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  • ImageMagick PDF to JPEG conversion results in green square where image should be

    - by ceejayoz
    I'm attempting to convert a PDF to a JPEG using ImageMagick. The PDF: baby_aRCWTU.pdf The command: convert -density 260 -profile 'SWOP.icc' -profile 'sRGB.icm' 'baby_aRCWTU.pdf' 'baby_aRCWTU.jpg' The resulting JPEG: baby_aRCWTU.jpg As you can see, the text is rendered nicely, but the embedded image shows up as a green square. Any ideas? This occurs with and without the colour profiles. edit: reposted due to broken links

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  • Diamond square algorithm.

    - by Gabriel A. Zorrilla
    I'm trying to write the Diamond-Square algorithm in Java to generate a random map but can't figure out the implementation... Anyone with some Java code (or other language) so i can check how the loop is made would be greatly appreciated! Thanks!

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  • Regular expression to extract text between either square or curly brackets

    - by ObiWanKenobi
    Related to my previous question, I have a string on the following format: this {is} a [sample] string with [some] {special} words. [another one] What is the regular expression to extract the words within either square or curly brackets, ie. {is} [sample] [some] {special} [another one] Note: In my use case, brackets cannot be nested. I would also like to keep the enclosing characters, so that I can tell the difference between them when processing the results.

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  • Convert template from "rounded corners" to "square"

    - by marco92w
    I've downloaded the following template: http://www.styleshout.com/templates/preview/Refresh11/index.html But unfortunately, it has rounded corners and shades. I want it to have square corners and the shades should be removed, too. It should look like this: But I'm not good enough at (X)HTML and CSS so I didn't manage to achieve this. Could you please help me? How could I remove the rounded corners? Please don't say "Take another template" ;) It's also for learning purposes :)

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  • Texture coordintes for a polygon and a square texture

    - by user146780
    basically I have a texture. I also have a lets say octagon (or any polygon). I find that octagon's bounding box. Let's say my texture is the size of the octagon's bounding box. How could I figure out the texture coordinates so that the texture maps to it. To clarify, lets say you had a square of tin foil and cut the octagon out you'd be left with a tin foil textured polygon.I'm just not sure how to figure it out for an arbitrary polygon. Thanks

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  • Python: writing a program to compute the area of a circle and square

    - by user1672504
    I have a question with an assignment. I'm not sure how to write this program and I really need help! Could someone help me with this? This is the assignment: Write a program that asks the user to enter two values: an integer choice and a real number x. If choice is 1, compute and display the area of a circle of radius x. If choice is 2, compute and display the are of a square with sides of length x. If choice is neither 1, nor 2, will display the text Invalid choice. Sample run: Enter choice: 2 Enter x: 8 The area is: 64.0 Sample run: Enter choice: 1 Enter x: 8 The area is: 201.06176 My attempt: choice = input ('Enter Choice:') choice_1 = int (choice) if (choice_1==1): radius = (int) print('Enter x:',radius) pi = 3.14159 area = ( radius ** 2 ) * pi print ( 'The Area is=' , area )

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  • PHP: form input field names containing square brackets like field[index]

    - by gidireich
    Hi, I've seen lot of code that handle forms, which creates input fields with names containing square brackets. I understand that this is being somehow converted to PHP arrays when a PHP script examines the $_POST variable. My questions about this: What is the mechanism behind? At which point this names that merely contain brackets are converted to arrays? Is this a feature of the HTPP protocol? Of web servers? Of the PHP language? Continuing the previous question, is this a commonly used hack or a normal programming tool? What are (all) the rules of using brackets in input field names? Can multidimensional arrays be created this way? Thanks, Gidi

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  • Javascript search and replace sequence of characters that contain square brackets

