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  • Why does one of these statements compile in Scala but not the other?

    - by Jeff
    (Note: I'm using Scala 2.7.7 here, not 2.8). I'm doing something pretty simple -- creating a map based on the values in a simple, 2-column CSV file -- and I've completed it easily enough, but I'm perplexed at why my first attempt didn't compile. Here's the code: // Returns Iterator[String] private def getLines = Source.fromFile(csvFilePath).getLines // This doesn't compile: def mapping: Map[String,String] = { Map(getLines map { line: String => val pairArr = line.split(",") pairArr(0) -> pairArr(1).trim() }.toList:_*) } // This DOES compile def mapping: Map[String,String] = { def strPair(line: String): (String,String) = { val pairArr = line.split(",") pairArr(0) -> pairArr(1).trim() } Map(getLines.map( strPair(_) ).toList:_*) } The compiler error is CsvReader.scala:16: error: value toList is not a member of (St ring) = (java.lang.String, java.lang.String) [scalac] possible cause: maybe a semicolon is missing before `value toList'? [scalac] }.toList:_*) [scalac] ^ [scalac] one error found So what gives? They seem like they should be equivalent to me, apart from the explicit function definition (vs. anonymous in the nonworking example) and () vs. {}. If I replace the curly braces with parentheses in the nonworking example, the error is "';' expected, but 'val' found." But if I remove the local variable definition and split the string twice AND use parens instead of curly braces, it compiles. Can someone explain this difference to me, preferably with a link to Scala docs explaining the difference between parens and curly braces when used to surround method arguments?

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  • Python: needs more than 1 value to unpack

    - by Rosarch
    What am I doing wrong to get this error? replacements = {} replacements["**"] = ("<strong>", "</strong>") replacements["__"] = ("<em>", "</em>") replacements["--"] = ("<blink>", "</blink>") replacements["=="] = ("<marquee>", "</marquee>") replacements["@@"] = ("<code>", "</code>") for delimiter, (open_tag, close_tag) in replacements: # error here message = self.replaceFormatting(delimiter, message, open_tag, close_tag); The error: Traceback (most recent call last): File "", line 1, in for shit, (a, b) in replacements: ValueError: need more than 1 value to unpack All the values tuples have two values. Right?

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  • java - coding errors causing endless loop

    - by Daniel Key
    Im attempting to write a program that takes a population's birthrate and deathrate and loops the annual population until it either reaches 0 or doubles. My problem it that it continuously loops an endless amount of illegible numbers and i cant fix it. please help. //***************************************** //This program displays loop statements //Written by: Daniel Kellogg //Last Edited: 9/28/12 //**************************************** import java.util.Scanner; public class Hwk6 { public static void main (String[] args) { int currentYear, currentPopulation; double birthRate, deathRate; Scanner stdin = new Scanner(System.in); System.out.println("\nPopulation Estimator\n"); System.out.println("Enter Year"); currentYear = stdin.nextInt(); System.out.println("Enter Current Population"); currentPopulation = stdin.nextInt(); System.out.println("Enter Birthrate of Population"); birthRate = stdin.nextDouble(); System.out.println("Enter Deathrate of Population"); deathRate = stdin.nextDouble(); int counter = currentPopulation; System.out.println("Population: "); while (currentPopulation != -1) while (counter < currentPopulation * 2) { System.out.print(counter + " "); counter = counter + (int)(counter * birthRate - counter * deathRate); } System.exit(0); } }

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  • Is Odersky serious with "bills !*&^%~ code!" ?

    - by stacker
    In his book programming in scala (Chapter 5 Section 5.9 Pg 93) Odersky mentioned this expression "bills !*&^%~ code! In the footnote on same page: "By now you should be able to figure out that given this code,the Scala compiler would invoke (bills.!*&^%~(code)).!()." That's a bit to cryptic for me, could someone explain what's going on here?

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  • When to use or not use symbols in PHP

    - by brett
    I'm reading a PHP book where the author says that symbols should be avoided except when it's valid to use them. Very informative stuff, if he could only elaborate or give code examples but he doesn't. Can someone from the experienced PHP bunch give me an example of what these symbols are, and when it makes sense to use them or not. I'm looking for a code example that I can wrap my head around since I don't quite get it in plain English. Code is more plain English to me.

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  • json object composition details

    - by Ethan
    in .json text, is the 'value' in a basic single pair object the title of a value type (e.g. [string, number, object]), or a value for a typed object (e.g. 2, or "dog", or Object3)? This is how http://www.json.org/ presents the information: "An object is an unordered set of name/value pairs. An object begins with { (left brace) and ends with } (right brace). Each name is followed by : (colon) and the name/value pairs are separated by , (comma)."

