Search Results

Search found 4783 results on 192 pages for 'txt'.

Page 34/192 | < Previous Page | 30 31 32 33 34 35 36 37 38 39 40 41  | Next Page >

• Do you need to advertise an AFP service via Avahi for an Ubuntu Server to show up in OSX Finder?

  - by James

  I am only advertising an NFS share plus the "model", and I don't want to install extra services on the Server unless I have to, ie netatalk, as it is used solely for NFS exports. Currently there is no entry in Finder under "Shared" with below config of Avahi. serveradmin@FILESERVER:/etc/avahi/services$ cat nfs.service <?xml version="1.0" standalone='no'?><!--*-nxml-*--> <!DOCTYPE service-group SYSTEM "avahi-service.dtd"> <service-group> <name replace-wildcards="yes">%h</name> <service> <type>_nfs._tcp</type> <port>2049</port> <txt-record>path=/Volumes/StoragePool</txt-record> </service> <service> <type>_device-info._tcp</type> <port>0</port> <txt-record>model=Xserve</txt-record> </service> </service-group> Server: Ubuntu 12.04.01 x64 Clients: OSX 10.6.8 , 10.7.5, 10.8.2 The goal is to advertise that NFS share, then assign a really old Model code of Mac like a Powermac and switch out the icon for a more "LinuxServer-y" one. Plus allow users to connect to NFS in a manner they are familiar with like our other Xserve servers. I think Avahi is working in general as if I do: nfs://FILESERVER.local/Volumes/StoragePool it will connect fine. Any ideas?

  Read the article

• Adding License to VMware Server 2 via scripting command?

  - by andyt25

  Hi all, I recently discovered the vimsvc/license command in vmware-vim-cmd and was trying to use that to automatically add my license key to a fresh vmware installation. vmware-vim-cmd -H hostip -O portnumber vimsvc/license --source file '/path/to/plaintext-file-that-contains-my-license-key.txt' plaintext-file-that-contains-my-license-key.txt contains my key in XXXXX-XXXXX-XXXXX-XXXXX format, I've also tried it with an extra carriage return at the end. Adding the key that way doesn't work, however. I always get the following error message: [200] Reading local file: /path/to/plaintext-file-that-contains-my-license-key.txt [200] Size of file is 24 bytes. returned were XXXXX-XXXXX-XXXXX-XXXXX [200] Changing license source to: file:/path/to/plaintext-file-that-contains-my-license-key.txt [500] Caught unexpected exception Type: N5Vmomi5Fault17NotEnoughLicenses9ExceptionE what() =vmodl.fault.NotEnoughLicenses GetMsg() = There are not enough licenses installed to perform the operation. It's kinda silly to require a license to be able to add a license, don't you think? ;-) So how do I go about and add the key via script? I would like to avoid any interaction as I have the rest of the install fully scripted and non-interactive. Kind Regards, Stefan

  Read the article

• PsExec and Remote Environment Variables, Logging, Etc.

  - by alharaka

  When I run PsExec on a remote computer, I always fall short of what I want. What I would like ideally in most situations is a) a log on an admin server where each individual log has the name of each the remote computer it was generated from (e.g. COMPNAME1.log, COMPNAME2.log, etc.) or b) a log file on each remote computer with whatever name I specify. When I try scenario (a), I use the following command. %SystemDrive%\path\to\psexec.exe @listofcomputers.txt -u DOMAIN\username cmd /c echo TEST >> \\server.company.tld\share\%computername%.log Problem is that it never works. All the computers just write to the log where %computername% is just the computer I execute PsExec from in my office. What I want are unique logs for each computer specific in the listofcomputers.txt that will correctly use the hostname from the remote environment variable without issue. Is that even possible? It does not seem to work for me. I tried this, and the syntax is clearly wrong. %SystemDrive%\path\to\psexec.exe @listofcomputers.txt -u DOMAIN\username "cmd /c echo TEST >> \\server.company.tld\share\%computername%.log" PsExec just fails saying the system file cannot be found (read: syntax fail). As for scenario (b), it appears to be a variation of a similar problem. When I run a command like this, it does not work. %SystemDrive%\path\to\psexec.exe @listofcomputers.txt -u DOMAIN\username "cmd /c echo %computername% >> \\server.company.tld\share\aggregated.log" Is there something I do not understand about remote path and environment variables with PsExec on the cmd.exe console (I have not even tried the dreaded PowerShell yet). I know such things work in a batch file (cmd /c \\server.company.tld\share\runthis.bat), but is there a reason it will not work when executing commands as arguments? I always need this, and can never get it!

  Read the article

• Usage of putty in command line from Hudson

  - by kij

  Hi, I'm trying to use putty in command line from an hudson job. The command is the following one: putty -ssh -2 -P 22 USERNAME@SERVER_ADDR -pw PASS -m command.txt Where 'command.txt' is a shell script to execute in the server through SSH. If i launch this command from the Window command prompt, it works, the shell script is executed on the server machine. If i launch a build of the hudson job configured with this batch command, it doesn't work. The build is running... and running... and running.. without doing anything, and i have to stop it manually. So my question is: Is it possible to launch an external programm (i.e. putty) from an hudson job ? ps: i tried SSH plugin but... not a really good plugin (pre/post build, fail status of the commands launched not caught by hudson, etc.) Thanks in advance for your help. Best regards. kij EDIT: These are the build logs: [workspace] $ cmd /c call C:\WINDOWS\TEMP\hudson7429256014041663539.bat C:\Hudson\jobs\Artifact deployer\workspace>putty -ssh -2 -P 22 USER@SERV_ADD -pw PASS -m com.txt Le build a été annulé Finished: ABORTED And the Hudson.err.log file at the same time (after a stop): 3 juin 2010 18:27:28 hudson.model.Run run INFO: Artifact deployer #6 aborted java.lang.InterruptedException at java.lang.ProcessImpl.waitFor(Native Method) at hudson.Proc$LocalProc.join(Proc.java:179) at hudson.Launcher$ProcStarter.join(Launcher.java:278) at hudson.tasks.CommandInterpreter.perform(CommandInterpreter.java:83) at hudson.tasks.CommandInterpreter.perform(CommandInterpreter.java:58) at hudson.tasks.BuildStepMonitor$1.perform(BuildStepMonitor.java:19) at hudson.model.AbstractBuild$AbstractRunner.perform(AbstractBuild.java:601) at hudson.model.Build$RunnerImpl.build(Build.java:174) at hudson.model.Build$RunnerImpl.doRun(Build.java:138) at hudson.model.AbstractBuild$AbstractRunner.run(AbstractBuild.java:416) at hudson.model.Run.run(Run.java:1241) at hudson.model.FreeStyleBuild.run(FreeStyleBuild.java:46) at hudson.model.ResourceController.execute(ResourceController.java:88) at hudson.model.Executor.run(Executor.java:124) My shell script only write "hello" in a "hello.txt" file on the server, and nothing is done.

  Read the article

• DNS zone file SPF configuration to support sending mail from multiple servers and gmail

  - by Tauren

  I want to configure SPF on a domain to allow mail to be sent from: the x.com website server (x.com and www.x.com - both at same IP) it's MX servers (smtp.x.com, mx.x.com, mail.x.com) another server that isn't listed as an MX server (somehost.x.com) via gmail using an account that has authenticated use of [email protected] Will this zone file work? If not, what are the problems with it? $ttl 38400 @ IN SOA ns1.x.com. hostmaster.x.com. ( 201003092 ; serial 8H ; refresh 15M ; retry 1W ; expire 1H ) ; minimum @ NS ns1.x.com. @ NS ns2.x.com. @ MX 10 mx.x.com. @ MX 20 smtp.x.com. @ MX 30 mailhost.x.com. ; SPF records @ IN TXT "v=spf1 a mx a:somehost.x.com include:_spf.google.com ~all" mx IN TXT "v=spf1 a -all" smtp IN TXT "v=spf1 a -all" mailhost IN TXT "v=spf1 a -all" Questions: Is _spf.google.com the right thing to include for gmail.com, or is it only for Google Hosted Apps? If only for Google Apps, what should I include to send from gmail.com? If mail shouldn't be sent from anywhere else, is it safe to use -all instead of ~all? Does it make sense to add specific SPF records for each of the mail servers? Any other problems with the zone file? I want to confirm these things before making changes to my zone file. The file has SPF configured basically the same now, just without google.com and somehost, but I want to make sure I won't break things when I change it.

  Read the article

• How do I format a text file for IIS Mailroot Pickup so that it sends an e-mail with attachments?

