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  • Can I serialize a BitArray to XML?

    - by SimonNet
    Hello I have a business class which I need to serialize to xml. It has a BitArray property. I have decorated it with [XmlAttribute] but the serialization is failing with To be XML serializable, types which inherit from ICollection must have an implementation of Add(System.Boolean) at all levels of their inheritance hierarchy. System.Collections.BitArray does not implement Add(System.Boolean). I am not sure whether its possible to serialize to xml? If not what would be an efficient means of serializing the BitArray Thanks for looking

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  • XML deserialization doubling up on entities

    - by Nathan Loding
    I have an XML file that I am attempting to deserialize into it's respective objects. It works great on most of these objects, except for one item that is being doubled up on. Here's the relevant portion of the XML: <Clients> <Client Name="My Company" SiteID="1" GUID="xxx-xxx-xxx-xxx"> <Reports> <Report Name="First Report" Path="/Custom/FirstReport"> <Generate>true</Generate> </Report> </Reports> </Client> </Clients> "Clients" is a List<Client> object. Each Client object has a List<Report> object within it. The issue is that when this XML is deserialized, the List<Report> object has a count of 2 -- the "First Report" Report object is in there twice. Why? Here's the C#: public class Client { [System.Xml.Serialization.XmlArray("Reports"), System.Xml.Serialization.XmlArrayItem(typeof(Report))] public List<Report> Reports; } public class Report { [System.Xml.Serialization.XmlAttribute("Name")] public string Name; public bool Generate; [System.Xml.Serialization.XmlAttribute("Path")] public string Path; } class Program { static void Main(string[] args) { List<Client> _clients = new List<Client>(); string xmlFile = "myxmlfile.xml"; System.Xml.Serialization.XmlSerializer xmlSerializer = new System.Xml.Serialization.XmlSerializer(typeof(List<Client>), new System.Xml.Serialization.XmlRootAttribute("Clients")); using (FileStream stream = new FileStream(xmlFile, FileMode.Open)) { _clients = xmlSerializer.Deserialize(stream) as List<Client>; } foreach(Client _client in _clients) { Console.WriteLine("Count: " + _client.Reports.Count); // This write "2" foreach(Report _report in _client.Reports) { Console.WriteLine("Name: " + _report.Name); // Writes "First Report" twice } } } }

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  • Parsing xml files locally from assets folder using XmlPullParser

    - by Randolphg
    Im trying to parse a local xml file that I place in my assets folder. I've been trying to do this for almost a week now. Here is my test xml file Test1 Test2 Test3 Test4 Test5 I keep getting the same error: W/System.err(22458): org.xmlpull.v1.XmlPullParserException: unexpected type (position:TEXT Code: public void xmlParser() throws XmlPullParserException, IOException, ParserConfigurationException, SAXException { Log.d("tag", "xmlParsing...."); Arithmetic arthm = new Arithmetic(); XmlPullParserFactory xmlPF = XmlPullParserFactory.newInstance(); xmlPF.setValidating(false); XmlPullParser xml = xmlPF.newPullParser(); InputStream raw = getApplication().getAssets().open("menu.xml"); xml.setInput(raw, null); xml.nextTag(); Log.d("tag", "start parsing...."); String elementText = null; String elemName = null; int nofTags = 0; while (xml.getEventType() != XmlPullParser.END_DOCUMENT) { Log.d("tag", "while(xml.next)..."); switch (xml.getEventType()) { case XmlPullParser.START_DOCUMENT: Log.d("tag", "while (xml.getEventType() != XmlPullParser.END_DOCUMENT)"); break; case XmlPullParser.START_TAG: Log.d("tag", " case XmlPullParser.START_TAG"); elementText = xml.getName(); Log.d("tag", "elementText = " + elementText); if (xml.getEventType() != XmlPullParser.END_TAG) { xml.nextTag(); } break; case XmlPullParser.TEXT: Log.d("tag", "case TEXT"); if (elementText.equals("menu") && xml.isWhitespace()) { Log.d("tag", "<" + elementText + ">"); arthm.menu_name = xml.getText(); Log.d("tag", "value " + xml.getText() + " added"); } else if (elementText.equals("item")) { arthm.description = xml.getText(); Log.d("tag", "value " + xml.getText() + " added"); } else if (elementText.equals("SUBCATEGORY NAME")) { arthm.subcategoryDesc.add(xml.getText()); Log.d("tag", "value " + xml.getText() + " added"); } else if (elementText.equals("SUBCATEGORY DESC")) { arthm.subcategoryName.add(xml.getText()); Log.d("tag", "value " + xml.getText() + " added"); } break; case XmlPullParser.END_TAG: Log.d("tag", "case END_TAG"); nofTags += 1; String tags = Integer.toString(nofTags); Log.d("tags", elementText + " number of tags" + tags); if (xml.nextTag() != XmlPullParser.START_TAG) { xml.next(); } break; case XmlPullParser.END_DOCUMENT: Log.d("tag", "case END_DOCUMENT"); break; default: break; } } Log.d("tag", "Success!"); } Thanks in advance.

