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  • How do I delete in Django? (mysql transactions)

    - by alex
    If you are familiar with Django, you know that they have a Authentication system with User model. Of course, I have many other tables that have a Foreign Key to this User model. If I want to delete this user, how do I architect a script (or through mysql itself) to delete every table that is related to this user? My only worry is that I can do this manually...but if I add a table , but I forget to add that table to my DELETE operation...then I have a row that links to a deleted, non-existing User.

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  • Doing a count over a filter query efficiently in django

    - by apple_pie
    Hello, Django newbie here, I need to do a count over a certain filter in a django model. If I do it like so: my_model.objects.filter(...).count() I'm guessing it does the SQL query that retrieves all the rows and only afterwards does the count. To my knowledge it's much more efficient to do the count without retrieving those rows like so "SELECT COUNT(*) FROM ...". Is there a way to do so in django?

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  • Can Django be used for web services?

    - by alex
    My friend said, "Pylons is so much better for web services." My other friend said, "You can modify Django in a way to do exactly whatever you like." In Django, what is necessary to be modified (urls.py? models classes? settings?) in order to do "web services" with APIs and REST and versioning, etc etc.?

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  • Recursion function not working properly

    - by jakecar
    I'm having quite a hard time figuring out what's going wrong here: class iterate(): def init(self): self.length=1 def iterated(self, n): if n==1: return self.length elif n%2==0: self.length+=1 self.iterated(n/2) elif n!=1: self.length+=1 self.iterated(3*n+1) For example, x=iterate() x.iterated(5) outputs None. It should output 6 because the length would look like this: 5 -- 16 -- 8 -- 4 -- 2 -- 1 After doing some debugging, I see that the self.length is returned properly but something goes wrong in the recursion. I'm not really sure. Thanks for any help.

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  • Infinite recursion trying to check all elements of a TreeCtrl

    - by mavnn
    I have a TreeCtrl in which more than one Item can be assigned the same object as PyData. When the object is updated, I want to update all of the items in the tree which have that object as their PyData. I thought the following code would solve the problem quite neatly, but for some reason the logical test (current != self.GetFirstVisibleItem()) always returns true leading to infinite recursion. Can anyone explain why? def RefreshNodes(self, obj, current=None): print "Entered refresh" current = current or self.GetFirstVisibleItem() if current.IsOk(): print self.GetPyData(current).name if self.GetPyData(current) == obj: self.RefreshNode(current) current = self.GetNextVisible(current) if current != self.GetFirstVisibleItem(): self.RefreshNodes(obj, current) Edit: the above is obviously part of a class based on wx.TreeCtrl

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  • How would I make this faster? Parsing Word/sorting by heading [on hold]

    - by Doof12
    Currently it takes about 3 minutes to run through a single 53 page word document. Hopefully you all have some advice about speeding up the process. Code: import win32com.client as win32 from glob import glob import io import re from collections import namedtuple from collections import defaultdict import pprint raw_files = glob('*.docx') word = win32.gencache.EnsureDispatch('Word.Application') word.Visible = False oFile = io.open("rawsort.txt", "w+", encoding = "utf-8")#text dump doccat= list() for f in raw_files: word.Documents.Open(f) doc = word.ActiveDocument #whichever document is active at the time doc.ConvertNumbersToText() print doc.Paragraphs.Count for x in xrange(1, doc.Paragraphs.Count+1):#for loop to print through paragraphs oText = doc.Paragraphs(x) if not oText.Range.Tables.Count >0 : results = re.match('(?P<number>(([1-3]*[A-D]*[0-9]*)(.[1-3]*[0-9])+))', oText.Range.Text) stylematch = re.match('Heading \d', oText.Style.NameLocal) if results!= None and oText.Style != None and stylematch != None: doccat.append((oText.Style.NameLocal, oText.Range.Text[:len(results.group('number'))],oText.Range.Text[len(results.group('number')):])) style = oText.Style.NameLocal else: if oText.Range.Font.Bold == True : doccat.append(style, oText) oFile.write(unicode(doccat)) oFile.close() The for Paragraph loop obviously takes the most amount of time. Is there some way of identifying and appending it without going through every Paragraph?

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  • best way to find out type

    - by laspal
    hi, I have a dict val_dict - {'val1': 'abcd', 'val': '1234', 'val3': '1234.00', 'val4': '1abcd 2gfff'} All the values to my keys are string. So my question is how to find out type for my values in the dict. I mean if i say`int(val_dict['val1']) will give me error. Basically what I am trying to do is find out if the string is actual string or int or float.` if int( val_dict['val1'): dosomething else if float(val_dict['val1']): dosomething thanks

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  • how to capture the right click event using getMouse()

    - by Leyond
    I am trying to use graphics.py to write a user graphics interface. The problem is that how can I capture the right click event? It seems that the function getMouse() could just returns where the mouse was left-clicked as a Point object. from graphics import * def main(): win = GraphWin("My Circle", 100, 100) c = Circle(Point(50,50), 10) c.draw(win) win.getMouse() # pause for click in window win.close() main() I want to know how can I capture the right-click event in the window, thanks.