  - by Ben McCormack

  How do I need to format a text file so that it can be read by an SMTP service to send an e-mail that has an attachment? We have a server where we are using II6 SMTP to send mail from a Pickup folder. The goal is to drop a properly formatted text file into Mailroot\Pickup and then the file will be automatically processed and sent to the correct SMTP recipient. For simple files, this works correctly. Here's an example of a simple file that works (domain names changed): From:[email protected] To:[email protected] Subject:Hello World! Test Body Of The E-mail When I drop a text file containing the above contents into the Mailroot\Pickup folder, it sends correctly. However, I haven't been able to figure out how to get an attachment to work. I found some material that explained how to encode an SMTP attachment and another tool for simple base64 encoding conversion. Using the information on those pages, I came up with the following text: From:[email protected] To:[email protected] Subject:Hello World! MIME-Version: 1.0 Content-Type: text/plain; boundary="Attached" Content-Disposition: inline; --Attached Content-Transfer-Encoding: base64 Content-Type: text/plain; name="attachment.txt" Content-Disposition: attachment; filenamename="attachment.txt" VGhpcyBpcyBhIHRlc3Qgb2Ygc29tZXRoaW5nIHRvIGVuY29kZS4NCk5ldyBsaW5lDQpOZXcgTGlu ZQ0KIkhlbGxvdyIgISEhDQo9PT09ICcgZnNkZnNkZiAxMjM1NDU2MzQzNA== --Attached-- However, when I place the above text in a file and drop it into Mailroot\Pickup, it doesn't send an attachment correctly. Instead, an e-mail shows up with the following in the body of the e-mail: MIME-Version: 1.0 Content-Type: text/plain; boundary="Attached" Content-Disposition: inline; --Attached Content-Transfer-Encoding: base64 Content-Type: text/plain; name="attachment.txt" Content-Disposition: attachment; filenamename="attachment.txt" VGhpcyBpcyBhIHRlc3Qgb2Ygc29tZXRoaW5nIHRvIGVuY29kZS4NCk5ldyBsaW5lDQpOZXcgTGlu ZQ0KIkhlbGxvdyIgISEhDQo9PT09ICcgZnNkZnNkZiAxMjM1NDU2MzQzNA== --Attached-- I can't figure out what I need to do to format the text file so that the SMTP service correctly sends attachments.

  Read the article

• Comparing 2 (or 3 Files If Possible) "Line By Line"

  - by PythEch

  I want to find out the differences of 2 (or 3 files if possible) line by line. Diff utils can do this, however it gives inaccurate results. Because, 2 files have exact number of lines which is "134". But diff gives me "Added Lines" and "Removed Lines". However this is wrong, they have exact the same number of lines, there is no added or removed lines. The text files which I want to find differences of them, have only numbers written, maybe that's why that algortihm fails. I couldn't find any option to prevent that, however I may be wrong, I mean there should be an option for that, but again, I couldn't find. This is what I get (5am.txt vs 6am.txt, there is a huge problem): This is what I want (6am.txt vs 7am.txt, still has problems): But, first the first image still has this problem, at the last lines. Edit: After I figured out that there is no utility to do this, I handled myself. I almost did the same thing as what RedGrittyBrick have done. This script imitates diff utility so I (or you) can use it with diff2html. To use it with diff2html, just change line diff_stdout = os.popen("diff %s" % string.join(argv[1:]), "r") to diff_stdout = os.popen("script.py %s" % string.join(argv[1:]), "r") and name this script whatever you want: import sys f1=open(sys.argv[1],"r") f1_read=f1.readlines() f1.close() f2=open(sys.argv[2],"r") f2_read=f2.readlines() f2.close() changed={} first_c = "" for n in range(len(f1_read)): if f1_read[n]!=f2_read[n]: if first_c == "": first_c=n+1 changed[first_c]=n+1 else: first_c="" #Let's imitate diff-utils... for (x, y) in changed.items(): print "%d,%dc%d,%d" % (x,y,x,y) for i in range(x,y+1): sys.stdout.write("< %s" % f1_read[i-1]) print "---" for i in range(x,y+1): sys.stdout.write("> %s" % f2_read[i-1]) Final results:

  Read the article

• recursively "normalize" filenames

  - by user66732

  i have made a script, that can recursively rename files to get rid of special chars, etc. in filenames e.g.: before: THIS i.s my file (1).txt after running the script: This-i-s-my-file-1.txt Ok. here it is: But: when i wanted to test it "fully", with filenames like this: ¤¥¦§¨©ª«¬®¯°±²³´µ¶·¸¹º»¼½¾¿ÀÂÃÄÅÆÇÈÊËÌÎÏÐÑÒÔÕ×ØÙUÛUÝÞßàâãäåæçèêëìîïðñòôõ÷øùûýþÿ.txt áíüuúöoóéÁÍÜUÚÖOÓÉ!"#$%&'()*+,:;<=>?@[\]^_`{|}~€‚ƒ„…†‡ˆ‰Š‹ŒŽ‘’“”•–—˜™š›œžŸ¡¢£.txt it fails: $ sh renamer.sh directorythathasthefiles mv: cannot stat `./áíüuúöoóéÁÍÜUÚÖOÓÉ!"#$%&\'()*+,:;<=>?@[]^_`{|}~€‚ƒ„…†‡ˆ‰Š‹ŒŽ‘’“”•–—˜™š›œžŸ¡¢£': No such file or directory mv: cannot stat `./áíüuúöoóéÁÍÜUÚÖOÓÉ!"#$%&\'()*+,:;<=>?@[]^_`{|}~€‚ƒ„…†‡ˆ‰Š‹ŒŽ‘’“”•–—˜™š›œžŸ¡¢£': No such file or directory mv: cannot stat `./áíüuúöoóéÁÍÜUÚÖOÓÉ!"#$%&\'()*+,:;<=>?@[]^_`{|}~€‚ƒ„…†‡ˆ‰Š‹ŒŽ‘’“”•–—˜™š›œžŸ¡¢£': No such file or directory mv: cannot stat `./áíüuúöoóéÁÍÜUÚÖOÓÉ!"#$%&\'()*+,:;<=>?@[]^_`{|}~€‚ƒ„…†‡ˆ‰Š‹ŒŽ‘’“”•–—˜™š›œžŸ¡¢£': No such file or directory mv: cannot stat `./áíüuúöoóéÁÍÜUÚÖOÓÉ!"#$%&\'()*+,:;<=>?@[]^_`{|}~€‚ƒ„…†‡ˆ‰Š‹ŒŽ‘’“”•–—˜™š›œžŸ¡¢£': No such file or directory mv: cannot stat `./áíüuúöoóéÁÍÜUÚÖOÓÉ!"#$%&\'()*+,:;<=>?@[]^_`{|}~€‚ƒ„…†‡ˆ‰Š‹ŒŽ‘’“”•–—˜™š›œžŸ¡¢£': No such file or directory ...and so on so "mv" can't handle special chars.. :\ i worked on it for many hours.. does anyone has a working one? [that can handle chars [filenames] in that 2 lines too?] Q on pastebin: http://pastebin.com/raw.php?i=19iYZpwY

  Read the article

• recursively "normalize" filenames

  - by user62367

  i mean getting rid of special chars in filenames, etc. i have made a script, that can recursively rename files [http://pastebin.com/raw.php?i=kXeHbDQw]: e.g.: before: THIS i.s my file (1).txt after running the script: This-i-s-my-file-1.txt Ok. here it is: But: when i wanted to test it "fully", with filenames like this: ¤¥¦§¨©ª«¬®¯°±²³´µ¶·¸¹º»¼½¾¿ÀÂÃÄÅÆÇÈÊËÌÎÏÐÑÒÔÕ×ØÙUÛUÝÞßàâãäåæçèêëìîïðñòôõ÷øùûýþÿ.txt áíüuúöoóéÁÍÜUÚÖOÓÉ!"#$%&'()*+,:;<=>?@[\]^_`{|}~€‚ƒ„…†‡ˆ‰Š‹ŒŽ‘’“”•–—˜™š›œžŸ¡¢£.txt it fails [http://pastebin.com/raw.php?i=iu8Pwrnr]: $ sh renamer.sh directorythathasthefiles mv: cannot stat `./áíüuúöoóéÁÍÜUÚÖOÓÉ!"#$%&\'()*+,:;<=>?@[]^_`{|}~€‚ƒ„…†‡ˆ‰Š‹ŒŽ‘’“”•–—˜™š›œžŸ¡¢£': No such file or directory mv: cannot stat `./áíüuúöoóéÁÍÜUÚÖOÓÉ!"#$%&\'()*+,:;<=>?@[]^_`{|}~€‚ƒ„…†‡ˆ‰Š‹ŒŽ‘’“”•–—˜™š›œžŸ¡¢£': No such file or directory mv: cannot stat `./áíüuúöoóéÁÍÜUÚÖOÓÉ!"#$%&\'()*+,:;<=>?@[]^_`{|}~€‚ƒ„…†‡ˆ‰Š‹ŒŽ‘’“”•–—˜™š›œžŸ¡¢£': No such file or directory mv: cannot stat `./áíüuúöoóéÁÍÜUÚÖOÓÉ!"#$%&\'()*+,:;<=>?@[]^_`{|}~€‚ƒ„…†‡ˆ‰Š‹ŒŽ‘’“”•–—˜™š›œžŸ¡¢£': No such file or directory mv: cannot stat `./áíüuúöoóéÁÍÜUÚÖOÓÉ!"#$%&\'()*+,:;<=>?@[]^_`{|}~€‚ƒ„…†‡ˆ‰Š‹ŒŽ‘’“”•–—˜™š›œžŸ¡¢£': No such file or directory mv: cannot stat `./áíüuúöoóéÁÍÜUÚÖOÓÉ!"#$%&\'()*+,:;<=>?@[]^_`{|}~€‚ƒ„…†‡ˆ‰Š‹ŒŽ‘’“”•–—˜™š›œžŸ¡¢£': No such file or directory mv: cannot stat `./áíüuúöoóéÁÍÜUÚÖOÓÉ!"#$%&\'()*+,:;<=>?@[]^_`{|}~€‚ƒ„…†....and so on $ so "mv" can't handle special chars.. :\ i worked on it for many hours.. does anyone has a working one? [that can handle chars [filenames] in that 2 lines too?]

