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  • IE8 and below <input type="image"> value work around

    - by kielie
    Hi guys, I have a slight problem, I am trying to capture the input of two buttons, one yes, one no, into a database but for some reason the database doesn't always show the value of the button clicked, it just shows up blank. <form action="refer.php" method="post" id="formID" > <div class="prompt_container" style="float: left;"> <span class="prompt_item"><input type="image" src="images/yes.jpg" alt="submit" value="yes" onclick="this.disabled=true,this.form.submit();" /></span> <input type="hidden" name="refer" value="yes"> </div> </form> <form action="thank_you.php" method="post" id="formID" > <div class="prompt_container" style="float: right;"> <span class="prompt_item"><input type="image" src="images/no.jpg" alt="submit" value="no" onclick="this.disabled=true,this.form.submit();" /></span> <input type="hidden" name="refer" value="no" > </div> </form> Apparently anything lower than IE8 will ignore the value attribute of all form inputs. How could I get this to work properly in all browsers? jQuery or Javascript maybe?

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  • Random Record from Recordset

    - by Tony Hanks
    I have the fillowing Query: SELECT a.*, ps4_media.filename, ps4_galleries.name as galleryname, ps4_media_iptc.description, ps4_media_iptc.title, ps4_media_iptc.headline, ps4_media.date_added, ps4_galleries.created, ps4_folders.name as foldername, ps4_galleries.gallery_count FROM ps4_media_galleries a INNER JOIN (SELECT ps4_media_galleries.gallery_id, min(ps4_media_galleries.gmedia_id) AS minID FROM ps4_media_galleries GROUP BY ps4_media_galleries.gallery_id) b ON a.gallery_id = b.gallery_id AND a.gmedia_id = b.minID INNER JOIN ps4_media ON ps4_media.media_id = a.gmedia_id INNER JOIN ps4_folders ON ps4_folders.folder_id = ps4_media.folder_id INNER JOIN ps4_galleries ON ps4_galleries.gallery_id = a.gallery_id INNER JOIN ps4_media_iptc ON ps4_media_iptc.media_id = a.gmedia_id ORDER BY ps4_galleries.created DESC How do I get ps4_media.filename to be random, everything else is fine just want the thumbnail which ps4_media.filename is to be and of the records in the found set.

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  • fetch some data from two tables

    - by user1753971
    i have site like imdb and we provide movie information sin site..and our website have option to rate all movies for every users. I have two tables 1 . imdb (its for store movie details) id,name,actors,vote 2. ratings (its for store users rating details) id,rating_id(its same as id from first table),rating_num,IP now what am doing is..when anyone rating a movie take the avg of that movie rating by using rating tables (total ratings/number of ratings) and insert that value into "vote" column in first table..my demands this..thats why done like this.. Now my problem is..i want to fetch top rated movies..i mean in vote column which movie have top rating which want to list and one more condition is that that movie should rated by 10 users(use ratings table for that) thanks in advance

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  • Insert names into table if not already existing

    - by John
    I am trying to build an application that allows users to submit names to be added to a db table (runningList). Before the name is added tho, I would like to check firstname and lastname against another table (controlList). It must exist in (controlList) or reply name not valid. If the name is valid I would like to then check firstname and lastname against (runningList) it make sure it isnt already there. If it isnt there, then insert firstname & lastname. If it is there, reply name already used. Below is code that worked before I tried to add the test against the controlList, I somehow broke it altogether while trying to add the extra step. if (mysql_num_rows(mysql_query('SELECT * FROM runninglist WHERE firstname=\'' .$firstname . '\' AND lastname=\'' . $lastname . '\' LIMIT 1')) == 0) { $sql="INSERT INTO runninglist (firstname, lastname) VALUES ('$_POST[firstname]','$_POST[lastname]')"; } else { echo "This name has been used."; } Any direction would be appreciated. Thanx John

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  • PhpMyAdmin; Should I disable root login?

    - by Camran
    I have this setup in Phpmyadmin: USER HOST PASSW PRIVILEGES GRANT debian-sys-maint localhost Yes ALL PRIVILEGES YES phpmyadmin localhost Yes USAGE NO root 127.0.0.1 Yes ALL PRIVILEGES YES root localhost Yes ALL PRIVILEGES YES root my_hostname Yes ALL PRIVILEGES YES username localhost Yes ALL PRIVILEGES YES Where "username" is my username and "my_hostname" is my hostname. I am currently only logging in as the last one (username, localhost). Also, I have php which also uses the last ones login details. Should I disable the other ones? And, what other security measures should I take? BTW: My server is Linux and I have root access. Thanks

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  • Good article about File- and Folder Permissions on production server?

