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  • Heroku Push Problem part 2 - Postgresql - PGError Relations does not exist - Ruby on Rails

    - by bgadoci
    Ok so got through my last problem with the difference between Postgresql and SQLite and seems like Heroku is telling me I have another one. I am new to ruby and rails so a lot of this stuff I can't decipher at first. Looking for a little direction here. The error message and PostsController Index are below. I checked my routes.rb file and all seems well there but I could be missing something. I will post if you need. Processing PostsController#index (for 99.7.50.140 at 2010-04-23 15:19:22) [GET] ActiveRecord::StatementInvalid (PGError: ERROR: relation "tags" does not exist : SELECT a.attname, format_type(a.atttypid, a.atttypmod), d.adsrc, a.attnotnull FROM pg_attribute a LEFT JOIN pg_attrdef d ON a.attrelid = d.adrelid AND a.attnum = d.adnum WHERE a.attrelid = '"tags"'::regclass AND a.attnum > 0 AND NOT a.attisdropped ORDER BY a.attnum ): PostsController#index def index @tag_counts = Tag.count(:group => :tag_name, :order => 'count_all DESC', :limit => 20) conditions, joins = {}, :votes @ugtag_counts = Ugtag.count(:group => :ugctag_name, :order => 'count_all DESC', :limit => 20) conditions, joins = {}, :votes @vote_counts = Vote.count(:group => :post_title, :order => 'count_all DESC', :limit => 20) conditions, joins = {}, :votes unless(params[:tag_name] || "").empty? conditions = ["tags.tag_name = ? ", params[:tag_name]] joins = [:tags, :votes] end @posts=Post.paginate( :select => "posts.*, count(*) as vote_total", :joins => joins, :conditions=> conditions, :group => "votes.post_id, posts.id ", :order => "created_at DESC", :page => params[:page], :per_page => 5) @popular_posts=Post.paginate( :select => "posts.*, count(*) as vote_total", :joins => joins, :conditions=> conditions, :group => "votes.post_id, posts.id", :order => "vote_total DESC", :page => params[:page], :per_page => 3) respond_to do |format| format.html # index.html.erb format.xml { render :xml => @posts } format.json { render :json => @posts } format.atom end end

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  • PHP & MySQL Pagination

    - by Francesc
    Hi. I have a MySQL query SELECT * FROM 'redirect' WHERE 'user_id'= \''.$_SESSION['user_id'].' \' ORDER BY 'timestamp'` I want to paginate 10 results per page. How Can I do it?

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  • Ordering columns in Rails, cakephp style.

    - by Smickie
    CakePHP's built in pagination helpers automatically allow column ordering in the view. If you bake the view you get a link on each column to order it by that data. Is there a way to get this functionality in Rails? The standard will paginate doesn't offer it, anyone know any good ones?

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  • Django microblog showing a logged in user only his posts

    - by dana
    i have a miniblog application, with a class named New(refering to a new post), having a foreign key to an user(who has posted the entry). above i have a method that displays all the posts from all the users. I'd like to show to the logged in user, only his posts How can i do it? Thanks in advance! def paginate(request): paginator = New.objects.all() return render_to_response('news/newform.html', { 'object_list': paginator, }, context_instance=RequestContext(request))

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  • Adding custom query to paginator (KNP Paginator) in Symfony2?

    - by Unni
    I have the following query , how to write these query in Symfony2 SELECT Inventory_Stock.id, Inventory_Stock.quantity, SUM(InventoryUsage.quantity) ,Inventory_Stock.quantity - SUM(InventoryUsage.quantity) AS Stock FROM Inventory_Stock LEFT JOIN InventoryUsage ON Inventory_Stock.id = InventoryUsage.InventoryStock_id WHERE Inventory_Stock.id = 26 OR Inventory_Stock.id = 27 GROUP BY Inventory_Stock.id ORDER BY Stock DESC I need to paginate this as well Would be great if any one could help me out as this has been pulling my hair out for couple of days.