  Read the article

• SFTP, ChrootDirectory and multiple users

  - by mdo

  I need a setup where I can put the contents of several user folders to a DMZ server from where external clients can download it, protocol SFTP, Linux, OpenSSH. To ease administration we want to use one single user for the upload. What does work is to define ChrootDirectory /home/sftp/ in sshd_config, set the according ownership and modes and define a home dir in passwd so that the working directory of the user fits. This is my structure: /home/sftp/uploader/user1/file1.txt /user2/file2.txt The uploader user can write file1.txt and file2.txt to the corresponding folders and by having the user folders (user1, user2) set to the users' primary group + setting SETGUID on the folders the users are able to even delete the files (which is necessary). Only problem: because /home/sftp/ is the chroot base dir the users can change updir and see other users' folders, though not being able to change into because of access rights. Requirement: We want to prevent users to change to /home/sftp/uploader/ and see other users' folders. My requirements are to use SFTP, have one upload user and every user must have write access to his home dir. Obviously it's not an option to use something like ChrootDirectory %h because every path component of the chroot path needs to have limited access rights, so as far as I understand this does not work.

  Read the article

• Linux: Can't overwrite files on samba store

  - by jonescb

  I'm using CentOS 5.5 with smbclient 3.0.33-3.28-el5 (latest version in repo), and I can't overwrite files in my Samba store. I am not the admin for the Samba server, so there isn't anything I can do server side. But I do have write permission to the server. I know the server runs Windows XP or Server 2003; I don't know. I can delete the file, and then copy the new version over, but I can't overwrite it. Using the cp command I'll get this error: [jonescb@localhost ~]$ cp foo.txt /mnt/si_storage/foo.txt cp: cannot create regular file `/mnt/si_storage/foo.txt': No such file or directory` And if I edit a file on the server using vim, I can save it once, but if I save it again I get this: "/mnt/si_storage/foo.txt" E212: Can't open file for writing This is my /etc/fstab entry for the samba server: //192.168.1.2/SI_STORAGE /mnt/si_storage cifs username=myuser,password=mypass 0 0 Edit: I can overwrite files just fine on my XP machine. The CentOS box is the only one having problems.

  Read the article

• Computing Number of Bits in Public Key

  - by eb80

  I am working with DKIM and trying to compute the public key size of some DKIM signatures. I know from tools that Gmail's is now 2048, but how could I have figured this out myself (i.e., what exact Linux commands and why)? user@host$ dig txt 20120113._domainkey.gmail.com ; <<>> DiG 9.8.3-P1 <<>> txt 20120113._domainkey.gmail.com ;; global options: +cmd ;; Got answer: ;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 52228 ;; flags: qr rd ra; QUERY: 1, ANSWER: 1, AUTHORITY: 0, ADDITIONAL: 0 ;; QUESTION SECTION: ;20120113._domainkey.gmail.com. IN TXT ;; ANSWER SECTION: 20120113._domainkey.gmail.com. 300 IN TXT "k=rsa\; p=MIIBIjANBgkqhkiG9w0BAQEFAAOCAQ8AMIIBCgKCAQEA1Kd87/UeJjenpabgbFwh+eBCsSTrqmwIYYvywlbhbqoo2DymndFkbjOVIPIldNs/m40KF+yzMn1skyoxcTUGCQs8g3FgD2Ap3ZB5DekAo5wMmk4wimDO+U8QzI3SD0" "7y2+07wlNWwIt8svnxgdxGkVbbhzY8i+RQ9DpSVpPbF7ykQxtKXkv/ahW3KjViiAH+ghvvIhkx4xYSIc9oSwVmAl5OctMEeWUwg8Istjqz8BZeTWbf41fbNhte7Y+YqZOwq1Sd0DbvYAD9NOZK9vlfuac0598HY+vtSBczUiKERHv1yRbcaQtZFh5wtiRrN04BLUTD21MycBX5jYchHjPY/wIDAQAB" ;; Query time: 262 msec ;; SERVER: 8.8.8.8#53(8.8.8.8) ;; WHEN: Mon Nov 19 10:52:06 2012 ;; MSG SIZE rcvd: 462

  Read the article

• I need to take the first three letters of a filename and set it into a text file, in a certain fashion. How can I do this?

  - by JuniorD

  Okay, so I need to take the first three letters of a file from a list of files, and place this into a text file in a certain manner. I will provide examples below. Lets say that I have two file names in the same directory, one called cougar.txt and the other bear.txt. These are in the animals directory. I need to take the first three letters of these words, and transpose them into a text file along with the directory, in the following format: BEA = "animals/bear.txt" COU = "animals/cougar.txt" This should happen with any random thing that might be in the list. I'm fairly new to this sort of coding, so I'm not quite sure which language to use, and I'm learning as I go. This new challenge seems fairly daunting to me, and I would be much appreciated if you guys could help. Also, I'm using Windows 7. Been attempting at this all day, to no avail. Preferably done in batch, but if that is impossible I'm open to recommendations.

