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  • jQuery: Show and hide child div when hovering

    - by Björn
    Hi there, I've got a set of items. Each item has two images and some text. For the images I've created a parent div which has an overflow:hidden CSS value. I want to achieve an mouseover effect. As soon as you hover over the images I want to hide the current div and show the second div. Here's a small snippet: <div class="product-images"> <div class="product-image-1"><img src="image1.gif>" /></div> <div class="product-image-2"><img src="images2.gif" /></div> </div> I've created a small jQuery snippet: jQuery(document).ready(function() { jQuery('.product-images').mouseover(function() { jQuery('.product-image-1').hide(); }).mouseout(function() { jQuery('.product-image-1').show(); }); }); Now the problem is that not only the currently hovered child is hidden. Instead all other existing childs are hidden as well. I need something like "this" or "current" but I don't know which jQuery function is the right one. Any idea? Thanks, BJ

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  • How can I set a Java applet transparency to show contents behind it?

    - by yuri
    I've got a web page with an applet inside. This applet is a drop target on a drag and drop action from the OS, I simply take an image from a folder, drag it on the applet and something happens. I give this webpage to a graphic designer and he ask to if he can put an image behind the java applet so he can simulate to change the background using CSS (it is a skinned app and graphic design can change during execution). Practically i supposed to do: <div> <applet width="50" height="50" /> </div> with this CSS: div { width:50px; height:50px; background-image: url(image.jpg) center center no-repeat; } But it doesn't work (background is opaque). It is possible to set transparency to the applet without loosing drag and drop capabilities ? I'm searching something similar to flash wmode parameter. Better solutions implies only changes on the CSS/HTML without recompiling java class so the designing team can change the page structure without changing the Java.

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  • problem creating jpg thumb with php

    - by Ross
    Hi, I am having problems creating a thumbnail from an uploaded image, my problem is (i) the quality (ii) the crop http://welovethedesign.com.cluster.cwcs.co.uk/phpimages/large.jpg http://welovethedesign.com.cluster.cwcs.co.uk/phpimages/thumb.jpg If you look the quality is very poor and the crop is taken from the top and is not a resize of the original image although the dimesions mean it is in proportion. The original is 1600px wide by 1100px high. Any help would be appreciated. $thumb = $targetPath."Thumbs/".$fileName; $imgsize = getimagesize($targetFile); $image = imagecreatefromjpeg($targetFile); $width = 200; //New width of image $height = 138; //This maintains proportions $src_w = $imgsize[0]; $src_h = $imgsize[1]; $thumbWidth = 200; $thumbHeight = 138; // Intended dimension of thumb // Beyond this point is simply code. $sourceImage = imagecreatefromjpeg($targetFile); $sourceWidth = imagesx($sourceImage); $sourceHeight = imagesy($sourceImage); $targetImage = imagecreate($thumbWidth,$thumbHeight); imagecopyresized($targetImage,$sourceImage,0,0,0,0,$thumbWidth,$thumbWidth,imagesx($sourceImage),imagesy($sourceImage)); //imagejpeg($targetImage, "$thumbPath/$thumbName"); imagejpeg($targetImage, $thumb); chmod($thumb, 0755);

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  • xsl transform: problem with Ampersand URL parameters

    - by Rac123
    I'm having issues with transforming XSL with parameters in a URL. I'm at a point that I can't change the C# code anymore, only can make changes to xsl file. C# code: string xml = "<APPLDATA><APPID>1052391</APPID></APPLDATA>"; XmlDocument oXml = new XmlDocument(); oXml.LoadXml(xml); XslTransform oXslTransform = new XslTransform(); oXslTransform.Load(@"C:\Projects\Win\ConsoleApps\XslTransformTest\S15033.xsl"); StringWriter oOutput = new StringWriter(); oXslTransform.Transform(oXml, null, oOutput) XSL Code: <body> <xsl:variable name="app"> <xsl:value-of select="normalize-space(APPLDATA/APPID)" /> </xsl:variable> <div id="homeImage" > <xsl:attribute name="style"> background-image:url("https://server/image.gif?a=10&amp;Id='<xsl:value-of disable-output-escaping="yes" select="$app" />'") </xsl:attribute> </div> </body> </html> URL transformed: https://server/image.gif?a=10&Id='1052391' URL Expected: https://server/image.gif?a=10&Id='1052391' How do I fix this? The output (oOutput.ToString()) is being used in an email template so it's taking the URL transformed literally. When you click on this request (with the correct server name of course), the 403 (Access forbidden) error is being thrown.