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  • grails portlet pagination on Liferay

    - by srinath
    Hi , How to implement pagination in grails portlet on Liferay. The basic pagination was not working on Liferay. When clicked on next the page is jumping from Liferay url to normal url I used like this : <g:paginate next="Forward" prev="Back" maxsteps="10" controller="book" action="list" total="${Book.count()}" /> thanks in advance.

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  • unknown action with will_paginate

    - by merlin
    In my users controller I have this in a method: @users = User.paginate :page => params[:page], :per_page => 10, The results are rendered on users/search. The 2nd page link points to users/search?page=2, but it leads to an unknown action error.

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  • Wordpress custom query pagination

    - by Uffo
    I have a wordpress site, where on the main page I list the content from more categories. My question is, is there a plugin where I can paginate the results from a category?I mean something like $this-plugin_paginate('category_id'); or smth? Best Regards,

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  • ruby on rails ferret search:.only 10 records are getting from table

    - by jissy
    ruby on rails ferret search:.only 10 records are getting from table.For pagination i did it ,but only 10 records are getting even though there exists more records satisfying the search condition.if any of you know how to solve this,please reply. no limit is givenf it is not a ferret search all records are getting from table , and pagination is working the code is: @search_sd_ticket_result=ServiceDeskTicket.find_with_ferret(params[:sd_ticket][:servicedeskticket]).paginate :per_page =5, :page=params[:page]

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  • PHP Filesystem Pagination

    - by Byron
    How does one paginate a large listing of files within a folder? I can't see any functions in the PHP documentation that mention any way to specify an 'offset'. Both glob() and scandir() simply return all the files in the folder, and I'm afraid that won't be a good idea for a huge directory. Is there any better way of doing this than simply going through all the files and chopping off the first X number of files?

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  • Complex query with two tables and multilpe data and price ranges

    - by TiuTalk
    Let's suppose that I have these tables: [ properties ] id (INT, PK) name (VARCHAR) [ properties_prices ] id (INT, PK) property_id (INT, FK) date_begin (DATE) date_end (DATE) price_per_day (DECIMAL) price_per_week (DECIMAL) price_per_month (DECIMAL) And my visitor runs a search like: List the first 10 (pagination) properties where the price per day (price_per_day field) is between 10 and 100 on the period for 1st may until 31 december I know thats a huge query, and I need to paginate the results, so I must do all the calculation and login in only one query... that's why i'm here! :)

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  • First record does not show in pagination script

    - by whitstone86
    This is my pagination script which extracts info for my TV guide project that I am working on. Currently I've been experimenting with different PHP/MySQL before it becomes a production site. This is my current script: <?php /*********************************** * PhpMyCoder Paginator * * Created By PhpMyCoder * * 2010 PhpMyCoder * * ------------------------------- * * You may use this code as long * * as this notice stays intact and * * the proper credit is given to * * the author. * ***********************************/ // set the default timezone to use. Available since PHP 5.1 putenv("TZ=US/Eastern") ?> <head> <title> Pagination Test - Created By PhpMyCoder</title> <style type="text/css"> #nav { font: normal 13px/14px Arial, Helvetica, sans-serif; margin: 2px 0; } #nav a { background: #EEE; border: 1px solid #DDD; color: #000080; padding: 1px 7px; text-decoration: none; } #nav strong { background: #000080; border: 1px solid #DDD; color: #FFF; font-weight: normal; padding: 1px 7px; } #nav span { background: #FFF; border: 1px solid #DDD; color: #999; padding: 1px 7px; } </style> </head> <?php //Require the file that contains the required classes include("pmcPagination.php"); //PhpMyCoder Paginator $paginator = new pmcPagination(20, "page"); //Connect to the database mysql_connect("localhost","root","PASSWORD"); //Select DB mysql_select_db("mytvguide"); //Select only results for today and future $result = mysql_query("SELECT programme, channel, airdate, expiration, episode, setreminder FROM lagunabeach where expiration >= now() order by airdate, 3 ASC LIMIT 0, 100;"); //You can also add reuslts to paginate here mysql_data_seek($queryresult,0) ; while($row = mysql_fetch_array($result)) { $paginator->add(new paginationData($row['programme'], $row['channel'], $row['airdate'], $row['expiration'], $row['episode'], $row['setreminder'])); } ?> <?php //Show the paginated results $paginator->paginate (); ?><? include("pca-footer1.php"); ?> <?php //Show the navigation $paginator->navigation(); ?> Despite me having two records for the programmes airing today, it only shows records from the second one onwards - the programme that airs at 8:35pm UK time GMT does not show, but the later 11:25pm UK time GMT one does show. How should I fix this? Above is my code if that is of any use! Thanks

