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  • Problems with moving 2D circle/box collision detection

    - by dario3004
    This is my first game ever and I'm a newbie in computer physics. I've got this code for the collision detection and it works fine for BOTTOM and TOP collision.It miss the collision detection with the paddle's edge and angles so I've (roughly) tried to implement it. Main method that is called for bouncing, it checks if it bounce with wall, or with top (+ right/left side) or with bottom (+ right/left side): protected void handleBounces(float px, float py) { handleWallBounce(px, py); if(mBall.y < getHeight()/4){ if (handleRedFastBounce(mRed, px, py)) return; if (handleRightSideBounce(mRed,px,py)) return; if (handleLeftSideBounce(mRed,px,py)) return; } if(mBall.y > getHeight()/4 * 3){ if (handleBlueFastBounce(mBlue, px, py)) return; if (handleRightSideBounce(mBlue,px,py)) return; if (handleLeftSideBounce(mBlue,px,py)) return; } } This is the code for the BOTTOM bounce: protected boolean handleRedFastBounce(Paddle paddle, float px, float py) { if (mBall.goingUp() == false) return false; // next position tx = mBall.x; ty = mBall.y - mBall.getRadius(); // actual position ptx = px; pty = py - mBall.getRadius(); dyp = ty - paddle.getBottom(); xc = tx + (tx - ptx) * dyp / (ty - pty); if ((ty < paddle.getBottom() && pty > paddle.getBottom() && xc > paddle.getLeft() && xc < paddle.getRight())) { mBall.x = xc; mBall.y = paddle.getBottom() + mBall.getRadius(); mBall.bouncePaddle(paddle); playSound(mPaddleSFX); increaseDifficulty(); return true; } else return false; } As long as I understood it should be something like this: So I tried to make the "left side" and "right side" bounce method: protected boolean handleLeftSideBounce(Paddle paddle, float px, float py){ // next position tx = mBall.x + mBall.getRadius(); ty = mBall.y; // actual position ptx = px + mBall.getRadius(); pty = py; dyp = tx - paddle.getLeft(); yc = ty + (pty - ty) * dyp / (ptx - tx); if (ptx < paddle.getLeft() && tx > paddle.getLeft()){ System.out.println("left side bounce1"); System.out.println("yc: " + yc + "top: " + paddle.getTop() + " bottom: " + paddle.getBottom()); if (yc > paddle.getTop() && yc < paddle.getBottom()){ System.out.println("left side bounce2"); mBall.y = yc; mBall.x = paddle.getLeft() - mBall.getRadius(); mBall.bouncePaddle(paddle); playSound(mPaddleSFX); increaseDifficulty(); return true; } } return false; } I think I'm quite near to the solution but I'm having big troubles with the new "yc" formula. I tried so many versions of it but since I don't know the theory behind it I can't adjust for the Y axis. Since the Y axis is inverted I even tried this: yc = ty - (pty - ty) * dyp / (ptx - tx); I tried Googling it but I can't seem to find a solution for it. Also this method fails when ball touches the angle and I don't think is a nice way because it just test "one" point of the ball and probably there will be many cases in which the ball won't bounce.

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  • NINE Great Reasons to Attend the GlassFish Community Event at JavaOne 2012

    - by Alexandra Huff
    Are you coming to the annual GlassFish Community Event at JavaOne this year? Here are nine great reasons not to miss it! Great company Meet and mingle with community leaders and luminaries, the GlassFish engineering team, and Oracle executives! Learn from others How are your peers using GlassFish in creative ways? A few community members will share their challenges and creative solutions. Ask tough questions Meet Oracle GlassFish and Middleware executives; the panel discussion will be moderated by one of our stellar community leaders! Shirts! Be sure to get this year's GlassFish T-shirt, designed by and voted on by YOU, our community members! Don't miss it - they go fast. Share your story Give us a two minute update on why you love GlassFish and how you are using it! We will immortalize you in a very brief video and post it to our GlassFish Stories page! Find out... about the new book, hot off the press, authored by our very own Arun Gupta: "Java EE 6 Pocket Guide: A Quick Reference for Simplified Enterprise Java Development" If you share... your story, you will win a copy of Arun's new book as our thank you gift! Suggest... some ideas on how to make GlassFish even better! Have fun Lively discussion, news and updates, excellent company -- this is THE place to be on Sunday at JavaOne! Convinced? Excellent! Then please register here! A JavaOne Pass is required to enter Moscone Center. All passes accepted, including Discover, Exhibitor, Press, Blogger, etc. Agenda 11:00 - 11:05: Introduction 11:05 - 11:30: Roadmap and Community Updates 11:30 - 12:15: Q&A with Executive Speaker Panel from Oracle and the GlassFish Team 12:15 - 01:00: Customer Testimonials Location: Moscone West, Room 2005 Add sessions UGF10359 and UGF10360 to Schedule Builder

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  • Detecting collision between ball (circle) and brick(rectangle)?

