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  • How to update csv column names with database table header

    - by user1523311
    I am facing this problem some past days and now frustrate because I have to do it. I need to update my CSV file columns name with database table header. My database table fields are different from CSV file. Now the problem is that first I want to update column name of CSV file with database table headers and then import its data with field mapping into database. Please help me I don't know how I can solve this. This is my php code: $file = $_POST['fileName']; $filename = "../files/" . $file; $list = $_POST['str']; $array_imp = implode(',', $list); $array_exp = explode(',', $array_imp); $fp = fopen("../files/" . $file, "w"); $num = count($fp); for ($c = 0; $c < $num; $c++) { if ($fp[c] !== '') { fputcsv($fp, $array_exp); } } fclose($fp);

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  • Application logic for invoicing and subscriptions?

    - by Industrial
    Hi everyone, We're just in the planning stage of a web app that offers subscriptions to our customers. The subscription periods varies and can be prolonged indefinitely by our customers, but are always at least one month (30 days). When a customer signs up, the customer information (billing address, phone number and so on) are stored in a customers table and a subscription is created in the subscriptions table: id | start_date | end_date | customer_id -------------------------------------------------------- 1 | 2010-12-31 | 2011-01-31 | 1 Every month we'll loop through the subscriptions table (cronjob preferably) and create invoices for the past subscription period, which are housed in their own table - invoices. Depending on the customer, invoices are manually printed out and sent by mail, or just emailed to the customer. Due to the nature of our customers and the product, we need to offer a variety of different payment alternatives including wire transfer and card payments, hence some invoices may need to be manually handled and registered as paid by our staff. The 15th every month, the invoices table are looped through and if no payment has been marked for the actual invoice, the according subscription will be removed. If there's a payment registered, the end_date in the subscriptions table is incremented by another 30 days (or what now our period our customer has chosen). Are we looking at headaches by incrementing dates forwards and backwards to handle non-paying customers and extending subscriptions? Would it be a better idea to add new subscriptions as customers extends their subscription?

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  • Pagination links do not work properly - incorrect PHP function??

    - by ClarkSKent
    Hi everyone, I am still trying to figure out how to fix my pagination script to work properly. the problem I am having is when I click any of the pagination number links to go the next page, the new content does not load. literally nothing happens and when looking at the console in Firebug, nothing is sent or loaded. I have on the main page 3 links to filter the content and display it. When any of these links are clicked the results are loaded and displayed along with the associated pagination numbers for that specific content. I believe the problem is coming from the function(generate_pagination.php (seen below)). Here is the main page so you can how I am including and starting the function(I'm new to php): <?php include_once('generate_pagination.php'); ?> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript" src="jquery_pagination.js"></script> <div id="loading" ></div> <div id="content" data-page="1"></div> <ul id="pagination"> <?php generate_pagination($sql) ?> </ul> <br /> <br /> <a href="#" class="category" id="marketing">Marketing</a> <a href="#" class="category" id="automotive">Automotive</a> <a href="#" class="category" id="sports">Sports</a> This is as mentioned above, where i think the problem persists since I know nothing of the function formats and how to properly incorporate them: <?php function generate_pagination($sql) { include_once('config.php'); $per_page = 3; //Calculating no of pages $result = mysql_query($sql); $count = mysql_fetch_row($result); $pages = ceil($count[0]/$per_page); //Pagination Numbers for($i=1; $i<=$pages; $i++) { echo '<li class="page_numbers" id="'.$i.'">'.$i.'</li>'; } } $ids=$_GET['ids']; generate_pagination("SELECT COUNT(*) FROM explore WHERE category='$ids'"); ?> I thought I might as well through in the jquery if someone wants to see: $(document).ready(function(){ //Display Loading Image function Display_Load() { $("#loading").fadeIn(900,0); $("#loading").html("<img src='bigLoader.gif' />"); } //Hide Loading Image function Hide_Load() { $("#loading").fadeOut('slow'); }; //Default Starting Page Results $("#pagination li:first").css({'color' : '#FF0084'}).css({'border' : 'none'}); Display_Load(); $("#content").load("pagination_data.php?page=1", Hide_Load()); //Pagination Click $("#pagination li").click(function(){ Display_Load(); //CSS Styles $("#pagination li") .css({'border' : 'solid #dddddd 1px'}) .css({'color' : '#0063DC'}); $(this) .css({'color' : '#FF0084'}) .css({'border' : 'none'}); //Loading Data var pageNum = this.id; $("#content").load("pagination_data.php?page=" + pageNum, function(){ $(this).attr('data-page', pageNum); Hide_Load(); }); }); // Editing below. // Sort content Marketing $("a.category").click(function() { Display_Load(); var this_id = $(this).attr('id'); $.get("pagination.php", { category: this.id }, function(data){ //Load your results into the page var pageNum = $('#content').attr('data-page'); $("#pagination").load('generate_pagination.php?category=' + pageNum +'&ids='+ this_id ); $("#content").load("filter_marketing.php?page=" + pageNum +'&id='+ this_id, Hide_Load()); }); }); }); Any help would be appreciated on getting the function to work properly. Thank you.

