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  • matlab: figure size, same axis size

    - by Art
    I have a figure with fixed size, like that: hFig = figure(1); set(hFig, 'Position', [200 200 500 500]) But the thing is, that I want to have my AXIS with fixed size (i want them to be a square), not (necessary) the whole figure... - see image attached, Y axis is a bit longer than X axis (of course longer in a meaning of display... X and Y axis range is set to the same value). How to adjust it? Thanks!

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  • Factorising program not working. Help required.

    - by Ender
    I am working on a factorisation problem using Fermat's Factorization and for small numbers it is working well. I've been able to calculate the factors (getting the answers from Wolfram Alpha) for small numbers, like the one on the Wikipedia page (5959). Just when I thought I had the problem licked I soon realised that my program was not working when it came to larger numbers. The program follows through the examples from the Wikipedia page, printing out the values a, b, a2 and b2; the results printed for large numbers are not correct. I've followed the pseudocode provided on the Wikipedia page, but am struggling to understand where to go next. Along with the Wikipedia page I have been following this guide. Once again, as my Math knowledge is pretty poor I cannot follow what I need to do next. The code I am using so far is as follows: import java.math.BigInteger; /** * * @author AlexT */ public class Fermat { private BigInteger a, b; private BigInteger b2; private static final BigInteger TWO = BigInteger.valueOf(2); public void fermat(BigInteger N) { // floor(sqrt(N)) BigInteger tmp = getIntSqrt(N); // a <- ceil(sqrt(N)) a = tmp.add(BigInteger.ONE); // b2 <- a*a-N b2 = (a.multiply(a)).subtract(N); final int bitLength = N.bitLength(); BigInteger root = BigInteger.ONE.shiftLeft(bitLength / 2); root = root.add(b2.divide(root)).divide(TWO); // while b2 not square root while(!(isSqrt(b2, root))) { // a <- a + 1 a = a.add(BigInteger.ONE); // b2 <- (a * a) - N b2 = (a.multiply(a)).subtract(N); root = root.add(b2.divide(root)).divide(TWO); } b = getIntSqrt(b2); BigInteger a2 = a.pow(2); // Wrong BigInteger sum = (a.subtract(b)).multiply((a.add(b))); //if(sum.compareTo(N) == 0) { System.out.println("A: " + a + "\nB: " + b); System.out.println("A^2: " + a2 + "\nB^2: " + b2); //} } /** * Is the number provided a perfect Square Root? * @param n * @param root * @return */ private static boolean isSqrt(BigInteger n, BigInteger root) { final BigInteger lowerBound = root.pow(2); final BigInteger upperBound = root.add(BigInteger.ONE).pow(2); return lowerBound.compareTo(n) <= 0 && n.compareTo(upperBound) < 0; } public BigInteger getIntSqrt(BigInteger x) { // It returns s where s^2 < x < (s+1)^2 BigInteger s; // final result BigInteger currentRes = BigInteger.valueOf(0); // init value is 0 BigInteger currentSum = BigInteger.valueOf(0); // init value is 0 BigInteger sum = BigInteger.valueOf(0); String xS = x.toString(); // change input x to a string xS int lengthOfxS = xS.length(); int currentTwoBits; int i=0; // index if(lengthOfxS % 2 != 0) {// if odd length, add a dummy bit xS = "0".concat(xS); // add 0 to the front of string xS lengthOfxS++; } while(i < lengthOfxS){ // go through xS two by two, left to right currentTwoBits = Integer.valueOf(xS.substring(i,i+2)); i += 2; // sum = currentSum*100 + currentTwoBits sum = currentSum.multiply(BigInteger.valueOf(100)); sum = sum.add(BigInteger.valueOf(currentTwoBits)); // subtraction loop do { currentSum = sum; // remember the value before subtract // in next 3 lines, we work out // currentRes = sum - 2*currentRes - 1 sum = sum.subtract(currentRes); // currentRes++ currentRes = currentRes.add(BigInteger.valueOf(1)); sum = sum.subtract(currentRes); } while(sum.compareTo(BigInteger.valueOf(0)) >= 0); // the loop stops when sum < 0 // go one step back currentRes = currentRes.subtract(BigInteger.valueOf(1)); currentRes = currentRes.multiply(BigInteger.valueOf(10)); } s = currentRes.divide(BigInteger.valueOf(10)); // go one step back return s; } /** * @param args the command line arguments */ public static void main(String[] args) { Fermat fermat = new Fermat(); //Works //fermat.fermat(new BigInteger("5959")); // Doesn't Work fermat.fermat(new BigInteger("90283")); } } If anyone can help me out with this problem I'll be eternally grateful.

