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  • Process not Listed by PS or in /proc/

    - by Hammer Bro.
    I'm trying to figure out how to operate a rather large Java program, 'prog'. If I go to its /bin/ dir and configure its setenv.sh and prog.sh to use local directories and my current user account. Then I try to run it via "./prog.sh start". Here are all the relevant bits of prog.sh: USER=(my current account) _CMD="/opt/jdk/bin/java -server -Xmx768m -classpath "${CLASSPATH}" -jar "${DIR}/prog.jar"" case "${ACTION}" in start) nohup su ${USER} -c "exec ${_CMD} >>${_LOGFILE} 2>&1" >/dev/null & echo $! >${_PID} echo "Prog running. PID="`cat ${_PID}` ;; stop) PID=`cat ${_PID} 2>/dev/null` echo "Shutting down prog: ${PID} kill -QUIT ${PID} 2>/dev/null kill ${PID} 2>/dev/null kill -KILL ${PID} 2>/dev/null rm -f ${_PID} echo "STOPPED `date`" >>${_LOGFILE} ;; When I actually do ./prog.sh start, it starts. But I can't find it at all on the process list. Nor can I kill it manually, using the same command the shell script uses. But I can tell it's running, because if I do ./prog.sh stop, it stops (and some temporary files elsewhere clean themselves out). ./prog.sh start Prog running. PID=1234 ps eaux | grep 1234 ps eaux | grep -i prog.jar ps eaux >> pslist.txt (It's not there either by PID or any clear name I can find: prog, java or jar.) cd /proc/1234/ -bash: cd: /proc/1234/: No such file or directory kill -QUIT 1234 kill 1234 kill -KILL 1234 -bash: kill: (1234) - No such process ./prog.sh stop Shutting down prog: 1234 As far as I can tell, the process is running yet not in any way listed by the system. I can't find it in ps or /proc/, nor can I kill it. But the shell script can still stop it properly. So my question is, how can something like this happen? Is the process supremely hidden, actually unlisted, or am I just missing it in some fashion? I'm trying to figure out what makes this program tick, and I can barely prove that it's ticking! Edit: ps eu | grep prog.sh (after having restarted; so random PID) 50038 19381 0.0 0.0 4412 632 pts/3 S+ 16:09 0:00 grep prog.sh HOSTNAME=machine.server.com TERM=vt100 SHELL=/bin/bash HISTSIZE=1000 SSH_CLIENT=::[STUFF] 1754 22 CVSROOT=:[DIR] SSH_TTY=/dev/pts/3 ANT_HOME=/opt/apache-ant-1.7.1 USER=[USER] LS_COLORS=[COLORS] SSH_AUTH_SOCK=[DIR] KDEDIR=/usr MAIL=[DIR] PATH=[DIRS] INPUTRC=/etc/inputrc PWD=[PWD] JAVA_HOME=/opt/jdk1.6.0_21 LANG=en_US.UTF-8 SSH_ASKPASS=/usr/libexec/openssh/gnome-ssh-askpass M2_HOME=/opt/apache-maven-2.2.1 SHLVL=1 HOME=[~] LOGNAME=[USER] SSH_CONNECTION=::[STUFF] LESSOPEN=|/usr/bin/lesspipe.sh %s G_BROKEN_FILENAMES=1 _=/bin/grep OLDPWD=[DIR] I just realized that the stop) part of prog.sh isn't actually a guarantee that the process it claims to be stopping is running -- it just tries to kill the PID and suppresses all output then deletes the temporary file and manually inserts STOPPED into the log file. So I'm no longer so certain that the process is always running when I ps for it, although the code sample above indicates that it at least runs erratically. I'll continue looking into this undocumented behemoth when I return to work tomorrow.

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  • PyDev and Django: PyDev breaking Django shell?