  Read the article

• Need some help on how to replay the last game of a java maze game

  - by Marty

  Hello, I am working on creating a Java maze game for a project. The maze is displayed on the console as standard output not in an applet. I have created most of hte code I need, however I am stuck at one problem and that is I need a user to be able to replay the last game i.e redraw the maze with the users moves but without any input from the user. I am not sure on what course of action to take, i was thinking about copying each users move or the position of each move into another array, as you can see i have 2 variables which hold the position of the player, plyrX and plyrY do you think copying these values into a new array after each move would solve my problem and how would i go about this? I have updated my code, apologies about the textIO.java class not being present, not sure how to resolve that exept post a link to TextIO.java [TextIO.java][1] My code below is updated with a new array of type char to hold values from the original maze (read in from text file and displayed using unicode characters) and also to new variables c_plyrX and c_plyrY which I am thinking should hold the values of plyrX and plyrY and copy them into the new array. When I try to call the replayGame(); method from the menu the maze loads for a second then the console exits so im not sure what I am doing wrong Thanks public class MazeGame { //unicode characters that will define the maze walls, //pathways, and in game characters. final static char WALL = '\u2588'; //wall final static char PATH = '\u2591'; //pathway final static char PLAYER = '\u25EF'; //player final static char ENTRANCE = 'E'; //entrance final static char EXIT = '\u2716'; //exit //declaring member variables which will hold the maze co-ordinates //X = rows, Y = columns static int entX = 0; //entrance X co-ordinate static int entY = 1; //entrance y co-ordinate static int plyrX = 0; static int plyrY = 1; static int exitX = 24; //exit X co-ordinate static int exitY = 37; //exit Y co-ordinate //static member variables which hold maze values //used so values can be accessed from different methods static int rows; //rows variable static int cols; //columns variable static char[][] maze; //defines 2 dimensional array to hold the maze //variables that hold player movement values static char dir; //direction static int spaces; //amount of spaces user can travel //variable to hold amount of moves the user has taken; static int movesTaken = 0; //new array to hold player moves for replaying game static char[][] mazeCopy; static int c_plyrX; static int c_plyrY; /** userMenu method for displaying the user menu which will provide various options for * the user to choose such as play a maze game, get instructions, etc. */ public static void userMenu(){ TextIO.putln("Maze Game"); TextIO.putln("*********"); TextIO.putln("Choose an option."); TextIO.putln(""); TextIO.putln("1. Play the Maze Game."); TextIO.putln("2. View Instructions."); TextIO.putln("3. Replay the last game."); TextIO.putln("4. Exit the Maze Game."); TextIO.putln(""); int option; //variable for holding users option TextIO.put("Type your choice: "); option = TextIO.getlnInt(); //gets users option //switch statement for processing menu options switch(option){ case 1: playMazeGame(); case 2: instructions(); case 3: if (c_plyrX == plyrX && c_plyrY == plyrY)replayGame(); else { TextIO.putln("Option not available yet, you need to play a game first."); TextIO.putln(); userMenu(); } case 4: System.exit(0); //exits the user out of the console default: TextIO.put("Option must be 1, 2, 3 or 4"); } } //end of userMenu /**main method, will call the userMenu and get the users choice and call * the relevant method to execute the users choice. */ public static void main(String[]args){ userMenu(); //calls the userMenu method } //end of main method /**instructions method, displays instructions on how to play * the game to the user/ */ public static void instructions(){ TextIO.putln("To beat the Maze Game you have to move your character"); TextIO.putln("through the maze and reach the exit in as few moves as possible."); TextIO.putln(""); TextIO.putln("Your characer is displayed as a " + PLAYER); TextIO.putln("The maze exit is displayed as a " + EXIT); TextIO.putln("Reach the exit and you have won escaped the maze."); TextIO.putln("To control your character type the direction you want to go"); TextIO.putln("and how many spaces you want to move"); TextIO.putln("for example 'D3' will move your character"); TextIO.putln("down 3 spaces."); TextIO.putln("Remember you can't walk through walls!"); boolean insOption; //boolean variable TextIO.putln(""); TextIO.put("Do you want to play the Maze Game now? (Y or N) "); insOption = TextIO.getlnBoolean(); if (insOption == true)playMazeGame(); else userMenu(); } //end of instructions method /**playMazeGame method, calls the loadMaze method and the charMove method * to start playing the Maze Game. */ public static void playMazeGame(){ loadMaze(); plyrMoves(); } //end of playMazeGame method /**loadMaze method, loads the 39x25 maze from the MazeGame.txt text file * and inserts values from the text file into the maze array and * displays the maze on screen using the unicode block characters. * plyrX and plyrY variables are set at their staring co ordinates so that when * a game is completed and the user selects to play a new game * the player character will always be at position 01. */ public static void loadMaze(){ plyrX = 0; plyrY = 1; TextIO.readFile("MazeGame.txt"); //now reads from the external MazeGame.txt file rows = TextIO.getInt(); //gets the number of rows from text file to create X dimensions cols = TextIO.getlnInt(); //gets number of columns from text file to create Y dimensions maze = new char[rows][cols]; //creates maze array of base type char with specified dimnensions //loop to process the array and read in values from the text file. for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ maze[i][j] = TextIO.getChar(); } TextIO.getln(); } //end for loop TextIO.readStandardInput(); //closes MazeGame.txt file and reads from //standard input. //loop to process the array values and display as unicode characters for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ if (i == plyrX && j == plyrY){ plyrX = i; plyrY = j; TextIO.put(PLAYER); //puts the player character at player co-ords } else{ if (maze[i][j] == '0') TextIO.putf("%c",WALL); //puts wall block if (maze[i][j] == '1') TextIO.putf("%c",PATH); //puts path block if (maze[i][j] == '2') { entX = i; entY = j; TextIO.putf("%c",ENTRANCE); //puts entrance character } if (maze[i][j] == '3') { exitX = i; //holds value of exit exitY = j; //co-ordinates TextIO.putf("%c",EXIT); //puts exit character } } } TextIO.putln(); } //end for loop } //end of loadMaze method /**redrawMaze method, method for redrawing the maze after each move. * */ public static void redrawMaze(){ TextIO.readFile("MazeGame.txt"); //now reads from the external MazeGame.txt file rows = TextIO.getInt(); //gets the number of rows from text file to create X dimensions cols = TextIO.getlnInt(); //gets number of columns from text file to create Y dimensions maze = new char[rows][cols]; //creates maze array of base type char with specified dimnensions //loop to process the array and read in values from the text file. for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ maze[i][j] = TextIO.getChar(); } TextIO.getln(); } //end for loop TextIO.readStandardInput(); //closes MazeGame.txt file and reads from //standard input. //loop to process the array values and display as unicode characters for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ if (i == plyrX && j == plyrY){ plyrX = i; plyrY = j; TextIO.put(PLAYER); //puts the player character at player co-ords } else{ if (maze[i][j] == '0') TextIO.putf("%c",WALL); //puts wall block if (maze[i][j] == '1') TextIO.putf("%c",PATH); //puts path block if (maze[i][j] == '2') { entX = i; entY = j; TextIO.putf("%c",ENTRANCE); //puts entrance character } if (maze[i][j] == '3') { exitX = i; //holds value of exit exitY = j; //co-ordinates TextIO.putf("%c",EXIT); //puts exit character } } } TextIO.putln(); } //end for loop } //end redrawMaze method /**replay game method * */ public static void replayGame(){ c_plyrX = plyrX; c_plyrY = plyrY; TextIO.readFile("MazeGame.txt"); //now reads from the external MazeGame.txt file rows = TextIO.getInt(); //gets the number of rows from text file to create X dimensions cols = TextIO.getlnInt(); //gets number of columns from text file to create Y dimensions mazeCopy = new char[rows][cols]; //creates maze array of base type char with specified dimnensions //loop to process the array and read in values from the text file. for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ mazeCopy[i][j] = TextIO.getChar(); } TextIO.getln(); } //end for loop TextIO.readStandardInput(); //closes MazeGame.txt file and reads from //standard input. //loop to process the array values and display as unicode characters for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ if (i == c_plyrX && j == c_plyrY){ c_plyrX = i; c_plyrY = j; TextIO.put(PLAYER); //puts the player character at player co-ords } else{ if (mazeCopy[i][j] == '0') TextIO.putf("%c",WALL); //puts wall block if (mazeCopy[i][j] == '1') TextIO.putf("%c",PATH); //puts path block if (mazeCopy[i][j] == '2') { entX = i; entY = j; TextIO.putf("%c",ENTRANCE); //puts entrance character } if (mazeCopy[i][j] == '3') { exitX = i; //holds value of exit exitY = j; //co-ordinates TextIO.putf("%c",EXIT); //puts exit character } } } TextIO.putln(); } //end for loop } //end replayGame method /**plyrMoves method, method for moving the players character * around the maze. */ public static void plyrMoves(){ int nplyrX = plyrX; int nplyrY = plyrY; int pMoves; direction(); //UP if (dir == 'U' || dir == 'u'){ nplyrX = plyrX; nplyrY = plyrY; for(pMoves = 0; pMoves <= spaces; pMoves++){ if (maze[nplyrX][nplyrY] == '0'){ TextIO.putln("Invalid move, try again."); } else if (pMoves != spaces){ nplyrX =plyrX + 1; } else { plyrX = plyrX-spaces; c_plyrX = plyrX; movesTaken++; } } }//end UP if //DOWN if (dir == 'D' || dir == 'd'){ nplyrX = plyrX; nplyrY = plyrY; for (pMoves = 0; pMoves <= spaces; pMoves ++){ if (maze[nplyrX][nplyrY] == '0'){ TextIO.putln("Invalid move, try again"); } else if (pMoves != spaces){ nplyrX = plyrX+1; } else{ plyrX = plyrX+spaces; c_plyrX = plyrX; movesTaken++; } } } //end DOWN if //LEFT if (dir == 'L' || dir =='l'){ nplyrX = plyrX; nplyrY = plyrY; for (pMoves = 0; pMoves <= spaces; pMoves++){ if (maze[nplyrX][nplyrY] == '0'){ TextIO.putln("Invalid move, try again"); } else if (pMoves != spaces){ nplyrY = plyrY + 1; } else{ plyrY = plyrY-spaces; c_plyrY = plyrY; movesTaken++; } } } //end LEFT if //RIGHT if (dir == 'R' || dir == 'r'){ nplyrX = plyrX; nplyrY = plyrY; for (pMoves = 0; pMoves <= spaces; pMoves++){ if (maze[nplyrX][nplyrY] == '0'){ TextIO.putln("Invalid move, try again."); } else if (pMoves != spaces){ nplyrY += 1; } else{ plyrY = plyrY+spaces; c_plyrY = plyrY; movesTaken++; } } } //end RIGHT if //prints message if player escapes from the maze. if (maze[plyrX][plyrY] == '3'){ TextIO.putln("****Congratulations****"); TextIO.putln(); TextIO.putln("You have escaped from the maze."); TextIO.putln(); userMenu(); } else{ movesTaken++; redrawMaze(); plyrMoves(); } } //end of plyrMoves method /**direction, method * */ public static char direction(){ TextIO.putln("Enter the direction you wish to move in and the distance"); TextIO.putln("i.e D3 = move down 3 spaces"); TextIO.putln("U - Up, D - Down, L - Left, R - Right: "); dir = TextIO.getChar(); if (dir =='U' || dir == 'D' || dir == 'L' || dir == 'R' || dir == 'u' || dir == 'd' || dir == 'l' || dir == 'r'){ spacesMoved(); } else{ loadMaze(); TextIO.putln("Invalid direction!"); TextIO.put("Direction must be one of U, D, L or R"); direction(); } return dir; //returns the value of dir (direction) } //end direction method /**spaces method, gets the amount of spaces the user wants to move * */ public static int spacesMoved(){ TextIO.putln(" "); spaces = TextIO.getlnInt(); if (spaces <= 0){ loadMaze(); TextIO.put("Invalid amount of spaces, try again"); spacesMoved(); } return spaces; } //end spacesMoved method } //end of MazeGame class

  Read the article

• NTFS Issues in Windows 7 and 2008 R2 - 'Is it a Bug?'

