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  • Missing Java error on conditional expression?

    - by Federico Cristina
    With methods test1() and test2(), I get a Type Mismatch Error: Cannot convert from null to int, which is correct; but why am I not getting the same in method test3()? How does Java evaluates the conditional expression differently in that case? (obviusly, a NullPointerException will rise in runtime). Is it a missing error? public class Test { public int test1(int param) { return null; } public int test2(int param) { if (param > 0) return param; return null; } public int test3(int param) { return (param > 0 ? return param : return null); } } Thanks in advance!

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  • LINQ Expression not evaluating correctly

    - by WedTM
    I have the following LINQ expression that's not returning the appropriate response var query = from quote in db.Quotes where quote.QuoteStatus == "Estimating" || quote.QuoteStatus == "Rejected" from emp in db.Employees where emp.EmployeeID == quote.EmployeeID orderby quote.QuoteID descending select new { quote.QuoteID, quote.DateDue, Company = quote.Company.CompanyName, Attachments = quote.Attachments.Count, Employee = emp.FullName, Estimator = (quote.EstimatorID != null && quote.EstimatorID != String.Empty) ? db.Employees.Single (c => c.EmployeeID == quote.EstimatorID).FullName : "Unassigned", Status = quote.QuoteStatus, Priority = quote.Priority }; The problem lies in the Estimator = (quote.EstimatorID != null && quote.EstimatorID != String.Empty) ? db.Employees.Single(c => c.EmployeeID == quote.EstimatorID).FullName : "Unassigned" part. I NEVER get it to evalueate to "Unassigned", on the ones that are supposed to, it just returns null. Have I written this wrong?

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  • help converting sql to linq expression with count

    - by Philip
    I am trying to convert the following SQL into a LINQ expression SELECT COUNT(ID) AS Count, MyCode FROM dbo.Archive WHERE DateSent=@DateStartMonth AND DateSent<=@DateEndMonth GROUP BY MyCode and I have been trying to follow this webpage as an example http://stackoverflow.com/questions/606124/converting-sql-containing-top-count-group-and-order-to-linq-2-entities I got this so far but I am stuck on understanding the new part var res=(from p in db.Archives where (p.DateSent>= dateStartMonth) && (p.DateSent< dateToday) group p by p.MyCode into g select new { ??????MyCode = g.something?, MonthlyCount= g.Count() }); Thanks in advance for helping greatly appreciated Philip

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  • Use of "setTimeout()" in my jQuery Expression

    - by Aaron Salazar
    I'm trying to add the JavaScript function setTimeout() to my jQuery expression. Without the setTimeout() my function loads a partial view with updated information when I enter text into my textbox. But, it loads the information with every keystroke. My logic is that if I can put in a timer then when the user stops typing, a second later the data is updated. As you can see I tried to put a setTimer() in but it doesn't seem to be working. $(function() { $('#DocId').live('keyup', function() { setTimeout(var styleValue = $(this).val(); $('#tableContent').load( '/CurReport/TableResults', { style: $(this).val()}), 1000); }), }); Thank you, Aaron

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  • entity framework, loadproperty not working - The selector expression for LoadProperty must be a Memb

    - by SLC
    The selector expression for LoadProperty must be a MemberAccess for the property. I'm converting some C# to VB, this is the C# line: entities.LoadProperty((MyType)MyTargetObject, c => c.MyProperty); I convert it to VB like so: entities.LoadProperty(DirectCast(MyTargetObject, MyType), Function(c) c.MyProperty) However I get the error above. I don't understand what the code is doing, or anything at all, I am simply converting it line by line into Visual Basic. When I run the project, the error I get is the one above. All I can see is that Entities is a class that inherits ObjectContext, which might mean something. Any help would be soooo good because I am stressing out big time. Thanks.

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  • php regex expression to get title

    - by 55skidoo
    I'm trying to strip content titles out of the middle of text strings. Could I use regex to strip everything out of this string except for the title (in italics) in these strings? Or is there a better way? Joe User wrote a blog post called The 10 Best Regex Expressions in the category Regex. Jane User wrote a blog post called Regex is Hard! in the category TechProblems. I've tried to come up with a regex expression to cover this, but I think it might need two. The trick is that the text in bold is always the same, so you could search for that, like this: regex: delete everything before and including wrote a blog post called regex: delete in the category and everything after it.

