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  • Why does this XML validation via XSD fail in libxml2 (but succeed in xmllint) and how do I fix it?

    - by mtree
    If I run this XML validation via xmllint: xmllint --noout --schema schema.xsd test.xml I get this success message: .../test.xml validates However if I run the same validation via libxml2's C API: int result = xmlSchemaValidateDoc(...) I get a return value of 1845 and this failure message: Element '{http://example.com/XMLSchema/1.0}foo': No matching global declaration available for the validation root. Which I can make absolutely no sense of. :( schema.xsd: <?xml version="1.0" encoding="utf-8" ?> <!DOCTYPE xs:schema PUBLIC "-//W3C//DTD XMLSCHEMA 200102//EN" "XMLSchema.dtd" > <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://example.com/XMLSchema/1.0" targetNamespace="http://example.com/XMLSchema/1.0" elementFormDefault="qualified" attributeFormDefault="unqualified"> <xs:element name="foo"> </xs:element> </xs:schema> test.xml: <?xml version="1.0" encoding="UTF-8"?> <foo xmlns="http://example.com/XMLSchema/1.0"> </foo> main.c: #include <stdio.h> #include <sys/stat.h> #include <sys/types.h> #include <string.h> #include <libxml/parser.h> #include <libxml/valid.h> #include <libxml/xmlschemas.h> u_int32_t get_file_size(const char *file_name) { struct stat buf; if ( stat(file_name, &buf) != 0 ) return(0); return (unsigned int)buf.st_size; } void handleValidationError(void *ctx, const char *format, ...) { char *errMsg; va_list args; va_start(args, format); vasprintf(&errMsg, format, args); va_end(args); fprintf(stderr, "Validation Error: %s", errMsg); free(errMsg); } int main (int argc, const char * argv[]) { const char *xsdPath = argv[1]; const char *xmlPath = argv[2]; printf("\n"); printf("XSD File: %s\n", xsdPath); printf("XML File: %s\n", xmlPath); int xmlLength = get_file_size(xmlPath); char *xmlSource = (char *)malloc(sizeof(char) * xmlLength); FILE *p = fopen(xmlPath, "r"); char c; unsigned int i = 0; while ((c = fgetc(p)) != EOF) { xmlSource[i++] = c; } printf("\n"); printf("XML Source:\n\n%s\n", xmlSource); fclose(p); printf("\n"); int result = 42; xmlSchemaParserCtxtPtr parserCtxt = NULL; xmlSchemaPtr schema = NULL; xmlSchemaValidCtxtPtr validCtxt = NULL; xmlDocPtr xmlDocumentPointer = xmlParseMemory(xmlSource, xmlLength); parserCtxt = xmlSchemaNewParserCtxt(xsdPath); if (parserCtxt == NULL) { fprintf(stderr, "Could not create XSD schema parsing context.\n"); goto leave; } schema = xmlSchemaParse(parserCtxt); if (schema == NULL) { fprintf(stderr, "Could not parse XSD schema.\n"); goto leave; } validCtxt = xmlSchemaNewValidCtxt(schema); if (!validCtxt) { fprintf(stderr, "Could not create XSD schema validation context.\n"); goto leave; } xmlSetStructuredErrorFunc(NULL, NULL); xmlSetGenericErrorFunc(NULL, handleValidationError); xmlThrDefSetStructuredErrorFunc(NULL, NULL); xmlThrDefSetGenericErrorFunc(NULL, handleValidationError); result = xmlSchemaValidateDoc(validCtxt, xmlDocumentPointer); leave: if (parserCtxt) { xmlSchemaFreeParserCtxt(parserCtxt); } if (schema) { xmlSchemaFree(schema); } if (validCtxt) { xmlSchemaFreeValidCtxt(validCtxt); } printf("\n"); printf("Validation successful: %s (result: %d)\n", (result == 0) ? "YES" : "NO", result); return 0; } console output: XSD File: /Users/dephiniteloop/Desktop/xml_validate/schema.xsd XML File: /Users/dephiniteloop/Desktop/xml_validate/test.gkml XML Source: <?xml version="1.0" encoding="UTF-8"?> <foo xmlns="http://example.com/XMLSchema/1.0"> </foo> Validation Error: Element '{http://example.com/XMLSchema/1.0}foo': No matching global declaration available for the validation root. Validation successful: NO (result: 1845) In case it matters: I'm on OSX 10.6.7 with its default libxml2.dylib (/Developer/SDKs/MacOSX10.6.sdk/usr/lib/libxml2.2.7.3.dylib)