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  • show array size with will_paginate

    - by chief
    @users = User.paginate( :page => params[:page], :per_page => 2, I would like to return the total number of results. @users.size simply gives me the number of results on a page. If page 1 has 2 users @users.size = 2, going to page 2 with say 1 user @users.size = 1. How can I show the size of all the users?

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  • Working with nested models in ROR

    - by user487429
    Hi there, I'm trying to create an application where users can freely create shops and associated shop item for a specific shop is displayed when a show action is called but I seem to be doing something wrong. Any help here will be appreciated. I have attached shots of my code below. class ShopItem < ActiveRecord::Base belongs_to :shop def self.find_shop_items_for_sale find(:all, :order => "title", :conditions => ["shop_id = ?", @shop.id]) end end class Shop < ActiveRecord::Base has_many :shop_items end #Controllers class ShopsController < ApplicationController def new @shop = Shop.new end def create @shop = Shop.new(params[:shop]) @shop.user_id = current_user.id respond_to do |format| if @shop.save flash[:notice] = "Successfully created shop." format.html {redirect_to(all_shops_shops_url)} format.xml {render :xml => @shop, :status => :created, :location => @shop } else format.html {render :action => 'new'} format.xml { render :xml => @shop.errors, :status => :unprocessable_entity } end end end def show @shop = Shop.find(params[:id]) @shop_items = ShopItem.find_shop_items_for_sale @shop_cart = find_shop_cart end class ShopItemsController < ApplicationController def user @per_page ||= 5 @user = User.find(params[:id]) @shop_items = ShopItem.find(:all, :conditions=>["user_id = ?", @user.id], :order=>"id desc") end def show @shop_item = ShopItem.find(params[:id]) @shop = @shop_item.shop respond_to do |format| format.html # show.html.erb format.xml { render :xml => @shop_item } end end # GET /shop_items/new # GET /shop_items/new.xml def new @shop_item = ShopItem.new @shop = Shop.find(params[:id]) #@shop_items = ShopItem.paginate(:all, :condition=>["shop_id] = ?", @shop.id], :order=> "id desc", :page => params[:page],:per_page => @per_page) @shop_items = ShopItem.find(:all, :conditions=>["shop_id = ?", @shop.id], :order=> "id desc") @shop_item.shop_id = params[:id] respond_to do |format| format.html # new.html.erb format.xml { render :xml => @shop_item } end end # GET /shop_items/1/edit def edit @shop_item = ShopItem.find(params[:id]) end # POST /shop_items # POST /shop_items.xml def create @shop_item = ShopItem.new(params[:shop_item]) @shop_item.user_id = current_user.id respond_to do |format| if @shop_item.save flash[:notice] = 'Shop item was successfully created.' format.html { redirect_to(@shop_item) } format.xml { render :xml => @shop_item, :status => :created, :location => @shop_item } else @shop = Shop.find(@shop_item.shop_id) #@shop_items = ShopItem.paginate(:all, :condition =>["shop_id = ?", @shop.id], :order=> "id desc" , :page => params[:page], :per_page => @per_page) @shop_items = ShopItem.find(:all, :conditions =>["shop_id = ?", @shop.id], :order=> "id desc") format.html { render :action => "new" } format.xml { render :xml => @shop_item.errors, :status => :unprocessable_entity } end end end

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  • Pagination of Date-Based Generic Views in Django

    - by Apreche
    I have a pretty simple question. I want to make some date-based generic views on a Django site, but I also want to paginate them. According to the documentation the object_list view has page and paginate_by arguments, but the archive_month view does not. What's the "right" way to do it?

