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  • How to get the IP Address for your Local Area Connection on Windows Server?

    - by Geo
    I want to create a batch or vbs file that will put together a url and executed. Part of that url needs to be the actual ip address of the machine. How I am able to get that IP address in a variable to include it on the script? EDIT 1: I found out that the command below will give me the IP Address, but still don't know how to get that value into a variable to use it in a script. c:\> wmic NICCONFIG WHERE IPEnabled=true GET IPAddress /format:csv Node,IPAddress IP-0AFB,{10.25.5.2}

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  • Why configuring manual IP do not work for me in DHCP?

    - by user58859
    I have broadband connection in my laptop. It's getting the IP by protocol. configuration is : ip : 192.168.1.2 subnet : 255.255.255.0 gateway : 192.168.1.1 Now I am curious, In IPV4 properties when instead of choosing "Obtain an IP address automatically", I choose "Use the following IP address" and configure everything same, why it do not work? Do DHCP do not work when we configure the IP manually? (operating system : windows-7) EDIT : After configuring the ip manually, when I used ipconfig/all , it's showing dhcp enabled : NO. I am not doing it. Why it got disabled automatically? and how to enable it? DHCP Enabled. . . . . . . . . . . : No Autoconfiguration Enabled . . . . : Yes IPv4 Address. . . . . . . . . . . : 192.168.1.2(Preferred) Subnet Mask . . . . . . . . . . . : 255.255.255.0 Default Gateway . . . . . . . . . : 192.168.1.1 NetBIOS over Tcpip. . . . . . . . : Enabled

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  • Can I determine a machine's outward facing IP with PHP without relying on external services?

    - by editor
    I'm working with an API that requires the machine's external IP. As far as I know, the PHP environment I'm using can only get our internal IP. The option on the table is using an external service such as whatismyip.com to tell us: wget -q -O - http://whatismyip.com/automation/n09230945.asp My concern is what happens if that fails. Is there a bulletproof way of determining a machine's IP without relying on external services?

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  • Maximum Length Of IP Address: 15 (IPv4) & 39(IPv6)

    - by Gopinath
    Problem You are designing a database table for a web application that requires to store IP address of users who visits the site. The IP address is required to be stored a character data in the table. To define size of the character column you need to know maximum length of IP address. So, what is the maximum length of an IP address? Solution The IPv4 version of IP address is in the following format 255.255.255.255 To store IPv4 address we require 15 characters. The IPv6 version of IP address is grouped into sets of 4 hex digits separated by colons, like the below 2001:0db8:85a3:0000:0000:8a2e:0370:7334 To store IPv6 address you require a 39 characters long column. Conclusion As IPv4 and IPv6 are the commonly use protocols, you better define a column with 39 characters length so that both the format address are saved in to the table without any issues. This article titled,Maximum Length Of IP Address: 15 (IPv4) & 39(IPv6), was originally published at Tech Dreams. Grab our rss feed or fan us on Facebook to get updates from us.

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  • Oracle SOA Suite on Virtual Box

    - by sravan.sarraju(at)oracle.com
    Recently I have started my journey Oracle SOA Suite and the first big hurdle everyone warned me off is setting up Oracle SOA Suite environment in our personal machine for learning. My laziness pushed me to search for much easier way than regular all download, configuration stuff and bang..! I found in the solution oracle site itself. Oracle SOA Suite on Virtual Box. For those who are not aware of Virtual Box, it’s a virtualization software which enables u to install multiple operating systems on a virtual hard drive which in turn managed by Virtual Box. In short pack ur Operating System, Software, Files everything into a VM and carry it wherever u go. Coming to Oracle SOA Suite, Oracle is offering a prebuilt VM for download which u can mount on ur Virtual box and that all you need. Here is the link for Virtual Box image of Oracle SOA Suite. Virtual Box can be downloaded here It’s a huge download. I’m yet to try it myself. Will get back to my writer again once I’m done.

