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  • restoring with mysqldump, but where is the data?

    - by Ole Media
    Ok, so I'm in need to restore a table and I do: mysqldump --opt database table_name < table_name.sql I hit enter and Done! Well, not really, when I go to see if there is anything on the table it show 0 records. I have look into the table_name.sql and I see two records. What am I doing wrong?

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  • Copying a database into a new database including structure and data

    - by Jason
    In phpMyAdmin under operations I can "Copy database to:" and select Structure and data CREATE DATABASE before copying Add AUTO_INCREMENT value I need to be able to do that without using phpMyAdmin. I know how to create the database and user. I have a source database that's a shell that I can work from so all I really need is the how to copy all the table structure and data part. (I know, the harder part) system() & exec() are not options for me which rules out mysqldump. (I think) How can I loop through each table and recreate it's structure and data? Is it just looping through the results of SHOW TABLES then for each table looping through DESCRIBE tablename Then, is there an easy way for getting the data copied?

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  • trying to redirect the php page is get id is empty ir does not exists.

    - by user570782
    <? include..... if ($picid != $_GET['picid']) || (empty($picid)) { echo "page not working"; } else { $picid = $_GET['picid']; $query = mysql_query("SELECT * FROM pic_info WHERE picid = 'picid1' ");// problem while($rows = mysql_fetch_assoc($query)): $picid = $rows['picid']; $title = $rows['title']; $link = $rows['link']; $description = $rows['description']; $movie_pic = $rows['movie_pic']; $source = $rows['source']; } $get_comment = mysql_query("SELECT * FROM comment WHERE picid ='$picid'");// work partially $comment_count = mysql_num_rows($get_comment); if ($comment_count>0) { messages = " "; while ($com = mysql_fetch_array($get_comment)){ $comment_id = $com['comment_id']; $name = $com['name']; $message = $com['message']; $time_post= $com['time_post']; $messages .= '<em> on ' .$time_post.'</em><b> '.$name.' said.....</b><br/> '.$message.'<hr/>'; // line with problem } } ?> i am stuck i am trying to say that if $_GET['picid']; is empty echo out error message or if the movid does not exist in the db echo out error message. when i run it i get an error. not sure if i am calling the correct function. what am i doing wrong please help

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  • I cant get a field on report from a view

    - by felipedz
    When I get a field, this work good. But, when get a field from a 'VIEW', is a problem because the code of a VIEW is: CREATE OR REPLACE VIEW tabla_clientes AS SELECT id_cliente,nombre, CONCAT('$ ',FORMAT(monto_a_favor,0), '???'), CONCAT('$ ',FORMAT(calcular_monto_por_cobrar_cliente(id_cliente),0)) FROM cliente; When I compile this. Appears errors from the name of fields. Description | Object ---------------------------------------------------------------------------- Syntax error, insert ";" to complete BlockStatements | ${CONCAT('$ ',FORMAT(monto_a_favor,0)} Syntax error on tokens, delete these tokens | ${CONCAT('$ ',FORMAT(monto_a_favor,0)} Syntax error on token ",", delete this token | ${CONCAT('$ ',FORMAT(monto_a_favor,0)} If I change the name at this field appears other error.

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  • PHP Code Problem...

    - by aamir Fayyaz
    function check_login($array_val) { $strQury = "Select * from tblsignup where usr_email ='".$array_val[0]."' and usr_password = '".$array_val[1]."'" ; $result = mysql_query($strQury); $row_user = mysql_fetch_array($result); if(mysql_num_rows($result)>0) { $msg = "true"; } else { $msg = "false"; } return $msg ; } The return value is Object id #1true???? what is object id#1?

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  • Is this possible with sql?

    - by Andrew
    Is it possible to do something like this: INSERT INTO table(col1, col2) VALUES(something_from_another_table, value); With something_from_another_table being a SQL command? Like, is there something I can do that's equivelant to: INSERT INTO table(col1, col2) VALUES((SELECT value FROM table2 WHERE id = 3), value);

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  • Xampp error on windows

    - by Deepak Kumar
    My problem is when i use xampp i see many error and when i use my web it has no error Notice: Undefined index: action in C:\xampp\htdocs\xyz\index.php on line 3 Notice: Undefined index: usNick in C:\xampp\htdocs\xyz\config.php on line 11 Notice: Use of undefined constant setname - assumed 'setname' in C:\xampp\htdocs\xyz\config.php on line 31 Notice: Use of undefined constant setname - assumed 'setname' in C:\xampp\htdocs\xyz\config.php on line 31 Notice: Undefined index: usNick in C:\xampp\htdocs\xyz\config.php on line 34 Notice: A session had already been started - ignoring session_start() in C:\xampp\htdocs\xyz\data.php on line 2 Notice: Undefined index: r in C:\xampp\htdocs\xyz\data.php on line 4 Notice: Undefined index: ucNick in C:\xampp\htdocs\xyz\data.php on line 8 I have tried many time changing things in Setting, Security, Privileges etc but nothing changed, I want to know if im missing something out Thanks

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  • A better understanding of the relations beetween database tables

    - by Nistor Alexandru
    Hi I am trying to get a better understanding of relational databases and there is something that I keep bumping into and don't understand.Let's take this two tables: In this case Login.ID is the primary key with auto_increment set and Profile.ID_LOGIN is the Foreign KEY.When a user is created and it's username and password is stored in the login database does the ID coresponding to the curesnt username and password get automaticly added into ID_LOGIN or do I have to create an SQL statement to do this? If I have to create a SQL statement how should I aproach adding the ID_LOGIN to make sure I am adding it corectly?

