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  • ajax html vs xml/json responses - perfomance or other reasons

    - by pedalpete
    I've got a fairly ajax heavy site and some 3k html formatted pages are inserted into the DOM from ajax requests. What I have been doing is taking the html responses and just inserting the whole thing using jQuery. My other option is to output in xml (or possibly json) and then parse the document and insert it into the page. I've noticed it seems that most larger site do things the json/xml way. Google Mail returns xml rather than formatted html. Is this due to performance? or is there another reason to use xml/json vs just retrieving html? From a javascript standpoint, it would seem injecting direct html is simplest. In jQuery I just do this jQuery.ajax({ type: "POST", url: "getpage.php", data: requestData, success: function(response){ jQuery('div#putItHear').html(response); } with an xml/json response I would have to do jQuery.ajax({ type: "POST", url: "getpage.php", data: requestData, success: function(xml){ $("message",xml).each(function(id) { message = $("message",xml).get(id); $("#messagewindow").prepend(""+$("author",message).text()+ ": "+$("text",message).text()+ ""); }); } }); clearly not as efficient from a code standpoint, and I can't expect that it is better browser performance, so why do things the second way?

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  • Transform RSS-Feed into another "standard" XML-Format with PHP

    - by ChrisBenyamin
    Hey friends, quick question: I need to transform a default RSS Structure into another XML-format. The RSS File is like.... Name des RSS Feed Feed Beschreibung de http://xml-rss.de Sat, 1 Jan 2000 00:00:00 GMT Titel der Nachricht Die Nachricht an sich http://xml-rss.de/link-zur-nachricht.htm Sat, 1. Jan 2000 00:00:00 GMT 01012000-000000 Titel der Nachricht Die Nachricht an sich http://xml-rss.de/link-zur-nachricht.htm Sat, 1. Jan 2000 00:00:00 GMT 01012000-000000 Titel der Nachricht Die Nachricht an sich http://xml-rss.de/link-zur-nachricht.htm Sat, 1. Jan 2000 00:00:00 GMT 01012000-000000 ...and I want to extract only the item-elements (with childs and attributes) XML like: <?xml version="1.0" encoding="ISO-8859-1"?> <item> <title>Titel der Nachricht</title> <description>Die Nachricht an sich</description> <link>http://xml-rss.de/link-zur-nachricht.htm</link> <pubDate>Sat, 1. Jan 2000 00:00:00 GMT</pubDate> <guid>01012000-000000</guid> </item> ... It hasn't to be stored into a file. I need just the output. I tried different approaches with DOMNode, SimpleXML, XPath, ... but without success. Thanks chris

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  • Java: Ignoring escapes when parsing XML

    - by Personman
    I'm using a DocumentBuilder to parse XML files. However, the specification for the project requires that within text nodes, strings like " and < be returned literally, and not turned into the corresponding ASCII values. A previous similar question, http://stackoverflow.com/questions/1979785/read-escaped-quote-as-escaped-quote-from-xml, received one answer that seems to be specific to Apache, and another that appears to simply not not do what it says it does. I'd love to be proven wrong on either count, however :) For reference, here is some code: file = new File(fileName); DocBderFac = DocumentBuilderFactory.newInstance(); DocBder = DocBderFac.newDocumentBuilder(); doc = DocBder.parse(file); NodeList textElmntLst = doc.getElementsByTagName(text); Element textElmnt = (Element) textElmntLst.item(0); NodeList txts = textElmnt.getChildNodes(); String txt = ((Node) txts.item(0)).getNodeValue(); System.out.println(txt); I would like that println() to produce things like &quot;3&gt;2&quot; instead of "3>2" which is what currently happens. Thanks!

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  • C# XML export for Excel table using XmlDocument

    - by Mark
    I am trying to write the following into an XML document: <head> <xml> <x:ExcelWorkbook> <x:ExcelWorksheets> <x:ExcelWorksheet> other code here </x:ExcelWorksheet> </x:ExcelWorksheets> </x:ExcelWorkbook> </xml> </head> However, if I use the following code, it strips out the 'x:'. System.Xml.XmlDocument document = new System.Xml.XmlDocument(); System.Xml.XmlElement htmlNode = document.CreateElement("html"); htmlNode.SetAttribute("xmlns:o", "urn:schemas-microsoft-com:office:office"); htmlNode.SetAttribute("xmlns:x", "urn:schemas-microsoft-com:office:excel"); htmlNode.SetAttribute("xmlns", "http://www.w3.org/TR/REC-html40"); document.AppendChild(htmlNode); System.Xml.XmlElement headNode = document.CreateElement("head"); htmlNode.AppendChild(headNode); headNode.AppendChild( document.CreateElement("xml")).AppendChild( document.CreateElement("x:ExcelWorkbook"))).AppendChild( document.CreateElement("x:ExcelWorksheets")).AppendChild( document.CreateElement("x:ExcelWorksheet")).InnerText="other code here"; How can I stop this from happening? Thanks!

