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  • Chroot jail of Nginx and php

    - by sqren
    I'm hosting multiple websites on one VPS, and want to chroot each website, eg. /chroot/website1 /chroot/website2 I'm using makejail, which is a highlevel tool, for creating the jails, and copying the libraries and dependencies. Easy peasy. Each website will need nginx, php and mysql. For php I'm using php5-fpm which actually supports chroot by configuration, however I'm not using this (maybe I should?) My question is which approach of the following three is the better: 1) Every website will have its own seperated instance of nginx, php and mysql. The downside is, that each webserver + php has to listen to a different port. I also need a "master" nginx web server in front of them, reverse proxying to the chrooted servers behind it. Probably most secure, but also most advanced. 2) I don't make any chroot jails manually. I setup one nginx web server, that proxies php requests to php-fpm, on different ports. I can have multiple php-fpm configurations each with is own chroot'ed folder. This is quite managable - however only php will be chrooted. Not the actual webserver. Is this secure enough. Also, I tried this option out, and it seems I will need to use TCP instead of sockets for connecting to MySQL. 3) You tell me ;) I'm quite new to chroot jailing, so please correct me if I'm wrong in my assumptions. I've been reading all the tutorials I could find, however, I find the market for chroot guides very scarce. Any help or inputs much appreciated!

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  • A complicated nginx/php-fpm chroot setup

    - by Rsaesha
    I'm running nginx and php-fpm, and I want to set up jails for each host. My setup is a little complicated, so following tutorials on the web gets me nowhere. Each site has a directory /var/www/domain.name/ Inside that directory, there will be a public/ directory which will be the website root, a logs/ directory which will store nginx logs for that site specifically, and the chroot filesystem (etc/, usr/, etc.) The first problem I've run into is that nomatter how I configure it, PHP-FPM cannot find the files that are passed to it via nginx. They result in a "Primary script unknown" error, and to make matters worse, the error messages from PHP-FPM are no more verbose than that, so I can't figure out what path is being passed by nginx. A php-fpm pool configuration for a host looks like this: [host] user = host group = www-data chroot = /var/www/domain.name chdir = /public listen = 127.0.0.1:900x 'x' is incremented for each pool. The nginx config for this host looks like this: server { listen 80; server_name domain.name *.domain.name; root /var/www/domain.name/public; index index.php index.html index.html; location ~ \.php$ { expires epoch; fastcgi_split_path_info ^(.+\.php)(/.+)$; include fastcgi_params; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; fastcgi_pass 127.0.0.1:9001; } } I'm guessing that the problem is the SCRIPT_FILENAME parameter, but I've changed it to just $fastcgi_script_name, and various other combinations, but to no avail. Can anyone help?

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  • Apache is sending php files to my browser instead of parsing

    - by justen doherty
    i have to setup php on an existing web host, i have made a virtual host entry but for some reason apache is sending the php to the browser instead of parsing.. from googling around it looks like its a problem with the mimetypes, but im not an apache expert by any means - so if anyone can help it would be appreciated... i have the following in my httpd.conf AddHandler php5-script php DirectoryIndex index.html index.phtml index.php index.phps AddType application/x-httpd-php .phtml AddType application/x-httpd-php .php AddType application/x-httpd-php-source .phps the php module is loaded into apache: /usr/sbin/apachectl -M Loaded Modules: core_module (static) mpm_prefork_module (static) http_module (static) so_module (static) auth_basic_module (shared) auth_digest_module (shared) authn_file_module (shared) authn_alias_module (shared) authn_anon_module (shared) authn_dbm_module (shared) authn_default_module (shared) authz_host_module (shared) authz_user_module (shared) authz_owner_module (shared) authz_groupfile_module (shared) authz_dbm_module (shared) authz_default_module (shared) ldap_module (shared) authnz_ldap_module (shared) include_module (shared) log_config_module (shared) logio_module (shared) env_module (shared) ext_filter_module (shared) mime_magic_module (shared) expires_module (shared) deflate_module (shared) headers_module (shared) usertrack_module (shared) setenvif_module (shared) mime_module (shared) dav_module (shared) status_module (shared) autoindex_module (shared) info_module (shared) dav_fs_module (shared) vhost_alias_module (shared) negotiation_module (shared) dir_module (shared) actions_module (shared) speling_module (shared) userdir_module (shared) alias_module (shared) rewrite_module (shared) proxy_module (shared) proxy_balancer_module (shared) proxy_ftp_module (shared) proxy_http_module (shared) proxy_connect_module (shared) cache_module (shared) suexec_module (shared) disk_cache_module (shared) file_cache_module (shared) mem_cache_module (shared) cgi_module (shared) version_module (shared) fcgid_module (shared) perl_module (shared) php5_module (shared) proxy_ajp_module (shared) ssl_module (shared) and this is my virtual host entry: ServerName viridor-cms.co.uk ServerAlias www.viridor-cms.co.uk UseCanonicalName Off DocumentRoot /var/www/vhosts/viridor-cms.co.uk/httpdocs CustomLog /var/www/vhosts/viridor-cms.co.uk/cms-access_log common ErrorLog /var/www/vhosts/viridor-cms.co.uk/cms-error_log DirectoryIndex index.php index.html php_admin_flag engine on php_admin_flag safe_mode on php_admin_flag engine on php_admin_flag safe_mode on AddType application/x-httpd-php .php AddType application/x-httpd-php-source .phps please help, my head is so sore from banging it againest the table and the wall !

