Search Results

Search found 1329 results on 54 pages for 'square bracket'.

Page 6/54 | < Previous Page | 2 3 4 5 6 7 8 9 10 11 12 13  | Next Page >

  • Running python batch file that has a path with SPACE character

    - by prosseek
    The batch file is something like this, I put the python in some directory that has SPACE character in its path. C:\"Documents and Settings"\Administrator\Desktop\bracket\python\python C:\\"Documents and Settings"\\Administrator\\Desktop\\bracket\\[10,20]\\brackettest.py When I run this one, I get this error. C:\Documents and Settings\Administrator\Desktop\bracket\python\python: can't ope n file 'C:\Documents and Settings\\Administrator\\Desktop\\bracket\\[10,20]\\bra ckettest.py': [Errno 2] No such file or directory C:\Documents and Settings\Administrator\Desktop\bracket What might be wrong? Wrapping the path doesn't solve this problem. "C:\\Documents and Settings\\Administrator\\Desktop\\bracket\\[10,20]\\brackettest.py" Are the brackets ('[]') cause of the problem? On Mac, python works well with bracket character.

    Read the article

  • Is the Asus Lion Square compatible with an AMD Athlon II AM3?

    - by wag2639
    I bought an Asus Lion Square compatible with a AMD Athlon II X3 435 Socket AM3 processor? I know strictly speaking, the Lion Square specifies AM2 but I'm a little confused since AM2 and AM3 are suppose to be socket compatible (I'm a little confused here as well but I assume it means an AM3 board will support AM2/AM2+ CPUs). However, will there be a problem with chip height and spacing? Or do people have experience asking ASUS for a standoff adapter?

    Read the article

  • JustCode Q1 SP1 &ndash;Typing Assistance Improvements

    Our goal is to make JustCodes typing assistance save keystrokes, without getting in your way. As such, typing assistance received quite a few changes for SP1.  It now works faster, and better than ever :)      Bracket Completion When you add an  open bracket at the beginning of a line, JustCode will now add the closing bracket for you at the end of the line, even if there is code. When you hit enter, the auto formatter will run.    Prevents Bracket Doubling The SP1 release now does its best to prevent you from doubling parenthesis, braces, and brackets. Instead of doubling up these items up, it will move your cursor outside the closing item.   Auto Format on Semi-Colon, and Close Bracket JustCode now automatically runs the auto formatter when you press semi-colon, or add a closing bracket at the end of a line.    Auto Completion of Singe & ...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

    Read the article

  • Retrieving an element by array index in jQuery vs the each() function.

    - by Alex Ciminian
    I was writing a "pluginable" function when I noticed the following behavior (tested in FF 3.5.9 with Firebug 1.5.3). $.fn.computerMove = function () { var board = $(this); var emptySquares = board.find('div.clickable'); var randPosition = Math.floor(Math.random() * emptySquares.length); emptySquares.each(function (index) { if (index === randPosition) { // logs a jQuery object console.log($(this)); } }); target = emptySquares[randPosition]; // logs a non-jQuery object console.log(target); // throws error: attr() not a function for target board.placeMark({'position' : target.attr('id')}); } I noticed the problem when the script threw an error at target.attr('id') (attr not a function). When I checked the log, I noticed that the output (in Firebug) for target was: <div style="width: 97px; height: 97px;" class="square clickable" id="8"></div> If I output $(target), or $(this) from the each() function, I get a nice jQuery object: [ div#8.square ] Now here comes my question: why does this happen, considering that find() seems to return an array of jQuery objects? Why do I have to do $() to target all over again? [div#0.square, div#1.square, div#2.square, div#3.square, div#4.square, div#5.square, div#6.square, div#7.square, div#8.square] Just a curiosity :).

