Search Results

Search found 14399 results on 576 pages for 'python noob'.

Page 378/576 | < Previous Page | 374 375 376 377 378 379 380 381 382 383 384 385  | Next Page >

  • methods of metaclasses on class instances.

    - by Stefano Borini
    I was wondering what happens to methods declared on a metaclass. I expected that if you declare a method on a metaclass, it will end up being a classmethod, however, the behavior is different. Example >>> class A(object): ... @classmethod ... def foo(cls): ... print "foo" ... >>> a=A() >>> a.foo() foo >>> A.foo() foo However, if I try to define a metaclass and give it a method foo, it seems to work the same for the class, not for the instance. >>> class Meta(type): ... def foo(self): ... print "foo" ... >>> class A(object): ... __metaclass__=Meta ... def __init__(self): ... print "hello" ... >>> >>> a=A() hello >>> A.foo() foo >>> a.foo() Traceback (most recent call last): File "<stdin>", line 1, in <module> AttributeError: 'A' object has no attribute 'foo' What's going on here exactly ? edit: bumping the question

    Read the article

  • How to display multiple images?

    - by misterwebz
    I'm trying to get multiple image paths from my database in order to display them, but it currently doesn't work. Here's what i'm using: def get_image(self, userid, id): image = meta.Session.query(Image).filter_by(userid=userid) permanent_file = open(image[id].image_path, 'rb') if not os.path.exists(image.image_path): return 'No such file' data = permanent_file.read() permanent_file.close() response.content_type = guess_type(image.image_path)[0] or 'text/plain' return data I'm getting an error regarding this part: image[id].image_path What i want is for Pylons to display several jpg files on 1 page. Any idea how i could achieve this?

    Read the article

  • How to give points for each indices of list

    - by Eric Jung
    def voting_borda(rank_ballots): '''(list of list of str) -> tuple of (str, list of int) The parameter is a list of 4-element lists that represent rank ballots for a single riding. The Borda Count is determined by assigning points according to ranking. A party gets 3 points for each first-choice ranking, 2 points for each second-choice ranking and 1 point for each third-choice ranking. (No points are awarded for being ranked fourth.) For example, the rank ballot shown above would contribute 3 points to the Liberal count, 2 points to the Green count and 1 point to the CPC count. The party that receives the most points wins the seat. Return a tuple where the first element is the name of the winning party according to Borda Count and the second element is a four-element list that contains the total number of points for each party. The order of the list elements corresponds to the order of the parties in PARTY_INDICES.''' #>>> voting_borda([['GREEN','NDP', 'LIBERAL', 'CPC'], ['GREEN','CPC','LIBERAL','NDP'], ['LIBERAL','NDP', 'CPC', 'GREEN']]) #('GREEN',[4, 6, 5, 3]) list_of_party_order = [] for sublist in rank_ballots: for party in sublist[0]: if party == 'GREEN': GREEN_COUNT += 3 elif party == 'NDP': NDP_COUNT += 3 elif party == 'LIBERAL': LIBERAL_COUNT += 3 elif party == 'CPC': CPC_COUNT += 3 for party in sublist[1]: if party == 'GREEN': GREEN_COUNT += 2 elif party == 'NDP': NDP_COUNT += 2 elif party == 'LIBERAL': LIBERAL_COUNT += 2 elif party == 'CPC': CPC_COUNT += 2 for party in sublist[2]: if party == 'GREEN': GREEN_COUNT += 1 elif party == 'NDP': NDP_COUNT += 1 elif party == 'LIBERAL': LIBERAL_COUNT += 1 elif party == 'CPC': CPC_COUNT += 1 I don't know how I would give points for each indices of the list MORE SIMPLY. Can someone please help me? Without being too complicated. Thank you!

    Read the article

  • How to convert string "0671" or "0x45" into integer form with 0 and 0x in the beginning.

    - by Harshit Sharma
    I wanted to make my own encryption algorithm and decryption algorithm , encryption algorithm works fine and converts ascii value of the characters into alternate hexadecimal and octal representations. But when I tried decryption, problem occured as it return int('0671') = 671, as 0671 is string type in the following code. Is there a method to convert "ox56" into integer form?????? NOTE: Following string is alternate octal and hexa of ascii value of char. ///////////////DECRYPTION/////// l="01630x7401620x6901560x67" f=len(l) k=0 d=0 x=[] for i in range(0,f,4): g=l[i:i+4] print g k=k+1 if(k%2==0): p=g print p else: p=int(g) print p

    Read the article

  • Why is django.test.client.Client not keeping me logged in.

