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  • Scheme: what are the benefits of letrec?

    - by Ixmatus
    While reading "The Seasoned Schemer" I've begun to learn about letrec. I understand what it does (can be duplicated with a Y-Combinator) but the book is using it in lieu of recurring on the already defined function operating on arguments that remain static. An example of an old function using the defined function recurring on itself (nothing special): (define (substitute new old lat) (cond ((null? l) '()) ((eq? (car l) old) (cons new (substitute new old (cdr l)))) (else (cons (car l) (substitute new old (cdr l)))))) Now for an example of that same function but using letrec: (define (substitute new old lat) (letrec ((replace (lambda (l) (cond ((null? l) '()) ((eq? (car l) old) (cons new (replace (cdr l)))) (else (cons (car l) (replace (cdr l)))))))) (replace lat))) Aside from being slightly longer and more difficult to read I don't know why they are rewriting functions in the book to use letrec. Is there a speed enhancement when recurring over a static variable this way because you don't keep passing it?? Is this standard practice for functions with arguments that remain static but one argument that is reduced (such as recurring down the elements of a list)? Some input from more experienced Schemers/LISPers would help!

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  • Inheritance classes in Scheme

    - by DreamWalker
    Now I research OOP-part of Scheme. I can define class in Scheme like this: (define (create-queue) (let ((mpty #t) (the-list '())) (define (enque value) (set! the-list (append the-list (list value))) (set! mpty #f) the-list) (define (deque) (set! the-list (cdr the-list)) (if (= (length the-list) 0) (set! mpty #t)) the-list) (define (isEmpty) mpty) (define (ptl) the-list) (define (dispatch method) (cond ((eq? method 'enque) enque) ((eq? method 'deque) deque) ((eq? method 'isEmpty) isEmpty) ((eq? method 'print) ptl))) dispatch)) (Example from css.freetonik.com) Can I implement class inheritance in Scheme?

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  • Force CL-Lex to read whole word

    - by Flávio Cruz
    I'm using CL-Lex to implement a lexer (as input for CL-YACC) and my language has several keywords such as "let" and "in". However, while the lexer recognizes such keywords, it does too much. When it finds words such as "init", it returns the first token as IN, while it should return a "CONST" token for the "init" word. This is a simple version of the lexer: (define-string-lexer lexer (...) ("in" (return (values :in $@))) ("[a-z]([a-z]|[A-Z]|\_)" (return (values :const $@)))) How do I force the lexer to fully read the whole word until some whitespace appears?

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  • Find all paths from root to leaves of tree in Scheme

    - by grifaton
    Given a tree, I want to find the paths from the root to each leaf. So, for this tree: D / B / \ A E \ C-F-G has the following paths from root (A) to leaves (D, E, G): (A B D), (A B E), (A C F G) If I represent the tree above as (A (B D E) (C (F G))) then the function g does the trick: (define (g tree) (cond ((empty? tree) '()) ((pair? tree) (map (lambda (path) (if (pair? path) (cons (car tree) path) (cons (car tree) (list path)))) (map2 g (cdr tree)))) (else (list tree)))) (define (map2 fn lst) (if (empty? lst) '() (append (fn (car lst)) (map2 fn (cdr lst))))) But this looks all wrong. I've not had to do this kind of thinking for a while, but I feel there should be a neater way of doing it. Any ideas for a better solution (in any language) would be appreciated.

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  • Does CLOS have an eql specialization dispatch on strings?

    - by mhb
    Examples of what you can do. (defmethod some-fn ((num real)) (print "an integer")) (defmethod some-fn ((num real)) (print "a real")) (defmethod some-fn ((num (eql 0))) (print "zero")) (some-fn 19323923198319) "an integer" (some-fn 19323923198319.3) "a real" (some-fn 0) "zero" It also works with a general 'string type. (defmethod some-fn ((num string)) (print "a string")) (some-fn "asrt") "a string" Not with a specific string, however (defmethod some-fn ((num (eql "A")) (print "a specifict string"))) => doesn't compile I imagine it doesn't work because eql does not work on strings in the way that would be necessary for it to work. (eql "a" "a") => nil Is there a way to do it?

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  • How do I write Push and Pop in Scheme?

    - by kunjaan
    Right now I have (define (push x a-list) (set! a-list (cons a-list x))) (define (pop a-list) (let ((result (first a-list))) (set! a-list (rest a-list)) result)) But I get this result: Welcome to DrScheme, version 4.2 [3m]. Language: Module; memory limit: 256 megabytes. > (define my-list (list 1 2 3)) > (push 4 my-list) > my-list (1 2 3) > (pop my-list) 1 > my-list (1 2 3) What am I doing wrong? Is there a better way to write push so that the element is added at the end and pop so that the element gets deleted from the first?