    Read the article

  • Making Visual C++ DLL from C++ class

    - by prosseek
    I have the following C++ code to make dll (Visual Studio 2010). class Shape { public: Shape() { nshapes++; } virtual ~Shape() { nshapes--; }; double x, y; void move(double dx, double dy); virtual double area(void) = 0; virtual double perimeter(void) = 0; static int nshapes; }; class __declspec(dllexport) Circle : public Shape { private: double radius; public: Circle(double r) : radius(r) { }; virtual double area(void); virtual double perimeter(void); }; class __declspec(dllexport) Square : public Shape { private: double width; public: Square(double w) : width(w) { }; virtual double area(void); virtual double perimeter(void); }; I have the __declspec, class __declspec(dllexport) Circle I could build a dll with the following command CL.exe /c example.cxx link.exe /OUT:"example.dll" /DLL example.obj When I tried to use the library, Square* square; square->area() I got the error messages. What's wrong or missing? example_unittest.obj : error LNK2001: unresolved external symbol "public: virtual double __thiscall ... Square::area(void)" (?area@Square@@UAENXZ) ADDED Following wengseng's answer, I modified the header file, and for DLL C++ code, I added #define XYZLIBRARY_EXPORT However, I still got errors. example_unittest.obj : error LNK2019: unresolved external symbol "__declspec(dllimport) public: __th iscall Circle::Circle(double)" (__imp_??0Circle@@QAE@N@Z) referenced in function "protected: virtual void __thiscall TestOne::SetUp(void)" (?SetUp@TestOne@@MAEXXZ) example_unittest.obj : error LNK2019: unresolved external symbol "__declspec(dllimport) public: __th iscall Square::Square(double)" (__imp_??0Square@@QAE@N@Z) referenced in function "protected: virtual void __thiscall TestOne::SetUp(void)" (?SetUp@TestOne@@MAEXXZ) example_unittest.obj : error LNK2001: unresolved external symbol "public: virtual double __thiscall Square::area(void)" (?area@Square@@UAENXZ) example_unittest.obj : error LNK2001: unresolved external symbol "public: virtual double __thiscall Square::perimeter(void)" (?perimeter@Square@@UAENXZ) example_unittest.obj : error LNK2001: unresolved external symbol "public: virtual double __thiscall Circle::area(void)" (?area@Circle@@UAENXZ) example_unittest.obj : error LNK2001: unresolved external symbol "public: virtual double __thiscall Circle::perimeter(void)" (?perimeter@Circle@@UAENXZ)

    Read the article

  • C++ beginner question regarding chars

    - by Samwhoo
    I'm just messing around with some C++ at the moment trying to make a simple tic-tac-toe game and I'm running into a bit of a problem. This is my code: #include <iostream> using namespace std; class Square { public: char getState() const; void setState(char); Square(); ~Square(); private: char * pState; }; class Board { public: Board(); ~Board(); void printBoard() const; Square getSquare(short x, short y) const; private: Square board[3][3]; }; int main() { Board board; board.getSquare(1,2).setState('1'); board.printBoard(); return 0; } Square::Square() { pState = new char; *pState = ' '; } Square::~Square() { delete pState; } char Square::getState() const { return *pState; } void Square::setState(char set) { *pState = set; } Board::~Board() { } Board::Board() { } void Board::printBoard() const { for (int x = 0; x < 3; x++) { cout << "|"; for (int y = 0; y < 3; y++) { cout << board[x][y].getState(); } cout << "|" << endl; } } Square Board::getSquare(short x, short y) const { return board[x][y]; } Forgive me if there are blatantly obvious problems with it or it's stupidly written, this is my first program in C++ :p However, the problem is that when I try and set the square 1,2 to the char '1', it doesn't print out as a 1, it prints out as some strange character I didn't recognise. Can anyone tell me why? :) Thanks in advance.