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  • How to check if a node's value in one XML is present in another XML with a specific attribute?

    - by Manish
    The question seems to be little confusing. So let me describe my situation through an example: Suppose I have an XML: A.xml <Cakes> <Cake>Egg</Cake> <Cake>Banana</Cake> </Cakes> Another XML: B.xml <Cakes> <Cake show="true">Egg</Cake> <Cake show="true">Strawberry</Cake> <Cake show="false">Banana</Cake> </Cakes> Now I want to show some text say "TRUE" if all the Cake in A.xml have show="true" in B.xml else "FALSE". In the above case, it will print FALSE. I need to develop an XSL for that. I can loop through all the Cake in A.xml and check if that cake has show="true" in B.xml but I don't know how to break in between (and set a variable) if a show="false" is found. Is it possible? Any help/comments appreciated.

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  • Parsing XHTML with inline tags

    - by user290796
    Hi, I'm trying to parse an XHTML document using TBXML on the iPhone (although I would be happy to use either libxml2 or NSXMLParser if it would be easier). I need to extract the content of the body as a series of paragraphs and maintain the inline tags, for example: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> <head> <title>Title</title> <link rel="stylesheet" href="css/style.css" type="text/css"/> <meta http-equiv="Content-Type" content="application/xhtml+xml; charset=utf-8"/> </head> <body> <div class="body"> <div> <h3>Title</h3> <p>Paragraph with <em>inline</em> tags</p> <img src="image.png" /> </div> </div> </body> </html> I need to extract the paragraph but maintain the <em>inline</em> content with the paragraph, all my testing so far has extracted that as a subelement without me knowing exactly where it fitted in the paragraph. Can anyone suggest a way to do this? Thanks.

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  • Convert an XML object back into a string in ColdFusion

    - by jpmyob
    In ColdFusion, I can parse a string of XML formatted data into an XML Object using xmlParse(). How can I convert it back into a string? When I tried using toString() it throws an error that "it can't convert complex object to simple objects....", which is ironic because that's what it's supposed to do. I need to use XMLTransform() which requires the first argument to be an xml string. But I also need to use xmlSearch() to get a node to pass into my transform, and xmlSearch returns an xmlObject. So now I need to put that object back into xml string format to pass into xmlTransform.

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  • Syntax Error? When parsing XML value

    - by Ace Munim
    I don't know if I'm having a syntax error but the compiler is giving me TypeError: 'undefined' is not an object (evaluating 'xmlDoc.getElementsByTagName("icon")[i].childNodes') Its me giving me this problem when im parsing the XML from my server, my actual javascript code is like this var xmlDoc = Obj.responseXML; var count = 0; if(xmlDoc){ while(count <= xmlDoc.getElementsByTagName("item").length){ document.getElementById("flow").innerHTML += "<div class='item'><img class='content' src='" + xmlDoc.getElementsByTagName("icon")[i].childNodes[0].nodeValue.replace(/\s+$/g,' ') +"' /></div>"; count++; } }else{ alert("Unable to parse!"); } and my XML goes like this. <feed> <item> <title>Given Title</title> <icon> http://i178.photobucket.com/albums/w255/ace003_album/Logo-ETC-RGB-e1353503652739.jpg </icon> </item> <item>...</item> <item>...</item> <item>...</item> <item>...</item> <item>...</item> <item>...</item> </feed> i just want to parse the image link and to show it.

