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  • Is there an exponent operator in C#?

    - by Charlie
    For example, does an operator exist to handle this? float Result, Number1, Number2; Number1 = 2; Number2 = 2; Result = Number1 (operator) Number2; In the past the ^ operator has served as an exponential operator in other languages, but in C# it is a bit-wise operator. Do I have to write a loop or include another namespace to handle exponential operations? If so, how do I handle exponential operations using non-integers?

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  • Prefix and Postfix operator's necessity

    - by Karthi prime
    What is the necessity of both prefix and postfix increment operators? Is not one enough? To the point, there exists like a similar while/do-while necessity problem, yet, there in no so much confusion (in understanding and usage) in having them, but with having both prefix and postfix (like priority of these operators, their association, usage, working). And do anyone been through a situation where you saidd "Hey, I am going to use postfix increment. Its useful here"

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  • Consistency in placing operator functions

    - by wrongusername
    I have a class like this: class A { ...private functions, variables, etc... public: ...some public functions and variables... A operator * (double); A operator / (double); A operator * (A); ...and lots of other operators } However, I want to also be able to do stuff like 2 * A instead of only being allowed to do A * 2, and so I would need functions like these outside of the class: A operator * (double, A); A operator / (double, A); ...etc... Should I put all these operators outside of the class for consistency, or should I keep half inside and half outside?

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  • Implementing a non-public assignment operator with a public named method?

    - by Casey
    It is supposed to copy an AnimatedSprite. I'm having second thoughts that it has the unfortunate side effect of changing the *this object. How would I implement this feature without the side effect? EDIT: Based on new answers, the question should really be: How do I implement a non-public assignment operator with a public named method without side effects? (Changed title as such). public: AnimatedSprite& AnimatedSprite::Clone(const AnimatedSprite& animatedSprite) { return (*this = animatedSprite); } protected: AnimatedSprite& AnimatedSprite::operator=(const AnimatedSprite& rhs) { if(this == &rhs) return *this; destroy_bitmap(this->_frameImage); this->_frameImage = create_bitmap(rhs._frameImage->w, rhs._frameImage->h); clear_bitmap(this->_frameImage); this->_frameDimensions = rhs._frameDimensions; this->CalcCenterFrame(); this->_frameRate = rhs._frameRate; if(rhs._animation != nullptr) { delete this->_animation; this->_animation = new a2de::AnimationHandler(*rhs._animation); } else { delete this->_animation; this->_animation = nullptr; } return *this; }

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  • What is the rationale to non allow overloading of C++ conversions operator with non-member functio

    - by Vicente Botet Escriba
    C++0x has added explicit conversion operators, but they must always be defined as members of the Source class. The same applies to the assignment operator, it must be defined on the Target class. When the Source and Target classes of the needed conversion are independent of each other, neither the Source can define a conversion operator, neither the Target can define a constructor from a Source. Usually we get it by defining a specific function such as Target ConvertToTarget(Source& v); If C++0x allowed to overload conversion operator by non member functions we could for example define the conversion implicitly or explicitly between unrelated types. template < typename To, typename From operator To(const From& val); For example we could specialize the conversion from chrono::time_point to posix_time::ptime as follows template < class Clock, class Duration operator boost::posix_time::ptime( const boost::chrono::time_point& from) { using namespace boost; typedef chrono::time_point time_point_t; typedef chrono::nanoseconds duration_t; typedef duration_t::rep rep_t; rep_t d = chrono::duration_cast( from.time_since_epoch()).count(); rep_t sec = d/1000000000; rep_t nsec = d%1000000000; return posix_time::from_time_t(0)+ posix_time::seconds(static_cast(sec))+ posix_time::nanoseconds(nsec); } And use the conversion as any other conversion. So the question is: What is the rationale to non allow overloading of C++ conversions operator with non-member functions?

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  • What's the false operator in C# good for?

