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  • How to repeatedly show a Dialog with PyGTK / Gtkbuilder?

    - by Julian
    I have created a PyGTK application that shows a Dialog when the user presses a button. The dialog is loaded in my __init__ method with: builder = gtk.Builder() builder.add_from_file("filename") builder.connect_signals(self) self.myDialog = builder.get_object("dialog_name") In the event handler, the dialog is shown with the command self.myDialog.run(), but this only works once, because after run() the dialog is automatically destroyed. If I click the button a second time, the application crashes. I read that there is a way to use show() instead of run() where the dialog is not destroyed, but I feel like this is not the right way for me because I would like the dialog to behave modally and to return control to the code only after the user has closed it. Is there a simple way to repeatedly show a dialog using the run() method using gtkbuilder? I tried reloading the whole dialog using the gtkbuilder, but that did not really seem to work, the dialog was missing all child elements (and I would prefer to have to use the builder only once, at the beginning of the program). [SOLUTION] As pointed out by the answer below, using hide() does the trick. But one has to take care that the dialog is in fact destroyed if one does not catch its "delete-event". A simple example that works is: import pygtk import gtk class DialogTest: def rundialog(self, widget, data=None): self.dia.show_all() result = self.dia.run() def destroy(self, widget, data=None): gtk.main_quit() def closedialog(self, widget, data=None): self.dia.hide() return True def __init__(self): self.window = gtk.Window(gtk.WINDOW_TOPLEVEL) self.window.connect("destroy", self.destroy) self.dia = gtk.Dialog('TEST DIALOG', self.window, gtk.DIALOG_MODAL | gtk.DIALOG_DESTROY_WITH_PARENT) self.dia.vbox.pack_start(gtk.Label('This is just a Test')) self.dia.connect("delete-event", self.closedialog) self.button = gtk.Button("Run Dialog") self.button.connect("clicked", self.rundialog, None) self.window.add(self.button) self.button.show() self.window.show() if __name__ == "__main__": testApp = DialogTest() gtk.main()

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  • numpy.equal with string values

    - by Morgoth
    The numpy.equal function does not work if a list or array contains strings: >>> import numpy >>> index = numpy.equal([1,2,'a'],None) Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: function not supported for these types, and can't coerce safely to supported types What is the easiest way to workaround this without looping through each element? In the end, I need index to contain a boolean array indicating which elements are None.

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  • How do i add a new object with suds?

    - by Jerome
    I'm trying to use suds but have so far been unsuccessful at figuring this out. Hopefully it's something simple that i'm missing. Any help would be highly appreciated. This is supposed to be the raw soap message that i need to achieve: <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:api="http://api.service.apimember.soapservice.com/"> <soapenv:Header/> <soapenv:Body> <api:insertOrUpdateMemberByObj> <token>t67GFCygjhkjyUy8y9hkjhlkjhuii</token> <member> <dynContent> <entry> <key>FIRSTNAME</key> <value>hhhhbbbbb</value> </entry> </dynContent> <email>[email protected]</email> </member> </api:insertOrUpdateMemberByObj> </soapenv:Body> </soapenv:Envelope> So i use suds to create the member object: member = client.factory.create('member') produces: (apiMember){ attributes = (attributes){ entry[] = <empty> } } How exactly do i append an 'entry'? I try this: member.attributes.entry.append({'key':'FIRSTNAME','value':'test'}) and that produces this: (apiMember){ attributes = (attributes){ entry[] = { value = "test" key = "FIRSTNAME" }, } } However, what i actually need is: (apiMember){ attributes = (attributes){ entry[] = (entry) { value = "test" key = "FIRSTNAME" }, } } How do i achieve this?

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  • How can I login in a website with Pyhon?

    - by Shady
    How can I do it? I was trying to enter some specified link (with urllib), but to do it, I need to log. I have this source from the site <form id="login-form" action="auth/login" method="post"> <div> <!--label for="rememberme">Remember me</label><input type="checkbox" class="remember" checked="checked" name="remember me" /--> <label for="email" id="email-label" class="no-js">Email</label> <input id="email-email" type="text" name="handle" value="" autocomplete="off" /> <label for="combination" id="combo-label" class="no-js">Combination</label> <input id="password-clear" type="text" value="Combination" autocomplete="off" /> <input id="password-password" type="password" name="password" value="" autocomplete="off" /> <input id="sumbitLogin" class="signin" type="submit" value="Sign In" /> It's possible?

