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  • Using Qt's XML library for simple operation

    - by David Powers
    I basically want to use the XML parser from Qt in my existing project. I have only used Qt once before, and that was with Qt Designer, and I am not having much luck finding anything on Google about how to just use the XML library. I have downloaded a web page that has one large list, and I want to parse it and add each list item to a c++ list. I found this sample code on Ubuntu forums... http://www.uluga.ubuntuforums.org/showpost.php?p=9112973&postcount=6 I want to use that except I need to know what exactly I need to add to the project to get access to it. One other small question is QDomDocument seems to be for files (makes sense) but I have the XML in a string. What part of the XML library works for contents of a string?

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  • Declaring the datatype dynamically reading from an xml string

    - by NLV
    Hello I've this strange issue. I've an xml string which looks like below - <key><int>5</int></key><value><int>10</int> The above xml is obtained after serializing a Dictionary using Paul's Code. Now i want to convert the xml back to the dictionary. How can i get the type "int" from the xml and declare the dictionary as follows? Dictionary<int, int> Any clues?

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  • Intercepting Xstream conversion while parsing XML

    - by Shane Bell
    Suppose I have a simple Java class like this: public class User { String firstName; String lastName; public String getFirstName() { return firstName; } public void setFirstName(String firstName) { this.firstName = firstName; } public String getLastName() { return lastName; } public void setLastName(String lastName) { this.lastName = lastName; } } Now, suppose I want to parse the following XML: <user> <firstName>Homer</firstName> <lastName>Simpson</lastName> </user> I can do this with no problems in XStream like so: User homer = (User) xstream.fromXML(xml); Ok, all good so far, but here's my problem. Suppose I have the following XML that I want to parse: <user> <fullName>Homer Simpson</fullName> </user> How can I convert this XML into the same User object using XStream? I'd like a way to implement some kind of callback so that when XStream parses the fullName field, I can split the string in two and manually set the first name and last name fields on the user object. Is this possible? Note that I'm not asking how to split the string in two (that's the easy part), I want to know how to intercept the XML parsing so XStream doesn't try to reflectively set the fullName field on the User object (which obviously doesn't exist). I looked at the converters that XStream provides but couldn't figure out how to use it for this purpose. Any help would be appreciated.

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  • CDATA xml parsing extra greater than problem

    - by Ruchir Shah
    Hi, I am creating an xml using php and parsing that xml in iphone application code. In description field there is some html tags and text. I am using following line to convert this html tags in to xml tag using CDATA. $response .= '<desc><![CDATA['.trim($feed['fulltext']).']]></desc>'; Now, here my $feed['fulltext'] value is like this <span class="ABC">...text...</span> In xml I am getting following response, <desc><![CDATA[><span class"ABC">...text...</span>]]></desc> You can see here, I am getting an extra greater-than symbol just before the value of $feed['fulltext'] starts. (like this: ...text...) Any solution or suggestion for this? Thanks in advance. Cheers.

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  • How to merge elements from two XML files?

    - by Googler
    Hi all, I need a c# lang code to merge two xml files into one, from the specified content. XML FILE 1 : <exchange-documents> <documentlegal> <bibliographic-data> <applicants> <applicant-name> <name>CENTURY PRODUCTS CO [US]</name> </applicant-name> </applicants> </bibliographic-data> </documentlegal> </exchange-documents> XML FILE 2: <exchange-documents> <documentpatent> <bibliographic-data> <applicants> <applicant-name> <name>CENTURY PRODUCTS CO [US]</name> </applicant-name> </applicants> </bibliographic-data> </documentpatent> </exchange-documents> I need to read the above two xml files and write it into a new xml files with selected elements? OUTPUT XML: <documentlegal> <bibliographic-data> <applicants> <applicant-name> <name>CENTURY PRODUCTS CO [US]</name> </applicant-name> </applicants> </bibliographic-data> </documentlegal> <documentpatent> <bibliographic-data> <applicants> <applicant-name> <name>CENTURY PRODUCTS CO [US]</name> </applicant-name> </applicants> </bibliographic-data> </documentpatent> I dont need the exchnage document element. Can anyone provide me a c# code to achiev the above scenario?

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  • FOR XML PATH Query results to file with SSIS

    - by whimsql
    In SSMS I've gotten my for xml path query written and it's beautiful. I put it in an "Execute SQL Task" in the Control Flow, set the resultset to XML. Now how to I get the results into an actual xml file that I can turn around and FTP to a third party? This should have been so easy! I would put the XML into a variable but we are looking at a HUGE file, possibly 100mb+ Do I need to use a Script Task? (I'd like to avoid that if there is another option.)

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  • xml and external swf documents

    - by VideoDnd
    My XML scripts work fine in the local swf. If I load an external swf, can I still retreive XML data from the same way, or do I have to declare the root somewhere? It's a general question. I know that when animating external swf files, you have to set it up differently, if so I would like an example, and a pitcher of beer. It's St. Patrick's weekend. SAMPLE CODE ONLY XML <?xml version="1.0" encoding="utf-8"?> <SESSION> <COUNT TITLE="starting position">-77777</COUNT> </SESSION> loader swf 'nodes' //grab the data as a string myString = myXML.COUNT.text(); //grab the data as an int count = int(myXML.COUNT.text()); external swf 'variables' var myString:String = ""; var count:int = int(myString); trace(count);

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  • How to parse XML with special characters?

