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  • Oracle anuncia la disponibilidad de Oracle Knowledge 8.5

    - by Noelia Gomez
    Normal 0 21 false false false ES X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-family:"Calibri","sans-serif";} El lanzamiento más completo de la gestión del conocimiento de Oracle ayuda a las organizaciones a ofrecer las respuestas correctas en el momento adecuado a los Agentes y Clientes Normal 0 21 false false false ES X-NONE X-NONE MicrosoftInternetExplorer4 -"/ /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-family:"Calibri","sans-serif";} Continuando con su compromiso de ayudar a las organizaciones a ofrecer la mejor experiencia del cliente con la exploración de los datos empresariales, Oracle anunció Oracle Knowledge 8.5, el software líder en la industria del conocimiento que soporta la gestión web de autoservicio, servicio asistido por agente y comunidades de clientes. Oracle Knowledge 8.5 es la versión más completa desde la adquisición de InQuira en octubre de 2011. Se introduce importantes mejoras de productos, análisis de mejora y los avances en el rendimiento y la escalabilidad. Actualmente, las organizaciones entienden la necesidad imperiosa de ofrecer un servicio al cliente consistente y de alta calidad, a través de diferentes canales. Además, las organizaciones reconocen la necesidad de información que sirva para este proceso. Oracle Knowledge 8,5 proactivamente brinda conocimientos relevantes y contextuales en el punto de interacción con los agentes, con los trabajadores del conocimiento y con los clientes - ayudando a aumentar la lealtad del cliente y reducir costes. Al permitir búsquedas a través de una amplia variedad de fuentes, Oracle Knowledge 8,5 amplifica el acceso al conocimiento, una vez oculto en los sistemas múltiples, aplicaciones y bases de datos utilizadas para almacenar contenido empresarial. Nuevas capacidades: AnswerFlow : Oracle Knowledge 8.5 introduce AnswerFlow, una nueva aplicación para la resolución de problemas guiada, diseñado para mejorar la eficiencia, reducir los costes de servicio y proporcionar experiencias de servicio al cliente personalizado. Mejora la analítica del conocimiento: estandarizado en Oracle Business Intelligence Enterprise Edition, el líder en la industria de las soluciones de Business Intelligence, Oracle Knowledge 8.5 proporciona una funcionalidad analítica robusta que se puede adaptar para satisfacer las necesidades únicas de cada negocio. Soporte de idiomas mejorada: Con las capacidades mejoradas en varios idiomas disponibles en Oracle Knowledge 8.5, incluyendo soporte Natural Language Search con 16 Idiomas y búsqueda por palabra clave mejorado para la mayoría de las otras lenguas , las empresas pueden llegar rápidamente a nuevos clientes y, al mismo tiempo, reducir los costes de hacerlo. Mejora la funcionalidad iConnect:Oracle Knowledge 8.5 ofrece iConnect mejorada para una mayor facilidad de uso y rendimiento. Esta aplicación especializada en conocimiento ofrece de forma proactiva un conocimiento contextualizado directamente en las aplicaciones de CRM, permitiendo a los empleados reducir el esfuerzo para servir a los clientes. Estandarización de Plataforma y Tecnología: Oracle Knowledge 8.5 ha sido certificado en tecnologías Oracle, incluyendo Oracle WebLogic Server, Oracle Business Intelligence, Oracle Exadata Database Machine y Oracle Exalogic Elastic Cloud, reduciendo el coste y la complejidad para los clientes a administrar los activos de todas las plataformas."Hemos realizado importantes inversiones de desarrollo desde nuestra adquisición de InQuira, y ahora estamos muy orgullosos de anunciar la disponibilidad de estos esfuerzos con el lanzamiento de Oracle Knowledge 8.5, por lo que es más fácil para las organizaciones obtener una ventaja diferencial a un coste total de propiedad significativamente menor ". dijo David Vap,Vicepresident productos de Oracle. Puedes encontrar más información aquí: Oracle Knowledge 8.5 Oracle Customer Experience Oracle WebLogic Server Oracle Business Intelligence Enterprise Edition

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  • La búsqueda de la eficiencia como Santo Grial de las TIC sanitarias

