Search Results

Search found 91862 results on 3675 pages for 'new account'.

Page 345/3675 | < Previous Page | 341 342 343 344 345 346 347 348 349 350 351 352  | Next Page >

  • Sending the files (At least 11 files) from folder through web service to android app.

    - by Shashank_Itmaster
    Hello All, I stuck in middle of this situation,Please help me out. My question is that I want to send files (Total 11 PDF Files) to android app using web service. I tried it with below code.Main Class from which web service is created public class MultipleFilesImpl implements MultipleFiles { public FileData[] sendPDFs() { FileData fileData = null; // List<FileData> filesDetails = new ArrayList<FileData>(); File fileFolder = new File( "C:/eclipse/workspace/AIPWebService/src/pdfs/"); // File fileTwo = new File( // "C:/eclipse/workspace/AIPWebService/src/simple.pdf"); File sendFiles[] = fileFolder.listFiles(); // sendFiles[0] = fileOne; // sendFiles[1] = fileTwo; DataHandler handler = null; char[] readLine = null; byte[] data = null; int offset = 0; int numRead = 0; InputStream stream = null; FileOutputStream outputStream = null; FileData[] filesData = null; try { System.out.println("Web Service Called Successfully"); for (int i = 0; i < sendFiles.length; i++) { handler = new DataHandler(new FileDataSource(sendFiles[i])); fileData = new FileData(); data = new byte[(int) sendFiles[i].length()]; stream = handler.getInputStream(); while (offset < data.length && (numRead = stream.read(data, offset, data.length - offset)) >= 0) { offset += numRead; } readLine = Base64Coder.encode(data); offset = 0; numRead = 0; System.out.println("'Reading File............................"); System.out.println("\n"); System.out.println(readLine); System.out.println("Data Reading Successful"); fileData.setFileName(sendFiles[i].getName()); fileData.setFileData(String.valueOf(readLine)); readLine = null; System.out.println("Data from bean " + fileData.getFileData()); outputStream = new FileOutputStream("D:/" + sendFiles[i].getName()); outputStream.write(Base64Coder.decode(fileData.getFileData())); outputStream.flush(); outputStream.close(); stream.close(); // FileData fileDetails = new FileData(); // fileDetails = fileData; // filesDetails.add(fileData); filesData = new FileData[(int) sendFiles[i].length()]; } // return fileData; } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } catch (Exception e) { e.printStackTrace(); } return filesData; } } Also The Interface MultipleFiles:- public interface MultipleFiles extends Remote { public FileData[] sendPDFs() throws FileNotFoundException, IOException, Exception; } Here I am sending an array of bean "File Data",having properties viz. FileData & FileName. FileData- contains file data in encoded. FileName- encoded file name. The Bean:- (FileData) public class FileData { private String fileName; private String fileData; public String getFileName() { return fileName; } public void setFileName(String fileName) { this.fileName = fileName; } public String getFileData() { return fileData; } public void setFileData(String string) { this.fileData = string; } } The android DDMS gives out of memory exception when tried below code & when i tried to send two files then only first file is created. public class PDFActivity extends Activity { private final String METHOD_NAME = "sendPDFs"; private final String NAMESPACE = "http://webservice.uks.com/"; private final String SOAP_ACTION = NAMESPACE + METHOD_NAME; private final String URL = "http://192.168.1.123:8080/AIPWebService/services/MultipleFilesImpl"; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); TextView textViewOne = (TextView) findViewById(R.id.textViewOne); try { SoapObject soapObject = new SoapObject(NAMESPACE, METHOD_NAME); SoapSerializationEnvelope envelope = new SoapSerializationEnvelope( SoapEnvelope.VER11); envelope.setOutputSoapObject(soapObject); textViewOne.setText("Web Service Started"); AndroidHttpTransport httpTransport = new AndroidHttpTransport(URL); httpTransport.call(SOAP_ACTION, envelope); // SoapObject result = (SoapObject) envelope.getResponse(); Object result = envelope.getResponse(); Log.i("Result", result.toString()); // String fileName = result.getProperty("fileName").toString(); // String fileData = result.getProperty("fileData").toString(); // Log.i("File Name", fileName); // Log.i("File Data", fileData); // File pdfFile = new File(fileName); // FileOutputStream outputStream = // openFileOutput(pdfFile.toString(), // MODE_PRIVATE); // outputStream.write(Base64Coder.decode(fileData)); Log.i("File", "File Created"); // textViewTwo.setText(result); // Object result = envelope.getResponse(); // FileOutputStream outputStream = openFileOutput(name, mode) } catch (Exception e) { e.printStackTrace(); } } } Please help with some explanation or changes in my code. Thanks in Advance.

    Read the article

  • Encryption using rijndael

    - by user363295
    Hi all. I'm quite new in programming .I wrote the below code in order to prompt the user for a password to encrypting a file, But it just work when the length of password is 8, What can I do on order to accepting any number of characters for the password? string pass = textBox2.Text.ToString(); string password = @"" + pass + ""; UnicodeEncoding UE = new UnicodeEncoding(); byte[] key = UE.GetBytes(password); FileStream fsCrypt = new FileStream(@"c:\\users\\new", FileMode.Create); name = fsCrypt.Name; RijndaelManaged RMCrypto = new RijndaelManaged(); CryptoStream cs = new CryptoStream(fsCrypt, RMCrypto.CreateEncryptor(key, key), CryptoStreamMode.Write); FileStream fsIn = new FileStream(filename, FileMode.Open); int data; while ((data = fsIn.ReadByte()) != -1) cs.WriteByte((byte)data);

    Read the article

  • How to pass special characters so ASP.NET MVC can handle correctly query string data?