    - by Mystic
    I'm using django.test.client.Client to test whether some text shows up when a user is logged in. However, I the Client object doesn't seem to be keeping me logged in. This test passes if done manually with Firefox but not when done with the Client object. class Test(TestCase): def test_view(self): user.set_password(password) user.save() client = self.client # I thought a more manual way would work, but no luck # client.post('/login', {'username':user.username, 'password':password}) login_successful = client.login(username=user.username, password=password) # this assert passes self.assertTrue(login_successful) response = client.get("/path", follow=True) #whether follow=True or not doesn't seem to work self.assertContains(response, "needle" ) When I print response it returns the login form that is hidden by: {% if not request.user.is_authenticated %} ... form ... {% endif %} This is confirmed when I run ipython manage.py shell. The problem seems to be that the Client object is not keeping the session authenticated.

    Read the article

  • Assigning a material in Blender with a script

    - by Narcolapser
    Question: How do you assign a material with a script to an object in blender? Info: I have this script to import a proprietary model type of mine that is basically a star map with object consisting of a single vertex. in order to make them look like stars and be visible they are all going to have a halo material assigned to them. I'm figuring out how to make this material and give it the values just fine, but I can't seem to get it to assign. I tried the most obvious thing which was: objectName.setMaterial(materialName) but that did nothing. and when i would take an object that had a material and call the getMaterial function on it, it would return nothing. there is something I'm missing here, can some one shed some light on it? Thanks. ~TA

    Read the article

  • Segment string into array, regex?

    - by Hanpan
    I have a string which looks like this: "[segment1][segment2][segment2]" What I'd like is to be able to split the string into an array, so I'd end up with: Array[0] = "segment1", Array[1] = "segment2", Array[2] = "segment3" I've tried using the string split function, but it doesn't seem to do exactly what I want. I was wondering if anyone has some regex which might help me out? Thanks in advance

    Read the article

  • Distance between numpy arrays, columnwise

    - by Jaapsneep
    I have 2 arrays in 2D, where the column vectors are feature vectors. One array is of size F x A, the other of F x B, where A << B. As an example, for A = 2 and F = 3 (B can be anything): arr1 = np.array( [[1, 4], [2, 5], [3, 6]] ) arr2 = np.array( [[1, 4, 7, 10, ..], [2, 5, 8, 11, ..], [3, 6, 9, 12, ..]] ) I want to calculate the distance between arr1 and a fragment of arr2 that is of equal size (in this case, 3x2), for each possible fragment of arr2. The column vectors are independent of each other, so I believe I should calculate the distance between each column vector in arr1 and a collection of column vectors ranging from i to i + A from arr2 and take the sum of these distances (not sure though). Does numpy offer an efficient way of doing this, or will I have to take slices from the second array and, using another loop, calculate the distance between each column vector in arr1 and the corresponding column vector in the slice?

    Read the article

  • Is there a functional way to do this?

    - by Ishpeck
    def flattenList(toFlatten): final=[] for el in toFlatten: if isinstance(el, list): final.extend(flattenList(el)) else: final.append(el) return final When I don't know how deeply the lists will nest, this is the only way I can think to do this. 2

    Read the article

  • What can I use the Google App Engine for?

    - by Sergio Boombastic
    This question possibly doesn't belong here. We'll see how the answers pan out, if this doesn't belong here please move it to where it belongs. I'm following the getting started guide for Google App Engine, and I'm seeing what it can and can't do. Basically, I'm seeing it's very similar to an MVC pattern. You create your model, then create a View that uses that Model to display information. Not only that, but it uses a controller of some kind in this fashion: application = webapp.WSGIApplication( [('/', MainPage)], debug=True) My question is, why would you use this Google App Engine if it's the same as using a number of other MVC frameworks? Is the only benefit you gain the load balancing being handled by Google automagically? What is a good example of something you would need the App Engine for? I'm trying to learn, so thanks for the discussion.

    Read the article

  • How to create a HTML world map with GeoDjango ?

    - by pierre-guillaume-degans
    The GeoDjango tutorial explains how to insert world borders into a spatial database. I would like to create a world Map in HTML with these data, with both map and area tags. Something like that. I just don't know how to retrieve the coordinates for each country (required for the area's coords attribute). from world.models import WorldBorders for country in WorldBorders.objects.all(): print u'<area shape="poly" title="%s" alt="%s" coords="%s" />' % (v.name, v.name, "???") Thanks !