    Read the article

  • Parenting Opengl with Groups in LibGDX

    - by Rudy_TM
    I am trying to make an object child of a Group, but this object has a draw method that calls opengl to draw in the screen. Its class its this public class OpenGLSquare extends Actor { private static final ImmediateModeRenderer renderer = new ImmediateModeRenderer10(); private static Matrix4 matrix = null; private static Vector2 temp = new Vector2(); public static void setMatrix4(Matrix4 mat) { matrix = mat; } @Override public void draw(SpriteBatch batch, float arg1) { // TODO Auto-generated method stub renderer.begin(matrix, GL10.GL_TRIANGLES); renderer.color(color.r, color.g, color.b, color.a); renderer.vertex(x0, y0, 0f); renderer.color(color.r, color.g, color.b, color.a); renderer.vertex(x0, y1, 0f); renderer.color(color.r, color.g, color.b, color.a); renderer.vertex(x1, y1, 0f); renderer.color(color.r, color.g, color.b, color.a); renderer.vertex(x1, y1, 0f); renderer.color(color.r, color.g, color.b, color.a); renderer.vertex(x1, y0, 0f); renderer.color(color.r, color.g, color.b, color.a); renderer.vertex(x0, y0, 0f); renderer.end(); } } In my screen class I have this, i call it in the constructor MyGroupClass spriteLab = new MyGroupClass(spriteSheetLab); OpenGLSquare square = new OpenGLSquare(); square.setX0(100); square.setY0(200); square.setX1(400); square.setY1(280); square.color.set(Color.BLUE); square.setSize(); //spriteLab.addActorAt(0, clock); spriteLab.addActor(square); stage.addActor(spriteLab); And the render in the screen I have @Override public void render(float arg0) { this.gl.glClear(GL10.GL_COLOR_BUFFER_BIT |GL10.GL_DEPTH_BUFFER_BIT); stage.draw(); stage.act(Gdx.graphics.getDeltaTime()); } The problem its that when i use opengl with parent, it resets all the other chldren to position 0,0 and the opengl renderer paints the square in the exact position of the screen and not relative to the parent. I tried using batch.enableBlending() and batch.disableBlending() that fixes the position problem of the other children, but not the relative position of the opengl drawing and it also puts alpha to the glDrawing. What am i doing wrong?:/

    Read the article

  • GAME MAKER Problem with sprites! Can't see the sprite after mouse action

    - by user46882
    I have got a problem in Game Maker Pro: http://www.directupload.net/file/d/3646/egdpdu6u_gif.htm At the start we see a white square moving. If I press a key the square stop to move and the background changes to white. If the background changes to white a new animation/sprite should play on the same position where the white square was. BUT IT DOESNT! (Actually it is still there! It just does not move and this is fine) The animation is basically a sprite animation with some outlines of the square. If I press a key again, the background changes to white and we see the animation of the sprite.. but we do not see the animation of the sprites when it does not move. And this is strange!! I want to have the animation of the square when it doesn't move. But I don't get it.. by the way.. the .gif is a old version. I allready fixed the problem with the moving animation.. but I am still not able to play the animation if the square does not fly. The color of the animation is allready set to green or something! for better contrast. But still.. can't see it. Here is the code: obj.weisse.kugel.stepevent = the white square with the movements and sprite animations etc. if (global.kweiss == 1 ) { // vspeed = 8; //visible = true // sprite_index=spr_weisse_kugel; image_speed = 0; image_index = 0; } else if (global.kweiss == 0) { sprite_index=spr_animation_fade_out; image_speed =0.2; image_index=image_number-1 vspeed = 0; //visible = false // } then I have 1 create event for all the global.variables obj.global_var globalvar kweiss; kweiss = 1; globalvar kschwarz; kschwarz = 0; and then I have 1 controll stepevent in a new obj: if device_mouse_check_button_pressed (0, mb_left) { if background_color = c_black { background_color = c_white } else { background_color = c_black } // change of the square to white if (global.kweiss = 0) { global.kweiss = 1; } else { global.kweiss = 0; } if (global.kschwarz = 0) // change the square to black (other bullets.. we do not need this at the moment!) { global.kschwarz = 1; } else { global.kschwarz = 0; } Many thanks in advance