    - by Rosarch
    I've set up a new project, and populated it with simple models. (Essentially I'm following the tut.) When I run python manage.py shell on the command line, it works fine: >python manage.py shell Python 2.6.4 (r264:75708, Oct 26 2009, 08:23:19) [MSC v.1500 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license" for more information. (InteractiveConsole) >>> from mysite.myapp.models import School >>> School.objects.all() [] Works great. Then, I try to do the same thing in Eclipse (using a Django project that is composed of the same files.) Right click on mysite project Django Shell with Django environment This is the output from the PyDev Console: >>> import sys; print('%s %s' % (sys.executable or sys.platform, sys.version)) C:\Python26\python.exe 2.6.4 (r264:75708, Oct 26 2009, 08:23:19) [MSC v.1500 32 bit (Intel)] >>> >>> from django.core import management;import mysite.settings as settings;management.setup_environ(settings) 'path\\to\\mysite' >>> from mysite.myapp.models import School >>> School.objects.all() Traceback (most recent call last): File "<console>", line 1, in <module> File "C:\Python26\lib\site-packages\django\db\models\query.py", line 68, in __repr__ data = list(self[:REPR_OUTPUT_SIZE + 1]) File "C:\Python26\lib\site-packages\django\db\models\query.py", line 83, in __len__ self._result_cache.extend(list(self._iter)) File "C:\Python26\lib\site-packages\django\db\models\query.py", line 238, in iterator for row in self.query.results_iter(): File "C:\Python26\lib\site-packages\django\db\models\sql\query.py", line 287, in results_iter for rows in self.execute_sql(MULTI): File "C:\Python26\lib\site-packages\django\db\models\sql\query.py", line 2368, in execute_sql cursor = self.connection.cursor() File "C:\Python26\lib\site-packages\django\db\backends\__init__.py", line 81, in cursor cursor = self._cursor() File "C:\Python26\lib\site-packages\django\db\backends\sqlite3\base.py", line 170, in _cursor self.connection = Database.connect(**kwargs) OperationalError: unable to open database file What am I doing wrong here?

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  • Django 1.4.1 error loading MySQLdb module when attempting 'python manage.py shell'

    - by Paul
    I am trying to set up MySQL, and can't seem to be able to enter the Django manage.py shell interpreter. Getting the output below: rrdhcp-10-32-44-126:django pavelfage$ python manage.py shell Traceback (most recent call last): File "manage.py", line 10, in <module> execute_from_command_line(sys.argv) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 443, in execute_from_command_line utility.execute() File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 382, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 196, in run_from_argv self.execute(*args, **options.__dict__) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 232, in execute output = self.handle(*args, **options) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 371, in handle return self.handle_noargs(**options) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/commands/shell.py", line 45, in handle_noargs from django.db.models.loading import get_models File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/__init__.py", line 40, in <module> backend = load_backend(connection.settings_dict['ENGINE']) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/__init__.py", line 34, in __getattr__ return getattr(connections[DEFAULT_DB_ALIAS], item) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/utils.py", line 92, in __getitem__ backend = load_backend(db['ENGINE']) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/utils.py", line 24, in load_backend return import_module('.base', backend_name) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/utils/importlib.py", line 35, in import_module __import__(name) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/backends/mysql/base.py", line 16, in <module> raise ImproperlyConfigured("Error loading MySQLdb module: %s" % e) django.core.exceptions.ImproperlyConfigured: Error loading MySQLdb module: No module named _mysql Any suggestions really appreciated.

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  • Best Practice for Shell Layout and Switching Views - Prism, SL4, On Demand Load Modules

    - by kmacmahon
    I am learning Prism, and I have a question on the best approach for the main Shell. Assuming the Shell has 2 regions: Toolbar, Main. The toolbar has 3 main buttons that each represent a different On Demand Load Module. Each of these modules currently register themselves as fitting in the Main Region. When I click one of the buttons I want to do the following: Notify any active view that its switching, with an option to cancel if there is a pending action still required. This might cascade to child views. If the action isn't cancelled then load the on demand module if it has not yet been loaded, else activate it within the region. Should these three modules all fit in the same Region or should my shell have 3 regions defined within content presenters? One of the areas I got stuck on was that when you register a view from the Module Initialize, it doesn't get added with a strongly typed name, so when I tried to determine if my view was already added to the region with GetView(viewname) it always returns null, so I end up adding another view to the region.