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  • Python optimization problem?

    - by user342079
    Alright, i had this homework recently (don't worry, i've already done it, but in c++) but I got curious how i could do it in python. The problem is about 2 light sources that emit light. I won't get into details tho. Here's the code (that I've managed to optimize a bit in the latter part): import math, array import numpy as np from PIL import Image size = (800,800) width, height = size s1x = width * 1./8 s1y = height * 1./8 s2x = width * 7./8 s2y = height * 7./8 r,g,b = (255,255,255) arr = np.zeros((width,height,3)) hy = math.hypot print 'computing distances (%s by %s)'%size, for i in xrange(width): if i%(width/10)==0: print i, if i%20==0: print '.', for j in xrange(height): d1 = hy(i-s1x,j-s1y) d2 = hy(i-s2x,j-s2y) arr[i][j] = abs(d1-d2) print '' arr2 = np.zeros((width,height,3),dtype="uint8") for ld in [200,116,100,84,68,52,36,20,8,4,2]: print 'now computing image for ld = '+str(ld) arr2 *= 0 arr2 += abs(arr%ld-ld/2)*(r,g,b)/(ld/2) print 'saving image...' ar2img = Image.fromarray(arr2) ar2img.save('ld'+str(ld).rjust(4,'0')+'.png') print 'saved as ld'+str(ld).rjust(4,'0')+'.png' I have managed to optimize most of it, but there's still a huge performance gap in the part with the 2 for-s, and I can't seem to think of a way to bypass that using common array operations... I'm open to suggestions :D

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  • VB.NET trying simple captcha

    - by Pride Grimm
    I'm trying to write a simple captcha program in vb.net. I'm just wanting to make an image from random numbers and display it, check the answer, and then proceed. I'm pretty new to vb.net, so I found some code to generate the information. I will cite the owner when I find it again (http://www.knowlegezone.com/80/article/Technology/Software/Asp-Net/Simple-ASP-NET-CAPTCHA-Tutorial) This is in the onload() of default2.aspx Public Sub returnNumer() Dim num1 As New Random Dim num2 As New Random Dim numQ1 As Integer Dim numQ2 As Integer Dim QString As String numQ1 = num1.Next(10, 15) numQ2 = num2.Next(17, 31) QString = numQ1.ToString + " + " + numQ2.ToString + " = " Session("answer") = numQ1 + numQ2 Dim bitmap As New Bitmap(85, 35) Dim Grfx As Graphics = Graphics.FromImage(bitmap) Dim font As New Font("Arial", 18, FontStyle.Bold, GraphicsUnit.Pixel) Dim Rect As New Rectangle(0, 0, 100, 50) Grfx.FillRectangle(Brushes.Brown, Rect) Grfx.DrawRectangle(Pens.PeachPuff, Rect) ' Border Grfx.DrawString(QString, font, Brushes.Azure, 0, 0) Response.ContentType = "Image/jpeg" bitmap.Save(Response.OutputStream, System.Drawing.Imaging.ImageFormat.Jpeg) bitmap.Dispose() Grfx.Dispose() End Sub So I put this in a separate page, like this This all works find and dandy, but when I get the answer from the session like this Dim literal As String = Convert.ToString(Session("answer")) It's always one behind. So if The images adds to 32, the answer in session isn't 32. But after a refresh (and a new image) the session("answer") will be 32. Is there a way to refresh the session on page 1, after the default2.aspx loads? Is there a better way to do this? I though about trying to run the code all on one page, and trying to set the src of and image to returnNumber(), but I need a bit of help on that one.

