Search Results

Search found 16680 results on 668 pages for 'python datetime'.

Page 365/668 | < Previous Page | 361 362 363 364 365 366 367 368 369 370 371 372  | Next Page >

• django admin - adding fields on the fly

  - by Thomas

  Basically I am writing a simple shopping cart. Each item can have multiple prices. (i.e. shirts where each size is priced differently). I would like to have a single price field in my admin panel, where when the first price is entered, an additional price field pops up. However I am kind of at a loss as to how to do this. What would be the best way to do this?

  Read the article

• [PyGTK] How to Create a Multiline Button

  - by EShull

  I'm trying to create a multiline button with PyGTK. I have a label added to my subclass of gtk.Button, but I'm having trouble sizing the label to the button. If the label makes it's own size, there is no text wrapping even with label.set_line_wrap(True) because the label simply resizes beyond the bounds of the button. I would set the size of the label to that of the button, but unless I explicitly set the size of the button using set_size_request, I haven't been able to find out how big the button is (it's packed in a table). Any suggestions?

  Read the article

• ¿How to change language from Django URL?

  - by eos87

  Hi, i want to change the language when the user introduce in the url the locale, something like this http://mysite.com/es/, http://mysite.com/es/article-name, http://mysite.com/en/. how can i do that? Thanks

  Read the article

• Pylons error "No object (name: request) has been registered for this thread" with debug = false

  - by Evgeny

  I'm unable to access the request object in my Pylons 0.9.7 controller when I set debug = false in the .ini file. I have the following code: def run_something(self): print('!!! request = %r' % request) print('!!! request.params = %r' % request.params) yield 'Stuff' With debugging enabled this works fine and prints out: !!! request = <Request at 0x9571190 POST http://my_url> !!! request.params = UnicodeMultiDict([... lots of stuff ...]) If I set debug = false I get the following: !!! request = <paste.registry.StackedObjectProxy object at 0x4093790> Error - <type 'exceptions.TypeError'>: No object (name: request) has been registered for this thread The stack trace confirms that the error is on the print('!!! request.params = %r' % request.params) line. I'm running it using the Paste server and these two lines are the very first lines in my controller method. This only occurs if I have yield statements in the method (even though the statements aren't reached). I'm guessing Pylons sees that it's a generator method and runs it on some other thread. My questions are: How do I make it work with debug = false ? Why does it work with debug = true ? Obviously this is quite a dangerous bug, since I normally develop with debug = true, so it can go unnoticed during development.

  Read the article

• In Django, can you add a method to querysets?

  - by Paul D. Waite

  In Django, if I have a model class, e.g. from django.db import models class Transaction(models.Model): ... then if I want to add methods to the model, to store reasonably complex filters, I can add a custom model manager, e.g. class TransactionManager(models.Manager): def reasonable_complex_filter(self): return self.get_query_set().filter(...) class Transaction(models.Model): objects = TransactionManager() And then I can do: >>> Transaction.objects.reasonably_complex_filter() Is there any way I can add a custom method that can be chained to the end of a query set from the model? I.e. add the custom method in such a way that I can do this: >>> Transaction.objects.filter(...).reasonably_complex_filter()

  Read the article

• Modifying Bresenham's line algorithm

  - by sphennings

  I'm trying to use Bresenham's line algorithm to compute Field of View on a grid. The code I'm using calculates the lines without a problem but I'm having problems getting it to always return the line running from start point to endpoint. What do I need to do so that all lines returned run from (x0,y0) to (x1,y1) def bresenham_line(self, x0, y0, x1, y1): steep = abs(y1 - y0) > abs(x1 - x0) if steep: x0, y0 = y0, x0 x1, y1 = y1, x1 if x0 > x1: x0, x1 = x1, x0 y0, y1 = y1, y0 if y0 < y1: ystep = 1 else: ystep = -1 deltax = x1 - x0 deltay = abs(y1 - y0) error = -deltax / 2 y = y0 line = [] for x in range(x0, x1 + 1): if steep: line.append((y,x)) else: line.append((x,y)) error = error + deltay if error > 0: y = y + ystep error = error - deltax return line

  Read the article

• Py2exe, PyQt4 and Postgre Driver (QPSQL)