    - by labilbe
    Hello, I am using a route like this one: routes.MapRoute("Invoice-New-NewCustomer", "Invoice/New/Customer/New/{*name}", new { controller = "Customer", action = "NewInvoice" }, new { name = @"[^\.]*" }); There is an action which handles this route: public ActionResult NewInvoice(string name) { AddClientSideValidation(); CustomerViewData viewData = GetNewViewData(); viewData.InvoiceId = "0"; viewData.Customer.Name = name; return View("New", viewData); } When I call return RedirectToAction("NewInvoice", "Customer", new {name}); and name is equal to "The C# Guy", the "name" parameter is truncated to "The C". So my question is : What is the best way to handle this kind of special character with ASP.NET MVC? Thanks!

    Read the article

  • Grouping a generic list via LINQ in VB.NET

    - by CD Smith
    I need to take a collection and group it via Linq but all the examples I've seen fail in some manner or other with some syntax difference that I can't quite lick. My collection: Dim a As New List(Of ProcessAlert) a.Add(New ProcessAlert("0000112367", "[email protected]", "Alert", 2)) a.Add(New ProcessAlert("0000112367", "[email protected]", "Document", 2)) a.Add(New ProcessAlert("0000112367", "[email protected]", "Note", 2)) a.Add(New ProcessAlert("0000112367", "[email protected]", "Alert", 1)) a.Add(New ProcessAlert("0000112367", "[email protected]", "Document", 1)) a.Add(New ProcessAlert("0000112367", "[email protected]", "Note", 1)) Return a I need to turn this collection into a simple way to give this final outcome: "[email protected]", "Alert, Document, Note" "[email protected]", "Alert, Document, Note" Here's the definition of the ProcessAlert class: Public Class ProcessAlert Public LoanNumber As String Public EmailAddress As String Public AlertType As String Public AlertMethodID As Byte End Class Thanks in advance, CD

    Read the article

  • Using STI path with same controller

    - by TenJack
    I am using STI and am wondering, do I have to have a separate controller for each model? I have a situation where I only use the create and edit actions for one model in the STI relationship, but I get an 'undefined method' error if I try to do a form for. More specifically, I have two models that inherit from List: class RegularList < List class OtherList < List and I have a lists controller that handles these actions, but I only create new models with RegularList using forms. i.e. the only situation where I use a form_for to create a new List object is with RegularList. What I would like to do is something like: class ListsController < ApplicationController def new @list = RegularList.new end otherwise the route for creating a new list looks like regular_list/new but I would like it to just be list/new. Thoughts?

    Read the article

  • My Lucene queries only ever find one hit

    - by Bob
    I'm getting started with Lucene.Net (stuck on version 2.3.1). I add sample documents with this: Dim indexWriter = New IndexWriter(indexDir, New Standard.StandardAnalyzer(), True) Dim doc = Document() doc.Add(New Field("Title", "foo", Field.Store.YES, Field.Index.TOKENIZED, Field.TermVector.NO)) doc.Add(New Field("Date", DateTime.UtcNow.ToString, Field.Store.YES, Field.Index.TOKENIZED, Field.TermVector.NO)) indexWriter.AddDocument(doc) indexWriter.Close() I search for documents matching "foo" with this: Dim searcher = New IndexSearcher(indexDir) Dim parser = New QueryParser("Title", New StandardAnalyzer()) Dim Query = parser.Parse("foo") Dim hits = searcher.Search(Query) Console.WriteLine("Number of hits = " + hits.Length.ToString) No matter how many times I run this, I only ever get one result. Any ideas?

    Read the article

  • Validate an XML File Against Multiple Schema Definitions

    - by Jon
    I'm trying to validate an XML file against a number of different schemas (apologies for the contrived example): a.xsd b.xsd c.xsd c.xsd in particular imports b.xsd and b.xsd imports a.xsd, using: <xs:include schemaLocation="b.xsd"/> I'm trying to do this via Xerces in the following manner: XMLSchemaFactory xmlSchemaFactory = new XMLSchemaFactory(); Schema schema = xmlSchemaFactory.newSchema(new StreamSource[] { new StreamSource(this.getClass().getResourceAsStream("a.xsd"), "a.xsd"), new StreamSource(this.getClass().getResourceAsStream("b.xsd"), "b.xsd"), new StreamSource(this.getClass().getResourceAsStream("c.xsd"), "c.xsd")}); Validator validator = schema.newValidator(); validator.validate(new StreamSource(new StringReader(xmlContent))); but this is failing to import all three of the schemas correctly resulting in cannot resolve the name 'blah' to a(n) 'group' component. I've validated this successfully using Python, but having real problems with Java 6.0 and Xerces 2.8.1. Can anybody suggest what's going wrong here, or an easier approach to validate my XML documents?