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  • jQuery image grid effect

    - by anon
    I have an image sitting on a page that I want to create a grid type overlay (that covers the image with a black fill) which will be partitioned into 50x50 pixels (what ever size, tbh) squares. The squares on the grid will then flip over, one at a time, in random positions revealing the image below it. The only way I can think of accomplishing this would be to create a whole bunch of grid squares and overlay them on the image with jQuery, then flip each image square individually. This, though, would be a pain in the ass. Doing this all dynamically in jQuery is what I'm hoping to accomplish. Any ideas?

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  • Mac dashboard widgets not loading external images

    - by andrhamm
    I set out to make a quick Mac OS X dashboard widget. I read the documentation and was pleased to find out they use simple HTML, JS, and CSS. I created my widget and it works when I open the .html file in Firefox, but it does not work when I install the widget to the dashboard. The widget is simple: it displays the most recent image from a weather web cam stream. The image URLs look like this: http://webcam.com/stream.jpg?1274213999617. The timestamp is appended to the URL and the server automatically responds with the latest image for that time. I did not write the server script. The widget appears to be loading correctly, but the web cam image will not load. Notice the blue question mark in the upper left. The image should appear over the square background image. Is there any special procedure for loading external images into a widget?

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  • Dynamic programming: Largest diamond(rhombus) block

    - by Darksody
    I have a small program to do in Java. I have a 2D array filled with 0 and 1, and I must find the largest rhombus (as in square rotated by 90 degrees) and their numbers. Example: 0 1 0 0 0 1 1 0 1 1 1 0 1 0 1 1 1 1 0 1 1 1 1 1 0 0 1 1 1 1 1 1 1 1 1 1 Result: 1 1 1 1 1 1 1 1 1 1 1 1 1 The problem is similar to this SO question. If you have any idea, post it here.

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  • C++ double division by 0.0 versus DBL_MIN

    - by wonsungi
    When finding the inverse square root of a double, is it better to clamp invalid non-positive inputs at 0.0 or MIN_DBL? (In my example below double b may end up being negative due to floating point rounding errors and because the laws of physics are slightly slightly fudged in the game.) Both division by 0.0 and MIN_DBL produce the same outcome in the game because 1/0.0 and 1/DBL_MIN are effectively infinity. My intuition says MIN_DBL is the better choice, but would there be any case for using 0.0? Like perhaps sqrt(0.0), 1/0.0 and multiplication by 1.#INF000000000000 execute faster because they are special cases. double b = 1 - v.length_squared()/(c*c); #ifdef CLAMP_BY_0 if (b < 0.0) b = 0.0; #endif #ifdef CLAMP_BY_DBL_MIN if (b <= 0.0) b = DBL_MIN; #endif double lorentz_factor = 1/sqrt(b); double division in MSVC: 1/0.0 = 1.#INF000000000000 1/DBL_MIN = 4.4942328371557898e+307

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  • Is there a way to move two squares in OpenGL simultaneously?

    - by thyrgle
    Hi, so I have a function that handles key presses in a game I'm working on in OpenGL. But, the thing is that even though I have made two squares and they both move when the correct key is pressed only one square is moved. Is there a way I can make the two squares move. This is the glutKeyboardFunc function I implimented: void handleKeypress(unsigned char key, int x, int y) { switch (key) { case 27: exit(0); break; case 'w': glutTimerFunc(0.001, moveSquareUp, 0); break; case 'd': glutTimerFunc(0.001, moveSquareRight, 0); break; case 's': glutTimerFunc(0.001, moveSquareDown, 0); break; case 'a': glutTimerFunc(0.001, moveSquareLeft, 0); break; } } If you need any more code just ask.

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  • Which containers / graphics components to use in a simple Java Swing game?

    - by rize
    I'm creating a simple labyrinth game with Java + Swing. The game draws a randomized labyrinth on the screen, places a figure in the middle, and the player is then supposed to find the way out by moving the figure with arrow-keys. As for now, I'm using a plain background and drawing the walls of the labyrinth with Graphics.drawLine(). I have a custom picture of the figure in a .gif file, which I load as a BufferedImage object. However, I want the player to see only part of the labyrinth at a time, and the screen should follow the figure in the game, as the player moves around. I'm planning to do this by creating an Image object of the whole labyrinth when it is created, and then "cutting" a square around the current position of the figure and displaying this with Graphics.drawImage(). I'm new with Swing though, and I can't figure out how to draw the figure at different positions "above" the labyrinth without redrawing the whole thing. Which container/component should I use for the labyrinth and then for the figure to achieve this?