    Read the article

  • Check if something is a list

    - by 8EM
    What is the easiest way to check if something is a list? A method doSomething has the parameters a and b. In the method, it will loop through the list a and do something. I'd like a way to make sure a is a list, before looping through - thus avoiding an error or the unfortunate circumstance of passing in a string then getting back each letter. This question must have been asked before - however my googles failed me. Cheers.

    Read the article

  • django join-like expansion of queryset

    - by jimbob
    I have a list of Persons each which have multiple fields that I usually filter what's upon, using the object_list generic view. Each person can have multiple Comments attached to them, each with a datetime and a text string. What I ultimately want to do is have the option to filter comments based on dates. class Person(models.Model): name = models.CharField("Name", max_length=30) ## has ~30 other fields, usually filtered on as well class Comment(models.Model): date = models.DateTimeField() person = models.ForeignKey(Person) comment = models.TextField("Comment Text", max_length=1023) What I want to do is get a queryset like Person.objects.filter(comment__date__gt=date(2011,1,1)).order_by('comment__date') send that queryset to object_list and be able to only see the comments ordered by date with only so many objects on a page. E.g., if "Person A" has comments 12/3/11, 1/2/11, 1/5/11, "Person B" has no comments, and person C has a comment on 1/3, I would see: "Person A", 1/2 - comment "Person C", 1/3 - comment "Person A", 1/5 - comment I would strongly prefer not to have to switch to filtering based on Comments.objects.filter(), as that would make me have to largely repeat large sections of code in the both the view and template. Right now if I tried executing the following command, I will get a queryset returning (PersonA, PersonC, PersonA), but if I try rendering that in a template each persons comment_set will contain all their comments even if they aren't in the date range. Ideally they're would be some sort of functionality where I could expand out a Person queryset's comment_set into a larger queryset that can be sorted and ordered based on the comment and put into a object_list generic view. This normally is fairly simple to do in SQL with a JOIN, but I don't want to abandon the ORM, which I use everywhere else.

    Read the article

  • Django - foreignkey problem

    - by realshadow
    Hey, Imagine you have this model: class Category(models.Model): node_id = models.IntegerField(primary_key = True) type_id = models.IntegerField(max_length = 20) parent_id = models.IntegerField(max_length = 20) sort_order = models.IntegerField(max_length = 20) name = models.CharField(max_length = 45) lft = models.IntegerField(max_length = 20) rgt = models.IntegerField(max_length = 20) depth = models.IntegerField(max_length = 20) added_on = models.DateTimeField(auto_now = True) updated_on = models.DateTimeField(auto_now = True) status = models.IntegerField(max_length = 20) node = models.ForeignKey(Category_info, verbose_name = 'Category_info', to_field = 'node_id' The important part is the foreignkey. When I try: Category.objects.filter(type_id = type_g.type_id, parent_id = offset, status = 1) I get an error that get returned more than category, which is fine, because it is supposed to return more than one. But I want to filter the results trough another field, which would be type id (from the second Model) Here it is: class Category_info(models.Model): objtree_label_id = models.AutoField(primary_key = True) node_id = models.IntegerField(unique = True) language_id = models.IntegerField() label = models.CharField(max_length = 255) type_id = models.IntegerField() The type_id can be any number from 1 - 5. I am desparately trying to get only one result where the type_id would be number 1. Here is what I want in sql: SELECT n.*, l.* FROM objtree_nodes n JOIN objtree_labels l ON (n.node_id = l.node_id) WHERE n.type_id = 15 AND n.parent_id = 50 AND l.type_id = 1 Any help is GREATLY appreciated. Regards

    Read the article

  • Looping through a directory on the web and displaying its contents (files and other directories) via

    - by al jaffe
    In the same vein as http://stackoverflow.com/questions/2593399/process-a-set-of-files-from-a-source-directory-to-a-destination-directory-in-pyth I'm wondering if it is possible to create a function that when given a web directory it will list out the files in said directory. Something like... files[] for file in urllib.listdir(dir): if file.isdir: # handle this as directory else: # handle as file I assume I would need to use the urllib library, but there doesn't seem to be an easy way of doing this, that I've seen at least.