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  • emacs: Inferior-mode python-shell appears "lagged"

    - by Begbie00
    Hi all - I'm a Python(3.1.2)/emacs(23.2) newbie teaching myself tkinter using the pythonware tutorial found here. Relevant code is pasted below the question. Question: when I click the Hello button (which should call the say_hi function) why does the inferior python shell (i.e. the one I kicked off with C-c C-c) wait to execute the say_hi print function until I either a) click the Quit button or b) close the root widget down? When I try the same in IDLE, each click of the Hello button produces an immediate print in the IDLE python shell, even before I click Quit or close the root widget. Is there some quirk in the way emacs runs the Python shell (vs. IDLE) that causes this "lagged" behavior? I've noticed similar emacs lags vs. IDLE as I've worked through Project Euler problems, but this is the clearest example I've seen yet. FYI: I use python.el and have a relatively clean init.el... (setq python-python-command "d:/bin/python31/python") is the only line in my init.el. Thanks, Mike === Begin Code=== from tkinter import * class App: def __init__(self,master): frame = Frame(master) frame.pack() self.button = Button(frame, text="QUIT", fg="red", command=frame.quit) self.button.pack(side=LEFT) self.hi_there = Button(frame, text="Hello", command=self.say_hi) self.hi_there.pack(side=LEFT) def say_hi(self): print("hi there, everyone!") root = Tk() app = App(root) root.mainloop()

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  • How to avoid shell execution of a Process?

    - by adeel amin
    When I start a process like process = Runtime.getRuntime().exec("gnome-terminal");, it starts shell execution. I want to stop shell execution and want to redirect I/O from process, can anybody tell how I can do this? My code is: public void start_process() { try { process= Runtime.getRuntime().exec("gnome-terminal"); pw= new PrintWriter(process.getOutputStream(),true); br=new BufferedReader(new InputStreamReader(process.getInputStream())); err=new BufferedReader(new InputStreamReader(process.getErrorStream())); } catch (Exception ioe) { System.out.println("IO Exception-> " + ioe); } } public void execution_command() { if(check==2) { try { boolean flag=thread.isAlive(); if(flag==true) thread.stop(); Thread.sleep(30); thread = new MyReader(br,tbOutput,err,check); thread.start(); }catch(Exception ex){ JOptionPane.showMessageDialog(null, ex.getMessage()+"1"); } } else { try { Thread.sleep(30); thread = new MyReader(br,tbOutput,err,check); thread.start(); check=2; }catch(Exception ex){ JOptionPane.showMessageDialog(null, ex.getMessage()+"1"); } } } private void jButton3ActionPerformed(java.awt.event.ActionEvent evt) { // TODO add your handling code here: command=tfCmd.getText().toString().trim(); pw.println(command); execution_command(); } When I enter some command in textfield and press execute button, nothing is displayed on my output textarea, how I can stop shell execution and redirect input and output?

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  • Restarting shell script with &disown using Monit

    - by Solas Admin
    I have a shell script that runs a C++ backend mail system (PluginHandler). I need to monitor this process in Monit and restart it if it fails. The script: export LD_LIBRARY_PATH=/usr/local/lib/:/CONFIDENTAL/CONFIDENTAL/Common/ cd PluginHandler/ ./PluginHandler This script does not have a PID file and we run this script by executing ./rundaemon.sh &disown ./pluginhandler starts the process and starts logging into /etc/output/output.log I stop the process by identifying the process ID with [ps -f | grep PluginHandler] and then killing the process. I can check the process in Monit just fine, but I think Monit is starting the process if it is not running but it can't do &disown so the process ends as soon as it starts. This is the code in the monitrc file for checking this process: check process Backend matching "PluginHandler" if not exist then alert start "PATH/TO/SCRIPT/rundaemon.sh &disown" alert [email protected] only on {timeout} with mail-format {subject: "[BLAH"} I tried to stop the script from terminating by modifying the script like the following but this does not work either. export LD_LIBRARY_PATH=/usr/local/lib/:/home/CONFIDENTAL/production/CONFIDENTAL/Common/ cd PluginHandler/ (nohup ./PluginHandler &) return Any help to write a proper Monit rules to resolve this issue would be greatly appreciated :)

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  • Run a shell script using cron