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  • How to center an R plot after removing axis labels

    - by ConnorG
    I'm working on visualizing a matrix in R (almost exactly like http://reference.wolfram.com/mathematica/ref/MatrixPlot.html), and I've been using image(<matrix>,axes=FALSE) to draw the picture. However, I noticed that with the y-axis turned off, the plot isn't centered--the space is still there for the axis ticks + label. I can finagle some centering with par(oma=c(0,0,0,2.5)) but this seems inefficient and error-prone (if my matrix were to change dimensions/become non-square). Is there a better way to force the graphic to center? The right hand margin is significantly smaller than the left.

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  • Make jQuery-ui draggable handle cover entire page

    - by Acorn
    What would be the best way to make an element draggable when clicking anywhere in the window? Would I have to use a container <div> that covers the whole window? I tried making the body draggable but that didn't work. The problem with using a container <div> is that it moves and therefore doesn't cover the whole of the screen any more after it has been dragged. What about making a really vast container <div> that spans a large number of pixels in every direction so you would never get to the edge of it. Is that a bad idea? The idea (simplified) is to have a page with a square in the middle that can be dragged by dragging any part of the window. Here's a wonderfully unnecessary mockup :)

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  • Dynamic programming: Find largest diamond (rhombus)

    - by Darksody
    I have a small program to do in Java. I have a 2D array filled with 0 and 1, and I must find the largest rhombus (as in square rotated by 90 degrees) and their numbers. Example: 0 1 0 0 0 1 1 0 1 1 1 0 1 0 1 1 1 1 0 1 1 1 1 1 0 0 1 1 1 1 1 1 1 1 1 1 Result: 1 1 1 1 1 1 1 1 1 1 1 1 1 The problem is similar to this SO question. If you have any idea, post it here.

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  • C# huge size 2-dim arrays

    - by 4eburek
    I need to declare square matrices in C# WinForms with more than 20000 items in a row. I read about 2GB .Net object size limit in 32bit and also the same case in 64bit OS. So as I understood the single answer - is using unsafe code or separate library built withing C++ compiler. The problem for me is worth because ushort[20000,20000] is smaller then 2GB but actually I cannot allocate even 700MB of memory. My limit is 650MB and I don't understand why - I have 32bit WinXP with 3GB of memory. I tried to use Marshal.AllocHGlobal(700<<20) but it throws OutOfMemoryException, GC.GetTotalMemory returns 4.5MB before trying to allocate memory. I found only that many people say use unsafe code but I cannot find example of how to declare 2-dim array in heap (any stack can't keep so huge amount of data) and how to work with it using pointers. Is it pure C++ code inside of unsafe{} brackets? Could you please provide a small example of working with matrices using pointers in unsafe code.

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  • Can bad stuff happen when dividing 1/a very small float?

    - by Jeremybub
    If I want to check that positive float A is less than the inverse square of another positive float B (in C99), could something go wrong if B is very small? I could imagine checking it like if(A<1/(B*B)) but if B is small enough, would this possibly result in infinity? If that were to happen, would the code still work correctly in all situations? in a similar vein, I might do if(1/A>B*B) Which might be slightly better because B*B might be zero if B is small (is this true?) Finally, a solution that I can't imagine being wrong is if(sqrt(1/A)>B) Which I don't think would ever result in zero division, but still might be problematic if A is close to zero. So basically, my questions are Can 1/X ever be infinity if X is greater than zero (but small)? Can X*X ever be zero if X is greater than zero? Will comparisons with infinity work the way I would expect them to?

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  • Have a link that is imported in xml, clickable to execute a function

    - by Benjamin Sterling
    Ok, here's the question, I have an xml doc that is being import into an AS3 file and then with .htmlText, appending it to a movie clip. An example of what this looks like is: <abstract><![CDATA[<p><strong>AEO Times Square</strong> Store Wins Prestigious SEGD Merit Award for Dynamic Environments <a href='event:OpenArticle1'>View Article</a></p>]]></abstract> What I'd like to have happen is when I click that view article link that I can call a function passing in "OpenArticle1". Thanks in advance.