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  • Django 1.5 custom User model error. "Manager isn't available; User has been swapped"

    - by bpetit
    I extend the django user model as described in the dev doc. I wan't to keep most of the original User model features so I extend the AbstractUser class. I've defined in settings.py: AUTH_USER_MODEL = 'myapp.CustomUser' My user class: class CustomUser(AbstractUser): custom_field = models.ForeignKey('OtherModel') objects = UserManager() Everything seems to work fine but when I try to make it managed by the admin site: admin.site.register(CustomUser, UserAdmin) I get this error on the admin CustomUser creation page (after validation of the password confirmation form): AttributeError: Manager isn't available; User has been swapped for 'myapp.CustomUser' The point is that I need this model managed by the admin site in order to have the same creation process as with the original User model (two step process with password validation). Thanks for any reply

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  • Relative path in JLabel HTML

    - by kroiz
    Hi, I am trying to make JLabel show an html which is referencing an image using a relative path. But I cannot make JLabel locate the image. It works fine when I am using absolute path. I have tried running the program from the command line or from eclipse and add dialog to show me where is the current working directory but for avail. I have therefor came to the conclusion that the image is not searched in the current directory - which brings me to the point. where is the image looked for? here is a test code that show what I am doing: import javax.swing.*; public class HTMLLabel extends JFrame { public HTMLLabel() { setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); JOptionPane.showMessageDialog( this, System.getProperty("user.dir")); String html = "<html>\n" + " <body>\n" + " <div style=\"text-align: center;\">\n" + " <img src=\"file://s.png\">\n"+ " </div>\n"+ " </body>\n"+ "</html>"; JLabel label = new JLabel(html); add(label); pack(); setVisible(true); } public static void main(String[] args) { new HTMLLabel(); } }

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  • Load images into separate movie clips from a XML, Flash, Actionscript 3.0

    - by James Dunay
    I have an xml image bank, pretty standard, and I have a loader, along with movie clips that I want the images loaded into, the problem that I am running into is I want the images to load into separate movie clips, so I’m using a case statement to specify where they go. However, I can only get them to load into a single movie clip, I assume they are loading ontop of each other and I don’t know how to get them to separate out. I’ll post my code. It doesn’t make any sense to me but if you have any suggestions that would be real great. I can make separate loaders and then just do 1 image per loader, but that just doesn’t sound right to me. var counterNumber:Number = 0; function callThumbs():void{ for (var i:Number = 0; i <3; i++){ thumbLoaded(); counterNumber++; } } function thumbLoaded(){ var photoLoader = new Loader(); switch (counterNumber){ case 1: photoLoader.load(new URLRequest(MovieClip(this.parent).xml.photos.imageOne.image.@url[0])); whole.boxOne.pictureLoader.addChild(photoLoader); trace("1Done"); break; case 2: photoLoader.load(new URLRequest(MovieClip(this.parent).xml.photos.imageTwo.image.@url[0])); whole.boxTwo.pictureLoader.addChild(photoLoader); trace("2Done"); break; } }

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  • css caption issue

    - by Moode Osman
    i have problem with caption to make caption appear under each photo when hover over it but thr problem here they appear all on one side one place the left bottom side here the code for HTML <div id="content2"> <ul style="width: 5020px; height: 600px;"> <li class="image" style="width: 392px;"><img src="images/pr1x.jpg" ><p class="caption">1st caption</p></li> <li class="image" style="width: 392px;"><img src="images/pr2x.jpg" ><p class="caption">2st caption</p></li> </ul></div> here the code for CSS li.image p.caption { position:absolute; display: none; font-size: 28px; color: red; } li.image:hover p.caption { display: list-item; }? #content2{ width: 150%; height: 600px; float:left; overflow:hidden; } #content2 p{ width: 150%; } .scrollbar-hor{ background-color: #e5e2de; height: 24px; width: 150%; float:left; } .handle-hor{ height: 25px; width: 400px; background: url(http://brafitting.info/images/bar.jpg) no-repeat; } plz help ty

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  • javascript - rollover effect on overlapping transparent images

    - by user427969
    I want to add rollover effect on overlapping transparent images. For example: The following image is divided into 5 parts and I want to add rollover effect (different image) on each of them When O tried with div or img tag, the image is rendered as a rectangle so rollover effect is not proper. When i rollover on green part between yellow, the yellow image gets highlighted because its z-index is high. Following is the code that I tried: <body> <br /> <img src="part1.png" onclick="console.log('test1');"/> <img src="part2.png" onclick="console.log('test2');" style="position:absolute; left:30px; top: 19px;"/> <img src="part3.png" onclick="console.log('test3');" style="position:absolute; left:70px; top: 15px;"/> <img src="part4.png" onclick="console.log('test4');" style="position:absolute; left:95px; top: 16px;"/> <img src="part5.png" onclick="console.log('test5');" style="position:absolute; left:123px; top: 24px;"/> </body> images = , , , , I don't want to use jQuery, if possible.