  - by renewieldraaijer

  I have been using the various versions of the Microsoft Windows product line since NT4 and I really thought I knew the ins and outs about the NTFS filesystem by now. There were always a few rules of thumb to understand what happens if you move data around. These rules were: "If you copy data, the copied data will inherit the permissions of the location it is being copied to. The same goes for moving data between disk partitions. Only when you move data within the same partition, the permissions are kept."  Recently I was asked to assist in troubleshooting some NTFS related issues. This forced me to have another good look at this theory. To my surprise I found out that this theory does not completely stand anymore. Apparently some things have changed since the release of Windows Vista / Windows 2008. Since the release of these Operating Systems, a move within the same disk partition results in the data inheriting the permissions of the location it is being copied into. A major change in the NTFS filesystem you would think!  Not quite! The above only counts when the move operation is being performed by using Windows Explorer. A move by using the 'move' command from within a cmd prompt for example, retains the NTFS permissions, just like before in Windows XP and older systems. Conclusion: The Windows Explorer is responsible for changing the ACL's of the moved data. This is a remarkable change, but if you follow this theory, the resulting ACL after a move operation is still predictable.  We could say that since Windows Vista and Windows 2008, a new rule set applies: "If you copy data, the copied data will inherit the permissions of the location it is being copied to. Same goes for moving data between disk partitions and within disk partitions. Only when you move data within the same partition by using something else than the Windows Explorer, the permissions are kept." The above behavior should be unchanged in Windows 7 / Windows 2008 R2, compared to Windows Vista / 2008. But somehow the NTFS permissions are not so predictable in Windows 7 and Windows 2008 R2. Moving data within the same disk partition the one time results in the permissions being kept and the next time results in inherited permissions from the destination location. I will try to demonstrate this in a few examples: Example 1 (Incorrect behavior): Consider two folders, 'Folder A' and 'Folder B' with the following permissions configured.                    Now we create the test file 'test file 1.txt' in 'Folder A' and afterwards move this file to 'Folder B' using Windows Explorer.                       According to the new theory, the file should inherit the permissions of 'Folder B' and therefore 'Group B' should appear in the ACL of 'test file 1.txt'. In the screenshot below the resulting permissions are displayed. The permissions from the originating location are kept, while the permissions of 'Folder B' should be inherited.                   Example 2 (Correct behavior): Again, consider the same two folders. This time we make a small modification to the ACL of 'Folder A'. We add 'Group C' to the ACL and again we create a file in 'Folder A' which we name 'test file 2.txt'.                    Next, we move 'test file 2.txt' to 'Folder B'.                       Again, we check the permissions of 'test file 2.txt' at the target location. We can now see that the permissions are inherited. This is what should be happening, and can be considered 'correct behavior' for Windows Vista / 2008 / 7 / 2008 R2. It remains uncertain why this behavior is so inconsistent. At this time, this is under investigation with Microsoft Support. The investigation has been going for the last two weeks and it is beginning to look like there is no rational reason for this, other than a bug in the Windows Explorer in Windows 7 and 2008 R2. As soon as there is any certainty on this, I will note it here in this blog.                   The examples above are harmless tests, by using my own laptop. If you would create the same set of folders and groups, and configure exactly the same permissions, you will see exactly the same behavior. Be sure to use Windows 7 or Windows 2008 R2.   Initially the problem arose at a customer site where move operations on data on the fileserver by users would result in unpredictable results. This resulted in the wrong set of people having àccess permissions on data that they should not have permissions to. Off course this is something we want to prevent at all costs.   I have also done several tests with move operations by using the move command in a cmd prompt. This way the behavior is always consistent. The inconsistent behavior is only exposed when using the Windows Explorer to initiate the move operation, and only when using Windows 7 or Windows 2008 R2 systems. It is evident that this behavior changes when the ACL of a folder has been changed, for example by adding an extra entry. The reason for this remains uncertain though. To be continued…. A dutch version of this post can be found at: http://blogs.platani.nl/?p=612

  Read the article

• error in finding out the lexems and no of lines of a text file in C

  - by mekasperasky

  #include<stdio.h> #include<ctype.h> #include<string.h> int main() { int i=0,j,k,lines_count[2]={1,1},operand_count[2]={0},operator_count[2]={0},uoperator_count[2]={0},control_count[2]={0,0},cl[13]={0},variable_dec[2]={0,0},l,p[2]={0},ct,variable_used[2]={0,0},constant_count[2],s[2]={0},t[2]={0}; char a,b[100],c[100]; char d[100]={0}; j=30; FILE *fp1[2],*fp2; fp1[0]=fopen("program1.txt","r"); fp1[1]=fopen("program2.txt","r"); //the source file is opened in read only mode which will passed through the lexer fp2=fopen("ccv1ouput.txt","wb"); //now lets remove all the white spaces and store the rest of the words in a file if(fp1[0]==NULL) { perror("failed to open program1.txt"); //return EXIT_FAILURE; } if(fp1[1]==NULL) { perror("failed to open program2.txt"); //return EXIT_FAILURE; } i=0; k=0; ct=0; while(ct!=2) { while(!feof(fp1[ct])) { a=fgetc(fp1[ct]); if(a!=' '&&a!='\n') { if (!isalpha(a) && !isdigit(a)) { switch(a) { case '+':{ i=0; cl[0]=1; operator_count[ct]=operator_count[ct]+1;break;} case '-':{ cl[1]=1; operator_count[ct]=operator_count[ct]+1;i=0;break;} case '*':{ cl[2]=1; operator_count[ct]=operator_count[ct]+1;i=0;break;} case '/':{ cl[3]=1; operator_count[ct]=operator_count[ct]+1;i=0;break;} case '=':{a=fgetc(fp1[ct]); if (a=='='){cl[4]=1; operator_count[ct]=operator_count[ct]+1; operand_count[ct]=operand_count[ct]+1;} else { cl[5]=1; operator_count[ct]=operator_count[ct]+1; operand_count[ct]=operand_count[ct]+1; ungetc(1,fp1[ct]); } break;} case '%':{ cl[6]=1; operator_count[ct]=operator_count[ct]+1;i=0;break;} case '<':{ a=fgetc(fp1[ct]); if (a=='=') {cl[7]=1; operator_count[ct]=operator_count[ct]+1;} else { cl[8]=1; operator_count[ct]=operator_count[ct]+1; ungetc(1,fp1[ct]); } break; } case '>':{ ; a=fgetc(fp1[ct]); if (a=='='){cl[9]=1; operator_count[ct]=operator_count[ct]+1;} else { cl[10]=1; operator_count[ct]=operator_count[ct]+1; ungetc(1,fp1[ct]); } break;} case '&':{ cl[11]=1; a=fgetc(fp1[ct]); operator_count[ct]=operator_count[ct]+1; operand_count[ct]=operand_count[ct]+1; variable_used[ct]=variable_used[ct]-1; break; } case '|':{ cl[12]=1; a=fgetc(fp1[ct]); operator_count[ct]=operator_count[ct]+1; operand_count[ct]=operand_count[ct]+1; variable_used[ct]=variable_used[ct]-1; break; } case '#':{ while(a!='\n') { a=fgetc(fp1[ct]); } } } } else { d[i]=a; i=i+1; k=k+1; } } else { //printf("%s \n",d); if((strcmp(d,"if")==0)){ memset ( d, 0, 100 ); i=0; control_count[ct]=control_count[ct]+1; } else if(strcmp(d,"then")==0){ i=0;memset ( d, 0, 100 );control_count[ct]=control_count[ct]+1;} else if(strcmp(d,"else")==0){ i=0;memset ( d, 0, 100 );control_count[ct]=control_count[ct]+1;} else if(strcmp(d,"while")==0){ i=0;memset ( d, 0, 100 );control_count[ct]=control_count[ct]+1;} else if(strcmp(d,"int")==0){ while(a != '\n') { a=fgetc(fp1[ct]); if (isalpha(a) ) variable_dec[ct]=variable_dec[ct]+1; } memset ( d, 0, 100 ); lines_count[ct]=lines_count[ct]+1; } else if(strcmp(d,"char")==0){while(a != '\n') { a=fgetc(fp1[ct]); if (isalpha(a) ) variable_dec[ct]=variable_dec[ct]+1; } memset ( d, 0, 100 ); lines_count[ct]=lines_count[ct]+1; } else if(strcmp(d,"float")==0){while(a != '\n') { a=fgetc(fp1[ct]); if (isalpha(a) ) variable_dec[ct]=variable_dec[ct]+1; } memset ( d, 0, 100 ); lines_count[ct]=lines_count[ct]+1; } else if(strcmp(d,"printf")==0){while(a!='\n') a=fgetc(fp1[ct]); memset(d,0,100); } else if(strcmp(d,"scanf")==0){while(a!='\n') a=fgetc(fp1[ct]); memset(d,0,100);} else if (isdigit(d[i-1])) { memset ( d, 0, 100 ); i=0; constant_count[ct]=constant_count[ct]+1; operand_count[ct]=operand_count[ct]+1; } else if (isalpha(d[i-1]) && strcmp(d,"int")!=0 && strcmp(d,"char")!=0 && strcmp(d,"float")!=0 && (strcmp(d,"if")!=0) && strcmp(d,"then")!=0 && strcmp(d,"else")!=0 && strcmp(d,"while")!=0 && strcmp(d,"printf")!=0 && strcmp(d,"scanf")!=0) { memset ( d, 0, 100 ); i=0; operand_count[ct]=operand_count[ct]+1; } else if(a=='\n') { lines_count[ct]=lines_count[ct]+1; memset ( d, 0, 100 ); } } } fclose(fp1[ct]); operand_count[ct]=operand_count[ct]-5; variable_used[0]=operand_count[0]-constant_count[0]; variable_used[1]=operand_count[1]-constant_count[1]; for(j=0;j<12;j++) uoperator_count[ct]=uoperator_count[ct]+cl[j]; fprintf(fp2,"\n statistics of program %d",ct+1); fprintf(fp2,"\n the no of lines ---> %d",lines_count[ct]); fprintf(fp2,"\n the no of operands --->%d",operand_count[ct]); fprintf(fp2,"\n the no of operator --->%d",operator_count[ct]); fprintf(fp2,"\n the no of control statments --->%d",control_count[ct]); fprintf(fp2,"\n the no of unique operators --->%d",uoperator_count[ct]); fprintf(fp2,"\n the no of variables declared--->%d",variable_dec[ct]); fprintf(fp2,"\n the no of variables used--->%d",variable_used[ct]); fprintf(fp2,"\n ---------------------------------"); fprintf(fp2,"\n \t \t \t"); ct=ct+1; } t[0]=lines_count[0]+control_count[0]+uoperator_count[0]; t[1]=lines_count[1]+control_count[1]+uoperator_count[1]; s[0]=operator_count[0]+operand_count[0]+variable_dec[0]+variable_used[0]; s[1]=operator_count[1]+operand_count[1]+variable_dec[1]+variable_used[1]; fprintf(fp2,"\n the time complexity of program 1 is %d",t[0]); fprintf(fp2,"\n the time complexity of program 2 is %d",t[1]); fprintf(fp2,"\n the space complexity of program 1 is %d",s[0]); fprintf(fp2,"\n the space complexity of program 2 is %d",s[1]); if((t[0]>t[1]) && (s[0] >s[1])) fprintf(fp2,"\n the efficiency of program 2 is greater than program 1"); else if(t[0]<t[1] && s[0] < s[1]) fprintf(fp2,"\n the efficiency of program 1 is greater than program 2 " ); else if (t[0]+s[0] > t[1]+s[1]) fprintf(fp2,"\n the efficiency of program 1 is greater than program 2"); else if (t[0]+s[0] < t[1]+s[1]) fprintf(fp2,"\n the efficiency of program 2 is greater than program 1"); else if (t[0]+s[0] == t[1]+s[1]) fprintf(fp2,"\n the efficiency of program 1 is equal to that of program 2"); fclose(fp2); return 0; } this code basically compares two c codes and finds out the no. of variables declared , used , no. of control statements , no. of lines and no. of unique operators , and operands , so as to find out the time complexity and space complexity of of the two programs given in the text file program1.txt and program2.txt ... Lets say program1.txt is this #include<stdio.h> #include<math.h> int main () { FILE *fp; fp=fopen("output.txt","w"); long double t,y=0,x=0,e=5,f=1,w=1; for (t=0;t<10;t=t+0.01) { //if (isnan(y) || isinf(y)) //break; fprintf(fp,"%ld\t%ld\n",y,x); y = y + ((e*(1 - (x*x))*y) - x + f*cos(w*0.1))*0.1; x = x + y*0.1; } fclose(fp); return (0); } i havent indented it as its just a text file . But my output is totally faulty . Its not able to find the any of the ouput that i need . Where is the bug in this ? I am not able to figure out as the algorithm looks fine .