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  • SQL query for fetching friend list

    - by Bhavyanshu
    I need help with SQL query. I have two tables. One is users and other one is userfriends users table: aid email firstname 1 [email protected] example 2 [email protected] example2 3 [email protected] example3 4 [email protected] example4 userfriends tables: reqid email friendemail status 1 [email protected] [email protected] 1 (example1 is frnds with example2) 2 [email protected] [email protected] 2 (example2 request pending) 3 [email protected] [email protected] 1 (example1 is frnds with example3) 4 [email protected] [email protected] 1 (example1 is frnds with example4) So when status is 2 the add request is pending and at status 1 they are friends. What i want is that i want to retrieve the complete friendlist for user example1. I want to pull out names from users table for corresponding output from previous query to display as friendlist.

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  • php search database for row

    - by Brenden Morley
    Okay I got code the code to pull data based on a users account number well here is what im using (And yes I know it isnt safe now that is the reason for my post) <?php include('config.php'); $user_info = fetch_user_info($_GET['AccountNumber']); ?> <html> <body> <div> <?php if ($user_info === false){ $Output = 'http://www.MyDomain.Com/'; echo '<META HTTP-EQUIV=Refresh CONTENT="0; URL='.$Output.'">'; }else{ ?> <center> <title><?php echo $user_info['FirstName'], ' ', $user_info['LastName'], ' - ', $user_info['City'], ', ', $user_info['State']; ?> - Name of site</title> So basically what this code is allowing me to do is have a file called Profile.php And when a user visits this this page it will return the data Like this http://MyDomain.com/Profile.php?AccountNumber=50b9c965b7c3b How can I do this securely cause right now its using a get method really unsafe to retive the account number from the url bar.

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  • Find the closest locations to a given address

    - by xtine
    I have built an application in CakePHP that lists businesses. There are about 2000 entries, and the latitude and longitude coordinates for each business is in the DB. I now am trying to tackle the search function. There will be an input box where the user can put a street address, city, or zipcode, and then I would like it to return the 11 closest businesses as found from the database. How would I go about doing this?

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  • Separating Variables Inside an Array

    - by Jake Avila Talledo
    Hey i have an array an I need to separate each value so it would be something like this $arry = array(a,b,c,d,e,f) $point1 = (SELECT distance FROM Table WHERE Origin = a AND Destination = b); $point2 = (SELECT distance FROM Table WHERE Origin = b AND Destination = c); $point3 = (SELECT distance FROM Table WHERE Origin = c AND Destination = d); $point4 = (SELECT distance FROM Table WHERE Origin = d AND Destination = e); $point5 = (SELECT distance FROM Table WHERE Origin = e AND Destination = f); $point6 = (SELECT distance FROM Table WHERE Origin = f AND Destination = g); $point7 = (SELECT distance FROM Table WHERE Origin = g AND Destination = f); $total_trav = $point1+$point2+$point3+$point4+$point5+$point6+$point7

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  • Can't use method return value in write context; Not sure where to go from here

    - by Morgan Green
    This is my source for the variable. <?php if ($admin->get_permissions()=3) echo 'Welcome to the Admin Panel'; else echo 'Sorry, You do not have access to this page'; ?> And the code that I'm actually trying to call with the if statement is: public function get_permissions() { $username = $_SESSION['admin_login']; global $db; $info = $db->get_row("SELECT `permissions` FROM `user` WHERE `username` = '" . $db->escape($username) . "'"); if(is_object($info)) return $info->permissions; else return ''; } This should be a simple way to call my pages that the user is authorized for by using an else if statement. Or So I thought