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  • What to pass to UserType, BlobType.setPreparedStatement session parameter

    - by dlots
    http://blog.xebia.com/2009/11/09/understanding-and-writing-hibernate-user-types/ I am attempting to defined a customer serialization UserType that mimics, the XStreamUserType referenced and provided here: http://code.google.com/p/aphillips/source/browse/commons-hibernate-usertype/trunk/src/main/java/com/qrmedia/commons/persistence/hibernate/usertype/XStreamableUserType.java My serializer outputs a bytearray that should presumably written to a Blob. I was going to do: public class CustomSerUserType extends DirtyCheckableUserType { protected SerA ser=F.g(SerA.class); public Class<Object> returnedClass() { return Object.class; } public int[] sqlTypes() { return new int[] {Types.BLOB}; } public Object nullSafeGet(ResultSet resultSet,String[] names,Object owner) throws HibernateException,SQLException { if() } public void nullSafeSet(PreparedStatement preparedStatement,Object value,int index) throws HibernateException,SQLException { BlobType.nullSafeSet(preparedStatement,ser.ser(value),index); } } Unfortunetly, the BlobType.nullSafeSet method requires the session. So how does one define a UserType that gets access to a servlet requests session? EDIT: There is a discussion of the issue here and it doesn't appear there is a solution: Best way to implement a Hibernate UserType after deprecations?

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  • WCF method that updates object passed in

    - by Georgia Brown
    Am I correct in thinking that if I have a WCF OperationContract takes in an object and needs to set a property on that object so the client gets the update, I need to declare it to return the object. e.g. given a datacontract: [DataContract] public class CompositeType { [DataMember] public int Key { get; set; } [DataMember] public string Something { get; set; } } this will not work with WCF: public void GetDataUsingDataContract(CompositeType composite) { composite.Key = 42; } this will work: public CompositeType GetDataUsingDataContract(CompositeType composite) { composite.Key = 42; return new CompositeType { Key = composite.Key, Something = composite.Something }; }

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  • Testing a Django view cause "AttributeError: 'NoneType' object has no attribute 'handler500'" error

    - by jack
    I just wanted to start testing a Django view using the code below: from django.test.client import Client c = Client() response = c.get('/search/keyword') print response.content It just throws out following error message: "/usr/local/lib/python2.6/dist-packages/django/test/client.py", line 286, in get response = self.request(**r) File "/usr/local/lib/python2.6/dist-packages/django/test/client.py", line 230, in request response = self.handler(environ) File "/usr/local/lib/python2.6/dist-packages/django/test/client.py", line 74, in __call__ response = self.get_response(request) File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/base.py", line 143, in get_response return self.handle_uncaught_exception(request, resolver, exc_info) File "/usr/local/lib/python2.6/dist-packages/django/core/handlers/base.py", line 178, in handle_uncaught_exception callback, param_dict = resolver.resolve500() File "/usr/local/lib/python2.6/dist-packages/django/core/urlresolvers.py", line 268, in resolve500 return self._resolve_special('500') File "/usr/local/lib/python2.6/dist-packages/django/core/urlresolvers.py", line 258, in _resolve_special callback = getattr(self.urlconf_module, 'handler%s' % view_type) AttributeError: 'NoneType' object has no attribute 'handler500' The view works in browser. What's wrong with above code?

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  • iphone pushviewcontroller to landscape

    - by satyam
    I've simple iphone application. it has 3 views. first view is portrait view that has 3 buttons. second view has a table view which is also a portrait. In first view, on click of a button second view is shown. on click of a cell in second view, thrid view is shown. but third view is a landscape. I'm using "pushViewController" to navigate from each view. When creating views in IB, first two views are portait and 3rd view is a landscape. In 3rd viewcontroller, i'm using following code as well: - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { //return UIInterfaceOrientationIsLandscape(interfaceOrientation); return ((interfaceOrientation == UIInterfaceOrientationLandscapeRight) || (interfaceOrientation == UIInterfaceOrientationLandscapeLeft)); } How can I show first two views in portrait and third view in landscape.