    - by Jakub Šturc
    There are two weird operators in C#: the true operator the false operator If I understand this right these operators can be used in types which I want to use instead of a boolean expression and where I don't want to provide an implicit conversion to bool. Let's say I have a following class: public class MyType { public readonly int Value; public MyType(int value) { Value = value; } public static bool operator true (MyType mt) { return mt.Value > 0; } public static bool operator false (MyType mt) { return mt.Value < 0; } } So I can write the following code: MyType mTrue = new MyType(100); MyType mFalse = new MyType(-100); MyType mDontKnow = new MyType(0); if (mTrue) { // Do something. } while (mFalse) { // Do something else. } do { // Another code comes here. } while (mDontKnow) However for all the examples above only the true operator is executed. So what's the false operator in C# good for? Note: More examples can be found here, here and here.

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  • Why do not C++11's move constructor/assignment operator act as expected

    - by xmllmx
    #include <iostream> using namespace std; struct A { A() { cout << "A()" << endl; } ~A() { cout << "~A()" << endl; } A(A&&) { cout << "A(A&&)" << endl; } A& operator =(A&&) { cout << "A& operator =(A&&)" << endl; return *this; } }; struct B { // According to the C++11, the move ctor/assignment operator // should be implicitly declared and defined. The move ctor // /assignment operator should implicitly call class A's move // ctor/assignment operator to move member a. A a; }; B f() { B b; // The compiler knows b is a temporary object, so implicitly // defined move ctor/assignment operator of class B should be // called here. Which will cause A's move ctor is called. return b; } int main() { f(); return 0; } My expected output should be: A() A(A&&) ~A() ~A() However, the actual output is: (The C++ compiler is: Visual Studio 2012) A() ~A() ~A() Is this a bug of VC++? or just my misunderstanding?

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  • C++ operator lookup rules / Koenig lookup

    - by John Bartholomew
    While writing a test suite, I needed to provide an implementation of operator<<(std::ostream&... for Boost unit test to use. This worked: namespace theseus { namespace core { std::ostream& operator<<(std::ostream& ss, const PixelRGB& p) { return (ss << "PixelRGB(" << (int)p.r << "," << (int)p.g << "," << (int)p.b << ")"); } }} This didn't: std::ostream& operator<<(std::ostream& ss, const theseus::core::PixelRGB& p) { return (ss << "PixelRGB(" << (int)p.r << "," << (int)p.g << "," << (int)p.b << ")"); } Apparently, the second wasn't included in the candidate matches when g++ tried to resolve the use of the operator. Why (what rule causes this)? The code calling operator<< is deep within the Boost unit test framework, but here's the test code: BOOST_AUTO_TEST_SUITE(core_image) BOOST_AUTO_TEST_CASE(test_output) { using namespace theseus::core; BOOST_TEST_MESSAGE(PixelRGB(5,5,5)); // only compiles with operator<< definition inside theseus::core std::cout << PixelRGB(5,5,5) << "\n"; // works with either definition BOOST_CHECK(true); // prevent no-assertion error } BOOST_AUTO_TEST_SUITE_END() For reference, I'm using g++ 4.4 (though for the moment I'm assuming this behaviour is standards-conformant).

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  • On C++ global operator new: why it can be replaced

    - by Jimmy
    I wrote a small program in VS2005 to test whether C++ global operator new can be overloaded. It can. #include "stdafx.h" #include "iostream" #include "iomanip" #include "string" #include "new" using namespace std; class C { public: C() { cout<<"CTOR"<<endl; } }; void * operator new(size_t size) { cout<<"my overload of global plain old new"<<endl; // try to allocate size bytes void *p = malloc(size); return (p); } int main() { C* pc1 = new C; cin.get(); return 0; } In the above, my definition of operator new is called. If I remove that function from the code, then operator new in C:\Program Files (x86)\Microsoft Visual Studio 8\VC\crt\src\new.cpp gets called. All is good. However, in my opinion, my implementations of operator new does NOT overload the new in new.cpp, it CONFLICTS with it and violates the one-definition rule. Why doesn't the compiler complain about it? Or does the standard say since operator new is so special, one-definition rule does not apply here? Thanks.