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  • jQuery add class is not working

    - by user1269625
    Hey ya'll I have this code here and it suppose to add the class name "cboxElement" $(".wpcart_gallery a:first").addClass("cboxElement"); but it does not work. I have the proper Jquery file in my header, I have surrounded this in jQuery('document').ready(function($){......}); and it works for all my other Jquery but the add class call. here is what I am trying to add the class to... <div class="wpcart_gallery" style="text-align:center; padding-top:5px;"> <a class="thickbox" href="DSC_0037.jpg" rev="DSC_0037.jpg"></a> </div> Anybody know why this isnt working? I am new to jquery this is also in wordpress hence the jQuery('document')

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  • Code doesn't work in foreach

    - by Arlen Beiler
    Here is my code: var divarray = document.getElementById("yui-main").getElementsByTagName("div"); var articleHTML; var absHTML; var keyHTML; var bodyHTML = []; for( var i in divarray) { if(divarray[i].className == "articleBody"){ articleHTML = divarray[i]; for( var j in articleHTML ){ bodyHTML[i] = ''; if(articleHTML[j].className == "issueMiniFeature"){continue;} if(articleHTML[j].className == "abstract"){absHTML = articleHTML[i]; continue;} if(articleHTML[j].className == "journalKeywords"){keyHTML = articleHTML[i]; continue;} bodyHTML[i] = articleHTML[i]; } break; } i++; } The error I am getting is: SyntaxError: Unexpected token var I am using Google Chrome

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  • php : echo"", print(), printf()

    - by marc-andre menard
    Is there a better way to output data to html page with PHP ? if i like to make a div with some var in php i will write something like that print ('<div>'.$var.'</div>); or echo "'<div>'.$var.'</div>'"; what is the PROPER way to do that ? or a better way, fill a $tempvar and print it once? like that: $tempvar = '<div>'.$var.'</div>' print ($tempvar); in fact, in real life, the var will be fill with much more !

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  • User control loosing its contents when loaded programatically

    - by Phil
    I have a usercontrol which contains 2 repeaters and the code to populate them with data. If i manually insert this into the page then it works correctly, the repeaters populate etc. If I load it programatically using this method; 1) add class name to user control ClassName="ContentModule" 2) reference this in the default.aspx <%@ Reference Control="~/modules/content.ascx" %> 3) Add the code to my codebehind page_load to do the loading; Private loadmodule As ASP.ContentModule Try If themodule = "content" Then loadmodule = CType(LoadControl("~\Modules\Content.ascx"), ASP.ContentModule) Modulecontainer.Controls.Add(loadmodule) End If Catch ex As Exception Response.Write(ex.ToString & "<br />") End Try Nothing from within the usercontrol is loaded to the page. Although if I add some static text i.e "TEST" to the top of the usercontrol this is displayed ok on the default.aspx page. This makes me think that the control is loaded ok, but there is something in the way I have loaded it that is causing the contents to not properly execute. Very frustrating this one! Any help greatly appreciated!

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  • HOw I can verify my SQL / SQL Pl syntax

    - by rima
    Hi all Sorry my English is bad.I hope u can get what I want. I have lots of *.sql files that i want to write a program to compile them and if there is any issue(problem or mistake) report me. One of my friend write an IDE for java,as I remember he use javac to generate the codes error,in other hand maybe u see when u try to write code in a Visual stadio or Netbean the IDE generate errors for u.so now I want to know any one have any idea how I can do it for my sql files? In other mean I want to write a Editor for SQL files(PL/SQL) that compile my code and tell me what is my error. this problem raise up when I try to compile all of them in SQL PLUS,it's so boring. please help me...

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  • VBA: Difference in two ways of declaring a new object? (Trying to understand why my solution works)

    - by Matt
    I was creating a new object within a loop, and adding that object to a collection; but when I read back the collection after, it was always filled entirely with the last object I had added. I've come up with two ways around this, but I simply do not understand why my initial implementation was wrong. Original: Dim oItem As Variant Dim sOutput As String Dim i As Integer Dim oCollection As New Collection For i = 0 To 10 Dim oMatch As New clsMatch oMatch.setLineNumber i oCollection.Add oMatch Next For Each oItem In oCollection sOutput = sOutput & "[" & oItem.lineNumber & "]" Next MsgBox sOutput This resulted in every lineNumber being 10; I was obviously not creating new objects, but instead using the same one each time through the loop, despite the declaration being inside of the loop. So, I added Set oMatch = Nothing immediately before the Next line, and this fixed the problem, it was now 0 to 10. So if the old object was explicitly destroyed, then it was willing to create a new one? I would have thought the next iteration through the loop would cause anything declared within the loop do be destroyed due to scope? Curious, I tried another way of declaring a new object: Dim oMatch As clsMatch: Set oMatch = New clsMatch. This, too, results in 0 to 10. Can anyone explain to me why the first implementation was wrong?