    Read the article

  • java socket programming problem

    - by mk.persia
    Hi, what's wrong with my code? sorry about my bad English package sockettest; import java.io.*; import java.net.*; class sevr implements Runnable{ public void run() { ServerSocket sSkt = null; Socket skt = null; BufferedReader br = null; BufferedWriter bw = null; try{ System.out.println("Server: is about to create socket"); sSkt = new ServerSocket(6666); System.out.println("Server: socket created"); } catch(IOException e){ System.out.println("Server: socket creation failure"); } try{ System.out.println("Server: is listening"); skt = sSkt.accept(); System.out.println("Server: Connection Established"); } catch(IOException e){ System.out.println("Server: listening failed"); } try{ System.out.println("Server: creating streams"); br = new BufferedReader(new InputStreamReader(skt.getInputStream())); bw = new BufferedWriter(new OutputStreamWriter(skt.getOutputStream())); System.out.println("Server: stream done"); } catch(IOException e){ System.out.println("Server: stream failed"); } System.out.println("Server: reading the request"); try{ String line = null; while((line =br.readLine()) != null){ System.out.println("Server: client said- "+ line); } } catch(IOException e){ System.out.println("Server: reading failed"); } System.out.println("Server: reading fished"); System.out.println("Server: responding"); try{ bw.write("Hi! I am server!"); } catch(IOException e){ System.out.println("Server: responding failed"); } System.out.println("Server: responding finished"); System.out.println("Server: is finishing"); try { br.close(); bw.close(); skt.close(); sSkt.close(); } catch (IOException e) { System.out.println("Server: finishing failed"); } System.out.println("Server: done"); } } class clnt implements Runnable{ public void run() { Socket skt = null; BufferedReader br = null; BufferedWriter bw = null; try{ System.out.println("Client: about to create socket"); skt = new Socket(InetAddress.getLocalHost(),6666); System.out.println("Client: socket created"); } catch(IOException e){ System.out.println("Client: socket creation failure"); } try{ System.out.println("Client: creating streams"); br = new BufferedReader(new InputStreamReader(skt.getInputStream())); bw = new BufferedWriter(new OutputStreamWriter(skt.getOutputStream())); System.out.println("Client: stream done"); } catch(IOException e){ System.out.println("Client: stream failed"); } System.out.println("Client: requesting"); try{ bw.write("Hi! I am Client!"); } catch(IOException e){ System.out.println("Client: requesting failed"); } System.out.println("Client: requesting finished"); System.out.println("Client: reading the respond"); try{ String line = null; while((line =br.readLine()) != null){ System.out.println("Client: server said- "+ line); } } catch(IOException e){ System.out.println("Client: reading failed"); } System.out.println("Client: reading fished"); System.out.println("Clientrver: is finishing"); try { br.close(); bw.close(); skt.close(); } catch (IOException e) { System.out.println("Client: finishing failed"); } System.out.println("Client: done"); } } public class Main { public static void main(String[] args) { System.out.println("Main started"); Thread sThread = new Thread(new sevr()); Thread cThread = new Thread(new clnt()); sThread.start(); cThread.start(); try { sThread.join(); cThread.join(); } catch (InterruptedException ex) { System.out.println("joining failed"); } System.out.println("Main done"); } } output: Main started Server: is about to create socket Client: about to create socket Client: socket created Client: creating streams Server: socket created Server: is listening Server: Connection Established Server: creating streams Server: stream done Server: reading the request Client: stream done Client: requesting Client: requesting finished Client: reading the respond and it waits here forever!

    Read the article

  • How do i have optional parameter but still validate them in asp.net mvc routing ?

    - by ooo
    I have this route that i just added routes.MapRoute( "MyRoute", "MyController/{action}/{orgId}/{startDate}/{endDate}", new { controller = "MyController", action = "MyAction", orgId = 0, startDate = DateTime.Today.AddMonths(-1), endDate = DateTime.Today }, new { action = new FromValuesListConstraint(new string[] { "MyAction", "MyActionEx" }), orgId = new IntegerRouteConstraint(), startDate = new DateTimeRouteConstraint(), endDate = new DateTimeRouteConstraint() } when i put in this url, it resolves down to the default route (controller, action,id) and the above rout does not catch this url: http://localhost:1713/MyController/MyAction/16 But this below works fine. http://localhost:1713/MyController/MyAction/16/11-May-10/11-May-10 my question is that i thought both would work as i am giving default values to the startDate and enddate fields i tested this using the RouteDebugger and this route turned up false how can i have these last two parameter as optional but still have the validation ?

    Read the article

  • Final enum in Thread's run() method

    - by portoalet
    Hi, Why is the Elvis elvis definition has to be final to be used inside the Thread run() method? Elvis elvis = Elvis.INSTANCE; // ----> should be final Elvis elvis = Elvis.INSTANCE elvis.sing(4); Thread t1 = new Thread( new Runnable() { @Override public void run() { elvis.sing(6); // --------> elvis has to be final to compile } } ); public enum Elvis { INSTANCE(2); Elvis() { this.x = new AtomicInteger(0); } Elvis(int x){ this.x = new AtomicInteger(x); } private AtomicInteger x = new AtomicInteger(0); public int getX() { return x.get(); } public void setX(int x) {this.x = new AtomicInteger(x);} public void sing(int x) { this.x = new AtomicInteger(x); System.out.println("Elvis singing.." + x); } }