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  • How fast can you make linear search?

    - by Mark Probst
    I'm looking to optimize this linear search: static int linear (const int *arr, int n, int key) { int i = 0; while (i < n) { if (arr [i] >= key) break; ++i; } return i; } The array is sorted and the function is supposed to return the index of the first element that is greater or equal to the key. They array is not large (below 200 elements) and will be prepared once for a large number of searches. Array elements after the n-th can if necessary be initialized to something appropriate, if that speeds up the search. No, binary search is not allowed, only linear search.

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  • adding child nodes to a treeview control in wpf,c#

    - by ebhakt
    Hi , i have implemented a treeview control on a buttonclick event like this: using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Windows; using System.Windows.Controls; using System.Windows.Data; using System.Windows.Documents; using System.Windows.Input; using System.Windows.Media; using System.Windows.Media.Imaging; using System.Windows.Navigation; using System.Windows.Shapes; using System.Collections.ObjectModel; namespace TaxonomyTreeview { /// /// Interaction logic for Window1.xaml /// public partial class Window1 : Window { ObservableCollection _TaxonomyCollection = new ObservableCollection(); public Window1() { InitializeComponent(); } private void Window_Loaded(object sender, RoutedEventArgs e) { } public ObservableCollection<TaxonomyData> TaxonomyCollection { get { return _TaxonomyCollection; } } private void SelectedTaxonomyChanged(object sender, RoutedPropertyChangedEventArgs<Object> e) { TaxonomyData taxo = taxonomytree.SelectedItem as TaxonomyData; if (taxo != null) { MessageBox.Show("" + taxo.Tid); } } public class TaxonomyData { private string _name; private string _tid; public string Tid { get { return _tid; } set { _tid = value; } } public string Name { get { return _name; } set { _name = value; } } public TaxonomyData(string name, string tid) { Name = name; Tid = tid; } } private void populate_Click(object sender, RoutedEventArgs e) { taxonomytree.Items.Clear(); TaxonomyCollection.Add(new TaxonomyData("Taxonomy1", "1")); taxonomytree.Items.Add(TaxonomyCollection[0]); } } } The xaml code is : <TextBox Height="23" Margin="20,9,0,0" Name="startvid" VerticalAlignment="Top" HorizontalAlignment="Left" Width="120" /> <TextBox Height="23" Margin="165,9,151,0" Name="endvid" VerticalAlignment="Top" /> <Button Height="23.78" HorizontalAlignment="Right" Margin="0,8.22,11,0" Name="populate" VerticalAlignment="Top" Width="115" Click="populate_Click">Populate</Button> <TreeView HorizontalAlignment="Left" Margin="20,53,0,144" Width="120" Name="taxonomytree" ItemsSource="{Binding Window1.TaxonomyCollection}" SelectedItemChanged="SelectedTaxonomyChanged"> <TreeView.ItemTemplate> <DataTemplate> <TextBlock Text="{Binding Path=Name}" /> </DataTemplate> </TreeView.ItemTemplate> </TreeView> </Grid> As i want to display, the structure in a hierarchy , i want to know what is the best method to add a child node to this Please help

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  • Searching documents by tag using the Scribd API is no longer returning expected results.

    - by George
    Recently I have encountered an issue with Scribd where searching via Scribd API (docs.search) for documents by tag is no longer working. This has been working (for over 6 months) to return a number of documents that I have tagged with "fdsafetyandprevention" (accessible here http://www.scribd.com/tag/fdsafetyandprevention). Just recently my search via the API has stopped working. Note that test searches such as @tags "selfhelp" as described in the Scribd documentation DO work. Could my issue be related to caching or the age of my documents and Scribd choosing to not return them in search results? I have been using scribd.php (http://www.scribd.com/developers/libraries) to interface with the API using $scribd-search(@tags "fdsafetyandprevention", 20, 0, "all"). I am following the Scribd documentation for docs.search and advanced help (http://www.scribd.com/developers/search_help). Help greatly appreciated. George.