  - by Marshall

  Hi, I`m trying to freeze my application using Py2exe. My app uses PyQt4 and it apparently works fine with py2exe. But once I`ve uninstalled PyQt, it shows the following error: QSqlDatabase: QPSQL driver not loaded QSqlDatabase: available driver: QPSQL7 QPSQL Which doesn't make sense at all. If PyQt4 is still installed, it works just fine. This is my py2exe parameters: data_files = [ ('sqldrivers', [ 'C:\Python26\Lib\site-packages\PyQt4\plugins\sqldrivers\qsqlpsql4.dll' ]) ] setup(console=["delivery.py"], options={"py2exe" : {"includes" : ["sip", "PyQt4.QtSql", "PyQt4.QtWebKit", "PyQt4.QtNetwork"]}}, data_files=data_files)

  Read the article

• Django template-printing variables

  - by Hulk

  In django views def add(request): dict{} co_data = optarr dict.update({'co_data' : co_data}) logging.debug(co_data) return render_to_response('scheme/create.html',context_instance=RequestContext(request,{'dict': dict})) And data has the following string 1##2##3##4## And in the template when i say {{co_data}} it doesnt display the values.Please point out whats wrong in the code. Thanks..

  Read the article

• Copying contents of a module

  - by Hulk

  If there exists an old data of a model say , query=Emp.objects.filter(pk=profile.id) Is there a easier way to copy the same values into the same model again.. Now that the id will be different so.. I have this requirement. Thanks..

  Read the article

• Migration for creating and deleting model in South

  - by Almad

  I've created a model and created initial migration for it: db.create_table('tvguide_tvguide', ( ('id', models.AutoField(primary_key=True)), ('date', models.DateField(_('Date'), auto_now=True, db_index=True)), )) db.send_create_signal('tvguide', ['TVGuide']) models = { 'tvguide.tvguide': { 'channels': ('models.ManyToManyField', ["orm['tvguide.Channel']"], {'through': "'ChannelInTVGuide'"}), 'date': ('models.DateField', ["_('Date')"], {'auto_now': 'True', 'db_index': 'True'}), 'id': ('models.AutoField', [], {'primary_key': 'True'}) } } complete_apps = ['tvguide'] Now, I'd like to drop it: db.drop_table('tvguide_tvguide') However, I have also deleted corresponding model. South (at least 0.6.2) is however trying to access it: (venv)[almad@eva-03 project]$ ./manage.py migrate tvguide Running migrations for tvguide: - Migrating forwards to 0002_removemodels. > tvguide: 0001_initial Traceback (most recent call last): File "./manage.py", line 27, in <module> execute_from_command_line() File "/usr/lib/python2.6/site-packages/django/core/management/__init__.py", line 353, in execute_from_command_line utility.execute() File "/usr/lib/python2.6/site-packages/django/core/management/__init__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/usr/lib/python2.6/site-packages/django/core/management/base.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "/usr/lib/python2.6/site-packages/django/core/management/base.py", line 222, in execute output = self.handle(*args, **options) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/management/commands/migrate.py", line 91, in handle skip = skip, File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/migration.py", line 581, in migrate_app result = run_forwards(mapp, [mname], fake=fake, db_dry_run=db_dry_run, verbosity=verbosity) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/migration.py", line 388, in run_forwards verbosity = verbosity, File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/migration.py", line 287, in run_migrations orm = klass.orm File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 62, in __get__ self.orm = FakeORM(*self._args) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 45, in FakeORM _orm_cache[args] = _FakeORM(*args) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 106, in __init__ self.models[name] = self.make_model(app_name, model_name, data) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/orm.py", line 307, in make_model tuple(map(ask_for_it_by_name, bases)), File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/utils.py", line 23, in ask_for_it_by_name ask_for_it_by_name.cache[name] = _ask_for_it_by_name(name) File "/home/almad/projects/mypage-all/lib/python2.6/site-packages/south/utils.py", line 17, in _ask_for_it_by_name return getattr(module, bits[-1]) AttributeError: 'module' object has no attribute 'TVGuide' Is there a way around?