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  • One of my VMs went boom using Virtual Box and how it got fixed

    - by Enrique Lima
    I am running an HP Envy 15, 16GB and 500GB (7200 RPM) Hard drive. Had a VM configured from another environment, created the virtual machine config file on Virtual Box, everything seemed ok. Fired it up, and it was  s   l   o   w, it took close to 10 minutes for it to load, and about 5 more to see Windows was in the process of loading before the BSOD.  Thought, maybe, just maybe it will not happen again … oh was I wrong. Frustration had already hit an all time high with this configuration and the number of issues I’ve had. How I did the troubleshooting … The best thing to do (IMO) is to step back, and gather your tools to debug this situation. Tools:  Virtual Box command line tools, Windows Debug. Virtual Box comes with a pretty good set of tools to examine, migrate and overall tasks to deal with VMs. The firs step:  use VBoxManage to prevent the VM from rebooting after the error to get enough time to really dig into the BSOD issue. Command used:   VBoxManage setextradata VMNAME "VBoxInternal/PDM/HaltOnReset" 1 Once this was done, the error reported was an “Inaccessible boot device” coming from a “Stop – 7B” type of error on the BSOD. The issue I had with this, my VM was configured to use a virtual SATA controller, and thought Windows 2008 R2 would handle this fine … again wrong!  Because the integration tools from the other product where wanting to take effect that was throwing everything off. The fix The fix was almost handed to me, edited the configuration for the VM, removed the SATA controller from it, added the virtual hard drive under an IDE controller, boot up and voilà … it works! I was then able to install the Virtual Box guest tools and such, but have decided to favor “keep on working” over “let’s try SATA again”

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  • Where is the virtual function call overhead?

    - by Semen Semenych
    Hello everybody, I'm trying to benchmark the difference between a function pointer call and a virtual function call. To do this, I have written two pieces of code, that do the same mathematical computation over an array. One variant uses an array of pointers to functions and calls those in a loop. The other variant uses an array of pointers to a base class and calls its virtual function, which is overloaded in the derived classes to do absolutely the same thing as the functions in the first variant. Then I print the time elapsed and use a simple shell script to run the benchmark many times and compute the average run time. Here is the code: #include <iostream> #include <cstdlib> #include <ctime> #include <cmath> using namespace std; long long timespecDiff(struct timespec *timeA_p, struct timespec *timeB_p) { return ((timeA_p->tv_sec * 1000000000) + timeA_p->tv_nsec) - ((timeB_p->tv_sec * 1000000000) + timeB_p->tv_nsec); } void function_not( double *d ) { *d = sin(*d); } void function_and( double *d ) { *d = cos(*d); } void function_or( double *d ) { *d = tan(*d); } void function_xor( double *d ) { *d = sqrt(*d); } void ( * const function_table[4] )( double* ) = { &function_not, &function_and, &function_or, &function_xor }; int main(void) { srand(time(0)); void ( * index_array[100000] )( double * ); double array[100000]; for ( long int i = 0; i < 100000; ++i ) { index_array[i] = function_table[ rand() % 4 ]; array[i] = ( double )( rand() / 1000 ); } struct timespec start, end; clock_gettime(CLOCK_PROCESS_CPUTIME_ID, &start); for ( long int i = 0; i < 100000; ++i ) { index_array[i]( &array[i] ); } clock_gettime(CLOCK_PROCESS_CPUTIME_ID, &end); unsigned long long time_elapsed = timespecDiff(&end, &start); cout << time_elapsed / 1000000000.0 << endl; } and here is the virtual function variant: #include <iostream> #include <cstdlib> #include <ctime> #include <cmath> using namespace std; long long timespecDiff(struct timespec *timeA_p, struct timespec *timeB_p) { return ((timeA_p->tv_sec * 1000000000) + timeA_p->tv_nsec) - ((timeB_p->tv_sec * 1000000000) + timeB_p->tv_nsec); } class A { public: virtual void calculate( double *i ) = 0; }; class A1 : public A { public: void calculate( double *i ) { *i = sin(*i); } }; class A2 : public A { public: void calculate( double *i ) { *i = cos(*i); } }; class A3 : public A { public: void calculate( double *i ) { *i = tan(*i); } }; class A4 : public A { public: void calculate( double *i ) { *i = sqrt(*i); } }; int main(void) { srand(time(0)); A *base[100000]; double array[100000]; for ( long int i = 0; i < 100000; ++i ) { array[i] = ( double )( rand() / 1000 ); switch ( rand() % 4 ) { case 0: base[i] = new A1(); break; case 1: base[i] = new A2(); break; case 2: base[i] = new A3(); break; case 3: base[i] = new A4(); break; } } struct timespec start, end; clock_gettime(CLOCK_PROCESS_CPUTIME_ID, &start); for ( int i = 0; i < 100000; ++i ) { base[i]->calculate( &array[i] ); } clock_gettime(CLOCK_PROCESS_CPUTIME_ID, &end); unsigned long long time_elapsed = timespecDiff(&end, &start); cout << time_elapsed / 1000000000.0 << endl; } My system is LInux, Fedora 13, gcc 4.4.2. The code is compiled it with g++ -O3. The first one is test1, the second is test2. Now I see this in console: [Ignat@localhost circuit_testing]$ ./test2 && ./test2 0.0153142 0.0153166 Well, more or less, I think. And then, this: [Ignat@localhost circuit_testing]$ ./test2 && ./test2 0.01531 0.0152476 Where are the 25% which should be visible? How can the first executable be even slower than the second one? I'm asking this because I'm doing a project which involves calling a lot of small functions in a row like this in order to compute the values of an array, and the code I've inherited does a very complex manipulation to avoid the virtual function call overhead. Now where is this famous call overhead?