  Read the article

• javaf, problem...plz help someone...urgent [closed]

  - by innovative_aj

  i have made a word guessing game, when i click myButton to check if the guessed word is right or wrong, ball1 is moved into the "container" if its right, i want that when i click the button again and if the typed word is right, the 2nd ball should move into the container too... means one ball per correct answer...plz help me someone and provide me with the code that i can implement, its quite urgent... controller class coding /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package project3; import java.net.URL; import java.util.ResourceBundle; import javafx.event.ActionEvent; import javafx.event.EventHandler; import javafx.fxml.FXML; import javafx.fxml.Initializable; import javafx.scene.control.Button; import javafx.scene.control.Label; import javafx.scene.control.TextField; import javafx.scene.layout.StackPane; import javafx.scene.shape.Circle; /** * FXML Controller class * * @xxx */ public class MyFxmlController implements Initializable { @FXML // fx:id="ball1" private Circle ball1; // Value injected by FXMLLoader @FXML // fx:id="ball2" private Circle ball2; // Value injected by FXMLLoader @FXML // fx:id="ball3" private Circle ball3; // Value injected by FXMLLoader @FXML // fx:id="ball4" private Circle ball4; // Value injected by FXMLLoader @FXML // fx:id="container" private Circle container; // Value injected by FXMLLoader @FXML // fx:id="myButton" private Button myButton; // Value injected by FXMLLoader @FXML // fx:id="myLabel1" private Label myLabel1; // Value injected by FXMLLoader @FXML // fx:id="myLabel2" private Label myLabel2; // Value injected by FXMLLoader @FXML // fx:id="pane" private StackPane pane; // Value injected by FXMLLoader @FXML // fx:id="txt" private TextField txt; // Value injected by FXMLLoader @Override // This method is called by the FXMLLoader when initialization is complete public void initialize(URL fxmlFileLocation, ResourceBundle resources) { assert ball1 != null : "fx:id=\"ball1\" was not injected: check your FXML file 'MyFxml.fxml'."; assert ball2 != null : "fx:id=\"ball2\" was not injected: check your FXML file 'MyFxml.fxml'."; assert ball3 != null : "fx:id=\"ball3\" was not injected: check your FXML file 'MyFxml.fxml'."; assert ball4 != null : "fx:id=\"ball4\" was not injected: check your FXML file 'MyFxml.fxml'."; assert container != null : "fx:id=\"container\" was not injected: check your FXML file 'MyFxml.fxml'."; assert myButton != null : "fx:id=\"myButton\" was not injected: check your FXML file 'MyFxml.fxml'."; assert myLabel1 != null : "fx:id=\"myLabel1\" was not injected: check your FXML file 'MyFxml.fxml'."; assert myLabel2 != null : "fx:id=\"myLabel2\" was not injected: check your FXML file 'MyFxml.fxml'."; assert pane != null : "fx:id=\"pane\" was not injected: check your FXML file 'MyFxml.fxml'."; assert txt != null : "fx:id=\"txt\" was not injected: check your FXML file 'MyFxml.fxml'."; // initialize your logic here: all @FXML variables will have been injected myButton.setOnAction(new EventHandler<ActionEvent>(){ @Override public void handle(ActionEvent event) { int count = 0; String guessed=txt.getText(); boolean result; result=MyCode.check(guessed); if(result) { ball1.setTranslateX(600); ball1.setTranslateY(250-container.getRadius()); //ball2.setTranslateX(600); // ball2.setTranslateY(250-container.getRadius()); } else System.out.println("wrong"); } }); } } word guessing logic public class MyCode { static String x="Netbeans"; static String y[]={"net","beans","neat","beat","bet"}; //static int counter; // public MyCode() { // counter++; //} static boolean check(String guessed) { int count=0; boolean result=false; //counter++; //System.out.println("turns"+counter); for(count=0;count<5;count++) { if(guessed.equals(y[count])) { result=true; break; } } if(result) System.out.println("Right"); else System.out.println("Wrong"); return result; } }

  Read the article

• java: how to compress data into a String and uncompress data from the String

  - by Guillaume

  I want to put some compressed data into a remote repository. To put data on this repository I can only use a method that take the name of the resource and its content as a String. (like data.txt + "hello world"). The repository is moking a filesystem but is not, so I can not use File directly. I want to be able to do the following: client send to server a file 'data.txt' server compress 'data.txt' into data.zip server send to repository content of data.zip repository store data.zip client download from repository data.zip and his able to open it with its favorite zip tool I have tried a lots of compressing example found on the web but each time a send the data to the repository, my resulting zip file is corrupted. Here is a sample class, using the zip*stream and that emulate the repository showcasing my problem. The created zip file is working, but after its 'serialization' it's get corrupted. (the sample class use jakarta commons.io ) Many thanks for your help. package zip; import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.util.zip.ZipEntry; import java.util.zip.ZipInputStream; import java.util.zip.ZipOutputStream; import org.apache.commons.io.FileUtils; /** * Date: May 19, 2010 - 6:13:07 PM * * @author Guillaume AME. */ public class ZipMe { public static void addOrUpdate(File zipFile, File ... files) throws IOException { File tempFile = File.createTempFile(zipFile.getName(), null); // delete it, otherwise you cannot rename your existing zip to it. tempFile.delete(); boolean renameOk = zipFile.renameTo(tempFile); if (!renameOk) { throw new RuntimeException("could not rename the file " + zipFile.getAbsolutePath() + " to " + tempFile.getAbsolutePath()); } byte[] buf = new byte[1024]; ZipInputStream zin = new ZipInputStream(new FileInputStream(tempFile)); ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFile)); ZipEntry entry = zin.getNextEntry(); while (entry != null) { String name = entry.getName(); boolean notInFiles = true; for (File f : files) { if (f.getName().equals(name)) { notInFiles = false; break; } } if (notInFiles) { // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(name)); // Transfer bytes from the ZIP file to the output file int len; while ((len = zin.read(buf)) > 0) { out.write(buf, 0, len); } } entry = zin.getNextEntry(); } // Close the streams zin.close(); // Compress the files if (files != null) { for (File file : files) { InputStream in = new FileInputStream(file); // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(file.getName())); // Transfer bytes from the file to the ZIP file int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } // Complete the entry out.closeEntry(); in.close(); } // Complete the ZIP file } tempFile.delete(); out.close(); } public static void main(String[] args) throws IOException { final String zipArchivePath = "c:/temp/archive.zip"; final String tempFilePath = "c:/temp/data.txt"; final String resultZipFile = "c:/temp/resultingArchive.zip"; File zipArchive = new File(zipArchivePath); FileUtils.touch(zipArchive); File tempFile = new File(tempFilePath); FileUtils.writeStringToFile(tempFile, "hello world"); addOrUpdate(zipArchive, tempFile); //archive.zip exists and contains a compressed data.txt that can be read using winrar //now simulate writing of the zip into a in memory cache String archiveText = FileUtils.readFileToString(zipArchive); FileUtils.writeStringToFile(new File(resultZipFile), archiveText); //resultingArchive.zip exists, contains a compressed data.txt, but it can not //be read using winrar: CRC failed in data.txt. The file is corrupt } }

  Read the article

• java: how to get a string representation of a compressed byte array ?