    - by Ruth
    Hello all I'm trying to search for '[EN]' in the string 'Nationality [EN] [ESP]', I want to remove this from the string so I'm using a replace method, code examaple below var str = 'Nationality [EN] [ESP]'; var find = "[EN]"; var regex = new RegExp(find, "g"); alert(str.replace(regex, '')); Since [EN] is identified as a character set this will output the string 'Nationality [] [ESP]' but I want to remove the square brackets aswell. I thought that I could escape them using \ but it didn't work Any advice would be much appreciated

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  • Opengl Triangle instead of square

    - by Dave
    Im trying to create a spinning square inside of xcode using opengl but instead for some reason I have a spinning triangle? I'm doing this inside of sio2 but I dont think this is the problem. Here is the triangle: http://img220.imageshack.us/img220/7051/snapzproxscreensnapz001.png Here is my code: void templateRender( void ) { const GLfloat squareVertices[] ={ 100.0f, -100.0f, 100.0f, -100.0f, -100.0f, 100.0f, 100.0f, 100.0f, }; const unsigned char squareColors[] = { 255, 255, 0, 255, 0, 255, 255, 255, 0, 0, 0, 0, 255, 0, 255, 255, }; glMatrixMode( GL_MODELVIEW ); glLoadIdentity(); glClear( GL_DEPTH_BUFFER_BIT | GL_COLOR_BUFFER_BIT ); // Your rendering code here... sio2WindowEnter2D( sio2->_SIO2window, 0.0f, 1.0f ); { glVertexPointer( 2, GL_FLOAT, 0, squareVertices ); glEnableClientState(GL_VERTEX_ARRAY); //set up the color array glColorPointer( 4, GL_UNSIGNED_BYTE, 0, squareColors ); glEnableClientState( GL_COLOR_ARRAY ); glTranslatef( sio2->_SIO2window->scl->x * 0.5f, sio2->_SIO2window->scl->y * 0.5f, 0.0f ); static float rotz = 0.0f; glRotatef( rotz, 0.0f, 0.0f, 1.0f ); rotz += 90.0f * sio2->_SIO2window->d_time; glDrawArrays(GL_TRIANGLE_STRIP, 0, 4); } sio2WindowLeave2D(); }

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  • Python, dictionaries, and chi-square contingency table

    - by rohanbk
    I have a file which contains several lines in the following format (word, time that the word occurred in, and frequency of documents containing the given word within the given instance in time): #inputfile <word, time, frequency> apple, 1, 3 banana, 1, 2 apple, 2, 1 banana, 2, 4 orange, 3, 1 I have Python class below that I used to create 2-D dictionaries to store the above file using as the key, and frequency as the value: class Ddict(dict): ''' 2D dictionary class ''' def __init__(self, default=None): self.default = default def __getitem__(self, key): if not self.has_key(key): self[key] = self.default() return dict.__getitem__(self, key) wordtime=Ddict(dict) # Store each inputfile entry with a <word,time> key timeword=Ddict(dict) # Store each inputfile entry with a <time,word> key # Loop over every line of the inputfile for line in open('inputfile'): word,time,count=line.split(',') # If <word,time> already a key, increment count try: wordtime[word][time]+=count # Otherwise, create the key except KeyError: wordtime[word][time]=count # If <time,word> already a key, increment count try: timeword[time][word]+=count # Otherwise, create the key except KeyError: timeword[time][word]=count The question that I have pertains to calculating certain things while iterating over the entries in this 2D dictionary. For each word 'w' at each time 't', calculate: The number of documents with word 'w' within time 't'. (a) The number of documents without word 'w' within time 't'. (b) The number of documents with word 'w' outside time 't'. (c) The number of documents without word 'w' outside time 't'. (d) Each of the items above represents one of the cells of a chi-square contingency table for each word and time. Can all of these be calculated within a single loop or do they need to be done one at a time? Ideally, I would like the output to be what's below, where a,b,c,d are all the items calculated above: print "%s, %s, %s, %s" %(a,b,c,d)

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  • specifying multiple URLs with cURL/PHP using square brackets