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  • Help calling class from a class above.

    - by wtzolt
    Hello, How to call from class oneThread: back to class fun:? As in, address a class written below. Is it possible? class oneThread(threading.Thread): def __init__(self): threading.Thread.__init__(self) self.start() def run(self): print "1" time.sleep(1) print "2" time.sleep(1) print "3" self.wTree.get_widget("entryResult").set_text("Done with One.") # How to call from here back to class fun, which of course is below...? class fun: wTree = None def __init__( self ): self.wTree = gtk.glade.XML( "main.glade" ) self.wTree.signal_autoconnect( {"on_buttonOne" : self.one} ) gtk.main() def one(self, widget): oneThread(); gtk.gdk.threads_init() do=fun()

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  • Get particular row as series from pandas dataframe

    - by Pratyush
    How do we get a particular filtered row as series? Example dataframe: >>> df = pd.DataFrame({'date': [20130101, 20130101, 20130102], 'location': ['a', 'a', 'c']}) >>> df date location 0 20130101 a 1 20130101 a 2 20130102 c I need to select the row where location is c as a series. I tried: row = df[df["location"] == "c"].head(1) # gives a dataframe row = df.ix[df["location"] == "c"] # also gives a dataframe with single row In either cases I can't the row as series.

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  • socket.accept error 24: To many open files

    - by Creotiv
    I have a problem with open files under my Ubuntu 9.10 when running server in Python2.6 And main problem is that, that i don't know why it so.. I have set ulimit -n = 999999 net.core.somaxconn = 999999 fs.file-max = 999999 and lsof gives me about 12000 open files when server is running. And also i'm using epoll. But after some time it's start giving exeption: File "/usr/lib/python2.6/socket.py", line 195, in accept error: [Errno 24] Too many open files And i don't know how it can reach file limit when it isn't reached. Thanks for help)

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  • how to speed up the code??

