Generating new tasks in a foreach loop
- by Scott Chamberlain
I know from the codeing guidlines that I have read you should not do
for (int i = 0; i < 5; i++)
{
Task.Factory.StartNew(() => Console.WriteLine(i));
}
Console.ReadLine();
as it will write 5 5's, I understand that and I think i understand why it is happening. I know the solution is just to do
for (int i = 0; i < 5; i++)
{
int localI = i;
Task.Factory.StartNew(() => Console.WriteLine(localI));
}
Console.ReadLine();
However is something like this ok to do?
Task currentTask = myFirstTask;
currentTask.Start();
foreach (Task task in _TaskList)
{
currentTask.ContinueWith((antecendent) =>
{
if(antecendent.IsCompleated)
{
task.Start();
}
else
//do error handling;
});
currentTask = task;
}
}
or do i need to do this?
Task currentTask = myFirstTask;
foreach (Task task in _TaskList)
{
Task localTask = task;
currentTask.ContinueWith((antecendent) =>
{
if(antecendent.IsCompleated)
{
localTask.Start();
}
else
//do error handling;
});
currentTask = task;
}