    - by Raj Gundu
    I have a large array of URLS similar to this: $nodes = array( 'http://www.example.com/product.php?page=1&sortOn=sellprice', 'http://www.example.com/product.php?page=2&sortOn=sellprice', 'http://www.example.com/product.php?page=3&sortOn=sellprice' ); The cURL manual states here (http://curl.haxx.se/docs/manpage.html) that i can use square brackets '[]' to specify multiple urls. Used in the above example this would be similar to this: 'http://www.example.com/product.php?page=[1-3]&sortOn=sellprice' So far i have been unable to reference this correctly. This is the complete code segment I'm currently trying to utilize this with: $nodes = array( 'http://www.example.com/product.php?page=1&sortOn=sellprice', 'http://www.example.com/product.php?page=2&sortOn=sellprice', 'http://www.example.com/product.php?page=3&sortOn=sellprice' ); $node_count = count($nodes); $curl_arr = array(); $master = curl_multi_init(); for($i = 0; $i < $node_count; $i++) { $url =$nodes[$i]; $curl_arr[$i] = curl_init($url); curl_setopt($curl_arr[$i], CURLOPT_RETURNTRANSFER, true); curl_multi_add_handle($master, $curl_arr[$i]); } do { curl_multi_exec($master,$running); } while($running > 0); echo "results: "; for($i = 0; $i < $node_count; $i++) { $results = curl_multi_getcontent ( $curl_arr[$i] ); echo( $i . "\n" . $results . "\n"); echo 'done'; I can't seem to find any more documentation on this. Thanks in advance.

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  • strange chi-square result using scikit_learn with feature matrix

    - by user963386
    I am using scikit learn to calculate the basic chi-square statistics(sklearn.feature_selection.chi2(X, y)): def chi_square(feat,target): """ """ from sklearn.feature_selection import chi2 ch,pval = chi2(feat,target) return ch,pval chisq,p = chi_square(feat_mat,target_sc) print(chisq) print("**********************") print(p) I have 1500 samples,45 features,4 classes. The input is a feature matrix with 1500x45 and a target array with 1500 components. The feature matrix is not sparse. When I run the program and I print the arrray "chisq" with 45 components, I can see that the component 13 has a negative value and p = 1. How is it possible? Or what does it mean or what is the big mistake that I am doing? I am attaching the printouts of chisq and p: [ 9.17099260e-01 3.77439701e+00 5.35004211e+01 2.17843312e+03 4.27047184e+04 2.23204883e+01 6.49985540e-01 2.02132664e-01 1.57324454e-03 2.16322638e-01 1.85592258e+00 5.70455805e+00 1.34911126e-02 -1.71834753e+01 1.05112366e+00 3.07383691e-01 5.55694752e-02 7.52801686e-01 9.74807972e-01 9.30619466e-02 4.52669897e-02 1.08348058e-01 9.88146259e-03 2.26292358e-01 5.08579194e-02 4.46232554e-02 1.22740419e-02 6.84545170e-02 6.71339545e-03 1.33252061e-02 1.69296016e-02 3.81318236e-02 4.74945604e-02 1.59313146e-01 9.73037448e-03 9.95771327e-03 6.93777954e-02 3.87738690e-02 1.53693158e-01 9.24603716e-04 1.22473138e-01 2.73347277e-01 1.69060817e-02 1.10868365e-02 8.62029628e+00] ********************** [ 8.21299526e-01 2.86878266e-01 1.43400668e-11 0.00000000e+00 0.00000000e+00 5.59436980e-05 8.84899894e-01 9.77244281e-01 9.99983411e-01 9.74912223e-01 6.02841813e-01 1.26903019e-01 9.99584918e-01 1.00000000e+00 7.88884155e-01 9.58633878e-01 9.96573548e-01 8.60719653e-01 8.07347364e-01 9.92656816e-01 9.97473024e-01 9.90817144e-01 9.99739526e-01 9.73237195e-01 9.96995722e-01 9.97526259e-01 9.99639669e-01 9.95333185e-01 9.99853998e-01 9.99592531e-01 9.99417113e-01 9.98042114e-01 9.97286030e-01 9.83873717e-01 9.99745466e-01 9.99736512e-01 9.95239765e-01 9.97992843e-01 9.84693908e-01 9.99992525e-01 9.89010468e-01 9.64960636e-01 9.99418323e-01 9.99690553e-01 3.47893682e-02]

