Search Results

Search found 19664 results on 787 pages for 'python for ever'.

Page 403/787 | < Previous Page | 399 400 401 402 403 404 405 406 407 408 409 410  | Next Page >

  • django file serving issues

    - by tipu
    I have in my url patterns, urlpatterns += patterns('', (r'^(?P<path>.*)$', 'django.views.static.serve', {'document_root': '/home/tipu/Dropbox/dev/workspace/search/images'}) In my template when I do <link rel="stylesheet" type="text/css" href="{{ MEDIA_URL }}style.css" /> It serves the css just fine. But the file logo.png, that's in the same directory as style.css, doesn't show when I do this: <img src = "{{ MEDIA_URL }}logo.png" id = "logo" /> Any idea why?

    Read the article

  • How to turn this simple 10 digit hex number back into 8 digits?

    - by Babil
    The algorithm to convert input 8 digit hex number into 10 digit are following: Given that the 8 digit number is: '12 34 56 78' x1 = 1 * 16^8 * 2^3 x2 = 2 * 16^7 * 2^2 x3 = 3 * 16^6 * 2^1 x4 = 4 * 16^4 * 2^4 x5 = 5 * 16^3 * 2^3 x6 = 6 * 16^2 * 2^2 x7 = 7 * 16^1 * 2^1 x8 = 8 * 16^0 * 2^0 Final 10 digit hex is: = x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = '08 86 42 98 E8' The problem is - how to go back to 8 digit hex from a given 10 digit hex (for example: 08 86 42 98 E8 to 12 34 56 78) Some sample input and output are following: input output 11 11 11 11 08 42 10 84 21 22 22 33 33 10 84 21 8C 63 AB CD 12 34 52 D8 D0 88 64 45 78 96 32 21 4E 84 98 62 FF FF FF FF 7B DE F7 BD EF

    Read the article

  • programs hangs during socket interaction

    - by herrturtur
    I have two programs, sendfile.py and recvfile.py that are supposed to interact to send a file across the network. They communicate over TCP sockets. The communication is supposed to go something like this: sender =====filename=====> receiver sender <===== 'ok' ======= receiver or sender <===== 'no' ======= receiver if ok: sender ====== file ======> receiver I've got The sender and receiver code is here: Sender: import sys from jmm_sockets import * if len(sys.argv) != 4: print "Usage:", sys.argv[0], "<host> <port> <filename>" sys.exit(1) s = getClientSocket(sys.argv[1], int(sys.argv[2])) try: f = open(sys.argv[3]) except IOError, msg: print "couldn't open file" sys.exit(1) # send filename s.send(sys.argv[3]) # receive 'ok' buffer = None response = str() while 1: buffer = s.recv(1) if buffer == '': break else: response = response + buffer if response == 'ok': print 'receiver acknowledged receipt of filename' # send file s.send(f.read()) elif response == 'no': print "receiver doesn't want the file" # cleanup f.close() s.close() Receiver: from jmm_sockets import * s = getServerSocket(None, 16001) conn, addr = s.accept() buffer = None filename = str() # receive filename while 1: buffer = conn.recv(1) if buffer == '': break else: filename = filename + buffer print "sender wants to send", filename, "is that ok?" user_choice = raw_input("ok/no: ") if user_choice == 'ok': # send ok conn.send('ok') #receive file data = str() while 1: buffer = conn.recv(1) if buffer=='': break else: data = data + buffer print data else: conn.send('no') conn.close() I'm sure I'm missing something here in the sorts of a deadlock, but don't know what it is.

    Read the article

  • Easy way to keep counting up infinitely

    - by Andrew Alexander
    What's a good way to keep counting up infinitely? I'm trying to write a condition that will keep going until there's no value in a database, so it's going to iterate from 0, up to theoretically infinity (inside a try block, of course). How would I count upwards infinitely? Or should I use something else? I am looking for something similar to i++ in other languages, where it keeps iterating until failure.

    Read the article

  • Various way to send data to the web server

    - by Webrsk
    Client Environment : Windows XP , Internet connection Available, PHP Not installed. Server Environment : CentOS , Internet connection Available, PHP , MYsql installed. Data are stored in files at client machine , suggest better ways to send data fetched from the file to the server. Normally i would be using HTTP request using Curl to send the data to the server but client machine doesnt have php installed. What all are the ways to send data to the server and the comparisons?

    Read the article

  • Return an object after parsing xml with SAX

    - by sentimental_turtle
    I have some large XML files to parse and have created an object class to contain my relevant data. Unfortunately, I am unsure how to return the object for later processing. Right now I pickle my data and moments later depickle the object for access. This seems wasteful, and there surely must be a way of grabbing my data without hitting the disk. def endElement(self, name): if name == "info": # done collecting this iteration self.data.setX(self.x) self.data.setY(self.y) elif name == "lastTagOfInterest": # done with file # want to return my object from here filehandler = open(self.outputname + ".pi", "w") pickle.dump(self.data, filehandler) filehandler.close() I have tried putting a return statement in my endElement tag, but that does not seem to get passed up the chain to where I call the SAX parser. Thanks for any tips.