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  • codesniffer command not being recognized after several installs and upgrades

    - by numerical25
    I've tried to install codesniffer using pear but my mac is not recognizing the phpcs command. pear config Configuration (channel pear.php.net): ===================================== Auto-discover new Channels auto_discover 1 Default Channel default_channel pear.php.net HTTP Proxy Server Address http_proxy <not set> PEAR server [DEPRECATED] master_server pear.php.net Default Channel Mirror preferred_mirror pear.php.net Remote Configuration File remote_config <not set> PEAR executables directory bin_dir /usr/local/pear/bin PEAR documentation directory doc_dir /usr/local/pear/docs PHP extension directory ext_dir /opt/local/lib/php/extensions/no-debug-non-zts-20090626 PEAR directory php_dir /usr/local/pear/share/pear PEAR Installer cache directory cache_dir /private/tmp/pear/cache PEAR configuration file cfg_dir /usr/local/pear/cfg directory PEAR data directory data_dir /usr/local/pear/data PEAR Installer download download_dir /tmp/pear/install directory PHP CLI/CGI binary php_bin /opt/local/bin/php php.ini location php_ini /opt/local/etc/php5/php.ini-development --program-prefix passed to php_prefix <not set> PHP's ./configure --program-suffix passed to php_suffix <not set> PHP's ./configure PEAR Installer temp directory temp_dir /tmp/pear/install PEAR test directory test_dir /usr/local/pear/tests PEAR www files directory www_dir /usr/local/pear/www Cache TimeToLive cache_ttl 3600 Preferred Package State preferred_state stable Unix file mask umask 22 Debug Log Level verbose 1 PEAR password (for password <not set> maintainers) Signature Handling Program sig_bin /usr/local/bin/gpg Signature Key Directory sig_keydir /opt/local/etc/pearkeys Signature Key Id sig_keyid <not set> Package Signature Type sig_type gpg PEAR username (for username <not set> maintainers) User Configuration File Filename /Users/anthonygordon/.pearrc System Configuration File Filename /opt/local/etc/pear.conf i checked php_bin and the php executable is there. when i run phpcs i get command not found Ive tried to upgrade pear, uninstall reinstall code sniffer, everything. when i run installs list i get Pear List Package Version State Archive_Tar 1.3.10 stable Console_Getopt 1.3.1 stable PEAR 1.9.4 stable PHP_CodeSniffer 1.4.0 stable Structures_Graph 1.0.4 stable XML_Util 1.2.1 stable

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  • PHP, jQuery and Ajax Object Orientation

    - by pastylegs
    I'm a fairly experienced programmer getting my head around PHP and Ajax for the first time, and I'm having a bit of trouble figuring out how to incorperate object oriented PHP into my ajax webapp. I have an admin page (admin.php) that will load and write information (info.xml) from an XML file depending on the users selection of a form on the admin page. I have decided to use an object (ContentManager.php) to manage the loading and writing of the XML file to disk, i.e : class ContentManager{ var $xml_attribute_1 ... function __construct(){ //load the xml file from disk and save its contents into variables $xml_attribute = simplexml_load_file(/path/to/xml) } function get_xml_contents(){ return xml_attribute; } function write_xml($contents_{ } function print_xml(){ } } I create the ContentManager object in admin.php like so <?php include '../includes/CompetitionManager.php'; $cm = new CompetitionManager() ?> <script> ...all my jquery </script> <html> ... all my form elements </html> So now I want to use AJAX to allow the user to retrieve information from the XML file via the ContentManger app using an interface (ajax_handler.php) like so <?php if(_POST[]=="get_a"){ }else if() } ... ?> I understand how this would work if I wasn't using objects, i.e. the hander php file would do a certain action depending on a variable in the .post request, but with my setup, I can't see how I can get a reference to the ContentManager object I have created in admin.php in the ajax_handler.php file? Maybe my understanding of php object scope is flawed. Anyway, if anyone can make sense of what I'm trying to do, I would appreciate some help!

