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  • Add 30 seconds to the time with PHP

    - by Sam
    Hey all, just wondering how I can add 30 seconds on to this? $time = date("m/d/Y h:i:s a", time()); Thankyou, again. I wasn't sure how to do it because it is showing lots of different units of time, when I only want to add 30 seconds.

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  • php:: apply backticks to first word in sentence

    - by Hailwood
    Hi guys, basically what I am trying to do is, I have an array that looks something like this: array( array( 'select' =>'first string', 'escape' => true ), array( 'select' =>'second', 'escape' => true ), array( 'select' =>'the third string', 'escape' => true ), array( 'select' =>'fourth string', 'escape' => false ), ) I am looping over it and I want to end up with this output array( array( 'select' =>'`first` string', 'escape' => true ), array( 'select' =>'`second`', 'escape' => true ), array( 'select' =>'`the` third string', 'escape' => true ), array( 'select' =>'fourth string', 'escape' => false ), ) so basic rules are backticks are only applied if escape is true backticks are only applied to the first word in a sentence if there is only one word backticks are applied to the word My plan was to use if($item['escape']) { $pos = (strpos($item['select'], ' ') === false ? strlen($item['select']) : strpos($item['select'], ' ')); $item['select'] = '`' . substr($item['select'], 0, $pos) . '`' . substr($item['select'], $pos, strlen($item['select'])); } but the $item['select'] = line seems rather long winded, is there a better way to write it?

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  • PHP string enocding issue - Extra characters appearing

    - by ryan
    I see extra characters like â showing because of encoding issues as I found out here - HTML encoding issues - "Â" character showing up instead of "&nbsp;" I understand that if I set the browser meta encoding to UTF-8, these will not affect anything but I need to strip these extra characters from the database for other purposes. For eg. : Text: ↑ should be become Text: ? But if I run it through utf8_decode it gives me Text: ??? For every other occurrence of the â character, it converts properly to a blank space. Any help will be appreciated.

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  • PHP variable question

    - by Kyle Parisi
    This works: $customerBox = mysql_query("MY SQL STATEMENT HERE"); $boxRow = mysql_fetch_array($customerBox); $customerBox = mysql_query("MY SQL STATEMENT AGAIN"); while($item = mysql_fetch_assoc($customerBox)) { foreach ($item as $columnName = $value) { if (empty($value)) { print $columnName; } } } This does not: $customerBox = mysql_query("MY SQL STATEMENT HERE"); $boxRow = mysql_fetch_array($customerBox); while($item = mysql_fetch_assoc($customerBox)) { foreach ($item as $columnName = $value) { if (empty($value)) { print $columnName; } } } Why? I guess I don't understand how variables work yet.

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  • cache problem uinsg php and jquery

    - by pradeep
    hi , i am using jquery stars plugin and asking users to rate . the form works well,but caching has become a big problem. even after refresh of the page .it does not show the latest ratings . only after i clear the cache new ratings gets showed.

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  • PHP: reusing database class

    - by citricsquid
    Hi, I built a class that allows me to do: $db->query($query); and it works perfectly, although if I want to do: $db->query($query); while($row = $db->fetch_assoc()){ $db->query($anotherquery); echo $db->result(); } it "breaks" the class. I don't want to constantly have to redeclare my class (eg: $seconddb = new database()), is there a way to get around this? I want to be able to reuse $db within $db, without overwriting the "outside" db. currently I'm create an array of data (from db-fetch_assoc() then doing a foreach and then doing the db call inside that: $db->query('SELECT * FROM table'); while($row = $db->fetch_assoc()){ $arr[] = $row; } foreach($arr as $a){ $db->query(); // query and processing here } Is this the best method or am I missing the obvious? Should I consider passing a connection link ID with the database connection?