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  • capturing video from ip camera

    - by Ruby
    I am trying to capture video from ip camera into my application , its giving exception com.sun.image.codec.jpeg.ImageFormatException: Not a JPEG file: starts with 0x0d 0x0a at sun.awt.image.codec.JPEGImageDecoderImpl.readJPEGStream(Native Method) at sun.awt.image.codec.JPEGImageDecoderImpl.decodeAsBufferedImage(Unknown Source) at test.AxisCamera1.readJPG(AxisCamera1.java:130) at test.AxisCamera1.readMJPGStream(AxisCamera1.java:121) at test.AxisCamera1.readStream(AxisCamera1.java:100) at test.AxisCamera1.run(AxisCamera1.java:171) at java.lang.Thread.run(Unknown Source) its giving exception at image = decoder.decodeAsBufferedImage(); Here is the code i am trying private static final long serialVersionUID = 1L; public boolean useMJPGStream = true; public String jpgURL = "http://ip here/video.cgi/jpg/image.cgi?resolution=640×480"; public String mjpgURL = "http://ip here /video.cgi/mjpg/video.cgi?resolution=640×480"; DataInputStream dis; private BufferedImage image = null; public Dimension imageSize = null; public boolean connected = false; private boolean initCompleted = false; HttpURLConnection huc = null; Component parent; /** Creates a new instance of AxisCamera */ public AxisCamera1(Component parent_) { parent = parent_; } public void connect() { try { URL u = new URL(useMJPGStream ? mjpgURL : jpgURL); huc = (HttpURLConnection) u.openConnection(); // System.out.println(huc.getContentType()); InputStream is = huc.getInputStream(); connected = true; BufferedInputStream bis = new BufferedInputStream(is); dis = new DataInputStream(bis); if (!initCompleted) initDisplay(); } catch (IOException e) { // incase no connection exists wait and try // again, instead of printing the error try { huc.disconnect(); Thread.sleep(60); } catch (InterruptedException ie) { huc.disconnect(); connect(); } connect(); } catch (Exception e) { ; } } public void initDisplay() { // setup the display if (useMJPGStream) readMJPGStream(); else { readJPG(); disconnect(); } imageSize = new Dimension(image.getWidth(this), image.getHeight(this)); setPreferredSize(imageSize); parent.setSize(imageSize); parent.validate(); initCompleted = true; } public void disconnect() { try { if (connected) { dis.close(); connected = false; } } catch (Exception e) { ; } } public void paint(Graphics g) { // used to set the image on the panel if (image != null) g.drawImage(image, 0, 0, this); } public void readStream() { // the basic method to continuously read the // stream try { if (useMJPGStream) { while (true) { readMJPGStream(); parent.repaint(); } } else { while (true) { connect(); readJPG(); parent.repaint(); disconnect(); } } } catch (Exception e) { ; } } public void readMJPGStream() { // preprocess the mjpg stream to remove the // mjpg encapsulation readLine(3, dis); // discard the first 3 lines readJPG(); readLine(2, dis); // discard the last two lines } public void readJPG() { // read the embedded jpeg image try { JPEGImageDecoder decoder = JPEGCodec.createJPEGDecoder(dis); image = decoder.decodeAsBufferedImage(); } catch (Exception e) { e.printStackTrace(); disconnect(); } } public void readLine(int n, DataInputStream dis) { // used to strip out the // header lines for (int i = 0; i < n; i++) { readLine(dis); } } public void readLine(DataInputStream dis) { try { boolean end = false; String lineEnd = "\n"; // assumes that the end of the line is marked // with this byte[] lineEndBytes = lineEnd.getBytes(); byte[] byteBuf = new byte[lineEndBytes.length]; while (!end) { dis.read(byteBuf, 0, lineEndBytes.length); String t = new String(byteBuf); System.out.print(t); // uncomment if you want to see what the // lines actually look like if (t.equals(lineEnd)) end = true; } } catch (Exception e) { e.printStackTrace(); } } public void run() { System.out.println("in Run..................."); connect(); readStream(); } @SuppressWarnings("deprecation") public static void main(String[] args) { JFrame jframe = new JFrame(); jframe.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); AxisCamera1 axPanel = new AxisCamera1(jframe); new Thread(axPanel).start(); jframe.getContentPane().add(axPanel); jframe.pack(); jframe.show(); } } Any suggestions what I am doing wrong here??