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  • Operator+ for a subtype of a template class.

    - by baol
    I have a template class that defines a subtype. I'm trying to define the binary operator+ as a template function, but the compiler cannot resolve the template version of the operator+. #include <iostream> template<typename other_type> struct c { c(other_type v) : cs(v) {} struct subtype { subtype(other_type v) : val(v) {} other_type val; } cs; }; template<typename other_type> typename c<other_type>::subtype operator+(const typename c<other_type>::subtype& left, const typename c<other_type>::subtype& right) { return typename c<other_type>::subtype(left.val + right.val); } // This one works // c<int>::subtype operator+(const c<int>::subtype& left, // const c<int>::subtype& right) // { return c<int>::subtype(left.val + right.val); } int main() { c<int> c1 = 1; c<int> c2 = 2; c<int>::subtype cs3 = c1.cs + c2.cs; std::cerr << cs3.val << std::endl; } I think the reason is because the compiler (g++4.3) cannot guess the template type so it's searching for operator+<int> instead of operator+. What's the reason for that? What elegant solution can you suggest?

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  • Operator+ for a subtype of a template classe.

    - by baol
    I have a template class that defines a subtype. I'm trying to define the binary operator+ as a template function, but the compiler cannot resolve the template version of the operator+. #include <iostream> template<typename other_type> struct c { c(other_type v) : cs(v) {} struct subtype { subtype(other_type v) : val(v) {} other_type val; } cs; }; template<typename other_type> typename c<other_type>::subtype operator+(const typename c<other_type>::subtype& left, const typename c<other_type>::subtype& right) { return typename c<other_type>::subtype(left.val + right.val); } // This one works // c<a>::subtype operator+(const c<a>::subtype& left, // const c<a>::subtype& right) // { return c<a>::subtype(left.val + right.val); } int main() { c<int> c1 = 1; c<int> c2 = 2; c<int>::subtype cs3 = c1.cs + c2.cs; std::cerr << cs3.val << std::endl; } I think the reason is because the compiler (g++4.3) cannot guess the template type so it's searching for operator+<int> instead of operator+. What's the reason for that? What elegant solution can you suggest?

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  • List of mail servers using DKIM, SPF and SenderID

    - by Ashish
    Hi, I am setting up Postfix mail server. What I want to know is that, what the popular mail server's like yahoo, gmail, AOL, Microsoft Outlook server etc. use for sender identification of e-mails. e.g: Which one use SPF or DKIM or SenderId etc. Any listing enumerating about these properties would be highly useful. Thanks in advance Ashish

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  • Flush all messages in mailbox from Zimbra to another server

    - by Giovanni Lovato
    I have a primary Dovecot + Postfix mail server and a secondary Zimbra 8.0.1 server. The primary server went down for a week and all the incoming messages were delivered to the secondary server which has configured a "catch all" account. Now that the primary server is back online, I'd like to flush all messages on the "catch all" mailbox to the primary server for appropriate delivery to the corresponding user mailbox (and its own rules). Is that possible?

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  • Easiest way to send mail from Linux Server

    - by QAH
    Hello everyone! I want my server to send me email alerts every time it does things such as run a backup. I have tried to setup programs like Sendmail, Postfix, etc on my Ubuntu Server box and it is really a pain for me to get it working. Is there any online service or some easy gateway where my server can send email alerts? If not, is there any easy scripts to get a Linux mail program up and running? Thanks

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  • Postix transport smtp failover

    - by SimonJGreen
    We have a multi-tenant email relay set up that has a transport map file that looks like this: domain1.com smtp:mail.domain1.com domain2.com smtp:mail.domain2.com domain3.com smtp:mail.domain3.com [etc] In the event mail.domain1.com is down, email for domain1.com will be held by the postfix server until mail.domain1.com starts responding again. However we have a customer who has a backup DSL line on their site, an their email server is also available over this. How can I tell the transport to failover to a different host if the first is unavailable?

