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  • Django - The included urlconf doesn't have any patterns in it

    - by unsorted
    My website, which was working before, suddenly started breaking with the error "ImproperlyConfigured at / The included urlconf resume.urls doesn't have any patterns in it" The project base is called resume. In settings.py I have set ROOT_URLCONF = 'resume.urls' Here's my resume.urls, which sits in the project root directory. from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^resume/', include('resume.foo.urls')), # Uncomment the admin/doc line below and add 'django.contrib.admindocs' # to INSTALLED_APPS to enable admin documentation: (r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: (r'^admin/', include(admin.site.urls)), (r'^accounts/login/$', 'django.contrib.auth.views.login'), #(r'^employer/', include(students.urls)), (r'^ajax/', include('urls.ajax')), (r'^student/', include('students.urls')), (r'^club/(?P<object_id>\d+)/$', 'resume.students.views.club_detail'), (r'^company/(?P<object_id>\d+)/$', 'resume.students.views.company_detail'), (r'^program/(?P<object_id>\d+)/$', 'resume.students.views.program_detail'), (r'^course/(?P<object_id>\d+)/$', 'resume.students.views.course_detail'), (r'^career/(?P<object_id>\d+)/$', 'resume.students.views.career_detail'), (r'^site_media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': 'C:/code/django/resume/media'}), ) I have a folder called urls and a file ajax.py inside. (I also created a blank init.py in the same folder so that urls would be recognized.) This is ajax.py. from django.conf.urls.defaults import * urlpatterns = patterns('', (r'^star/(?P<object_id>\d+)$', 'resume.students.ajax-calls.star'), ) Anyone know what's wrong? This is driving me crazy. Thanks,

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  • CentOS: make python 2.6 see django

    - by NP
    In a harrowing attempt to get mod_wsgi to run on CentOS 5.4, I've added python 2.6 as an optional library following the instructions here. The configuration seems fine except that when trying to ping the server the Apache log prints this error: mod_wsgi (pid=20033, process='otalo', application='127.0.0.1|'): Loading WSGI script '...django.wsgi'. [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] mod_wsgi (pid=20033): Target WSGI script '...django.wsgi' cannot be loaded as Python module. [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] mod_wsgi (pid=20033): Exception occurred processing WSGI script '...django.wsgi'. [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] Traceback (most recent call last): [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] File "...django.wsgi", line 8, in [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] import django.core.handlers.wsgi [Sat Mar 27 16:11:45 2010] [error] [client 171.66.52.218] ImportError: No module named django.core.handlers.wsgi when I go to my python2.6 install's command line and try 'import django', the module is not found (ImportError). However, my default python 2.4 installation (still working fine) is able to import successfully. How do I point python 2.6 to django? Thanks in advance.

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  • Django choking oddly on some static media

    - by Edan Maor
    My situation: I'm serving static media via Django on my dev machine. On some files that I try and load, I get back this error: Traceback: File "c:\Program Files\Python26\Lib\site-packages\django\core\handlers\base.py" in get_response 92. response = callback(request, *callback_args, **callback_kwargs) File "E:\Stack2Blog\src.hg\stack2blog\..\stack2blog\stack2blogapp\views.py" in userpage 71. so_user = site.user(userid) File "E:\Stack2Blog\src.hg\stack2blog\..\stack2blog\stack2blogapp\stackexchange.py" in user 476. u, = self.users((nid,), **kw) File "E:\Stack2Blog\src.hg\stack2blog\..\stack2blog\stack2blogapp\stackexchange.py" in users 481. return self._get(User, ids, 'users', kw) File "E:\Stack2Blog\src.hg\stack2blog\..\stack2blog\stack2blogapp\stackexchange.py" in _get 471. return self.build(root, typ, coll, kw) File "E:\Stack2Blog\src.hg\stack2blog\..\stack2blog\stack2blogapp\stackexchange.py" in build 448. json = self._request(url, kw) File "E:\Stack2Blog\src.hg\stack2blog\..\stack2blog\stack2blogapp\stackexchange.py" in _request 422. dump = json.load(data) File "c:\Program Files\Python26\lib\json\__init__.py" in load 264. return loads(fp.read(), Exception Type: AttributeError at /userpage/362498 Exception Value: 'str' object has no attribute 'read' I've traced it to specific files which don't work (by going to their specific urls). Here's the odd part: changing the filename of the files makes them suddenly work. For example, I had a file called 'post.jpg', which gave this error. I renamed it to 'pos.jpg' and it worked. Back to 'post.jpg' and it gives the same error.