    Read the article

  • Creating ActionEvent object for CustomButton in Java

    - by Crystal
    For a hw assignment, we were supposed to create a custom button to get familiar with swing and responding to events. We were also to make this button an event source which confuses me. I have an ArrayList to keep track of listeners that would register to listen to my CustomButton. What I am getting confused on is how to notify the listeners. My teacher hinted at having a notify and overriding actionPerformed which I tried doing, but then I wasn't sure how to create an ActionEvent object looking at the constructor documentation. The source, id, string all confuses me. Any help would be appreciated. Thanks! code: import java.awt.*; import java.awt.event.*; import javax.swing.*; import java.util.List; import java.util.ArrayList; public class CustomButton { public static void main(String[] args) { EventQueue.invokeLater(new Runnable() { public void run() { CustomButtonFrame frame = new CustomButtonFrame(); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setVisible(true); } }); } public void addActionListener(ActionListener al) { listenerList.add(al); } public void removeActionListener(ActionListener al) { listenerList.remove(al); } public void actionPerformed(ActionEvent e) { System.out.println("Button Clicked!"); } private void notifyListeners() { ActionEvent event = new ActionEvent(CONFUSED HERE!!!!; for (ActionListener action : listenerList) { action.actionPerfomed(event); } } List<ActionListener> listenerList = new ArrayList<ActionListener>(); } class CustomButtonFrame extends JFrame { // constructor for CustomButtonFrame public CustomButtonFrame() { setTitle("Custom Button"); CustomButtonSetup buttonSetup = new CustomButtonSetup(); this.add(buttonSetup); this.pack(); } } class CustomButtonSetup extends JComponent { public CustomButtonSetup() { ButtonAction buttonClicked = new ButtonAction(); this.addMouseListener(buttonClicked); } // because frame includes borders and insets, use this method public Dimension getPreferredSize() { return new Dimension(200, 200); } public void paintComponent(Graphics g) { Graphics2D g2 = (Graphics2D) g; // first triangle coords int x[] = new int[TRIANGLE_SIDES]; int y[] = new int[TRIANGLE_SIDES]; x[0] = 0; y[0] = 0; x[1] = 200; y[1] = 0; x[2] = 0; y[2] = 200; Polygon firstTriangle = new Polygon(x, y, TRIANGLE_SIDES); // second triangle coords x[0] = 0; y[0] = 200; x[1] = 200; y[1] = 200; x[2] = 200; y[2] = 0; Polygon secondTriangle = new Polygon(x, y, TRIANGLE_SIDES); g2.drawPolygon(firstTriangle); g2.setColor(firstColor); g2.fillPolygon(firstTriangle); g2.drawPolygon(secondTriangle); g2.setColor(secondColor); g2.fillPolygon(secondTriangle); // draw rectangle 10 pixels off border int s1[] = new int[RECT_SIDES]; int s2[] = new int[RECT_SIDES]; s1[0] = 5; s2[0] = 5; s1[1] = 195; s2[1] = 5; s1[2] = 195; s2[2] = 195; s1[3] = 5; s2[3] = 195; Polygon rectangle = new Polygon(s1, s2, RECT_SIDES); g2.drawPolygon(rectangle); g2.setColor(thirdColor); g2.fillPolygon(rectangle); } private class ButtonAction implements MouseListener { public void mousePressed(MouseEvent e) { System.out.println("Click!"); firstColor = Color.GRAY; secondColor = Color.WHITE; repaint(); } public void mouseReleased(MouseEvent e) { System.out.println("Released!"); firstColor = Color.WHITE; secondColor = Color.GRAY; repaint(); } public void mouseEntered(MouseEvent e) {} public void mouseExited(MouseEvent e) {} public void mouseClicked(MouseEvent e) {} } public static final int TRIANGLE_SIDES = 3; public static final int RECT_SIDES = 4; private Color firstColor = Color.WHITE; private Color secondColor = Color.DARK_GRAY; private Color thirdColor = Color.LIGHT_GRAY; }

    Read the article

  • Consuming Web Service via Windows Authentication

    - by saravanaram
    I am just trying to consuming a web service in remote computer using windows authentication however login credentials are different in local & remote computer. Code Snippet: Dim objproxy As New WebReference.Service1 'Create a new instance of CredentialCache. Dim mycredentialCache As CredentialCache = New CredentialCache() 'Create a new instance of NetworkCredential using the client Dim credentials As NetworkCredential = New NetworkCredential("username", "pwd","domain") 'Add the NetworkCredential to the CredentialCache. 'mycredentialCache.Add(New Uri(objproxy.Url), "Basic", credentials) objproxy.Credentials = credentials It is timing out but when i use mycredentialCache.Add(New Uri(objproxy.Url), "Basic", credentials) I get "401 Unauthorized" message, Please assist.

    Read the article

  • very simple delegate musing

    - by Ted
    Sometimes the simplest questions make me love C/C++ and C# more and more. Today sitting on the bus musing aout delegates I remembered reading somwhere you don't need to use the new keyword when instaniating a new delegate. For example: public static void SomeMethod(string message) { ... } ... public delegate void TestDelgate(string message); //Define a delegate ........... //create a new instance ..METHOD 1 TestDelgate t = new TestDelgate(SomeMethod); //OR another way to create a new instance ..METHOD 2 TestDelgate t = SomeMethod; //create a new instance ..METHOD 2 So todays questions are What happens under the hood in method 2. Does the compiler expand method 2 into method 1, hence writing TestDelgate t = SomeMethod; is just a shortcut for TestDelgate t = new TestDelgate(SomeMethod);, or is there another reason for the exsitence of method 2 Do you guys think method 1 or method 2 is better for readability (this is a subjective question, but I'd just like to get a unscientific feel of general opinion of stackoverflow :-))

    Read the article

  • how to write a text file after the previous line in c#??