    - by Eloy M. Rodríguez
    Las XVIII Jornadas de Informática Sanitaria en Andalucía se han cerrado el pasado viernes con 11.500 horas de inteligencia colectiva. Aunque el cálculo supongo que resulta de multiplicar las horas de sesiones y talleres por el número de inscritos, lo que no sería del todo real ya que la asistencia media calculo que andaría por las noventa personas, supongo que refleja el global si incluimos el montante de interacciones informales que el formato y lugar de celebración favorecen. Mi resumen subjetivo es que todos somos conscientes de que debemos conseguir más eficiencia en y gracias a las TIC y que para ello hemos señalado algunas pautas, que los asistentes, en sus diferentes roles debiéramos aplicar y ayudar a difundir. En esa línea creo que destaca la necesidad de tener muy claro de dónde se parte y qué se quiere conseguir, para lo que es imprescindible medir y que las medidas ayuden a retroalimentar al sistema en orden de conseguir sus objetivos. Y en este sentido, a nivel anecdótico, quisiera dejar una paradoja que se presentó sobre la eficiencia: partiendo de que el coste/día de hospitalización es mayor al principio que los últimos días de la estancia, si se consigue ser más eficiente y reducir la estancia media, se liberarán últimos días de estancia que se utilizarán para nuevos ingresos, lo que hará que el número de primeros días de estancia aumente el coste económico total. En este caso mejoraríamos el servicio a los ciudadanos pero aumentaríamos el coste, salvo que se tomasen acciones para redimensionar la oferta hospitalaria bajando el coste y sin mejorer la calidad. También fue tema destacado la posibilidad/necesidad de aprovechar las capacidades de las TIC para realizar cambios estructurales y hacer que la medicina pase de ser reactiva a proactiva mediante alarmas que facilitasen que se actuase antes de ocurra el problema grave. Otro tema que se trató fue la necesidad real de corresponsabilizar de verdad al ciudadano, gracias a las enormes posibilidades a bajo coste que ofrecen las TIC, asumiendo un proceso hacia la salud colaborativa que tiene muchos retos por delante pero también muchas más oportunidades. Y la carpeta del ciudadano, emergente en varios proyectos e ideas, es un paso en ese aspecto. Un tema que levantó pasiones fue cuando la Directora Gerente del Sergas se quejó de que los proyectos TIC eran lentísimos. Desgraciadamente su agenda no le permitió quedarse al debate que fue bastante intenso en el que salieron temas como el larguísimo proceso administrativo, las especificaciones cambiantes, los diseños a medida, etc como factores más allá de la eficiencia especifica de los profesionales TIC involucrados en los proyectos. Y por último quiero citar un tema muy interesante en línea con lo hablado en las jornadas sobre la necesidad de medir: el Índice SEIS. La idea es definir una serie de criterios agrupados en grandes líneas y con un desglose fino que monitorice la aportación de las TIC en la mejora de la salud y la sanidad. Nos presentaron unas versiones previas con debate aún abierto entre dos grandes enfoques, partiendo desde los grandes objetivos hasta los procesos o partiendo desde los procesos hasta los objetivos. La discusión no es sólo académica, ya que influye en los parámetros a establecer. La buena noticia es que está bastante avanzado el trabajo y que pronto los servicios de salud podrán tener una herramienta de comparación basada en la realidad nacional. Para los interesados, varios asistentes hemos ido tuiteando las jornadas, por lo que el que quiera conocer un poco más detalles puede ir a Twitter y buscar la etiqueta #jisa18 y empezando del más antiguo al más moderno se puede hacer un seguimiento con puntos de vista subjetivos sobre lo allí ocurrido. No puedo dejar de hacer un par de autocríticas, ya que soy miembro de la SEIS. La primera es sobre el portal de la SEIS que no ha tenido la interactividad que unas jornadas como estas necesitaban. Pronto empezará a tener documentos y análisis de lo allí ocurrido y luego vendrán las crónicas y análisis más cocinados en la revista I+S. Pero en la segunda década del siglo XXI se necesita bastante más. La otra es sobre la no deseada poca presencia de usuarios de las TIC sanitarias en los roles de profesionales sanitarios y ciudadanos usuarios de los sistemas de información sanitarios. Tenemos que ser proactivos para que acudan en número significativo, ya que si no estamos en riesgo de ser unos TIC-sanitarios absolutistas: todo para los usuarios pero sin los usuarios. Tweet

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  • How to write a buffer-overflow exploit in windows XP,x86?