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  • Declare models elsewhere than in "models.py"

    - by sebpiq
    Hi ! I have an application that splits models into different files. Actually the folder looks like : >myapp __init__.py models.py >hooks ... ... myapp don't care about what's in the hooks, folder, except that there are models, and that they have to be declared somehow. So, I put this in myapp.__init__.py : from django.conf import settings for hook in settings.HOOKS : try : __import__(hook) except ImportError as e : print "Got import err !", e #where HOOKS = ("myapp.hooks.a_super_hook1", ...) The problem is that it doesn't work when I run syncdb(and throws some strange "Got import err !"... strange considering that it's related to another module of my program that I don't even import anywhere :/ ) ! So I tried successively : 1) for hook in settings.HOOKS : try : exec ("from %s import *" % hook) doesn't work either : syncdb doesn't install the models in hooks 2) from myapp.hooks.a_super_hook1 import * This works 3) exec("from myapp.hooks.a_super_hook1 import *") This works to So I checked that in the test 1), the statement executed is the same than in tests 2) and 3), and it is exactly the same ... Any idea ???

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  • Django: DatabaseError column does not exist

    - by Rosarch
    I'm having a problem with Django 1.2.4. Here is a model: class Foo(models.Model): # ... ftw = models.CharField(blank=True) bar = models.ForeignKey(Bar) Right after flushing the database, I use the shell: Python 2.6.6 (r266:84292, Sep 15 2010, 15:52:39) [GCC 4.4.5] on linux2 Type "help", "copyright", "credits" or "license" for more information. (InteractiveConsole) >>> from apps.foo.models import Foo >>> Foo.objects.all() Traceback (most recent call last): File "<console>", line 1, in <module> File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 67, in __repr__ data = list(self[:REPR_OUTPUT_SIZE + 1]) File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 82, in __len__ self._result_cache.extend(list(self._iter)) File "/usr/local/lib/python2.6/dist-packages/django/db/models/query.py", line 271, in iterator for row in compiler.results_iter(): File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/compiler.py", line 677, in results_iter for rows in self.execute_sql(MULTI): File "/usr/local/lib/python2.6/dist-packages/django/db/models/sql/compiler.py", line 732, in execute_sql cursor.execute(sql, params) File "/usr/local/lib/python2.6/dist-packages/django/db/backends/util.py", line 15, in execute return self.cursor.execute(sql, params) File "/usr/local/lib/python2.6/dist-packages/django/db/backends/postgresql_psycopg2/base.py", line 44, in execute return self.cursor.execute(query, args) DatabaseError: column foo_foo.bar_id does not exist LINE 1: ...t_omg", "foo_foo"."ftw", "foo_foo... What am I doing wrong here?

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  • Declaring models elsewhere than in "models.py" AND dynamically

    - by sebpiq
    Hi ! I have an application that splits models into different files. Actually the folder looks like : >myapp __init__.py models.py >hooks ... ... myapp don't care about what's in the hooks, folder, except that there are models, and that they have to be declared somehow. So, I put this in myapp.__init__.py : from django.conf import settings for hook in settings.HOOKS : try : __import__(hook) except ImportError as e : print "Got import err !", e #where settings.HOOKS = ("myapp.hooks.a_super_hook1", ...) The problem is that it doesn't work when I run syncdb(and throws some strange "Got import err !"... strange considering that it's related to another module of my program that I don't even import anywhere :/ ) ! So I tried successively : 1) for hook in settings.HOOKS : try : exec ("from %s import *" % hook) - doesn't work either : syncdb doesn't install the models in hooks 2) from myapp.hooks.a_super_hook1 import * - This works 3) exec("from myapp.hooks.a_super_hook1 import *") - This works to So I checked that in the test 1), the statement executed is the same than in tests 2) and 3), and it is exactly the same ... Any idea ???

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  • Configure Django project in a subdirectory using mod_python. Admin not working.

