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  • Django Forms Help needed

    - by user320993
    Hi All, Im new to django and trying to make a user registration form with few validations. Apart from this I also want a username suggestion code which will tell the user if the username he is trying to register is available or already in use. Then it should give few suggestions that might be available to choose from. Can anyone who might have worked on the same or somewhat same project help me with this. Thanks

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  • Django templates check condition

    - by Hulk
    If there are are no values in the table how can should the code be to indicate no name found else show the drop down box in the below code {% for name in dict.names %} <option value="{{name.id}}" {% for selected_id in selected_name %}{% ifequal name.id selected_id %} {{ selected }} {% endifequal %} {% endfor %}>{{name.firstname}}</option>{% endfor %} </select> Thanks..

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  • I'm making a simulated tv

    - by Jam
    I need to make a tv that shows the user the channel and the volume, and shows whether or not the television is on. I have the majority of the code made, but for some reason the channels won't switch. I'm fairly unfamiliar with how properties work, and I think that's what my problem here is. Help please. class Television(object): def __init__(self, __channel=1, volume=1, is_on=0): self.__channel=__channel self.volume=volume self.is_on=is_on def __str__(self): if self.is_on==1: print "The tv is on" print self.__channel print self.volume else: print "The television is off." def toggle_power(self): if self.is_on==1: self.is_on=0 return self.is_on if self.is_on==0: self.is_on=1 return self.is_on def get_channel(self): return channel def set_channel(self, choice): if self.is_on==1: if choice>=0 and choice<=499: channel=self.__channel else: print "Invalid channel!" else: print "The television isn't on!" channel=property(get_channel, set_channel) def raise_volume(self, up=1): if self.is_on==1: self.volume+=up if self.volume>=10: self.volume=10 print "Max volume!" else: print "The television isn't on!" def lower_volume(self, down=1): if self.is_on==1: self.volume-=down if self.volume<=0: self.volume=0 print "Muted!" else: print "The television isn't on!" def main(): tv=Television() choice=None while choice!="0": print \ """ Television 0 - Exit 1 - Toggle Power 2 - Change Channel 3 - Raise Volume 4 - Lower Volume """ choice=raw_input("Choice: ") print if choice=="0": print "Good-bye." elif choice=="1": tv.toggle_power() tv.__str__() elif choice=="2": change=raw_input("What would you like to change the channel to?") tv.set_channel(change) tv.__str__() elif choice=="3": tv.raise_volume() tv.__str__() elif choice=="4": tv.lower_volume() tv.__str__() else: print "\nSorry, but", choice, "isn't a valid choice." main() raw_input("Press enter to exit.")

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  • Writing a blocking wrapper around twisted's IRC client

    - by Andrey Fedorov
    I'm trying to write a dead-simple interface for an IRC library, like so: import simpleirc connection = simpleirc.Connect('irc.freenode.net', 6667) channel = connection.join('foo') find_command = re.compile(r'google ([a-z]+)').findall for msg in channel: for t in find_command(msg): channel.say("http://google.com/search?q=%s" % t) Working from their example, I'm running into trouble (code is a bit lengthy, so I pasted it here). Since the call to channel.__next__ needs to be returned when the callback <IRCClient instance>.privmsg is called, there doesn't seem to be a clean option. Using exceptions or threads seems like the wrong thing here, is there a simpler (blocking?) way of using twisted that would make this possible?

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  • Reliable and fast way to convert a zillion ODT files in PDF?