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  • Online validators, syntax checkers, testing tools

    - by Max Gontar
    I often need to verify some simple code before posting, and it's great if I have installed IDE, but what if not? It would be nice to have online free tools for SQL, VB.NET, C# code validation, or maybe even testing. EDIT What I actually mean are online live web tools, like JSLint for javascript. Have you seen any?

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  • how to modify this jquery syntax

    - by Gandalf StormCrow
    Hi all, this example below works when hover event is trigered and when its not, its working for elements already in DOM, but when element created dynamically it doesn't work, I realize I need to use jQuery live() or delegate() for this, the thing is I tried to modify it and its not producing the results as expected, here is the working code : $(".sidebar li").hover( function(){ $(this).css("background-color", "#F9F4D0"); $(this).append($('<button class="promoter" type="button" title="Active promotion"></button>')); }, function(){ $(this).css("background-color", "#F9FAFA"); $(this).children("button").remove(); } ); Here is the bit when I wanted to add live but it's not producing correct results : $(".sidebar li").live('hover', function(){ $(this).css("background-color", "#F9F4D0"); $(this).append($('<button class="promoter" type="button" title="Active promotion"></button>')); }, function(){ $(this).css("background-color", "#F9FAFA"); $(this).children("button").remove(); } ); Where did I made mistake, thank you

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  • Why does Perl's shift complain 'Type of arg 1 to shift must be array (not grep iterator).'?

    - by wes
    I've got a data structure that is a hash that contains an array of hashes. I'd like to reach in there and pull out the first hash that matches a value I'm looking for. I tried this: my $result = shift grep {$_->{name} eq 'foo'} @{$hash_ref->{list}}; But that gives me this error: Type of arg 1 to shift must be array (not grep iterator). I've re-read the perldoc for grep and I think what I'm doing makes sense. grep returns a list, right? Is it in the wrong context? I'll use a temporary variable for now, but I'd like to figure out why this doesn't work.

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  • Inline HTML Syntax for Helpers in ASP.NET MVC

    - by kouPhax
    I have a class that extends the HtmlHelper in MVC and allows me to use the builder pattern to construct special output e.g. <%= Html.FieldBuilder<MyModel>(builder => { builder.Field(model => model.PropertyOne); builder.Field(model => model.PropertyTwo); builder.Field(model => model.PropertyThree); }) %> Which outputs some application specific HTML, lets just say, <ul> <li>PropertyOne: 12</li> <li>PropertyTwo: Test</li> <li>PropertyThree: true</li> </ul> What I would like to do, however, is add a new builder methid for defining some inline HTML without having to store is as a string. E.g. I'd like to do this. <% Html.FieldBuilder<MyModel>(builder => { builder.Field(model => model.PropertyOne); builder.Field(model => model.PropertyTwo); builder.ActionField(model => %> Generated: <%=DateTime.Now.ToShortDate()%> (<a href="#">Refresh</a>) <%); }).Render(); %> and generate this <ul> <li>PropertyOne: 12</li> <li>PropertyTwo: Test</li> <li>Generated: 29/12/2008 <a href="#">Refresh</a></li> </ul> Essentially an ActionExpression that accepts a block of HTML. However to do this it seems I need to execute the expression but point the execution of the block to my own StringWriter and I am not sure how to do this. Can anyone advise?

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  • Jquery: syntax for inserting a function

    - by kelly
    I'm trying to integrate an animation by using the bezier path plug-in and I can't seem to implement it right. Stripped down, here's what I have: $('#next2btn').live('click', function(){ $(this).attr('id','next3btn'); $('#content2').show(300, function() { $('#account').fadeTo(500,1.0) var arc_params = { center: [278,120], radius: 186, start: -90, end: 90, dir: -1 }; }); $("#account").animate({path : new $.path.arc(arc_params)},1000); }); So, I'm trying to add this piece of code into what I have: var arc_params = { center: [278,120], radius: 186, start: -90, end: 90, dir: -1 }; }); $("#account").animate({path : new $.path.arc(arc_params)},1000) which works on its own as does the other. I'm thinking it's something about declaring that variable and where I do that. I'm essentially chaining a few different animations/actions upon a button click. Thanks for any insight- kj

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