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  • regular expression to read the string between <title> and </title>

    - by user262325
    Hello every one I hope to read the contents between and in a html string. I think it should be in objective-c @"<title([\\s\\S]*)</title>" below are the codes that rewrited for regular expression //source of NSStringCategory.h #import <Foundation/Foundation.h> #import <regex.h> @interface NSStringCategory:NSObject { regex_t preg; } -(id)initWithPattern:(NSString *)pattern options:(int)options; -(void)dealloc; -(BOOL)matchesString:(NSString *)string; -(NSString *)matchedSubstringOfString:(NSString *)string; -(NSArray *)capturedSubstringsOfString:(NSString *)string; +(NSStringCategory *)regexWithPattern:(NSString *)pattern options:(int)options; +(NSStringCategory *)regexWithPattern:(NSString *)pattern; +(NSString *)null; +(void)initialize; @end @interface NSString (NSStringCategory) -(BOOL)matchedByPattern:(NSString *)pattern options:(int)options; -(BOOL)matchedByPattern:(NSString *)pattern; -(NSString *)substringMatchedByPattern:(NSString *)pattern options:(int)options; -(NSString *)substringMatchedByPattern:(NSString *)pattern; -(NSArray *)substringsCapturedByPattern:(NSString *)pattern options:(int)options; -(NSArray *)substringsCapturedByPattern:(NSString *)pattern; -(NSString *)escapedPattern; @end and .m file #import "NSStringCategory.h" static NSString *nullstring=nil; @implementation NSStringCategory -(id)initWithPattern:(NSString *)pattern options:(int)options { if(self=[super init]) { int err=regcomp(&preg,[pattern UTF8String],options|REG_EXTENDED); if(err) { char errbuf[256]; regerror(err,&preg,errbuf,sizeof(errbuf)); [NSException raise:@"CSRegexException" format:@"Could not compile regex \"%@\": %s",pattern,errbuf]; } } return self; } -(void)dealloc { regfree(&preg); [super dealloc]; } -(BOOL)matchesString:(NSString *)string { if(regexec(&preg,[string UTF8String],0,NULL,0)==0) return YES; return NO; } -(NSString *)matchedSubstringOfString:(NSString *)string { const char *cstr=[string UTF8String]; regmatch_t match; if(regexec(&preg,cstr,1,&match,0)==0) { return [[[NSString alloc] initWithBytes:cstr+match.rm_so length:match.rm_eo-match.rm_so encoding:NSUTF8StringEncoding] autorelease]; } return nil; } -(NSArray *)capturedSubstringsOfString:(NSString *)string { const char *cstr=[string UTF8String]; int num=preg.re_nsub+1; regmatch_t *matches=calloc(sizeof(regmatch_t),num); if(regexec(&preg,cstr,num,matches,0)==0) { NSMutableArray *array=[NSMutableArray arrayWithCapacity:num]; int i; for(i=0;i<num;i++) { NSString *str; if(matches[i].rm_so==-1&&matches[i].rm_eo==-1) str=nullstring; else str=[[[NSString alloc] initWithBytes:cstr+matches[i].rm_so length:matches[i].rm_eo-matches[i].rm_so encoding:NSUTF8StringEncoding] autorelease]; [array addObject:str]; } free(matches); return [NSArray arrayWithArray:array]; } free(matches); return nil; } +(NSStringCategory *)regexWithPattern:(NSString *)pattern options:(int)options { return [[[NSStringCategory alloc] initWithPattern:pattern options:options] autorelease]; } +(NSStringCategory *)regexWithPattern:(NSString *)pattern { return [[[NSStringCategory alloc] initWithPattern:pattern options:0] autorelease]; } +(NSString *)null { return nullstring; } +(void)initialize { if(!nullstring) nullstring=[[NSString alloc] initWithString:@""]; } @end @implementation NSString (NSStringCategory) -(BOOL)matchedByPattern:(NSString *)pattern options:(int)options { NSStringCategory *re=[NSStringCategory regexWithPattern:pattern options:options|REG_NOSUB]; return [re matchesString:self]; } -(BOOL)matchedByPattern:(NSString *)pattern { return [self matchedByPattern:pattern options:0]; } -(NSString *)substringMatchedByPattern:(NSString *)pattern options:(int)options { NSStringCategory *re=[NSStringCategory regexWithPattern:pattern options:options]; return [re matchedSubstringOfString:self]; } -(NSString *)substringMatchedByPattern:(NSString *)pattern { return [self substringMatchedByPattern:pattern options:0]; } -(NSArray *)substringsCapturedByPattern:(NSString *)pattern options:(int)options { NSStringCategory *re=[NSStringCategory regexWithPattern:pattern options:options]; return [re capturedSubstringsOfString:self]; } -(NSArray *)substringsCapturedByPattern:(NSString *)pattern { return [self substringsCapturedByPattern:pattern options:0]; } -(NSString *)escapedPattern { int len=[self length]; NSMutableString *escaped=[NSMutableString stringWithCapacity:len]; for(int i=0;i<len;i++) { unichar c=[self characterAtIndex:i]; if(c=='^'||c=='.'||c=='['||c=='$'||c=='('||c==')' ||c=='|'||c=='*'||c=='+'||c=='?'||c=='{'||c=='\\') [escaped appendFormat:@"\\%C",c]; else [escaped appendFormat:@"%C",c]; } return [NSString stringWithString:escaped]; } @end I use the codes below to get the string between "" and "" NSStringCategory *a=[[NSStringCategory alloc] initWithPattern:@"<title([\s\S]*)</title>" options:0];// Unfortunately [a matchedSubstringOfString:response]] always returns nil I do not if the regular expression is wrong or any other reason. Welcome any comment Thanks interdev