    - by James Harrison
    Ok so this is for a small uni project. My lecturer provided me with a framework for a simple brickbreaker game. I am currently trying to overcome to problem of detecting a collision between the two game objects. One object is always the ball and the other objects can either be the bricks or the bat. public Collision hitBy( GameObject obj ) { //obj is the bat or the bricks //the current object is the ball // if ball hits top of object if(topX + width >= obj.topX && topX <= obj.topX + obj.width && topY + height >= obj.topY - 2 && topY + height <= obj.topY){ return Collision.HITY; } //if ball hits left hand side else if(topY + height >= obj.topY && topY <= obj.topY + obj.height && topX + width >= obj.topX -2 && topX + width <= obj.topX){ return Collision.HITX; } else return Collision.NO_HIT; } So far I have a method that is used to detect this collision. The the current obj is a ball and the obj passed into the method is the the bricks. At the moment I have only added statement to check for left and top collisions but do not want to continue as I have a few problems. The ball reacts perfectly if it hits the top of the bricks or bat but when it hits the ball often does not change directing. It seems that it is happening toward the top of the left hand edge but I cannot figure out why. I would like to know if there is another way of approaching this or if people know where I'm going wrong. Lastly the collision.HITX calls another method later on the changes the x direction likewise with y.

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  • Implementing Circle Physics in Java

    - by Shijima
    I am working on a simple physics based game where 2 balls bounce off each other. I am following a tutorial, 2-Dimensional Elastic Collisions Without Trigonometry, for the collision reactions. I am using Vector2 from the LIBGDX library to handle vectors. I am a bit confused on how to implement step 6 in Java from the tutorial. Below is my current code, please note that the code strictly follows the tutorial and there are redundant pieces of code which I plan to refactor later. Note: refrences to this refer to ball 1, and ball refers to ball 2. /* * Step 1 * * Find the Normal, Unit Normal and Unit Tangential vectors */ Vector2 n = new Vector2(this.position[0] - ball.position[0], this.position[1] - ball.position[1]); Vector2 un = n.normalize(); Vector2 ut = new Vector2(-un.y, un.x); /* * Step 2 * * Create the initial (before collision) velocity vectors */ Vector2 v1 = this.velocity; Vector2 v2 = ball.velocity; /* * Step 3 * * Resolve the velocity vectors into normal and tangential components */ float v1n = un.dot(v1); float v1t = ut.dot(v1); float v2n = un.dot(v2); float v2t = ut.dot(v2); /* * Step 4 * * Find the new tangential Velocities after collision */ float v1tPrime = v1t; float v2tPrime = v2t; /* * Step 5 * * Find the new normal velocities */ float v1nPrime = v1n * (this.mass - ball.mass) + (2 * ball.mass * v2n) / (this.mass + ball.mass); float v2nPrime = v2n * (ball.mass - this.mass) + (2 * this.mass * v1n) / (this.mass + ball.mass); /* * Step 6 * * Convert the scalar normal and tangential velocities into vectors??? */

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  • Circle vs Edge collision detection / resolution

    - by topheman
    I made a javascript class Ball.js that handles physics interactions betweens balls as well as painting. In the v1.0, the ball vs ball collision detection and resolution is well handled. In the next version (v2), I'm trying to add edgeCollision handling. I'm having some problems, maybe you will be able to help me. All the v2 branch source code is on github repository : https://github.com/topheman/Ball.js/tree/v2 The v2 demos (where you can see the bug I will be talking about) : http://labs.topheman.com/Ball-v2/#help As you will see on the demo, I have two major problems that I'm having a really hard time to solve on Ball.js : method resolveEdgeCollision : bounce angle is inconsistent method checkEdgeCollision : if the ball's velocity (the length that it runs each frame) is higher than its diameter, eventually, it will pass through an edge, without triggering any collision Any Ideas ?...