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  • Updating PHP on Linux - "No Packages marked for Update"?

    - by Aristotle
    I'm very new to server-administration, but I was thinking the task of updating PHP to 5.2+ should be relatively simple. Online I found that the following was allegedly sufficient to do this: yum update php But when I run this, the following is output: [root@ip-XXX-XXX-XXX-XXX /]# php -v PHP 5.1.6 (cli) (built: Jan 13 2010 17:13:05) Copyright (c) 1997-2006 The PHP Group Zend Engine v2.1.0, Copyright (c) 1998-2006 Zend Technologies [root@ip-XXX-XXX-XXX-XXX /]# yum update php Loaded plugins: fastestmirror Determining fastest mirrors * addons: p3plmirror02.prod.phx3.secureserver.net * base: p3plmirror02.prod.phx3.secureserver.net * extras: p3plmirror02.prod.phx3.secureserver.net * turbopanel-base: p3plmirror02.prod.phx3.secureserver.net * turbopanel-centos5: p3plmirror02.prod.phx3.secureserver.net * update: p3plmirror02.prod.phx3.secureserver.net addons | 951 B 00:00 addons/primary | 201 B 00:00 base | 2.1 kB 00:00 base/primary_db | 1.6 MB 00:00 extras | 1.1 kB 00:00 extras/primary | 107 kB 00:00 extras 325/325 turbopanel-base | 951 B 00:00 turbopanel-base/primary | 72 kB 00:00 turbopanel-base 494/494 turbopanel-centos5 | 951 B 00:00 turbopanel-centos5/primary | 2.1 kB 00:00 turbopanel-centos5 8/8 update | 1.9 kB 00:00 update/primary_db | 463 kB 00:00 Setting up Update Process No Packages marked for Update [root@ip-XXX-XXX-XXX-XXX /]# php -v PHP 5.1.6 (cli) (built: Jan 13 2010 17:13:05) Copyright (c) 1997-2006 The PHP Group Zend Engine v2.1.0, Copyright (c) 1998-2006 Zend Technolog [root@ip-XXX-XXX-XXX-XXX /]# No Packages marked for Update [root@ip-XXX-XXX-XXX-XXX /]# php -v bash: No: command not found [root@ip-XXX-XXX-XXX-XXX /]# [root@ip-XXX-XXX-XXX-XXX /]# php -v bash: [root@ip-XXX-XXX-XXX-XXX: command not found [root@ip-XXX-XXX-XXX-XXX /]# PHP 5.1.6 (cli) (built: Jan 13 2010 17:13:05) bash: syntax error near unexpected token `(' [root@ip-XXX-XXX-XXX-XXX /]# Copyright (c) 1997-2006 The PHP Group bash: syntax error near unexpected token `c' [root@ip-XXX-XXX-XXX-XXX /]# Zend Engine v2.1.0, Copyright (c) 1998-2006 Zend Technologies bash: syntax error near unexpected token `(' [root@ip-XXX-XXX-XXX-XXX /]# My PHP version is 5.1.6 before, and after running the command. Am I being too naive here with this update process? Is there a more verbose route that is necessary for me to take?

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  • SuPHP custom php.ini doesn't get read