    - by Blanca
    Hi! I have this FeedIndexer.sh: #!/bin/sh java -jar FeedIndexer.jar Just to run FeedIndexer.jar which is in the same directory as the .sh, I would like to run it using crontab, so I did this: # /etc/crontab: system-wide crontab # Unlike any other crontab you don't have to run the `crontab' # command to install the new version when you edit this file # and files in /etc/cron.d. These files also have username fields, # that none of the other crontabs do. SHELL=/bin/sh PATH=/usr/local/sbin:/usr/local/bin:/sbin:/bin:/usr/sbin:/usr/bin # m h dom mon dow user command 17 * * * * root cd / && run-parts --report /etc/cron.hourly 25 6 * * * root test -x /usr/sbin/anacron || ( cd / && run-parts --report /etc/cron.daily ) 47 6 * * 7 root test -x /usr/sbin/anacron || ( cd / && run-parts --report /etc/cron.weekly ) 52 6 1 * * root test -x /usr/sbin/anacron || ( cd / && run-parts --report /etc/cron.monthly ) 01 01 * * * root run-parts --report /home/slosada/workspace/FeedIndexer/target/FeedIndexer.sh # But I don't know how to run it. Have i made any mistake?? Thank you!

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  • run script as another user from a root script with no tty stdin

    - by viktor tron
    Using CentOs, I want to run a script as user 'training' as a system service. I use daemontools to monitor the process, which needs a launcher script that is run as root and has no tty standard in. Below I give my four different attempts which all fail. : #!/bin/bash exec >> /var/log/training_service.log 2>&1 setuidgid training training_command This last line is not good enough since for training_command, we need environment for trqaining user to be set. : su - training -c 'training_command' This looks like it (http://serverfault.com/questions/44400/run-a-shell-script-as-a-different-user) but gives 'standard in must be tty' as su making sure tty is present to potentially accept password. I know I could make this disappear by modifying /etc/sudoers (a la http://superuser.com/questions/119376/bash-su-script-giving-an-error-standard-in-must-be-a-tty) but i am reluctant and unsure of consequences. : runuser - training -c 'training_command' This one gives runuser: cannot set groups: Connection refused. I found no sense or resolution to this error. : ssh -p100 training@localhost 'source $HOME/.bashrc; training_command' This one is more of a joke to show desparation. Even this one fails with Host key verification failed. (the host key IS in known_hosts, etc). Note: all of 2,3,4 work as they should if I run the wrapper script from a root shell. problems only occur if the system service monitor (daemontools) launches it (no tty terminal I guess). I am stuck. Is this something so hard to achieve? I appreciate all insight and guidance to best practice. (this has also been posted on superuser: http://superuser.com/questions/434235/script-calling-script-as-other-user)

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  • How can I disable the CTRL-ALT-DEL key combination completely on XP/Vista/7?

    - by Travesty3
    I have been googling extensively to figure this out, and nobody seems to be able to give a direct answer. Let me start by saying that I'm NOT talking about requiring CTRL-ALT-DEL to enter logon information. I'm working on a golf simulator program which is used at golf centers. I need the ability to completely disable the CTRL-ALT-DEL key sequence so that the golf center customers can't get out of the program and access the computer at all. I realize there are other key combinations that need to be handled as well, we already have this entire feature working in XP, but we're going to be switching to Windows 7 soon, and CTRL-ALT-DEL is the only one that doesn't seem to work in Win7. I'd really like an all-around solution if at all possible. This same program may also be installed on a client's personal computer for an in-home golf simulator, but the computers that really need this feature (golf center computers) are provided to the golf center by us, so would the best option be to write a new shell? I don't know anything about that at all, other than others that suggest writing a new shell for kiosk mode. I'd really like a simpler option, like modifying the registry in some way. I have heard that you can remove some buttons from the menu screen that pops up, but unless I can remove pretty much all of them (including the shutdown/restart button in the bottom-right corner), this won't be enough of a solution for me. Thanks for taking the time to read this and thanks again for any help you could provide! -Travis

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  • ksh Auto-Completion PuTTY Configuration

    - by Nitrodist
    I'm having a bit of a problem configuring my PuTTY client to work with the auto-completion feature in the ksh shell. I do a listing on the root with the directories /home and /homeroot and it returns the directories in a list just fine. I can't select it, though, by hitting X = (where X is the number). /home/nitrodist>ls /h #hits esc + = 1) home/ 2) homeroot/ #hits 2 + = for the 'homeroot' dir 1) home/ 2) homeroot/ #hits just the '=' key. 1) home/ 2) homeroot/ Any ideas? I've su -'d to another user who can actually do it with their PuTTY session and I can't do it there, which makes me think it's a PuTTY configuration issue. This is running on a ksh93 shell on HP-UX, if that makes any difference. Here's my ksh config: /home/campbelm>set -o Current option settings allexport off bgnice on emacs off errexit off gmacs off ignoreeof off interactive on keyword off markdirs off monitor on noexec off noclobber off noglob off nolog off notify off nounset off privileged off restricted off trackall off verbose off vi on viraw on xtrace off /home/campbelm>

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  • ssh initial prompt hangs for 10 minutes but console login and initial prompt is very responsive - why?