  Read the article

• Django and Reportlab Question

  - by Hellnar

  Hello, I have written this small Django view to return pdf. @login_required def code_view(request,myid): try: deal = Deal.objects.get(id=myid) except: raise Http404 header = deal.header code = deal.code response = HttpResponse(mimetype='application/pdf') response['Content-Disposition'] = 'attachment; filename=code.pdf' p = canvas.Canvas(response) p.drawString(10, 800, header) p.drawString(10, 700, code) p.showPage() p.save() return response And my questions: Utf-8 characters are not shown correctly within the pdf. How can I include an image ? How can I include a very basic html such as: . <ul> <li>List One</li> <li>List Two</li> <li>List Three</li> </ul>

  Read the article

• Apps not showing in Django admin site

  - by jack

  I have a Django project with about 10 apps in it. But the admin interface only shows Auth and Site models which are part of Django distribution. Yes, the admin interface is up and working but none of my self-written apps shows there. INSTALLED_APPS INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.sites', 'django.contrib.contenttypes', 'django.contrib.humanize', 'django.contrib.sessions', 'django.contrib.admin', 'django.contrib.admindocs', 'project.app1', ... app1/admin.py from django.contrib import admin from project.app1.models import * admin.site.register(model1) admin.site.register(model2) admin.site.register(model3) What could be wrong in this case? Looks like everything is configured as what document says. Thank you in advance.

  Read the article

• Django Admin Page missing CSS

  - by super9

  I saw this question and recommendation from Django Projects here but still can't get this to work. My Django Admin pages are not displaying the CSS at all. This is my current configuration. settings.py ADMIN_MEDIA_PREFIX = '/media/admin/' httpd.conf <VirtualHost *:80> DocumentRoot /home/django/sgel ServerName ec2-***-**-***-***.ap-**********-1.compute.amazonaws.com ErrorLog /home/django/sgel/logs/apache_error.log CustomLog /home/django/sgel/logs/apache_access.log combined WSGIScriptAlias / /home/django/sgel/apache/django.wsgi <Directory /home/django/sgel/media> Order deny,allow Allow from all </Directory> <Directory /home/django/sgel/apache> Order deny,allow Allow from all </Directory> LogLevel warn Alias /media/ /home/django/sgel/media/ </VirtualHost> <VirtualHost *:80> ServerName sgel.com Redirect permanent / http://www.sgel.com/ </VirtualHost> In addition, I also ran the following to create (I think) the symbolic link ln -s /home/djangotest/sgel/media/admin/ /usr/lib/python2.6/site-packages/django/contrib/admin/media/ UPDATE In my httpd.conf file, User django Group django When I run ls -l in my /media directory drwxr-xr-x 2 root root 4096 Apr 4 11:03 admin -rw-r--r-- 1 root root 9 Apr 8 09:02 test.txt Should that root user be django instead? UPDATE 2 When I enter ls -la in my /media/admin folder total 12 drwxr-xr-x 2 root root 4096 Apr 13 03:33 . drwxr-xr-x 3 root root 4096 Apr 8 09:02 .. lrwxrwxrwx 1 root root 60 Apr 13 03:33 media -> /usr/lib/python2.6/site-packages/django/contrib/admin/media/ The thing is, when I navigate to /usr/lib/python2.6/site-packages/django/contrib/admin/media/, the folder was empty. So I copied the CSS, IMG and JS folders from my Django installation into /usr/lib/python2.6/site-packages/django/contrib/admin/media/ and it still didn't work

  Read the article

• (interactive) graph as in graph theory on a web page ?

  - by LB

  Hi, I have to integrate a graph with nodes and edges on a web page. Ideally, i would like to be able to interact with it (like moving the nodes around). Actually, i'm beginning by representing trees, so i would appreciate to be able to collapse subtrees. How can I do that ? I was considering google-visualization api but i wasn't able to find the kind of visualization i'm looking for (org chart doesn't allow to have multiple fathers, if i understood well) I've got no idea of the kind of technology so my tagging may not be really accurate :-). thanks

  Read the article

• Django: reverse lookup URL of feeds?

  - by Santa

  I am having trouble doing a reverse URL lookup for Django-generated feeds. I have the following setup in urls.py: feeds = { 'latest': LatestEntries, } urlpatterns = patterns('', # ... # enable feeds (RSS) url(r'^feeds/(?P<url>.*)/$', 'django.contrib.syndication.views.feed', {'feed_dict': feeds}, name='feeds_view'), ) I have tried using the following template tag: <a href="{% url feeds_view latest %}">RSS feeds</a> But the resulting link is not what want (http://my.domain.com/feeds//). It should be http://my.domain.com/feeds/latest/. For now, I am using a hack to generate the URL for the template: <a href="http://{{ request.META.HTTP_HOST }}/feeds/latest">RSS feeds</a> But, as you can see, it clearly is not DRY. Is there something I am missing?