    - by David
    HI guys. I was trying to configure my django project in a subdirectory of the root, but didn't get things working.(LOcally it works perfect). I followed the django official django documentarion to deploy a project with mod_python. The real problem is that I am getting "Page not found" errors, whenever I try to go to the admin or any view of my apps. Here is my python.conf file located in /etc/httpd/conf.d/ in Fedora 7 LoadModule python_module modules/mod_python.so SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE mysite.settings PythonOption django.root /mysite PythonDebug On PythonPath "['/var/www/vhosts/mysite.com/httpdocs','/var/www/vhosts/mysite.com/httpdocs/mysite'] + sys.path" I know /var/www/ is not the best place to put my django project, but I just want to send a demo of my work in progress to my customer, later I will change the location. For example. If I go to www.domain.com/mysite/ I get the index view I configured in mysite.urls. But I cannot access to my app.urls (www.domain.com/mysite/app/) and any of the admin.urls.(www.domain.com/mysite/admin/) Here is mysite.urls: urlpatterns = patterns('', url(r'^admin/password_reset/$', 'django.contrib.auth.views.password_reset', name='password_reset'), (r'^password_reset/done/$', 'django.contrib.auth.views.password_reset_done'), (r'^reset/(?P<uidb36>[0-9A-Za-z]+)-(?P<token>.+)/$', 'django.contrib.auth.views.password_reset_confirm'), (r'^reset/done/$', 'django.contrib.auth.views.password_reset_complete'), (r'^$', 'app.views.index'), (r'^admin/', include(admin.site.urls)), (r'^app/', include('mysite.app.urls')), (r'^photologue/', include('photologue.urls')), ) I also tried changing admin.site.urls with ''django.contrib.admin.urls' , but it didn't worked. I googled a lot to solve this problem and read how other developers configure their django project, but didn't find too much information to deploy django in a subdirectory. I have the admin enabled in INSTALLED_APPS and the settings.py is ok. Please if you have any guide or telling me what I am doing wrong it will be much appreciated. THanks.

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  • Java PlayFramework & Python Django GAE

    - by Maik Klein
    I already know Java, C# and C++. Now I want to start with web development and I saw that some really big sites are built with Python/C++. I like the coding style of Python, it looks really clean, but some other things like no errors before runtime is really strange. However, I don't know what I should learn now. I started with Python but then I saw that Google App Engine also supports Java and the PlayFramework looks amazing too. Now I am really confused. Should I go with Python or Java? I found the IDE for Python "PyCharm" really amazing for web development. Does Java have something similar, eclipse maybe? I know that this question isn't constructive, but it will help me with my decision. What are pro and cons of both languages?

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  • Django vs Ruby on Rails [closed]

    - by Michal Gumny
    I know that this is not place for languages war, but my question is quite specific. I'm iOS developer and I have friend who is Android developer, we have idea to make some commercial project together, but we will need quite advaned back-end. We want to learn one of this two frameworks and their languages from scratch, so my question is what language is faster to learn, and write app, which is better for small start up

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  • Django - how should I implement generic apps that have dependencies on other generic apps?

    - by MikeRand
    Hi all, I'm using Marty Alchin's Django app that creates historical records (add, change, delete) based on models found in other Django apps (found in chapter 11 of Pro Django). Question: how do I implement this historical_records app into my other generic Django apps while still maintaining loose coupling? For example, I have a generic app (forecast) that manages a Forecast (of any other model). For one project, I'd like to use historical_records so that I can track changes to a Forecast instance. But I don't want to require all future projects that might want to use forecast to also use historical_records. Any guidance would be greatly appreciated. Thanks, Mike

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  • Next steps for Asp.Net C# developer (RoR vs Python Django vs PhP Drupal)

    - by ProfessorB
    A majority of my web development experience has been on the .Net stack (mainly Asp.net C#). I am looking to learn something new in my spare time, for the use of personal projects and possibly for use professionally (as an ISV). I know some Python, done some scripting with it in the past, nothing on the web though. Php has been around for a long time and RoR has gained a lot of popularity. Are there any developers from the .NET world that have migrated over to one or more of the other platforms? If so, which do you prefer and why? Which would you suggest and why?

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  • What sorts of tools make a Django Developer valuable? [closed]

    - by MrOodles
    I am a Django Consultant and I want to increase the value that I provide to clients. My first question was an epic failure according to the FAQ. So I'll try again before I delete it. What types of tools should a Django developer have in his tool belt to increase the value to the client? Would a collection of project templates be useful? Are there open-source project templates available that can be forked and altered? Is there a proper way to configure templates to include dependencies for certain types of projects? What about deployment scripts using tools like Puppet or Chef? Does it make a lot of sense to fork Django apps on GitHub and make contributions to open source projects there? Would clients percieve extra value in programmers that are contributing to open source projects? Are there industry best practices for implementing continuous integration in a Django project? I want the answer to be open ended, as I'm at the beginning of my research. I am curious to know what sorts of tools other Django consultants use on a daily and per-project basis, and how they use them.