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  • Compiler warning when passing NSError ** as a method parameter

    - by splicer
    I've been scratching my head about this for the last 4 hours, trying out all kinds of little experiments, but I can't seem to figure out what's going wrong. Could this be a compiler bug? Test.m: - (id)initWithContentsOfURL:(NSURL *)aURL error:(NSError **)error { if (!(self = [super init])) { return nil; } return self; } main.m: NSError *error; Test *t = [[Test alloc] initWithContentsOfURL:[NSURL fileURLWithPath:@"/"] error:&error]; Here's the compiler warning (from main.m): warning: incompatible Objective-C types 'struct NSError **', expected 'struct NSDictionary **' when passing argument 2 of 'initWithContentsOfURL:error:' from distinct Objective-C type I'm using the latest versions of Xcode and Snow Leopard.

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  • How to move a google doc into a folder using Zend Gdata

    - by Andre
    Hi Guys I am really struggling with moving a document from my root folder to another folder using zend gdata here is how i am trying to do it, but its not working. $service = Zend_Gdata_Docs::AUTH_SERVICE_NAME; $client = Zend_Gdata_ClientLogin::getHttpClient($gUser, $gPass, $service); $link = "https://docs.google.com/feeds/documents/private/full/spreadsheet:0AUFNVEpLOVg2U0E"; // Not real id for privacy purposes $docs = new Zend_GData_Docs($client); // Attach a category object of folder to this entry // I have tried many variations of this including attaching label categories $cat = new Zend_Gdata_App_Extension_Category('My Folder Name','http://schemas.google.com/docs/2007#folder'); $entry = $docs->getDocumentListEntry($link); $entry->setCategory(array($cat)); $return = $docs->updateEntry($entry,$entry->getEditLink()->href); When I run this I get No errors, but nothing seems to change, and the return data does not contain the new category. EDIT: Ok I realised that its not the category but the link that decides which "collection" (folder) a resource belongs too. https://developers.google.com/google-apps/documents-list/#managing_collections_and_their_contents says that each resource has as et of parent links, so I tried changing my code to do set link instead of set category, but this did not work. $folder = "https://docs.google.com/feeds/documents/private/full/folder%3A0wSFA2WHc"; $rel = "http://schemas.google.com/docs/2007#parent"; $linkObj = new Zend_Gdata_App_Extension_Link($folder,$rel,'application/atom+xml', NULL,'Folder Name'); $links = $entry->getLink(); array_push($links,$linkObj); $entry->setLink($links); $return = $docs->updateEntry($entry,$entry->getEditLink()->href); EDIT: SOLVED [nearly] OK Here is how to move/copy, sort of, from one folder to another: simpler than initially thought, but problem is it creates a reference and NOT a move! It now in both places at the same time.... // Folder you wnat to move too $folder = "https://docs.google.com/feeds/folders/private/full/folder%asdsad"; $data = $docs->insertDocument($entry, $folder); // Entry is the entry you want moved using insert automatically assigns link & category for you...

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  • How come module-level validators are evaluated only after property-level validators?

    - by jonathanconway
    I'm using the module-level validator: 'PropertiesMustMatch' on my view-model, like so: [PropertiesMustMatch("Password", "PasswordConfirm")] public class HomeIndex { [Required] public string Name { get; set; } public string Password { get; set; } public string PasswordConfirm { get; set; } } I'm noticing that if I submit the form without Name filled in, the ValidationSummary() helper returns only the following error: The Name field is required. However, if I fill in Name, then ValidationSummary() will return a PropertiesMustMatch error: 'Password' and 'PasswordConfirm' do not match. So it looks like the property-level validators are being evaluated first, then the model-level validators. I would much prefer if they were all validated at once, and ValidationSummary would return: The Name field is required. 'Password' and 'PasswordConfirm' do not match. Any ideas what I can do to fix this? I'm studying the MVC 2 source-code to try to determine why this happens.

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  • Generic function to handle DataType Conversion

    - by Tommo1977
    I have the following function in C#, that I want to pass a MySQL DataReader value/object. If the value of the object passed is a DBNull I need to handle it and return a Null value of that data type e.g null int. Otherwise I want to convert the returned value like Convert.ToInt32(value) or similar. public static T ConvertFromDB<T>(object value) { return value == DBNull.Value ? default(T) : (T)value; } Can anyone offer any help on this ?