  Read the article

• Edit nested dictionary with limited information

  - by user1082764

  How can i change the 'space' of 'albert' if i dont know if he is a donkey or a zebra? self.object_attr = {'donkey': { 'name': 'roger', 'zone': 'forrest', 'space': [0, 0]}{ 'name': 'albert', 'zone': 'forrest', 'space': [1, 1]} 'zebra': { 'name': 'roger', 'zone': 'forrest', 'space': [0, 0]}{ 'name': 'albert', 'zone': 'forrest', 'space': [1, 1]}} This can search for albert in the dictionary but how can i change his location? for i in self.object_attr for j in self.object_attr[x][name] if j == 'albert'

  Read the article

• Where is the Google App Engine SDK path on OSX?

  - by Curyous

  I need to know for creating a Pydev Google App Engine Project in Eclipse.

  Read the article

• Extending Django Flatpages to accept template tags

  - by Tristan

  I use django flatpages for a lot of content on our site, I'd like to extend it to accept django template tags in the content as well. I found this snippet but after much larking about I couldn't get it to work. Am I correct in assuming that you would need too "subclass" the django flatpages app to get this to work? Is this best way of doing it? I'm not quite sure how to structure it, as I don't really want to directly modify the django distribution.

  Read the article

• Using scipy.interpolate.splrep function

  - by Koustav Ghosal

  I am trying to fit a cubic spline to a given set of points. My points are not ordered. I CANNOT sort or reorder the points, since I need that information. But since the function scipy.interpolate.splrep works only on non-duplicate and monotonically increasing points I have defined a function that maps the x-coordinates to a monotonically increasing space. My old points are: xpoints=[4913.0, 4912.0, 4914.0, 4913.0, 4913.0, 4913.0, 4914.0, 4915.0, 4918.0, 4921.0, 4925.0, 4932.0, 4938.0, 4945.0, 4950.0, 4954.0, 4955.0, 4957.0, 4956.0, 4953.0, 4949.0, 4943.0, 4933.0, 4921.0, 4911.0, 4898.0, 4886.0, 4874.0, 4865.0, 4858.0, 4853.0, 4849.0, 4848.0, 4849.0, 4851.0, 4858.0, 4864.0, 4869.0, 4877.0, 4884.0, 4893.0, 4903.0, 4913.0, 4923.0, 4935.0, 4947.0, 4959.0, 4970.0, 4981.0, 4991.0, 5000.0, 5005.0, 5010.0, 5015.0, 5019.0, 5020.0, 5021.0, 5023.0, 5025.0, 5027.0, 5027.0, 5028.0, 5028.0, 5030.0, 5031.0, 5033.0, 5035.0, 5037.0, 5040.0, 5043.0] ypoints=[10557.0, 10563.0, 10567.0, 10571.0, 10575.0, 10577.0, 10578.0, 10581.0, 10582.0, 10582.0, 10582.0, 10581.0, 10578.0, 10576.0, 10572.0, 10567.0, 10560.0, 10550.0, 10541.0, 10531.0, 10520.0, 10511.0, 10503.0, 10496.0, 10490.0, 10487.0, 10488.0, 10488.0, 10490.0, 10495.0, 10504.0, 10513.0, 10523.0, 10533.0, 10542.0, 10550.0, 10556.0, 10559.0, 10560.0, 10559.0, 10555.0, 10550.0, 10543.0, 10533.0, 10522.0, 10514.0, 10505.0, 10496.0, 10490.0, 10486.0, 10482.0, 10481.0, 10482.0, 10486.0, 10491.0, 10497.0, 10506.0, 10516.0, 10524.0, 10534.0, 10544.0, 10552.0, 10558.0, 10564.0, 10569.0, 10573.0, 10576.0, 10578.0, 10581.0, 10582.0] Plots: The code for the mapping function and interpolation is: xnew=[] ynew=ypoints for c3,i in enumerate(xpoints): if np.isfinite(np.log(i*pow(2,c3))): xnew.append(np.log(i*pow(2,c3))) else: if c==0: xnew.append(np.random.random_sample()) else: xnew.append(xnew[c3-1]+np.random.random_sample()) xnew=np.asarray(xnew) ynew=np.asarray(ynew) constant1=10.0 nknots=len(xnew)/constant1 idx_knots = (np.arange(1,len(xnew)-1,(len(xnew)-2)/np.double(nknots))).astype('int') knots = [xnew[i] for i in idx_knots] knots = np.asarray(knots) int_range=np.linspace(min(xnew),max(xnew),len(xnew)) tck = interpolate.splrep(xnew,ynew,k=3,task=-1,t=knots) y1= interpolate.splev(int_range,tck,der=0) The code is throwing an error at the function interpolate.splrep() for some set of points like the above one. The error is: File "/home/neeraj/Desktop/koustav/res/BOS5/fit_spline3.py", line 58, in save_spline_f tck = interpolate.splrep(xnew,ynew,k=3,task=-1,t=knots) File "/usr/lib/python2.7/dist-packages/scipy/interpolate/fitpack.py", line 465, in splrep raise _iermessier(_iermess[ier][0]) ValueError: Error on input data But for other set of points it works fine. For example for the following set of points. xpoints=[1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1629.0, 1630.0, 1630.0, 1630.0, 1631.0, 1631.0, 1631.0, 1631.0, 1630.0, 1629.0, 1629.0, 1629.0, 1628.0, 1627.0, 1627.0, 1625.0, 1624.0, 1624.0, 1623.0, 1620.0, 1618.0, 1617.0, 1616.0, 1615.0, 1614.0, 1614.0, 1612.0, 1612.0, 1612.0, 1611.0, 1610.0, 1609.0, 1608.0, 1607.0, 1607.0, 1603.0, 1602.0, 1602.0, 1601.0, 1601.0, 1600.0, 1599.0, 1598.0] ypoints=[10570.0, 10572.0, 10572.0, 10573.0, 10572.0, 10572.0, 10571.0, 10570.0, 10569.0, 10565.0, 10564.0, 10563.0, 10562.0, 10560.0, 10558.0, 10556.0, 10554.0, 10551.0, 10548.0, 10547.0, 10544.0, 10542.0, 10541.0, 10538.0, 10534.0, 10532.0, 10531.0, 10528.0, 10525.0, 10522.0, 10519.0, 10517.0, 10516.0, 10512.0, 10509.0, 10509.0, 10507.0, 10504.0, 10502.0, 10500.0, 10501.0, 10499.0, 10498.0, 10496.0, 10491.0, 10492.0, 10488.0, 10488.0, 10488.0, 10486.0, 10486.0, 10485.0, 10485.0, 10486.0, 10483.0, 10483.0, 10482.0, 10480.0] Plots: Can anybody suggest what's happening ?? Thanks in advance......