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  • How to change aif to be able to access 'it' within the macrocall without making 'it' public in the package

    - by Sim
    If you put the aif code presented in onlisp in a package and try to use it in another you run in the problem that packagename:it is not external. (in-package :packagename) (defmacro aif (test-form then-form &optional else-form) ‘(let ((it ,test-form)) (if it ,then-form ,else-form))) wanted call syntax (in-package :otherpackage) (aif (do-stuff) (FORMAT t "~a~%" it) (FORMAT t "just got nil~%")) How can I fix this behavior in code, without making the variable it external in the package declaration and beeing able to access it just by it instead of packagename:it?

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  • Writing an Eval Procedure in Scheme?

    - by Planeman
    My problem isn't with the built-in eval procedure but how to create a simplistic version of it. Just for starters I would like to be able to take this in '(+ 1 2) and have it evaluate the expression + where the quote usually takes off the evaluation. I have been thinking about this and found a couple things that might be useful: Unquote: , (quasiquote) (apply) My main problem is regaining the value of + as a procedure and not a symbol. Once I get that I think I should just be able to use it with the other contents of the list. Any tips or guidance would be much appreciated.

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  • Finding greatest product of two lists, but keep getting #unspecific

    - by user1787030
    (define (greatest-product lst1 lst2) (define (helper lst addtimes total toacc) (cond ((null? lst) '()) ((= (countatoms lst) 1) (display total)) ((= addtimes (cadr lst)) (helper (cdr lst) 1 total total)) (else (helper lst (+ 1 addtimes) (+ toacc total) toacc)))) (cond ((> (helper lst1 0 0 (car lst1)) (helper lst2 0 0 (car lst2))) (helper lst1 0 0 (car lst1))) ((< (helper lst1 0 0 (car lst1)) (helper lst2 0 0 (car lst2))) (helper lst2 0 0 (car lst2))) ((= (helper lst1 0 0 (car lst1)) (helper lst2 0 0 (car lst2))) (display 'equal)))) Scheme keeps returning back that it cannot perform the procedure with #unspecific Im running it with (display (greatest-product '(1 2 3) '(4 5 6))) (display (greatest-product '(1 2 3) '(1 2 3))) (display (greatest-product '(1 2 3) '())) what is wrong with it? the problem seems to be occurring

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  • format - Help with printing a table

    - by Michael Kohl
    This question will probably end in a facepalm, but I've tried for a while and am still stuck despite reading through the hyperspec. Basically what I want to do is something like (format t "~{|~{ ~5d~}|~%~}" '((1 23 2 312) (23 456 1 7890))) but instead of hard-coding the 5 it should be calculated from the list (length of longest element from any nested list + 1) to give something like | 1 23 2 312| | 23 456 1 7890| Maybe I'm thinking way too complicated here and there is an easier way to do what I want, but I think I ran myself into a mental corner that I can't get out of.

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  • Scheme Function to reverse elements of list of 2-list

    - by sudhirc
    This is an exercise from EOPL. Procedure (invert lst) takes lst which is a list of 2-lists and returns a list with each 2-list reversed. (define invert (lambda (lst) (cond((null? lst ) '()) ((= 2 (rtn-len (car lst))) ( cons(swap-elem (car lst)) (invert (cdr lst)))) ("List is not a 2-List")))) ;; Auxiliry Procedure swap-elements of 2 element list (define swap-elem (lambda (lst) (cons (car (cdr lst)) (car lst)))) ;; returns lengh of the list by calling (define rtn-len (lambda (lst) (calc-len lst 0))) ;; calculate length of the list (define calc-len (lambda (lst n) (if (null? lst) n (calc-len (cdr lst) (+ n 1))))) This seems to work however looks very verbose. Can this be shortened or written in more elegant way ? How I can halt the processing in any of the individual element is not a 2-list? At the moment execution proceed to next member and replacing current member with "List is not a 2-List" if current member is not a 2-list.

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  • How to cast a character to int in Clojure?