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  • java.lang.Void in C#?

    - by user313661
    Hi, I am currently working with .Net 2.0 and have an interface whose generic type is used to define a method's return type. Something like interface IExecutor<T> { T Execute() { ... } } My problem is that some classes that implement this interface do not really need to return anything. In Java you can use java.lang.Void for this purpose, but after quite a bit of searching I found no equivalent in C#. More generically, I also did not find a good way around this problem. I tried to find how people would do this with delegates, but found nothing either - which makes me believe that the problem is that I suck at searching :) So what's the best way to solve this? How would you do it? Thanks!

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  • Adding a generic image field onto a ModelForm in django

    - by Prairiedogg
    I have two models, Room and Image. Image is a generic model that can tack onto any other model. I want to give users a form to upload an image when they post information about a room. I've written code that works, but I'm afraid I've done it the hard way, and specifically in a way that violates DRY. Was hoping someone who's a little more familiar with django forms could point out where I've gone wrong. Update: I've tried to clarify why I chose this design in comments to the current answers. To summarize: I didn't simply put an ImageField on the Room model because I wanted more than one image associated with the Room model. I chose a generic Image model because I wanted to add images to several different models. The alternatives I considered were were multiple foreign keys on a single Image class, which seemed messy, or multiple Image classes, which I thought would clutter my schema. I didn't make this clear in my first post, so sorry about that. Seeing as none of the answers so far has addressed how to make this a little more DRY I did come up with my own solution which was to add the upload path as a class attribute on the image model and reference that every time it's needed. # Models class Image(models.Model): content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey('content_type', 'object_id') image = models.ImageField(_('Image'), height_field='', width_field='', upload_to='uploads/images', max_length=200) class Room(models.Model): name = models.CharField(max_length=50) image_set = generic.GenericRelation('Image') # The form class AddRoomForm(forms.ModelForm): image_1 = forms.ImageField() class Meta: model = Room # The view def handle_uploaded_file(f): # DRY violation, I've already specified the upload path in the image model upload_suffix = join('uploads/images', f.name) upload_path = join(settings.MEDIA_ROOT, upload_suffix) destination = open(upload_path, 'wb+') for chunk in f.chunks(): destination.write(chunk) destination.close() return upload_suffix def add_room(request, apartment_id, form_class=AddRoomForm, template='apartments/add_room.html'): apartment = Apartment.objects.get(id=apartment_id) if request.method == 'POST': form = form_class(request.POST, request.FILES) if form.is_valid(): room = form.save() image_1 = form.cleaned_data['image_1'] # Instead of writing a special function to handle the image, # shouldn't I just be able to pass it straight into Image.objects.create # ...but it doesn't seem to work for some reason, wrong syntax perhaps? upload_path = handle_uploaded_file(image_1) image = Image.objects.create(content_object=room, image=upload_path) return HttpResponseRedirect(room.get_absolute_url()) else: form = form_class() context = {'form': form, } return direct_to_template(request, template, extra_context=context)

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  • How should I rewrite my code to make it amenable to unittesting?

    - by justin
    I've been trying to get started with unit-testing while working on a little cli program. My program basically parses the command line arguments and options, and decides which function to call. Each of the functions performs some operation on a database. So, for instance, I might have a create function: def create(self, opts, args): #I've left out the error handling. strtime = datetime.datetime.now().strftime("%D %H:%M") vals = (strtime, opts.message, opts.keywords, False) self.execute("insert into mytable values (?, ?, ?, ?)", vals) self.commit() Should my test case call this function, then execute the select sql to check that the row was entered? That sounds reasonable, but also makes the tests more difficult to maintain. Would you rewrite the function to return something and check for the return value? Thanks

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  • Java: how to initialize int without assigning a value?

    - by HH
    $ javac InitInt.java InitInt.java:9: '[' expected right = new int; ^ InitInt.java:9: ']' expected right = new int; ^ InitInt.java:13: ';' expected } ^ InitInt.java:14: ';' expected public int getRight(){return right;} ^ InitInt.java:15: reached end of file while parsing } ^ 5 errors $ cat InitInt.java import java.util.*; import java.io.*; public class InitInt { private final int right; public static void main(String[] args) { // I don't want to assign any value. // just initialize it, how? right = new int; // later assiging a value } public int getRight(){return right;} }

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  • How to apply custom BidirectionalGraph from QuickGraph to GraphLayout from Graph#?