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  • create xml from object

    - by Gannesh
    Basically i want to create XMLDesigner kind of thing in Flex, using which user can add/edit components and properties of view/dashboard. i am storing view structure in a xml file. i parsed that file at runtime and display view. How to convert an object (having properties and sub-objects) to xml node (having attributes and elements) and add that xml to the existing xml file. so that next time when i parsed xml file i'll get that new component in my view/dashboard. for e.g, object structure of component in xml file : <view id="productView" label="Products"> <panel id="chartPanel" type="CHART" ChartType="Pie2D" title="Productwise Sales" x="215" y="80" width="425" height="240" showValues="0" > </panel> </view> Thanks in Advance.

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  • XmlAttribute/XmlText cannot be used to encode complex type

    - by Conrad C
    I want to serialize a class Ticket into xml. I get the error :"XmlAttribute/XmlText cannot be used to encode complex type" because of my customfield class. This is how the xml for customfields should look like ( the attribute array is nesseray but I don't understand how to create it): <custom_fields type="array"> <custom_field name="Standby Reason" id="6"> <value/> </custom_field> <custom_field name="Close Date" id="84"> Class Ticket public class Ticket { [XmlElement("custom_fields")] public CustomFields Custom_fields { get; set; } Class CustomFields [Serializable] public class CustomFields { [XmlAttribute("array")] public List<CustomField> custom_field { get; set; } Class CustomField [Serializable] public class CustomField { [XmlIgnore] public string Name { get; set; } [XmlElement] public int Id { get; set; } [XmlElement] public string Value { get; set; }

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  • Default entries on a first time creation for a serialized class

    - by MGSoto
    I have a class I am using for serializing various configuration options for an application I am working on. I'm adding a new property to the class that is a List, and I'd like it to fill this list if it does not exist already in a XML file. My first thought was to check if the list contained zero items, however this is not acceptable because there are times I want to have zero items in the list. In essence I want a file that has been serialized with an older version of the same class to be "upgraded" and have defaults automatically inserted for new properties. How can I do this? For a more visual example of what I'm trying to do, see below: When I deserialize an XML file that contains: <Item1>wtfe</Item1> <Item2>wtfe</Item2> and after I've added a list property it will serialze as: <Item1>wtfe</Item1> <Item2>wtfe</Item2> <Item3/> I want it to serialize as: <Item1>wtfe</Item1> <Item2>wtfe</Item2> <Item3> <DefaultSubItem/ Field="wtfe"> <DefaultSubItem/ Field="wtfe"> </Item3> But allow me to change it to: <Item1>wtfe</Item1> <Item2>wtfe</Item2> <Item3></Item3>

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  • Can we replace XML with JSON entirely?