    Read the article

  • AS3 URLRequest in for Loop problem

    - by Adrian
    Hi guys, I read some data from a xml file, everything works great besides urls. I can't figure what's the problem with the "navigateURL" function or with the eventListener... on which square I click it opens the last url from the xml file for(var i:Number = 0; i <= gamesInput.game.length() -1; i++) { var square:square_mc = new square_mc(); //xml values var tGame_name:String = gamesInput.game.name.text()[i];//game name var tGame_id:Number = gamesInput.children()[i].attributes()[2].toXMLString();//game id var tGame_thumbnail:String = thumbPath + gamesInput.game.thumbnail.text()[i];//thumb path var tGame_url:String = gamesInput.game.url.text()[i];//game url addChild(square); square.tgname_txt.text = tGame_name; square.tgurl_txt.text = tGame_url; //load & attach game thumb var getThumb:URLRequest = new URLRequest(tGame_thumbnail); var loadThumb:Loader = new Loader(); loadThumb.load(getThumb); square.addChild(loadThumb); // square.y = squareY; square.x = squareX; squareX += square.width + 10; square.buttonMode = true; this.addEventListener(MouseEvent.CLICK, navigateURL); } function navigateURL(event:MouseEvent):void { var url:URLRequest = new URLRequest(tGame_url); navigateToURL(url, "_blank"); trace(tGame_url); } Many thanks!

    Read the article

  • C# iterator is executed twice when composing two IEnumerable methods

    - by achristoph
    I just started learning about C# iterator but got confused with the flow of the program after reading the output of the program. The foreach with uniqueVals seems to be executed twice. My understanding is that the first few lines up to the line before "Nums in Square: 3" should not be there. Can anyone help to explain why this happens? The output is: Unique: 1 Adding to uniqueVals: 1 Unique: 2 Adding to uniqueVals: 2 Unique: 2 Unique: 3 Adding to uniqueVals: 3 Nums in Square: 3 Unique: 1 Adding to uniqueVals: 1 Square: 1 Number returned from Unique: 1 Unique: 2 Adding to uniqueVals: 2 Square: 2 Number returned from Unique: 4 Unique: 2 Unique: 3 Adding to uniqueVals: 3 Square: 3 Number returned from Unique: 9 static class Program { public static IEnumerable<T> Unique<T>(IEnumerable<T> sequence) { Dictionary<T, T> uniqueVals = new Dictionary<T, T>(); foreach (T item in sequence) { Console.WriteLine("Unique: {0}", item); if (!uniqueVals.ContainsKey(item)) { Console.WriteLine("Adding to uniqueVals: {0}", item); uniqueVals.Add(item, item); yield return item; Console.WriteLine("After Unique yield: {0}", item); } } } public static IEnumerable<int> Square(IEnumerable<int> nums) { Console.WriteLine("Nums in Square: {0}", nums.Count()); foreach (int num in nums) { Console.WriteLine("Square: {0}", num); yield return num * num; Console.WriteLine("After Square yield: {0}", num); } } static void Main(string[] args) { var nums = new int[] { 1, 2, 2, 3 }; foreach (int num in Square(Unique(nums))) Console.WriteLine("Number returned from Unique: {0}", num); Console.Read(); } }

    Read the article

  • Running python batch file that has a path

    - by prosseek
    The batch file is something like this, I put the python in some directory that has SPACE character in its path. C:\"Documents and Settings"\Administrator\Desktop\bracket\python\python C:\\"Documents and Settings"\\Administrator\\Desktop\\bracket\\[10,20]\\brackettest.py When I run this one, I get this error. C:\Documents and Settings\Administrator\Desktop\bracket\python\python: can't ope n file 'C:\Documents and Settings\\Administrator\\Desktop\\bracket\\[10,20]\\bra ckettest.py': [Errno 2] No such file or directory C:\Documents and Settings\Administrator\Desktop\bracket What might be wrong? Wrapping the path doesn't solve this problem. "C:\\Documents and Settings\\Administrator\\Desktop\\bracket\\[10,20]\\brackettest.py"

    Read the article

  • How to make smooth movements in OpenGL?

    - by thyrgle
    So this kind of on topic to my other OpenGL question (not my OpenGL ES question but OpenGL the desktop version). If you have someone press a key to move a square how do you make the square movement naturally and less jumpy but also at the same speed I have it now? This is my code for the glutKeyboardFunc() function: void handleKeypress(unsigned char key, int x, int y) { if (key == 'w') { for (int i = 0; i < 12; i++) { if (i == 1 || i == 7 || i == 10 || i == 4) { square[i] = square[i] + 1; } } glutPostRedisplay(); } if (key == 'd') { for (int i = 0; i < 12; i++) { if (i == 0 || i % 3 == 0) { square[i] = square[i] + 1; } } glutPostRedisplay(); } if (key == 's') { for (int i = 0; i < 12; i++) { if (i == 1 || i == 7 || i == 10 || i == 4) { square[i] = square[i] - 1; } } glutPostRedisplay(); } if (key == 'a') { for (int i = 0; i < 12; i++) { if (i == 0 || i % 3 == 0) { square[i] = square[i] - 1; } } glutPostRedisplay(); } } I'm sorry if this doesn't quite make sense I'll try to rephrase it in a better way if it doesn't make sense.