    - by Mathieu Dumoulin
    Took me about 4 hours to get a FastCGI + SuPHP running off Ubuntu 11.10 and i'm now happy that it works mighty fine except for ONE big problem. Custom php.ini's don't seem to load. I tried changing some options and then firing off a phpinfo() and nothing changes in the phpinfo() which leads me to think that there is definitely a problem with the loading of the configuration file. <IfModule mod_suphp.c> AddHandler x-httpd-php .php <Location /> SuPHP_AddHandler x-httpd-php </Location> suPHP_ConfigPath /home/mdumoulin/Documents/tests/tests suPHP_Engine on </IfModule> As you can see, i took great care in making sure i wasn't referencing the php.ini file itself but the directory of the vhost. In the php.ini located in "/home/mdumoulin/Documents/tests/tests/php.ini", you can find: [PHP] error_reporting = E_ALL & ~E_DEPRECATED & ~E_NOTICE display_errors = Off And the log in /var/log/suphp/suphp.log doesn't contain anything relevant, (only old errors that occured before this post while i was testing suphp... So i'm stumped there, dunno what more i can do! Anyone got an idea? EDIT: FINALY, got time to work on this, i disabled FCGI and only enabled SuPHP but after restarting i still see "Server API: CGI/FastCGI". Is this what i should be getting or not? I believe that it's normal i get CGI since SUPHP works with a CGI... But i'm not too sure anymore...

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  • Handling Errors In PHP When Using MVC

    - by James Jeffery
    I've been using Codeigniter a lot recently, but one thing that gets on my nerves is handling errors and displaying them to the user. I've never been good at handling errors without it getting messy. My main concern is when returning errors to the user. Is it good practice to use exceptions and throw/catch exceptions rather than returning 0 or 1 from functions and then using if/else to handle the errors. Thus, making it easier to inform the user about the issue. I tend to go away from exceptions. My Java tutor at university some years ago told me "exceptions shouldn't be used in production code it's more for debugging". I get the feeling he was lying. But, an example, I have code that adds a user to a database. During the process more than 1 thing could go wrong, such as a database issue, a duplicate entry, a server issue, etc. When an issue happens during registration the user needs to know about it. What's the best way to handle errors in PHP, keeping in mind that I'm using an MVC framework.

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  • What do I need to develop a PHP extension in lampp?

    - by Fernando Costa
    Actually I'm dealing with a trouble in my system, I have to delivery the system to clients and it was built in PHP, JS, ShellScript and SQL. I would like to encrypt the code or obfuscate it from eyes of others! Then someone from the community told me about build my own PHP extension, it sounds to me as a great idea, since it will not be with the main code of the system. But I have a problem doing this way, if a programmer get in the extensions and find it, all the hard work has gone. Then I'm here to ask again about this matter. What is the best way to hide my Business Logic from third parties? I know that has stuffs like IonCube, Zend Guard, and many others. But I'm looking something that I can build myself. Is PHP extension the right way to follow? Or some Half SaaS system, with dependencies (Business Logic) in a remote server? About the environment OS: Kernel Linux 2.6.37.1-1.2 - LAMPP (Apache 2.2, MySQL 5.5 PHP 5.3.8) In php generally the extension is located at /php/ext/ but in lampp I have no idea where it is, I just found a folder /opt/lampp/lib/php/extensions/ is that right place?

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  • php on ubuntu 13.10 won't get parsed

    - by fefe
    I'm facing a strange issue with a fresh installed ubuntu 13.10 apache2 with mysql and php. My php won't get parsed and I have been doing every changes what I found during my researches PHP 5.5.3-1ubuntu2 (cli) (built: Oct 9 2013 14:49:12) sudo a2enmod php5 apache2.conf <FilesMatch \.php$> SetHandler application/x-httpd-php </FilesMatch> /etc/apache2/mods-enabled/php5.conf </FilesMatch> # Deny access to files without filename (e.g. '.php') <FilesMatch "^\.ph(p[345]?|t|tml|ps)$"> Order Deny,Allow Deny from all </FilesMatch> # Running PHP scripts in user directories is disabled by default # # To re-enable PHP in user directories comment the following lines # (from <IfModule ...> to </IfModule>.) Do NOT set it to On as it # prevents .htaccess files from disabling it. #<IfModule mod_userdir.c> # <Directory /home/*/public_html> # php_admin_value engine Off # </Directory> #</IfModule>

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  • How can I add my desired links to be read using PHP Universal FeedParser

    - by lightingwrist
    Hello, I have been trying to use the PHP Universal FeedParser to read RSS feeds and display the output on my site. Problem is I am VERY green with this and although it seems very simple. the only link that is working is the link provided in the sample. When I try to add another address with the xml or rss.php extensions, I keep getting errors,the page is loading blank,or the designated area for the feeds is blank. In addition to this, how can I add multiple links to feeds in a syntactically correct manor and how can I limit the amount of feeds? Thank you Here it is: <?php require_once($_SERVER['DOCUMENT_ROOT'] . '/includes/system/FeedParser.php'); $Parser = new FeedParser(); $Parser->parse("http://www.sitepoint.com/rss.php"); $channels = $Parser->getChannels(); $items = $Parser->getItems(); ?> and then: <div id="rss_feeder"> <h1 id="title"><a href="<?php echo $channels['LINK']; ?>"><?php echo $channels['TITLE']; ?></a></h1> <p id="description"><?php echo $channels['DESCRIPTION']; ?> </p> <?php foreach($items as $item): ?> <a class="feed-title" href="<?php echo $item['LINK']; ?>"><?php echo $item['TITLE']; ?></a> <p class="feed-description"><?php echo $item['DESCRIPTION']; ?></p> <?php endforeach;?> </div>