    - by Saeed Neamati
    I'm sure lots of developers are familiar with XML and JSON, and they've used both of them. Thus no point in explaining what they are, and what is their purpose, even in brief. If we try to map their concepts, we can say (correct me if I'm wrong): XML tags are equivalent to JSON {} XML attributes are equivalent to JSON properties XML tag collection is equivalent to JSON [] The only thing I can think of, which doesn't exist in JSON, is XML Namespaces. The question is, considering this mapping, and considering that JSON is highly lighter in this mapping, can we see a world in future (or at least theoretically think of a world) without XML, but with JSON doing everything XML does? Can we use JSON everywhere XML is used? PS: Please note that I've seen this question. It's something entirely different from what I'm asking here. Thus please don't mention duplicate.

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  • Loading a new instance of a class through XML not working quite right

    - by Thegluestickman
    I'm having trouble with XML and XNA. I want to be able to load weapon settings through XML to make my weapons easier to make and to have less code in the actual project file. So I started out making a basic XML document, something to just assign variables with. But no matter what I changed it gave me a new error every time. The code below gives me a "XML element 'Tag' not found", I added and it started to say the variables weren't found. What I wanted to do in the XML file as well, was load a texture for the file too. So I created a static class to hold my texture values, then in the Texture tag of my XML document I would set it to that instance too. I think that's were the problems are occuring because that's where the "XML element 'Tag' not found" error is pointing me too. My XML document: <XnaContent> <Asset Type="ConversationEngine.Weapon"> <weaponStrength>0</weaponStrength> <damageModifiers>0</damageModifiers> <speed>0</speed> <magicDefense>0</magicDefense> <description>0</description> <identifier>0</identifier> <weaponTexture>LoadWeaponTextures.ironSword</weaponTexture> </Asset> </XnaContent> My Class to load the weapon XML: public static class LoadWeaponXML { static Weapon Weapons; public static Weapon WeaponLoad(ContentManager content, int id) { Weapons = content.Load<Weapon>(@"Weapons/" + id); return Weapons; } } public static class LoadWeaponTextures { public static Texture2D ironSword; public static void TextureLoad(ContentManager content) { ironSword = content.Load<Texture2D>("Sword"); } } I'm not entirely sure if you can load textures through XML, but any help would be greatly appreciated.

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  • Receive the Broadcast program with XML [on hold]

    - by bitmez4
    I have a channel publishing sites and I wanna get into the channel CNN broadcast program.. CNN broadcast the program here: (you can see in source - xml File) http://tvprofil.net/xmltv/data/cnn.info/weekly_cnn.info_tvprofil.net.xml How the data according to the time of withdrawal? For example: Now program: "bitmez's table" next program: "stack's table" in 30 minute Is this possible? UPDATE 1 // -I can take the XML data but to all of XML file- <?php if(!$xml=simplexml_load_file('http://tvprofil.net/xmltv/data/cnn.info/weekly_cnn.info_tvprofil.net.xml')){ trigger_error('XML file -- read error',E_USER_ERROR); } echo 'X-'; foreach($xml as $programme){ echo 'Now: '.$programme->title.' <br/>'; } ?>

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  • Unit Testing XML independent of physical XML file

    - by RAbraham
    Hi, My question is: In JUnit, How do I setup xml data for my System Under Test(SUT) without making the SUT read from an XML file physically stored on the file system Background: I am given a XML file which contains rules for creation of an invoice. My job is to convert these rules from XMl to Java Objects e.g. If there is a tag as below in my XML file which indicates that after a period of 30 days, the transaction cannot be invoiced <ExpirationDay>30</ExpirationDay> this converts to a Java class , say ExpirationDateInvoicingRule I have a class InvoiceConfiguration which should take the XML file and create the *InvoicingRule objects. I am thinking of using StAX to parse the XML document within InvoiceConfiguration Problem: I want to unit test InvoiceConfiguration. But I dont want InvoiceConfiguration to read from an xml file physically on the file system . I want my unit test to be independent of any physical stored xml file. I want to create a xml representation in memory. But a StAX parser only takes FileReader( or I can play with the File Object)

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  • How to deserialize MXML with PHP?