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  • Regular expression replace in PL/pgSQL

    - by dreamlax
    If I have the following input (excluding quotes): "The ancestral territorial imperatives of the trumpeter swan" How can I collapse all multiple spaces to a single space so that the input is transformed to: "The ancestral territorial imperatives of the trumpeter swan" This is going to be used in a trigger function on insert/update (which already trims leading/trailing spaces). Currently, it raises an exception if the input contains multiple adjacent spaces, but I would rather it simply transforms it into something valid before inserting. What is the best approach? I can't seem to find a regular-expression replace function for PL/pgSQL. There is a text_replace function, but this will only collapse at most two spaces down to one (meaning three consecutive spaces will collapse to two). Calling this function over and over is not ideal.

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  • Regular expression in C#

    - by user340015
    i have text something like this. @@MMIVLoader@[email protected]@BCM_7400S_LE@Product@Aug 21 2009@ @@MMIVLib@[email protected]@BCM_7400S_LE@Product@Aug 21 2009@ @@HuaweFGDLDrv@[email protected]@7324@PRODUCT@Aug 20 2009@ @@ProtectVer@[email protected] @BCM_SDE5.03@PRODUCT@Aug 4 2009 06:56:19@ @@KernelSw@[email protected]@BCM-7454@PRODUCT@ Dec 19 2007@ @@ReceiverSw@[email protected]@HWBC01ZS@PRODUCT@May 3 2010@ i want the out put in an array like MMIVLoader 4.1.2 MMIVLib 4.1.2 HuaweFGDLDrv 01.00.09 ProtectVer 127.8.1 KernelSw 0.0.1 ReceiverSw E.5.6.001 Can any one suggest me how to do this in c# using regular expression or is there a any sophisticated way to do this thanks in advance

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  • OSLO, ANTLR or other parser grammar, for parsing QUERY EXPRESSION

    - by Jay Allard
    Greetings I'm working on a project that requires me to write queries in text form, then convert them to some easily processed nodes to be processed by some abiguous repository. Of everything there, the part I'm least interested is the part that converts the text to nodes. I'm hoping it's already done somewhere. Because I'm making stuff up as I go, I chose to use a LINQish expression syntax. from m in Movie select m.A, m.B I started parsing it manually and got the basics, but it's pretty cheesy. I'm looking for the better solution. I made some progress using MGrammar, but it would be nice if such a thing already existed. Does anyone know of anything that already does this? I looked for existing ANTLR templates, but no luck. Thanks for the help.

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  • PHP Form Validation Regular Expression, no symbols or numbers

    - by MrEnder
    Ok I am trying to get the users First Name the form gets their name perfectly fine and posts it into a variable. Now I am trying to do error checking else if(!preg_match("/^[\w-]+$/", $firstNameSignup)) { $firstNameSignupError = "Your first name cannot contain numbers or symbols, you entered " . $firstNameSignup; $firstNameSignup = ""; } I tried the above code and it does not like me but my if statement if(!isset($firstNameSignup) || $firstNameSignup == "") { $firstNameSignupError = "You must enter your first name"; } works fine so I know that the error is in that else if statement... most likely in my regular expression any help??? I'm totally at a loss (really new to PHP and regular expressions) Thanks Shelby

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  • JavaScript String Replace with a tricky regular expression

