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  • Regular expression does not find the first occurance

    - by scharan
    I have the following input to a perl script and I wish to get the first occurrence of NAME="..." strings in each of the ... structures. The entire file is read into a single string and the reg exp acts on that input. However, the regex always returns the LAST occurrence of NAME="..." strings. Can anyone explain what is going on and how this can be fixed? Input file: ADSDF <TABLE> NAME="ORDERSAA" line1 line2 NAME="ORDERSA" line3 NAME="ORDERSAB" </TABLE> <TABLE> line1 line2 NAME="ORDERSB" line3 </TABLE> <TABLE> line1 line2 NAME="ORDERSC" line3 </TABLE> <TABLE> line1 line2 NAME="ORDERSD" line3 line3 line3 </TABLE> <TABLE> line1 line2 NAME="QUOTES2" line3 NAME="QUOTES3" NAME="QUOTES4" line3 NAME="QUOTES5" line3 </TABLE> <TABLE> line1 line2 NAME="QUOTES6" NAME="QUOTES7" NAME="QUOTES8" NAME="QUOTES9" line3 line3 </TABLE> <TABLE> NAME="MyName IsKhan" </TABLE> Perl Code starts here: use warnings; use strict; my $nameRegExp = '(<table>((NAME="(.+)")|(.*|\n))*</table>)'; sub extractNames($$){ my ($ifh, $ofh) = @_; my $fullFile; read ($ifh, $fullFile, 1024);#Hardcoded to read just 1024 bytes. while( $fullFile =~ m#$nameRegExp#gi){ print "found: ".$4."\n"; } } sub main(){ if( ($#ARGV + 1 )!= 1){ die("Usage: extractNames infile\n"); } my $infileName = $ARGV[0]; my $outfileName = $ARGV[1]; open my $inFile, "<$infileName" or die("Could not open log file $infileName"); my $outFile; #open my $outFile, ">$outfileName" or die("Could not open log file $outfileName"); extractNames( $inFile, $outFile ); close( $inFile ); #close( $outFile ); } #call main();

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  • Regular Expression: back references

    - by sixtyfootersdude
    sed 's/^\(\h*\)\(.*\)$/\1<!-- \2 -->/' web.xml I think that this should take this xml: <a> <d> bla </d> </a> And turn it into: <!-- <a> --> <!-- <d> --> <!-- bla --> <!-- </d> --> <!-- </a> --> But what is doing is this: <!-- <a> --> <!-- <d> --> <!-- bla --> <!-- </d> --> <!-- </a> -->

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  • How to access a plugin model from a regular controller in PHP Cake 1.1

    - by Duncan
    Hopefully a simple question: I've a plugin which uses a set of tables (kb_items, kb_item_tags, etc). and I'd like to be able to access these models from another controller (say, my Pages controller), thus: class PagesController extends AppController{ function knowledgebase(){ $items = $this->KbItem->findAll(...); } } I am admittedly breaking the rules a little (by not placing this controller inside the knowledge base plugin), but this in this case its a custom page that doesn't need to be part of the knowledge base plugin code base. Please let me know if you need more details. Thanks in advance for any help!

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  • Extract 2 numbers preceded with two different strings in a paragrapf using TCL Regular Expression

    - by Madhu
    Hi, I need to extract two different numbers preceded by two different strings. Employee Id-- Employee16(I need 16) and Employee links-- Employee links:2 (I need 2). Source String looks like following: Employee16, Employee name is QueenRose Working for 46w0d Billing is Distributed 65537 assigned tasks, 0 reordered, 0 unassigned 0 discarded, 0 lost received, 5/255 load received sequence unavailable, 0xC2E7 sent sequence Employee links: 2 active, 0 inactive (max not set, min not set) Dt3/5/10:0, since 46w0d, no tasks pending Dt3/5/10:10, since 21w0d, no tasks rcvd Employee is currently working in Hardware section. Employee19, Employee name is Edward11 Working for 48w4d Billing is Distributed 206801498 assigned tasks, 0 reordered, 0 unassigned 655372 discarded, 0 lost received, 9/255 load received sequence unavailable, 0x23CA sent sequence Employee links: 7 active, 0 inactive (max not set, min not set) Dt3/5/10:0, since 47w2d, tasks pending Dt3/5/10:10, since 28w6d, no tasks pending Dt3/5/10:11, since 18w4d, no tasks pending Dt3/5/10:12, since 18w4d, no tasks pending Dt3/5/10:13, since 18w4d, no tasks pending Dt3/5/10:14, since 18w4d, no tasks pending Dt3/5/10:15, since 7w2d, no tasks pending Employee is currently working in Hardware sectione. Employee6 (inactive) Employee links: 2 Dt3/5/10:0 (inactive) Dt3/5/10:10 (inactive) Employee7 (inactive) Employee links: 2 Dt3/5/10:0 (inactive) Dt3/5/10:10 (inactive) Tried with the following: Multilink(\d+)[^\n\r]*[^M]*Member links:\s+(\d+) But is not listing all the Ids and links. Can anybody help me getting this? Thanks in advance, Madhu.

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  • Javascript Regular expression to enforce 2 digits after decimal points

    - by Manas Saha
    I need to validate a text box where users are supposed to enter numeric values with 2 decimal places. I am validating the text in client side javascript. The validation will pass only if the number has precisely 2 decimal places, and there is at least 1 digit before the decimal point. (could be zero) the number before the decimal point can be 0, but can not be multiple zeroes. like 00 or 000 The number before the decimal point can not begin with more than 1 zero. Example of Passed validation: 0.01 0.12 111.23 1234.56 012345.67 123.00 0.00 Example of failed validation .12 1.1 0.0 00.00 1234. 1234.567 1234 00123.45 abcd.12 12a4.56 1234.5A I have tried with [0-9][.][0-9][0-9]$ But it is allowing alphabets before decimal point. like 12a4.56 Can anyone please fix the expression? thanks a lot in advance.