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  • n00b needs some PHP syntax guidance [closed]

    - by Michael
    If you look at http://www.cruc.es/?paged=12/ and go to the bottom of the page you'll see the bottom navigation with the next and previous options. I've been able to make the page numbers work by changing page to paged= in the code. I don't know enough about PHP to get the previous/next options to work. Any advice would be appreciated and I've pasted the code below. Thank you: n00b if ( $query->found_posts > $query->query_vars["posts_per_page"] ) { echo '<ul class="paging">'; // Previous link? if ( $page > 1 ) { echo '<li class="previous"><a href="'.$baseURL.'/page/'.($page-1).'/'.$qs.'">previous</a></li>'; } // Loop through pages for ( $i=1; $i <= $query->max_num_pages; $i++ ) { // Current page or linked page? if ( $i == $page ) { echo '<li class="active">'.$i.'</li>'; } else { echo '<li><a href="'.$baseURL.'/?paged='.$i.'/'.$qs.'">'.$i.'</a></li>'; } } // Next link? if ( $page < $query->max_num_pages ) { echo '<li><a href="'.$baseURL.'/page/'.($page+1).'/'.$qs.'">next</a></li>'; } echo '</ul>'; }

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  • (PHP vs Python vs Perl) vs Ruby [closed]

    - by Dr.Kameleon
    OK, here's what : I've programmed in over 20 different languages and now, because of a large project I'm currently working on for Mac OS X (in Objective-C/Cocoa), I need to make a final decision on which language to use for my background scripting + plugin functionality. Definitely, one factor that'll ultimately influence my decision is which one I'm most familiar with, which is PHP (one of the ugliest languages around, which I however adore... lol), then Python / Perl (the "proven values"... )... and then Ruby (which, to me, is almost confusing and I've only played with it for some time.) Now, here's my considerations : (As previously mentioned) Being familiar with it (anyway, if X is better in my case, I really don't mind studying it from scratch...) Speed Good interaction with the Shell + ease of integration with my Cocoa application Btw, some of the reasons that made me wonder if Ruby would be a good choice is : The hype around it (although, I still don't get why; but that's probably just me...) My major competitor (we're actually talking about the same type of software here) is using Ruby for its backend scripting almost exclusively (ok, along with some BASH). Isn't Ruby considered slower e.g. than Perl? Why did he choose that? Simply, a matter of personal taste? So... your thoughts?

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  • PHP ORM style of querying

    - by Petah
    Ok so I have made an ORM library for PHP. It uses syntax like so: *(assume that $business_locations is an array)* Business::type(Business:TYPE_AUTOMOTIVE)-> size(Business::SIZE_SMALL)-> left_join(BusinessOwner::table(), BusinessOwner::business_id(), SQL::OP_EQUALS, Business::id())-> left_join(Owner::table(), SQL::OP_EQUALS, Owner::id(), BusinessOwner::owner_id())-> where(Business::location_id(), SQL::in($business_locations))-> group_by(Business::id())-> select(SQL::count(BusinessOwner::id()); Which can also be represented as: $query = new Business(); $query->set_type(Business:TYPE_AUTOMOTIVE); $query->set_size(Business::SIZE_SMALL); $query->left_join(BusinessOwner::table(), BusinessOwner::business_id(), SQL::OP_EQUALS, $query->id()); $query->left_join(Owner::table(), SQL::OP_EQUALS, Owner::id(), BusinessOwner::owner_id()); $query->where(Business::location_id(), SQL::in($business_locations)); $query->group_by(Business::id()); $query->select(SQL::count(BusinessOwner::id()); This would produce a query like: SELECT COUNT(`business_owners`.`id`) FROM `businesses` LEFT JOIN `business_owners` ON `business_owners`.`business_id` = `businesses`.`id` LEFT JOIN `owners` ON `owners`.`id` = `business_owners`.`owner_id` WHERE `businesses`.`type` = 'automotive' AND `businesses`.`size` = 'small' AND `businesses`.`location_id` IN ( 1, 2, 3, 4 ) GROUP BY `businesses`.`id` Please keep in mind that the syntax might not be prefectly correct (I only wrote this off the top of my head) Any way, what do you think of this style of querying? Is the first method or second better/clearer/cleaner/etc? What would you do to improve it?