    - by Camran
    I have a classifieds website, and users may post classifieds, add images, remove classifieds etc etc... I have no idea what to set the permissions to on folders. For instance, a php script which I have uploads a file to a directory. What would you have set the directory permissions to? Nobody need access to the directory, only the php script... Just wonder if anybody has a good (brief) article about setting the "right" permissions? Thanks

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  • allowing bb code but not java script

    - by user1405062
    Hello im trying to get the hang of using bb codes onto my normal php site ( not forum or anything just a normal site ) I have seen a few posts like this one http://www.pixel2life.com/forums/index.php?/topic/10659-php-bbcode-parser/ which says i need a bb parser. I was just wondering can anyone show me how i would use one ? I have a status box were users can update there status but i would like to allow bb codes but not java script. So when im doing my inserting into the db i strip the status like so.. $status= mysql_real_escape_string($_POST['status']); $status2= strip_tags($status); And that stops the java script and tags from getting though but i need the bb code tags to come though but carry on blocking the java script code is there anyway to do this ? Also then i just echo it out echo $status2 ; But just plain text shows so was just wondering if anyone knows how to let though bb code and stop java script and could some one show me how to use the bb parasher ? also need to know how to echo out the bb coding...

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  • How to translate this query:

    - by xRobot
    How can I translate this 2 queries in postgresql ? : . CREATE TABLE example ( id int(10) unsigned NOT NULL auto_increment, from varchar(255) NOT NULL default '0', message text NOT NULL, lastactivity timestamp NULL default '0000-00-00 00:00:00', read int(10) unsigned NOT NULL, PRIMARY KEY (id), KEY from (from) ) DEFAULT CHARSET=utf8; . SELECT * FROM table_1 LEFT OUTER JOIN table_2 ON ( table_1.id = table_2.id ) WHERE (table_1.lastactivity > NOW()-100);

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  • How to check if a checkbox/ radio button is checked in php

    - by user225269
    I have this html code: <tr> <td><label><input type="text" name="id" class="DEPENDS ON info BEING student" id="example">ID</label></td> </tr> <tr> <td> <label> <input type="checkbox" name="yr" class="DEPENDS ON info BEING student"> Year</label> </td> </tr> But I don't have any idea on how do I check this checkboxes if they are checked using php, and then output the corresponding data based on the values that are checked. Please help, I'm thinking of something like this. But of course it won't work, because I don't know how to equate checkboxes in php if they are checked: <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $id = mysql_real_escape_string($_POST['idnum']); if($_POST['id'] == checked & $_POST['yr'] ==checked ){ $result2 = mysql_query("SELECT * FROM student WHERE IDNO='$id'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> </tr>"; while($row = mysql_fetch_array($result2)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "</tr>"; } echo "</table>"; } mysql_close($con); ?>

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  • help me with the following sql query

    - by rupeshmalviya
    could somebody correct my following query, i am novice to software development realm, i am to a string builder object in comma separated form to my query but it's not producing desired result qyery is as follows and string cmd = "SELECT * FROM [placed_student] WHERE passout_year=@passout AND company_id=@companyId AND course_id=@courseId AND branch_id IN('" + sb + "')"; StringBuilder sb = new StringBuilder(); foreach (ListItem li in branch.Items) { if (li.Selected == true) { sb.Append(Convert.ToInt32(li.Value) +", "); } } li is integer value of my check box list which are getting generated may be differne at different time ...please also suggest me some good source to learn sql..

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  • insert into table where if not in list

    - by jim smith
    Can anybody help me with the syntax? insert into history (company,partnumber,price) values ('blah','IFS0090','0.00') if company NOT IN ('blah','blah2','blah3','blah4','blah4') and partnumber='IFS0090'; Background: I have a history table which stores daily company, products and prices. But sometimes a company will remove itself for a few days. Complicating the issue is because I'm only saving daily CHANGES to prices only and not snapshotting the entire days list (the data would be huge) when I display the data the company will still come up for the previous days price. So I need to do something like this, where a 0.00 price means they're no longer there.

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  • why is ADODB inserting NULL values on update?

    - by every_answer_gets_a_point
    i have: With rs .AddNew ' create a new record ' add values to each field in the record .Fields("datapath") = dpath .Fields("analysistime") = "atime" .Fields("reporttime") = "rtime" .Fields("lastcalib") = "lcalib" .Fields("analystname") = "aname" .Fields("reportname") = "rname" .Fields("batchstate") = "bstate" .Fields("instrument") = "NA" .Update ' stores the new record End With when i check the database, it looks like it ONLY inserted the last field! has anyone encountered this problem?