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  • Circle physics and collision using vectors

    - by Joe Hearty
    This is a problem I've been having, When making a set number of filled circles at random locations on a JPanel and applying a gravity (a negative change in the y), each of the circles collide. I want them to have collision detection and push in the opposite direction using vectors but I don't know how to apply that to my scenario could someone help? public void drawballs(Graphics g){ g.setColor (Color.white); //displays circles for(int i = 0; i<xlocationofcircles.length-1; i++){ g.fillOval( (int) xlocationofcircles[i], (int) (ylocationofcircles[i]) ,16 ,16 ); ylocationofcircles[i]+=.2; //gravity if(ylocationofcircles[i] > 550) //stops gravity at bottom of screen ylocationofcircles[i]-=.2; //Check distance between circles(i think..) float distance =(xlocationofcircles[i+1]-xlocationofcircles[i]) + (ylocationofcircles[i+1]-xlocationofcircles[i]); if( Math.sqrt(distance) <16) ...

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  • Great Debugging skills weak problem solving

    - by Mahmoud
    For the 5 years I worked for various companies, I worked in large software like computer vision kits, embedded, games. I found myself very good at debuggins skills, I've even found and fixed bugs in frameworks and I solved them. The problem is that I'm very weak at problem solving. I got interview with Qualcomm, and they said you're fine at software, but you have a limited problem solving, I also had the same results with Google. I'm very bad at solving puzzles and brain teasers. During the interviews I solve all of the software related problems on the blackboard, but when I went to the GM and face math problems and probabilities, I struggle. How can I improve my problem solving skills? Edit Some of the problems: A cake that is cut from anywhere and needs just one cut to halved in equal. I told him cut it horizontally, he said No, consider it as a 2D Problem!. Consider a concenteric 3 circles, each one can get a color, but not matched with the other circle, how many blobs you can make out of those circles ? this was with the GM ( Augmented Reality SDK) Consider a train, an infinite one, and you looked at the window, and there are two cars, one big, and one small, what is the probability of having only a big car, I said 50%, he said, what if that two cars you dont know their length, and you want to get the probability of getting the biggest one, I struggled, didn't solve it... I was really exahusted after long day of interviews prob of having a number divisible by 5 in numbers from 1 to 100.. struggled!! All coding questions I solved them like reverse a string, detect a cycle in a linked list,..etc.

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  • Get Angle to Tangent that Intersects Point

    - by Christian Stewart
    I have a circle around a given point, call this point (x1, y1). I know the radius of the circle around this point. I also have a second point (x2, y2), that is a distance away, outside the radius of the circle. I need a algebraic way through code to calculate the heading (angle from vertical) needed to intersect the circle at 90* to the center point (I.E. get the angle of the tangent intersecting line 2) around the point (x1, y1) from the second point (x2, y2) A bit of background: Essentially the two points are GPS coordinates on a 2D map, I need to know the target heading to intersect the circle in order to follow its path around the center point. Thanks! Christian

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  • What makes a great place to work

    - by Rob Farley
    Co-incidentally, I’ve been looking for office space for LobsterPot Solutions during the same few days that Luke Hayler ( @lukehayler ) has asked for my thoughts (okay, he ‘tagged’ me) on what makes a great place to work . He lists People and Environment, and I’m inclined to agree, but with a couple of other things too. I have three children. Two of them (both boys) are in school, but my daughter is only two. For the boys’ schools, we quickly realised that what they need most is a feeling of safety...(read more)

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  • What makes a great place to work

    - by Rob Farley
    Co-incidentally, I’ve been looking for office space for LobsterPot Solutions during the same few days that Luke Hayler ( @lukehayler ) has asked for my thoughts (okay, he ‘tagged’ me) on what makes a great place to work . He lists People and Environment, and I’m inclined to agree, but with a couple of other things too. I have three children. Two of them (both boys) are in school, but my daughter is only two. For the boys’ schools, we quickly realised that what they need most is a feeling of safety...(read more)

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  • Great Web Apps With New HTML5 APIs

    Great Web Apps With New HTML5 APIs This talk is in hebrew. It cover new techniques for building modern web apps and how to utilize the latest HTML5 APIs to create a new class of web apps that will delight and amaze your users. In this talk, Ido Green, developer advocate in Google and the author of Web Workers, will cover the following: - HTML5 APIs - New and useful. - Some tips on Chrome DevTools - ChromeOS update. From: GoogleDevelopers Views: 301 35 ratings Time: 01:08:05 More in Science & Technology