    - by Ivan Petrushev
    Hello, I have an array structure that have to be converted to MXML. I know of PEAR XML_Serialize extension but it seems the output format it produces is a bit different. PHP generated XML: <zone columns="3"> <select column="1" /> <select column="4" /> </zone> MXML format: <mx:zone columns="3"> <mx:select column="1" /> <mx:select column="4" /> </mx:zone> Is that "mx:" prefix required for all the tags? If yes, can I make the XML_Serialize put it before each tag (without renaming my data structure fields to "mx:something")? Here are my options for XML_Serialize: $aOptions = array('addDecl' => true, 'indent' => " ", 'rootName' => 'template', 'scalarAsAttributes' => true, 'mode' => 'simplexml');

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  • Read XML Files using LINQ to XML and Extension Methods

    - by psheriff
    In previous blog posts I have discussed how to use XML files to store data in your applications. I showed you how to read those XML files from your project and get XML from a WCF service. One of the problems with reading XML files is when elements or attributes are missing. If you try to read that missing data, then a null value is returned. This can cause a problem if you are trying to load that data into an object and a null is read. This blog post will show you how to create extension methods to detect null values and return valid values to load into your object. The XML Data An XML data file called Product.xml is located in the \Xml folder of the Silverlight sample project for this blog post. This XML file contains several rows of product data that will be used in each of the samples for this post. Each row has 4 attributes; namely ProductId, ProductName, IntroductionDate and Price. <Products>  <Product ProductId="1"           ProductName="Haystack Code Generator for .NET"           IntroductionDate="07/01/2010"  Price="799" />  <Product ProductId="2"           ProductName="ASP.Net Jumpstart Samples"           IntroductionDate="05/24/2005"  Price="0" />  ...  ...</Products> The Product Class Just as you create an Entity class to map each column in a table to a property in a class, you should do the same for an XML file too. In this case you will create a Product class with properties for each of the attributes in each element of product data. The following code listing shows the Product class. public class Product : CommonBase{  public const string XmlFile = @"Xml/Product.xml";   private string _ProductName;  private int _ProductId;  private DateTime _IntroductionDate;  private decimal _Price;   public string ProductName  {    get { return _ProductName; }    set {      if (_ProductName != value) {        _ProductName = value;        RaisePropertyChanged("ProductName");      }    }  }   public int ProductId  {    get { return _ProductId; }    set {      if (_ProductId != value) {        _ProductId = value;        RaisePropertyChanged("ProductId");      }    }  }   public DateTime IntroductionDate  {    get { return _IntroductionDate; }    set {      if (_IntroductionDate != value) {        _IntroductionDate = value;        RaisePropertyChanged("IntroductionDate");      }    }  }   public decimal Price  {    get { return _Price; }    set {      if (_Price != value) {        _Price = value;        RaisePropertyChanged("Price");      }    }  }} NOTE: The CommonBase class that the Product class inherits from simply implements the INotifyPropertyChanged event in order to inform your XAML UI of any property changes. You can see this class in the sample you download for this blog post. Reading Data When using LINQ to XML you call the Load method of the XElement class to load the XML file. Once the XML file has been loaded, you write a LINQ query to iterate over the “Product” Descendants in the XML file. The “select” portion of the LINQ query creates a new Product object for each row in the XML file. You retrieve each attribute by passing each attribute name to the Attribute() method and retrieving the data from the “Value” property. The Value property will return a null if there is no data, or will return the string