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  • A better understanding of the relations beetween database tables

    - by Nistor Alexandru
    Hi I am trying to get a better understanding of relational databases and there is something that I keep bumping into and don't understand.Let's take this two tables: In this case Login.ID is the primary key with auto_increment set and Profile.ID_LOGIN is the Foreign KEY.When a user is created and it's username and password is stored in the login database does the ID coresponding to the curesnt username and password get automaticly added into ID_LOGIN or do I have to create an SQL statement to do this? If I have to create a SQL statement how should I aproach adding the ID_LOGIN to make sure I am adding it corectly?

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  • PHP - advice for java HashMap alternative in php?

    - by teutara
    I know it is super noob and will be answered in no time, but I could not figure.. sorry for any inconvenience.. Here is the thing: ID colA colB Length 1 seq1 seq11 1 2 seq1 seq11 11 3 seq3 seq33 21 4 seq3 seq33 14 I have a db with this kind of a table, has more than 10M rows. I want to loop though colA first, get the relevant colB value, and check if there are any other occurrences of the same value. For example in colB (seq11) there are 2 occurrences of colA(seq1), this time I have to combine those and output the sum of the length. Similar to this: ID colA colB Length 1 seq1 seq11 12 2 seq3 seq33 35 I am a bit java guy, but because my colleague has written everything in php and this will be just an adding, i need a php solution. With java i would have used hashmap, so that I would have the colA data once and just increment the value of "Length Column".. I know it is not a proper question, but.. Thank you in advance.. $$$$$$$$$$ EDIT $$$$$$$$$$ I tried this query in order to group by occurences: SELECT COUNT(*) SeqName FROM SeqTable GROUP BY SeqName HAVING COUNT(*)>0;

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  • How can I use an array within a SQL query

    - by ThinkingInBits
    So I'm trying to take a search string (could be any number of words) and turn each value into a list to use in the following IN statement) in addition, I need a count of all these values to use with my having count filter $search_array = explode(" ",$this->search_string); $tag_count = count($search_array); $db = Connect::connect(); $query = "select p.id from photographs p left join photograph_tags c on p.id = c.photograph_id and c.value IN ($search_array) group by p.id having count(c.value) >= $tag_count"; This currently returns no results, any ideas?

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  • Cannot running next process when a variable save no value

    - by bruine
    First, I wanna compare between 2 tables tb_wrapper and tb_summary to get the data in the tb_wrapper that doesn't exist in the tb_summary then save in $link. If I don't get the same data, I want to print the result $link. When I don't get the not same data, I want it to go to another process. Here's the code : $q2 = mysql_query(" SELECT a.doc_url FROM tb_wrapper a LEFT JOIN tb_summary b ON a.doc_name = b.doc_summ WHERE b.doc_summ IS NULL"); while ($row = mysql_fetch_array($q2)){ $link = $row['doc_url']; if (!$link){ include 'next_process.php'; } else { print_r($link); } } it doesn't work. When I don't get the not same data or $link not save a value. table : CREATE TABLE tb1 (`id` int, `doc_name` varchar(100), `doc_url` varchar(50)) } CREATE TABLE tb2 (`id` int, `doc_summ` varchar(100)) }

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  • fetch some data from two tables

    - by user1753971
    i have site like imdb and we provide movie information sin site..and our website have option to rate all movies for every users. I have two tables 1 . imdb (its for store movie details) id,name,actors,vote 2. ratings (its for store users rating details) id,rating_id(its same as id from first table),rating_num,IP now what am doing is..when anyone rating a movie take the avg of that movie rating by using rating tables (total ratings/number of ratings) and insert that value into "vote" column in first table..my demands this..thats why done like this.. Now my problem is..i want to fetch top rated movies..i mean in vote column which movie have top rating which want to list and one more condition is that that movie should rated by 10 users(use ratings table for that) thanks in advance

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  • Securing database keys for client-side processing

    - by danp
    I have a tree of information which is sent to the client in a JSON object. In that object, I don't want to have raw IDs which are coming from the database. I thought of making a hash of the id and a field in the object (title, for example) or a salt, but I'm worried that this might have a serious effect on processing overhead. SELECT * FROM `things` where md5(concat(id,'some salt')) = md5('1some salt'); Is there a standard practice for obscuring IDs in this kind of situation?