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  • php adding value to session

    - by antikbd
    I am trying to implement a 'shopping cart' where, if the 'Add to Cart' has been clicked, the respective item is either added to the cart or incremented by one if already present. However, the following code isn't working and giving me a "Cannot use a scalar value as an array" error. Any help would be highly appreciated. if (isset($_POST['fan']) && ($_POST['fan']=="Add to Cart")) { if (($_SESSION['cart']['fan']==0) || (!isset($_SESSION['cart']['fan']))) { $_SESSION['cart']['fan']=1; } else { $_SESSION['cart']['fan']++; } }

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  • Basic PHP logic problem

    - by Joe Smalley
    $this->totplpremium is 2400 $this->minpremiumq is 800 So why would this ever return true?! if ($this->totplpremium < $this->minpremiumq){ The figures are definitely correct and I am definitely using the 'less than' symbol. I can't work it out.

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  • Changing key of Multidimensional array in PHP

    - by Thyu
    This is my first array Array ( [0] => Array ( [0] => 1 [1] => Elite [2] => Air-Con Bus [3] => Monday ) [1] => Array ( [0] => 4 [1] => KBZ [2] => Airplane [3] => Wednesday ) [2] => Array ( [0] => 5 [1] => Yoma [2] => Cruise [3] => Tuesday ) ) I want to be inner array[0] to the outer array key. Like the following array: Can I or not? Please suggest me. Array( [1] => Array ( [0] => 1 [1] => Elite [2] => Air-Con Bus [3] => Monday ) [4] => Array ( [0] => 4 [1] => KBZ [2] => Airplane [3] => Wednesday ) [5] => Array ( [0] => 5 [1] => Yoma [2] => Cruise [3] => Tuesday ) )

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  • Problem with php GD image not creating

    - by ThinkingInBits
    With the following code, my browser is returning 'image not created or saved'. I assure you the location of the image exists. So the line within the if statement is returning false for some reason, and yes GD is installed. Any ideas? if ($img = @imagecreatefromjpeg("/var/www/images/upload/1/1.jpg")) { $image_width = imagesx($img); $image_height = imagesy($img); $target_width = 150; $target_height = 150; if ($image_width > $image_height) { $percentage = ($target_width / $image_width); } else { $percentage = ($target_height / $image_height); } $new_image_width = round($image_width * $percentage); $new_image_height = round($image_height * $percentage); $imgResized = imagecreatetruecolor($new_image_width, $new_image_height); imagecopyresampled($imgResized, $img, 0, 0, 0, 0, $new_image_width, $new_image_height, $image_width, $image_height); imagejpeg($imgResized, $this->path, 100); imagedestroy($img); imagedestroy($imgResized); $this->storeThumbnailLocation(); } else { die ("image was not created or saved"); }

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  • Substr from end of string php?

    - by Gorostas
    I have this kind of array, i will make it very simple to understand $picture = ( 'artist2-1_thumb.jpg', 'artist2-2.jpg' , 'artist2-3_thumb.jpg', 'artist2-4.jpg', 'artist2-5_thumb.jpg'); Now i want use substr to get new array that only have thumb, to have new array like this $picturethumbs = ( 'artist2-1_thumb.jpg', 'artist2-3_thumb.jpg', 'artist2-5_thumb.jpg'); Can some substr but where to start?

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  • Php function within SQL statement syntax

    - by Vafello
    I have the following code. I would like username to take the value of the getUserName function however I am fighting with syntax. Can anybody tell me what should be the correct one? $query = "SELECT user FROM users_entity WHERE username = getUserName()";

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  • PHP parameter without value using for navigation

    - by somewalri
    Hello, I am trying to set up a navigation system that uses GET parameters with no value, example: http://foo.bar/?mainPage takes the visitor to the main page. So I am using if statements and I am wondering if there is a way I can do this without a bunch of if statements? I don't think switch statements would work for this. This is currently what I have: $mainPage = $_GET['mainPage']; $contact = $_GET['contact']; if(isset($mainPage)) { // go to main page } if(isset($contact)) { // go to contact page } I don't want to have to end up writing a ton of if statements, though. Any ideas? Thanks.

