Search Results

Search found 33438 results on 1338 pages for 'html tags'.

Page 365/1338 | < Previous Page | 361 362 363 364 365 366 367 368 369 370 371 372  | Next Page >

  • Selecting an option with javascript

    - by Fibericon
    I have a drop down menu that I want to have selected on page load. This is what I'm using at the moment: var selector = document.getElementById("action_person").firstChild; var n = 0; while(selector.options[n] != null) { if(selector.options[n].value == "person") { selector.options.selectedIndex = n; } n++; } I've also tried replacing selector.options.selectedIndex = n with selector.options[n].selected = true. However, it never selects for me. It always shows the item at the top of the drop down. I've verified that the value "person" does exist in the drop down, and that the variable "selector" does point to a valid drop down. What am I doing wrong here?

    Read the article

  • How to select first empty value option in a select menu??

    - by alex
    Hi there, The following always preselects the last option, but i like the first option to be preselected? <select name="filter"> <option value="" selected>Make a choice</option> <option value="1">1</option> <option value="3">3</option> <option value="7">7</option> <option value="">all</option> </select> even with the first selected?? Can this be done??

    Read the article

  • Disabled javascript for printing?

    - by Probocop
    This may seem a strange question, but is it possible to disable javascript for the printed version of a webpage? The reason being, it causes the printout's layout to all be on top of each other. But if I turn off javascript it works fine. Any ideas?

    Read the article

  • Why should I use display:table instead of table

    - by nimo9367
    What's the benefits of structuring my site with divs and apply the display:table property ( display:tr, display:tr). Doesn't this mean that the divs will behave exactly like tr and td elements? I know I probably shouldn’t use tables or table behavior for layout at all but I'm just curious if there's a difference and a benefit?

    Read the article

  • problem with logout script in php

    - by user225269
    I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

    Read the article

  • "Share on LinkedIn" widget chokes on encoded spaces in url param

    - by David Droddy
    Does anyone know why I am not able to include my own, URL encoded URL params with URL encoded spaces? See the URL on my jsBin page constructed from LinkedIn's example--I have added (%3FnestedParam%3Done%20space) at the end of the "URL" value. THEN, if you remove the encoded space (%3FnestedParam%3DoneSpace) it works fine: Try it out: http://jsbin.com/acosa3/3 Thanks!

    Read the article

  • sql query selecting one name no matter how many rows it was mentioned in

    - by Baruch
    Basically what I'm trying to do is get the information from column x no matter how many times it was mentioned. means that if I have this kind of table: x | y | z ------+-------+-------- hello | one | bye hello | two | goodbye hi | three | see you so what I'm trying to do is create a query that would get all of the names that are mentions in the x column without duplicates and put it into a select list. my goal is that I would have a select list with TWO not THREE options, hello and hi this is what I have so far which isn't working. hope you guys know the answer to that: function getList(){ $options="<select id='names' style='margin-right:40px;'>"; $c_id = $_SESSION['id']; $sql="SELECT * FROM names"; $result=mysql_query($sql); $options.="<option value='blank'>-- Select something --</option>" ; while ($row=mysql_fetch_array($result)) { $name=$row["x"]; $options.="<option value='$name'>$name</option>"; } $options.= "</SELECT>"; return "$options"; } Sorry for confusing... i edited my source

    Read the article

  • How to change the text of a div tag

    - by michael
    Hi, I have a simple div tag. Can you please tell me how can I change the text to 'mouse in' in my onmouseover handler? and 'mouse out' in my onmouseout handler? <div id="div1" onmouseover="alert(1);" width="100px" height="200px" border="1"> test </div> and why the width/height and border attributes do not work? I want to set the border to be 1 pixel with width = 100 pixels and height = 200 pixels. Thank you.

    Read the article

  • How to override "inherited" z-indexes?

    - by Earlz
    I am needing to override the notion of inherited z-indexes. For instance in this code <style> div{ background-color:white; top: 0px; bottom: 0px; left: 0px; right: 0px; } </style> <div style="position: fixed; z-index: 2;"> div 1 <div style="position: fixed; z-index: 3;"> div 2 </div> </div> <div style="position: fixed; z-index: 2;"> div 3 </div> http://jsbin.com/epoqo3/3 I want for div 2 to be displayed, but instead div 3 is displayed. How can I change this behavior without changing my structure.

    Read the article

  • i get error when i try to upload a file?

    - by getaway
    I keep getting an error:Notice: Undefined index: on line 35 line 35: $handle = new Upload($_FILES['my_field']); this is my input field <input type="file" size="32" name="my_field" value="" /> I do not understand this error, thanks!!! EDIT: <form name="upload" id="upload" enctype="multipart/form-data" method="post" action="actions/upload.php" /> <p><input type="file" size="32" name="my_field" value="" /></p> <p class="button"><input type="hidden" name="action" value="image" /> <br> <input style="margin-left:224px;" type="submit" name="submit" value="upload" />

    Read the article

  • How to hide/show div using jQuery without altering dimensions?