value of the attribute. The Convert class is used to convert the value retrieved into the appropriate data type required by the Product class. private void LoadProducts(){  XElement xElem = null;   try  {    xElem = XElement.Load(Product.XmlFile);     // The following will NOT work if you have missing attributes    var products =         from elem in xElem.Descendants("Product")        orderby elem.Attribute("ProductName").Value        select new Product        {          ProductId = Convert.ToInt32(            elem.Attribute("ProductId").Value),          ProductName = Convert.ToString(            elem.Attribute("ProductName").Value),          IntroductionDate = Convert.ToDateTime(            elem.Attribute("IntroductionDate").Value),          Price = Convert.ToDecimal(elem.Attribute("Price").Value)        };     lstData.DataContext = products;  }  catch (Exception ex)  {    MessageBox.Show(ex.Message);  }} This is where the problem comes in. If you have any missing attributes in any of the rows in the XML file, or if the data in the ProductId or IntroductionDate is not of the appropriate type, then this code will fail! The reason? There is no built-in check to ensure that the correct type of data is contained in the XML file. This is where extension methods can come in real handy. Using Extension Methods Instead of using the Convert class to perform type conversions as you just saw, create a set of extension methods attached to the XAttribute class. These extension methods will perform null-checking and ensure that a valid value is passed back instead of an exception being thrown if there is invalid data in your XML file. private void LoadProducts(){  var xElem = XElement.Load(Product.XmlFile);   var products =       from elem in xElem.Descendants("Product")      orderby elem.Attribute("ProductName").Value      select new Product      {        ProductId = elem.Attribute("ProductId").GetAsInteger(),        ProductName = elem.Attribute("ProductName").GetAsString(),        IntroductionDate =            elem.Attribute("IntroductionDate").GetAsDateTime(),        Price = elem.Attribute("Price").GetAsDecimal()      };   lstData.DataContext = products;} Writing Extension Methods To create an extension method you will create a class with any name you like. In the code listing below is a class named XmlExtensionMethods. This listing just shows a couple of the available methods such as GetAsString and GetAsInteger. These methods are just like any other method you would write except when you pass in the parameter you prefix the type with the keyword “this”. This lets the compiler know that it should add this method to the class specified in the parameter. public static class XmlExtensionMethods{  public static string GetAsString(this XAttribute attr)  {    string ret = string.Empty;     if (attr != null && !string.IsNullOrEmpty(attr.Value))    {      ret = attr.Value;    }     return ret;  }   public static int GetAsInteger(this XAttribute attr)  {    int ret = 0;    int value = 0;     if (attr != null && !string.IsNullOrEmpty(attr.Value))    {      if(int.TryParse(attr.Value, out value))        ret = value;    }     return ret;  }   ...  ...} Each of the methods in the XmlExtensionMethods class should inspect the XAttribute to ensure it is not null and that the value in the attribute is not null. If the value is null, then a default value will be returned such as an empty string or a 0 for a numeric value. Summary Extension methods are a great way to simplify your code and provide protection to ensure problems do not occur when reading data. You will probably want to create more extension methods to handle XElement objects as well for when you use element-based XML. Feel free to extend these extension methods to accept a parameter which would be the default value if a null value is detected, or any other parameters you wish. NOTE: You can download the complete sample code at my website. http://www.pdsa.com/downloads. Choose “Tips & Tricks”, then "Read XML Files using LINQ to XML and Extension Methods" from the drop-down. Good Luck with your Coding,Paul D. Sheriff  