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  • Hibernate: how to maintain insertion order

    - by jwaddell
    I have a list of entities where creation order is important, but they do not contain a timestamp to use for sorting. Entities are added to the end of the list as they are created so they will be ordered correctly in the list itself. After persisting the list using Hibernate the entities appear in the database table in the order that they were created. However when retrieving the list using a new Hibernate session the list is now in reverse order of insertion/creation. Is this expected behaviour? Is there any way to retrieve the list in the same order as it appears in the table? The primary key is a UUID, and the list of entities should always have been created on the same IP address and JVM. This mean sorting by UUID is a possibility but I'd rather not make assumptions. Another possibility is if the list is guaranteed to always come out in reverse order I could always just work through it backwards.

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  • Very very weird problem with UIImageView property - I can access it then I can't, and it's not nil.

    - by just_another_coder
    Very very weird problem with UIImageView property on iPad application @interface MyViewController : UIViewController { IBOutlet UIImageView* coverImage; } @property(nonatomic, retain) IBOutlet UIImageView* coverImage; … more code @implementation MyViewController @synthesize coverImage; … more code - (void)viewDidLoad { [super viewDidLoad]; NSString* imageName = @"my_image.png"; UIImage* tempImage = [UIImage imageNamed:imageName]; [self.coverImage setImage:tempImage]; } The above code WILL display the image. In another part of code: -(IBAction) stopButtonPressed:(id)sender { [self.coverImage setHidden:YES]; NSLog(@"coverImage desc: %@", [coverImage description]); } The image will NOT disappear. I know the reference to the image isn't nil, because it gives me this output: 2010-05-29 17:37:40.706 MyApp[95360:207] coverImage desc: UIImageView: 0x5128420; frame = (0 0; 1024 768); autoresize = RM+BM; userInteractionEnabled = NO; layer = CALayer: 0x512bed0 In addition, if I move the code in viewDidLoad to another part of the class, and try to execute it from there, it fails to show the image at all.

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  • Sharing same vector control between different places

    - by Alexander K
    Hi everyone, I'm trying to implement the following: I have an Items Manager, that has an Item class inside. Item class can store two possible visual representations of it - BitmapImage(bitmap) and UserControl(vector). Then later, in the game, I need to share the same image or vector control between all possible places it takes place. For example, consider 10 trees on the map, and all point to the same vector control. Or in some cases this can be bitmap image source. So, the problem is that BitmapImage source can be easily shared in the application by multiple UIElements. However, when I try to share vector control, it fails, and says Child Element is already a Child element of another control. I want to know how to organize this in the best way. For example replace UserControl with other type of control, or storage, however I need to be sure it supports Storyboard animations inside. The code looks like this: if (bi.item.BitmapSource != null) { Image previewImage = new Image(); previewImage.Source = bi.item.BitmapSource; itemPane.ItemPreviewCanvas.Children.Add(previewImage); } else if (bi.item.VectorSource != null) { UserControl previewControl = bi.item.VectorSource; itemPane.ItemPreviewCanvas.Children.Add(previewControl); } Thanks in advance

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  • Moving Multiple Divs With Same Class Inside Parent

    - by superzilla
    So, My website is hosted on enjin.com and when you give users a tag with an image it appears on the forums under their name, however it's a vertical list with the tag names. I want to organize it so all of the tag images appear on one line and all of the tag names appear on a horizontal list below it. They use div tags somewhat like this <div class="tag"> <div class="tag-image"></div> <!-- If the tag lacks an image this is excluded --> <div class="tag-text">Tag Name</div> <!-- If you want the name to be hidden this is excluded --> </div> They then pretty much repeat this for every tag. Somewhat the same thing is used for forum posts too. So, I want to move all the tag-image divs together on a single line and all of the tag-text divs down and give each it's own line. I only want to move them within their parent element (to avoid images/tags from one forum user from going to another). I know how to append things with jquery and have googled how to move elements around, but I'm afraid that they're all going to end up together under another user's avatar.