    Read the article

  • How to draw an unfilled square on top of a stream video using a mouse and track the object enclosed

    - by Haxed
    Hi, I am making an object tracking application. I have used Emgucv 2.1.0.0 to load a video file to a picturebox. I have also taken the video stream from a web camera. Now, I want to draw an unfilled square on the video stream using a mouse and then track the object enclosed by the unfilled square as the video continues to stream. This is what people have suggested so far:- (1) .NET Video overlay drawing(DirectX) - but this is for C++ users, the suggester said that there are .NET wrappers, but I had a hard time finding any. (2) DxLogo sample DxLogo – A sample application showing how to superimpose a logo on a data stream. It uses a capture device for the video source, and outputs the result to a file. Sadly, this does not use a mouse. (3) GDI+ and mouse handling - this area I do not have a clue. And for tracking the object in the square, I would appreciate if someone give me some research paper links to read. Any help as to using the mouse to draw on a video is greatly appreciated. Thank you for taking the time to read this. Many Thanks

    Read the article

  • How do I overload the square-bracket operator in C#?

    - by Coderer
    DataGridView, for example, lets you do this: DataGridView dgv = ...; DataGridViewCell cell = dgv[1,5]; but for the life of me I can't find the documentation on the index/square-bracket operator. What do they call it? Where is it implemented? Can it throw? How can I do the same thing in my own classes? ETA: Thanks for all the quick answers. Briefly: the relevant documentation is under the "Item" property; the way to overload is by declaring a property like public object this[int x, int y]{ get{...}; set{...} }; the indexer for DataGridView does not throw, at least according to the documentation. It doesn't mention what happens if you supply invalid coordinates. ETA Again: OK, even though the documentation makes no mention of it (naughty Microsoft!), it turns out that the indexer for DataGridView will in fact throw an ArgumentOutOfRangeException if you supply it with invalid coordinates. Fair warning.

    Read the article

  • Define a positive number to be isolated if none of the digits in its square are in its cube [closed]

    - by proglaxmi
    Define a positive number to be isolated if none of the digits in its square are in its cube. For example 163 is n isolated number because 69*69 = 26569 and 69*69*69 = 4330747 and the square does not contain any of the digits 0, 3, 4 and 7 which are the digits used in the cube. On the other hand 162 is not an isolated number because 162*162=26244 and 162*162*162 = 4251528 and the digits 2 and 4 which appear in the square are also in the cube. Write a function named isIsolated that returns 1 if its argument is an isolated number, it returns 0 if its not an isolated number and it returns -1 if it cannot determine whether it is isolated or not (see the note below). The function signature is: int isIsolated(long n) Note that the type of the input parameter is long. The maximum positive number that can be represented as a long is 63 bits long. This allows us to test numbers up to 2,097,151 because the cube of 2,097,151 can be represented as a long. However, the cube of 2,097,152 requires more than 63 bits to represent it and hence cannot be computed without extra effort. Therefore, your function should test if n is larger than 2,097,151 and return -1 if it is. If n is less than 1 your function should also return -1. Hint: n % 10 is the rightmost digit of n, n = n/10 shifts the digits of n one place to the right. The first 10 isolated numbers are N n*n n*n*n 2 4 8 3 9 27 8 64 512 9 81 729 14 196 2744 24 576 13824 28 784 21952 34 1156 39304 58 3364 195112 63 3969 250047

    Read the article

  • Technical differences between square and hexagon for a grid?

    - by Marlon Dias
    I'm developing a 2D city-building game and trying to decide on the type of grid. There will be vehicles, so the unit movement is important too. I know there are visual differences for using Squares or Hexagons, what I want know is: What are the issues for programming each type of grid regarding implementation and performance? Is there a tradeoff or specific benefit for using one of them in a game context?