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  • Iterate through deserialized xml object

    - by Bruce Adams
    I have a deserialized xml c# objet. I need to iterate through the oject to display all items, in this case there's just one, and display the name, colors and sizes for each item. The xml: <?xml version="1.0" encoding="utf-8"?> <Catalog Name="Example"> <Items> <Item Name="ExampleItem"> <Colors> <Color Name="Black" Value="#000" /> <Color Name="White" Value="#FFF" /> </Colors> <Sizes> <Size Name="Small" Value="10" /> <Size Name="Medium" Value="20" /> </Sizes> </Item> </Items> </Catalog> xsd.exe generated classes: //------------------------------------------------------------------------------ // <auto-generated> // This code was generated by a tool. // Runtime Version:2.0.50727.4927 // // Changes to this file may cause incorrect behavior and will be lost if // the code is regenerated. // </auto-generated> //------------------------------------------------------------------------------ using System.Xml.Serialization; // // This source code was auto-generated by xsd, Version=2.0.50727.42. // /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.42")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] [System.Xml.Serialization.XmlRootAttribute(Namespace="", IsNullable=false)] public partial class Catalog { private CatalogItemsItem[][] itemsField; private string nameField; /// <remarks/> [System.Xml.Serialization.XmlArrayAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] [System.Xml.Serialization.XmlArrayItemAttribute("Item", typeof(CatalogItemsItem[]), Form=System.Xml.Schema.XmlSchemaForm.Unqualified, IsNullable=false)] public CatalogItemsItem[][] Items { get { return this.itemsField; } set { this.itemsField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Name { get { return this.nameField; } set { this.nameField = value; } } } /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.42")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] public partial class CatalogItemsItem { private CatalogItemsItemColorsColor[][] colorsField; private CatalogItemsItemSizesSize[][] sizesField; private string nameField; /// <remarks/> [System.Xml.Serialization.XmlArrayAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] [System.Xml.Serialization.XmlArrayItemAttribute("Color", typeof(CatalogItemsItemColorsColor[]), Form=System.Xml.Schema.XmlSchemaForm.Unqualified, IsNullable=false)] public CatalogItemsItemColorsColor[][] Colors { get { return this.colorsField; } set { this.colorsField = value; } } /// <remarks/> [System.Xml.Serialization.XmlArrayAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] [System.Xml.Serialization.XmlArrayItemAttribute("Size", typeof(CatalogItemsItemSizesSize[]), Form=System.Xml.Schema.XmlSchemaForm.Unqualified, IsNullable=false)] public CatalogItemsItemSizesSize[][] Sizes { get { return this.sizesField; } set { this.sizesField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Name { get { return this.nameField; } set { this.nameField = value; } } } /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.42")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] public partial class CatalogItemsItemColorsColor { private string nameField; private string valueField; /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Name { get { return this.nameField; } set { this.nameField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Value { get { return this.valueField; } set { this.valueField = value; } } } /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.42")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] public partial class CatalogItemsItemSizesSize { private string nameField; private string valueField; /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Name { get { return this.nameField; } set { this.nameField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute()] public string Value { get { return this.valueField; } set { this.valueField = value; } } } /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.42")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] [System.Xml.Serialization.XmlRootAttribute(Namespace="", IsNullable=false)] public partial class NewDataSet { private Catalog[] itemsField; /// <remarks/> [System.Xml.Serialization.XmlElementAttribute("Catalog")] public Catalog[] Items { get { return this.itemsField; } set { this.itemsField = value; } } } Deserialization code: System.Xml.Serialization.XmlSerializer xSerializer = new System.Xml.Serialization.XmlSerializer(typeof(Catalog)); TextReader reader = new StreamReader("catalog.xml"); Catalog catalog = (Catalog)xSerializer.Deserialize(reader); foreach (var item in catalog.Items) { } reader.Close(); When I setp through the code there is one item present in catalog.items, but it is empty, no name, colors or sizes. Any ideas what I need to do? Thanks

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  • JBoss AS: use .xml files in the properties-service.xml

    - by fgysin
    The properties service (configured in properties-service.xml) in JBoss application server lets you specify external .properties files that are loaded and can then be accessed as system properties from the deployed applications. (See here http://community.jboss.org/wiki/PropertiesService for more info...) Is it also possible to load config files in the .xml format instead of .properties? I know it is possible for certain given configs like for example the mail-service.xml and the jboss-log4j.xml... But they are both loaded directly by JBoss, and not via the properties service.

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  • InvalidOperationException When XML Serializing Inherited Class

    - by Nick
    I am having an issue serializing a c# class to an XML file that has a base class... here is a simple example: namespace Domain { [Serializable] public class ClassA { public virtual int MyProperty { get; set; } } } namespace Derived { public class ClassA : Domain.ClassA { public override int MyProperty { get { return 1; } set { /* Do Nothing */ } } } } When I attempt to serialize an instance of Derived.ClassA, I receive the following exception: InvalidOperationException(Types 'Domain.ClassA' and 'Derived.ClassA' both use the XML type name 'ClassA', from the namespace ". Use XML attributes to specify a unique XML name and/or namespace for the type.) The problem is that I want to create a single base class that simply defines the structure of the XML file, and then allow anyone else to derive from that class to insert business rules, but that the formatting will come through from the base. Is this possible, and if so, how do I attribute the base class to allow this?