    - by Byron S
    I have a div that is holding a google chart: <div id="chart_div" style="width: 600px; height: 300px;"></div> It has one CSS property: display: none. On the click of a button, I would like to have the chart be displayed using jQuery hide() and show(). It's working, however, the chart's dimensions are set to something different than I have specified and refuse to change to what I have specified. Here is my jquery code: $(document).ready(function(){ var chart = $('#chart_div'); $('#submit').click(function(){ chart.show('slow'); }); }); Let me know if theres any more code you would like to see. By the way, the chart div is not being contained in anything else so that isn't the problem.

    Read the article

  • "Close" button on the page.

    - by TRAVA
    Is there any possibility to make a link or a button to close the current page? Like I have this: <div id="arrows"> <a href="It works"><div id="arrow_left"></div></a> <a href="It works too"><div id="arrow_right"></div></a> <a href="??? =("><div id="arrow_close"></div></a> </div> And this if it's necessary this: #arrow_close{ height: 7px;display: inline;float: left;width: 7px; background: url(../i/close-20.png) no-repeat; } And I want to close the page with a button "close".

    Read the article

  • Lining up content in divs without table cells

    - by Mike
    Hi, I have two rows of links like: Link 1 Link 2 Link 3 Link 4 Link 5 Link 6 Link 7 LInk 8 I need the top four links to align with the top bottom links regardless of how many characters are in the link. For example, This is link 1 This is link 2 Link 3 L4 LInk 1 Link 2 that is longer Link 3 L4 I can do this with tables and td cells but how can this be accomplished just using divs? Thanks.

    Read the article

  • How do I implement jQuery image cycle loops on rollover for multiple thumbnail sets on a page?

    - by Kendrick Ledet
    Here is the Javascript I currently have <script type="text/javascript"> $(function() { $('.slideshow').hover( function() { $('.slides').cycle('resume'); }, function() { $('.slides').cycle('pause'); } ); $('.slides').cycle({ fx: 'fade', speed: .3, timeout: 280, next: '#next', prev: '#prev' }).cycle("pause"); }); </script> It works; but the thing is it works for all thumbnail sets on the page, and whenever I mouseover on one set of images, every other set of images loops as well. I do see that this is because I'm targeting classes, but my jQuery experience is quite limited so I have no idea how to only target a single instance of each class without effecting the others, and I can't go in and hardcode id's because my thumbnails and amount of videos on each page are determined dynamically via this Django template. http://pastebin.com/nf42bSAx I would greatly appreciate any help, as this is essential for my project (open source media platform). Thank you.

    Read the article

  • how to leave a gap in select list from left

    - by Mayur
    Hi All, I m trying to leave a gap from left in select list, but its getting problem in firefox and safari please give me source code or any reference link from where i can work... code which i use : <select style="padding:10px"> <option>Male</option> <option>female</option> <option>other</option> </select> Thanks

    Read the article

  • jquery flash object show hide

    - by coure06
    i am trying to show/hide a flash object based on click of button, but the code is not working //to hide $('object').css({visibility: 'hidden'}); //to show $('object').css({visibility: 'visible'}); i dont want to use .show() and .hide() as they will also remove the area of flash content.

    Read the article

  • post values to external page explicitly PHP

    - by JPro
    Hi, I want to post values to a page through a hyperlink in another page. Is it possible to do that? Let's say I have a page results.php which has the starting line, <?php if(isset($_POST['posted_value'])) { echo "expected value"; // do something with the data } else { echo "no the value expected"; } If from another page say link.php I place a hyperlink like this: <a href="results.php?posted_value=1"> , will this be accepetd by the results page? If instead if I replace the above starting line with if(isset($_REQUEST['posted_value'])), will this work? I believe the above hyperlink evaluates to GET, but since the only visibility difference between GET and POST that is you can see parameters in the address bar with GET But, is there any other way to place a hyperlink which can post values to a page? or can we use jquery in the place of hyperlink to POST the values? Can anyone please suggest me something on this please? Thanks.

    Read the article

  • Playing with selects and javascript

    - by Tom
    My code is: <select name='main'> <option>Animals</option> <option>Food</option> <option>Cars</option> </select> <select name='other'> <option>Rats</option> <option>Cats</option> <option>Oranges</option> <option>Audi</option> </select> How do I filter my second select, so it would only show items which I want eg. if I Choose Animals, my select would be: <select name='other'> <option>Rats</option> <option>Cats</option> </select> and if I choose Food, my select would be: <select name='other'> <option>Oranges</option> </select> Well, I hope you get the idea. Thanks.

    Read the article

< Previous Page | 361 362 363 364 365 366 367 368 369 370 371 372  | Next Page >