    - by Snooze
    Whenever I try to parse XML with special characters such as o or ???? I get an error. The xml documents claims to use UTF-8 encoding but that does not seem to be the case. Here is what the troublesome text looks like when I view the XML in Firefox: Bleach: The Diamond Dust Rebellion - MÅ? Hitotsu no HyÅ?rinmaru; Bleach - The DiamondDust Rebellion - Mou Hitotsu no Hyourinmaru On the actual website, Å? is actually the character o. <br /> One day, Doraemon and his friends meet Professor Mangetsu (æº?æ??å??ç??, Professor Mangetsu?), who studies magic and magical beings such as goblins, and his daughter Miyoko (ç¾?å¤?å­?, Miyoko?), and are warned of the dangerous approximation of the &quot;star of the Underworld&quot; to the Earth&#039;s orbit.<br /> <br /> And once again, on the actual website, those characters appear as ???? and ???. The actual XML file is formatted properly other than those special characters, which certainly do not appear to be using the UTF-8 encoding. Is there a way to get NSXML to parse these XML files?

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  • In php, Prepare string and create XML/RSS Feed

    - by Bill
    I want to create my own RSS/XML feed. I fetch data from the database to display, but keep getting invalid character errors. If the string has an ampersand or other strange characters in it, the XML will be invalid. I tried using urlencode and htmlentities, but these don't capture all possible characters which need to be escaped. Does anyone know of a PHP function which will prepare a string for XML output?

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  • How to write two-dimensional array to xml in Scala 2.8.0

    - by Shadowlands
    The following code (copied from a question from about a year ago) works fine under Scala 2.7.7, but does not behave correctly under Scala 2.8.0 (Beta 1, RC8). import scala.xml class Person(name : String, age : Int) { def toXml(): xml.Elem = <person><name>{ name }</name><age>{ age }</age></person> } def peopleToXml(people: Array[Person]): xml.Elem = { <people>{ for {person <- people} yield person.toXml }</people> } val data = Array(new Person("joe",40), new Person("mary", 35)) println(peopleToXml(data)) The output (according to 2.7.7) should be: <people><person><name>joe</name><age>40</age></person><person><name>mary</name><age>35</age></person></people> but instead comes out as: <people>\[Lscala.xml.Elem;@17821782</people> How do I get this to behave as it did in 2.7.x?

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  • Simple XML parsing with Google Picasa API and JQuery

    - by zeedog
    I'm starting to look into Google's Picasa API for photo data, which provides you with a big XML file with info about albums and photos. I'm doing some quick and dirty tests to parse the XML file (which is saved locally to my hard drive for now) with JQuery and pull out the album id's, which are stored as "gphoto:id" tags, and display them in a div: $(document).ready(function() { $.get( 'albums.xml', function(data) { $(data).find('entry').each(function() { var albumId = $(this).children('gphoto:id').text(); $('#photos').append(albumId + '<br />'); }) }) }) I'm getting the following error in the console: jquery.js:3321 - Uncaught Syntax error, unrecognized expression: Syntax error, unrecognized expression: id This will work with other tags in the XML file (such as title, author, updated, etc.), but I'm trying to understand what's going on here. Does it have to do with the colon in "gphoto:id", somehow?

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  • How to display information contained in XML file from another website

    - by Tristan
    Hello, I have an XML file ( XML file I produce ) which contains information about my parteners. I want them to display on their website information relative to them by picking them into the XML file. I have no idea to do that, ecxept that i need to write a 'parser' in javascript to display information. could you please provide me examples to do that ? (how to write a parser, how to display only information for one partener ?) Thank you, Regards

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  • Extract some data from a lot of xml files

    - by LifeH2O
    I have cricket player profiles saved in the form of .xml files in a folder. each file has these tags in it <playerid>547</playerid> <majorteam>England</majorteam> <playername>Don</playername> the playerid is same as in .xml (each file is of different size,1kb to 5kb). These are about 500 files. What i need is to extract the playername, majorteam, and playerid from all these files to a list. I will convert that list to XML later. If you know how can i do it directly to XML i will be very thankful.

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  • Convert XML to .plist

    - by Dror Sabbag
    Hey, I have an XML exported from Oracle DB, which will be downloaded into my application main bundle. i would like to convert this XML file into .plist file so i can assign the values into NSDictionary and NSArrays.. Is there a way to get this to work? or is there a better way to work with an external XML file? note that one of the fields in the XML is a full HTML content example: <main> <DATA_RECORD> <ID>ID1</ID> <NO>1234512</NO> <TYPE>NEW</TYPE> <TYPE_NO>0</TYPE_NO> <TEXT_ID>TEXT1</TEXT_ID> <TEXT><HTML>some html goes here</HTML></TEXT> </DATA_RECORD> </main>

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  • XML - python prints extra lines

    - by horse
    `from xml import xpath from xml.dom import minidom xmldata = minidom.parse('model.xml').documentElement for maks in xpath.Evaluate('/cacti/results/maks/text()', xmldata): print maks.nodeValue ` and I get result: 85603399.14 398673062.66 95785523.81 But I needed to be: 85603399.14 NO SPACE 398673062.66 NO SPACE 95785523.81 Can somebody help me, i new at programing :( ?