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  • Take positive square root in Mathematica

    - by Sagekilla
    Hi all, I'm currently doing some normalization along the lines of: J = Integrate[Psi[x, 0]^2, {x, 0, a}] sol = Solve[J == 1, A] A /. sol For this type of normalization, the negative square root is extraneous. My results are: In[49]:= J = Integrate[Psi[x, 0]^2, {x, 0, a}] Out[49]= 2 A^2 In[68]:= sol = Solve[J == 1, A] Out[68]= {{A -> -(1/Sqrt[2])}, {A -> 1/Sqrt[2]}} Even if I try giving it an Assuming[...] or Simplify[...], it still gives me the same results: In[69]:= sol = Assuming[A > 0, Solve[J == 1, A]] Out[69]= {{A -> -(1/Sqrt[2])}, {A -> 1/Sqrt[2]}} In[70]:= sol = FullSimplify[Solve[J == 1, A], A > 0] Out[70]= {{A -> -(1/Sqrt[2])}, {A -> 1/Sqrt[2]}} Can anyone tell me what I'm doing wrong here? I'd much appreciate it! If it helps any, I'm running Mathematica 7 on Windows 7 64-bit.

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  • sum of square of each elements in the vector using for_each

    - by pierr
    Hi, As the function accepted by for_each take only one parameter (the element of the vector), I have to define a static int sum = 0 somewhere so that It can be accessed after calling the for_each . I think this is awkward. Any better way to do this (still use for_each) ? #include <algorithm> #include <vector> #include <iostream> using namespace std; static int sum = 0; void add_f(int i ) { sum += i * i; } void test_using_for_each() { int arr[] = {1,2,3,4}; vector<int> a (arr ,arr + sizeof(arr)/sizeof(arr[0])); for_each( a.begin(),a.end(), add_f); cout << "sum of the square of the element is " << sum << endl; } In Ruby, We can do it this way: sum = 0 [1,2,3,4].each { |i| sum += i*i} #local variable can be used in the callback function puts sum #=> 30 Would you please show more examples how for_each is typically used in practical programming (not just print out each element)? Is it possible use for_each simulate 'programming pattern' like map and inject in Ruby (or map /fold in Haskell). #map in ruby >> [1,2,3,4].map {|i| i*i} => [1, 4, 9, 16] #inject in ruby [1, 4, 9, 16].inject(0) {|aac ,i| aac +=i} #=> 30 EDIT: Thank you all. I have learned so much from your replies. We have so many ways to do the same single thing in C++ , which makes it a little bit difficult to learn. But it's interesting :)

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  • Square collision detection problem (iPhone).

    - by thyrgle
    Hi, I know I've probably posted three questions related to this then deleted them, but thats only because I solved them before I got an answer. But, this one I can not solve and I don't believe it is that hard compared to the others. So, with out further ado, here is my problem: So I am using Cocos2d and one of the major problem is they don't have buttons. To compensate for there lack in buttons I am trying to detect if when a touch ended did it collide with a square (the button). Here is my code: - (void)ccTouchesEnded:(NSSet*)touches withEvent:(UIEvent*)event { UITouch *touch = [touches anyObject]; CGPoint location = [touch locationInView:touch.view]; NSLog(@"%f", 240-location.y); if (isReady == YES) { if (((240-location.y) <= (240-StartButton.position.x - 100) || -(240-location.y) >= (240-StartButton.position.x) + 100) && ((160-location.x) <= (160-StartButton.position.y) - 25 || (160-location.x) >= (160-StartButton.position.y) + 25)) { NSLog(@"Coll:%f", 240-StartButton.position.x); CCScene *scene = [PlayScene node]; [[CCDirector sharedDirector] replaceScene:[CCZoomFlipAngularTransition transitionWithDuration:2.0f scene:scene orientation:kOrientationRightOver]]; } } } Do you know what I am doing wrong?