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  • How can I use an array within a SQL query

    - by ThinkingInBits
    So I'm trying to take a search string (could be any number of words) and turn each value into a list to use in the following IN statement) in addition, I need a count of all these values to use with my having count filter $search_array = explode(" ",$this->search_string); $tag_count = count($search_array); $db = Connect::connect(); $query = "select p.id from photographs p left join photograph_tags c on p.id = c.photograph_id and c.value IN ($search_array) group by p.id having count(c.value) >= $tag_count"; This currently returns no results, any ideas?

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  • Magento: Add (and retrieve) custom database field for CMS pages

    - by Toby H
    I want to assign custom parameters to CMS pages in Magento (i.e. 'about', 'customer service', etc), so they can be grouped. The end goal is to use the parameters for each page to show (or hide) them in a nav menu. Writing a quick method in the page/html block to retrieve the pages (active only) for the menu was easy, but I can't figure out how to group them so that 'testimonials', 'history', and 'contact' are associated with 'about', and 'return policy', 'shipping', and 'contact' are associated with 'customer service'. Any help to point me in the right direction would be greatly appreciated. Thanks!

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  • check if a table exsist in where

    - by Luca Romagnoli
    This query generates an error because table2 doesn't exist: Select * FROM table WHERE table2.id IS NOT NULL Is there anything like this for check the table2 before apply the check on the id? Select * FROM table WHERE (EXIST(table2) AND table2.id IS NOT NULL) or not EXIST(table2) Thanks

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  • Selecting rows distinctively

    - by noway
    Lets assume my database table structure is something like | items | weight | |============|==========| | item_1 | 50 | | item_2 | 90 | | item_2 | 45 | | item_2 | 60 | | item_3 | 40 | In the select statement, I want to show an item only for once with the highest weight also ordered by height. So the result should be : | items | weight | |============|==========| | item_2 | 90 | | item_1 | 50 | | item_3 | 40 | I tried something like SELECT DISTINCT items, weight FROM mytable ORDER BY weight DESC but it didn't work because the results are actually distinct. How can I make that selection?

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  • Array "tree" creation from db table

    - by Tural Teyyuboglu
    Trying to create array tree for db driven navigation. Getting following errur: array_key_exists() expects exactly 2 parameters, 1 given on line if (!array_key_exists($tree[$parent]['children'][$id])) Function looks like that $tree = array(); $sql = "SELECT id, parent, name FROM menu WHERE parent ... etc.... "; $results = mysql_query($sql) or die(mysql_error()); while(list($id, $parent, $name) = mysql_fetch_assoc($results)) { $tree[$id] = array('name' => $name, 'children' => array(), 'parent' => $parent); if (!array_key_exists($tree[$parent]['children'][$id])) { $tree[$parent]['children'][$id] = $id; } } Db structure How can I fix that? Whats wrong in this function?

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  • php query cant figure out the problem

    - by Eat
    I dont get an error but it does not return me the row values as well. How can I address the problem? <?php //DATABASE $dbConn = mysql_connect($host,$username,$password); mysql_select_db($database,$dbConn); $SQL = mysql_query("SELECT N.*, C.CatID FROM News N INNER JOIN Categories C ON N.CatID = C.CatID WHERE N.Active = 1 ORDER BY DateEntered DESC"); while ( $Result = mysql_fetch_array($SQL) or die(mysql_error())) { $CatID[] = $Result[CatID]; $NewsName[] = $Result[NewsName]; $NewsShortDesc[] = $Result[NewsShortDesc]; } // mysql_free_result($Result); ?> <div class="toparticle"> <span class="section"><?=$CatID[0] ?> </span> <span class="headline"><?=$NewsName[0] ?></span> <p><?=$NewsShortDesc[0] ?></p> </div>

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  • Show parts of the result of an SQL statement using PHP

    - by mouthpiec
    I have an SQL query which returns a set of data (around 40-50 tuples). I would like to display the results 5 at a time on an HTML page using PHP. I already managed to have the right SELECT statement, but i am having problems to display the results 5 by 5 using a "more" button. Can you please help? Note that every time i call the query, the data is being randomized, so it is not possible to set limits and call the query again. I have to find the method to store the results somewhere, and then show them 5 by 5.

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  • Better mode for do a select with group by

    - by Luca Romagnoli
    Hi i've wrote a query that works: SELECT `comments`.* FROM `comments` RIGHT JOIN (SELECT MAX( id ) AS id, core_id, topic_id FROM comments GROUP BY core_id, topic_id order by id desc) comm ON comm.id = comments.id LIMIT 10 I want know if is possible and how rewrite it for get better performance. thanks

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