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  • Joining the same model twice in a clean way, but making the code reusable

    - by Shako
    I have a model Painting which has a Paintingtitle in each language and a Paintingdescription in each language: class Painting < ActiveRecord::Base has_many :paintingtitles, :dependent => :destroy has_many :paintingdescriptions, :dependent => :destroy end class Paintingtitle < ActiveRecord::Base belongs_to :painting belongs_to :language end class Paintingdescription < ActiveRecord::Base belongs_to :painting belongs_to :language end class Language < ActiveRecord::Base has_many :paintingtitles, :dependent => :nullify has_many :paintingdescriptions, :dependent => :nullify has_many :paintings, :through => :paintingtitles end As you might notice, I reference the Language model from my Painting model via both the Paintingtitle model and Paintingdescription model. This works for me when getting a list of paintings with their title and description in a specific language: cond = {"paintingdescription_languages.code" => language_code, "paintingtitle_languages.code" => language_code} cond['paintings.publish'] = 1 unless admin paginate( :all, :select => ["paintings.id, paintings.publish, paintings.photo_file_name, paintingtitles.title, paintingdescriptions.description"], :joins => " INNER JOIN paintingdescriptions ON (paintings.id = paintingdescriptions.painting_id) INNER JOIN paintingtitles ON (paintings.id = paintingtitles.painting_id) INNER JOIN languages paintingdescription_languages ON (paintingdescription_languages.id = paintingdescriptions.language_id) INNER JOIN languages paintingtitle_languages ON (paintingtitle_languages.id = paintingtitles.language_id) ", :conditions => cond, :page => page, :per_page => APP_CONFIG['per_page'], :order => "id DESC" ) Now I wonder if this is a correct way of doing this. I need to fetch paintings with their title and description in different functions, but I don't want to specify this long join statement each time. Is there a cleaner way, for instance making use of the has_many through? e.g. has_many :paintingdescription_languages, :through => :paintingdescriptions, :source => :language has_many :paintingtitle_languages, :through => :paintingtitles, :source => :language But if I implement above 2 lines together with the following ones, then only paintingtitles are filtered by language, and not the paintingdescriptions: cond = {"languages.code" => language_code} cond['paintings.publish'] = 1 unless admin paginate( :all, :select => ["paintings.id, paintings.publish, paintings.photo_file_name, paintingtitles.title, paintingdescriptions.description"], :joins => [:paintingdescription_languages, :paintingtitle_languages], :conditions => cond, :page => page, :per_page => APP_CONFIG['per_page'], :order => "id DESC" )

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  • check_box_tag and find condition

    - by red
    <%= check_box_tag('videos_count')%> If this box is checked, the param will say "videos_count"="1" . In the controller I have this: videos_count = params[:videos_count] @cars = Car.paginate( :page => params[:page], :per_page => 10, :conditions => ["videos_count = ?", videos_count], when the box is checked I see the correct parameter in the server log, but the find returns all of the results instead of results with videos_count = 1.

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  • Excel Single column into rows, VBA script insight

    - by Sanityvoid
    Okay, so much similiar to the below link but mine is a bit different. Paginate Rows into Columns in Excel I have a lot of data in column A, I want to take every 14 to 15 rows and make them a new row with multiple columns. I'm trying to get it into a format where SQL can intake the data. I figured the best way was to get them into rows then make a CSV with the data. So it would like like below: (wow, the format totally didn't stick when posting) column A column B C D etc 1 1 2 3 x 2 16 17 a b 3 x y z 15 16 17 a b c I can clarify if needed, but I'm stumped on how to get the data out of the single column with so many rows in the column. Thanks for the help!!!