    - by Learning Clojure
    How to cast a character to int in Clojure? I am trying to write a rot 13 in clojure, so I need to have something to cast my char to int. I found something called (int), so I put: (int a) Get: CompilerException java.lang.RuntimeException: Unable to resolve symbol: a in this context, compiling:(NO_SOURCE_PATH:13:1) Then I put: (int 'a) Get: ClassCastException clojure.lang.Symbol cannot be cast to java.lang.Character clojure.lang.RT.intCast (RT.java:1087) Then: (rot13 ''a') Get: ClassCastException clojure.lang.PersistentList cannot be cast to java.lang.Character clojure.lang.RT.intCast (RT.java:1087) And: (rot13 "a") Get: ClassCastException java.lang.String cannot be cast to java.lang.Character clojure.lang.RT.intCast (RT.java:1087) So what is the right way to do it? btw, I always get confused with all these clojure syntax. But I can never find any source only help me with my problem. Any suggestions? Thank you!!

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  • Why does using cons to create a pair of two lists produce a list and two elements?

    - by fingerprint211b
    I've started learning Scheme, for fun mostly, and because I've never used a functional language before. I chose Scheme because I wanted to read SICP for a long time. Anyway, I'm currently learning about lists, and before that I learned about cons, car and cdr. And there's an example that creates a list of lists with cons, like this : (cons (list 1 2) (list 3 4)) The resulting list is ((1 2) 3 4), which doesn't make sense to me, I would expect ((1 2)(3 4)) to be the result (a list made out of two lists). Why does it behave like that? I realize that if I were to use car, I would get (1 2), and cdr I'd get (3 4) becaue cdr always returns "the rest", but I don't understand why the list isn't made of two lists?

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  • Consecutive calls/evaulations in a form?

    - by Dave
    Hey guys, simple question... Working with XLISP to write a program, but I've seemed to run into a simple fundamental problem that I can't seem to work around: perhaps someone has a quick fix. I'm trying to write an if statement who's then-clause evaluates multiple forms and returns the value of the last. In example: (setq POSITION 'DINING-ROOM) (defun LOOK (DIRECTION ROOM) ... ) (defun SETPOS (ROOM) ... ) (defun WHERE () ... ) (defun MOVE (DIRECTION) (if (not(equal nil (LOOK DIRECTION POSITION))) ; If there is a room in that direction ( ; Then-block: Go to that room. Return where you are. (SETPOS (LOOK DIRECTION ROOM)) (WHERE) ) ( ; Else-block: Return error (list 'CANT 'GO 'THERE) ) ) The logical equivalent intended is: function Move (Direction) { if(Look(Direction, Room) != null) { SetPos(Look(Direction,Room)); return Where(); } else { return "Can't go there"; } } (Apologies for the poor web-formatting.) The problem I have is with: ( (SETPOS (LOOK DIRECTION ROOM)) (WHERE) ) I simply want to return the evaluation of WHERE, but I need to execute the SETPOS function first. XLISP doesn't like the extra parentheses: if I remove the outer set, my WHERE list becomes my else (I don't want that). If I remove the sets around SETPOS and WHERE, it treats WHERE like an argument for SETPOS; I also don't want that. So, how do I simply evaluate the first, then the second and then return the values of the last evaluated?

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  • Generate Permutations of a List

    - by Eric Mercer
    I'm writing a function that takes a list and returns a list of permutations of the argument. I know how to do it by using a function that removes an element and then recursively use that function to generate all permutations. I now have a problem where I want to use the following function: (define (insert-everywhere item lst) (define (helper item L1 L2) (if (null? L2) (cons (append L1 (cons item '())) '()) (cons (append L1 (cons item L2)) (helper item (append L1 (cons (car L2) '())) (cdr L2))))) (helper item '() lst)) This function will insert the item into every possible location of the list, like the following: (insert-everywhere 1 '(a b)) will get: '((1 a b) (a 1 b) (a b 1)) How would I use this function to get all permutations of a list? I now have: (define (permutations lst) (if (null? lst) '() (insert-helper (car lst) (permutations (cdr lst))))) (define (insert-helper item lst) (cond ((null? lst) '()) (else (append (insert-everywhere item (car lst)) (insert-helper item (cdr lst)))))) but doing (permutations '(1 2 3)) just returns the empty list '().

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  • How do I learn Scheme?

    - by Gautam
    Hey, I'm a relative newbie to programming. I've picked up some very basic Java (File I/O, GUIs, inheritance) and would like to take a look at functional programming - in particular, I would like to learn Scheme. I'm having some trouble finding a Scheme implementation I can understand. Interpreters are weird; I'm not sure how to save my programs and create executables. I've downloaded PLT Scheme, but I would prefer using something less condescending, something similar to NetBeans. Is there a plugin or tool that will allow me to quickly and easily create and manage Scheme programs? All help is appreciated!