    - by Mask
    void function(int a, int b, int c) { char buffer1[5]; char buffer2[10]; int *ret; ret = buffer1 + 12; (*ret) += 8;//why is it 8?? } void main() { int x; x = 0; function(1,2,3); x = 1; printf("%d\n",x); } The above demo is from here: http://insecure.org/stf/smashstack.html But it's not working here: D:\test>gcc -Wall -Wextra hw.cpp && a.exe hw.cpp: In function `void function(int, int, int)': hw.cpp:6: warning: unused variable 'buffer2' hw.cpp: At global scope: hw.cpp:4: warning: unused parameter 'a' hw.cpp:4: warning: unused parameter 'b' hw.cpp:4: warning: unused parameter 'c' 1 And I don't understand why it's 8 though the author thinks: A little math tells us the distance is 8 bytes. My gdb dump as called: Dump of assembler code for function main: 0x004012ee <main+0>: push %ebp 0x004012ef <main+1>: mov %esp,%ebp 0x004012f1 <main+3>: sub $0x18,%esp 0x004012f4 <main+6>: and $0xfffffff0,%esp 0x004012f7 <main+9>: mov $0x0,%eax 0x004012fc <main+14>: add $0xf,%eax 0x004012ff <main+17>: add $0xf,%eax 0x00401302 <main+20>: shr $0x4,%eax 0x00401305 <main+23>: shl $0x4,%eax 0x00401308 <main+26>: mov %eax,0xfffffff8(%ebp) 0x0040130b <main+29>: mov 0xfffffff8(%ebp),%eax 0x0040130e <main+32>: call 0x401b00 <_alloca> 0x00401313 <main+37>: call 0x4017b0 <__main> 0x00401318 <main+42>: movl $0x0,0xfffffffc(%ebp) 0x0040131f <main+49>: movl $0x3,0x8(%esp) 0x00401327 <main+57>: movl $0x2,0x4(%esp) 0x0040132f <main+65>: movl $0x1,(%esp) 0x00401336 <main+72>: call 0x4012d0 <function> 0x0040133b <main+77>: movl $0x1,0xfffffffc(%ebp) 0x00401342 <main+84>: mov 0xfffffffc(%ebp),%eax 0x00401345 <main+87>: mov %eax,0x4(%esp) 0x00401349 <main+91>: movl $0x403000,(%esp) 0x00401350 <main+98>: call 0x401b60 <printf> 0x00401355 <main+103>: leave 0x00401356 <main+104>: ret 0x00401357 <main+105>: nop 0x00401358 <main+106>: add %al,(%eax) 0x0040135a <main+108>: add %al,(%eax) 0x0040135c <main+110>: add %al,(%eax) 0x0040135e <main+112>: add %al,(%eax) End of assembler dump. Dump of assembler code for function function: 0x004012d0 <function+0>: push %ebp 0x004012d1 <function+1>: mov %esp,%ebp 0x004012d3 <function+3>: sub $0x38,%esp 0x004012d6 <function+6>: lea 0xffffffe8(%ebp),%eax 0x004012d9 <function+9>: add $0xc,%eax 0x004012dc <function+12>: mov %eax,0xffffffd4(%ebp) 0x004012df <function+15>: mov 0xffffffd4(%ebp),%edx 0x004012e2 <function+18>: mov 0xffffffd4(%ebp),%eax 0x004012e5 <function+21>: movzbl (%eax),%eax 0x004012e8 <function+24>: add $0x5,%al 0x004012ea <function+26>: mov %al,(%edx) 0x004012ec <function+28>: leave 0x004012ed <function+29>: ret In my case the distance should be - = 5,right?But it seems not working..

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  • How to write a buffer-overflow exploit in GCC,windows XP,x86?

    - by Mask
    void function(int a, int b, int c) { char buffer1[5]; char buffer2[10]; int *ret; ret = buffer1 + 12; (*ret) += 8;//why is it 8?? } void main() { int x; x = 0; function(1,2,3); x = 1; printf("%d\n",x); } The above demo is from here: http://insecure.org/stf/smashstack.html But it's not working here: D:\test>gcc -Wall -Wextra hw.cpp && a.exe hw.cpp: In function `void function(int, int, int)': hw.cpp:6: warning: unused variable 'buffer2' hw.cpp: At global scope: hw.cpp:4: warning: unused parameter 'a' hw.cpp:4: warning: unused parameter 'b' hw.cpp:4: warning: unused parameter 'c' 1 And I don't understand why it's 8 though the author thinks: A little math tells us the distance is 8 bytes. My gdb dump as called: Dump of assembler code for function main: 0x004012ee <main+0>: push %ebp 0x004012ef <main+1>: mov %esp,%ebp 0x004012f1 <main+3>: sub $0x18,%esp 0x004012f4 <main+6>: and $0xfffffff0,%esp 0x004012f7 <main+9>: mov $0x0,%eax 0x004012fc <main+14>: add $0xf,%eax 0x004012ff <main+17>: add $0xf,%eax 0x00401302 <main+20>: shr $0x4,%eax 0x00401305 <main+23>: shl $0x4,%eax 0x00401308 <main+26>: mov %eax,0xfffffff8(%ebp) 0x0040130b <main+29>: mov 0xfffffff8(%ebp),%eax 0x0040130e <main+32>: call 0x401b00 <_alloca> 0x00401313 <main+37>: call 0x4017b0 <__main> 0x00401318 <main+42>: movl $0x0,0xfffffffc(%ebp) 0x0040131f <main+49>: movl $0x3,0x8(%esp) 0x00401327 <main+57>: movl $0x2,0x4(%esp) 0x0040132f <main+65>: movl $0x1,(%esp) 0x00401336 <main+72>: call 0x4012d0 <function> 0x0040133b <main+77>: movl $0x1,0xfffffffc(%ebp) 0x00401342 <main+84>: mov 0xfffffffc(%ebp),%eax 0x00401345 <main+87>: mov %eax,0x4(%esp) 0x00401349 <main+91>: movl $0x403000,(%esp) 0x00401350 <main+98>: call 0x401b60 <printf> 0x00401355 <main+103>: leave 0x00401356 <main+104>: ret 0x00401357 <main+105>: nop 0x00401358 <main+106>: add %al,(%eax) 0x0040135a <main+108>: add %al,(%eax) 0x0040135c <main+110>: add %al,(%eax) 0x0040135e <main+112>: add %al,(%eax) End of assembler dump. Dump of assembler code for function function: 0x004012d0 <function+0>: push %ebp 0x004012d1 <function+1>: mov %esp,%ebp 0x004012d3 <function+3>: sub $0x38,%esp 0x004012d6 <function+6>: lea 0xffffffe8(%ebp),%eax 0x004012d9 <function+9>: add $0xc,%eax 0x004012dc <function+12>: mov %eax,0xffffffd4(%ebp) 0x004012df <function+15>: mov 0xffffffd4(%ebp),%edx 0x004012e2 <function+18>: mov 0xffffffd4(%ebp),%eax 0x004012e5 <function+21>: movzbl (%eax),%eax 0x004012e8 <function+24>: add $0x5,%al 0x004012ea <function+26>: mov %al,(%edx) 0x004012ec <function+28>: leave 0x004012ed <function+29>: ret In my case the distance should be - = 5,right?But it seems not working.. Why function needs 56 bytes for local variables?( sub $0x38,%esp )