    Read the article

  • How can I create a square 10x10 grid using nested for loops in Java? [migrated]

    - by help
    I'm trying to create a 10x10 grid using for loops in Java. I'm able to create rows going up and down but not repeating. for(int i = 1; i < temperatures.length; i++) { temperatures[i] = (temperatures[i-1] + 12) / 2; //takes average of 12 and previous temp } } public void paint(Graphics g) { for(int y = 1; y < 9; y++) { g.setColor(Color.black); g.drawRect(10, 10, 10, 10); g.drawRect(10, 10, 10, 20); g.drawRect(10, 10, 10, 30); g.drawRect(10, 10, 10, 40); g.drawRect(10, 10, 10, 50); g.drawRect(10, 10, 10, 60); g.drawRect(10, 10, 10, 70); g.drawRect(10, 10, 10, 80); g.drawRect(10, 10, 10, 90); g.drawRect(10, 10, 10, 100); for(int x = 1; x < 9; x++) { g.setColor(Color.black); g.drawRect(10, 10, 10, 10); g.drawRect(10, 10, 20, 10); g.drawRect(10, 10, 30, 10); g.drawRect(10, 10, 40, 10); g.drawRect(10, 10, 50, 10); g.drawRect(10, 10, 60, 10); g.drawRect(10, 10, 70, 10); g.drawRect(10, 10, 80, 10); g.drawRect(10, 10, 90, 10); g.drawRect(10, 10, 100, 10); } } } }

    Read the article

  • Why are textures always square powers of two? What if they aren't?

    - by Keavon
    Why are the resolution of textures in games always a power of two (128x128, 256x256, 512x512, 1024x1024, etc.)? Wouldn't it be smart to save on the game's file size and make the texture exactly fit the UV unwrapped model? What would happen if there was a texture that was not a power of two? Would it be incorrect to have a texture be something like 256x512, or 512x1024? Or would this cause the problems that non-power-of-two textures may cause?

    Read the article

  • Why is my primitive xna square not drawn/shown?

    - by Mech0z
    I have made this class to draw a rectangle, but I cant get it to be drawn, I have no issues displaying a 3d model created in 3dmax, but shown these primitives seems much harder I use this to create it board = new Board(Vector3.Zero, 1000, 1000, Color.Yellow); And here is the implementation using System; using System.Net; using System.Windows; using System.Windows.Controls; using System.Windows.Documents; using System.Windows.Ink; using System.Windows.Input; using System.Windows.Shapes; using Quadro.Models; using Microsoft.Xna.Framework; using Microsoft.Xna.Framework.Graphics; namespace Quadro { public class Board : IGraphicObject { //Private Fields private Vector3 modelPosition; private BasicEffect effect; private VertexPositionColor[] vertices; private Matrix rotationMatrix; private GraphicsDevice graphicsDevice; private Matrix cameraProjection; //Constructor public Board(Vector3 position, float length, float width, Color color) { var _color = color; vertices = new VertexPositionColor[6]; vertices[0].Position = new Vector3(position.X, position.Y, position.Z); vertices[1].Position = new Vector3(position.X, position.Y + width, position.Z); vertices[2].Position = new Vector3(position.X + length, position.Y, position.Z); vertices[3].Position = new Vector3(position.X + length, position.Y, position.Z); vertices[4].Position = new Vector3(position.X, position.Y + width, position.Z); vertices[5].Position = new Vector3(position.X + length, position.Y + width, position.Z); for(int i = 0; i < vertices.Length; i++) { vertices[i].Color = color; } initFields(); } private void initFields() { graphicsDevice = SharedGraphicsDeviceManager.Current.GraphicsDevice; effect = new BasicEffect(graphicsDevice); modelPosition = Vector3.Zero; float screenWidth = (float)graphicsDevice.Viewport.Width; float screenHeight = (float)graphicsDevice.Viewport.Height; float aspectRatio = screenWidth / screenHeight; this.cameraProjection = Matrix.CreatePerspectiveFieldOfView(MathHelper.ToRadians(45.0f), aspectRatio, 1.0f, 10000.0f); this.rotationMatrix = Matrix.Identity; } //Public Methods public void Update(GameTimerEventArgs e) { } public void Draw(Vector3 cameraPosition, GameTimerEventArgs e) { Matrix cameraView = Matrix.CreateLookAt(cameraPosition, Vector3.Zero, Vector3.Up); foreach (EffectPass pass in effect.CurrentTechnique.Passes) { pass.Apply(); effect.World = rotationMatrix * Matrix.CreateTranslation(modelPosition); effect.View = cameraView; effect.Projection = cameraProjection; graphicsDevice.DrawUserPrimitives(PrimitiveType.TriangleList, vertices, 0, 2, VertexPositionColor.VertexDeclaration); } } public void Rotate(Matrix rotationMatrix) { this.rotationMatrix = rotationMatrix; } public void Move(Vector3 moveVector) { this.modelPosition += moveVector; } } }

