  • ASIHTTPRequest on www.blau.de?

    - by rdesign
    Hey guys, I need to login here. I've tried the ASIHTTPRequest and ASIFormDataRequest. None of them works as expected. I only got the data from the loginpage in the response string, not the data from the secure area. What am I doing wrong here? ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:[NSURL URLWithString:@"https://www.blau.de/"]]; [request setPostValue:@"USERNAME" forKey:@"quickLoginNumber"]; [request setPostValue:@"PASSWORD" forKey:@"quickLoginPassword"]; [request startAsynchronous];

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  • Mule ESB - How to get MimeMessage instead of MimeBodyPart?

    - by Padmarag
    I'm trying to get the FROM email address in Mule ESB. I'm getting the retrieved object as MimeBodyPart, I'd like to have MimeMessage instead. How to do this? Any solution - either in Mule or Java is welcome. The Mule config part for inbound end-point is as below - <inbound> <pop3s:inbound-endpoint user="xxx%40gmail.com" password="xxx" host="pop.gmail.com"/> </inbound> Thanks in advance.

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  • PHP/GnuPG Decryption -- Syntax error?

    - by NeedBeerStat
    I'm using php to invoke gpg, but I'm getting a pipe error. I thought that if I read in the password from a file, I could then pipe it to the command itself? But, I keep getting: Syntax error: "|" unexpected Here's the code: (Note: The files are being iterated over in a foreach loop...) foreach($files as $k => $v) { $encrypted = $v; $filename = explode('.',$v); $decrypted = $filename[0].'.txt'; shell_exec("echo $passphrase | gpg --no-tty --passphrase-fd 0 -o $decrypted -d $encrypted"); }

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  • Retrieving JSON from a web URL

    - by npeterson
    This may be a terribly uninformed question, brace yourself. A company I'm working with has given an 'API' that I can use to access orders, however, there are only two real commands, getorders and getorderdetails. These commands are put in the format of http://www.server.com/path/to/the/orderapi/getorders/UniqueKey/ If I go to that web address, I'm prompted for a username and password, and once authenticating, get presented with a page of JSON formatted order details, contained in the body of the html page. I would like a service to check this information and create orders in our crm based on it, is there an obvious way to access it without the browser/client interaction?

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  • How do I get the displayname of the logged in user in EWS?

    - by tig
    Exchange Autodiscovery will give me the user's Display Name via the UserSettingName.UserDisplayName property. However, in cases where autodiscovery fails and connection needs to be done manually I can't figure out how to get the DisplayName. I tried this, but I just get the users' email address: _service = new ExchangeService(); _service.Credentials = new System.Net.NetworkCredential(exchangeSettings.EmailAddress, exchangeSettings.Password); _service.Url = new Uri(exchangeSettings.ExternalEwsUrl); NameResolutionCollection resolvedNames = _service.ResolveName(exchangeSettings.EmailAddress); exchangeSettings.UserDisplayName = resolvedNames.First().Mailbox.Name; Thanks

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  • Googles App Engine, Python: How to get parameters from a log-in pages?

    - by brilliant
    Here is a quote from here: So in short ... you need to look into login page, see what params it uses e.g login=xxx, password=yyy, post it to that page and you will have to manage the cookies too, that is where library like twill etc come into picture. How could I do it using Python and Google App Engine? Can anybody please give me some clue? I have already asked a question about the authenticated request, but here it seems the matter is different as here I am suggested to look into login page and get parameters, and also I have to deal with cookies.

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  • AlertDialog Input Text

    - by soclose
    Hi, I'd like to use AlertDialog as a pin code or password dialog. Here is my code - AlertDialog.Builder alert = new AlertDialog.Builder(this); alert.setTitle("Login"); alert.setMessage("Enter Pin :"); // Set an EditText view to get user input final EditText input = new EditText(this); alert.setView(input); alert.setPositiveButton("Ok", new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int whichButton) { String value = input.getText().toString(); Log.d( TAG, "Pin Value : " + value); return; } }); alert.setNegativeButton("Cancel", new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int which) { // TODO Auto-generated method stub return; } }); alert.show(); How to code that all input text will appear like ' * '

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  • How to catch prompts with PySVN?

    - by Geoff
    I'm new to Python and PySVN in general, and I'm trying to export my SVN repository using pysvn. Here's my code: #set up svn login data def svn_credentials (realm, username, may_save): return True, svn_login_name, svn_login_password, False #establish connection svn_client = pysvn.Client () svn_client.callback_get_login = svn_credentials #export data svn_client.export('server-path-goes-here', 'client-path-goes-here', force=True Which works fine, but if the password is wrong or the user name is unknown, this code just sits. I believe it's being presented with a user login prompt on the SVN side, but I'm at a loss as to how to check whats happening with callback_get_login. Any help would be greatly appreciated.