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  • Multiple XML/XSLT files in PHP, transform one with XSLT and add others but process it first with PHP

    - by ipalaus
    I am processing XML files transformations with XSLT in PHP correctly. Actually I use this code: $xml = new DOMDocument; $xml->LoadXML($xml_contents); $xsl = new DOMDocument; $xsl->load($xsl_file); $proc = new XSLTProcesoor; $proc->importStyleSheet($xsl); echo $proc->transformToXml($xml); $xml_contents is the XML processed with PHP, this is done by including the XML file first and then assigning $xml_contents = ob_get_contents(); ob_end_clean();. This forces to process the PHP code on the XML, and it works perfectly. My problem is that I use more than one XML file and this XML files has PHP code on it that need to be processed AND have a XSLT file associated to process the data. Actually I'm including this files in XSLT with the next code: <!-- First I add the XML file --> <xsl:param name="menu" select="document('menu.xml')" /> <!-- Next I add the transformations for menu.xml file --> <xsl:include href="menu.xsl" /> <!-- Finally, I process it on the actual ("parent") XML --> <xsl:apply-templates select="$menu/menu" /> My questiion is how I can handle this. I need to add mutiple XML(+XSLT) files to my first XML file that will containt PHP so it needs to be processed. Thank you in advance!

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  • Inheriting XML files and modifying values

    - by Veehmot
    This is a question about concept. I have an XML file, let's call it base: <base id="default"> <tags> <tag>tag_one</tag> <tag>tag_two</tag> <tag>tag_three</tag> </tags> <data> <data_a>blue</data_a> <data_b>3</data_b> </data> </base> What I want to do is to be able to extend this XML in another file, modifying individual properties. For example, I want to inherit that file and make a new one with a different data/data_a node: <base id="green" import="default"> <data> <data_a>green</data_a> </data> </base> So far it's pretty simple, it replaces the old data/data_a with the new one. I even can add a new node: <base id="ext" import="default"> <moredata> <data>extended version</data> </moredata> </base> And still it's pretty simple. The problem comes when I want to delete a node or deal with XML Lists (like the tags node). How should I reference a particular index on a list? I was thinking doing something like: <base id="diffList" import="default"> <tags> <tag index="1">this is not anymore tag_two</tag> </tags> </base> And for deleting a node / array index: <base id="deleting" import="default"> <tags> <tag index="2"/> </tags> <data/> </base> <!-- This will result in an XML containing these values: --> <base> <tag>tag_one</tag> <tag>tag_two</tag> </base> But I'm not happy with my solutions. I don't know anything about XSLT or other XML transformation tools, but I think someone must have done this before. The key goal I'm looking for is ease to write the XML by hand (both the base and the "extended"). I'm open to new solutions besides XML, if they are easy to write manually. Thanks for reading.

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  • How to make restrictions on XML Schema Complex type?

    - by chobo2
    Hi I am reading the tutorials on w3cschools ( http://www.w3schools.com/schema/schema_complex.asp ) but they don't seem to mention how you could add restrictions on complex types. Like for instance I have this schema. <xs:element name="employee"> <xs:complexType> <xs:sequence> <xs:element name="firstname" type="xs:string"/> <xs:element name="lastname" type="xs:string"/> </xs:sequence> </xs:complexType> </xs:element> now I want to make sure the firstname is no more then 10 characters long. How do I do this? I tried to put in the simple type for the firstname but it says I can't do that since I am using a complex type. So how do I put restrictions like that on the file so the people who I give the schema to don't try to make the firstname 100 characters.

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  • DocumentBuilder.parse() / Parsing Entities

    - by stormin986
    I'm new to parsing XML and am having an issue with entities. (Am doing this on Android, if it makes a difference). Is there a way to have it turn an entity into the character it represents? I have this in the child of an element: "isn&#39;t" (minus quotes). I would prefer it parse it and the end result be a single text node. However, right now this is turned in to TEXT, ENTITY, TEXT. Is there a way to automatically have it parse the entity into text, or a manual way to do it?

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  • XSLT : I need to parse the xml with same element name with sequence of order to map in to another xml with different name

    - by Karuna
    As the below source XML Value/string element value has to be replace with target element value, Could some please help me out how to create the XSL to transform from source xml into target xml .Please. Source XML: <PricingResultsV6> <subItems> <SubItem> <profiles> <ProfileValues> <values> <strings>800210</strings> <strings>THC</strings> <strings>10.0</strings> <strings>20.0</strings> <strings>30.0</strings> <strings>40.0</strings> <strings>550.0</strings> <strings>640.0</strings> </values> </ProfileValues> </rofiles> </SubItem> </subItems> </PricingResultsV6> Target XML : <CalculationOutput> <PolicyNumber> 800210 </PolicyNumber> <CommissionFactorMultiplier> THC </CommissionFactorMultiplier> <PremiumValue>10.0</PremiumValue> <SalesmanCommissionValue>20.0</SalesmanCommissionValue> <ManagerCommissionValue>30.0</ManagerCommissionValue> <GL_COR> 550.0</GL_COR> <GL_OPO>640.0</GL_OPO> </CalculationOutput>

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  • Webserver directory index: index.xml?