    - by kaushik
    i have very huge code about 600 lines plus. cant post the whole thing here. but a particular code snippet is taking so much time,leading to problems. here i post that part of code please tell me what to do speed up the processing.. please suggest the part which may be the reason and measure to improve them if this small part of code is understandable. using_data={} def join_cost(a , b): global using_data #print a #print b save_a=[] save_b=[] print 1 #for i in range(len(m)): #if str(m[i][0])==str(a): save_a=database_index[a] #for i in range(len(m)): # if str(m[i][0])==str(b): #print 'save_a',save_a #print 'save_b',save_b print 2 save_b=database_index[b] using_data[save_a[0]]=save_a s=str(save_a[1]).replace('phone','text') s=str(s)+'.pm' p=os.path.join("c:/begpython/wavnk/",s) x=open(p , 'r') print 3 for i in range(6): x.readline() k2='a' j=0 o=[] while k2 is not '': k2=x.readline() k2=k2.rstrip('\n') oj=k2.split(' ') o=o+[oj] #print o[j] j=j+1 #print j #print o[2][0] temp=long(1232332) end_time=save_a[4] #print end_time k=(j-1) for i in range(k): diff=float(o[i][0])-float(end_time) if diff<0: diff=diff*(-1) if temp>diff: temp=diff pm_row=i #print pm_row #print temp #print o[pm_row] #pm_row=3 q=[] print 4 l=str(p).replace('.pm','.mcep') z=open(l ,'r') for i in range(pm_row): z.readline() k3=z.readline() k3=k3.rstrip('\n') q=k3.split(' ') #print q print 5 s=str(save_b[1]).replace('phone','text') s=str(s)+'.pm' p=os.path.join("c:/begpython/wavnk/",s) x=open(p , 'r') for i in range(6): x.readline() k2='a' j=0 o=[] while k2 is not '': k2=x.readline() k2=k2.rstrip('\n') oj=k2.split(' ') o=o+[oj] #print o[j] j=j+1 #print j #print o[2][0] temp=long(1232332) strt_time=save_b[3] #print strt_time k=(j-1) for i in range(k): diff=float(o[i][0])-float(strt_time) if diff<0: diff=diff*(-1) if temp>diff: temp=diff pm_row=i #print pm_row #print temp #print o[pm_row] #pm_row=3 w=[] l=str(p).replace('.pm','.mcep') z=open(l ,'r') for i in range(pm_row): z.readline() k3=z.readline() k3=k3.rstrip('\n') w=k3.split(' ') #print w cost=0 for i in range(12): #print q[i] #print w[i] h=float(q[i])-float(w[i]) cost=cost+math.pow(h,2) j_cost=math.sqrt(cost) #print cost return j_cost def target_cost(a , b): a=(b+1)*3 b=(a+1)*2 t_cost=(a+b)*5/2 return t_cost r1='shht:ra_77' r2='grx_18' g=[] nodes=[] nodes=nodes+[[r1]] for i in range(len(y_in_db_format)): g=y_in_db_format[i] #print g #print g[0] g.remove(str(g[0])) nodes=nodes+[g] nodes=nodes+[[r2]] print nodes print "lenght of nodes",len(nodes) lists=[] #lists=lists+[r1] for i in range(len(nodes)): for j in range(len(nodes[i])): lists=lists+[nodes[i][j]] #lists=lists+[r2] print lists distance={} for i in range(len(lists)): if i==0: distance[str(lists[i])]=0 else: distance[str(lists[i])]=long(123231223) #print distance group_dist=[] infinity=long(123232323) for i in range(len(nodes)): distances=[] for j in range(len(nodes[i])): #distances=[] if i==0: distances=distances+[[nodes[i][j], 0]] else: distances=distances+[[nodes[i][j],infinity]] group_dist=group_dist+[distances] #print distances print "group_distances",group_dist #print "check",group_dist[0][0][1] #costs={} #for i in range(len(lists)): #if i==0: # costs[str(lists[i])]=1 #else: # costs[str(lists[i])]=get_selfcost(lists[i]) path=[] for i in range(len(nodes)): mini=[] if i!=(len(nodes)-1): #temp=long(123234324) #Now calculate the cost between the current node and each of its neighbour for k in range(len(nodes[(i+1)])): for j in range(len(nodes[i])): current=nodes[i][j] #print "current_node",current j_distance=join_cost( current , nodes[i+1][k]) #t_distance=target_cost( current , nodes[i+1][k]) t_distance=34 #print distance #print "distance between current and neighbours",distance total_distance=(.5*(float(group_dist[i][j][1])+float(j_distance))+.5*(float(t_distance))) #print "total distance between the intial_nodes and current neighbour",total_distance if int(group_dist[i+1][k][1]) > int(total_distance): group_dist[i+1][k][1]=total_distance #print "updated distance",group_dist[i+1][k][1] a=current #print "the neighbour",nodes[i+1][k],"updated the value",a mini=mini+[[str(nodes[i+1][k]),a]] print mini

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  • how to speed up the code??

    - by kaushik
    in my program i have a method which requires about 4 files to be open each time it is called,as i require to take some data.all this data from the file i have been storing in list for manupalation. I approximatily need to call this method about 10,000 times.which is making my program very slow? any method for handling this files in a better ways and is storing the whole data in list time consuming what is better alternatives for list? I can give some code,but my previous question was closed as that only confused everyone as it is a part of big program and need to be explained completely to understand,so i am not giving any code,please suggest ways thinking this as a general question... thanks in advance

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  • What is the Simplest Possible Payment Gateway to Implement? (using Django)

    - by b14ck
    I'm developing a web application that will require users to either make one time deposits of money into their account, or allow users to sign up for recurring billing each month for a certain amount of money. I've been looking at various payment gateways, but most (if not all) of them seem complex and difficult to get working. I also see no real active Django projects which offer simple views for making payments. Ideally, I'd like to use something like Amazon FPS, so that I can see online transaction logs, refund money, etc., but I'm open to other things. I just want the EASIEST possible payment gateway to integrate with my site. I'm not looking for anything fancy, whatever does the job, and requires < 10 hours to get working from start to finish would be perfect. I'll give answer points to whoever can point out a good one. Thanks!