    - by Marco Mariani
    I need to pre-produce a million or two PDF files from a simple template (a few pages and tables) with embedded fonts. Usually, I would stay low level in a case like this, and compose everything with a library like ReportLab, but I joined late in the project. Currently, I have a template.odt and use markers in the content.xml files to fill with data from a DB. I can smoothly create the ODT files, they always look rigth. For the ODT to PDF conversion, I'm using openoffice in server mode (and PyODConverter w/ named pipe), but it's not very reliable: in a batch of documents, there is eventually a point after which all the processed files are converted into garbage (wrong fonts and letters sprawled all over the page). Problem is not predictably reproducible (does not depend on the data), happens in OOo 2.3 and 3.2, in Ubuntu, XP, Server 2003 and Windows 7. My Heisenbug detector is ticking. I tried to reduce the size of batches and restarting OOo after each one; still, a small percentage of the documents are messed up. Of course I'll write about this on the Ooo mailing lists, but in the meanwhile, I have a delivery and lost too much time already. Where do I go? Completely avoid the ODT format and go for another template system. Suggestions? Anything that takes a few seconds to run is way too slow. OOo takes around a second and it sums to 15 days of processing time. I had to write a program for clustering the jobs over several clients. Keep the format but go for another tool/program for the conversion. Which one? There are many apps in the shareware or commercial repositories for windows, but trying each one is a daunting task. Some are too slow, some cannot be run in batch without buying it first, some cannot work from command line, etc. Open source tools tend not to reinvent the wheel and often depend on openoffice. Converting to an intermediate .DOC format could help to avoid the OOo bug, but it would double the processing time and complicate a task that is already too hairy. Try to produce the PDFs twice and compare them, discarding the whole batch if there's something wrong. Although the documents look equal, I know of no way to compare the binary content. Restart OOo after processing each document. it would take a lot more time to produce them it would lower the percentage of the wrong files, and make it very hard to identify them. Go for ReportLab and recreate the pages programmatically. This is the approach I'm going to try in a few minutes. Learn to properly format bulleted lists Thanks a lot.

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  • Correct way to detect sequence parameter?

    - by noamtm
    I want to write a function that accepts a parameter which can be either a sequence or a single value. The type of value is str, int, etc., but I don't want it to be restricted to a hardcoded list. In other words, I want to know if the parameter X is a sequence or something I have to convert to a sequence to avoid special-casing later. I could do type(X) in (list, tuple) but there may be other sequence types I'm not aware of, and no common base class. -N. Edit: See my "answer" below for why most of these answers don't help me. Maybe you have something better to suggest.

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  • Extracting attribute data from a raster

    - by user308827
    Hi, I have a raster file (basically 2D array) with close to a million points. I am trying to extract a circle from the raster (and all the points that lie within the circle. Using ArcGIS is exceedingly slow for this. Can anyone suggest any image processing library that is both easy to learn and powerful and quick enough for something like this? Thanks!

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  • Pygame program that can get keyboard input with caps

    - by None
    I have a Pygame program that needs text input. The way it does this is to get keyboard input and when a key is pressed it renders that key so it is added to the screen. Essentially it acts like a text field. The problem is, when you hold shift it doesn't do anything. I relize this is because the program ignores shift input and instead writes the text if it's number is under 128. I have thought of setting a variable when shift is pressed then capitalizing if it was true, but string capitalization only woks on letters, not things like numbers or semicolons. Is there maybe a number I can add to the ascii number typed to modify it if shift is pressed, or something else?

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  • Can a CLSID be different for the same program installed on two different machines?

    - by uberjumper
    I am using comtypes to generate wrappers for a certain com library. I am having certain issues with a few things, that are not being generated properly. I can get around this by doing the missing work, manually. However can i depend on the fact that CLSID's will not change? Lets say: I install a program with the com library Foo 1.0, now i install the exact same version of that program on another PC, will the CLSID's of the interfaces change? This might be a terribly dumb question.

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  • Spaceship objects

    - by Jam
    I'm trying to make a program which creates a spaceship and I'm using the status() method to display the ship's name and fuel values. However, it doesn't seem to be working. I think I may have messed something up with the status() method. I'm also trying to make it so that I can change the fuel values, but I don't want to create a new method to do so. I think I've taken a horrible wrong turn somewhere in there. Help please! class Ship(object): def __init__(self, name="Enterprise", fuel=0): self.name=name self.fuel=fuel print "The spaceship", name, "has arrived!" def status(): print "Name: ", self.name print "Fuel level: ", self.fuel status=staticmethod(status) def main(): ship1=Ship(raw_input("What would you like to name this ship?")) fuel_level=raw_input("How much fuel does this ship have?") if fuel_level<0: self.fuel=0 else: self.fuel(fuel_level) ship2=Ship(raw_input("What would you like to name this ship?")) fuel_level2=raw_input("How much fuel does this ship have?") if fuel_level2<0: self.fuel=0 else: self.fuel(fuel_level2) ship3=Ship(raw_input("What would you like to name this ship?")) fuel_level3=raw_input("How much fuel does this ship have?") if fuel_level3<0: self.fuel=0 else: self.fuel(fuel_level3) Ship.status() main() raw_input("Press enter to exit.")