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  • Can you execute multiple statements in with a If statement?

    - by Jack Null
    This is my function: (defun MyFunction(input) (let ((NEWNUM (find input num))) (if (find input num) //if this (setq num NEWNUM) (FUNCT2) //then execute both of these (list 'not found)))) //else output this So after the if statment I want to be able to execute (setq num NEWNUM) and (FUNCT2). One to set a new variable and then the other to call a function. Any ideas on how to do this?

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  • How do I take a slice of a list (A sublist) in scheme?

    - by troelskn
    Given a list, how would I select a new list, containing a slice of the original list (Given offset and number of elements) ? EDIT: Good suggestions so far. Isn't there something specified in one of the SRFI's? This appears to be a very fundamental thing, so I'm surprised that I need to implement it in user-land.

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  • infinite loop shutting down ensime

    - by Jeff Bowman
    When I run M-X ensime-disconnect I get the following forever: string matching regex `\"((?:[^\"\\]|\\.)*)\"' expected but `^@' found and I see this exception when I use C-c C-c Uncaught exception in com.ensime.server.SocketHandler@769aba32 java.net.SocketException: Broken pipe at java.net.SocketOutputStream.socketWrite0(Native Method) at java.net.SocketOutputStream.socketWrite(SocketOutputStream.java:109) at java.net.SocketOutputStream.write(SocketOutputStream.java:153) at sun.nio.cs.StreamEncoder.writeBytes(StreamEncoder.java:220) at sun.nio.cs.StreamEncoder.implFlushBuffer(StreamEncoder.java:290) at sun.nio.cs.StreamEncoder.implFlush(StreamEncoder.java:294) at sun.nio.cs.StreamEncoder.flush(StreamEncoder.java:140) at java.io.OutputStreamWriter.flush(OutputStreamWriter.java:229) at java.io.BufferedWriter.flush(BufferedWriter.java:253) at com.ensime.server.SocketHandler.write(server.scala:118) at com.ensime.server.SocketHandler$$anonfun$act$1$$anonfun$apply$mcV$sp$1.apply(server.scala:132) at com.ensime.server.SocketHandler$$anonfun$act$1$$anonfun$apply$mcV$sp$1.apply(server.scala:127) at scala.actors.Actor$class.receive(Actor.scala:456) at com.ensime.server.SocketHandler.receive(server.scala:67) at com.ensime.server.SocketHandler$$anonfun$act$1.apply$mcV$sp(server.scala:127) at com.ensime.server.SocketHandler$$anonfun$act$1.apply(server.scala:127) at com.ensime.server.SocketHandler$$anonfun$act$1.apply(server.scala:127) at scala.actors.Reactor$class.seq(Reactor.scala:262) at com.ensime.server.SocketHandler.seq(server.scala:67) at scala.actors.Reactor$$anon$3.andThen(Reactor.scala:240) at scala.actors.Combinators$class.loop(Combinators.scala:26) at com.ensime.server.SocketHandler.loop(server.scala:67) at scala.actors.Combinators$$anonfun$loop$1.apply(Combinators.scala:26) at scala.actors.Combinators$$anonfun$loop$1.apply(Combinators.scala:26) at scala.actors.Reactor$$anonfun$seq$1$$anonfun$apply$1.apply(Reactor.scala:259) at scala.actors.ReactorTask.run(ReactorTask.scala:36) at scala.actors.ReactorTask.compute(ReactorTask.scala:74) at scala.concurrent.forkjoin.RecursiveAction.exec(RecursiveAction.java:147) at scala.concurrent.forkjoin.ForkJoinTask.quietlyExec(ForkJoinTask.java:422) at scala.concurrent.forkjoin.ForkJoinWorkerThread.mainLoop(ForkJoinWorkerThread.java:340) at scala.concurrent.forkjoin.ForkJoinWorkerThread.run(ForkJoinWorkerThread.java:325) Is there something else I'm missing in my config or I should check on? Thanks, Jeff

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  • org-mode schedule weekly event for a period.

    - by Hamza Yerlikaya
    I would like to use agenda to keep track of my classes, assuming i have a com 355 class every week from march to june, <2010-03-23 Tue 10:40-12:10 +1w> this works but it schedules it indefinitely if i use, <2010-03-23 Tue 10:40-12:10 +1w>-<2010-06-23> it gets scheduled for everyday from march to june, how can i schedule this once a week for a period of time?

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