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  • mysql_fetch_object on complex objects

    - by Arsenal
    Say for example I have the follwoing DB structure Table book id title ... Table Author id name ... Table BookAuthor id bookid authorid And in PHP I have the following object class Book { var $id; var $title; var $authors = array(); function Book() {} } class Author { var $id; var $name; function Author(){} } Now, would it be possible using mysql_fetch_object to retrieve the bookobject including the authors as an array of author objects? If it's possible I'm pretty sure you'll need the basic inner join query SELECT * FROM tblbook INNER JOIN tblbookauthor on ... (wel you get the point) Is it possible? thanks!

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  • how to filter an id for subcategory in sql

    - by Naim Nsco
    i have create one table with A is 1,2,3 and B is 3,5,5,9,10,10 For example, i want to change from this table NP A B C 1 1 3 why not 1 1 5 weigh 1 1 5 hello 1 1 9 no way 1 1 10 now or never 1 1 10 float the boat, capt ain 1 1 12 no nelp 2 2 4 why 2 2 6 way too much 2 2 11 help 3 3 1 not now 3 3 2 not 3 3 7 milky way 3 3 7 this is stupid 3 3 8 one way To be like this:- A B C ---------- -- -------- 1 3 why not 5 weigh 5 hello 9 no way 10 now or never 10 float the boat, capt ain 12 no nelp 2 4 why 6 way too much 11 help 3 1 not now 2 not 7 milky way 7 this is stupid 8 one way How to do like that?. Anyone know about this?.

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  • Linking Post Title to Specific Page ID

    - by ThatMacLad
    I've created a form to update my websites homepage with content but I wanted to know how I could set it up so that a posts title links to a specific post ID. I'd also like to add a Read More link that directs anybody reading the blog to the correct post. Here is my PHP code: <html> <head> <title>Blog Name</title> </head> <body> <?php mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "SELECT * FROM php_blog ORDER BY timestamp DESC LIMIT 5"; $result = mysql_query($sql) or print ("Can't select entries from table php_blog.<br />" . $sql . "<br />" . mysql_error()); while($row = mysql_fetch_array($result)) { $date = date("l F d Y", $row['timestamp']); $title = stripslashes($row['title']); $entry = stripslashes($row['entry']); $password = $row['password']; $id = $row['id']; if ($password == 1) { echo "<p><strong>" . $title . "</strong></p>"; printf("<p>This is a password protected entry. If you have a password, log in below.</p>"); printf("<form method=\"post\" action=\"post.php?id=%s\"><p><strong><label for=\"username\">Username:</label></strong><br /><input type=\"text\" name=\"username\" id=\"username\" /></p><p><strong><label for=\"pass\">Password:</label></strong><br /><input type=\"password\" name=\"pass\" id=\"pass\" /></p><p><input type=\"submit\" name=\"submit\" id=\"submit\" value=\"submit\" /></p></form>",$id); print "<hr />"; } else { ?> <p><strong><?php echo $title; ?></strong><br /><br /> <?php echo $entry; ?><br /><br /> Posted on <?php echo $date; ?> <hr /></p> <?php } } ?> </body> </html> Thanks for any help. I really appreciate any input!

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  • Converting files to blob to save in database

    - by jimbo
    I have an old user site that we are currently updating. The site's users have previously uploaded profile pics that are stored in a directory. I am now wanting to keep these profile images in the database, (easy to backup all data) but am having trouble working out how to do it. There are a lot of tutorials talking about do ing this from files that have just been uploaded and using the tmp name etc, but how can I re-create with files that have already been uploaded? I have looked into $data = file_get_contents($filename); Which seems to create a binary file, but doesn't seem to save in database with: mysql_query("UPDATE profiles SET company_logo = mysql_real_escape_string('".$data."') WHERE id = 1 ") or die(mysql_error());

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  • cakephp: how to make NOW() work in search condition ?