    - by Juri
    Hi. I'm trying to work out what regular expression I would need to change this string html = '<img style="width: 311px; height: 376px;" alt="test" src="/img/1268749322.jpg" />'; to this html = '<img width="311" height="376" alt="test" src="/img/1268749322.jpg" />'; with the help of Javascript.replace. This is my start: html = html.replace(/ style="width:\?([0-9])px*"/g, "width=\"$1\""); Can anyone help me? THANKS

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  • How to use a variable in an awk expression

    - by lugte098
    I'm trying to make this command: sed bla bla filename | awk '{printf "%s %s_entry_%.3f %.3f %.3f %.3f",$1,$3,$4,$5,$6,$7}' But the thing is, i want the %.3f part to be variable. So in one case it could be %.3f and in another it could be %.3f %.3f %.3f. So i'll just use a static one in my example code for clarity. So if i want 4 of these %.3f and put them in variable $values like so: values="%.3f %.3f %.3f %.3f" Then how can i put this string in the awk expression, without making awk to just put literally "${values}" in there. The following is my non-working-attempt: sed bla bla filename | awk '{printf "%s %s_entry_${values}",$1,$3,$4,$5,$6,$7}'

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  • C# Lambda Expression Speed

    - by Nathan
    I have not used many lambda expressions before and I ran into a case where I thought I could make slick use of one. I have a custom list of ~19,000 records and I need to find out if a record exists or not in the list so instead of writing a bunch of loops or using linq to go through the list I decided to try this: for (int i = MinX; i <= MaxX; ++i) { tempY = MinY; while (tempY <= MaxY) { bool exists = myList.Exists(item => item.XCoord == i && item.YCoord == tempY); ++tempY; } } Only problem is it take ~9 - 11 seconds to execute. Am I doing something wrong is this just a case of where I shouldn't be using an expression like this? Thanks.

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  • Evaluating a regular expression range

    - by Dan Atkinson
    Hi there! Is there a nice way to evaluate a regular expression range, say, for a url such as http://example.com/[a-z]/[0-9].htm This would be converted into: http://example.com/a/0.htm http://example.com/a/1.htm http://example.com/a/2.htm ... http://example.com/a/9.htm ... http://example.com/z/0.htm http://example.com/z/1.htm http://example.com/z/2.htm ... http://example.com/z/9.htm I've been scratching my head about this, and there's no pretty way of doing it without going through the alphabet and looping through numbers. Thanks in advance!

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  • A regular expression that will allow a string with only one Capital Letter

    - by Phoenix
    The string should be 6 - 20 characters in length. And it should contain 1 Capital letter. I can do this in code using C# string st = "SomeString" Regex rg = new Regex("[A-Z]"); MatchCollection mc = rg.Matches(st); Console.WriteLine("Total Capital Letters: " + mc.Count); if (mc.Count > 1) { return false; } But what i really want is a Regular expression that will match my string if it only contains one capital. The string can start with a common letter and should have only letters. Thanks In advance. (I did look at some of the other RegEx questions but they did not help).

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  • Regex-expression with danish characters

    - by timkl
    I'm currently trying to wrap my head around regex, I have a validation snippet that tests an input box against a regex-expression: $.validator.addMethod("customerName", function(value, element){ return (/^[a-zA-Z]*$/).test(value); }, "Some text"); That works well, but when I try to add a space and some special danish characters, it doesn't filter the danish characters, only the space. $.validator.addMethod("customerName", function(value, element){ return (/^[a-zA-Z æøåÆØÅ]*$/).test(value); }, "Some text"); Any ideas to what could be wrong?

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  • Racket regular-expression matching

    - by Inaimathi
    I'm trying to create a regex that matches the inverse of a certain string type (so, strings not ending in ".js", for example). According to the documentation, that should be the expression #rx"(?!\\.js$)", but it doesn't seem to work. To test it out, I have this function: (define (match-test regex) (map (lambda (text) (regexp-match? regex text)) '("foo.js" "bar.css" "baz.html" "mumble.gif" "foobar"))) (match-test #rx"\\.js$") returns (#t #f #f #f #f) as expected, but (match-test #rx"(?!\\.js$)") returns (#t #t #t #t #t), where I would expect (#f #t #t #t #t). What am I doing wrong, and how do I actually get a regex in Racket to express the idea "match anything which does not contain [x]"?