    - by riad
    Dear all, My below code create a txt file and write something to that file.but i need to write new line after the previous lines when i run the script several times. code: string filePath = "D:\\DOT_NET\\C#\\abc.txt"; FileInfo t = new FileInfo(filePath); StreamWriter Tex = t.CreateText(); Tex.WriteLine("Hi freinds"); Tex.WriteLine("csharpfriends is the new url for c-sharp"); Tex.Write(Tex.NewLine); Tex.Close(); current output on the abc.txt file: Hi friends csharpfriends is the new url for c-sharp but i need the output if i run the script several times. Hi friends csharpfriends is the new url for c-sharp Hi friends csharpfriends is the new url for c-sharp Hi friends csharpfriends is the new url for c-sharp How can i do that? Pls help thanks Riad

    Read the article

  • Javascript Regex: how to remove string before > and including >

    - by Kim Jong Woo
    I have a string like so item[3]>something>another>more[1]>here hey>this>is>something>new . . . I would like to produce the following for each iteration indicated by each new line item[3]>something>another>more[1]>here something>another>more[1]>here another>more[1]>here more[1]>here here Another example: hey>this>is>something>new this>is>something>new is>something>new something>new new I would like a regex or some way to incrementally remove the furthest left string up to .

    Read the article

  • Image loader cant load my live image url

    - by Bindhu
    In my application i need to load the images in list view, when using locale(ip ported url) then no problem all images are loading properly, But when using live url then the images are not loading, My image loader class: public class ImageLoader { MemoryCache memoryCache = new MemoryCache(); FileCache fileCache; private Map<ImageView, String> imageViews = Collections .synchronizedMap(new WeakHashMap<ImageView, String>()); ExecutorService executorService; public ImageLoader(Context context) { fileCache = new FileCache(context); executorService = Executors.newFixedThreadPool(5); } final int stub_id = R.drawable.appointeesample; public void DisplayImage(String url, ImageView imageView) { imageViews.put(imageView, url); Bitmap bitmap = memoryCache.get(url); if (bitmap != null) imageView.setImageBitmap(bitmap); else { Log.d("stub", "stub" + stub_id); queuePhoto(url, imageView); imageView.setImageResource(stub_id); } } private void queuePhoto(String url, ImageView imageView) { PhotoToLoad p = new PhotoToLoad(url, imageView); executorService.submit(new PhotosLoader(p)); } private Bitmap getBitmap(String url) { File f = fileCache.getFile(url); // from SD cache Bitmap b = decodeFile(f); if (b != null) return b; // from web try { Bitmap bitmap = null; URL imageUrl = new URL(url); HttpURLConnection conn = (HttpURLConnection) imageUrl .openConnection(); conn.setConnectTimeout(30000); conn.setReadTimeout(30000); conn.setInstanceFollowRedirects(true); InputStream is = conn.getInputStream(); BufferedInputStream bis = new BufferedInputStream(is, 81960); BitmapFactory.Options opts = new BitmapFactory.Options(); opts.inJustDecodeBounds = true; OutputStream os = new FileOutputStream(f); Utils.CopyStream(bis, os); os.close(); bitmap = decodeFile(f); Log.d("bitmap", "Bit map" + bitmap); return bitmap; } catch (Exception ex) { ex.printStackTrace(); return null; } } // decodes image and scales it to reduce memory consumption private Bitmap decodeFile(File f) { try { try { BitmapFactory.Options o = new BitmapFactory.Options(); o.inJustDecodeBounds = true; BitmapFactory.decodeStream(new FileInputStream(f), null, o); final int REQUIRED_SIZE = 200; int scale = 1; while (o.outWidth / scale / 2 >= REQUIRED_SIZE && o.outHeight / scale / 2 >= REQUIRED_SIZE) scale *= 2; BitmapFactory.Options o2 = new BitmapFactory.Options(); o2.inSampleSize = scale; return BitmapFactory.decodeStream(new FileInputStream(f), null, o2); } catch (FileNotFoundException e) { } finally { System.gc(); } return null; } catch (Exception e) { } return null; } // Task for the queue private class PhotoToLoad { public String url; public ImageView imageView; public PhotoToLoad(String u, ImageView i) { url = u; imageView = i; } } class PhotosLoader implements Runnable { PhotoToLoad photoToLoad; PhotosLoader(PhotoToLoad photoToLoad) { this.photoToLoad = photoToLoad; } @Override public void run() { if (imageViewReused(photoToLoad)) return; Bitmap bmp = getBitmap(photoToLoad.url); memoryCache.put(photoToLoad.url, bmp); if (imageViewReused(photoToLoad)) return; BitmapDisplayer bd = new BitmapDisplayer(bmp, photoToLoad); Activity a = (Activity) photoToLoad.imageView.getContext(); a.runOnUiThread(bd); } } boolean imageViewReused(PhotoToLoad photoToLoad) { String tag = imageViews.get(photoToLoad.imageView); if (tag == null || !tag.equals(photoToLoad.url)) return true; return false; } // Used to display bitmap in the UI thread class BitmapDisplayer implements Runnable { Bitmap bitmap; PhotoToLoad photoToLoad; public BitmapDisplayer(Bitmap b, PhotoToLoad p) { bitmap = b; photoToLoad = p; } public void run() { if (imageViewReused(photoToLoad)) return; if (bitmap != null) photoToLoad.imageView.setImageBitmap(bitmap); else photoToLoad.imageView.setImageResource(stub_id); } } public void clearCache() { memoryCache.clear(); fileCache.clear(); } My Live Image url for Example: https://goappointed.com/images_upload/3330Torana_Logo.JPG I have referred google but no solution is working, Thanks a lot in advance.