    - by kaklon
    I'm trying to get all records with date greater then now. I tried this but it doeasnt work: $all_dates = $this->TourDate->find('all', array('conditions' => array('TourDate.date >=' => 'NOW()'), 'order' => array('TourDate.date ASC'))); If I replace NOW() with the current date it works. Why's that?

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  • Change an autoincrementing field to one previous

    - by jlan
    One day, wordpress suddenly jumped from pots id 9110 to 890000000 post. Days later I'd like to move back new posts to continue from id 9111. I'm sure that id will never reach id 890000000, no problem here, but id is an autoincrement field and "ALTER TABLE wp8_posts AUTO_INCREMENT =9111" is not working. Can I force id to continue from 9111 ?

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  • what's wrong with this code?

    - by user329820
    Hi this is my code which will not work correctly ! what is wrong with its data type :( thanks CREATE TABLE T1 (A INTEGER NOT NULL); CREATE TABLE T3 (A SMALLINT NOT NULL); INSERT T1 VALUES (32768.5); SELECT * FROM T1; INSERT T3 SELECT * FROM T1; SELECT * FROM T3;

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  • Why does this SELECT ... JOIN statement return no results?

    - by Stephen
    I have two tables: 1. tableA is a list of records with many columns. There is a timestamp column called "created" 2. tableB is used to track users in my application that have locked a record in tableA for review. It consists of four columns: id, user_id, record_id, and another timestamp collumn. I'm trying to select up to 10 records from tableA that have not been locked by for review by anyone in tableB (I'm also filtering in the WHERE clause by a few other columns from tableA like record status). Here's what I've come up with so far: SELECT tableA.* FROM tableA LEFT OUTER JOIN tableB ON tableA.id = tableB.record_id WHERE tableB.id = NULL AND tableA.status = 'new' AND tableA.project != 'someproject' AND tableA.created BETWEEN '1999-01-01 00:00:00' AND '2010-05-06 23:59:59' ORDER BY tableA.created ASC LIMIT 0, 10; There are currently a few thousand records in tableA and zero records in tableB. There are definitely records that fall between those timestamps, and I've verified this with a simple SELECT * FROM tableA WHERE created BETWEEN '1999-01-01 00:00:00' AND '2010-05-06 23:59:59' The first statement above returns zero rows, and the second one returns over 2,000 rows.

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  • Copying a database into a new database including structure and data

    - by Jason
    In phpMyAdmin under operations I can "Copy database to:" and select Structure and data CREATE DATABASE before copying Add AUTO_INCREMENT value I need to be able to do that without using phpMyAdmin. I know how to create the database and user. I have a source database that's a shell that I can work from so all I really need is the how to copy all the table structure and data part. (I know, the harder part) system() & exec() are not options for me which rules out mysqldump. (I think) How can I loop through each table and recreate it's structure and data? Is it just looping through the results of SHOW TABLES then for each table looping through DESCRIBE tablename Then, is there an easy way for getting the data copied?

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  • Get previous and next row from current id

    - by Hukr
    How can I do to get the next row in a table? `image_id` int(11) NOT NULL auto_increment `image_title` varchar(255) NOT NULL `image_text` mediumtext NOT NULL `image_date` datetime NOT NULL `image_filename` varchar(255) NOT NULL If the current image is 3 for example and the next one is 7 etc. this won’t work: $query = mysql_query("SELECT * FROM images WHERE image_id = ".intval($_GET['id'])); echo $_GET['id']+1; How should I do? thanks

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  • Convert multiquery to a query using group by and so on

    - by ffffff
    -schema CREATE TABLE `ratings` ( `id` int(11) NOT NULL default '0', `rating` int(11) NOT NULL default '1', `rating_start` datetime NOT NULL default '0000-00-00 00:00:00', PRIMARY KEY (`id`) ) TYPE=MyISAM -myprogram.php foreach($ids as $id){ $sql = "SELECT rating FROM ratings WHERE id = '$id' AND rating_start >= NOW()"; $sql .= "ORDER BY rating_start DESC LIMIT 1;" $ret = $db->execute($id); } Can I teke same date from a Query? by using id IN (".implode(",",$ids).") and GROUP BY id

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