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  • Solving a math problem/expression, which is a string, in PHP

    - by Koning WWWWWWWWWWWWWWWWWWWWWWW
    The user can enter a math problem (expression) like 5 + 654, 6 ^ 24, 2!, sqrt(543), log(54), sin 5, sin(50). After some reformatting (e.g. change sin 5 into sin(5)), and doing an eval, PHP gives me the right result: $problem = "5 + 5324"; eval("$result = " . $problem); echo $problem . " = " . $result; However, this is quite unsafe: /* If you read this, please, plz don't be stupid and DO NOT EXECUTE this code!!!!! */ $problem = "shell_exec('rm -rf /')"; eval("$result = " . $problem); /* Nukes system */ echo $problem . " = " . $result; Can anyone point me in the right direction parsing and solving a math question like the examples above, which is safe? Thanks.

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  • Java (Android) regular expression to strip out HTML paragraph

    - by jackbot
    I have an Android application which grabs some data from an external XML source. I've stripped out some HTML from one of the XML elements, but it's in the format: <p class="x">Some text...</p> <p>Some more text</p> <p>Some final text</p> I want to extract the middle paragraph text, how can I do this? Would a regular expression be the best way? I don't really want to start including external HTML parsing libraries.

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  • LINQ expression precedence with Skip(), Take() and OrderBy()

    - by Robert Koritnik
    I'm using LINQ to Entities and display paged results. But I'm having issues with the combination of Skip(), Take() and OrderBy() calls. Everything works fine, except that OrderBy() is assigned too late. It's executed after result set has been cut down by Skip() and Take(). So each page of results has items in order. But ordering is done on a page handful of data instead of ordering of the whole set and then limiting those records with Skip() and Take(). How do I set precedence with these statements? My example (simplified) var query = ctx.EntitySet.Where(/* filter */).OrderBy(/* expression */); int total = query.Count(); var result = query.Skip(n).Take(x).ToList();

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  • regular expression search in python

    - by Richard
    Hello all, I am trying to parse some data and just started reading up on regular Expressions so I am pretty new to it. This is the code I have so far String = "MEASUREMENT 3835 303 Oxygen: 235.78 Saturation: 90.51 Temperature: 24.41 DPhase: 33.07 BPhase: 29.56 RPhase: 0.00 BAmp: 368.57 BPot: 18.00 RAmp: 0.00 RawTem.: 68.21" String = String.strip('\t\x11\x13') String = String.split("Oxygen:") print String[1] String[1].lstrip print String[1] What I am trying to do is to do is remove the oxygen data (235.78) and put it in its own variable using an regular expression search. I realize that there should be an easy solution but I am trying to figure out how regular expressions work and they are making my head hurt. Thanks for any help Richard

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  • Type mismatch in expression in Delphi 7 on SQL append

    - by Demonick
    I have a code, that checks the current date when a form is loaded, performs a simple calculation, and appends a SQL in Delphi. It works on Windows 7 with Delphi 7, and on another computer with Xp, but doesn't on 3 other computers with Xp. When the form is loaded it shows a "Type mismatch in expression", and points to the line after the append. What could be the problem? procedure TfmJaunumi.FormCreate(Sender: TObject); var d1, d2: TDate; begin d1:= Date; d2:= Date-30; With qrJaunumi do begin Open; SQL.Append('WHERE Sanem_datums BETWEEN' + #39 + DateToStr(d1) + #39 + 'AND' + #39 + DateToStr(d2) + #39); Active := True; end; end;

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  • Python regular expression help

    - by dlw
    Hi SO, I can't seem to create the correct regular expression to extract the correct tokens from my string. Padding the beginning of the string with a space generates the correct output, but seems less than optimal: >>> import re >>> s = '-edge_0triggered a-b | -level_Sensitive c-d | a-b-c' >>> re.findall(r'\W(-[\w_]+)',' '+s) ['-edge_0triggered', '-level_Sensitive'] # correct output Here are some of the regular expressions I've tried, does anyone have a regex suggestion that doesn't involve changing the original string and generates the correct output >>> re.findall(r'(-[\w_]+)',s) ['-edge_0triggered', '-b', '-level_Sensitive', '-d', '-b', '-c'] >>> re.findall(r'\W(-[\w_]+)',s) ['-level_Sensitive'] Thanks -- DW

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  • parsing FireFox bookmarks using regular expression

    - by SIFE
    I tried to parse firefox bookmark(JSON exported version), using this efforts: cat boo.json | grep '\"uri\"\:\"^http\://[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}\"' cat boo.json | grep '"uri"\:"^http\://[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}' cat boo.json | grep '"uri"\:"^http\://[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}"' And few others but all fails, json bookmarked file will look like this: .........."uri":"http://www.google.com/?"......"uri":"http://stackoverflow.com/" So, the output should be like this: "uri":"http://www.google.com/?" "uri":"http://stackoverflow.com/" What is the missing part on my regular expression?

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