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  • How can I do fast Triangle/Square vs Triangle collision detection?

    - by Ólafur Waage
    I have a game world where the objects are in a grid based environment with the following restrictions. All of the triangles are 45-90-45 triangles that are unit length. They can only rotate 90°. The squares are of unit length and can not rotate (not that it matters) I have the Square vs Square detection down and it is very very solid and very fast (max vs min on x and y values) Wondering if there are any tricks I can employ since I have these restrictions on the triangles?

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  • E3 2012 : Square Enix dévoile "Luminous Studio ", son nouveau moteur de rendu, avec une vidéo rappelant l'univers de Final Fantasy

    E3 2012 : Square Enix dévoile "Luminous Studio " son nouveau moteur de rendu Une première démonstration dans la lignée des Final Fantasy Il y a sept mois, Square Enix avait présenté un nouveau moteur à la presse japonaise. Ce moteur vise les consoles à venir (XBox 720 / PS4). Voici les images qui avaient été présentées : [IMG]http://jeux.developpez.com/news/images/Luminous_Studio_1_thumb.jpg[/IMG] [IMG]http://jeux.developpez.com/news/images/Luminous_Studio_2_thumb.jpg[/IMG] Le développe...

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  • Code Golf: MSM Random Number Generator

    - by Vivin Paliath
    The challenge The shortest code by character count that will generate (pseudo)random numbers using the Middle-Square Method. The Middle-Square Method of (pseudo)random number generation was first suggested by John Von Neumann in 1946 and is defined as follows: Rn+1 = mid((Rn)2, m) For example: 34562 = 11943936 mid(11943936) = 9439 94392 = 89094721 mid(89094721) = 0947 9472 = 896809 mid(896809) = 9680 96802 = 93702400 mid(93702400) = 7024 Test cases: A seed of 8653 should give the following numbers (first 10): 8744, 4575, 9306, 6016, 1922, 6940, 1636, 6764, 7516, 4902

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  • [Netbeans 6.9] Java MethodOverloading error with double values

    - by Nimitips
    Here is a part of my code I'm having trouble with: ===Class Overload=== public class Overload { public void testOverLoadeds() { System.out.printf("Square of integer 7 is %d\n",square(7)); System.out.printf("Square of double 7.5 is %d\n",square(7.5)); }//..end testOverloadeds public int square(int intValue) { System.out. printf("\nCalled square with int argument: %d\n",intValue); return intValue * intValue; }//..end square int public double square(double doubleValue) { System.out.printf("\nCalled square with double argument: %d\n", doubleValue); return doubleValue * doubleValue; }//..end square double }//..end class overload ===Main=== public static void main(String[] args) { Overload methodOverload = new Overload(); methodOverload.testOverLoadeds(); } It compiles with no error, however when I try to run it the output is: Called square with int argument: 7 Square of integer 7 is 49 Exception in thread "main" java.util.IllegalFormatConversionException: d != java.lang.Double at java.util.Formatter$FormatSpecifier.failConversion(Formatter.java:3999) at java.util.Formatter$FormatSpecifier.printInteger(Formatter.java:2709) at java.util.Formatter$FormatSpecifier.print(Formatter.java:2661) at java.util.Formatter.format(Formatter.java:2433) at java.io.PrintStream.format(PrintStream.java:920) at java.io.PrintStream.printf(PrintStream.java:821) at methodoverload.Overload.square(Overload.java:19) at methodoverload.Overload.testOverLoadeds(Overload.java:8) at methodoverload.Main.main(Main.java:9) Called square with double argument:Java Result: 1 What am I doing wrong? I'm on Ubuntu 10.10, Netbeans 6.9. Thanks.

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