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  • Multiple synonym dictionary matches in PostgreSQL full text searching

    - by Ryan VanMiddlesworth
    I am trying to do full text searching in PostgreSQL 8.3. It worked splendidly, so I added in synonym matching (e.g. 'bob' == 'robert') using a synonym dictionary. That works great too. But I've noticed that it apparently only allows a word to have one synonym. That is, 'al' cannot be 'albert' and 'allen'. Is this correct? Is there any way to have multiple dictionary matches in a PostgreSQL synonym dictionary? For reference, here is my sample dictionary file: bob robert bobby robert al alan al albert al allen And the SQL that creates the full text search config: CREATE TEXT SEARCH DICTIONARY nickname (TEMPLATE = synonym, SYNONYMS = nickname); CREATE TEXT SEARCH CONFIGURATION dxp_name (COPY = simple); ALTER TEXT SEARCH CONFIGURATION dxp_name ALTER MAPPING FOR asciiword WITH nickname, simple; What am I doing wrong? Thanks!

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  • Problem with stack based implementation of function 0x42 of int 0x13

    - by IceCoder
    I'm trying a new approach to int 0x13 (just to learn more about the way the system works): using stack to create a DAP.. Assuming that DL contains the disk number, AX contains the address of the bootable entry in PT, DS is updated to the right segment and the stack is correctly set, this is the code: push DWORD 0x00000000 add ax, 0x0008 mov si, ax push DWORD [ds:(si)] push DWORD 0x00007c00 push WORD 0x0001 push WORD 0x0010 push ss pop ds mov si, sp mov sp, bp mov ah, 0x42 int 0x13 As you can see: I push the dap structure onto the stack, update DS:SI in order to point to it, DL is already set, then set AX to 0x42 and call int 0x13 the result is error 0x01 in AH and obviously CF set. No sectors are transferred. I checked the stack trace endlessly and it is ok, the partition table is ok too.. I cannot figure out what I'm missing... This is the stack trace portion of the disk address packet: 0x000079ea: 10 00 adc %al,(%bx,%si) 0x000079ec: 01 00 add %ax,(%bx,%si) 0x000079ee: 00 7c 00 add %bh,0x0(%si) 0x000079f1: 00 00 add %al,(%bx,%si) 0x000079f3: 08 00 or %al,(%bx,%si) 0x000079f5: 00 00 add %al,(%bx,%si) 0x000079f7: 00 00 add %al,(%bx,%si) 0x000079f9: 00 a0 07 be add %ah,-0x41f9(%bx,%si) I'm using qemu latest version and trying to read from hard drive (0x80), have also tried with a 4bytes alignment for the structure with the same result (CF 1 AH 0x01), the extensions are present.

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  • NASM and a question about ADC - ASM 8086

    - by Tal
    Hello,I study assembly on High-school and I would like to try to make assembly programs at home. I downloaded NASM but I don't understand how to run the .s files with it - if you can write a simple way here to run it I'd glad :-) and in addition I have a question: when I use ADC for exmaple: AL = 01 and BL = 02, and CF = 1, when I make this: ADC AL,BL Will AL be 3 or 4? (with the CF addition or without?) Thank you!!

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  • How to make the tokenizer detect empty spaces while using strtok()