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  • pycurl script can't login to website

    - by The Jug
    I'm currently trying to get a grasp on pycurl. I'm attempting to login to my own website. After logging into the site it should redirect to the main page. However when trying this script it just gets returned to the login page. What might I be doing wrong? import pycurl import urllib import StringIO import pycurl pf = {'username' : 'user', 'password' : 'pass' } fields = urllib.urlencode(pf) pageContents = StringIO.StringIO() p = pycurl.Curl() p.setopt(pycurl.FOLLOWLOCATION, 1) p.setopt(pycurl.COOKIEFILE, './cookie_test.txt') p.setopt(pycurl.COOKIEJAR, './cookie_test.txt') p.setopt(pycurl.POST, 1) p.setopt(pycurl.POSTFIELDS, fields) p.setopt(pycurl.WRITEFUNCTION, pageContents.write) p.setopt(pycurl.URL, 'http://localhost') p.perform() pageContents.seek(0) print pageContents.readlines()

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  • How can I run a command on a remote machine with Perl?

    - by Bharath Kumar
    I'm using following code to connect to a remote machine and try to execute one simple command on remote machine. cat tt.pl #!/usr/bin/perl #use strict; use warnings; use Net::Telnet; $telnet = new Net::Telnet ( Timeout=>2, Errmode=>'die'); $telnet->open('172.168.12.58'); $telnet->waitfor('/login:\s*/'); $telnet->print('admin'); $telnet->waitfor('/password:\s*/'); $telnet->print('Blue'); #$telnet->cmd('ver > C:\\log.txt'); $telnet->cmd('mkdir gy'); You have new mail in /var/spool/mail/root [root@localhost]# But when I'm executing this script it is throwing error messages [root@localhost]# perl tt.pl command timed-out at tt.pl line 12 [root@localhost]# Please help me in this

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  • routing problem in codeigniter

    - by Obay
    I'm new to CodeIgniter and routing. I have a Login controller whose index() loads up a view to enter a username/password. In the view, the form has action="login/authenticate". Login-authenticate() determines if the login is valid or not. If it's valid, redirect('lobby'), if not redirect('login') routes.php: $route['default_controller'] = "login" config.php: $config['base_url'] = "http://localhost/dts/"; $config['index_page'] = "index.php"; The problem is that when i go to http://localhost/dts/ , click login, I am correctly (?) redirected to http://localhost/dts/login/authenticate but the browser says Object not found!. But when I go to http://localhost/dts/index.php/ (with trailing slash), it works correctly (I get redirected to http://localhost/dts/index.php/login/authenticate, and am logged in) I tried removing "index.php" by using a .htaccess: RewriteEngine on RewriteCond $1 !^(index\.php|images|robots\.txt) RewriteRule ^(.*)$ /index.php/$1 [L] and it would no longer open even the http://localhost/dts/ I'm confused.. what's going on?

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  • ASP.NET access files on another computer shared folder

    - by Tomas
    Hello, I have ASP.NET project which do some file access and manipulation, the methods which I use for file access are below. Now I need to access files on another server shared folder, how to do that? I easily can change file path to shared folder path but I get "can't access" error because shares are password protected. As I understand I need somehow to send credentials to remote server before executing methods below. How to do that? FileStream("c:\MyProj\file.doc", FileMode.OpenOrCreate, FileAccess.Write) Context.Response.TransmitFile("c:\MyProj\file.doc"); Regards, Tomas

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  • Need help with ConnectionString value in C#

    - by SzamDev
    Hi I have an idea and I want to apply it to my Application (C# .NET). When we connect to a DB (MS SQL Server 2008) in VS 2008, the ConnectionString saved in the Application Setting and it's a static varriable (no one can edit it unless you edit it inside VS 2008). I want a way to let my Application search for MS SQL Server and save it to Application Setting and use it to connect to my DB Programmatically. When my application start, the first thing to do is checking the ConnectionString if vaild, NOT Empty and test connection to MS SQL Server Successfully so if there is a proplem I think to show a window form to let the user enter some data like username and password for MS SQL Server 2008 Is there any way to do it?

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  • Custom realm/starting Tomcat 6.0 from Netbeans 6.8/first HTTP request

    - by Drew
    I'm using NetBeans 6.8 and Tomcat 6.0.xx. I've created a custom realm and updated the NetBeans project build.xml to deploy the realm to Tomcat. When I debug the project, NetBeans starts the Tomcat server and makes an initial HTTP GET request for 'manager/list'. Tomcat graciously hands this request off to my custom realm for authentication. The request gets denied and NetBeans displays the following error in the output window: (note: error is displayed after NetBeans gets access denied) Access to Tomcat server has not been authorized. Set the correct username and password with the "manager" role in the Tomcat customizer in the Server Manager. Do I have something incorrectly configured? How do I prevent NetBeans from issuing this initial request? Thanks, Drew