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  • License Requirements for Including Dual-Licensed Open-Source Software

    - by Rick Roth
    How do you opt into one software license and not the other when the distributor gives the consumer more than one choice? For example I would like to use the DataTables JavaScript library in my web application. According to their web site, "DataTables is dual licensed under the GPL v2 license or a BSD (3-point) license." Furthermore, the source code of the JavaScript library has this text that calls out both licenses: /** * @summary DataTables * @description Paginate, search and sort HTML tables * @version 1.9.4 * @file jquery.dataTables.js * @author Allan Jardine (www.sprymedia.co.uk) * @contact www.sprymedia.co.uk/contact * * @copyright Copyright 2008-2012 Allan Jardine, all rights reserved. * * This source file is free software, under either the GPL v2 license or a * BSD style license, available at: * http://datatables.net/license_gpl2 * http://datatables.net/license_bsd * * This source file is distributed in the hope that it will be useful, but * WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY * or FITNESS FOR A PARTICULAR PURPOSE. See the license files for details. * * For details please refer to: http://www.datatables.net */ Finally, the web pages with the licensing text (e.g. the DataTables BSD license page) has this statement: "DataTables is made available under both the GPL v2 license and a BSD (3-point) style license. You can select which one you wish to use the DataTables code under." My specific question is "how do you select which one you want to use." In my case, I want to only use the BSD license and I want to make it explicitly clear that I do not opt into the GPL v2 license in any way. How do you do that and have it hold up to legal challenge?

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  • Installing Paperclip - "undefined method `has_attached_file` for" - Ruby on Rails

    - by bgadoci
    I just installed the plugin for Paperclip and I am getting an error message "undefined method has_attached_file for. Not sure why I am getting this. Here is the full error message. NoMethodError (undefined method `has_attached_file' for #<Class:0x10338acd0>): /Users/bgadoci/.gem/ruby/1.8/gems/will_paginate-2.3.12/lib/will_paginate/finder.rb:170:in `method_missing' app/models/post.rb:2 app/controllers/posts_controller.rb:50:in `show' For some reason it is referencing the will_paginate gem. From what I can find, it seems that either there is something wrong w/ my PostsController#index or perhaps a previously attempt at installing the gem instead of the plugin (in which case I have read I should be able to remedy through the /config/environments.rb file somehow). I didn't think that previous gem installation would matter as I did it in an old version of the site that I trashed before installing the plugin. In the current version of the site I show that the Table has been updated with the Paperclip columns after migration. Here is my code: PostsController#index def index @tag_counts = Tag.count(:group => :tag_name, :order => 'count_all DESC', :limit => 20) conditions, joins = {}, :votes @vote_counts = Vote.count(:group => :post_title, :order => 'count_all DESC', :limit => 20) conditions, joins = {}, :votes unless(params[:tag_name] || "").empty? conditions = ["tags.tag_name = ? ", params[:tag_name]] joins = [:tags, :votes] end @posts=Post.paginate( :select => "posts.*, count(*) as vote_total", :joins => joins, :conditions=> conditions, :group => "votes.post_id", :order => "created_at DESC", :page => params[:page], :per_page => 5) @popular_posts=Post.paginate( :select => "posts.*, count(*) as vote_total", :joins => joins, :conditions=> conditions, :group => "votes.post_id", :order => "vote_total DESC", :page => params[:page], :per_page => 3) respond_to do |format| format.html # index.html.erb format.xml { render :xml => @posts } format.json { render :json => @posts } format.atom end end Post Model class Post < ActiveRecord::Base has_attached_file :photo validates_presence_of :body, :title has_many :comments, :dependent => :destroy has_many :tags, :dependent => :destroy has_many :votes, :dependent => :destroy belongs_to :user after_create :self_vote def self_vote # I am assuming you have a user_id field in `posts` and `votes` table. self.votes.create(:user => self.user) end cattr_reader :per_page @@per_page = 10 end /views/posts/new.html.erb <h1>New post</h1> <%= link_to 'Back', posts_path %> <% form_for(@post, :html => { :multipart => true}) do |f| %> <%= f.error_messages %> <p> <%= f.label :title %><br /> <%= f.text_field :title %> </p> <p> <%= f.label :body %><br /> <%= f.text_area :body %> </p> <p> <%= f.file_field :photo %> </p> <p> <%= f.submit 'Create' %> </p> <% end %>