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  • Problem configuring virtual host.

    - by Zeeshan Rang
    I am tring to configure apache virtual host for my computer. But i am facing problem in doing so. i have made required changes in my C:\WINDOWS\system32\drivers\etc\hosts then C:\xampp\apache\conf\extra\httpd-vhosts.conf I added the following lines in httpd-vhosts.conf ########################Virtual Hosts Config below################## NameVirtualHost 127.0.0.1 <VirtualHost localhost> ServerName localhost DocumentRoot "C:\xampp\htdocs" DirectoryIndex index.php index.html <Directory "C:\xampp\htdocs"> AllowOverride All </Directory> </VirtualHost> <VirtualHost virtual.cloudse7en.com> ServerName virtual.cloudse7en.com DocumentRoot "C:\development\virtual.cloudse7en.com\httpdocs" DirectoryIndex index.php index.html <Directory "C:\development\virtual.cloudse7en.com\httpdocs"> Options Indexes FollowSymLinks Includes ExecCGI AllowOverride All Order allow,deny Allow from all </Directory> </VirtualHost> <VirtualHost virtual.app.cloudse7en.com> ServerName virtual.app.cloudse7en.com DocumentRoot "C:\development\virtual.app.cloudse7en.com\httpdocs" DirectoryIndex index.php index.html <Directory "C:\development\virtual.app.cloudse7en.com\httpdocs"> Options Indexes FollowSymLinks Includes ExecCGI AllowOverride All Order allow,deny Allow from all </Directory> </VirtualHost> ######################################################################## I started my xampp and tried http://localhost in a browser. This works and open up http://localhost/xampp/ but when i try http:http://virtual.app.cloudse7en.com it again opens up http://virtual.app.cloudse7en.com/xampp/ I do not understand the reason. Also i have a windows vista 64 bit, operating system. Do i need to make some other changes too? Regards Zee

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  • Allied Telesis router: IP filtering for the LOCAL interface

    - by syneticon-dj
    Given an Allied Telesis router with an AlliedWare OS (2.9.1) I would like to disable access to all management services of the router except for a number of subnets (or alternatively have what is a "management VLAN" with other manufacturers' switch and router models). What I have tried so far: creating a new VLAN and an appropriate IP interface, setting the LOCAL IP into this subnet, creating an IP filter for the IP interface and specifying my exclusion subnets: it simply does not work as intended as I can access the LOCAL IP set from any of the other VLAN interfaces - the traffic is apparently not going through my defined filter set at all creating a new IP filter set and binding it to the LOCAL IP interface: this seems not to affect any kind of traffic at all, the counters for the filter set remain at zero packets setting the Remote Security Officer Level IP address range: this only restricts the ability for a user with the Security Officer privilege level to log in from any but the specified address ranges / subnets. Unfortunately, it does not prevent service availability (and thus DoS capacity) or the ability to log in as a less privileged user (e.g. a "manager") calling technical support: unfortunately no solution so far What I have not tried: creating a filter set for each and every IP interface defined on the router and excluding access to the router's management IP: I would like to reduce the overhead induced by IP filters as the router already is CPU-constrained at times. Setting up filters for every IP interface would mean that each and every traffic packet would have to pass the filters, thus consuming CPU cycles. If by any means possible, I would like to find a different solution.

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  • C ++ virtual function

    - by user2950788
    masters of C++. I am trying to implement polymorphism in C++. I want to write a base class with a virtual function and then redefine that function in the child class. then demonstrate dynamic binding in my driver program. But I just couldn't get it to work. I know how to do it in C#, so I figured that I might have made some syntactical mistakes where I had used C#'s syntax in my C++ code, but these mistakes are not obvious to me at all. So I'd greatly appreciate it if you would correct my mistakes. class polyTest { public: polyTest(); virtual void type(); virtual ~polyTest(); }; void polyTest::type() { cout << "first gen"; } class polyChild: public polyTest { public: void type(); }; void polyChild::type() { cout << "second gen"; } int main() { polyChild * ptr1; polyChild * ptr2; ptr1 = new polyTest(); ptr2 = new polyChild(); ptr1 -> type(); ptr2 -> type(); }

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  • Distributing my Application inside a Debian Virtual Machine Image-- How to meet GPL obligations?