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  • Finding tags in query string with regular expression

    - by fatmatto
    Hi everybody! I have to set some routing rules in my php application, and they should be in the form /%var/something/else/%another_var In other words i beed a regex that returns me every URI piece marked by the % character, String marked by % represent var names so they can be almost every string. another example: from /%lang/module/controller/action/%var_1 i want the regex to extract lang and var_1 i tried something like /.*%(.*)[\/$]/ but it doesn't work.....

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  • Regular expression

    - by atno
    Hi I have an array that its first element might contains something like [some text, here. That's some text] I'm trying to figure out a pattern to check if such string exists and if not create it but having problem with making the pattern. Here's what I've done so far $pattern = '/^\[*\]$/'; if(preg_match($pattern,$exploded[0])){ $name = array_shift($exploded); }else{ $name = "[Unnamed import] - " .gmdate("His"); } But I always get [Unnamed import] - 032758 even when I'm sure that pattern match

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  • Help me to split string with Regular Expression

    - by Lu Lu
    Hello, I have a string: CriteriaCondition={FieldName={*EPS}*$MinValue=(-201)$MaxValue=(304)$TradingPeriod=(-1)} Help me to get the first word which ends with the first word "={" & get the next following word which ends with "}". The result must be: Word1 = "CriteriaCondition" Word2 = "FieldName={EPS}$MinValue=(-201)$MaxValue=(304)$TradingPeriod=(-1)" And with the string "FieldName=(EPS)$MinValue=(-201)$MaxValue=(304)$TradingPeriod=(-1)", help me to split to pairs: FieldName EPS MinValue -201 MaxValue 304 TradingPeriod -1 Thanks.

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  • Extract a regular expression match in R version 2.10

    - by tovare
    Hi, I'm trying to extract a number from a string. And do something like this [0-9]+ on this string "aaaa12xxxx" and get "12". I thought it would be something like: > grep("[0-9]+","aaa12xxx", value=TRUE) [1] "aaa12xxx" And then I figured... > sub("[0-9]+", "\\1", "aaa12xxxx") [1] "aaa12xxx" But I got some form of response doing: > sub("[0-9]+", "ARGH!", "aaa12xxxx") [1] "aaaARGH!xxx" There's a small detail I'm missing Please advice :-) I'm using R version 2.10.1 (2009-12-14) Thanks ! Comments on the solution The best solution is to ignore the standard functions and install Hadley Wickham's stringr package to get something that actually makes sense. Kudos to Marek for figuring out how the standard library worked.

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  • Pass a captured named regular expression to URL dictionary in generic view

    - by Trent Jurewicz
    I am working with a generic view in Django. I want to capture a named group parameter in the URL and pass the value to the URL pattern dictionary. For example, in the URLConf below, I want to capture the parent_slug value in the URL and pass it to the queryset dictionary value like so: urlpatterns = patterns('django.views.generic.list_detail', (r'^(?P<parent_slugs>[-\w])$', 'object_list', {'queryset':Promotion.objects.filter(category=parent_slug)}, 'promo_promotion_list'), ) Is this possible to do in one URLConf entry, or would it be wiser if I create a custom view to capture the value and pass the queryset directly to the generic view from my overridden view?

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  • Flex 3 Regular Expression Problem

    - by Tommy
    I've written a url validator for a project I am working on. For my requirements it works great, except when the last part for the url goes longer than 22 characters it breaks. My expression: /((https?):\/\/)([^\s.]+.)+([^\s.]+)(:\d+\/\S+)/i It expects input that looks like "http(s)://hostname:port/location". When I give it the input: https://demo10:443/111112222233333444445 it works, but if I pass the input https://demo10:443/1111122222333334444455 it breaks. You can test it out easily at http://ryanswanson.com/regexp/#start. Oddly, I can't reproduce the problem with just the relevant (I would think) part /(:\d+\/\S+)/i. I can have as many characters after the required / and it works great. Any ideas or known bugs?

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  • Scala: Matching optional Regular Expression groups

    - by Brian Heylin
    I'm trying to match on an option group in Scala 2.8 (beta 1) with the following code: import scala.xml._ val StatementPattern = """([\w\.]+)\s*:\s*([+-])?(\d+)""".r def buildProperty(input: String): Node = input match { case StatementPattern(name, value) => <propertyWithoutSign /> case StatementPattern(name, sign, value) => <propertyWithSign /> } val withSign = "property.name: +10" val withoutSign = "property.name: 10" buildProperty(withSign) // <propertyWithSign></propertyWithSign> buildProperty(withoutSign) // <propertyWithSign></propertyWithSign> But this is not working. What is the correct way to match optional regex groups?

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  • Find last match with python regular expression

    - by SDD
    I wanto to match the last occurence of a simple pattern in a string, e.g. list = re.findall(r"\w+ AAAA \w+", "foo bar AAAA foo2 AAAA bar2) print "last match: ", list[len(list)-1] however, if the string is very long, a huge list of matches is generated. Is there a more direct way to match the second occurence of "AAAA" or should I use this workaround?

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  • regular expression for letters, numbers and - _ .

    - by Jorre
    I'm having trouble checking in PHP if a value is is any of the following combinations letters (upper or lowercase) numbers (0-9) underscore (_) dash (-) point (.) no spaces! or other characters a few examples: OK: "screen123.css" OK: "screen-new-file.css" OK: "screen_new.js" NOT OK: "screen new file.css" I guess I need a regex for this, since I need to throw an error when a give string has other characters in it than the ones mentioned above.

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