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  • Increasing figure size in Matplotlib

    - by Anirudh
    I am trying to plot a graph from a distance matrix. The code words fine and gives me a image in 800 * 600 pixels. The image being too small, All the nodes are packed together. I want increase the size of the image. so I added the following line to my code - figure(num=None, figsize=(10, 10), dpi=80, facecolor='w', edgecolor='k') After this all I get is a blank 1000 * 1000 image file. My overall code - import networkx as nx import pickle import matplotlib.pyplot as plt print "Reading from pickle." p_file = open('pickles/names') Names = pickle.load(p_file) p_file.close() p_file = open('pickles/distance') Dist = pickle.load(p_file) p_file.close() G = nx.Graph() print "Inserting Nodes." for n in Names: G.add_node(n) print "Inserting Edges." for i in range(601): for j in range(601): G.add_edge(Names[i],Names[j],weight=Dist[i][j]) print "Drawing Graph." nx.draw(G) print "Saving Figure." #plt.figure(num=None, figsize=(10, 10)) plt.savefig('new.png') print "Success!"

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  • Converting contents of a byte array to wchar_t*

    - by Christopher MacKinnon
    I seem to be having an issue converting a byte array (containing the text from a word document) to a LPTSTR (wchar_t *) object. Every time the code executes, I am getting a bunch of unwanted Unicode characters returned. I figure it is because I am not making the proper calls somewhere, or not using the variables properly, but not quite sure how to approach this. Hopefully someone here can guide me in the right direction. The first thing that happens in we call into C# code to open up Microsoft Word and convert the text in the document into a byte array. byte document __gc[]; document = word->ConvertToArray(filename); The contents of document are as follows: {84, 101, 115, 116, 32, 68, 111, 99, 117, 109, 101, 110, 116, 13, 10} Which ends up being the following string: "Test Document". Our next step is to allocate the memory to store the byte array into a LPTSTR variable, byte __pin * value; value = &document[0]; LPTSTR image; image = (LPTSTR)malloc( document->Length + 1 ); Once we execute the line where we start allocating the memory, our image variable gets filled with a bunch of unwanted Unicode characters: ????????????????? And then we do a memcpy to transfer over all of the data memcpy(image,value,document->Length); Which just causes more unwanted Unicode characters to appear: ????????????????? I figure the issue that we are having is either related to how we are storing the values in the byte array, or possibly when we are copying the data from the byte array to the LPTSTR variable. Any help with explaining what I'm doing wrong, or anything to point me in the right direction will be greatly appreciated.

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  • Android Camera intent creating two files

    - by Kyle Ramstad
    I am making a program that takes a picture and then shows it's thumbnail. When using the emulator all goes well and the discard button deletes the photo. But on a real device the camera intent saves the image at the imageUri variable and a second one that is named like if I had just opened up the camera and took a picture by itself. private static final int CAMERA_PIC_REQUEST = 1337; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.camera); //start camera values = new ContentValues(); values.put(MediaStore.Images.Media.TITLE, "New Picture"); values.put(MediaStore.Images.Media.DESCRIPTION,"From your Camera"); imageUri = getContentResolver().insert(MediaStore.Images.Media.EXTERNAL_CONTENT_URI, values); image = (ImageView) findViewById(R.id.ImageView01); Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE); intent.putExtra(MediaStore.EXTRA_OUTPUT, imageUri); startActivityForResult(intent, CAMERA_PIC_REQUEST); //save the image buttons Button save = (Button) findViewById(R.id.Button01); Button close = (Button) findViewById(R.id.Button02); } @Override protected void onActivityResult(int requestCode, int resultCode, Intent data) { if (requestCode == CAMERA_PIC_REQUEST && resultCode == RESULT_OK) { try{ thumbnail = MediaStore.Images.Media.getBitmap(getContentResolver(), imageUri); image.setImageBitmap(thumbnail); } catch(Exception e){ e.printStackTrace(); } } else{ finish(); } } public void myClickHandler(View view) { switch (view.getId()) { case R.id.Button01: finish(); break; case R.id.Button02: dicard(); } } private void dicard(){ getContentResolver().delete(imageUri, null, null); finish(); }