  - by Guillaume

  I want to put some compressed data into a remote repository. To put data on this repository I can only use a method that take the name of the resource and its content as a String. (like data.txt + "hello world"). The repository is moking a filesystem but is not, so I can not use File directly. I want to be able to do the following: client send to server a file 'data.txt' server compress 'data.txt' into a compressed file 'data.zip' server send a string representation of data.zip to the repository repository store data.zip client download from repository data.zip and his able to open it with its favorite zip tool The problem arise at step 3 when I try to get a string representation of my compressed file. Here is a sample class, using the zip*stream and that emulate the repository showcasing my problem. The created zip file is working, but after its 'serialization' it's get corrupted. (the sample class use jakarta commons.io ) Many thanks for your help. package zip; import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.util.zip.ZipEntry; import java.util.zip.ZipInputStream; import java.util.zip.ZipOutputStream; import org.apache.commons.io.FileUtils; /** * Date: May 19, 2010 - 6:13:07 PM * * @author Guillaume AME. */ public class ZipMe { public static void addOrUpdate(File zipFile, File ... files) throws IOException { File tempFile = File.createTempFile(zipFile.getName(), null); // delete it, otherwise you cannot rename your existing zip to it. tempFile.delete(); boolean renameOk = zipFile.renameTo(tempFile); if (!renameOk) { throw new RuntimeException("could not rename the file " + zipFile.getAbsolutePath() + " to " + tempFile.getAbsolutePath()); } byte[] buf = new byte[1024]; ZipInputStream zin = new ZipInputStream(new FileInputStream(tempFile)); ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFile)); ZipEntry entry = zin.getNextEntry(); while (entry != null) { String name = entry.getName(); boolean notInFiles = true; for (File f : files) { if (f.getName().equals(name)) { notInFiles = false; break; } } if (notInFiles) { // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(name)); // Transfer bytes from the ZIP file to the output file int len; while ((len = zin.read(buf)) > 0) { out.write(buf, 0, len); } } entry = zin.getNextEntry(); } // Close the streams zin.close(); // Compress the files if (files != null) { for (File file : files) { InputStream in = new FileInputStream(file); // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(file.getName())); // Transfer bytes from the file to the ZIP file int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } // Complete the entry out.closeEntry(); in.close(); } // Complete the ZIP file } tempFile.delete(); out.close(); } public static void main(String[] args) throws IOException { final String zipArchivePath = "c:/temp/archive.zip"; final String tempFilePath = "c:/temp/data.txt"; final String resultZipFile = "c:/temp/resultingArchive.zip"; File zipArchive = new File(zipArchivePath); FileUtils.touch(zipArchive); File tempFile = new File(tempFilePath); FileUtils.writeStringToFile(tempFile, "hello world"); addOrUpdate(zipArchive, tempFile); //archive.zip exists and contains a compressed data.txt that can be read using winrar //now simulate writing of the zip into a in memory cache String archiveText = FileUtils.readFileToString(zipArchive); FileUtils.writeStringToFile(new File(resultZipFile), archiveText); //resultingArchive.zip exists, contains a compressed data.txt, but it can not //be read using winrar: CRC failed in data.txt. The file is corrupt } }

  Read the article

• Multiplying two matrices from two text files with unknown dimensions

  - by wes schwertner

  This is my first post here. I've been working on this c++ question for a while now and have gotten nowhere. Maybe you guys can give me some hints to get me started. My program has to read two .txt files each containing one matrix. Then it has to multiply them and output it to another .txt file. My confusion here though is how the .txt files are setup and how to get the dimensions. Here is an example of matrix 1.txt. #ivalue #jvalue value 1 1 1.0 2 2 1 The dimension of the matrix is 2x2. 1.0 0 0 1 Before I can start multiplying these matrices I need to get the i and j value from the text file. The only way I have found out to do this is int main() { ifstream file("a.txt"); int numcol; float col; for(int x=0; x<3;x++) { file>>col; cout<<col; if(x==1) //grabs the number of columns numcol=col; } cout<<numcol; } The problem is I don't know how to get to the second line to read the number of rows. And on top of that I don't think this will give me accurate results for other matrices files. Let me know if anything is unclear. UPDATE Thanks! I got getline to work correctly. But now I am running into another problem. In matrix B it is setup like: #ivalue #jvalue Value 1 1 0.1 1 2 0.2 2 1 0.3 2 2 0.4 I need to let the program know that it needs to go down 4 lines, maybe even more (The matrices dimensions are unknown. My matrix B example is a 2x2, but it could be a 20x20). I have a while(!file.eof()) loop my program to let it loop until the end of file. I know I need a dynamic array for multiplying, but would I need one here also? #include <iostream> #include <fstream> using namespace std; int main() { ifstream file("a.txt"); //reads matrix A while(!file.eof()) { int temp; int numcol; string numrow; float row; float col; for(int x=0; x<3;x++) { file>>col; if(x==1) { numcol=col; //number of columns } } string test; getline(file, test); //next line to get rows for(int x=0; x<3; x++) { file>>test; if(x==1) { numrow=test; //sets number of rows } } cout<<numrow; cout<<numcol<<endl; } ifstream file1("b.txt"); //reads matrix 2 while(!file1.eof()) { int temp1; int numcol1; string numrow1; float row1; float col1; for(int x=0; x<2;x++) { file1>>col1; if(x==1) numcol1=col1; //sets number of columns } string test1; getline(file1, test1); //In matrix B there are four rows. getline(file1, test1); //These getlines go down a row. getline(file1, test1); //Need help here. for(int x=0; x<2; x++) { file1>>test1; if(x==1) numrow1=test1; } cout<<numrow1; cout<<numcol1<<endl; } }

  Read the article

• cmake doesn't work in windows XP

  - by Runner

  I'm new with cmake,just installed it and following this article: http://www.cs.swarthmore.edu/~adanner/tips/cmake.php D:\Works\c\cmake\build>cmake .. -- Building for: NMake Makefiles CMake Warning at CMakeLists.txt:2 (project): To use the NMake generator, cmake must be run from a shell that can use the compiler cl from the command line. This environment does not contain INCLUDE, LIB, or LIBPATH, and these must be set for the cl compiler to work. -- The C compiler identification is unknown -- The CXX compiler identification is unknown CMake Warning at D:/Tools/CMake 2.8/share/cmake-2.8/Modules/Platform/Windows-cl.cmake:32 (ENABLE_LANGUAGE): To use the NMake generator, cmake must be run from a shell that can use the compiler cl from the command line. This environment does not contain INCLUDE, LIB, or LIBPATH, and these must be set for the cl compiler to work. Call Stack (most recent call first): D:/Tools/CMake 2.8/share/cmake-2.8/Modules/CMakeCInformation.cmake:58 (INCLUDE) CMakeLists.txt:2 (project) CMake Error: your RC compiler: "CMAKE_RC_COMPILER-NOTFOUND" was not found. Please set CMAKE_RC_COMPILER to a valid compiler path or name. -- Check for CL compiler version -- Check for CL compiler version - failed -- Check if this is a free VC compiler -- Check if this is a free VC compiler - yes -- Using FREE VC TOOLS, NO DEBUG available -- Check for working C compiler: cl CMake Warning at CMakeLists.txt:2 (PROJECT): To use the NMake generator, cmake must be run from a shell that can use the compiler cl from the command line. This environment does not contain INCLUDE, LIB, or LIBPATH, and these must be set for the cl compiler to work. CMake Warning at D:/Tools/CMake 2.8/share/cmake-2.8/Modules/Platform/Windows-cl.cmake:32 (ENABLE_LANGUAGE): To use the NMake generator, cmake must be run from a shell that can use the compiler cl from the command line. This environment does not contain INCLUDE, LIB, or LIBPATH, and these must be set for the cl compiler to work. Call Stack (most recent call first): D:/Tools/CMake 2.8/share/cmake-2.8/Modules/CMakeCInformation.cmake:58 (INCLUDE) CMakeLists.txt:2 (PROJECT) CMake Error at D:/Tools/CMake 2.8/share/cmake-2.8/Modules/CMakeRCInformation.cmake:22 (GET_FILENAME_COMPONENT): get_filename_component called with incorrect number of arguments Call Stack (most recent call first): D:/Tools/CMake 2.8/share/cmake-2.8/Modules/Platform/Windows-cl.cmake:32 (ENABLE_LANGUAGE) D:/Tools/CMake 2.8/share/cmake-2.8/Modules/CMakeCInformation.cmake:58 (INCLUDE) CMakeLists.txt:2 (PROJECT) CMake Error: CMAKE_RC_COMPILER not set, after EnableLanguage CMake Error: your C compiler: "cl" was not found. Please set CMAKE_C_COMPILER to a valid compiler path or name. CMake Error: Internal CMake error, TryCompile configure of cmake failed -- Check for working C compiler: cl -- broken CMake Error at D:/Tools/CMake 2.8/share/cmake-2.8/Modules/CMakeTestCCompiler.cmake:52 (MESSAGE): The C compiler "cl" is not able to compile a simple test program. It fails with the following output: CMake will not be able to correctly generate this project. Call Stack (most recent call first): CMakeLists.txt:2 (project) CMake Error: your C compiler: "cl" was not found. Please set CMAKE_C_COMPILER to a valid compiler path or name. CMake Error: your CXX compiler: "cl" was not found. Please set CMAKE_CXX_COMPILER to a valid compiler path or name. -- Configuring incomplete, errors occurred! What are the complete requirement to use cmake successfully in windows XP?I've already installed Visual Studio under D:\Tools\Microsoft Visual Studio 9.0