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  • Added tagging to existing model, now how does its admin work?

    - by Oli
    I wanted to add a StackOverflow-style tag input to a blog model of mine. This is a model that has a lot of data already in it. class BlogPost(models.Model): # my blog fields try: tagging.register(BlogPost) except tagging.AlreadyRegistered: pass I thought that was all I needed so I went through my old database of blog posts (this is a newly ported blog) and copied the tags in. It worked and I could display tags and filter by tag. However, I just wrote a new BlogPost and realise there's no tag field there. Reading the documentation (coincidentally, dry enough to be used as an antiperspirant), I found the TagField. Thinking this would just be a manager-style layer over the existing tagging register, I added it. It complained about there not being a Tag column. I'd rather not denormalise on tags just to satisfy create an interface for inputting them. Is there a TagManager class that I can just set on the model? tags = TagManager() # or somesuch

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  • Renaming TurboGears 2's Repoze Fields with TGAdmin

    - by William Chambers
    I've been working on renaming TurboGears 2's Repoze 'groups' field to 'roles' to free the namespace and db tables for other purposes. Also roles makes much more sense to me then groups because I have a strong Drupal background. Now I have found some of the docs to do this such as these: http://www.turbogears.org/2.1/docs/main/Auth/Customization.html#customizing-the-model-structure-assumed-by-the-quickstart http://code.gustavonarea.net/repoze.what-quickstart/#customizing-the-model-definition However these only go part of the way. I have made (I'm pretty sure at least, I've double checked a few times.) all the changes required as you can see in this diff. This seems to work fine however I've ran into a rather major issue with the TurboGears Admin system. I've tried http://turbogears.org/2.0/docs/main/Extensions/Admin/index.html and it didn't seem to make any difference, however I'm not 100% sure I did it correctly. The problem occurs when I attempt to go to localhost/admin/permissions/. It causes a Internal Server Error and outputs the following error. http://pastebin.com/YWMH3SiU This error does not happen on the Roles/Users pages and the permissions /edit/1 also works. I'm running kubuntu 10.04 with TG 2.1b2. (I'm running the beta mostly for easier mako support which is really important.) Any help would be very appreciated.

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  • app-engine-patch and "object_detail" view didn't work

    - by Hugh
    Hi(Sorry for my ugly english) When I calling the flowing: http://192.168.62.90:8000/blog/entry/?agphdXR1bW4xOTEychALEgpibG9nX2VudHJ5GCYM will use this: urlpatterns = patterns('', (r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT, 'show_indexes': True}), (r'^$', list_detail.object_list, entry_info), (r'^entry/(?P<object_id>.*)$', list_detail.object_detail, {'queryset': Entry.all(), 'template_name': 'sample_test_page.html'}), ) and the error is: Generic view must be called with either an object_id or a slug/slug_field. I want to know why this didn't work for me.

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  • regular expression to extract @name symbols from tweet

    - by Joey
    Hello All, I would like to use regular expression to extract only @patrick @michelle from the following sentence: @patrick @michelle we having diner @home tonight do you want to join? Note: @home should not be include in the result because, it is not at beginning of the sentence nor is followed by another @name. Any solution, tip, comments will be really appreciated.

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  • Configuration files for C in linux

    - by James
    Hi, I have an executable that run time should take configuration parameters from a script file. This way I dont need to re-compile the code for every configuration change. Right now I have all the configuration values in a .h file. Everytime I change it i need to re-compile. The platform is C, gcc under Linux. What is the best solution for this problem? I looked up on google and so XML, phthon and Lua bindings for C. Is using a separate scripting language the best approach? If so, which one would you recommend for my need? Thanks

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  • Django queries Especial Caracters

    - by Jorge Machado
    Hi, I Working on location from google maps and using django to. My question is: I have a String in request.GET['descricao'] lets say it contains "Via rapida". In my database i have store = "Via Rápida" i'm doing : local = Local.objects.filter(name__icontains=request.GET['descricao']) with that i can get everthing fine like "Via Rapida" but the result that have "Via rápida" never get match in the query (ASCI caracter may be ?) what must i do given a string "Via rapida" match "via rápida" and "via rapida" ? Regular Expressions ? how ? Thanks