    - by Shadi Al Mahallawy
    I am designing a c++ program, somewhere in the program i need to detect if there is a blank(empty token) next to the token used know eg. if(token1==start) { token2=strtok(NULL," "); if(token2==NULL) {LCCTR=0;} else {LCCTR=atoi(token2);} so in the previous peice token1 is pointing to start , and i want to check if there is anumber next to the start , so I used token2=strtok(NULL," ") to point to the next token but unfortunattly the strtok function cannot detect empty spaces so it gives me an error at run time"INVALID NULL POINTER" how can i fix it or is there another function to use to detect empty spaces #include <iostream> #include<string> #include<map> #include<iomanip> #include<fstream> #include<ctype.h> using namespace std; const int MAX=300; int LCCTR; int START(char* token1); char* PASS1(char*token1); void tokinizer() { ifstream in; ofstream out; char oneline[MAX]; in.open("infile.txt"); out.open("outfile.txt"); if(in.is_open()) { char *token1; in.getline(oneline,MAX); token1 = strtok(oneline," \t"); START (token1); //cout<<'\t'; while(token1!=NULL) { //PASS1(token1); //cout<<token1<<" "; token1=strtok(NULL," \t"); if(NULL==token1) {//cout<<endl; //cout<<LCCTR<<'\t'; in.getline(oneline,MAX); token1 = strtok(oneline," \t"); } } } in.close(); out.close(); } int START(char* token1) { string start("START"); char*token2; if(token1 != start) {LCCTR=0;} else if(token1==start) { token2=strchr(token1+2,' '); cout<<token2; if(token2==NULL) {LCCTR=0;} else {LCCTR=atoi(token2); if(atoi(token2)>9999||atoi(token2)<0){cout<<"IVALID STARTING ADDRESS"<<endl;exit(1);} } } return LCCTR; } char* PASS1 (char*token1) { map<string,int> operations; map<string,int>symtable; map<string,int>::iterator it; pair<map<string,int>::iterator,bool> ret; char*token3=NULL; char*token2=NULL; string test; string comp(" "); string start("START"); string word("WORD"); string byte("BYTE"); string resb("RESB"); string resw("RESW"); string end("END"); operations["ADD"] = 18; operations["AND"] = 40; operations["COMP"] = 28; operations["DIV"] = 24; operations["J"] = 0X3c; operations["JEQ"] =30; operations["JGT"] =34; operations["JLT"] =38; operations["JSUB"] =48; operations["LDA"] =00; operations["LDCH"] =50; operations["LDL"] =55; operations["LDX"] =04; operations["MUL"] =20; operations["OR"] =44; operations["RD"] =0xd8; operations["RSUB"] =0x4c; operations["STA"] =0x0c; operations["STCH"] =54; operations["STL"] =14; operations["STSW"] =0xe8; operations["STX"] =10; operations["SUB"] =0x1c; operations["TD"] =0xe0; operations["TIX"] =0x2c; operations["WD"] =0xdc; if(operations.find("ADD")->first==token1) { token2=strtok(NULL," "); //test=token2; cout<<token2; //if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} //else{LCCTR=LCCTR+3;} } /*else if(operations.find("AND")->first==token1) { token2=strtok(NULL," "); test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("COMP")->first==token1) { token2=token1+5; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("DIV")->first==token1) { token2=token1+4; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("J")->first==token1) { token2=token1+2; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("JEQ")->first==token1) { token2=token1+5; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("JGT")->first==token1) { token2=strtok(NULL," "); test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("JLT")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("JSUB")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("LDA")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("LDCH")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("LDL")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("LDX")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("MUL")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("OR")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("RD")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("RSUB")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("STA")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("STCH")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("STL")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("STSW")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("STX")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("SUB")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("TD")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("TIX")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("WD")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} }*/ //else if( if(word==token1) {LCCTR=LCCTR+3;} else if(byte==token1) {string test; token2=token1+7; test=token2; if(test[0]=='C') {token3=token1+10; test=token3; if(test.length()>15) {cout<<"ERROR"<<endl; exit(1);} } else if(test[0]=='X') {token3=token1+10; test=token3; if(test.length()>14) {cout<<"ERROR"<<endl; exit(1);} } LCCTR=LCCTR+test.length(); } else if(resb==token1) {token3=token1+5; LCCTR=LCCTR+atoi(token3);} else if(resw==token1) {token3=token1+5; LCCTR=LCCTR+3*atoi(token3);} else if(end==token1) {exit(1);} /*else { test=token1; int last=test.length(); if(token1==start||test[0]=='C'||test[0]=='X'||ispunct(test[last])||isdigit(test[0])||isdigit(test[1])||isdigit(test[2])||isdigit(test[3])){} else { token2=strtok(NULL," "); //test=token2; cout<<token2; if(token2!=NULL) { symtable.insert( pair<string,int>(token1,LCCTR)); for(it=symtable.begin() ;it!=symtable.end() ;++it) {/*cout<<"symbol: "<<it->first<<" LCCTR: "<<it->second<<endl;} } else{} } }*/ return token3; } int main() { tokinizer(); return 0; }

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  • 8086 programming using TASM: pc to pc communication

    - by Komal
    .model small .stack 100 .data .code mov ah,00h mov al,0e3h mov dx,00h int 14h back: nop l1: mov ah,03h mov dx,00h int 14h and ah,01h cmp ah,01h jne l1 mov ah,02h mov dx,00h int 21h mov dl,al mov ah,02h int 21h jmb back mov ah,4ch int 21h end this a pc to pc commnication receiver program.i would like to know why have we used the mov dx,00h function and what is the meaning of mov al,0e3h this ?

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  • Question about ADD on ASM 8086

    - by Tal
    Hello, I'm studying ASM 8086 theoretically on highschool. (that means that I study ASM 8086 on a notebook, and never got to run it over a computer). And I don't understand - what will happen if I do this: MOV AL, F2h ADD AL, 20h What will the computer do? (what will be the value of AL,AX, CF,ZF?) and what will happen if I do this: MOV AH,F2h ADD AH,20h Thank you !!