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  • Turn off gzip for a location in Nginx

    - by Nyxynyx
    How can gzip be turned off for a particular location and all its sub-directories? My main site is at http://mydomain.com and I want to turn gzip off for both http://mydomain.com/foo and http://mydomain.com/foo/bar. gzip is turned on in nginx.conf. I tried turning off gzip as shown below, but the Response Headers in Chrome's dev tools shows that Content-Encoding:gzip. How should gzip/output buffering be disabled properly? Attempt: server { listen 80; server_name www.mydomain.com mydomain.com; access_log /var/log/nginx/access.log; error_log /var/log/nginx/error.log; root /var/www/mydomain/public; index index.php index.html; location / { gzip on; try_files $uri $uri/ /index.php?$args ; } location ~ \.php$ { fastcgi_pass unix:/var/run/php5-fpm.sock; fastcgi_index index.php; include fastcgi_params; fastcgi_read_timeout 300; } location /foo/ { gzip off; try_files $uri $uri/ /index.php?$args ; } }

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  • How can I call a URL as a cron job in Webmin?

    - by EmmyS
    (Possibly this belongs on stackoverflow, although it's not really a programming issue since the code works when run directly. If it needs to be moved, though, no problem.) I have a PHP file (which consumers a National Weather Service web service via SOAP, if it matters) that I need to run on a scheduled basis. I'm trying to set up a cron job in Webmin. If I use an absolute path to the file in the Command field, when I run it I get some strange errors: /var/www/html/mysite.com/test/ndfdXMLclient.php: line 1: ?php: No such file or directory /var/www/html/mysite.com/test/ndfdXMLclient.php: line 2: //: is a directory /var/www/html/mysite.com/test/ndfdXMLclient.php: line 3: //DOCUMENTATION: No such file or directory /var/www/html/mysite.com/test/ndfdXMLclient.php: line 4: //: is a directory /var/www/html/mysite.com/test/ndfdXMLclient.php: line 5: syntax error near unexpected token `"running client code",' /var/www/html/mysite.com/test/ndfdXMLclient.php: line 5: `error_log("running client code", 1, "[email protected]");' The actual code in my file for those 5 lines looks like this: <?php // *************************************************************************** //DOCUMENTATION FROM WEATHER.GOV ALL STORED IN xmlClientComments.txt // *************************************************************************** error_log("running client code", 1, "[email protected]"); The code runs perfectly fine when I run it directly in my browser, so why doesn't webmin recognize it as code? (The same thing happens if I enter the actual URL in the command field - http://mysite.com/test/ndfdXMLclient.php.) I've never worked with webmin before; most of our hosts' cron control panels allow cron jobs to run PHP files like this with no issue. Is there some trick to getting webmin to read php as actual php?

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  • PHP, MySQL: mysql substitute for php in_array function

    - by Devner
    Hi all, Say if I have an array and I want to check if an element is a part of that array, I can go ahead and use in_array( needle, haystack ) to determine the results. I am trying to see the PHP equivalent of this for my purpose. Now you might have an instant answer for me and you might be tempted to say "Use IN". Yes, I can use IN, but that's not fetching the desired results. Let me explain with an example: I have a column called "pets" in DB table. For a record, it has a value: Cat, dog, Camel (Yes, the column data is a comma separated value). Consider that this row has an id of 1. Now I have a form where I can enter the value in the form input and use that value check against the value in the DB. So say I enter the following comma separated value in the form input: CAT, camel (yes, CAT is uppercase & intentional as some users tend to enter it that way). Now when I enter the above info in the form input and submit, I can collect the POST'ed info and use the following query: $search = $_POST['pets']; $sql = "SELECT id FROM table WHERE pets IN ('$search') "; The above query is not fetching me the row that already exists in the DB (remember the record which has Cat, dog, Camel as the value for the pets column?). I am trying to get the records to act as a superset and the values from the form input as subsets. So in this case I am expecting the id value to show up as the values exist in the column, but this is not happending. Now say if I enter just CAT as the form input and perform the search, it should show me the ID 1 row. Now say if I enter just camel, cAT as the form input and perform the search, it should show me the ID 1 row. How can I achieve the above? Thank you.