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  • Always get the correct datetime?

    - by Jesper Mansa
    I was wandering if there is a way/site/link whith the correct time? Not the servers datetime or the clients datetime. I'm using datetime to count down on my gaming site for when it is the users time to make a play. Users come from all ower the world so using the users client time would not match if its from the US to Europe. Then normally I would use the servers time, but somehow it skips 1.2 hours sometimes? I would like to make sure that everbody makes a timestamp from the same source and that source always is correct! Hoping for help and thanks in advance.

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  • Convert multiquery to a query using group by and so on

    - by ffffff
    -schema CREATE TABLE `ratings` ( `id` int(11) NOT NULL default '0', `rating` int(11) NOT NULL default '1', `rating_start` datetime NOT NULL default '0000-00-00 00:00:00', PRIMARY KEY (`id`) ) TYPE=MyISAM -myprogram.php foreach($ids as $id){ $sql = "SELECT rating FROM ratings WHERE id = '$id' AND rating_start >= NOW()"; $sql .= "ORDER BY rating_start DESC LIMIT 1;" $ret = $db->execute($id); } Can I teke same date from a Query? by using id IN (".implode(",",$ids).") and GROUP BY id

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  • Select rows where column LIKE dictionary word

    - by Gerve
    I have 2 tables: Dictionary - Contains roughly 36,000 words CREATE TABLE IF NOT EXISTS `dictionary` ( `word` varchar(255) NOT NULL, PRIMARY KEY (`word`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; Datas - Contains roughly 100,000 rows CREATE TABLE IF NOT EXISTS `datas` ( `ID` int(11) NOT NULL AUTO_INCREMENT, `hash` varchar(32) NOT NULL, `data` varchar(255) NOT NULL, `length` int(11) NOT NULL, `time` int(11) NOT NULL, PRIMARY KEY (`ID`), UNIQUE KEY `hash` (`hash`), KEY `data` (`data`), KEY `length` (`length`), KEY `time` (`time`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=105316 ; I would like to somehow select all the rows from datas where the column data contains 1 or more words. I understand this is a big ask, it would need to match all of these rows together in every combination possible, so it needs the best optimization. I have tried the below query, but it just hangs for ages: SELECT `datas`.*, `dictionary`.`word` FROM `datas`, `dictionary` WHERE `datas`.`data` LIKE CONCAT('%', `dictionary`.`word`, '%') AND LENGTH(`dictionary`.`word`) > 3 ORDER BY `length` ASC LIMIT 15 I have also tried something similar to the above with a left join, and on clause that specified the like statement.

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  • Random Alpha numeric generator

    - by AAA
    Hi, I want to give our users in the database a unique alpha-numeric id. I am using the code below, will this always generate a unique id? Below is the old and updated version of the code: New php: // Generate Guid function NewGuid() { $s = strtoupper(md5(uniqid("something",true))); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; Old PHP: // Generate Guid function NewGuid() { $s = strtoupper(md5(uniqid("something",true))); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; Will this first code guarantee uniqueness?

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  • GROUP BY on multiple columns

    - by Tams
    I have a table that looks like the following - Id Reference DateAttribute1 DateAttribute2 1 MMM005 2011-09-11 2012-09-10 2 MMM005 2012-06-13 2012-09-10 3 MMM006 2012-08-22 2012-09-10 4 MMM006 2012-08-22 2012-09-11 I have handle to the id values. I would like to query such that I get the following result Id Reference DateAttribute1 DateAttribute2 2 MMM005 2012-06-13 2012-09-10 4 MMM006 2012-08-22 2012-09-11 I would like my result to be grouped by reference and then 'DateAttribute1' and then 'DateAttribute2' as such - DateAttribute1 has a priority over DateAttribute2 as you can see above in the result. How should I write my query to fetch the results in the above manner? Any solution?

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  • Running a sharded DB from a single machine

    - by ming yeow
    This sounds kinda dumb, but I have a sharded DB that I no longer think I need to run on 2 machines, and would like to run on one single machine instead. Any ideas on how that can potentially be done? There are lots of resources on how i can achieve the converse, but very little on how this can be done

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  • Relating text fields to check boxes in Java