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  • Deserializing JSON in WCF throws xml errors in .Net 4.0

    - by Syg
    Hi there. I'm going slidely mad over here, maybe someone else can figure out what's going on here. I have a WCF service exposing a function using webinvoke, like so: [OperationContract] [WebInvoke(Method = "POST", BodyStyle = WebMessageBodyStyle.Wrapped, RequestFormat = WebMessageFormat.Json, ResponseFormat = WebMessageFormat.Json, UriTemplate = "registertokenpost" )] void RegisterDeviceTokenForYoumiePost(test token); The datacontract for the test class looks like this: [DataContract(Namespace="Zooma.Test", Name="test", IsReference=true)] public class test { string waarde; [DataMember(Name="waarde", Order=0)] public string Waarde { get { return waarde; } set { waarde = value; } } } When sending the following json message to the service, { "test": { "waarde": "bla" } } the trace log gives me errors (below). I have tried this with just a string instead of the datatype (void RegisterDeviceTokenForYoumiePost(string token); ) but i get the same error. All help is appreciated, can't figure it out. It looks like it's creating invalid xml from the json message, but i'm not doing any custom serialization here. The formatter threw an exception while trying to deserialize the message: Error in deserializing body of request message for operation 'RegisterDeviceTokenForYoumiePost'. Unexpected end of file. **Following elements are not closed**: waarde, test, root.</Message><StackTrace> at System.ServiceModel.Dispatcher.OperationFormatter.DeserializeRequest(Message message, Object[] parameters)

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  • JBOSS Security: web.xml vs. jboss-web.xml

    - by sixtyfootersdude
    What is the relation between web.xml and jboss-web.xml? Seems like: Jboss-web.xml specifies the security domain (which can be found in login-config.xml) web.xml specifies what the security level is I don't understand what happens when jboss-web.xml specifies a weak security domain. Ie: one that cannot do what web.xml specifies. What happens then?

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  • Getting ActiveRecord (Rails) to_xml to use xsi:nil and xsi:type instead of nil and type

    - by nbeyer
    The default behavior of XML serialization (to_xml) for ActiveRecord objects will emit 'type' and 'nil' attributes that are similar to XML Schema Instance attributes, but aren't set in a XML Namespace. For example, a model might produce an output like this: <user> <username nil="true" /> <first-name type="string">Name</first-name> </user> Is there anyway to get to_xml to utilize the XML Schema Instance namespace and prefix the attributes and the values? Using the above example, I'd like to produce the following: <user xmlns:xsi="http://www.w3.org/1999/XMLSchema-instance" xmlns:xs="http://www.w3.org/1999/XMLSchema"> <username xsi:nil="true" /> <first-name xsi:type="xs:string">Name</first-name> </user>

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  • Is xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" a special case in XML?

    - by Bytecode Ninja
    When we use a namespace, we should also indicate where its associated XSD is located at, as can be seen in the following example: <?xml version="1.0"?> <Artist BirthYear="1958" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.webucator.com/Artist" xsi:schemaLocation="http://www.webucator.com/Artist Artist.xsd"> <Name> <Title>Mr.</Title> <FirstName>Michael</FirstName> <LastName>Jackson</LastName> </Name> </Artist> Here, we have indicated that Artist.xsd should be used for validating the http://www.webucator.com/Artist namespace. However, we are also using the http://www.w3.org/2001/XMLSchema-instance namespace, but we have not specified where its XSD is located at. How do XML parsers know how to handle this namespace? Thanks in advance.