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  • Foreign keys and pagination

    - by whitstone86
    This is my pagination script: <?php /*********************************** * PhpMyCoder Paginator * * Created By PhpMyCoder * * 2010 PhpMyCoder * * ------------------------------- * * You may use this code as long * * as this notice stays intact and * * the proper credit is given to * * the author. * ***********************************/ ?> <head> <title> Pagination Test - Created By PhpMyCoder</title> <style type="text/css"> #nav { font: normal 13px/14px Arial, Helvetica, sans-serif; margin: 2px 0; } #nav a { background: #EEE; border: 1px solid #DDD; color: #000080; padding: 1px 7px; text-decoration: none; } #nav strong { background: #000080; border: 1px solid #DDD; color: #FFF; font-weight: normal; padding: 1px 7px; } #nav span { background: #FFF; border: 1px solid #DDD; color: #999; padding: 1px 7px; } </style> </head> <?php //Require the file that contains the required classes include("pmcPagination.php"); //PhpMyCoder Paginator $paginator = new pmcPagination(20, "page"); //Connect to the database mysql_connect("localhost","root","PASSWORD"); //Select DB mysql_select_db("tvguide"); //Select only results for today and future $result = mysql_query("SELECT programme, channel, airdate, expiration, episode, setreminder FROM epdata1 where airdate >= now() order by expiration GROUP BY airdate"); //You can also add reuslts to paginate here mysql_data_seek($queryresult,0) ; while($row = mysql_fetch_array($result)) { $paginator->add(new paginationData($row['programme'], $row['channel'], $row['airdate'], $row['expiration'], $row['episode'], $row['setreminder'])); } ?> <?php //Show the paginated results $paginator->paginate (); ?><? include("pca-footer1.php"); ?> <?php //Show the navigation $paginator->navigation(); ?> However, I have two tables in this, and they are epdata1 (where the airtimes for my show House M.D. are) and housemdep plus the setreminder table. How can I use foreign keys in relation to this? I'm not sure if this will work for my script, but am willing to try. What I would like to do is to select certain episodes from the table housemdep (episodes of the show) and if any are selected it shows them as this: House M.D. showing on Channel 1 June 6th - 8:00pm "Wilson" Set Reminder House M.D. showing on Channel 1 June 7th - 1:30am "Wilson" Set Reminder House M.D. showing on Channel 1 June 7th - 12:55pm "House's Head" Set Reminder or like this, if I have not selected an episode from the row: House M.D. showing on Channel 1 June 7th - 8:00pm "House's Head" Set Reminder House M.D. showing on Channel 1 June 8th - 9:00pm Set Reminder House M.D. showing on Channel 1 June 9th - 2:30pm Set Reminder House M.D. showing on Channel 1 June 7th - 8:00pm "Que Sera Sera" Set Reminder Foreign keys and relationship of interlinked tables are new to me, if anyone could help I'd appreciate this. I've tried some of what Google suggested on foreign keys in another version of this script (this is a clone of the original on my localhost server running Apache and PHP 5.28/MySQL), but am not sure how to implement this. Thanks.

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  • How to make sql query dynamic?