    - by Marius
    Hello there, I am making my first RSS-Feed, and I want to host it like this: www.example.com/rss/ I tried to name the xml-file "index.xml" and place it inside the directory, however, when I type http://www.example.com/rss/ i arrive at "Index of /rss" where the file is listed as being part of the directory, but it is not loaded automatically. What can be done about this? Thank you for your time. Kind regards, Marius

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  • Displaying XML in Chrome Browser

    - by Josh
    I love the Chrome browser but I use XML quite a lot in my development work and when I view it in Chrome I just get the rendered text. I know that the source view is slightly better but I'd really like to see the layout and functionality that IE adds to XML namely: Highlighting Open/close nodes Any ideas how I can get this on Chrome? Thanks, Josh UPDATE: The XMLTree Extension is available on Google Chrome Extension Beta Site. Thanks again for your help.

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  • Retrieve MS SQL database or table struture in XML

    - by clutch
    Is there a way to export the database schema in well formed XML of a MS 2000 SQL Server. I'm looking for just the structure not the data and the more detailed the better. The XML may be used in a migration processes. I'm more familiar with MySQL then with SQL Server so please be detailed if you hav time. Thanks

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  • Search in multiple xml files

    - by Ram
    I have a windows Xp Sp2 system where the windows explorer search is not able to find the text in xml files. Is there some setting that enable the search in xml files? It finds in text in text / doc files in the same folder.

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  • Notepad++ Reindent XML breaks lines.

    - by C. Ross
    I'm attempting to use Notepad++ TextFX HTMLTidy - Tidy: Reindent XML. This works well with the following exception. Lines longer than 70 character are wrapped, breaking the validity of my xml. This: <RevieweeDepartmentName>BB AAAAAAAAAA AAAAAAAAAA AAAA</RevieweeDepartmentName> Becomes this: <RevieweeDepartmentName>BB AAAAAAAAAA AAAAAAAAAA AAAA</RevieweeDepartmentName> How can I get it to stop this behavior?

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  • Retrieve MS SQL database or table structure in XML

    - by clutch
    Is there a way to export the database schema in well formed XML of a MS 2000 SQL Server. I'm looking for just the structure not the data and the more detailed the better. The XML may be used in a migration processes. I'm more familiar with MySQL then with SQL Server so please be detailed if you have time. Thanks

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  • Should all new web projects build their backend based on xml/json result sets?

    - by Blankman
    If you were building a new Saas project, would it make sense to start with all of the backend services returning xml/json? Because these days you need to build for both the web and mobile devices, and having a backend that is build from the start to return xml and json, you are ready to go mobile (all services have the business logic, so you won't be repeating anything). Now the web would be MVC, so the controller would just be routing the request to your service backend, and converting the json or xml to html. The obviousl downside is that you have to build a backend, and then another web project that calls your backend. But this also goes to you favor as it forces you to seperate your concerns, and not leak business logic in your controller/view layer. Thoughts?

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  • Mixing Silverlight-Specific System.Xml.Linq dll with Non-Silverlight System.Xml.Linq dll

    - by programatique
    I have a Logic layer that references Silverlight's System.Xml.Linq dll and a GUI that is in WPF (hence using the non-Silverlight System.Xml.Linq dll). When I attempt to pass an XElement from GUI project to a method in the Logic project, I am getting (basically) "XElement is not of type XElement" errors. To complicate matter, I am unable to edit the Logic layer project. The Non-Silverlight DLL is at: C:\Program Files (x86)\Reference Assemblies\Microsoft\Framework\v3.5\System.Xml.Linq.dll THe Silverlight DLL is at: C:\Program Files (x86)\Microsoft SDKs\Silverlight\v3.0\Libraries\Client\System.Xml.Linq.dll I am new to C# but I'm fairly sure my issue is that I am referencing different DLL's to access the System.Xml.Linq namespace. I attempted to replace my non-Silverlight System.Xml.Linq.dll with the Silverlight's System.Xml.Linq.dll, but received assembly errors. Is there any way to resolve this short of scrapping my WPF GUI project and creating a Silverlight project?

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