    Read the article

  • Using methods on 2 input files - 2nd is printing multiple times - Java

    - by Aaa
    I have the following code to read in text, store in a hashmap as bigrams (with other methods to sort them by frequency and do v. v. basic additive smoothing. I had it working great for one language input file (english) and then I want to expand it for the second language input file (japanese - doens;t matter what it is I suppose) using the same methods but the Japanese bigram hashmap is printing out 3 times in a row with diff. values. I've tried using diff text in the input file, making sure there are no gaps in text etc. I've also put print statements at certain places in the Japanese part of the code to see if I can get any clues but all the print statements are printing each time so I can't work out if it is looping at a certain place. I have gone through it with a fine toothcomb but am obviously missing something and slowly going crazy here - any help would be appreciated. thanks in advance... package languagerecognition2; import java.lang.String; import java.io.InputStreamReader; import java.util.*; import java.util.Iterator; import java.util.List.*; import java.util.ArrayList; import java.util.AbstractMap.*; import java.lang.Object; import java.io.*; import java.util.Enumeration; import java.util.Arrays; import java.lang.Math; public class Main { /** public static void main(String[] args) { //training English ----------------------------------------------------------------- File file = new File("english1.txt"); StringBuffer contents = new StringBuffer(); BufferedReader reader = null; try { reader = new BufferedReader(new FileReader(file)); String test = null; //test = reader.readLine(); // repeat until all lines are read while ((test = reader.readLine()) != null) { test = test.toLowerCase(); char[] charArrayEng = test.toCharArray(); HashMap<String, Integer> hashMapEng = new HashMap<String, Integer>(bigrams(charArrayEng)); LinkedHashMap<String, Integer> sortedListEng = new LinkedHashMap<String, Integer>(sort(hashMapEng)); int sizeEng=sortedListEng.size(); System.out.println("Total count of English bigrams is " + sizeEng); LinkedHashMap<String, Integer> smoothedListEng = new LinkedHashMap<String, Integer>(smooth(sortedListEng, sizeEng)); //print linkedHashMap to check values Set set= smoothedListEng.entrySet(); Iterator iter = set.iterator ( ) ; System.out.println("Beginning English"); while ( iter.hasNext()) { Map.Entry entry = ( Map.Entry ) iter.next ( ) ; Object key = entry.getKey ( ) ; Object value = entry.getValue ( ) ; System.out.println( key+" : " + value); } System.out.println("End English"); }//end while }//end try catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { try { if (reader != null) { reader.close(); } } catch (IOException e) { e.printStackTrace(); } } //End training English----------------------------------------------------------- //Training japanese-------------------------------------------------------------- File file2 = new File("japanese1.txt"); StringBuffer contents2 = new StringBuffer(); BufferedReader reader2 = null; try { reader2 = new BufferedReader(new FileReader(file2)); String test2 = null; //repeat until all lines are read while ((test2 = reader2.readLine()) != null) { test2 = test2.toLowerCase(); char[] charArrayJap = test2.toCharArray(); HashMap<String, Integer> hashMapJap = new HashMap<String, Integer>(bigrams(charArrayJap)); //System.out.println( "bigrams stage"); LinkedHashMap<String, Integer> sortedListJap = new LinkedHashMap<String, Integer>(sort(hashMapJap)); //System.out.println( "sort stage"); int sizeJap=sortedListJap.size(); //System.out.println("Total count of Japanese bigrams is " + sizeJap); LinkedHashMap<String, Integer> smoothedListJap = new LinkedHashMap<String, Integer>(smooth(sortedListJap, sizeJap)); System.out.println( "smooth stage"); //print linkedHashMap to check values Set set2= smoothedListJap.entrySet(); Iterator iter2 = set2.iterator(); System.out.println("Beginning Japanese"); while ( iter2.hasNext()) { Map.Entry entry2 = ( Map.Entry ) iter2.next ( ) ; Object key = entry2.getKey ( ) ; Object value = entry2.getValue ( ) ; System.out.println( key+" : " + value); }//end while System.out.println("End Japanese"); }//end while }//end try catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { try { if (reader2 != null) { reader2.close(); } } catch (IOException e) { e.printStackTrace(); } } //end training Japanese--------------------------------------------------------- } //end main (inner)

    Read the article

  • How can I delete a specific element in priority queue?

    - by Yuan
    import java.util.*; public class test4 { public static void main(String[] args){ PriorityQueue[] P = new PriorityQueue[10]; P[1] = new PriorityQueue<ClassEntry>(); P[1].add(new ClassEntry(1.2,1)); P[1].add(new ClassEntry(1.5,2)); P[1].add(new ClassEntry(1.2,3)); P[1].add(new ClassEntry(10,4)); P[1].remove(new ClassEntry(10,4));//I can't delete this object??? System.out.println(P[1].size()); ClassEntry ce = (ClassEntry) P[1].peek(); System.out.println(P[1].size()); System.out.println(ce.sim+"\t"+ce.index); } } Why i can't delete (10,4)? Can somebody teach how to implement...thanks!

    Read the article

  • How do I return the IDENTITY for an inserted record from a stored Proecedure?

    - by user54197
    I am adding data to my database, but would like to retrieve the UnitID that is Auto generated. using (SqlConnection connect = new SqlConnection(connections)) { SqlCommand command = new SqlCommand("ContactInfo_Add", connect); command.Parameters.Add(new SqlParameter("name", name)); command.Parameters.Add(new SqlParameter("address", address)); command.Parameters.Add(new SqlParameter("Product", name)); command.Parameters.Add(new SqlParameter("Quantity", address)); command.Parameters.Add(new SqlParameter("DueDate", city)); connect.Open(); command.ExecuteNonQuery(); } ... ALTER PROCEDURE [dbo].[Contact_Add] @name varchar(40), @address varchar(60), @Product varchar(40), @Quantity varchar(5), @DueDate datetime AS BEGIN SET NOCOUNT ON; INSERT INTO DBO.PERSON (Name, Address) VALUES (@name, @address) INSERT INTO DBO.PRODUCT_DATA (PersonID, Product, Quantity, DueDate) VALUES (@Product, @Quantity, @DueDate) END

    Read the article

  • What the best way to convert from String to HashMap?