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  • Show models.ManyToManyField as inline, with the same form as models.ForeignKey inline

    - by Kristian
    I have a model similar to the following (simplified): models.py class Sample(models.Model): name=models.CharField(max_length=200) class Action(models.Model): samples=models.ManyToManyField(Sample) title=models.CharField(max_length=200) description=models.TextField() Now, if Action.samples would have been a ForeignKey instead of a ManyToManyField, when I display Action as a TabularInline in Sample in the Django Admin, I would get a number of rows, each containing a nice form to edit or add another Action. However; when I display the above as an inline using the following: class ActionInline(admin.TabularInline): model=Action.samples.through I get a select box listing all available actions, and not a nifty form to create a new Action. My question is really: How do I display the ManyToMany relation as an inline with a form to input information as described? In principle it should be possible since, from the Sample's point of view, the situation is identical in both cases; Each Sample has a list of Actions regardless if the relation is a ForeignKey or a ManyToManyRelation. Also; Through the Sample admin page, I never want to choose from existing Actions, only create new or edit old ones.

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  • Accessing Python module fails although its package is imported

    - by codethief
    Hey Stackers! :) My Django project's directory hierarchy looks like this: + pybsd |---+ devices |---+ templates |---+ views |---+ interaction |---- __init__.py |---- geraete.py |---- geraetemodelle.py |---- geraetegruppen.py |---- __init__.py |---- ajax.py |---- html.py |---- misc.py |---- __init__.py |---- urls.py |---- __init__.py |---- urls.py (Please excuse the German names. I preferred not to replace them here since it would add yet another possible error source when trying out the solutions you'll hopefully suggest and answering your questions.) Every request to http://URL/devices/.* is dispatched to the urls.py file living in /devices: # ... from views import html, ajax, misc, interaction urlpatterns = patterns('', # ... (r'^ajax/update/(?P<table>[a-z_]+)$', ajax.update), (r'^ajax/delete/(?P<table>[a-z_]+)$', ajax.delete), (r'^ajax/select_options/(?P<table>[a-z_]+)$', ajax.select_options), (r'^interaction/geraete/info/(?P<geraet>\d+)$', interaction.geraete.info), (r'^interaction/geraete/delete/(?P<geraet>\d+)?$', interaction.geraete.delete), (r'^interaction/geraetemodelle/delete/(?P<geraetemodell>\d+)?$', interaction.geraetemodelle.delete), (r'^interaction/geraetegruppen/delete/(?P<geraetegruppe>\d+)?$', interaction.geraetegruppen.delete), # ... ) All URL definitions work except for those referencing the interaction package. I'm constantly getting the following error: File "/home/simon/projekte/pybsd/../pybsd/devices/urls.py", line 33, in `<module>` (r'^interaction/geraete/info/(?P<geraet>\d+)$', interaction.geraete.info), AttributeError: 'module' object has no attribute 'geraete' I double-checked that the __init__.py files don't contain anything. Maybe you've already found the (Python- or Django-related?) mistake I made and am apparently unable to see. If not, read on. In any case, thanks for reading this long post! Isolating the problem 1st test It works if I provide the view functions as strings: (r'^interaction/geraete/info/(?P<geraet>\d+)$', 'devices.views.interaction.geraete.info'), (r'^interaction/geraete/delete/(?P<geraet>\d+)?$', 'devices.views.interaction.geraete.delete'), (r'^interaction/geraetemodelle/delete/(?P<geraetemodell>\d+)?$', 'devices.views.interaction.geraetemodelle.delete'), (r'^interaction/geraetegruppen/delete/(?P<geraetegruppe>\d+)?$', 'devices.views.interaction.geraetegruppen.delete'), ... or add yet another line to the imports: from views.interaction import geraete, geraetemodelle, geraetegruppen Using from views.interaction import *, however, doesn't work either and results in the same error message. 2nd test I created a file test.py in /devices: from views import interaction print dir(interaction) Output: simon@bsd-simon:~/projekte/pybsd/devices$ python test.py ['__builtins__', '__doc__', '__file__', '__name__', '__package__', '__path__'] Again, no sign of the modules I created in the interaction package (geraete.py, geraetemodelle.py, geraetegruppen.py). Unlike in urls.py, trying from view.interaction import geraete, geraetegruppen, geraetemodelle in test.py results in ImportError: No module named view.interaction this time. 3rd test I started the Django shell: $ python manage.py shell >>> import devices.views.interaction.geraete >>> dir(devices.views.interaction.geraete) ['Abteilung', 'Auftrag', 'Auftragsvorlage', 'Geraet', 'Geraetegruppe', 'Geraetemodell', 'HttpResponse', 'HttpResponseBadRequest', 'HttpResponseRedirect', 'Raum', 'Standort', '__builtins__', '__doc__', '__file__', '__name__', '__package__', 'delete', 'info', 'models', 'move', 'render_to_response'] >>> $ python manage.py shell >>> from devices.views.interaction import geraete >>> dir(geraete) ['Abteilung', 'Auftrag', 'Auftragsvorlage', 'Geraet', 'Geraetegruppe', 'Geraetemodell', 'HttpResponse', 'HttpResponseBadRequest', 'HttpResponseRedirect', 'Raum', 'Standort', '__builtins__', '__doc__', '__file__', '__name__', '__package__', 'delete', 'info', 'models', 'move', 'render_to_response'] >>> $ python manage.py shell >>> import devices.views.interaction >>> devices.views.interaction.geraete Traceback (most recent call last): File "<console>", line 1, in <module> AttributeError: 'module' object has no attribute 'geraete' >>> dir(devices.views.interaction) ['__builtins__', '__doc__', '__file__', '__name__', '__package__', '__path__']