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  • Using XML as data storage

    - by Kian Mayne
    I was thinking about the XML format and the following quote: “XML is not a database. It was never meant to be a database. It is never going to be a database. Relational databases are proven technology with more than 20 years of implementation experience. They are solid, stable, useful products. They are not going away. XML is a very useful technology for moving data between different databases or between databases and other programs. However, it is not itself a database. Don't use it like one.“ -Effective XML: 50 Specific Ways to Improve Your XML by Elliotte Rusty Harold (page 230, Part 4, Item 41, 2nd paragraph) This seems to really stress that XML should not be used for data storage and should only be used for program to program interoperability. Personally, I disagree and .NET's app.config file that's used to store a program's settings is an example of data storage in an XML file. However for databases rather than configurations etc XML should not be used. To develop my point, I will use two examples: A) Data about customers with fields that are all on one level i.e. there are a number of fields all relating to one customer with no children B) Data about configuration of an application where nested fields and properties make a lot of sense So my question is, Is this still a valid statement and is it now acceptable to store data using XML? EDIT: I've sent an email to the author of that quote to ask for his input/extra context.

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  • XML + Xslt -> Xml with PHP

    - by rokdd
    Hi, I know that there are really a mass of XML XSLT php merging threads at SO. But php specific i could not found what might my problem: $xml = new DOMDocument; $xml-load("f.xml"); $xsl = new DOMDocument; $xsl-load('test.xsl'); // init and configure processor $proc = new XSLTProcessor; $proc-importStyleSheet($xsl); // import xsl document $xml2=$proc-transformToXML($xml); echo $xml2; My xslt file looks a bit empty.. However i tried ´output method="xml"´. but it doesnot help.. PHP returns always the data as text or html but not in XML.. what i am doing wrong. I only want to edit the XML with xslt and save back to XML (file). THanks for your help!

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  • Perl XML SAX parser emulating XML::Simple record for record

    - by DVK
    Short Q summary: I am looking a fast XML parser (most likely a wrapper around some standard SAX parser) which will produce per-record data structure 100% identical to those produced by XML::Simple. Details: We have a large code infrastructure which depends on processing records one-by-one and expects the record to be a data structure in a format produced by XML::Simple since it always used XML::Simple since early Jurassic era. An example simple XML is: <root> <rec><f1>v1</f1><f2>v2</f2></rec> <rec><f1>v1b</f1><f2>v2b</f2></rec> <rec><f1>v1c</f1><f2>v2c</f2></rec> </root> And example rough code is: sub process_record { my ($obj, $record_hash) = @_; # do_stuff } my $records = XML::Simple->XMLin(@args)->{root}; foreach my $record (@$records) { $obj->process_record($record) }; As everyone knows XML::Simple is, well, simple. And more importantly, it is very slow and a memory hog - due to being a DOM parser and needing to build/store 100% of data in memory. So, it's not the best tool for parsing an XML file consisting of large amount of small records record-by-record. However, re-writing the entire code (which consist of large amount of "process_record"-like methods) to work with standard SAX parser seems like an big task not worth the resources, even at the cost of living with XML::Simple. What I'm looking for is an existing module which will probably be based on a SAX parser (or anything fast with small memory footprint) which can be used to produce $record hashrefs one by one based on the XML pictured above that can be passed to $obj->process_record($record) and be 100% identical to what XML::Simple's hashrefs would have been. I don't care much what the interface of the new module is - e.g whether I need to call next_record() or give it a callback coderef accepting a record.

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  • WCF MessageContract Help - MessageBodyMember with hyphenated name

    - by Hcabnettek
    Hi All, I need a bit of WCF help. This project uses message contracts. The transport seems to work ok. I have this code for a response type. namespace tpoke.Contracts { [MessageContract(IsWrapped = true)] public class AuthenticationResponseMC { [MessageBodyMember(Name = "authentication-token")] public Guid AuthenticationToken; } } Now when I run the operation that returns this, I try to deserialize using the XmlSerializer. The is not what I'm needing. I need it to be <authentication-token xmlns="http://tpoke.wcf.com">e13xxxx-xxxx-xxxx-xxxxxx</authentication-token> How can I make this work correctly? Do I need to add the namespace to MessageBodyMember? Why is the hyphen being stripped out? Any tips or advice is certainly appreciated. Thanks, ~ck in San Diego

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