    Read the article

  • Basic Java drawing program: issue with squares

    - by Caminek
    I'm trying to create a simple drawing program that creates a square where the user clicks and drags. The square displays correctly as long as either x or y remain positive with respect to the original click position. If both x and y are negative with respect to the original click position, the square grows/shrinks, but also wanders about the screen. Is there a way to swap the origin point from top-left to bottom-right or to keep the square from wandering?

    Read the article

  • SQL UNION ALL with a INNER JOIN

    - by kOhm
    I'm looking for the best way to display all rows from two tables while joining first by one field (dwg) then where applicable a 2nd join on part. Table1 data consists of schematics(dwg) along with a list of parts required to build the item depicted in the drawing. Table2 consists of data about the actual parts ordered to build the schematic. Some parts in table2 are a combination of parts in table1 (ex: foo and bar in table1 were ordered as foobar in table2). I can display all rows in both tables with UNION ALL, but this doesn't join on both the dwg and part fields. I looked at FULL OUTER JOIN also, but I haven't figured out how to join first by dwg, then by part. Here is an example of the data. table1 table2 dwg part qty order dwg part qty ----- ----- ----- ----- ----- ----- ----- 123 foo 1 ord1 123 foobar 1 123 bar 1 ord1 123 bracket 2 123 widget 2 ord2 123 screw 4 123 bracket 4 ord2 123 nut 4 456 foo 1 ord2 123 widget 2 ord2 123 bracket 2 ord3 456 foo 1 Desired output: The goal is to create a view that provides visibility to all parts in table1 and the associated orders in table2 (including those parts that appear in one but not the other table) so that I can see all the drawing parts in table1 and the associated records in table2 along with records in table2 where the part wasn't in table1. part_request_order_report dwg part qty order part qty ----- ----- ----- ------ ----- ----- 123 foo 1 123 bar 1 123 widget 2 ord2 widget 2 123 bracket 4 ord1 bracket 2 123 bracket 4 ord2 bracket 2 123 ord1 foobar 1 123 ord1 screw 4 123 ord1 nut 4 456 foo 1 ord3 foo 1 Is this possible? Or am I better off iterating through the data to build the report table? Thanks in advance.

    Read the article

  • What's my best approach on this simple hierarchy Java Problem?