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  • Header already sent error in PHP joomla

    - by Leo
    hi all, $dbhost = 'localhost'; $dbuser = 'EhpEngineUser'; $dbpass = 'password'; $conn = mysql_pconnect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql'); $dbname = 'joomladb'; mysql_select_db($dbname); // include 'config.php'; // include 'opendb.php'; above code works fine, if i comment DB connection part and inculde config.db and Opendb, then i get the error as Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\Joomla\Config.php:8) in C:\xampp\htdocs\Joomla\ConfXml.php on line 103 Both file are used for opening DB only. regards, Leo

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  • Php sessions secure log in

    - by Doodle
    My question is about creating a secure log in routine. After comparing the user name and password to the stored values I set a session variable called logged to true. Then as the user surfs around the web page I just check the logged variable for true or false to determine if the user should have access. This is my first time creating something like this. Is this secure? I feel like there is something else that I should be doing to make sure that users are valid.

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  • Django: test failing on a view with @login_required

    - by Esteban Feldman
    Hi all, I'm trying to build a test for a view that's decorated with @login_required, since I failed to make it work, I did a simple test and still can't make it pass. Here is the code for the simple test and the view: def test_login(self): user = self._create_new_user() self.assertTrue(user.is_active) login = self.client.login(username=user.username, password=self.data['password1']) self.failUnless(login, 'Could not log in') response = self.client.get('/accounts/testlogin/') self.assertEqual(response.status_code, 200) @login_required def testlogin(request): print 'testlogin !! ' return HttpResponse('OK') _create_new_user() is saving the user and there is a test inside that method to see that is working. The test fails in the response.status_code, returning 302 and the response instance is of a HttpResponseRedirect, is redirecting it as if not logged in. Any clue? I'm missing something? Regards Esteban

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  • ArgumentOutOfRangeException at MySql execution. (MySqlConnector .NET)

    - by Lazlo
    I am getting this exception from a MySqlCommand.ExecuteNonQuery(): Index and length must refer to a location within the string. Parameter name: length The command text is as follows: INSERT INTO accounts (username, password, salt, pin, banned, staff, logged_in, points_a, points_b, points_c, birthday) VALUES ('adminb', 'aea785fbcac7f870769d30226ad55b1aab850fb0979ee00481a87bc846744a646a649d30bca5474b59e4292095c74fa47ae6b9b3a856beef332ff873474cc0d3', 'cb162ef55ff7c58c7cb9f2a580928679', '', '0, '0', '0', '0', '0', '0', '2010-04-18') Sorry for the long string, it is a SHA512 hash. I tried manually adding this data in the table from MySQL GUI tools, and it worked perfectly. I see no "out of range" problem in these strings. Does anybody see something wrong?

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  • GWT with spring security not working on app engine live server.