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  • SUDS rendering a duplicate node and wrapping everything in it

    - by PylonsN00b
    Here is my code: #Make the SOAP connection url = "https://api.channeladvisor.com/ChannelAdvisorAPI/v1/InventoryService.asmx?WSDL" headers = {'Content-Type': 'text/xml; charset=utf-8'} ca_client_inventory = Client(url, location="https://api.channeladvisor.com/ChannelAdvisorAPI/v1/InventoryService.asmx", headers=headers) #Make the SOAP headers login = ca_client_inventory.factory.create('APICredentials') login.DeveloperKey = 'REMOVED' login.Password = 'REMOVED' #Attach the headers ca_client_inventory.set_options(soapheaders=login) synch_inventory_item_list = ca_client_inventory.factory.create('SynchInventoryItemList') synch_inventory_item_list.accountID = "REMOVED" array_of_inventory_item_submit = ca_client_inventory.factory.create('ArrayOfInventoryItemSubmit') for product in products: inventory_item_submit = ca_client_inventory.factory.create('InventoryItemSubmit') inventory_item_list = get_item_list(product) inventory_item_submit = [inventory_item_list] array_of_inventory_item_submit.InventoryItemSubmit.append(inventory_item_submit) synch_inventory_item_list.itemList = array_of_inventory_item_submit #Call that service baby! ca_client_inventory.service.SynchInventoryItemList(synch_inventory_item_list) Here is what it outputs: <?xml version="1.0" encoding="UTF-8"?> <SOAP-ENV:Envelope xmlns:ns0="http://api.channeladvisor.com/webservices/" xmlns:ns1="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:tns="http://api.channeladvisor.com/webservices/" xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/"> <SOAP-ENV:Header> <tns:APICredentials> <tns:DeveloperKey>REMOVED</tns:DeveloperKey> <tns:Password>REMOVED</tns:Password> </tns:APICredentials> </SOAP-ENV:Header> <ns1:Body> <ns0:SynchInventoryItemList> <ns0:accountID> <ns0:accountID>REMOVED</ns0:accountID> <ns0:itemList> <ns0:InventoryItemSubmit> <ns0:Sku>1872</ns0:Sku> <ns0:Title>The Big Book Of Crazy Quilt Stitches</ns0:Title> <ns0:Subtitle></ns0:Subtitle> <ns0:Description>Embellish the seams and patches of crazy quilt projects with over 75 embroidery stitches and floral motifs. You&apos;ll use this handy reference book again and again to dress up wall hangings, pillows, sachets, clothing, and other nostalgic creations.</ns0:Description> <ns0:Weight>4</ns0:Weight> <ns0:FlagStyle/> <ns0:IsBlocked xsi:nil="true"/> <ns0:ISBN></ns0:ISBN> <ns0:UPC>028906018721</ns0:UPC> <ns0:EAN></ns0:EAN> <ns0:QuantityInfo> <ns0:UpdateType>UnShipped</ns0:UpdateType> <ns0:Total>0</ns0:Total> </ns0:QuantityInfo> <ns0:PriceInfo> <ns0:Cost>0.575</ns0:Cost> <ns0:RetailPrice xsi:nil="true"/> <ns0:StartingPrice xsi:nil="true"/> <ns0:ReservePrice xsi:nil="true"/> <ns0:TakeItPrice>6.95</ns0:TakeItPrice> <ns0:SecondChanceOfferPrice xsi:nil="true"/> <ns0:StorePrice>6.95</ns0:StorePrice> </ns0:PriceInfo> <ns0:ClassificationInfo> <ns0:Name>Books</ns0:Name> <ns0:AttributeList> <ns0:ClassificationAttributeInfo> <ns0:Name>Designer/Author</ns0:Name> <ns0:Value>Patricia Eaton</ns0:Value> </ns0:ClassificationAttributeInfo> <ns0:ClassificationAttributeInfo> <ns0:Name>Trim Size</ns0:Name> <ns0:Value></ns0:Value> </ns0:ClassificationAttributeInfo> <ns0:ClassificationAttributeInfo> <ns0:Name>Binding</ns0:Name> <ns0:Value>Leaflet</ns0:Value> </ns0:ClassificationAttributeInfo> <ns0:ClassificationAttributeInfo> <ns0:Name>Release Date</ns0:Name> <ns0:Value>11/1/1999 0:00:00</ns0:Value> </ns0:ClassificationAttributeInfo> <ns0:ClassificationAttributeInfo> <ns0:Name>Skill Level</ns0:Name> <ns0:Value></ns0:Value> </ns0:ClassificationAttributeInfo> <ns0:ClassificationAttributeInfo> <ns0:Name>Pages</ns0:Name> <ns0:Value>20</ns0:Value> </ns0:ClassificationAttributeInfo> <ns0:ClassificationAttributeInfo> <ns0:Name>Projects</ns0:Name> <ns0:Value></ns0:Value> </ns0:ClassificationAttributeInfo> </ns0:AttributeList> </ns0:ClassificationInfo> <ns0:ImageList> <ns0:ImageInfoSubmit> <ns0:PlacementName>ITEMIMAGEURL1</ns0:PlacementName> <ns0:FilenameOrUrl>1872.jpg</ns0:FilenameOrUrl> </ns0:ImageInfoSubmit> </ns0:ImageList> </ns0:InventoryItemSubmit> </ns0:itemList> </ns0:accountID> </ns0:SynchInventoryItemList> </ns1:Body> </SOAP-ENV:Envelope> See how it creates the accountID node twice and wraps the whole thing in it? WHY? How do I make it stop that?!