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  • Can't get gravity to work with RMagick and 'caption'

    - by mph
    I'm using RMagick 2.12.2 with ImageMagick 6.5.6-10 on Snow Leopard. I'm trying to put captions on a collection of photos, and I'm getting the caption to work (i.e. it appears on the image), but I can't get the gravity parameter to work correctly. No matter what I set it to, I end up with some variation on NorthGravity. For instance: Setting it to SouthWestGravity gives me NorthWestGravity. Setting it to SouthEastGravity gives me NorthEastGravity. Setting it to CenterGravity gives me NorthGravity. In other words, I can't get the caption to come down off the top of the image. I'd consider using "annotate," but I need "caption" so the lengthy caption text for each image will wrap. What am I doing wrong? Here's the code: #!/usr/bin/env ruby require "rubygems" require "yaml" require "RMagick" include Magick base_dir = "/Users/mike/Desktop/caption_test" photo_log = File.open("#{base_dir}/photo_log.yaml" ) YAML::load_documents(photo_log) do |doc| caption = doc["photo-caption"] filename = doc["file"] canvas = ImageList.new.from_blob(open("#{base_dir}/#{filename}") { |f| f.read } ) canvas << Magick::Image.read("caption:#{caption}") { self.gravity = SouthWestGravity self.size = "#{canvas.first.columns}" self.font = "Helvetica Neue" self.pointsize = 12 self.background_color = "#fff" }.first canvas.flatten_images.write("#{base_dir}/images/#{filename}") end

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  • setting write permissions on theme subdirectory?

    - by Scott B
    I've a theme which supports multiple templates, each with a header background image whose color can be set by the site owner via a colorpicker widget in my theme's options panel. This has the effect of opening the background image, recoloring it and resaving it back to the server. I've had zero issues with this routine until recently when a customer installed the theme on a web host whose default read/write permissions are apparently much more restrictive than the norm. In this case, the user was unable to alter the colors of the template images because of the permissions settings. I'm looking for a bit of understanding on what the permissions would need to be (assuming I purposefully set them via script) to allow the logged in wordpress user to write to files under my theme's styles directory. The code I'm using to write to the image file is below... $img = imagecreatefromgif("../wp-content/themes/mytheme/styles/".get_option('my_theme')."/image.gif"); $color = imagecolorallocate($img, $info["red"], $info["green"], $info["blue"]); imagecolorset($img, 0, $info["red"], $info["green"], $info["blue"]); imagegif($img, $path);

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  • PhotoChooserTask + Navigation.

    - by user562405
    I taken two Images & added event (MouseButtonDown) for them. When first image handles event to open Gallery. Second image handles events for open camera. When user has choosed his image from the gallery, I want to navigate to next page. Its navigates. But before completing navigation process, it displays MainPage & then moves toward next page. I didnt want to display the MainPage once user chooses the image from the gallery. Plz help. Thanks in advance. public partial class MainPage : PhoneApplicationPage { PhotoChooserTask objPhotoChooser; CameraCaptureTask cameraCaptureTask; // Constructor public MainPage() { InitializeComponent(); objPhotoChooser = new PhotoChooserTask(); objPhotoChooser.Completed += new EventHandler<PhotoResult>(objPhotoChooser_Completed); cameraCaptureTask = new CameraCaptureTask(); cameraCaptureTask.Completed += new EventHandler<PhotoResult>(objCameraCapture_Completed); } void objPhotoChooser_Completed(object sender, PhotoResult e) { if (e != null && e.TaskResult == TaskResult.OK) { //Take JPEG stream and decode into a WriteableBitmap object App.CapturedImage = PictureDecoder.DecodeJpeg(e.ChosenPhoto); //Delay navigation until the first navigated event NavigationService.Navigated += new NavigatedEventHandler(navigateCompleted); } } void navigateCompleted(object sender, EventArgs e) { //Do the delayed navigation from the main page this.NavigationService.Navigate(new Uri("/ImageViewer.xaml", UriKind.RelativeOrAbsolute)); NavigationService.Navigated -= new NavigatedEventHandler(navigateCompleted); } void objCameraCapture_Completed(object sender, PhotoResult e) { if (e.TaskResult == TaskResult.OK) { //Take JPEG stream and decode into a WriteableBitmap object App.CapturedImage = PictureDecoder.DecodeJpeg(e.ChosenPhoto); //Delay navigation until the first navigated event NavigationService.Navigated += new NavigatedEventHandler(navigateCompleted); } } protected override void OnBackKeyPress(System.ComponentModel.CancelEventArgs e) { e.Cancel = true; } private void image1_MouseLeftButtonDown(object sender, MouseButtonEventArgs e) { objPhotoChooser.Show(); } private void image2_MouseLeftButtonDown(object sender, MouseButtonEventArgs e) { cameraCaptureTask.Show(); }