    - by bedanand
    I configured gwt with spring and spring security that works fine on local development server on google app engine. I deployed to the appspot but there it shows critical error when i see on the log. and on the browser side shows 500 server error. log error Uncaught exception from servlet javax.servlet.UnavailableException: Initialization failed. at com.google.apphosting.runtime.jetty.AppVersionHandlerMap.createHandler(AppVersionHandlerMap.java:200) at com.google.apphosting.runtime.jetty.AppVersionHandlerMap.getHandler(AppVersionHandlerMap.java:168) at com.google.apphosting.runtime.jetty.JettyServletEngineAdapter.serviceRequest(JettyServletEngineAdapter.java:123) at com.google.apphosting.runtime.JavaRuntime.handleRequest(JavaRuntime.java:243) at com.google.apphosting.base.RuntimePb$EvaluationRuntime$6.handleBlockingRequest(RuntimePb.java:5838) at com.google.apphosting.base.RuntimePb$EvaluationRuntime$6.handleBlockingRequest(RuntimePb.java:5836) at com.google.net.rpc.impl.BlockingApplicationHandler.handleRequest(BlockingApplicationHandler.java:24) at com.google.net.rpc.impl.RpcUtil.runRpcInApplication(RpcUtil.java:398) at com.google.net.rpc.impl.Server$2.run(Server.java:852) at com.google.tracing.LocalTraceSpanRunnable.run(LocalTraceSpanRunnable.java:56) at com.google.tracing.LocalTraceSpanBuilder.internalContinueSpan(LocalTraceSpanBuilder.java:576) at com.google.net.rpc.impl.Server.startRpc(Server.java:807) at com.google.net.rpc.impl.Server.processRequest(Server.java:369) at com.google.net.rpc.impl.ServerConnection.messageReceived(ServerConnection.java:442) at com.google.net.rpc.impl.RpcConnection.parseMessages(RpcConnection.java:319) at com.google.net.rpc.impl.RpcConnection.dataReceived(RpcConnection.java:290) at com.google.net.async.Connection.handleReadEvent(Connection.java:474) at com.google.net.async.EventDispatcher.processNetworkEvents(EventDispatcher.java:831) at com.google.net.async.EventDispatcher.internalLoop(EventDispatcher.java:207) at com.google.net.async.EventDispatcher.loop(EventDispatcher.java:103) at com.google.net.rpc.RpcService.runUntilServerShutdown(RpcService.java:251) at com.google.apphosting.runtime.JavaRuntime$RpcRunnable.run(JavaRuntime.java:404) at java.lang.Thread.run(Unknown Source) web.xml <web-app> <servlet> <servlet-name>dispatcher</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>dispatcher</servlet-name> <url-pattern>*.rpc</url-pattern> </servlet-mapping> <filter> <filter-name>springSecurityFilterChain</filter-name> <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class> </filter> <filter-mapping> <filter-name>springSecurityFilterChain</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <!-- Default page to serve --> <welcome-file-list> <welcome-file>PushUrl.html</welcome-file> </welcome-file-list> </web-app> appengine-web.xml <application>pushurl</application> <version>1</version> <!-- Configure java.util.logging --> <system-properties> <property name="java.util.logging.config.file" value="WEB-INF/logging.properties"/> </system-properties> <sessions-enabled>true</sessions-enabled> applicationContext.xml <security:http auto-config="true"> <security:intercept-url pattern="/**/users.rpc" access="ROLE_USER"/> <security:intercept-url pattern="/**/categories.rpc" access="ROLE_ADMIN"/> <security:intercept-url pattern="/css/**" filters="none"/> <security:intercept-url pattern="/login.jsp*" filters="none"/> <security:form-login login-page='/login.jsp' /> </security:http> <security:authentication-manager> <security:authentication-provider> <security:user-service> <security:user name="jimi" password="jimi" authorities="ROLE_USER, ROLE_ADMIN" /> <security:user name="bob" password="bob" authorities="ROLE_USER" /> </security:user-service> </security:authentication-provider> </security:authentication-manager> dispatcher-servlet.xml <bean class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping"> <property name="mappings"> <value> /**/users.rpc=userService /**/categories.rpc=categoryService </value> </property> </bean> <bean id="userController" class="com.beda.pushurl.server.GwtRpcController"> <property name="remoteService" ref="userService"> </property> </bean> <bean id="userService" class="com.beda.pushurl.server.UserServiceImpl" > <property name="userDAO" ref="myUserDAO"></property> </bean> <bean id="categoryService" class="com.beda.pushurl.server.CategoryServiceImpl"> <property name="categoryDAO" ref="myCategoryDAO"></property> </bean> <bean id="myUserDAO" class="com.beda.pushurl.server.dao.UserDAOImpl"> </bean> <bean id="myCategoryDAO" class="com.beda.pushurl.server.dao.CategoryDAOImpl"> </bean>

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  • Python: Retrieve Image from MSSQL

    - by KoRkOnY
    Dear All, I'm working on a Python project that retrieves an image from MSSQL. My code is able to retrieve the images successfully but with a fixed size of 63KB. if the image is greater than that size, it just brings the first 63KB from the image! The following is my code: #!/usr/bin/python import _mssql mssql=_mssql.connect('<ServerIP>','<UserID>','<Password>') mssql.select_db('<Database>') x=1 while x==1: query="select TOP 1 * from table;" if mssql.query(query): rows=mssql.fetch_array() rowNumbers = rows[0][1] #print "Number of rows fetched: " + str(rowNumbers) for row in rows: for i in range(rowNumbers): FILE=open('/home/images/' + str(row[2][i][1]) + '-' + str(row[2][i][2]).strip() + ' (' + str(row[2][i][0]) + ').jpg','wb') FILE.write(row[2][i][4]) FILE.close() print 'Successfully downloaded image: ' + str(row[2][i][0]) + '\t' + str(row[2][i][2]).strip() + '\t' + str(row[2][i][1]) else: print mssql.errmsg() print mssql.stdmsg() mssql.close()

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  • Microsoft CRM could not log you on to the system. Make sure your user record...

    - by Willy
    "Microsoft CRM could not log you on to the system. Make sure your user record is enabled and that you have been assigned at least one security role. For more information, contact your system administrator." When I RDP into the server and try Microsoft CRM Workflow Manager/Monitor with http or https connectivity, it doesn't work. "The specified Microsoft CRM server is not responding. This might happen if it is currently unavaliable, it is not a Microsoft CRM server, or you are not a valid user. Contact your sys-admin." This is a Microsoft CRM v3.0 / Microsoft SQL server 2005 box, Active directory is on a seperate box.. When I right click Microsoft CRM Worlkflow Service, properties, log on: it shows "crmtestuser" and a password. I did not RDP or try logging in as that crmtestuser, but I am Admin... Could this be a clue? What can I try?

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