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  • In django, how can I include some default records in my models.py?

    - by kdt
    If I have a models.py like class WidgetType(models.Model): name = models.CharField(max_length=200) class Widget(models.Model): typeid = models.ForeignKey(WidgetType) data = models.CharField(max_length=200) How can I build in a set of built in constant values for WidgetType when I know I'm only going to have a certain few types of widget? Clearly I could fire up my admin interface and add them by hand, but I'd like to simplify configuration by having it built into the python.

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  • Issue using GAE appcfg.py

    - by JustSmith
    I get nothing out of appcfg.py besides the default output. I'm trying to upload some data to my development project with no luck at at all. From the instructions on the Google App Engine page the steps are as follows: Edit app.yaml update with appcfg.py make upload script upload with appcfg.py After step one I try to run the update and it never shows any success. The following commands product the same output: appcfg.py appcfg.py update appDir appcfg.py update appDir/ appcfg.py update /appDir If i try to follow the instructions from the appcfg.py output and type help upload and get: "help <action>" I get a response from the system, This command is not supported by the help utility. Try "update /?". cause I'm calling the system help command. If I use the command appcfg.py help upload I get the same result as just typing appcfg.py Can someone show me examples of the syntax to update the dev site, upload data to it and get appcfg.py to actually give help on its commands? Also I'm just assuming that the upload script and the .csv file that are being uploaded are in they myApp directory. Appreciate any help,

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  • MediaFileUpload of HTML in UTF-8 encoding using Python and Google-Drive-SDK

    - by Victoria
    Looking for example using MediaFileUpload has a reference to the basic documentation for creating/uploading a file to Google Drive. However, while I have code that creates files, converting from HTML to Google Doc format. It works perfectly when they contain only ASCII characters, but when I add a non-ASCII character, it fails, with the following traceback: Traceback (most recent call last): File "d:\my\py\ckwort.py", line 949, in <module> rids, worker_documents = analyze( meta, gd ) File "d:\my\py\ckwort.py", line 812, in analyze gd.mkdir( **iy ) File "d:\my\py\ckwort.py", line 205, in mkdir self.create( **( kw['subop'])) File "d:\my\py\ckwort.py", line 282, in create media_body=kw['media_body'], File "D:\my\py\gdrive2\oauth2client\util.py", line 120, in positional_wrapper return wrapped(*args, **kwargs) File "D:\my\py\gdrive2\apiclient\http.py", line 676, in execute headers=self.headers) File "D:\my\py\gdrive2\oauth2client\util.py", line 120, in positional_wrapper return wrapped(*args, **kwargs) File "D:\my\py\gdrive2\oauth2client\client.py", line 420, in new_request redirections, connection_type) File "D:\my\py\gdrive2\httplib2\__init__.py", line 1597, in request (response, content) = self._request(conn, authority, uri, request_uri, method, body, headers, redirections, cachekey) File "D:\my\py\gdrive2\httplib2\__init__.py", line 1345, in _request (response, content) = self._conn_request(conn, request_uri, method, body, headers) File "D:\my\py\gdrive2\httplib2\__init__.py", line 1282, in _conn_request conn.request(method, request_uri, body, headers) File "C:\Python27\lib\httplib.py", line 958, in request self._send_request(method, url, body, headers) File "C:\Python27\lib\httplib.py", line 992, in _send_request self.endheaders(body) File "C:\Python27\lib\httplib.py", line 954, in endheaders self._send_output(message_body) File "C:\Python27\lib\httplib.py", line 812, in _send_output msg += message_body UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in position 370: ordinal not in range(128) I don't find any parameter to use to specify what file encoding should be used by MediaFileUpload (My files are using UTF-8). Am I missing something?