    - by ClarkSKent
    Hello, I am using this pagination class and was looking for a way to make the sql query more dynamic instead of having it hardcoded. I have a 3 <li> elements that I want to be filter buttons, meaning when a user clicks on one of these elements I want It to send the id so I can use it in a sql query. So for the $sql = "select * from explore where category='marketing'"; (as seen below). When the user clicks on the 'automotive' button it will change the category above to automotive. Any help on this would be highly appreciated, Thanks. This is what my main page looks like: <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript" src="jquery_page.js"></script> <?php //Include the PS_Pagination class include('ps_pagination.php'); //Connect to mysql db $conn = mysql_connect('localhost', 'root', 'root'); mysql_select_db('ajax_demo',$conn); $sql = "select * from explore where category='marketing'"; //Create a PS_Pagination object $pager = new PS_Pagination($conn, $sql, 3, 11, 'param1=valu1&param2=value2'); //The paginate() function returns a mysql //result set for the current page $rs = $pager->paginate(); //Loop through the result set while($row = mysql_fetch_assoc($rs)) { echo "<table width='800px'>"; echo "<tr>"; echo"<td>"; echo $row['id']; echo"</td>"; echo"<td>"; echo $row['site_description']; echo"</td>"; echo"<td>"; echo $row['site_price']; echo"</td>"; echo "</tr>"; echo "</table>"; } echo "<ul id='pagination'>"; echo "<li>"; //Display the navigation echo $pager->renderFullNav(); echo "</li>"; echo "</ul>"; echo "<ul id='filter'>"; echo "<li id='marketing'>"; echo "Marketing"; echo "</li>"; echo "<li id='automotive'>"; echo "Automotive"; echo "</li>"; echo "<li id='sports'>"; echo "Sports"; echo "</li>"; echo "</ul>"; ?>

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  • OutOfMemoryError during the pdf merge

    - by Vijay
    the below code merges the pdf files and returns the combined pdf data. while this code runs, i try to combine the 100 files with each file approximately around 500kb, i get outofmemory error in the line document.close();. this code runs in the web environment, is the memory available to webspehere server is the problem? i read in an article to use freeReader method, but i cannot get how to use it my scenario. protected ByteArrayOutputStream joinPDFs(List<InputStream> pdfStreams, boolean paginate) { Document document = new Document(); ByteArrayOutputStream mergedPdfStream = new ByteArrayOutputStream(); try { //List<InputStream> pdfs = pdfStreams; List<PdfReader> readers = new ArrayList<PdfReader>(); int totalPages = 0; //Iterator<InputStream> iteratorPDFs = pdfs.iterator(); Iterator<InputStream> iteratorPDFs = pdfStreams.iterator(); // Create Readers for the pdfs. while (iteratorPDFs.hasNext()) { InputStream pdf = iteratorPDFs.next(); if (pdf == null) continue; PdfReader pdfReader = new PdfReader(pdf); readers.add(pdfReader); totalPages += pdfReader.getNumberOfPages(); } //clear this pdfStreams = null; //WeakReference ref = new WeakReference(pdfs); //ref.clear(); // Create a writer for the outputstream PdfWriter writer = PdfWriter.getInstance(document, mergedPdfStream); writer.setFullCompression(); document.open(); BaseFont bf = BaseFont.createFont(BaseFont.HELVETICA, BaseFont.CP1252, BaseFont.NOT_EMBEDDED); PdfContentByte cb = writer.getDirectContent(); // Holds the PDF // data PdfImportedPage page; int currentPageNumber = 0; int pageOfCurrentReaderPDF = 0; Iterator<PdfReader> iteratorPDFReader = readers.iterator(); // Loop through the PDF files and add to the output. while (iteratorPDFReader.hasNext()) { PdfReader pdfReader = iteratorPDFReader.next(); // Create a new page in the target for each source page. while (pageOfCurrentReaderPDF < pdfReader.getNumberOfPages()) { pageOfCurrentReaderPDF++; document.setPageSize(pdfReader .getPageSizeWithRotation(pageOfCurrentReaderPDF)); document.newPage(); // pageOfCurrentReaderPDF++; currentPageNumber++; page = writer.getImportedPage(pdfReader, pageOfCurrentReaderPDF); cb.addTemplate(page, 0, 0); // Code for pagination. if (paginate) { cb.beginText(); cb.setFontAndSize(bf, 9); cb.showTextAligned(PdfContentByte.ALIGN_CENTER, "" + currentPageNumber + " of " + totalPages, 520, 5, 0); cb.endText(); } } pageOfCurrentReaderPDF = 0; System.out.println("now the size is: "+pdfReader.getFileLength()); } mergedPdfStream.flush(); document.close(); mergedPdfStream.close(); return mergedPdfStream; } catch (Exception e) { e.printStackTrace(); } finally { if (document.isOpen()) document.close(); try { if (mergedPdfStream != null) mergedPdfStream.close(); } catch (IOException ioe) { ioe.printStackTrace(); } } return mergedPdfStream; } Thanks V

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  • Converting PHP pagination to jQuery?