    - by Dmitry
    Whats wrong? using QuickGraph; using GraphSharp; public class State { public string Name { get; set; } public override string ToString() { return Name; } } public class Event { public string Name; public override string ToString() { return Name; } } BidirectionalGraph<State, TaggedEdge<State, Event>> x = new BidirectionalGraph<State, TaggedEdge<State, Event>>(); GraphLayout graphLayout = new GraphLayout(); graphLayout.Graph = x; Error: Cannot implicitly convert type 'QuickGraph.BidirectionalGraph' to 'QuickGraph.IBidirectionalGraph'. An explicit conversion exists (are you missing a cast?) If I put the cast, then application gets fault error on start without any information Whats wrong?

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  • Implicit and Explicit implementation of interface.

    - by Amby
    While working on a upgrade i happened to come across a code like this. interface ICustomization { IMMColumnsDefinition GetColumnsDefinition(); } class Customization : ICustomization { private readonly ColumnDefinition _columnDefinition; //More code here. public ColumnsDefinition GetColumnsDefinition() { return _columnDefinition; } ColumnsDefinition ICustomization.GetColumnsDefinition() //redundant { return GetColumnsDefinition(); } } My question is: Is there any need/use of 'explicit' implementation of interface in this piece of code? Will it create any problem if i remove the method (explicit implementation of interface) that i have marked "redundant" above? PS: I understand that explicit implementation of interface is very important, and it can be used when we need to give access to a method at interface level only, and to use two interface with same signature of method.

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  • Getting really weird long Contact Group names

    - by Pentium10
    When looking at the Contact Groups on Google Contacts or in the People application of my HTC Legend phone, I get the groups names ok eg: Friends, Family, VIP, Favorite etc... But in my application I get really wrong names such as "Family" became "System Group: Family" "Friends" became "System Group: Friends" "Favorite" became "Favorite_5656100000000_3245664334564" I use the below code to read these values: public Cursor getFromSystem() { // Get the base URI for the People table in the Contacts content // provider. Uri contacts = ContactsContract.Groups.CONTENT_URI; // Make the query. ContentResolver cr = ctx.getContentResolver(); // Form an array specifying which columns to return. String[] projection = new String[] { ContactsContract.Groups._ID, ContactsContract.Groups.TITLE, ContactsContract.Groups.NOTES }; Cursor managedCursor = cr.query(contacts, projection, ContactsContract.Groups.DELETED + "=0", null, ContactsContract.Groups.TITLE + " COLLATE LOCALIZED ASC"); return managedCursor; } What I am missing?

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  • jquery.ajax multiple data problem

    - by Guillaume P
    Hi, I've been trying to make this code work for the last 3 hours. I've tried about everytinh, but I'm still unable to get it to work. I only managed to send 1 data. When I use this code, I only manage to retrieve recaptcha_challenge_field. If I remove recaptcha_challenge_field, I retrieve recaptcha_response_field. However, I am unable to retrieve the two at the same time. challengeField = $("#recaptcha_challenge_field").val(); responseField = $("#recaptcha_response_field").val(); var html = $.ajax( { global: false, type: "POST", async: false, dataType: "html", data: "recaptcha_response_field=" + responseField + "&recaptcha_challenge_field=" + challengeField, url: "../ajax.recaptcha.php" }).responseText; if(html == "success") { $("#captchaStatus").html("Success. Submitting form."); return true; } else { $("#captchaStatus").html("Your captcha is incorrect. Please try again"); Recaptcha.reload(); return false; }

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  • Kohana3 - ErrorException [ Notice ]: Undefined index: id - Error calling Auth::instance()