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  • How to reload Django models without losing my locals in an interactive session?

    - by Gj
    I'm doing some research with an interactive shell and using a Django app (shell_plus) for storing data and browsing it using the convenient admin. Occasionally I add or change some of the app models, and run a syncdb (or South migration when changing a model). The changes to the models don't take effect in my interactive session even if I re-import the app models. Thus I'm forced to restart the shell_plus and lose my precious locals() in the process. Is there any way to reload the models during a session? Thanks!!

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  • Django: Is there any way to have "unique for date range"?

    - by tomwolber
    If my model for Items is: class Item(models.Model): name = models.CharField(max_length=500) startDate = models.DateField("Start Date", unique="true") endDate = models.DateField("End Date") Each Item needs to have a unique date range. for example, if i create an Item that has a date range of June 1st to June 8th, how can I keep and Item with a date range of June 3rd to June 5th from being created (or render an error with template logic)?

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  • sqlite3 'database is locked' won't go away with retries

    - by Azarias
    I have a sqlite3 database that is accessed by a few threads (3-4). I am aware of the general limitations of sqlite3 with regards to concurrency as stated http://www.sqlite.org/faq.html#q6 , but I am convinced that is not the problem. All of the threads both read and write from this database. Whenever I do a write, I have the following construct: try: Cursor.execute(q, params) Connection.commit() except sqlite3.IntegrityError: Notify except sqlite3.OperationalError: print sys.exc_info() print("DATABASE LOCKED; sleeping for 3 seconds and trying again") time.sleep(3) Retry On some runs, I won't even hit this block, but when I do, it never comes out of it (keeps retrying, but I keep getting the 'database is locked' error from exc_info. If I understand the reader/writer lock usage correctly, some amount of waiting should help with the contention. What this sounds like is deadlock, but I do not use any transactions in my code, and every SELECT or INSERT is simply a one off. Some threads, however, keep the same connection when they do their operation (which includes a mix of SELECTS and INSERTS and other modifiers). I would appericiate it if you could shade a light on this, and also ways around fixing it (besides using a different database engine.)

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  • How to reset Scrapy parameters? (always running under same parameters)

    - by Jean Ventura
    I've been running my Scrapy project with a couple of accounts (the project scrapes a especific site that requieres login credentials), but no matter the parameters I set, it always runs with the same ones (same credentials). I'm running under virtualenv. Is there a variable or setting I'm missing? Edit: It seems that this problem is Twisted related. Even when I run: scrapy crawl -a user='user' -a password='pass' -o items.json -t json SpiderName I still get an error saying: ERROR: twisted.internet.error.ReactorNotRestartable And all the information I get, is the last 'succesful' run of the spider.

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  • django on appengine

    - by aks
    I am impressed with django.Am am currenty a java developer.I want to make some cool websites for myself but i want to host it in some third pary environmet. Now the question is can i host the django application on appengine?If yes , how?? Are there any site built using django which are already hosted on appengine?

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  • Scrape zipcode table for different urls based on county

    - by Dr.Venkman
    I used lxml and ran into a wall as my new computer wont install lxml and the code doesnt work. I know this is simple - maybe some one can help with a beautiful soup script. this is my code: import codecs import lxml as lh from selenium import webdriver import time import re results = [] city = [ 'amador'] state = [ 'CA'] for state in states: for city in citys: browser = webdriver.Firefox() link2 = 'http://www.getzips.com/cgi-bin/ziplook.exe?What=3&County='+ city +'&State=' + state + '&Submit=Look+It+Up' browser.get(link2) bcontent = browser.page_source zipcode = bcontent[bcontent.find('<td width="15%"'):bcontent.find('<p>')+0] if len(zipcode) > 0: print zipcode else: print 'none' browser.quit() Thanks for the help

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  • In plain English, what are Django generic views?