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  • PHP/MySQL Database application development tool

    - by RCH
    I am an amateur PHP coder, and have built a couple of dozen projects from scratch (including fairly simple e-commerce systems with user authentication, PayPal integration etc - all coded by hand from a clean page. Have also done a price comparison engine that takes data from multiple sites etc.). But I am no expert with OO and other such advanced techniques - I just have a fairly decent grasp of the basics of data processing, logic, functions and trying to optimize code as much as possible. I just want to make this clear so you have some idea of where I'm coming from. I have a couple of fairly large new projects on my plate for corporate clients - both require bespoke database-driven applications with complex relationships, many tables and lots of different front-end functions to manipulate that data for the internal staff in these companies. I figured building these systems from scratch would probably be a huge waste of time. Instead, there must be tools out there that will allow me to construct MySQL databases and build the pages with things like pagination, action buttons, table construction etc. Some kind of database abstraction layer, or system generator, if you will. What tool do you recommend for such a purpose for someone at my level? Open source would be great, but I don't mind paying for something decent as well. Thanks for any advice.

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  • PHP W3 Validator API, Is this good? [closed]

    - by Josh Purcell
    I was trying to find a way to see if my site's code was valid or not but I continuously going over to W3 Validator so I decided to make an "API" however it really isn't! I just wanted to know if anybody can find a better solution to the one I have made. This is what I currently use, with the usage of ?uri=http://www.mydomain.com : <?php if(!$_GET['uri']) { echo "No URI!"; } else { $CheckURI = "http://validator.w3.org/check?uri=".$_GET['uri']; $URL = file_get_contents($CheckURI); $Start = strpos($URL, "<title>") + 7; $End = strpos($URL, "</title>"); $Title = substr($URL, $Start, $End-$Start); if(preg_match('[Invalid]',$Title)) { //Code is INVALID echo "<a href='$CheckURI' title='This is not good!' target='_BLANK'>INVALID Source</a>"; } elseif(preg_match('[Valid]',$Title)) { //Code is VALID echo "<a href='$CheckURI' title='Check It Yourself!' target='_BLANK'>Valid Source</a>"; } else { //It Went WRONG echo ""; } }

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  • Building PHP For MacOS

    - by Eray
    I was using XAMPP and decided to uninstall it and use MacOS' in-built apache and php modules. But while uninstalling XAMPP I deleted /usr/bin/php files and other PHP-CLI files accidentally. And I decided to install newest version of PHP (5.5.12) instead of rebuilding current version (5.4.24). Downloaded it and unzip. After this executed this command as mentioned at this guide. ./configure '--with-apxs2=/usr/sbin/apxs' '--enable-cli' '--with-config-file-path=/etc' '--with-zlib=/usr' '--enable-bcmath' '--with-bz2=/usr' '--enable-calendar' '--disable-cgi' '--with-curl=/usr' '--enable-dba' '--enable-ndbm=/usr' '--enable-exif' '--enable-fpm' '--enable-ftp' '--with-gd' '--enable-gd-native-ttf' '--enable-mbregex' '--with-mysql=mysqlnd' '--with-mysqli=mysqlnd' '--with-pear' '--with-pdo-mysql=mysqlnd' '--with-mysql-sock=/var/mysql/mysql.sock' '--with-tidy' '--enable-wddx' '--with-xmlrpc' '--enable-zip' make make install When i check phpinfo() , it's still version 5.4.24 . This line from my httpd.conf LoadModule php5_module libexec/apache2/libphp5.so /usr/libexec/apache2/libphp5.so coming from old version and i couldn't ind libphp5.so for new version. There is no libphp5.so file inside modules dir. How can i use new PHP build with Apache ? UPDATE Results of php -v command . PHP 5.5.12 (cli) (built: May 27 2014 05:17:21) Copyright (c) 1997-2014 The PHP GroupZend Engine v2.5.0, Copyright (c) 1998-2014 Zend Technologies

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  • proc_open() path problem

    - by fadib
    Hi, i'm using linux and php 5.2.12 i have problem with executing proc_open if i use proc_open('php script.php', $descriptorspec, $pipes); it will show me error sh: /php: No such file or directory if i use proc_open('/usr/bin/php script.php', $descriptorspec, $pipes); or proc_open('php script.php', $descriptorspec, $pipes, '/usr/bin/'); it still show me same error. i have no idea why it always append slash in front of command. any help please? thanks!