    Read the article

  • How do you leave comments/like a specific page of a Facebook Canvas app?

    - by Sebastian
    I'm building a tabbed Facebook Canvas app that requires individual images to be "Like"d and commented on. Since each image is loaded up as its own page, in this style: http://apps.facebook.com/appname/image/333/ (which translates to: www.mydomain.com/image/333/) I was hoping I could just get a UID for each "image" page and then comment/like based off that. If that's possible, how exactly do I get the id for dynamically generated pages? Or any page for that matter? Thanks in advance.

    Read the article

  • Flask Admin didn't show all fields

    - by twoface88
    I have model like this: class User(db.Model): __tablename__ = 'users' __table_args__ = {'mysql_engine' : 'InnoDB', 'mysql_charset' : 'utf8'} id = db.Column(db.Integer, primary_key=True) username = db.Column(db.String(80), unique=True) email = db.Column(db.String(120), unique=True) _password = db.Column('password', db.String(80)) def __init__(self, username = None, email = None, password = None): self.username = username self.email = email self._set_password(password) def _set_password(self, password): self._password = generate_password_hash(password) def _get_password(self): return self._password def check_password(self, password): return check_password_hash(self._password, password) password = db.synonym("_password", descriptor=property(_get_password, _set_password)) def __repr__(self): return '<User %r>' % self.username I have ModelView: class UserAdmin(sqlamodel.ModelView): searchable_columns = ('username', 'email') excluded_list_columns = ['password'] list_columns = ('username', 'email') form_columns = ('username', 'email', 'password') But no matter what i do, flask admin didn't show password field when i'm editing user info. Is there any way ? Even just to edit hash code. UPDATE: https://github.com/mrjoes/flask-admin/issues/78

    Read the article

  • integrate / build 'weather radar' widget

    - by zack
    I'm looking to integrate a 'weather radar' widget into a site I'm building. The only available resource I can find is: http://www.meteoonline.co.uk/gadgets/Europe/Netherlands/135 which basically delivers a flash mov in a iframe ! urrrgh! - and 'permission denied' of course with any javascript interaction on the iframe.. Can anyone suggest an alternative resource / or approach ? I'm happy to work with the raw data if I can get it .. any ideas welcome ! site is like [ html5 + jquery on django ]

    Read the article

  • Pyjamas import statements

    - by Gordon Worley
    I'm starting to use Pyjamas and I'm running into some annoyances. I have to import a lot of stuff to make a script work well. For example, to make a button I need to first from pyjamas.ui.Button import Button and then I can use Button. Note that import pyjamas.ui.Button and then using Button.Button doesn't work (results in errors when you build to JavaScript, at least in 0.7pre1). Does anyone have a better example of a good way to do the import statements in Pyjamas than what the Pyjamas folks have on their site? Doing things their way is possible, but ugly and overly complicated from my perspective, especially when you want to use a dozen or more ui components.

    Read the article

  • wxPython ,Change the background colour of a StyledTextCtrl

    - by user1357159
    I tried (but nothing happens) self.txt.SetBackgroundColour ((255,0,0)) As said in the title I'm trying to change the background colour StyledTextCtrl. Does anyone know a method that could be used? I've checked the API docs but I couldn't seem to find one, http://wxpython.org/docs/api/wx.stc.StyledTextCtrl-class.html (by background colour, I mean the whole writing area, of course) Does anyone know a way I could do this? EDIT: The background doesn't change in the following code import wx import wx.stc app = wx.App(redirect=True) top = wx.Frame(None, title="StyledTXTCtrl", size=(300,200)) txt=wx.stc.StyledTextCtrl(top) txt.SetBackgroundColour((255,255,0)) txt.Refresh() top.Show() app.MainLoop()

    Read the article

  • Py GTK Drawing area and Rich Text Editor

    - by crashekar
    I would like to include a rich text editor in a pygtk drawing area for an application i am developing. The editor ( a small resizable widget ) should be able to move around the drawing area like a rectangle. I am not sure how to start as I am pretty new to PyGTK. thank you !

    Read the article

  • GQL Request BadArgument Error. How to get around with my case?

    - by awegawef
    My query is essentially the following: entries=Entry.all().order("-votes").order("-date").filter("votes >", VOTE_FILTER).fetch(PAGE_SIZE+1, page* PAGE_SIZE) I want to grab N of the latest entries that have a voting score above some benchmark (VOTE_FILTER). Google currently says that I cannot filter on 'votes' because I order by 'date.' I don't see a way that I can do this the way I want to, so I'd appreciate any advice.