    - by allyourcode
    The first two paragraphs of this page explain that generic views are supposed to make my life easier, less monotonous, and make me more attractive to women (I made up that last one): http://docs.djangoproject.com/en/dev/topics/generic-views/#topics-generic-views I'm all for improving my life, but what do generic views actually do? It seems like lots of buzzwords are being thrown around, which confuse more than they explain. Are generic views similar to scaffolding in Ruby on Rails? The last bullet point in the intro seems to indicate this. Is that an accurate statement?

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  • Estimating the boundary of arbitrarily distributed data

    - by Dave
    I have two dimensional discrete spatial data. I would like to make an approximation of the spatial boundaries of this data so that I can produce a plot with another dataset on top of it. Ideally, this would be an ordered set of (x,y) points that matplotlib can plot with the plt.Polygon() patch. My initial attempt is very inelegant: I place a fine grid over the data, and where data is found in a cell, a square matplotlib patch is created of that cell. The resolution of the boundary thus depends on the sampling frequency of the grid. Here is an example, where the grey region are the cells containing data, black where no data exists. OK, problem solved - why am I still here? Well.... I'd like a more "elegant" solution, or at least one that is faster (ie. I don't want to get on with "real" work, I'd like to have some fun with this!). The best way I can think of is a ray-tracing approach - eg: from xmin to xmax, at y=ymin, check if data boundary crossed in intervals dx y=ymin+dy, do 1 do 1-2, but now sample in y An alternative is defining a centre, and sampling in r-theta space - ie radial spokes in dtheta increments. Both would produce a set of (x,y) points, but then how do I order/link neighbouring points them to create the boundary? A nearest neighbour approach is not appropriate as, for example (to borrow from Geography), an isthmus (think of Panama connecting N&S America) could then close off and isolate regions. This also might not deal very well with the holes seen in the data, which I would like to represent as a different plt.Polygon. The solution perhaps comes from solving an area maximisation problem. For a set of points defining the data limits, what is the maximum contiguous area contained within those points To form the enclosed area, what are the neighbouring points for the nth point? How will the holes be treated in this scheme - is this erring into topology now? Apologies, much of this is me thinking out loud. I'd be grateful for some hints, suggestions or solutions. I suspect this is an oft-studied problem with many solution techniques, but I'm looking for something simple to code and quick to run... I guess everyone is, really! Cheers, David

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  • How to inject a key string to andoid device through ADB?

    - by Nandi
    Hi, Can somebody help me for the following. I want to select a perticular string in the list displayed in android phone. If i take example of phone book. i want to pass a person name to the device using adb interface and that name should get highlighted in the list. I tried all adb commands for this but could pass string and key events to the screen but not able to select the respective string. please help. Thanks in advance.

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  • How to generate lots of redundant ajax elements like checkboxes and pulldowns in Django?

    - by iJames
    Hello folks. I've been getting lots of answers from stackoverflow now that I'm in Django just be searching. Now I hope my question will also create some value for everybody. In choosing Django, I was hoping there was some similar mechanism to the way you can do partials in ROR. This was going to help me in two ways. One was in generating repeating indexed forms or form elements, and also in rendering only a piece of the page on the round trip. I've done a little bit of that by using taconite with a simple URL click but now I'm trying to get more advanced. This will focus on the form issue which boils down to how to iterate over a secondary object. If I have a list of photo instances, each of which has a couple of parameters, let's say a size and a quantity. I want to generate form elements for each photo instance separately. But then I have two lists I want to iterate on at the same time. Context: photos : Photo.objects.all() and forms = {} for photo in photos: forms[photo.id] = PhotoForm() In other words we've got a list of photo objects and a dict of forms based on the photo.id. Here's an abstraction of the template: {% for photo in photos %} {% include "photoview.html" %} {% comment %} So here I want to use the photo.id as an index to get the correct form. So that each photo has its own form. I would want to have a different action and each form field would be unique. Is that possible? How can I iterate on that? Thanks! {% endcomment %} Quantity: {{ oi.quantity }} {{ form.quantity }} Dimensions: {{ oi.size }} {{ form.size }} {% endfor %} What can I do about this simple case. And how can I make it where every control is automatically updating the server instead of using a form at all? Thanks! James

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