    - by bdk
    I have a Linux application I've developed, and I have created a standalone VMWare Image that people can download to try out the application without needing to install and configure a Linux Server. I created this VMWare Image by starting with a base Debian system, installing a bunch of packages and then configuring all the packages and daemons my application depends on. Upon load, the VMWare Image boots right into an X Server running only my application and no Window manager, so its more of a "Virtual Appliance" than a normal Linux Desktop environment. Users generally will never see a command prompt or any application other than my own. (My application itself I have a handle on the licensing issues of) Now I would like to distribute this image, but I'm not sure how to meet my GPL (and other licenses the various Debian components are released under) Obligations. As I understand it, I have two primary obligations to meet. Providing Copyright and License Information for each component I use. As I understand it, all the information I am required to present is located in the /usr/share directory in the Debian, but since my users generally will never touch a console or terminal, they will never see this. Does providing a text file containing a concatenation of all the files inside /usr/share meet this obligation Making source code available for all components I distribute. Since I am not creating the image from source, but from binary packages, I can't provide the actual source code that results in exactly my image being generated. Does providing an ftp mirror and an offer to send that mirror on DVDs of the Debian source debs for all the packages I use meet this obligation? Anything Else I'm required to do to legally distribute this image?

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  • How small (spec wise) can a virtual machine be and still boot up and run some sort of OS?

    - by IllvilJa
    One of the advantages with virtual machines is that you can be very flexible with their sizes. If the host system permits it, you can have a very large virtual machine with a lot of virtual RAM and disk. Also, you can decide to go the other way around, to give the virtual machine a very modest amount of RAM and disk and then choose and configure the OS appropriately. The question is, how small virtual machines have people managed to setup (and get to both boot up and to run)? Virtual machines doing something usuful is preferable, even if I know "useful" in this context is awfully subjective, but laboratory-cases with a configuration stripped beyond common sense could be intresting as well, just to see what people manage to boot and run. Quite open ended question and quite academic, but think of it: an extremely small VM (which still does something useful) takes very little memory and disk and can be quite quickly saved to and restored from disk. If it's also gentle on CPU resources, one might consider having a huge number of such VMs up and running on a host. (Imagine a VM running just an old Commodore 64 or Commodore Amiga in it. Ok, way wrong CPU architecture for modern Virtualization software running on a x86-based PC but still an interesting thought. You could have quite a few such small VMs running on a modern PC.)

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  • How to parse IP addresses with perl?

    - by Andrey Zentavr
    Hello! I have list of IPs: 238.51.208.96/28 238.51.209.180-199 238.51.209.100-109 238.51.213.2-254 ... How can I easily parse them? I need first and last IP from range. For First line I can use Net::Netmask CPAN module, but what can I do with others lines?

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  • UK IP address lookup API

    - by Phil Jackson
    Hi, im looking for a UK IP address lookup api ( or PHP script ) to find the location of a user. I want to produce more relevent results for a user when searching a directory. All the ones I have found just say 'UK' and dont get any more information than that. Can anyone point me in the right direction? Regards, Phil

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  • How to calculate an IPv6 IP Number?

    - by Bram
    I'm adding GeoIP tracking to WCF Web Service using MaxMinds' GeoIP Lite Country. All works well for their IPv4 database but they don't give any samples to calculate an IPv6 IP Number. I've contacted them and they said to use a search engine. Anyone have a sample they're willing to share? Any language will do.

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  • Redirect a specific IP address to a special page of my homepage with .htaccess

    - by Jim Knopf
    How can I use .htaccess to forward a visitor of a specific IP address to a webpage on my server? This example causes an infinite loop: RewriteCond %{REMOTE_ADDR} ^123\.\123\.123\.123$ RewriteRule ^(.*)$ /specialpage.php [R,L] I found this on the web but it just does not work: SetEnvIf REMOTE_ADDR 123.123.123.123 REDIR="redir" RewriteCond %{REDIR} redir RewriteRule ^(.*)$ /specialpage.php Note: My website consists of .htm, html and .php pages. Your help would be very much appreciated.

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