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  • AJAX response inside jqplot not working

    - by JuanGesino
    I'm trying to render data from an AJAX response as a bar chart with jqplot. To render this bar chart I use two variables: s1 which contains the numbers ex: s1 = [22,67,32,89] ticks which contains the name corresponding to a number inside s1 ex: ticks = ["Jack", "Mary", "Paul", "John"] So my AJAX returns two variables, data1 and data2. When I console.log(data1) I get 22,67,32,89 When I console.log(data2) I get "Jack", "Mary", "Paul", "John" I then add the square brackets and change variable: s1 = [data1] ticks = [data2] When I console.log(s1) I get ["22,67,32,89"] When I console.log(ticks) I get "Jack", "Mary", "Paul", "John" And the graph does not render, this is my code: s1 = [data]; ticks = [data]; plot4 = $.jqplot('chartdiv4', [s1], { animate: !$.jqplot.use_excanvas, series:[{color:'#5FAB78'}], seriesDefaults:{ renderer:$.jqplot.BarRenderer, pointLabels: { show: true } }, axes: { xaxis: { renderer: $.jqplot.CategoryAxisRenderer, ticks: ticks }, yaxis:{min:0, max:100, label:'%',labelRenderer: $.jqplot.CanvasAxisLabelRenderer} }, highlighter: { show: false } }); });

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  • Magento Product Details Image Size

    - by Jason
    Magento 1.4 Default Product Details image size is 265x265. All of our product images will be probably 2x taller than wide, and even if we pad them to make them square 265 will be too small to see detail in the image, so we'd like to make the image taller. I found the media.phtml file How would we go about modifying this file/Magento so that the product details page image is 265W x 530H. This looks like the code that displays the image. <p class="product-image"> <?php $_img = '<img src="'.$this->helper('catalog/image')->init($_product, 'image')->resize(265).'" alt="'.$this->htmlEscape($this->getImageLabel()).'" title="'.$this->htmlEscape($this->getImageLabel()).'" />'; echo $_helper->productAttribute($_product, $_img, 'image'); ?> </p> Thanks

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  • How to draw/manage a hexagon grid?

    - by W.N.
    I've read this article: generating/creating hexagon grid in C . But look like both the author and answerer have already abandoned it. v(hexagonSide - hexagonWidth * hexagonWidth): What's hexagonSide and hexagonWidth? Isn't it will < 0 (so square root can't be calculated). And, can I put a hexagon into a rectangle? I need to create a grid like this: One more thing, how can I arrange my array to store data, as well as get which cells are next to one cell? I have never been taught about hexagon, so I know nothing about it, but I can easily learn new thing, so if you can explain or give me a clue, I may do it myself.

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  • min max coordinate of cells , given cell length in c#

    - by Raj
    Please see attached picture to better understand my question i have a matrix of cells of [JXI] , cell is square in shape with length "a" my question is .. is there a way to use FOR loop to assign MIN,MAX coordinate to each cell taking origin (0,0) at one corner Thanks "freeimagehosting.net/uploads/3b09575180.jpg" i was trying following code but no success int a ; a = 1; for (int J=1; J<=5; J++) { for (int I = 1; I <= 5; I++) { double Xmin = ((I - 1)*a ); double Ymin = ((J - 1) * a); double Xmax = (I * a ); double Ymax = (J * a); } }

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  • Nested ng repeat not working

    - by Rodrigo Fonseca
    Ok, i've two ng-repeat working here, the first(board in boards) is working good, no problem, but the second(task in tasks), when i try to get "{{task.title}}" i don't get anything but i can display all the style from it... here is my model: $scope.tasks = [{boardIndex: 0, title: "test"}, {boardIndex: 1, title: "test2"}]; Here is my code(it's in jade, ok?) section(data-ng-repeat="board in boards", ng-cloak) .board_header div(data-ng-controller="AddTaskBtnController") i.add_task_btn.fa.fa-plus-square-o.fa-2x(ng-click='setSelected(board.id)', ng-class="{icon_add_hover: isSelected(board.id)}") h2(data-ng-bind="board.title") .content_board .task(data-ng-repeat="task in tasks", data-ng-if="task.boardIndex == board.id", data-ng-controller='TaskController', data-ng-hide='modeTask', data-ng-init='setTaskId()') .user_icon_task i.fa.fa-user.fa-3x.icon-user-not-selected .quest_task .puzzle_task(data-ng-hide='modeTask') i.fa.fa-check-circle-o.fa-lg h2 {{task.title}} ul.icons_details_task_wrapper li i.fa.fa-check-circle-o span.icon_counter li.pull_left i.fa.fa-puzzle-piece span.icon_counter ul.task_details_wrapper li.task_priority(data-ng-show='goal.selectedDrawAttention', data-ng-click='toggleSelected()', data-ng-class='{draw_attention_selected: goal.selectedDrawAttention }', style='cursor: inherit;') i.fa.fa-eye li.task_priority i.fa .task_time_ago span(am-time-ago='message.time')