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  • How ca I return a value from a function

    - by Shadi Al Mahallawy
    I used a function to calculate information about certain instructions I intialized in a map,like this void get_objectcode(char*&token1,const int &y) { map<string,int> operations; operations["ADD"] = 18; operations["AND"] = 40; operations["COMP"] = 28; operations["DIV"] = 24; operations["J"] = 0X3c; operations["JEQ"] =30; operations["JGT"] =34; operations["JLT"] =38; operations["JSUB"] =48; operations["LDA"] =00; operations["LDCH"] =50; operations["LDL"] =55; operations["LDX"] =04; operations["MUL"] =20; operations["OR"] =44; operations["RD"] =0xd8; operations["RSUB"] =0x4c; operations["STA"] =0x0c; operations["STCH"] =54; operations["STL"] =14; operations["STSW"] =0xe8; operations["STX"] =10; operations["SUB"] =0x1c; operations["TD"] =0xe0; operations["TIX"] =0x2c; operations["WD"] =0xdc; if ((operations.find("ADD")->first==token1)||(operations.find("AND")->first==token1)||(operations.find("COMP")->first==token1) ||(operations.find("DIV")->first==token1)||(operations.find("J")->first==token1)||(operations.find("JEQ")->first==token1) ||(operations.find("JGT")->first==token1)||(operations.find("JLT")->first==token1)||(operations.find("JSUB")->first==token1) ||(operations.find("LDA")->first==token1)||(operations.find("LDCH")->first==token1)||(operations.find("LDL")->first==token1) ||(operations.find("LDX")->first==token1)||(operations.find("MUL")->first==token1)||(operations.find("OR")->first==token1) ||(operations.find("RD")->first==token1)||(operations.find("RSUB")->first==token1)||(operations.find("STA")->first==token1)||(operations.find("STCH")->first==token1)||(operations.find("STCH")->first==token1)||(operations.find("STL")->first==token1) ||(operations.find("STSW")->first==token1)||(operations.find("STX")->first==token1)||(operations.find("SUB")->first==token1) ||(operations.find("TD")->first==token1)||(operations.find("TIX")->first==token1)||(operations.find("WD")->first==token1)) { int y=operations.find(token1)->second; //cout<<hex<<y<<endl; } return ; } which if I cout y in the function gives me an answer just fine which is what i need but there is a problem tring to return the value from the function so that I could use it outside the function , it gives a whole different answer, what is the problem

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  • vb.net -- Using arraylist as key in dictionary

    - by Zahid
    Dim dct As New Dictionary(Of ArrayList, ArrayList) ' Populate Dictionary dct.Add(New ArrayList({"Dot", "0"}), New ArrayList({20, 30, 40, 50})) dct.Add(New ArrayList({"Dot", "1"}), New ArrayList({120, 130, 140, 150})) ' Search in dictionary Dim al As New ArrayList({"Dot", "2"}) If dct.ContainsKey(al) Then *' does not work* MessageBox.Show("Found: " & al(0).ToString) End If

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  • Problem with asm program (nasm)

    - by GLeBaTi
    org 0x100 SEGMENT .CODE mov ah,0x9 mov dx, Msg1 int 0x21 ;string input mov ah,0xA mov dx,buff int 0x21 mov ax,0 mov al,[buff+1]; length ;string UPPERCASE mov cl, al mov si, buff cld loop1: lodsb; cmp al, 'a' jnb upper loop loop1 ;output mov ah,0x9 mov dx, buff int 0x21 exit: mov ah, 0x8 int 0x21 int 0x20 upper: sub al,32 jmp loop1 SEGMENT .DATA Msg1 db 'Press string: $' buff db 254,0 this code perform poorly. I think that problem in "jnb upper". This program make small symbols into big symbols.

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  • easy asm program(nasm)

    - by GLeBaTi
    org 0x100 SEGMENT .CODE mov ah,0x9 mov dx, Msg1 int 0x21 ;string input mov ah,0xA mov dx,buff int 0x21 mov ax,0 mov al,[buff+1]; length ;string UPPERCASE mov cl, al mov si, buff cld loop1: lodsb; cmp al, 'a' jnb upper loop loop1 ;output mov ah,0x9 mov dx, buff int 0x21 exit: mov ah, 0x8 int 0x21 int 0x20 upper: sub al,32 jmp loop1 SEGMENT .DATA Msg1 db 'Press string: $' buff db 254,0 this code perform poorly. I think that problem in "jnb upper". This program make small symbols into big symbols.

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  • Scan for first zero bit (Assembly)?

    - by cthulhu
    I have some numbers in AH, AL, BL, BH registers. I need to check whether there is 0 bit in each of the registers in left half of the number. If yes, then put into check variable value 10 else -10. How can I do this? I tried something like that: org 100h check dw 0 mov ah, 11111111b mov al, 11111111b mov bl, 11111111b mov bh, 11111111b mov check, -10 shr ah, 4 shr al, 4 shr bl, 4 shr bh, 4 cmp ah, 0Fh jz first first: cmp al, 0Fh jz second second: cmp bl, 0Fh jz third third: cmp bh, 0Fh jz final final: mov check, 10 ret

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  • Autocomplete for generic types in Eclipse

    - by AvrDragon
    "Refer to objects by their interfaces" is a good practise, as mentioned in Effective Java. So for example i prefer List<String> al = new ArrayList<String>(); over ArrayList<String> al = new ArrayList<String>(); in my code. One annoying thing is that if i type ArrayList<String> al = new and then hit Ctrl+Space in Eclipse i get ArrayList<String>() as propostal. But if i type List al = new and then hit Ctrl+Space i will get only propostal to define anonymous inner class, but not propostals such as new ArrayList<String>(), what is 99% the case, or for example new Vector<String>(). Is there any way to get the subclasses as propostals for generic types?