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  • GMail detecting mail as spam

    - by Petru Toader
    I've been trying for a long time to get our company's mail server send mail that will get accepted by the GMail spam filter. I have managed making it work for Yahoo Mail and Hotmail, sadly GMail is still marking our mails as spam. I have configured DKIM, SPF, DMARC and verified our mail server IP address against blacklists. I also have pasted here the headers GMail gets when we send a mail. Delivered-To: [email protected] Received: by 10.42.215.6 with SMTP id hc6csp107427icb; Wed, 20 Aug 2014 07:34:26 -0700 (PDT) X-Received: by 10.194.100.34 with SMTP id ev2mr59101019wjb.76.1408545265402; Wed, 20 Aug 2014 07:34:25 -0700 (PDT) Return-Path: <[email protected]> Received: from mail.phyramid.com (mail.phyramid.com. [178.157.82.23]) by mx.google.com with ESMTPS id dj10si4827754wib.79.2014.08.20.07.34.24 for <[email protected]> (version=TLSv1.1 cipher=ECDHE-RSA-RC4-SHA bits=128/128); Wed, 20 Aug 2014 07:34:25 -0700 (PDT) Received-SPF: pass (google.com: domain of [email protected] designates 178.157.82.23 as permitted sender) client-ip=178.157.82.23; Authentication-Results: mx.google.com; spf=pass (google.com: domain of [email protected] designates 178.157.82.23 as permitted sender) [email protected]; dkim=pass [email protected] Received: from localhost (localhost [127.0.0.1]) by mail.phyramid.com (Postfix) with ESMTP id ED2BB2017AC for <[email protected]>; Wed, 20 Aug 2014 17:33:23 +0300 (EEST) DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/simple; d=phyramid.com; h= content-type:content-type:mime-version:x-mailer:subject:subject :message-id:to:from:from:date:date; s=dkim; t=1408545197; x= 1409409197; bh=e04RtoyF7G39lfCvA9LLhTz4nF64siZtN5IYmC18Xsc=; b=o +6mO8Uz4Uf1G4U2q6tKUiEy2N2n/5R2VtPPwIvBE5xzK/hEd2sDGMxVzQVgIDCsK Q0Xh+auPaQpxldQ+AEcL2XSZMrk/g0mJONjkpI19I5AwGIJCR1SVvxdecohTn9iR bCHzrGi2wAicfDBzOH6lUBNfh2thri79aubdCYc97U= X-Amavis-Modified: Mail body modified (using disclaimer) - mail.phyramid.com X-Virus-Scanned: Debian amavisd-new at mail.phyramid.com Received: from mail.phyramid.com ([127.0.0.1]) by localhost (mail.phyramid.com [127.0.0.1]) (amavisd-new, port 10024) with ESMTP id 3JcgXZAXeFtX for <[email protected]>; Wed, 20 Aug 2014 17:33:17 +0300 (EEST) Received: from whiterock.local (unknown [109.98.21.30]) by mail.phyramid.com (Postfix) with ESMTPSA id 05CAE200280 for <[email protected]>; Wed, 20 Aug 2014 17:33:15 +0300 (EEST) Date: Wed, 20 Aug 2014 17:34:15 +0300 From: Company Mail <[email protected]> To: [email protected] Message-ID: <[email protected]> Subject: hey there! X-Mailer: Airmail (247) MIME-Version: 1.0 Content-Type: text/plain; charset="utf-8" Content-Transfer-Encoding: 7bit Content-Disposition: inline How was your summer? ---- Thanks a lot!

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  • Forward spam is dangerous for my domain repute?

    - by Memiux
    I have Postfix with spamassassin and forward the emails (including spam) to gmail.com, my problem is that when I send "legitimate" emails to gmail.com it is marked as spam, I've done everything that the guidelines said like signing with DKIM, setup a SPF for my domains, require authentication for outbound mails, etc. Now I wonder what I'm doing wrong?

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