    - by eugenn
    I would like to serialize a Java HashMap to string representation. The HashMap will contains only primitive values like string and integer. After that this string will be stored to db. How to restore back the HashMap? Is it make sense to use BeanUtils and interface Converter or use JSON? For example: List list = new ArrayList(); list.add(new Long(1)); list.add(new Long(2)); list.add(new Long(4)); Map map = new HashMap(); map.put("cityId", new Integer(1)); map.put("name", "test"); map.put("float", new Float(-3.2)); map.put("ids", list); map.toString() -> {float=-3.2,ids=[1, 2, 4],name=test,cityId=1} map.toJSON -> {"float":-3.2,"ids":[1,2,4],"name":"test","cityId":1}

    Read the article

  • Java, merging two arrays evenly

    - by user2435044
    What would be the best way to merge two arrays of different lengths together so they are evenly distributed in the new array? Say I have the following arrays String[] array1 = new String[7]; String[] array2 = new String[2]; String[] mergedArray = new String[array1.length + array2.length]; I would want mergedArray to have the following elements array1 array1 array1 array2 array1 array1 array1 array2 array1 but if I were to change the size of the arrays to String[] array1 = new String[5]; String[] array2 = new String[3]; String[] mergedArray = new String[array1.length + array2.length]; then I would want it to be array1 array2 array1 array2 array1 array2 array1 array1 basically if it can be helped each array2 element shouldn't be touching each other; exception if array2 has a size larger than array1.

    Read the article

  • Java: empty ArrayLists in a foor loop

    - by Patrick
    hi, I'm reusing the same ArrayList in a for loop, and I use for loop results = new ArrayList<Integer>(); experts = new ArrayList<Integer>(); output = new ArrayList<String>(); .... to create new ones. I guess this is wrong, because I'm allocating new memory. Is this correct ? If yes, how can I empty them ? Added: another example I'm creating new variables each time I call this method. Is this good practice ? I mean to create new precision, relevantFound.. etc ? Or should I declare them in my class, outside the method to not allocate more and more memory ? public static void computeMAP(ArrayList results, ArrayList experts) { //compute MAP double precision = 0; int relevantFound = 0; double sumprecision = 0; thanks

    Read the article

  • How to bind WPF TreeView to a List<Drink> programmatically?

    - by Joan Venge
    So I am very new to WPF and trying to bind or assign a list of Drink values to a wpf treeview, but don't know how to do that, and find it really hard to find anything online that just shows stuff without using xaml. struct Drink { public string Name { get; private set; } public int Popularity { get; private set; } public Drink ( string name, int popularity ) : this ( ) { this.Name = name; this.Popularity = popularity; } } List<Drink> coldDrinks = new List<Drink> ( ){ new Drink ( "Water", 1 ), new Drink ( "Fanta", 2 ), new Drink ( "Sprite", 3 ), new Drink ( "Coke", 4 ), new Drink ( "Milk", 5 ) }; } } How can I do this in code? For example: treeview1.DataItems = coldDrinks; and everything shows up in the treeview.

    Read the article

  • Help with getting data from resized image.

    - by nick
    I'm using an ASP.NET file upload control and then resizing an image and storing the new image in a new Bitmap. Here is the code I have so far: protected void ResizeImage() { Bitmap originalBMP = new Bitmap(FileUpload1.FileContent); //Calculate new image dimensions int origWidth = originalBMP.Width; int origHeight = originalBMP.Height; int sngRatio = origWidth / origHeight; int newWidth = 100; int newHeight = newWidth / sngRatio; Bitmap newBMP = new Bitmap(originalBMP, newWidth, newHeight); } I'm uploading directly to Amazon S3 and I need to pass some data to its upload method. How do I get the following information from my new bitmap that I have been using with the fileupload?: FileUpload1.FileBytes FileUpload1.FileBytes.Length Do I need to save my new bitmap to a stream so I can get an array of bytes?