    - by ahmet2106
    Hello everybody, I've now a Problem with the newest Version of KohanaPHP (kohanaphp.com). After I've registered me and logged in into my test page, some minutes later, there is now the error: ErrorException [ Notice ]: Undefined index: id MODPATH/orm/classes/kohana/orm.php [ 1316 ] 1311 * 1312 * @return mixed primary key 1313 */ 1314 public function pk() 1315 { 1316 return $this->_object[$this->_primary_key]; 1317 } 1318 1319 /** 1320 * Returns whether or not primary key is empty 1321 * I've searched a lot in Google, but i never found an answer, the Problem now is, that I cant reloggin to get a new instance, because I've to call Auth::instance()-login() again, and Auth::instance() is not callable. Whats todo now, how can I fix it, is there already a new Version of ORM or Auth Module? Thanks everybody Ahmet

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  • I keep Getting KeyError: 'tried' Whenever I Tried to Run Django Dev Server from Remote Machine

    - by Spikie
    I am running django on python2.6.1, and did start the django web server like this manage.py runserver 192.0.0.1:8000 then tried to connect to the django dev web server on http://192.0.0.1:8000/ keep getting this message on the remote computer Traceback (most recent call last): File "C:\Python26\Lib\site-packages\django\core\servers\basehttp.py", line 279, in run self.result = application(self.environ, self.start_response) File "C:\Python26\Lib\site-packages\django\core\servers\basehttp.py", line 651, in call return self.application(environ, start_response) File "C:\Python26\lib\site-packages\django\core\handlers\wsgi.py", line 241, in call response = self.get_response(request) File "C:\Python26\lib\site-packages\django\core\handlers\base.py", line 115, in get_response return debug.technical_404_response(request, e) File "C:\Python26\Lib\site-packages\django\views\debug.py", line 247, in technical_404_response tried = exception.args[0]['tried'] KeyError: 'tried' what i am doing wrong ? it seen to work ok if i run http://192.0.0.1:8000/ on the computer that runs the Django web server and have that ip 192.0.0.1:8000

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  • How to implement Xml Serialization with inherited classes in C#

    - by liorafar
    I have two classes : base class name Component and inheritd class named DBComponent [Serializable] public class Component { private string name = string.Empty; private string description = string.Empty; } [Serializable] public class DBComponent : Component { private List<string> spFiles = new List<string>(); // Storage Procedure Files [XmlArrayItem("SPFile", typeof(string))] [XmlArray("SPFiles")] public List<string> SPFiles { get { return spFiles; } set { spFiles = value; } } public DBComponent(string name, string description) : base(name, description) { } } [Serializable] public class ComponentsCollection { private static ComponentsCollection instance = null; private List<Component> components = new List<Component>(); public List<Component> Components { get { return components; } set { components = value; } } public static ComponentsCollection GetInstance() { if (ccuInstance == null) { lock (lockObject) { if (instance == null) PopulateComponents(); } } return instance; } private static void PopulateComponents() { instance = new CCUniverse(); XmlSerializer xs = new XmlSerializer(instance.GetType()); instance = xs.Deserialize(XmlReader.Create("Components.xml")) as ComponentsCollection; } } } I want read\write from a Xml file. I know that I need to implement the Serialization for DBComponent class otherwise it will not read it.But i cannot find any simple article for that. all the articles that I found were too complex for this simple scenario. The Xml file looks like this: <?xml version="1.0" encoding="utf-8" ?> <ComponentsCollection> <Components> <DBComponent Name="Tenant Historical Database" Description="Tenant Historical Database"> <SPFiles> <SPFile>Setup\TenantHistoricalSP.sql</SPFile> </SPFiles> </DBComponent> <Component Name="Agent" Description="Desktop Agent" /> </Components> </ComponentsCollection> Can someone please give me a simple example of how to read this kind of xml file and what should be implemented ? Thanks Lior

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  • ORACLE using function parametes in where claus

    - by Gainder
    Hello, I have created a simple static function in oracle 10g to get the reference of an object based on his pk. STATIC FUNCTION getRef(nome IN VARCHAR2) RETURN REF folder_typ IS fl_r REF folder_typ := null; BEGIN SELECT REF(fl) INTO fl_r FROM folder_tab fl WHERE fl.nome = nome; RETURN fl_r; END getRef; This gives me an error because he could't fetch the row. If insted of WHERE fl.nome = nome; I write WHERE fl.nome = 'folder1'; insted of passing it as parameter it works. I think im not using the parameter in the right way. How can I use it?

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