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  • Python Django MySQLdb setup problem:: setup.py dosen't build due to incorrect location of mysql

    - by 108860375137931889948
    I'm trying to install MySQLdb for python. but when I run the setup, this is the error I get. well I know why its giving all the missing file statements, but dont know where to change the bold marked location from. Please help gaurav-toshniwals-macbook-7:MySQL-python-1.2.3c1 gauravtoshniwal$ python setup.py build running build running build_py copying MySQLdb/release.py - build/lib.macosx-10.3-fat-2.6/MySQLdb running build_ext building '_mysql' extension gcc-4.0 -arch ppc -arch i386 -isysroot /Developer/SDKs/MacOSX10.4u.sdk -fno-strict-aliasing -fno-common -dynamic -DNDEBUG -g -O3 -Dversion_info=(1,2,3,'gamma',1) -D_version_=1.2.3c1 -I/Applications/MAMP/Library/include/mysql -I/Library/Frameworks/Python.framework/Versions/2.6/include/python2.6 -c _mysql.c -o build/temp.macosx-10.3-fat-2.6/_mysql.o _mysql.c:36:23: error: my_config.h: No such file or directory _mysql.c:36:23: error: my_config.h: No such file or directory _mysql.c:38:19: error: mysql.h: No such file or directory _mysql.c:38:19:_mysql.c:39:26: error: mysqld_error.h: No such file or directory error: _mysql.c:40:20:mysql.h: No such file or directory

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  • How to prevent HTTP 304 in Django test server

    - by Augusto Men
    I have a couple of projects in Django and alternate between one and another every now and then. All of them have a /media/ path, which is served by django.views.static.serve, and they all have a /media/css/base.css file. The problem is, whenever I run one project, the requests to base.css return an HTTP 304 (not modified), probably because the timestamp hasn't changed. But when I run the other project, the same 304 is returned, making the browser use the file cached by the previous project (and therefore, using the wrong stylesheet). Just for the record, here are the middleware classes: MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.middleware.transaction.TransactionMiddleware', ) I always use the default address http://localhost:8000. Is there another solution (other than using different ports - 8001, 8002, etc.)?

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  • Django 1.2 object level permissions - third party solutions?

    - by mawimawi
    Since Django 1.2 final is almost out, I am curious if there are already projects that use the new object level permissions / row level permissions system. [django-authority][1] which is a possible solution for Django up to 1.1 has not been updated for a while, and does not (yet) use the new permissions system. It seems to me that Django-Authority is in a comatose state. Does someone know about upcoming or maybe even finished solutions? I'd appreciate any good links to active projects with at least some downloadable content very much. [1]: http://packages.python.org/django-authority/ django-authority

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  • How to set up django-admin.py on windos vista?

    - by shin
    I manage to install Django after some struggles by using setup.py install on Windows Vista Now I tried to use django-admin.py but it is not working. According to this document, http://docs.djangoproject.com/en/dev/ref/django-admin/ The django-admin.py script should be on your system path if you installed Django via its setup.py utility. If it’s not on your path, ... For Windows users, who do not have symlinking functionality available, you can copy django-admin.py to a location on your existing path or edit the PATH settings (under Settings - Control Panel - System - Advanced - Environment...) to point to its installed location. I checked ComputerpropertiesEnvironment Variables, but path to django-admin.py is not in anywhere. So I added C:\Python25\Lib\site-packages\django\bin which is the folder of django-admin.py in User variables for shin Variable PATH, Value C:\Program Files\Google\google_appengine\;C:\Python25\Lib\site-packages\django\bin\ Am I supposed to add to System variables?? But it still does not work. Could anyone tell me how to add the Path in Environment Variables please? Thanks in advance.