    - by Nazgulled
    First, I'm sorry for the question title but I can't think of a better one to describe my problem. Feel free to change it :) Let's say I have this abstract class Box which implements a couple of constructors, methods and whatever on some private variables. Then I have a couple of sub classes like BoxA and BoxB. Both of these implement extra things. Now I have another abstract class Shape and a few sub classes like Square and Circle. For both BoxA and BoxB I need to have a list of Shape objects but I need to make sure that only Square objects go into BoxA's list and only Circle objects go into BoxB's list. For that list (on each box), I need to have a get() and set() method and also a addShape() and removeShape() methods. Another important thing to know is that for each box created, either BoxA or BoxB, each respectively Shape list is exactly the same. Let's say I create a list of Square's named ls and two BoxA objects named boxA1 and boxA2. No matter what, both boxA1 and boxA2 must have the same ls list. This is my idea: public abstract class Box { // private instance variables public Box() { // constructor stuff } // public instance methods } public class BoxA extends Box { // private instance variables private static List<Shape> list; public BoxA() { // constructor stuff } // public instance methods public static List<Square> getList() { List<Square> aux = new ArrayList<Square>(); for(Square s : list.values()) { aux.add(s.clone()); // I know what I'm doing with this clone, don't worry about it } return aux; } public static void setList(List<Square> newList) { list = new ArrayList<Square>(newList); } public static void addShape(Square s) { list.add(s); } public static void removeShape(Square s) { list.remove(list.indexOf(s)); } } As the list needs to be the same for that type of object, I declared as static and all methods that work with that list are also static. Now, for BoxB the class would be almost the same regarding the list stuff. I would only replace Square by Triangle and the problem was solved. So, for each BoxA object created, the list would be only one and the same for each BoxB object created, but a different type of list of course. So, what's my problem you ask? Well, I don't like the code... The getList(), setList(), addShape() and removeShape() methods are basically repeated for BoxA and BoxB, only the type of the objects that the list will hold is different. I can't think of way to do it in the super class Box instead. Doing it statically too, using Shape instead of Square and Triangle, wouldn't work because the list would be only one and I need it to be only one but for each sub class of Box. How could I do this differently and better? P.S: I could not describe my real example because I don't know the correct words in English for the stuff I'm doing, so I just used a box and shapes example, but it's basically the same.

    Read the article

  • bottom uicomponent does not receive mouse events

    - by firemonkey
    HI, I am sure this is very basic, however I am not able to find the solution. I have a base ShapeContainer(UIComponent). I add a uicomponent which has mouse down listener to ShapeContainer. the listener works great. When I add a simple sprite(draw square) on the ShapeContainer, The listener does not work any more. In the code, if I comment below lines, The event listener works fine. var square:Sprite = new Sprite(); square.graphics.lineStyle(4,0x00FF00); square.graphics.drawRect(0,0,20,20); square.mouseEnabled=false; shapeContainer.addChildAt(square,1); I have tried few things like, mouseenabled=false on top sprite. also tried to add addChildAt but non of them did any help. How can I draw a shape and also have the event listener work. enter code here protected function application1_creationCompleteHandler(event:FlexEvent):void { var shapeContainer:UIComponent = new UIComponent(); shapeContainer.x=100; shapeContainer.y=100; shapeContainer.width=200; shapeContainer.height=200; rawChildren.addChild(shapeContainer); var EventListenerShape:UIComponent = new UIComponent(); EventListenerShape.x=100; EventListenerShape.y=100; EventListenerShape.width=200;a EventListenerShape.height=200; EventListenerShape.graphics.clear(); EventListenerShape.graphics.beginFill(0xf1f1f1, 0.1); EventListenerShape.graphics.drawRoundRect(0, 0, 200, 200, 10, 10); EventListenerShape.alpha = 0; EventListenerShape.graphics.endFill(); EventListenerShape.addEventListener(MouseEvent.MOUSE_DOWN, mouseDownfunc); shapeContainer.addChild(EventListenerShape); var square:Sprite = new Sprite(); square.graphics.lineStyle(4,0x00FF00); square.graphics.drawRect(0,0,20,20); square.mouseEnabled=false; shapeContainer.addChildAt(square,1); } private function mouseDownfunc(e:MouseEvent){ trace("mouse Down **"); }    ]]> </mx:Script> <mx:Canvas id="uic" width="100%" height="100%" backgroundColor="0xFFFFFF"> </mx:Canvas>

    Read the article

  • Codeigniter Image Library Cropping an Image with 2 sets of coordinates to make square anywhere?

    - by chris
    Spending time reading through the docs, and searching for examples. I understand cropping an image from top 0, and left 0 is pretty straight forward. However. I would like to pass 2 sets of coordinates, a starting point and an ending point. Four Points, a Square that is defined anywhere. However from the examples I am finding, and from what I gather the rendition is not going to let me do this. codeigniter so I am seeking confirmation on this thought, is it true that I can only provide end points from 0, and it crops a square based on said end points or can I actually specify an x start, an x end, and similar for y? Or is there some other technique I can use within codeigniter that will allow me to pass for coordinates for starting and ending points?

    Read the article

< Previous Page | 2 3 4 5 6 7 8 9 10 11 12 13  | Next Page >