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  • Windows Phone Mango: Making a drawing app with various brushes option

    - by Md. Abdul Munim
    I am trying to make a drawing app. The purpose is simple. Let the user draw something on a canvas with various brush options like square brush,far brush,pencil brush and many more like any other drawing app available in android market. At present I can let the user draw smooth curves using following code: currentPoint = e.GetPosition(this.canvas); Line line = new Line() { X1 = currentPoint.X, Y1 = currentPoint.Y, X2 = oldPoint.X, Y2 = oldPoint.Y }; line.Stroke = new SolidColorBrush(Colors.Purple); line.StrokeThickness = 2; this.drawnImage.Add(line); this.canvas.Children.Add(line); oldPoint = currentPoint; Now I want some custom brush options and let the user draw using that.How can I achieve that? Thanks in advance.

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  • iphone tabbar with custom buttons and scrollvie

    - by chunjai
    i'm trying to get a tab bar effect not unlike russel quinn's 'creative review' app. the tabbar swipes across, which i have figured out, but the tabbar style itself is unlike anything i've seen on the iphone (though it looks so simple!). it has square buttons with a space between, and each button has a select/active/inactive state. i'm having a hard time seeing how this can be tabbar, but i don't know any other way. can someone explain this? here's the example :: http://bit.ly/c8CeBC. any help is appreciated.

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  • HTML 5 Canvas - Get pixel data for a path

    - by Mikey S.
    I wonder if is there any way I can get pixel data for the currently drawn path in the canvas tag. I can calculate the pixel data on my own when drawing simple shapes like square or a line, but things get messy with more complicated shapes like ellipse or even a simple circle. The reason i'm asking this is because I'm working on a web application which involves sending canvas pixels data to the server when I add a path to the canvas. The server needs to keep it's own copy of the entire canvas, and I really don't want to send the ENTIRE canvas image every single change, but only the delta for efficiency reasons... Thanks.

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  • How to get characters read from the keyboard?

    - by Sandy
    Hi, I am trying to get the characters read from the keyboard. I have the following list of that I wish to recognize if entered by a user. List of keyboard entries: letters [ ] ~ ^ numbers Part of the code: void HookManager_KeyUp(object sender, KeyEventArgs e) { string test = e.KeyCode.ToString(); Here numbers, letters and square brackets work correctly but the ~ and ^ which require shift key is read incorrectly. For eg. it reads ^ which is on key 6 as a value of 6 and not ^ as it should be. Any help would be appreciated. Thanks AA

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  • VB .NET Shared Function if called multiple times simultaneously

    - by Mehdi Anis
    Consider I have a shared function:- Public Shared Function CalculateAreaFromRadius(ByVal radius As Double) As Double ' square the radius... Dim radiusSquared As Double radiusSquared = radius * radius ' multiply it by pi... Dim result As Double result = radiusSquared * Math.PI 'Wait a bit, for the sake of testing and 'simulate another call will be made b4 earlier one ended or such for i as Integer = 0 to integer.Max Next ' return the result... Return result End Function My Questions: If I have two or more threads in the same vb .net app and each of them calls the shared function at the same time with different RADIUS, will they each get their own AREA? I want to know for each call to the function if it is using same local variables or each call creates new instances of local variables? Will the answers to above questions be same If I have multiple (2+) single threaded apps and they all call the function at the same time with different RADIUS value? I will appreciate your reponse. Thank you.

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  • listview tile layout problem (vb.net)

    - by Matt Facer
    hi guys, I have a listview which displays (eventually) an album cover of an itunes play list with the album name under it. the problem I am having is that I cannot get the album art (currently a blank square) ABOVE the album name. It always is on the side... how do I do it? I've tried adding column headers and alsorts... code to set up the listview Dim myImageList As ImageList albumList.View = View.Tile albumList.TileSize = New Size(120, 150) ' Initialize the item icons. myImageList = New ImageList() myImageList.Images.Add(Image.FromFile("c:/test.jpg")) myImageList.ImageSize = New Size(80, 80) albumList.LargeImageList = myImageList I then do a loop to display each album name which uses Dim item0 As New ListViewItem(New String() _ {Albums(i).Name}, 0) albumList.Items.Add(item0) the output is http://i111.photobucket.com/albums/n122/mfacer/Screenshot2010-05-02at164815.png but as i said, I want the album name under the orange box.... any ideas?? Thanks for any info!

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