This returns mysql_error:
<?php
$name = $_POST['inputName2'];
$email = $_POST['inputEmail2'];
$instruments = $_POST['instruments'];
$city = $_POST['inputCity'];
$country = $_POST['inputCountry'];
$distance = $_POST['distance'];
// ^^ These all echo properly ^^
// CONNECT TO DB
$dbhost = "xxx";
$dbname = "xxx";
$dbuser = "xxx";
$dbpass = "xxx";
$con = mysqli_connect("$dbhost", "$dbuser", "$dbpass", "$dbname");
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$query = "INSERT INTO depfinder (name, email, instrument1, instrument2, instrument3, instrument4, instrument5, city, country, max_distance) VALUES ($name, $email, $instruments[0], $instruments[1], $instruments[2], $instruments[3], $instruments[4], $city, $country, $max_distance)";
$result = mysqli_query($con, $query) or die(mysqli_error($con)); // script fails here
if (!$result)
{
echo "There was a problem with the signup process. Please try again later.";
}
else
{
echo "Success";
}
}
?>
N.B. I'm not sure whether it's relevant, but the user may not choose five instruments so some $instrument[] array values may be empty.
Bonus question: is my script secure enough or is there more I could do?