    - by rfreytag
    I have been running an ESXi 4.0 server for months with a couple of WinServer2003 and several Ubuntu Server 10.4 VMs. The performance has been impressive on 6GB i7 Asus P6T hardware. Suddenly, a week ago, ssh logins to the Ubuntu VMs take 10 minutes when connecting over the LAN (over a WAN the connection (pipe) is broken long before that). When logging in to these VMs the password prompt arrives immediately, and failed passwords are responded to immediately. But the moment I log in then the shell prompt appears and I hang for many minutes. Sometimes the connection hangs before the shell prompt appears and sometimes I can type in a command but the moment I hit return the machine hangs. 10 full minute later control returns and the VM is responsive. NOTE: there are several Ubuntu VMs on the same host machine that are identical in all ways that I can tell. However, only one of the VMs displays this behavior. That is why I mention the ESXi host in passing - I don't think it has anything to do with the problem. This behavior is never seen when I connect with the troubled-VM's console (through vSphere Client). From the console the Ubuntu VMs all respond beautifully. I have seen: http://kb.vmware.com/selfservice/microsites/search.do?cmd=displayKC&docType=kc&externalId=1003496&sliceId=1&docTypeID=DT_KB_1_1&dialogID=229586372&stateId=1%200%20229588522 ...and since that relates to delays in seeing the password prompt that does not appear to be the solution here. Any other suggestions very welcome - thank you.

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  • Sudo won't execute command as another user

    - by TOdorus
    I'm trying to get a unicorn server to start when the server boots. I've created a shell script which works if I log as the ubuntu user and run /etc/init.d/unicorn start Shell script #!/bin/sh case "$1" in start) cd /home/ubuntu/projects/asbest/current/ unicorn_rails -c /home/ubuntu/projects/asbest/current/config/unicorn.rb -D -E production ;; stop) if ps aux | awk '{print $2 }' | grep `cat ~/projects/asbest/current/tmp/pids/unicorn.pid`> /dev/null; then kill `cat ~/projects/asbest/current/tmp/pids/uni$ ;; restart) $0 stop $0 start ;; esac When I rebooted the server I noticed that the unicorn server wasn't listening to a socket. Since I ran the code succesfully as the ubuntu user I modified the script to let it always use the ubuntu user via sudo. #!/bin/sh case "$1" in start) cd /home/ubuntu/projects/asbest/current/ sudo -u ubuntu unicorn_rails -c /home/ubuntu/projects/asbest/current/config/unicorn.rb -D -E production ;; stop) if ps aux | awk '{print $2 }' | grep `cat ~/projects/asbest/current/tmp/pids/unicorn.pid`> /dev/null; then sudo -u ubuntu kill `cat ~/projects/asbest/current/tmp/pids/uni$ ;; restart) $0 stop $0 start ;; esac After rebooting unicorn still wouldn't start, so I tried running the script from the command line. Now I get the following error sudo: unicorn_rails: command not found I've searched high and low to what could cause this, but I'm afraid I've tapped my limited understanding of Linux. From what I can understand is that although sudo should use the ubuntu user to execute the commands, it still uses the environment of the root user, which isn't configured to run ruby or unicorn. Does anybody have any experience with this?

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  • Batch files - number of command line arguments

    - by pyko
    Just converting some shell scripts into batch files and there is one thing I can't seem to find...and that is a simple count of the number of command line arguments. eg. if you have: myapp foo bar In Shell: $# - 2 $* - foo bar $0 - myapp $1 - foo $2 - bar In batch ?? - 2 <---- what command?! %* - foo bar %0 - myapp %1 - foo %2 - bar So I've looked around, and either I'm looking in the wrong spot or I'm blind, but I can't seem to find a way to get a count of number of command line arguments passed in. Is there a command similar to shell's "$#" for batch files? ps. the closest i've found is to iterate through the %1s and use 'shift', but I need to refernece %1,%2 etc later in the script so that's no good.