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  • FBX SDK Not Converting Child Node Coordinate Systems

    - by Al Bundy
    I am trying to import a scene into my application from an fbx file. In 3DS Max, the scene and it’s local translations are as follows: Root (0, 0, 0) '-Sphere001 (-15, 30, 0) ' '-Sphere002 (-2, -30, 0) ' '-Sphere003 (-30, -20, 0) '-Cube001 (35, -15, 0) This is the code that I am using to get the translations of each node: FbxDouble3 fbxPosition = pChild->LclTranslation.Get(); FbxDouble3 fbxRotation = pChild->LclRotation.Get(); FbxDouble3 fbxScale = pChild->LclScaling.Get(); When I try to import the scene, the first node from the scene is getting converted to a right handed system, using this conversion: (X, Z, -Y), but none of their child nodes are. after importing the scene, the local translations I get are as follows: Root (0, 0, 0) --Sphere001 (-15, 0, -30) - converted ----Sphere002 (-2, -30, 0) - not converted ------Sphere003 (-30, -20, 0) - not converted --Cube001 (35, 0, 15) - converted Can anybody help me make sense of this? Thanks

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  • Workshop de desarrollo de aplicaciones Windows Store

    - by MarianoS
    La semana próxima con mi compañero de Lagash, RodoF, estaremos dando un Workshop de desarrollo de aplicaciones Windows Store en el MUG los dias 10, 11, y 12 de Octubre.Durante esos 3 dias haremos un repaso de la plataforma Windows 8, el diseño de aplicaciones Modern UI, y las herramientas y lenguajes que tenemos disponibles para desarrollarlas, todo esto con mucha practica.!Y como bonus al final del workshop se ofrecerá la posibilidad e subir las aplicaciones que se desarrollen al Windows Store!Aquí pueden ver el detalle del curso y registrarse.Los esperamos!!

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  • Expando Object and dynamic property pattern

    - by Al.Net
    I have read about 'dynamic property pattern' of Martin Fowler in his site under the tag 1997 in which he used dictionary kind of stuff to achieve this pattern. And I have come across about Expando object in c# very recently. When I see its implementation, I am able to see IDictionary implemented. So Expando object uses dictionary to store dynamic properties and is it what, Martin Fowler already defined 15 years ago?

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  • How can I keep the cpu temp low?