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  • How i display my scrollView instaed of splash screen?

    - by Rajendra Bhole
    HI, I develop an application in which i want to implement the splash screen, on that splash screen i want to bind the scrollView and UIImage. My code as follow, -(void)splashAnimation{ window = [[UIWindow alloc] initWithFrame:CGRectMake(0, 0, 320, 420)]; //scrollView = [[UIScrollView alloc] initWithFrame:[[UIScreen mainScreen] applicationFrame]]; scrollView = [[UIScrollView alloc] initWithFrame:[window bounds]]; scrollView.pagingEnabled = NO; scrollView.bounces = NO; UIImage *image = [UIImage imageNamed:@"splash.png"]; UIImageView *imageView = [[UIImageView alloc] initWithImage:image]; imageView.userInteractionEnabled = NO; [scrollView addSubview:imageView]; [scrollView setDelegate:self]; //[scrollView release]; /* window = [[UIWindow alloc] initWithFrame:CGRectMake(0, 0, 320, 420)]; UIView *splashView = [[UIView alloc] initWithFrame:[window bounds]]; UIImage *image = [UIImage imageNamed:@"splash.png"]; [splashView addSubview: [[UIImageView alloc] initWithImage:image]]; [window addSubview:splashView]; [window makeKeyAndVisible]; [window removeFromSuperview]; } - (void)applicationDidFinishLaunching:(UIApplication *)application { [self splashAnimation]; [self initControllers]; [window addSubview:[mainTabBarController view]]; [window makeKeyAndVisible]; } On my given code the one blank window comes up and stay on. I want to on that blank screen bind my splash.png.

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  • PHP Outputting File Attachments with Headers

    - by OneNerd
    After reading a few posts here I formulated this function which is sort of a mishmash of a bunch of others: function outputFile( $filePath, $fileName, $mimeType = '' ) { // Setup $mimeTypes = array( 'pdf' => 'application/pdf', 'txt' => 'text/plain', 'html' => 'text/html', 'exe' => 'application/octet-stream', 'zip' => 'application/zip', 'doc' => 'application/msword', 'xls' => 'application/vnd.ms-excel', 'ppt' => 'application/vnd.ms-powerpoint', 'gif' => 'image/gif', 'png' => 'image/png', 'jpeg' => 'image/jpg', 'jpg' => 'image/jpg', 'php' => 'text/plain' ); // Send Headers //-- next line fixed as per suggestion -- header('Content-Type: ' . $mimeTypes[$mimeType]); header('Content-Disposition: attachment; filename="' . $fileName . '"'); header('Content-Transfer-Encoding: binary'); header('Accept-Ranges: bytes'); header('Cache-Control: private'); header('Pragma: private'); header('Expires: Mon, 26 Jul 1997 05:00:00 GMT'); readfile($filePath); } I have a php page (file.php) which does something like this (lots of other code stripped out): // I run this thru a safe function not shown here $safe_filename = $_GET['filename']; outputFile ( "/the/file/path/{$safe_filename}", $safe_filename, substr($safe_filename, -3) ); Seems like it should work, and it almost does, but I am having the following issues: When its a text file, I am getting a strange symbol as the first letter in the text document When its a word doc, it is corrupt (presumably that same first bit or byte throwing things off). I presume all other file types will be corrupt - have not even tried them Any ideas on what I am doing wrong? Thanks - UPDATE: changed line of code as suggested - still same issue.

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