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  • How can I extract and save values from an XML file in Perl?

    - by Freddy
    Here is what I am trying to do in a Perl script: $data=""; sub loadXMLConfig() { $filename="somexml.xml" $data = $xml-XMLin($filename); } sub GetVariable() { ($FriendlyName) = @_; switch($FriendlyName) { case "My Friendly Name" {print $data-{my_xml_tag_name}} .... .... .... } } The problem is I am using Perl just because I am reading from an XML file, but I need to get these variables by a shell script. So, here is what I am using: $ perl -e 'require "scrpt.pl"; loadConfigFile(); GetVariable("My Variable")' This works exactly as expected, but I need to read the XML file every time I am getting a variable. Is there a way I could "preserve" $data across shell calls? The idea is that I read the XML file only once. If no, is there is a more simple way I could do this? These are the things I can't change: Config File is an XML Need the variables in a shell script

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  • Self-modify the classpath within a Scala script?

    - by Alex R
    I'm trying to replace a bunch of Linux shell scripts with Scala scripts. One of the remaining challenges is how to scan an entire directory of JARs and place them into the classpath. Currently this is done in the shell script prior to invoking the scala JVM. I'd like to eliminate the shell script completely. Is there an elegant scala idiom for this? I have found this other question but in Java it seems hardly worthwhile to mess with it: http://stackoverflow.com/questions/252893/how-do-you-change-the-classpath-within-java

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  • iPhone Shell - is there any?

    - by alee
    While working on iphone security architecture, i came to know that i can run applications from other applications in iphone. referring to the following url http://iphonedevelopertips.com/cocoa/launching-other-apps-within-an-iphone-application.html for example, i can put a link in a website with following hyperlink skype:// will result skype to run and call at particular number. Now i have few concerns here. is there a shell running in background in iphone, so that it allows other application to run basic app commands. if the above statement is true then how can i enable or run commands directly into iphone shell? if above statements are false, then could you please explain how these commands are being executed? is this part of iPhone SDK? or this funcationality is iPhone OS

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  • Practical differences between OpenBSD and FreeBSD?

    - by simon
    I have OpenBSD installed as a router/firewall, and have been thinking about trying either OpenBSD or FreeBSD out as a desktop system, as well. What kind of practical differences (not philosophical, like "OpenBSD's focus is security" [those are well explained at wikipedia ) are there between FreeBSD and OpenBSD? E.g. default shell, different commands or ways of configuring things etc.?

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  • Getting more helpful tab completion prompts in bash?

    - by Rory McCann
    Let's say I have a directory with a few files in it like this: $ ls file1 file2 file3 And I want to do some tab completion in bash: $ cat file<tab> file1 file2 file3 I remember seeing someone doing tab completion and the shell bolded the next parts, so in this case, it would bold the 1, 2 and 3 of the filename so it'll look like this: file**1** file**2** file**3** which will tell you what you should type in next. I think this was a feature of zsh, but is there any way to get it in bash?

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  • Elinks and flash

    - by bajki
    Hello everybody, is there a possibility to "use" flash based objects with elinks ? I mean, i have an online flash based multiplayer game ( http://haxball.appspot.com ) and i want to connect to game with elinks installed on my shell server to create an always-present game room. To do it, i need a terminal-based webbrowser with flash support. There is an elinks installed so it would be great if there is such a possibility in it. Any ideas? Thanks, Mike

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  • re-use '~/.profile` for Fish?

    - by Albert
    (I'm talking about the shell Fish, esp. Fish's Fish.) For Bash/ZSH, I had ~/.profile with some exports, aliases and other stuff. I don't want to have a separate config for environment variables for Fish, I want to re-use my ~/.profile. How? In The FAQ, it is stated that I can at least import those via /usr/local/share/fish/tools/import_bash_settings.py, however I don't really like running that for each Fish-instance.

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  • How do I prevent infinite recursion in X11 start-up process?

    - by chrisaycock
    I wasn't able to run X11 or Terminal after rebooting my Mac. After digging around, I got them to work when I commented-out this line in my .cshrc: xset b off It appears that xset will attempt to launch X11 if it isn't running already, and since X11 will launch the default shell through xterm and thus encounter the xset line above, we will have an infinite loop. I would like to keep the above line in my .cshrc. Is there a way to prevent X11 from launching itself?

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