    - by Newton
    I have an HP pavilion dv7, I'm using ubuntu 12.04 so the overheating problem with sandybridge cpu is a lot better. However my laptop is still becoming too hot to keep on my legs. The problem is that the fan wait too much before starting, so the medium temp is too hight. When I'm using windows 7 the laptop is room-temperature cold, I've absolutely no problem. On windows the fan is always spinning very low & very silently so the heat is continuously removed, without reaching an unconfortable temp. How can I force the computer to act like that also on ubuntu? PS The bios can't let me control this kind of thing, and this is my experience with lm-sensors and fancontrol al@notebook:~$ sudo sensors-detect [sudo] password for al: # sensors-detect revision 5984 (2011-07-10 21:22:53 +0200) # System: Hewlett-Packard HP Pavilion dv7 Notebook PC (laptop) # Board: Hewlett-Packard 1800 This program will help you determine which kernel modules you need to load to use lm_sensors most effectively. It is generally safe and recommended to accept the default answers to all questions, unless you know what you're doing. Some south bridges, CPUs or memory controllers contain embedded sensors. Do you want to scan for them? This is totally safe. (YES/no): y Module cpuid loaded successfully. Silicon Integrated Systems SIS5595... No VIA VT82C686 Integrated Sensors... No VIA VT8231 Integrated Sensors... No AMD K8 thermal sensors... No AMD Family 10h thermal sensors... No AMD Family 11h thermal sensors... No AMD Family 12h and 14h thermal sensors... No AMD Family 15h thermal sensors... No AMD Family 15h power sensors... No Intel digital thermal sensor... Success! (driver `coretemp') Intel AMB FB-DIMM thermal sensor... No VIA C7 thermal sensor... No VIA Nano thermal sensor... No Some Super I/O chips contain embedded sensors. We have to write to standard I/O ports to probe them. This is usually safe. Do you want to scan for Super I/O sensors? (YES/no): y Probing for Super-I/O at 0x2e/0x2f Trying family `National Semiconductor/ITE'... No Trying family `SMSC'... No Trying family `VIA/Winbond/Nuvoton/Fintek'... No Trying family `ITE'... No Probing for Super-I/O at 0x4e/0x4f Trying family `National Semiconductor/ITE'... Yes Found unknown chip with ID 0x8518 Some hardware monitoring chips are accessible through the ISA I/O ports. We have to write to arbitrary I/O ports to probe them. This is usually safe though. Yes, you do have ISA I/O ports even if you do not have any ISA slots! Do you want to scan the ISA I/O ports? (YES/no): y Probing for `National Semiconductor LM78' at 0x290... No Probing for `National Semiconductor LM79' at 0x290... No Probing for `Winbond W83781D' at 0x290... No Probing for `Winbond W83782D' at 0x290... No Lastly, we can probe the I2C/SMBus adapters for connected hardware monitoring devices. This is the most risky part, and while it works reasonably well on most systems, it has been reported to cause trouble on some systems. Do you want to probe the I2C/SMBus adapters now? (YES/no): y Using driver `i2c-i801' for device 0000:00:1f.3: Intel Cougar Point (PCH) Module i2c-i801 loaded successfully. Module i2c-dev loaded successfully. Next adapter: i915 gmbus disabled (i2c-0) Do you want to scan it? (YES/no/selectively): y Next adapter: i915 gmbus ssc (i2c-1) Do you want to scan it? (YES/no/selectively): y Next adapter: i915 GPIOB (i2c-2) Do you want to scan it? (YES/no/selectively): y Next adapter: i915 gmbus vga (i2c-3) Do you want to scan it? (YES/no/selectively): y Next adapter: i915 GPIOA (i2c-4) Do you want to scan it? (YES/no/selectively): y Next adapter: i915 gmbus panel (i2c-5) Do you want to scan it? (YES/no/selectively): y Client found at address 0x50 Probing for `Analog Devices ADM1033'... No Probing for `Analog Devices ADM1034'... No Probing for `SPD EEPROM'... No Probing for `EDID EEPROM'... Yes (confidence 8, not a hardware monitoring chip) Next adapter: i915 GPIOC (i2c-6) Do you want to scan it? (YES/no/selectively): y Client found at address 0x50 Probing for `Analog Devices ADM1033'... No Probing for `Analog Devices ADM1034'... No Probing for `SPD EEPROM'... No Probing for `EDID EEPROM'... Yes (confidence 8, not a hardware monitoring chip) Next adapter: i915 gmbus dpc (i2c-7) Do you want to scan it? (YES/no/selectively): y Next adapter: i915 GPIOD (i2c-8) Do you want to scan it? (YES/no/selectively): y Next adapter: i915 gmbus dpb (i2c-9) Do you want to scan it? (YES/no/selectively): y Next adapter: i915 GPIOE (i2c-10) Do you want to scan it? (YES/no/selectively): y Next adapter: i915 gmbus reserved (i2c-11) Do you want to scan it? (YES/no/selectively): y Next adapter: i915 gmbus dpd (i2c-12) Do you want to scan it? (YES/no/selectively): y Next adapter: i915 GPIOF (i2c-13) Do you want to scan it? (YES/no/selectively): y Next adapter: DPDDC-B (i2c-14) Do you want to scan it? (YES/no/selectively): y Now follows a summary of the probes I have just done. Just press ENTER to continue: Driver `coretemp': * Chip `Intel digital thermal sensor' (confidence: 9) To load everything that is needed, add this to /etc/modules: #----cut here---- # Chip drivers coretemp #----cut here---- If you have some drivers built into your kernel, the list above will contain too many modules. Skip the appropriate ones! Do you want to add these lines automatically to /etc/modules? (yes/NO)y Successful! Monitoring programs won't work until the needed modules are loaded. You may want to run 'service module-init-tools start' to load them. Unloading i2c-dev... OK Unloading i2c-i801... OK Unloading cpuid... OK al@notebook:~$ sudo /etc/init.d/module-init-tools restart Rather than invoking init scripts through /etc/init.d, use the service(8) utility, e.g. service module-init-tools restart Since the script you are attempting to invoke has been converted to an Upstart job, you may also use the stop(8) and then start(8) utilities, e.g. stop module-init-tools ; start module-init-tools. The restart(8) utility is also available. module-init-tools stop/waiting al@notebook:~$ sudo service module-init-tools restart stop: Unknown instance: module-init-tools stop/waiting al@notebook:~$ sudo service module-init-tools start module-init-tools stop/waiting al@notebook:~$ sudo pwmconfig # pwmconfig revision 5857 (2010-08-22) This program will search your sensors for pulse width modulation (pwm) controls, and test each one to see if it controls a fan on your motherboard. Note that many motherboards do not have pwm circuitry installed, even if your sensor chip supports pwm. We will attempt to briefly stop each fan using the pwm controls. The program will attempt to restore each fan to full speed after testing. However, it is ** very important ** that you physically verify that the fans have been to full speed after the program has completed. /usr/sbin/pwmconfig: There are no pwm-capable sensor modules installed Is my case too desperate?

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  • Does syntax really matter in a programming language?

    - by Saif al Harthi
    One of my professors says "the Syntax is the UI of a programming language", languages like ruby have great readability & its growing but we see alot of programmers productive with C\C++, so as programmers does it really matter that the syntax should be acceptable? I would love to know your opinion on that. Disclaimer: I'm not trying to start an argument I thought this is a good topic of discussion. Update : this turns out to be a good topic i'm glad you are all participating it , there will be more good questions to come

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  • I need a js function that can sort state from Dropbox and gave me a phone number to call [on hold]

    - by User584
    AL West AR West CT EAST DC EAST Il West MN East player one groupe A player tow Groupe B player zero Groupe D if the Group is A and the State is AL then Phone = 0762154852 if the Group is B and the State is AR then phone = 2145632541 if the group is D and the state is MN then phone = 2589632541 if i player from a dropbox and then i select State from a dropbox I want the Field phone Show the right number

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