    - by ClarkSKent
    Hey, I have been trying to get this pagination class that I am using to be more ajaxy - meaning when I click on the page number like page [2] the data loads, but I want to load in the data without going to a different page (HTTP request in the background, with no page reloads). Being new to both php and jquery, I am a little unsure on how to achieve this result, especially while using a php class. This is what the main page looks like by the way: <?php $categoryId=$_GET['category']; echo $categoryId; ?> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript" src="jquery_page.js"></script> <?php //Include the PS_Pagination class include('ps_pagination.php'); //Connect to mysql db $conn = mysql_connect('localhost', 'root', 'root'); mysql_select_db('ajax_demo',$conn); $sql = "select * from explore where category='$categoryId'"; //Create a PS_Pagination object $pager = new PS_Pagination($conn, $sql, 3, 11, 'param1=value1&param2=value2'); //The paginate() function returns a mysql //result set for the current page $rs = $pager->paginate(); //Loop through the result set echo "<table width='800px'>"; while($row = mysql_fetch_assoc($rs)) { echo "<tr>"; echo"<td>"; echo $row['id']; echo"</td>"; echo"<td>"; echo $row['site_description']; echo"</td>"; echo"<td>"; echo $row['site_price']; echo"</td>"; echo "</tr>"; } echo "</table>"; echo "<ul id='pagination'>"; echo "<li>"; //Display the navigation echo $pager->renderFullNav(); echo "</li>"; echo "</ul>"; ?> <div id="loading" ></div> <div id="content" ></div> Would I need to do something with this part of the class?, as seen above: $pager = new PS_Pagination($conn, $sql, 3, 11, 'param1=value1&param2=value2'); Or this?: echo $pager->renderFullNav(); I don't no much about jquery,but i guess I would start it like: $("#pagination li").click(function() { Then load something maybe... I don't no. Any help on this would be great. Thanks.

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  • How to Load In Content with jQuery?

    - by ClarkSKent
    Hello, I am trying to add ajax functionality to my pagination so the content loads in the same page instead of the user having to navigate to another page when clicking the page links. I should mention that I am using this php pagination class. Being new to jquery, I am unsure of how to properly do this with the pagination class. This is what the main page looks like: <?php $categoryId=$_GET['category']; echo $categoryId; ?> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript" src="jquery_page.js"></script> <?php //Include the PS_Pagination class include('ps_pagination.php'); //Connect to mysql db $conn = mysql_connect('localhost', 'root', 'root'); mysql_select_db('ajax_demo',$conn); $sql = "select * from explore where category='$categoryId'"; //Create a PS_Pagination object $pager = new PS_Pagination($conn, $sql, 3, 11, 'param1=value1&param2=value2'); //The paginate() function returns a mysql //result set for the current page $rs = $pager->paginate(); //Loop through the result set echo "<table width='800px'>"; while($row = mysql_fetch_assoc($rs)) { echo "<tr>"; echo"<td>"; echo $row['id']; echo"</td>"; echo"<td>"; echo $row['site_description']; echo"</td>"; echo"<td>"; echo $row['site_price']; echo"</td>"; echo "</tr>"; } echo "</table>"; echo "<ul id='pagination'>"; echo "<li>"; //Display the navigation echo $pager->renderFullNav(); echo "</li>"; echo "</ul>"; ?> <div id="loading" ></div> <div id="content" ></div> <a href="#" class="category" id="marketing">Marketing</a> <a href="#" class="category" id="automotive">Automotive</a> <a href="#" class="category" id="sports">Sports</a> Any help on this would be great. Thanks.

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