    Read the article

  • How different protocols interact with eachother in Twisted

    - by stsupermouse
    The scenario I want two different protocols interact with each other is as below: A and B is two different protocols. First A will interact with the server and retrieve some values. Only after A finishes retrieving the values , B will start to interact with the server. Now my problem is that is there an elegant way to initial B when A retrieves the values. Currently I just initial B in A's data process function. But i don't think that this is an elegant way. What I mean an elegant way is that the initialization of B is done by a flow controller or something like that, but not another protocol. Is there an elegant way? such using defered or any other things. I'm just new to twisted, not knowing very much about defered.... Thank you very much!

    Read the article

  • remove border of a gtk.button

    - by spanctus
    Hi, I want to remove the border of the gtk.button, but i Don't know how to do it. I tried with : button = gtk.Button() button.set_style("inner-border",0) but i have an error : the property doesn't exist. I tried too to create a new gtk.Style and use it for the button, but same error. Anyone has an idea ? Thanks

    Read the article

  • Django save method

    - by Marijus
    So I have a model with a FileField for excel spreadsheet. What I need to do this add another column in this spreadsheet, in each row let user pick from a drop-down list then save it and display it in html. All the picking and uploading will happen through the admin interface. So I have figured out way how to display a spreadsheet in html, however I have no idea how to write this save method. I could really use some hints and tips..

    Read the article

  • Get wrong PATH_INFO after rewriting in lighttpd

    - by Satoru.Logic
    In my lighttpd config file, I have a rewrite rule like this: $HTTP["host"] == "sub.example.com" { url.rewrite = ( "^/(.*)" => "/sub/$1" ) } So when a user visits http://sub.example.com, she's actually visiting http://example.com/sub. The problem is that the PATH_INFO seems wrong, URL: http://sub.example.com/extra PATH_INFO: expected: /extra what I get: /sub/extra Now whenever I call request.get_path(), it returns something like http://sub.example.com/sub/extra, which is not what I want. Of course, I can just override the get_path method of the request class, but I wonder if there is a simpler way like changing the lighttpd config?

    Read the article

  • App-Engine Parse a UrlFetch UTF-8 encoded stream

    - by Davidrd91
    I am trying to parse an XML from a URL using the xml.sax parser. I know there are other libraries to use but coming from Java this is the one I am most familiar with and seems the least complicated to me. The code I'm using to parse is as follows: parser = xml.sax.make_parser() handler = MangaHandler() parser.setContentHandler(handler) url = urlfetch.Fetch('http://www.mangapanda.com/alphabetical', allow_truncated = False, follow_redirects = False, deadline = False) xml.sax.parseString(url.content, handler) This returns a SaxException (invalid token) once the parser reaches the first & sign: SAXParseException: <unknown>:582:34: not well-formed (invalid token) Because urlfetch returns a string and not a stream I cannot use the parse() (which only works with streams) and am left to use parseString() instead. To see if parsing as a stream would fix this I tried: parser.parse(io.StringIO(url.content).encode('utf-8')) but this returns: TypeError: initial_value must be unicode or None, not str I have also tried to use the urllib2 libraries which do return a stream instead of urlfetch but the file is too large and is automatically truncated, leaving me with missing data. Any Sort of work-around for this would be greatly appreciated as I've spent days getting around one obstacle just to be stopped by another.

    Read the article

  • All minimum spanning trees implementation

    - by russtbarnacle
    I've been looking for an implementation (I'm using networkx library.) that will find all the minimum spanning trees (MST) of an undirected weighted graph. I can only find implementations for Kruskal's Algorithm and Prim's Algorithm both of which will only return a single MST. I've seen papers that address this problem (such as http://fano.ics.uci.edu/cites/Publication/Epp-TR-95-50.html) but my head tends to explode someway through trying to think how to translate it to code. In fact i've not been able to find an implementation in any language!

    Read the article

  • pandas read rotated csv files

    - by EricCoding
    Is there any function in pandas that can directly read a rotated csv file? To be specific, the header information in the first col instead of the first row. For example: A 1 2 B 3 5 C 6 7 and I would like the final DataFrame this way A B C 1 3 5 2 5 7 Of corse we can get around this problem using some data wangling techniques like transpose and slicing. I am wondering there should be a quick way in API but I could not find it.

    Read the article

< Previous Page | 374 375 376 377 378 379 380 381 382 383 384 385  | Next Page >