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  • Must See Conference Videos for Python/Django Developers

    - by Koobz
    There's lots of good conference videos online regarding Python and Django development. Instead of watching ST:TNG at the computer, I figure it'd more productive to hone my knowledge . Fire away with some of your most inspiring and educational Python, Django, or simply programming related talks. Provide an explanation of why you found the talk useful. Examples: James Bennet on Re-usable Apps - Got me to take a serious look at django apps. Put together a fairly robust site in two days afterwards with django-cms, django-photologue, django-contact-form. Good advice on when your app is crossing boundaries and why it's good to err on the site of 'make it a separate app.'

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  • How come my South migrations doesn't work for Django?

    - by TIMEX
    First, I create my database. create database mydb; I add "south" to installed Apps. Then, I go to this tutorial: http://south.aeracode.org/docs/tutorial/part1.html The tutorial tells me to do this: $ py manage.py schemamigration wall --initial >>> Created 0001_initial.py. You can now apply this migration with: ./manage.py migrate wall Great, now I migrate. $ py manage.py migrate wall But it gives me this error... django.db.utils.DatabaseError: (1146, "Table 'fable.south_migrationhistory' doesn't exist") So I use Google (which never works. hence my 870 questions asked on Stackoverflow), and I get this page: http://groups.google.com/group/south-users/browse_thread/thread/d4c83f821dd2ca1c Alright, so I follow that instructions >> Drop database mydb; >> Create database mydb; $ rm -rf ./wall/migrations $ py manage.py syncdb But when I run syncdb, Django creates a bunch of tables. Yes, it creates the south_migrationhistory table, but it also creates my app's tables. Synced: > django.contrib.admin > django.contrib.auth > django.contrib.contenttypes > django.contrib.sessions > django.contrib.sites > django.contrib.messages > south > fable.notification > pagination > timezones > fable.wall > mediasync > staticfiles > debug_toolbar Not synced (use migrations): - (use ./manage.py migrate to migrate these) Cool....now it tells me to migrate these. So, I do this: $ py manage.py migrate wall The app 'wall' does not appear to use migrations. Alright, so fine. I'll add wall to initial migrations. $ py manage.py schemamigration wall --initial Then I migrate: $ py manage.py migrate wall You know what? It gives me this BS: _mysql_exceptions.OperationalError: (1050, "Table 'wall_content' already exists") Sorry, this is really pissing me off. Can someone help ? thanks. How do I get South to work and sync correctly with everything?

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  • How to set up django-admin.py on windows vista?

    - by shin
    I manage to install Django after some struggles by using setup.py install on Windows Vista Now I tried to use django-admin.py but it is not working. According to this document, http://docs.djangoproject.com/en/dev/ref/django-admin/ The django-admin.py script should be on your system path if you installed Django via its setup.py utility. If it’s not on your path, ... For Windows users, who do not have symlinking functionality available, you can copy django-admin.py to a location on your existing path or edit the PATH settings (under Settings - Control Panel - System - Advanced - Environment...) to point to its installed location. I checked ComputerpropertiesEnvironment Variables, but path to django-admin.py is not in anywhere. So I added C:\Python25\Lib\site-packages\django\bin which is the folder of django-admin.py in User variables for shin Variable PATH, Value C:\Program Files\Google\google_appengine\;C:\Python25\Lib\site-packages\django\bin\ Am I supposed to add to System variables?? But it still does not work. Could anyone tell me how to add the Path in Environment Variables please? Thanks in advance.

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  • Making Django ignore string literals

    - by James
    UPDATE: It turns out this is a deeper question than I thought at first glance - the issue is that python is replacing the string literals before they ever get to django. I will do more investigating and update this if I find a solution. I'm using django to work with LaTeX templates for report generation, and am running into a lot of problems with the way Django replaces parts of strings. Specficially, I've run into two problems where I try to insert a variable containing latex code. The first was that it would replace HTML characters, such as the less than symbol, with their HTML codes, which are of course gibberish to a LaTeX interpreter. I fixed this by setting the context to never autoescape, like so: c = Context(inputs) c.autoescape = False However, I still have my second issue, which is that Django replaces string literals with their corresponding characers, so a double backslash becomes \, and \b becomes a backspace. How can I force Django to leave these characters in place, so inputs['variable'] = '{\bf this is code} \\' won't get mangled when I use {{variable}} to reference it in the django template?

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