  Read the article

• How to set up spf records to send mail from google hosted apps to gmail addresses

  - by Chris Adams

  Hi there, I'm trying to work out why email I send from one domain I own is rejected by another that I own, and while I think it may be related to how I've setup spf records, I'm not sure what steps I need to take to fix it. Here's the error message I receive: Technical details of permanent failure: Google tried to deliver your message, but it was rejected by the recipient domain. We recommend contacting the other email provider for further information about the cause of this error. The error that the other server returned was: 550 550-Verification failed for <[email protected]> 550-No Such User Here 550 Sender verify failed (state 14). Here's the response from [email protected] Delivered-To: [email protected] Received: by 10.86.92.9 with SMTP id p9cs85371fgb; Wed, 2 Sep 2009 22:33:32 -0700 (PDT) Received: by 10.90.205.4 with SMTP id c4mr2406190agg.29.1251956007562; Wed, 02 Sep 2009 22:33:27 -0700 (PDT) Return-Path: <[email protected]> Received: from verifier.port25.com (207-36-201-235.ptr.primarydns.com [207.36.201.235]) by mx.google.com with ESMTP id 26si831174aga.24.2009.09.02.22.33.25; Wed, 02 Sep 2009 22:33:26 -0700 (PDT) Received-SPF: pass (google.com: domain of [email protected] designates 207.36.201.235 as permitted sender) client-ip=207.36.201.235; Authentication-Results: mx.google.com; spf=pass (google.com: domain of [email protected] designates 207.36.201.235 as permitted sender) [email protected]; dkim=pass [email protected] DKIM-Signature: v=1; a=rsa-sha1; c=relaxed/relaxed; s=auth; d=port25.com; h=Date:From:To:Subject:Message-Id:In-Reply-To; [email protected]; bh=GRMrcnoucTl4upzqJYTG5sOZMLU=; b=uk6TjADEyZVRkceQGjH94ZzfVeRTsiZPzbXuhlqDt1m+kh1zmdUEoiTOzd89ryCHMbVcnG1JajBj 5vOMKYtA3g== DomainKey-Signature: a=rsa-sha1; c=nofws; q=dns; s=auth; d=port25.com; b=NqKCPK00Xt49lbeO009xy4ZRgMGpghvcgfhjNy7+qI89XKTzi6IUW0hYqCQyHkd2p5a1Zjez2ZMC l0u9CpZD3Q==; Received: from verifier.port25.com (127.0.0.1) by verifier.port25.com (PowerMTA(TM) v3.6a1) id hjt9pq0hse8u for <[email protected]>; Thu, 3 Sep 2009 01:26:52 -0400 (envelope-from <[email protected]>) Date: Thu, 3 Sep 2009 01:26:52 -0400 From: [email protected] To: [email protected] Subject: Authentication Report Message-Id: <[email protected]> Precedence: junk (auto_reply) In-Reply-To: <[email protected]> This message is an automatic response from Port25's authentication verifier service at verifier.port25.com. The service allows email senders to perform a simple check of various sender authentication mechanisms. It is provided free of charge, in the hope that it is useful to the email community. While it is not officially supported, we welcome any feedback you may have at <[email protected]>. Thank you for using the verifier, The Port25 Solutions, Inc. team ========================================================== Summary of Results ========================================================== SPF check: pass DomainKeys check: neutral DKIM check: neutral Sender-ID check: pass SpamAssassin check: ham ========================================================== Details: ========================================================== HELO hostname: fg-out-1718.google.com Source IP: 72.14.220.158 mail-from: [email protected] ---------------------------------------------------------- SPF check details: ---------------------------------------------------------- Result: pass ID(s) verified: [email protected] DNS record(s): stemcel.co.uk. 14400 IN TXT "v=spf1 include:aspmx.googlemail.com ~all" aspmx.googlemail.com. 7200 IN TXT "v=spf1 redirect=_spf.google.com" _spf.google.com. 300 IN TXT "v=spf1 ip4:216.239.32.0/19 ip4:64.233.160.0/19 ip4:66.249.80.0/20 ip4:72.14.192.0/18 ip4:209.85.128.0/17 ip4:66.102.0.0/20 ip4:74.125.0.0/16 ip4:64.18.0.0/20 ip4:207.126.144.0/20 ?all" ---------------------------------------------------------- DomainKeys check details: ---------------------------------------------------------- Result: neutral (message not signed) ID(s) verified: [email protected] DNS record(s): ---------------------------------------------------------- DKIM check details: ---------------------------------------------------------- Result: neutral (message not signed) ID(s) verified: NOTE: DKIM checking has been performed based on the latest DKIM specs (RFC 4871 or draft-ietf-dkim-base-10) and verification may fail for older versions. If you are using Port25's PowerMTA, you need to use version 3.2r11 or later to get a compatible version of DKIM. ---------------------------------------------------------- Sender-ID check details: ---------------------------------------------------------- Result: pass ID(s) verified: [email protected] DNS record(s): stemcel.co.uk. 14400 IN TXT "v=spf1 include:aspmx.googlemail.com ~all" aspmx.googlemail.com. 7200 IN TXT "v=spf1 redirect=_spf.google.com" _spf.google.com. 300 IN TXT "v=spf1 ip4:216.239.32.0/19 ip4:64.233.160.0/19 ip4:66.249.80.0/20 ip4:72.14.192.0/18 ip4:209.85.128.0/17 ip4:66.102.0.0/20 ip4:74.125.0.0/16 ip4:64.18.0.0/20 ip4:207.126.144.0/20 ?all" ---------------------------------------------------------- SpamAssassin check details: ---------------------------------------------------------- SpamAssassin v3.2.5 (2008-06-10) Result: ham (-2.6 points, 5.0 required) pts rule name description ---- ---------------------- -------------------------------------------------- -0.0 SPF_PASS SPF: sender matches SPF record -2.6 BAYES_00 BODY: Bayesian spam probability is 0 to 1% [score: 0.0000] 0.0 HTML_MESSAGE BODY: HTML included in message I've registered the spf records for my domain, as advised here Both domains pass validate according to Kitterman's spf record testing tools, so I'm somewhat confused about this. I also have the catchall address set up on the stemcel.co.uk domain here, but I don't have one setup for chrisadams.me.uk. Instead, we have the following forwarders setup [email protected] to [email protected] [email protected] to [email protected] [email protected] to [email protected] [email protected] to [email protected] Any ideas how to get this working? I'm not sure what I should be looking for here.

  Read the article

• Notepad and Textedit exchange

  - by Peter

  I use both W7 and Mac OSX on several machines, with sugarsync to sync files and directories. So far no problem. However txt files created by W7 Notepad are displayed differently with Mac TextEdit. And when I edit the file with TextEdit, it looks different again in W7 Notepad. Edits in Notepad again look different on the Mac. Problem areas are: - tabs - carriage returns - fonts. I use and edit one particular txt file on a daily basis: services.txt (here I keep all my web accounts etc). What can I do to keep these exactly the same whilst editing on either Mac or W7? thanks Peter

  Read the article

• setting up a shared folder in linux

  - by Chris

  I'm trying to set up a folder in my home directory that will be shared with another user but for some reason it is not working this is what I've done, I have tried two different ways using ACL's and chown/chgrp etc I set up a group called say: sharedgroup and added both my user (john) and fred to it so when I run groups john john wheel sharedgroup groups fred sharedgroup fred mkdir /home/john/shared vim /home/john/shared/hello.txt (typed in some text saved it) chown -R :sharedgroup shared chmod -R o=-rwx shared ll drwxrwx--- 2 john sharedgroup 4096 Sep 9 21:14 shared ll shared -rw-rw-r-- 1 john sharedgroup 7 Sep 9 21:14 hello.txt (I also tried adding in the s permissions but that didn't help either) then when I log out of the server and log back in as fred and try these commands they fail vim /home/john/shared/hello.txt (won't allow me to write opens a blank file) cd /home/john/shared -bash: cd: /home/john/cis: Permission Denied ls /home/john/shared -ls: /home/john/shared: Permission Denied ls -lad /home/john/shared -ls: /home/john/shared: Permission Denied id fred uid=500(fred) gid=502(sharedgroup) groups=502(sharedgroup),500(fred) context=user_u:system_r:unconfined_t Any idea what I'm doing wrong??

  Read the article

• Copy a file to a new directory path in DOS

  - by nodmonkey

  How can I copy a file using DOS commands into a directory structure that may not yet exist? I need to be able to force the creation of the directory path to the target file location if that location doesn't already exist. For example, there is already a file.txt in this location: C:\file.txt And I want to copy it to C:\example\new\path\to\copy\of\file\file.txt but at this time C:\example\ and all the subdirectories may or may not yet exist. Basically, I am looking for a "copy and create the target path if necessary" command. What would you recommend is the best way to achieve this?

  Read the article

< Previous Page | 30 31 32 33 34 35 36 37 38 39 40 41  | Next Page >