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  • How to check when animation finishes if animation block is

    - by pumpk1n
    I have a controller which adds as subviews a custom UIView class called Circle. Let's call a particular instance of Circle, "circle". I have a method in Circle, animateExpand, which expands the circle by animating the view. In the following code (which lives in the controller) I want to alloc and init a circle, add it to a NSMutableArray circleArray, animate the expansion, and at the end of the expansion, i want to remove the object from the array. My attempt: Circle *circle = [[Circle alloc] init]; [circleArray addObject:circle]; [circle animateExpand]; [circleArray removeObjectIdenticalTo:circle]; [circle release]; The problem is [circleArray removeObjectIdenticalTo:circle]; gets called before the animation finishes. Presumbly because the animation is done on a seperate thread. I cant implement the deletion in completion:^(BOOL finished){ }, because the Circle class does not know about a circleArray. Any solutions would be helpful, thanks!

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  • 10 Great Linux Apps You Might Not Have Discovered Yet

    <b>Linux Planet:</b> "The world of Linux applications continues to expand and improve, so check out Eric Geier's roundup of ten great Linux applications you might not have discovered yet: media players, Web page designer, video creation, run Linux on Windows, Windows apps on Linux, and more."

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  • Community is Great

    - by GrumpyOldDBA
    I have a great respect for so many who contribute to the community, without them I would often struggle in my role for sure. When "strange events" happen in a busy production environment it can be quite daunting when it seems everyone around is expecting you to have the answer/solution at your finger tips. I'm indebted to Paul White http://sqlblog.com/blogs/paul_white/default.aspx in confirming I'd found a bug and doing all the hard work including raising a connect item https:/...(read more)

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  • Great finds: More TechNet Survival Guides

    - by Enrique Lima
    It has been some time now since Windows Server 2008 R2 arrived, but the features and capabilities in many cases are just now starting to surface with company’s implementing or looking at using. Here is a link to the Survival Guide on TechNet: http://social.technet.microsoft.com/wiki/contents/articles/windows-server-2008-r2-survival-guide.aspx The other item that is coming stronger and stronger is PowerShell.  I mentioned before the need to learn and get into using it as it is a great tool. http://social.technet.microsoft.com/wiki/contents/articles/windows-powershell-survival-guide.aspx

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  • Cross-Cultural Design (great video from HFI) - #usableapps #UX #L10n

    - by ultan o'broin
    Great video from HFI Animate, featuring user-centered design for emerging markets called Cross Cultural Design: Getting It Right the First Time. Cross Cultural Design: Getting It Right the First Time Apala Lahiri Chavan talks about the issues involved in designing solutions for Africa, India, China and more markets! Design for the local customer's ecosystem - and their feelings! Timely reminder of the important of global and local research in UX!

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  • 4 Great Advantages of Top Website Building Software

    To build a website is one of the most crucial decisions you have to make when you own a business. So if you really want to earn a big profit, you need to have a great website that will pave the way for your business to reach more prospects. But you must understand that when you build your own website, you must not concentrate on its visual appearance alone.

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  • Every Linking Strategy Starts with Great Content

    Having great content is at the core of every effective linking strategy. In order to develop back links you absolutely must give other sites a reason to link to you in the first place. Having some ty... [Author: TJ Philpott - Web Design and Development - May 20, 2010]

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  • Why a SEO Service Can Be of Great Benefit to You

    One of the most important things that you have to remember is that your website should be able to well rank highly in any search engine. In other words, what you have to remember is that your website should be able to rank well in a search engine. This is the scenario chiefly due to the great fact that you will get a much greater perceptibility when your site ranks in the first page of Google.

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  • Chinese SEO - Scaling the Great Firewall

    At approximately 1.3 billion, it has the largest population in the world. The number of its Internet users rises significantly each year. It has a great virtual wall that rivals its real one that stretches 8,800 kilometers from Shanhaiguan to Lop Nur. It is the People's Republic of China (PRC).

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  • Great SharePoint Community Resources

    - by Enrique Lima
    3 sites that any person working with SharePoint should visit are: SharePoint Magazine SharePoint Magazine is an online magazine dedicated to the world of SharePoint and related Information Worker Technologies. End User SharePoint Community driven content, at this point in time the site is a historical archive of content released. Nothing But SharePoint I see this as the natural evolution of EndUserSharePoint.com Follows on the same great principle of community driven content, but expanding from the world of End User to the IT Pro and Developer realms.

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