    - by Finzz
    This program requires the user to login and request a database to access. The program then gets a connection object, searches through the database storing the column names into a vector for later use. The problem comes with implementing text fields to allow the user to search for specific values within the database. I can get the check boxes and text fields to appear using a gridlayout and add them to a panel. How do I relate the text fields to their appropriate check box? I've tried adding them to a vector, but then they can't also be added to the panel as well. I've searched for a way to name the text fields as the loop cycles through the column names, but it seems impossible to do without having them declared ahead of time. This can't be done either, as it's impossible to determine the attributes that the user will request. I just need to be able to know the names of the text fields so I can test to see if the user entered information and perform the necessary logic. Let me know if you have to see the rest of the code to give an answer, but hopefully you get the general idea of what I'm trying to accomplish. Picture of UI: try { ResultSet r2 = con.getMetaData().getColumns("", "", rb.getText(), ""); colNames1 = new Vector<String>(); columns1 = new Vector<JCheckBox>(); while (r2.next()) { colNames1.add(r2.getString(4)); JCheckBox cb = new JCheckBox(r2.getString(4)); JTextField tf = new JTextField(10); columns1.add(cb); p3.add(cb); p3.add(tf); } }

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  • insert multiple rows into database from arrays

    - by Mark
    Hi, i need some help with inserting multiple rows from different arrays into my database. I am making the database for a seating plan, for each seating block there is 5 rows (A-E) with each row having 15 seats. my DB rows are seat_id, seat_block, seat_row, seat_number, therefore i need to add 15 seat_numbers for each seat_row and 5 seat_rows for each seat_block. I mocked it up with some foreach loops but need some help turning it into an (hopefully single) SQL statement. $blocks = array("A","B","C","D"); $seat_rows = array("A","B","C","D","E"); $seat_nums = array("1","2","3","4","5","6","7","8","9","10","11","12","13","14","15"); foreach($blocks as $block){ echo "<br><br>"; echo "Block: " . $block . " - "; foreach($seat_rows as $rows){ echo "Row: " . $rows . ", "; foreach($seat_nums as $seats){ echo "seat:" . $seats . " "; } } } Maybe there's a better way of doing it instead of using arrays? i just want to avoid writing an SQL statement that is over 100 lines long ;) (im using codeigniter too if anyone knows of a CI specific way of doing it but im not too bothered about that)

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  • Help constructing query - Compare columns and replace numbers

    - by Tommy
    I have a feeling that this query is pretty easy to construct, I just can't figure it out. I want to replace all numbers in table X column C, with numbers in table Z column A, where numbers from table X column C matches numbers in table Z column B. I hope that makes sense. Perhaps a little background information will make it clearer. I've converted from one CMS to another, and the module I used to convert mapped the ids to the new database. Table X column A is the new id's. Table X column B is the old id's. Table Z is the table for an image gallery that I migrated, and column C contains the id's of the images owners. Can anyone crack this nut?

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  • where id = multiple artists

    - by pixel
    Any time there is an update within my music community (song comment, artist update, new song added, yadda yadda yadda), a new row is inserted in my "updates" table. The row houses the artist id involved along with other information (what type of change, time and date, etc). My users have a "favorite artists" section where they can do just that -- mark artists as their favorites. As such, I'd like to create a new feature that shows the user the changes made to their various favorite artists. How should I be doing this efficiently? SELECT * FROM table_updates WHERE artist_id = 1 and artist_id = 500 and artist_id = 60032 Keep in mind, a user could have 43,000 of our artists marked as a favorite. Thoughts?

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  • Storing "binary" data type in C program

    - by puchu
    I need to create a program that converts one number system to other number systems. I used itoa in Windows (Dev C++) and my only problem is that I do not know how to convert binary numbers to other number systems. All the other number systems conversion work accordingly. Does this involve something like storing the input to be converted using %? Here is a snippet of my work: case 2: { printf("\nEnter a binary number: "); scanf("%d", &num); itoa(num,buffer,8); printf("\nOctal %s",buffer); itoa(num,buffer,10); printf("\nDecimal %s",buffer); itoa(num,buffer,16); printf("\nHexadecimal %s \n",buffer); break; } For decimal I used %d, for octal I used %o and for hexadecimal I used %x. What could be the correct one for binary? Thanks for future answers!

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  • How to access website CMS with only access to database

    - by user1741615
    I have a website that uses an "in-house" cms and I don't know the login details. The platform itself doesn't have the "reset your password" functionality. I do have access to ftp and phmyadmin and I found the SQL table containing the user details, but of course the password is MD5 encryption. I tried manually creating a user in php my admin and filling in a password encrypted in MD5 (used a md service online for that), but it still doesn't work. Does anybody know other tricks I can use? Thanks.

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  • How do I return the numeric value from a database query in PHP?

    - by Luke
    Hello, I am looking to retreive a numerical value from the database function adminLevel() { $q = "SELECT userlevel FROM ".TBL_USERS." WHERE id = '$_SESSION[id]'"; return mysql_query($q, $this->connection); } This is the SQL. I then wrote the following php/html: <?php $q = $database->adminLevel(); if ($q > 7) { ?> <a href="newleague.php">Create a new league</a> <? } ?> The problem I have is that the userlevel returned isn't affecting the if statement. It is always displayed. How do i get it to test the value of userlevel is greater than 7? Thanks

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  • Help creating a SQL Query

    - by Wes
    Somewhat new to SQL queries and I need a little help with my join. I am supplied with gid For each of these I need to grab name from table wp_ngg_gallery then join in table wp_ngg_pictures and grab field filename limit 1 order DESC by field imagedate Anyone able to help?

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