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  • How to model a social news feed on Google App Engine

    - by PEZ
    We want to implement a "News feed" where a user can see messages broadcasted by her friends, sorted with newest message first. But the feed should reflect changes in her friends list. (If she adds new friends, messages from those should be included in the feed, and if she removes friends their messages should not be included.) If we use the pubsub-test example and attach a recipient list to each message this means a lot of manipulation of the message recipients lists when users connect and disconnect friends. We first modeled publish-subscribe "fan out" using conventional RDBMS thinking. It seemed to work at first, but then, since the IN operator works the way it does, we quickly realized we couldn't continue on that path. We found Brett Slatkin's presentation from last years Google I/O and we have now watched it a few times but it isn't clear to us how to do it with "dynamic" recipient lists. What we need are some hints on how to "think" when modeling this.

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  • Refining data stored in SQLite - how to join several contacts?

    - by Krab
    Problem background Imagine this problem. You have a water molecule which is in contact with other molecules (if the contact is a hydrogen bond, there can be 4 other molecules around my water). Like in the following picture (A, B, C, D are some other atoms and dots mean the contact). A B . . O / \ H H . . C D I have the information about all the dots and I need to eliminate the water in the center and create records describing contacts of A-C, A-D, A-B, B-C, B-D, and C-D. Database structure Currently, I have the following structure in the database: Table atoms: "id" integer PRIMARY KEY, "amino" char(3) NOT NULL, (HOH for water or other value) other columns identifying the atom Table contacts: "acceptor_id" integer NOT NULL, (the atom near to my hydrogen, here C or D) "donor_id" integer NOT NULL, (here A or B) "directness" char(1) NOT NULL, (this should be D for direct and W for water-mediated) other columns about the contact, such as the distance Current solution (insufficient) Now, I'm going through all the contacts which have donor.amino = "HOH". In this sample case, this would select contacts from C and D. For each of these selected contacts, I look up contacts having the same acceptor_id as is the donor_id in the currently selected contact. From this information, I create the new contact. At the end, I delete all contacts to or from HOH. This way, I am obviously unable to create C-D and A-B contacts (the other 4 are OK). If I try a similar approach - trying to find two contacts having the same donor_id, I end up with duplicate contacts (C-D and D-C). Is there a simple way to retrieve all six contacts without duplicates? I'm dreaming about some one page long SQL query which retrievs just these six wanted rows. :-) It is preferable to conserve information about who is donor where possible, but not strictly necessary. Big thanks to all of you who read this question to this point.

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  • How to exit an if clause

    - by Roman Stolper
    What sorts of methods exist for prematurely exiting an if clause? There are times when I'm writing code and want to put a break statement inside of an if clause, only to remember that those can only be used for loops. Lets take the following code as an example: if some_condition: ... if condition_a: # do something # and then exit the outer if block ... if condition_b: # do something # and then exit the outer if block # more code here I can think of one way to do this: assuming the exit cases happen within nested if statements, wrap the remaining code in a big else block. Example: if some_condition: ... if condition_a: # do something # and then exit the outer if block else: ... if condition_b: # do something # and then exit the outer if block else: # more code here The problem with this is that more exit locations mean more nesting/indented code. Alternatively, I could write my code to have the if clauses be as small as possible and not require any exits. Does anyone know of a good/better way to exit an if clause? If there are any associated else-if and else clauses, I figure that exiting would skip over them.

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  • XML file as model for django project

    - by Ankur Chauhan
    Hi, I have a XML file that is managed by other programs, I am writing a web service such that users are able to query this file. In essence i am using a xml based database instead of using sql as the model database in Django. how do i do this? all the tutorials that i find use a sql database in the backend. is there a way to use the xml file as a database.

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  • In Django : How to serialize dict object to json ?

    - by Rohit
    I have this very basic problem, >>> serializers.serialize("json", {'a':1}) Traceback (most recent call last): File "<console>", line 1, in <module> File "/usr/lib/pymodules/python2.6/django/core/serializers/__init__.py", line 87, in serialize s.serialize(queryset, **options) File "/usr/lib/pymodules/python2.6/django/core/serializers/base.py", line 40, in serialize for field in obj._meta.local_fields: AttributeError: 'str' object has no attribute '_meta' >>> How can this be done ? Thanks in advance !

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