    Read the article

  • Selenium selected option in dropdown not displayed correctly

    - by luckyfool
    I have the following issue with Selenium Webdriver. There are two dropdown menus on a page i am testing "brand" and "items". The options of "items" depend on which brand you choose. I am trying to iterate through all possible choices and print brand-item pairs. I use two possible ways to pick an option from each dropdown menu Using Select(): def retryingSelectOption(name,n): result=False attempts=0 while attempts<5: try: element=Select(driver.find_element_by_name(name)) element.select_by_index(n) print element.all_selected_options[0].text result=True break except StaleElementReferenceException: pass attempts+=1 return result And using .click(): def retryingClickOption(name,n): result=False attempts=0 while attempts<5: try: driver.find_element_by_name(name).find_elements_by_tag_name("option")[n].click() result=True break except StaleElementReferenceException: pass attempts+=1 return result My problem is that at ,what seem to me as random moments (sometimes it works sometimes it does not), even though the above functions return True and printing out the selected option shows me the correct answer, the browser still displays the previous option. So basically Selenium tells me i have picked the right option but the browser displays the previous one.No idea what is wrong.

    Read the article

  • Extract files from zip folder and store these files in blobstore

    - by Eng_Engineer
    i want to upload zip folder from file input in form the i want to extract the contents of this uploaded zip folder,and store the contents (files)of this zip in the blobstore in order to download them after putting these files in one folder,but the problem is that i can't deal with the zip folder directly(to read it), i tried as this: form = cgi.FieldStorage() file_upload = form['file'] zip1=file_upload.filename zipstream=StringIO.StringIO(zip1.read()) But the problem still that i can't read the zip as previous,also i tried to read zip folder directly like this: z1=zipfile.ZipFile(zip1,"r") But there was an error in this way.Please can any one help me.Thanks in advance.

    Read the article

  • How do you get SQLAlchemy to override MySQL "on update CURRENT_TIMESTAMP"

    - by nocola
    I've inherited an older database that was setup with a "on update CURRENT_TIMESTAMP" put on a field that should only describe an item's creation. With PHP I have been using "timestamp=timestamp" on UPDATE clauses, but in SQLAlchemy I can't seem to force the system to use the set timestamp. Do I have no choice and need to update the MySQL table (millions of rows)? foo = session.query(f).get(int(1)) ts = foo.timestamp setattr(foo, 'timestamp', ts) setattr(foo, 'bar', bar) www_model.www_Session.commit() I have also tried: foo = session.query(f).get(int(1)) setattr(foo, 'timestamp', foo.timestamp) setattr(foo, 'bar', bar) www_model.www_Session.commit()

    Read the article

  • Appengine Model SelfReferenceProperty and parent child relationship

    - by GeekTantra
    I have a scenario in which I need a self reference property as follow: class Post(db.Model): creator = db.UserProperty() post_title = db.StringProperty(required=True) post_status = db.StringProperty(required=True, choices=['draft', 'published']) post_parent = db.SelfReferenceProperty() Now, I want ensure that an entity shouldn't be its own parent and a child of an entity cannot be its parent. How can I ensure this kind of a relationship in the PostForm model form and the Post model.

    Read the article

  • how to fetch more than 1000 entities NON keybased?

    - by user291071
    If I should be approaching this problem through a different method, please suggest so. I am creating an item based collaborative filter. I populate the db with the LinkRating2 class and for each link there are more than a 1000 users that I need to call and collect their ratings to perform calculations which I then use to create another table. So I need to call more than 1000 entities for a given link. For instance lets say there are over a 1000 users rated 'link1' there will be over a 1000 instances of this class for the given link property that I need to call. How would I complete this example? class LinkRating2(db.Model): user = db.StringProperty() link = db.StringProperty() rating2 = db.FloatProperty() query =LinkRating2.all() link1 = 'link string name' a = query.filter('link = ', link1) aa = a.fetch(1000)##how would i get more than 1000 for a given link1 as shown? ##keybased over 1000 in other post example i need method for a subset though not key class MyModel(db.Expando): @classmethod def count_all(cls): """ Count *all* of the rows (without maxing out at 1000) """ count = 0 query = cls.all().order('__key__') while count % 1000 == 0: current_count = query.count() if current_count == 0: break count += current_count if current_count == 1000: last_key = query.fetch(1, 999)[0].key() query = query.filter('__key__ > ', last_key) return count

    Read the article

  • better for-loop syntax for detecting empty sequences?

    - by Dmitry Beransky
    Hi, Is there a better way to write the following: row_counter = 0 for item in iterable_sequence: # do stuff with the item counter += 1 if not row_counter: # handle the empty-sequence-case Please keep in mind that I can't use len(iterable_sequence) because 1) not all sequences have known lengths; 2) in some cases calling len() may trigger loading of the sequence's items into memory (as the case would be with sql query results). The reason I ask is that I'm simply curious if there is a way to make above more concise and idiomatic. What I'm looking for is along the lines of: for item in sequence: #process item *else*: #handle the empty sequence case (assuming "else" here worked only on empty sequences, which I know it doesn't)

    Read the article

< Previous Page | 399 400 401 402 403 404 405 406 407 408 409 410  | Next Page >