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  • MSSQL 2005 FOR XML

    - by Lima
    Hi, I am wanting to export data from a table to a specifically formated XML file. I am fairly new to XML files, so what I am after may be quite obvious but I just cant find what I am looking for on the net. The format of the XML results I need are: <data> <event start="May 28 2006 09:00:00 GMT" end="Jun 15 2006 09:00:00 GMT" isDuration="true" title="Writing Timeline documentation" image="http://simile.mit.edu/images/csail-logo.gif"> A few days to write some documentation </event> </data> My table structure is: name VARCHAR(50), description VARCHAR(255), startDate DATETIME, endDate DATETIME (I am not too interested in the XML fields image or isDuration at this point in time). I have tried: SELECT [name] ,[description] ,[startDate] ,[endTime] FROM [testing].[dbo].[time_timeline] FOR XML RAW('event'), ROOT('data'), type Which gives me: <data> <event name="Test1" description="Test 1 Description...." startDate="1900-01-01T00:00:00" endTime="1900-01-01T00:00:00" /> <event name="Test2" description="Test 2 Description...." startDate="1900-01-01T00:00:00" endTime="1900-01-01T00:00:00" /> </data> What I am missing, is the description needs to be outside of the event attributes, and there needs to be a tag. Is anyone able to point me in the correct direction, or point me to a tutorial or similar on how to accomplish this? Thanks, Matt

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  • Working with Database using LINQ to XML

    - by M.H
    Hi,I am Working on a project (C#) in the university and they said that we can't use a DBMS like SQL Server so we decide to use Linq and XML...we learned some basics in Linq to Xml But really we don't know how we can create tables and fields and work with them in Xml.any suggestions ?

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  • Parsing XML with jQuery

    - by Jamie
    I've used this: $(document).ready(function () { $.ajax({ type: "GET", url: "http://domain.com/languages.php", dataType: "xml", success: xmlParser }); }); function xmlParser(xml) { $('#load').fadeOut(); $(xml).find("result").each(function () { $(".main").append('' + $(this).find("language").text() + ''); $(".lang").fadeIn(1000); }); } I used a local XML file on my computer, it works fine, but when I change the URL to an website, it just keeps loading all the time... How do I get this to work?

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  • Embedding XSL Stylesheet into XML

    - by user700996
    I have the following XML: <?xml version="1.0" encoding="ISO-8859-1"?> <?xml-stylesheet type="text/xsl" href="http://www.fakedomain.com/sally.xsl"?> And the following content in sally.xsl: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <html> <body> <xsl:for-each select="documentcollection/document"> <p> <xsl:for-each select="rss/channel/item"> <xsl:value-of select="title"/><br /> <xsl:value-of select="description"/><br /> <xsl:value-of select="link"/><br /> </xsl:for-each> </p> </xsl:for-each> </body> </html> </xsl:template> </xsl:stylesheet> However, the browser displays the XML as though the XSL line is not present. Do you know why the browser is ignoring the XSL stylesheet? Is the style sheet wrong? Thanks

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  • How to XML escaping with Apache Velocity?

    - by Jan Algermissen
    I am generating XML using Apache Velocity. What is the best (most straight-forward) way to XML-escape the output? (I saw there is an escape tool, but could not figure out it's dev state. I also think that XML escaping is something that is very likely supported by Velocity directly.)

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  • MSSQL "for xml", multiple tables, multiple nodes

    - by Nelson
    Is it possible to select multiple tables at once? For example, I can do: SELECT ( SELECT * FROM Articles FOR XML PATH('article'), TYPE ) FOR XML PATH('articles'), ROOT('data') and SELECT ( SELECT * FROM ArticleTypes FOR XML PATH('articleType'), TYPE ) FOR XML PATH('articleTypes'), ROOT('data') Can I join both so that I get the following output? I can't use UNION because the table structures don't match. <data> <articles> <article>...</article> ... </articles> <articleTypes> <articleType>...</articleType> ... </articleTypes> </data>

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  • Leave entity intact in XML + XSLT

    - by Kuroki Kaze
    I transform XML to (sort of) HTML with XSL stylesheets (using Apache Xalan). In XML there can be entities like &mdash;, which must be left as is. In beginning of XML file I have a doctype which references these entities. What should I do for entity to be left unchanged? <!DOCTYPE article [ <!ENTITY mdash "&mdash;"><!-- em dash --> ]> gives me SAXParseException: Recursive entity expansion, 'mdash' when encountering &mdash in XML text.

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