    Read the article

  • Our Look at Opera 10.50 Web Browser

    - by Asian Angel
    Everyone has been talking about the newest version of Opera recently but perhaps you have not looked at it too closely yet. Today we will take a look at 10.50 and let you see what this “new browser” is all about. The New Engines Carakan JavaScript Engine: Runs web applications up to 7 times faster than its predecessor Futhark Vega Graphics Library: Enables super fast and smooth graphics on everything from tab switching to webpage animation Presto 2.5: Provides support for HTML5, CSS2.1 and the latest CSS3 standards A Look at the Features Available If you have installed or used older versions of Opera before then the default look after a clean install will probably seem rather different. The main differences in appearance are mainly located within the “glass border” areas of the browser. The “Speed Dial” setup looks and works just as well as in previous versions. You can set a favorite wallpaper or image as your background and choose the number of “dials” using the “Configure Speed Dial Command”. One of the “standout” differences is the “O Button”. All of the menus have been condensed into this single access point but it only takes a few moments to find what you are looking for. If you have used the style before in earlier versions of Opera some of the items have been moved around. For those who prefer the “Menu Bar” that can be easily restored using the “Show Menu Bar Command”. If desired you can actually “extend” the “Tab Bar” downwards to display thumbnails of your open tabs. Just use your mouse to grab the bottom of the “Tab Bar” and adjust it to suit your personal needs. The only problem with this feature is that it will quickly use up a good sized portion of your available UI and browser window space. The “Password Manager” is ready to access when needed…the background for the button will turn a shiny metallic blue when you open a webpage that you have “Login Information” saved for. One of the new features is a small “Recycle Bin Button” in the upper right corner. Clicking on this will display a list of recently closed tabs letting you have easy access to any tabs that you may have accidentally closed. This is definitely a great feature to have as an easy access button. For those who were used to how the “Zoom Feature” looked before it has a new “look” to it. Instead of the pop-up menu-type listing of “view sizes” present before you now have a slider button that you can use to adjust the zooming level. For our default setup here the “Sidebar Panels” available were: “Bookmarks, Widgets, Unite, Notes, Downloads, History, & Panels”. Additional panels such as “Links, Windows, Search, Info, etc.” are available if you want and/or need them (accessible using the “Panels Plus Sign Button”). The “Opera Link Button” makes it easy for you to synchronize your “Speed Dial, Bookmarks, Personal Bar, Custom Searches, History & Notes”. Note: “Opera Link” requires an account and can be signed up for using the link provided below. Want to share files with your family and friends? “Unite” allows you to do that and more. With “Unite” you can: “Stream Music, Show Photo Galleries, Share Files and/or Folders, & host webpages directly from your browser”. We have a more in-depth look at “Unite” in our article here. Note: Use of “Unite” requires an Opera account. Got a slow internet connection? “Opera Turbo” can help with that by running the web traffic through their “compression servers” to speed up your web browsing. Keep in mind that “Opera Turbo” will not engage if you are accessing a secure website (i.e. your bank’s website) thus preserving your security. Note: “Opera Turbo” can be set up to automatically detect slow internet connections (i.e. crowded Wi-Fi in a cafe). Opera has a built-in “Private Browsing Mode” now for those who prefer anonymous browsing and want to keep the “history records clean” on their computer. To access it go to “Tabs and windows” and select “New private tab” or “New private window” as desired. When you open your new “Private Tab or Window” you will see the following message with details on how Opera will handle browsing information and a large “door hanger symbol”. Notice that the one tab is locked into “Private Browsing Mode” while the others are still working in “Regular Browsing Mode”. Very nice! A miniature version of the “door hanger symbol” will be present on any tab that is locked into “Private Browsing Mode”. If you are using Windows 7 then you will love how things look from your “Taskbar”. Here you can see four very nice looking thumbnails for the tabs that we had open. All that you have to do is click on the desired thumbnail… The “Context Menu” looks just as lovely as the thumbnails and definitely has some terrific functionality built into it. Add Enhanced Aero Capability If you love “Aero” and want more for your new Opera install then we have the perfect theme for you. The theme’s name is Z1-AV69 and once you have downloaded it you will need to place it in the “Skins Subfolder” in Opera’s “Program Files Folder”. Note: For our example we used version 1.10 but version 2.00 is now available (link provided below). Once you have restarted Opera, go to the “O Menu” and select “Appearance”. When the “Appearance Window” opens click on “Z1-Glass Skin” and then click “OK”. All of a sudden you will have more “Aero Goodness” to enjoy. Compare this screenshot with the one at the top of this article…the only part that is not transparent now is the browser window area itself. Want even more “Aero Goodness”? Right click on the “Tab Bar” and set “Tab Bar Placement” to “Left”. Note: You can achieve the same effect by setting the “Tab Bar Placement” to “Right”. With the “Speed Dial” visible you will be able to see your wallpaper with ease. While this is obviously not for everyone it does make for a great visual trick. Portable Versions Perhaps you need this wonderful new version of Opera to go with you wherever you do during the day. Not a problem…just visit the Opera USB website to choose a version that works best for you. You can select from “Zip or Exe” setup files and if needed update an older portable version using a “Zipped Update Files Package”. If you are updating an older version keep in mind that you will need to delete the old “OperaUSB.exe. File” due to changes with the new setup files. During our tests updating older portable versions went well for the most part but we did experience a few “odd UI quirks” here and there…so we recommend setting up a clean install if possible. Conclusion The new 10.50 release is a pleasure to use and is a recommended install for your system. Whether you are considering trying Opera for the first time or have been using it for a bit we think that you will pleased with everything that the 10.50 release has to offer. For those who would like to add User Scripts to Opera be certain to look at our how-to article here. Links Download Opera 10.50 for your location (Windows) Get the latest Snapshot versions for Linux & Mac Sign up for an Opera Link account View In-Depth detail on Opera 10.50’s features Download the Z1-AV69 Aero Theme Download Portable Opera 10.50 Similar Articles Productive Geek Tips Set the Speed Dial as the Opera Startup PageSet Up User Scripts in Opera BrowserScan Files for Viruses Before You Download With Dr.WebTurn Your Computer into a File, Music, and Web Server with Opera UniteSet the Default Browser on Ubuntu From the Command Line TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Make your Joomla & Drupal Sites Mobile with OSMOBI Integrate Twitter and Delicious and Make Life Easier Design Your Web Pages Using the Golden Ratio Worldwide Growth of the Internet How to Find Your Mac Address Use My TextTools to Edit and Organize Text

    Read the article

< Previous Page | 341 342 343 344 345 346 347 348 349 350 351 352  | Next Page >