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  • Access php multidimensional array key based on a variable string

    - by ggirtsou
    I have stored the XML path to items in a string like this: response->items->item. What I need to do is to access an array called $xml_array like this: $xml_array['response']['items']['item'] When I write it in the code it works. The thing is that I want it to be done on the fly. I use this to convert response->items->item to ['response']['items']['item']: $xml_path = 'response->items->item'; $explode_path = explode('->', $xml_path); $correct_string = false; foreach($explode_path as $path) { $correct_string .= '[\''.$path.'\']'; } the problem is that I can't access $xml_array by doing this: $xml_array[$correct_string] So I end up with this: $xml_tag = 'title'; $xml_path = 'response->items->item'; $correct_string = '$items = $xml2array'; $explode_path = explode('->', $xml_path); foreach($explode_path as $path) { $correct_string .= '[\''.$path.'\']'; } $correct_string .= ';'; eval($correct_string); foreach($items as $item) { echo $item[$xml_tag].'<br />'; } and access the $xml_array array through $items array. Is there any way I can do this and avoid using eval()? Thanks in advance!

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  • Can't figure out what's wrong with my php/sql statement

    - by Olegious
    So this is probably a dumb beginner question, but I've been looking at it and can't figure it out. A bit of background: just practicing making a web app, a form on page 1 takes in some values from the user, posts them to the next page which contains the code to connect to the DB and populate the relevant tables. I establish the DB connection successfully, here's the code that contains the query: $conn->query("SET NAMES 'utf9'"); $query_str = "INSERT INTO 'qa'.'users' ('id', 'user_name','password' ,'email' ,'dob' ,'sx') VALUES (NULL, $username, $password, $email, $dob, $sx);"; $result = @$conn->query($query_str); Here's the error that is returned:Insert query failed: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''qa'.'users' ('id', 'user_name' ,'password' ,'email' ,'dob' ,'s' at line 1 Thanks in advance!

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  • PHP: Remove all fcn not acting as expected, Code Inside

    - by Josh K
    I made this simple function (remove all $elem from $array): function remall($array, $elem) { for($i=0; $i < count($array); $i++) if($array[$i] == $elem) unset($array[$i]); $newarray = array_values($array); return $newarray; } But it isn't working perfectly, here are some inputs and outputs $u = array(1, 7, 2, 7, 3, 7, 4, 7, 5, 7, 6, 7); $r = remall($u, 7); Output of $r: 12345767 $n = array(7, 7, 1, 7, 3, 4, 6, 7, 2, 3, 1, -3, 10, 11, 7, 7, 7, 2, 7); $r = remall($n, 7); Output of $r: 1346231-30117727 Notice how there are still 7s in my outputs. Also, My function will only be removing numbers from an array. Let me know if you spot something, thanks.

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  • Adding 30 minutes to time formatted as H:i in PHP

    - by bateman_ap
    Having a nightmare at the moment and just can't see why it isn't working I have a value in the form H:i (ie 10:00, 13:30) etc called $time What I want to do is create two new values, $startTime which is 30 mins before $time and $endTime which is 30 mins after $time I have tried the following but just doesn't seem to want to work $startTime = date("H:i",strtotime('-30 minutes',$time)); $endTime = date("H:i",strtotime('+30 minutes',$time)); If I pass through 10:00 as $time and echo out both $startTime and $endTime I get: $startTime = 00:30 $startTime = 01:30

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  • Difference between :: and -> in PHP

    - by vrode
    I always see people in serious projects use :: everywhere, and - only occasionally in local environment. I only use - myself and never end up in situations when I need a static value outside of a class. Am I a bad person? As I understand, the only situation when -> won't work is when I try following: class StaticDemo { private static $static } $staticDemo = new StaticDemo( ); $staticDemo->static; // wrong $staticDemo::static; // right But am I missing out on some programming correctness when I don't call simple public methods by :: ? Or is it just so that I can call a method without creating an instance?

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  • PHP : flatten array - fastest way?

    - by Industrial
    Is there any fast way to flatten an array and select subkeys ('key'&'value' in this case) without running a foreach loop, or is the foreach always the fastest way? Array ( [0] => Array ( [key] => string [value] => a simple string [cas] => 0 ) [1] => Array ( [key] => int [value] => 99 [cas] => 0 ) [2] => Array ( [key] => array [value] => Array ( [0] => 11 [1] => 12 ) [cas] => 0 ) ) To: Array ( [int] => 99 [string] => a simple string [array] => Array ( [0] => 11 [1] => 12 ) )

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