  Read the article

• Django MultiWidget Phone Number Field

  - by Birdman

  I want to create a field for phone number input that has 2 text fields (size 3, 3, and 4 respectively) with the common "(" ")" "-" delimiters. Below is my code for the field and the widget, I'm getting the following error when trying to iterate the fields in my form during initial rendering (it happens when the for loop gets to my phone number field): Caught an exception while rendering: 'NoneType' object is unsubscriptable class PhoneNumberWidget(forms.MultiWidget): def __init__(self,attrs=None): wigs = (forms.TextInput(attrs={'size':'3','maxlength':'3'}),\ forms.TextInput(attrs={'size':'3','maxlength':'3'}),\ forms.TextInput(attrs={'size':'4','maxlength':'4'})) super(PhoneNumberWidget, self).__init__(wigs, attrs) def decompress(self, value): return value or None def format_output(self, rendered_widgets): return '('+rendered_widgets[0]+')'+rendered_widgets[1]+'-'+rendered_widgets[2] class PhoneNumberField(forms.MultiValueField): widget = PhoneNumberWidget def __init__(self, *args, **kwargs): fields=(forms.CharField(max_length=3), forms.CharField(max_length=3), forms.CharField(max_length=4)) super(PhoneNumberField, self).__init__(fields, *args, **kwargs) def compress(self, data_list): if data_list[0] in fields.EMPTY_VALUES or data_list[1] in fields.EMPTY_VALUES or data_list[2] in fields.EMPTY_VALUES: raise fields.ValidateError(u'Enter valid phone number') return data_list[0]+data_list[1]+data_list[2] class AdvertiserSumbissionForm(ModelForm): business_phone_number = PhoneNumberField(required=True)

  Read the article

• Using urllib2 with SOCKS proxy

  - by roddik

  Hello. Is it possible to fetch pages with urllib2 through a SOCKS proxy on a one socks server per opener basic? I've seen the solution using setdefaultproxy method, but I need to have different socks in different openers.