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  • PHP-based indexing and search implementation

    - by Chris
    Is there such thing? I designed a while back a rudimentary form based app for my users. We receive from our suppliers hardware manufacturing data in XML files: file name is made of eleven fields separated by tildes, with each field having its own meaning. R&D guys wanted to be able to search each field of the file names so I used regex() with decent results. Problem is that we have now in the upwards of 2.5 million files. And my app can't hack it anymore. I looked at Apache Lucene & Solr. Though it seemed like the best solution to my problem, the fields in the filenames are not peers to the file content. Big no-no with Solr. What is the best way to implement a PHP app with indexing and search capability with such large number of files? Do I have to buy Zend and use Zend_Search? Is it the only way? Thanks for your input.

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  • Basic PHP OOPS Query

    - by appu
    Ok. I am starting out OOPS in PHP. Created a couple of classes: customer(parent) and sales(child) class that inherits from parent class. Created another testcustomer.php in which a new sales object is created however the salesprint() function defined in the sales class does not echo out customer's name though it is set to be "Jane" in the class.customer.php(parent). My thinking is that when sales class extends customer class PHP automatically includes all the code from class.customer.php to sales.customer.php and therefore the constructor in parent class set $name to "Jane". Here is the code: class.customer.php <?php class customer{ private $name; private $cust_no; public function __construct($customerid) { $this->name = 'Jane'; $this->cust_no = $customerid; } } ?> class.sales.php <?php require_once('class.customer.php'); class sales extends customer{ public function salesprint($customerid) { echo "Hello $this->name this is a print of your purchased products"; } } ?> testcustomer.php require_once('class.sales.php'); $objsales = new sales(17); $objsales->salesprint(17); ?> The Output I get Hello this is a print of your purchased products. What am i doing wrong ? thanks romesh

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  • PHP Calculating Text to Content Ratio

    - by James
    I am using the following code to calculate text to code ratio. I think it is crazy that no one can agree on how to properly calculate the result. I am looking any suggestions or ideas to improve this code that may make it more accurate. <?php // Returns the size of the content in bytes function findKb($content){ $count=0; $order = array("\r\n", "\n", "\r", "chr(13)", "\t", "\0", "\x0B"); $content = str_replace($order, "12", $content); for ($index = 0; $index < strlen($content); $index ++){ $byte = ord($content[$index]); if ($byte <= 127) { $count++; } else if ($byte >= 194 && $byte <= 223) { $count=$count+2; } else if ($byte >= 224 && $byte <= 239) { $count=$count+3; } else if ($byte >= 240 && $byte <= 244) { $count=$count+4; } } return $count; } // Collect size of entire code $filesize = findKb($content); // Remove anything within script tags $code = preg_replace("@<script[^>]*>.+</script[^>]*>@i", "", $content); // Remove anything within style tags $code = preg_replace("@<style[^>]*>.+</style[^>]*>@i", "", $content); // Remove all tags from the system $code = strip_tags($code); // Remove Extra whitespace from the content $code = preg_replace( '/\s+/', ' ', $code ); // Find the size of the remaining code $codesize = findKb($code); // Calculate Percentage $percent = $codesize/$filesize; $percentage = $percent*100; echo $percentage; ?> I don't know the exact calculations that are used so this function is just my guess. Does anyone know what the proper calculations are or if my functions are close enough for a good judgement.

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  • Good links somehow being converted to ones with a PHP redirect (not a virus)

    - by Rebecca
    This has happened to links we put on web pages and in emails. We might put www.oursite.org/work/ but when I view source it shows up as webmail.ourhosting.ca/hwebmail/services/go.php?url=https%3A%2F%2Fwww.oursite.org%2F%2work%2F This ends up at the webmail login page for our web host. But only some of the people who click the link get the login page; others go directly to the original page we intended. We don't want it to go to the webmail login page, nobody needs to log in to our web site. This occurs for links to pages on our site, but also to links to other sites that we put in emails or in posts. It seems to be browser independent as well as e-mail client independent as we variously have used Firefox and Chrome as well as MS Outlook and Thunderbird. I've tried to resolve the issue with our webhost but they keep telling me they don't support our browser, or our email client (i.e., they don't understand the issue). At the moment, our only option is to try another web host just to get rid of their login. Any ideas about what's going on?

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