  Read the article

• installing paramiko

  - by fixxxer

  This may sound like a repeated question on SF, but I could not find a clear answer to it, yet.So. I installed Paramiko 1.7 with "setup.py install" command and while running the demo.py program, I got this error: Traceback (most recent call last): File "C:\Documents and Settings\fixavier\Desktop\paramiko-1.7\demos\demo.py", line 33, in <module> import paramiko File "C:\Python26\lib\site-packages\paramiko\__init__.py", line 69, in <module> from transport import randpool, SecurityOptions, Transport File "C:\Python26\lib\site-packages\paramiko\transport.py", line 32, in <module> from paramiko import util File "C:\Python26\lib\site-packages\paramiko\util.py", line 31, in <module> from paramiko.common import * File "C:\Python26\lib\site-packages\paramiko\common.py", line 99, in <module> from Crypto.Util.randpool import PersistentRandomPool, RandomPool ImportError: No module named Crypto.Util.randpool I'm getting this error even after installing PyCrypto 2.1. On running test.py(which comes with the installation), I got the following error - Traceback (most recent call last): File "C:\Documents and Settings\fixavier\Desktop\pycrypto-2.0.1\pycrypto-2.0.1\test.py", line 18, in <module> from Crypto.Util import test File "C:\Documents and Settings\fixavier\Desktop\pycrypto-2.0.1\pycrypto-2.0.1\build/lib.win32-2.6\Crypto\Util\test.py", line 17, in <module> import testdata File "C:\Documents and Settings\fixavier\Desktop\pycrypto-2.0.1\pycrypto-2.0.1\test\testdata.py", line 450, in <module> from Crypto.Cipher import AES ImportError: cannot import name AES I don't have the confidence to go ahead and install AES after all this, for all I know I may get another ImportError! Please advice.Is it the way of installation thats problematic?

  Read the article

• Django models query

  - by Hulk

  Code: class criteria(models.Model): details = models.CharField(max_length = 512) Headerid = models.ForeignKey(Header) def __unicode__(self): return self.id() the details corresponds to a textarea in the UI and a validation is done for 512 characters but when this is saved. /home/project/django/django/core/handlers/base.py in get_response, line 109 Is this any thing related with schema or number of characters entered from UI

  Read the article

• Django User M2M relationship

  - by Antonio

  When trying to syncdb with the following models: class Contact(models.Model): user_from = models.ForeignKey(User,related_name='from_user') user_to = models.ForeignKey(User, related_name='to_user') class Meta: unique_together = (('user_from', 'user_to'),) User.add_to_class('following', models.ManyToManyField('self', through=Contact, related_name='followers', symmetrical=False)) I get the following error: Error: One or more models did not validate: auth.user: Accessor for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'. auth.user: Reverse query name for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'. auth.user: The model User has two manually-defined m2m relations through the model Contact, which is not permitted. Please consider using an extra field on your intermediary model instead. auth.user: Accessor for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'. auth.user: Reverse query name for m2m field 'following' clashes with related m2m field 'User.followers'. Add a related_name argument to the definition for 'following'.

  Read the article

• How do I pass a lot of parameters to views in Django?

  - by Mark

  I'm very new to Django and I'm trying to build an application to present my data in tables and charts. Till now my learning process went very smooth, but now I'm a bit stuck. My pageview retrieves large amounts of data from a database and puts it in the context. The template then generates different html-tables. So far so good. Now I want to add different charts to the template. I manage to do this by defining <img src=".../> tags. The Matplotlib chart is generate in my chartview an returned via: response=HttpResponse(content_type='image/png') canvas.print_png(response) return response Now I have different questions: the data is retrieved twice from the database. Once in the pageview to render the tables, and again in the chartview for making the charts. What is the best way to pass the data, already in the context of the page to the chartview? I need a lot of charts, each with different datasets. I could make a chartview for each chart, but probably there is a better way. How do I pass the different dataset names to the chartview? Some charts have 20 datasets, so I don't think that passing these dataset parameters via the url (like: <imgm src="chart/dataset1/dataset2/.../dataset20/chart.png />) is the right way. Any advice?

  Read the article

< Previous Page | 361 362 363 364 365 366 367 368 369 370 371 372  | Next Page >