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  • Setting `axes.linewidth` without changing the `rcParams` global dict

    - by mlvljr
    So, it seems one cannot do the following (it raises an error, since axes does not have a set_linewidth method): axes_style = {'linewidth':5} axes_rect = [0.1, 0.1, 0.9, 0.9] axes(axes_rect, **axes_style) and has to use the following old trick instead: rcParams['axes.linewidth'] = 5 # set the value globally ... # some code rcdefaults() # restore [global] defaults Is there an easy / clean way (may be one can set x- and y- axes parameters individually, etc)? P.S. If no, why?

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  • Display values and how many times they occured using a Dictionary

    - by user1730056
    I've been told to By using a dictionary (or your solution to Part 4), write a method at_least(a, n) that takes a list, a, and an integer, n, as arguments and returns a list containing only the elements of a that occur at least n times. For complete marks, the list should contain the elements in order of their first occurrence in a. I was able to figure this without using a dictionary, with def at_least2(a, n): return [x for x in a if a.count(x) is n] I was wondering how I can write this using a dictionary? The input is: a = [-6, 8, 7, 3, 2, -9, 1, -3, 2, -4, 4, -8, 7, 8, 2, -2, -7, 0, 1, -9, -3, -7, -3, -5, 6, -3, 6, -3, -10, -8] def at_least(a, 2): and the output: [8, 7, 2, -9, 1, -3, 2, -8, 7, 8, 2, -7, 1, -9, -3, -7, -3, 6, -3, 6, -3, -8] Edit: I don't understand how a dictionary is being used, yet the output isn't in dictionary form? My understanding is that dictionaries have values for each object. I'm not sure if I'm using the right terms.

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  • Take data from an XML file and put it into a MySQL database

    - by Aidan
    Hi Guys, I'm looking to construct a script that would go through an XML file. Would find specific tags in it, put them in a table and fill the table with specific tags within them. I'm using MySQL 5.1 so loadXML isn't an option and I think that ExtractData() method wont be much use either.. but I don't really know. What would be the best way to go about this?

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  • How to retrieve items from a django queryset?

    - by sharataka
    I'm trying to get the video element in a queryset but am having trouble retrieving it. user_channel = Everything.objects.filter(profile = request.user, playlist = 'Channel') print user_channel[0] #returns the first result without error print user_channel[0]['video'] #returns error Models.py: class Everything(models.Model): profile = models.ForeignKey(User) playlist = models.CharField('Playlist', max_length = 2000, null=True, blank=True) platform = models.CharField('Platform', max_length = 2000, null=True, blank=True) video = models.CharField('VideoID', max_length = 2000, null=True, blank=True) video_title = models.CharField('Title of Video', max_length = 2000, null=True, blank=True) def __unicode__(self): return u'%s %s %s %s %s' % (self.profile, self.playlist, self.platform, self.video, self.video_title)

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  • PHP CURL sending POST to Django app issue

    - by Felipe Pelá
    This code in PHP sends a HTTP POST to a Django app using CURL lib. I need that this code sends POST but redirect to the page in the same submit. Like a simple form does. The PHP Code: $c = curl_init(); curl_setopt($c, CURLOPT_FOLLOWLOCATION, true); curl_setopt($c, CURLOPT_URL, "http://www.xxx.com"); curl_setopt($c, CURLOPT_POST, true); curl_setopt($c, CURLOPT_POSTFIELDS, 'Var='.$var); curl_exec($c); curl_close ($c); In this case, the PHP is sending the HTTP POST, but is not redirecting to the page. He is printing the result. My URL still .php and not a django/url/ I need be redirected to the django URL with the Post like a simple form in HTML does. Any Idea? Thanks.

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  • Connect to a DB with an encrypted password with Django?

    - by Liam
    My place of employment requires that all passwords must be encrypted, including the ones used to connect to a database. What's the best way of handling this? I'm using the development version of Django with MySQL at the moment, but I will be eventually migrating to Oracle. Is this a job for Django, or the database? Edit: The encrypted password should be stored in the settings.py file, or somewhere else in the filesystem. This is the password that will be used to connect to the database.

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  • Psycopg2 doesn't like table names that start with a lower case letter

    - by Count Boxer
    I am running ActiveState's ActivePython 2.6.5.12 and PostgreSQL 9.0 Beta 1 under Windows XP. If I create a table with an upper case first letter (i.e. Books), psycopg2 returns the "Programming Error: relation "books" does not exist" error message when I run the select statement: execute("SELECT * FROM Books"). The same error is returned if I run: execute("SELECT * FROM books"). However, if I change the table to a lower case first name (i.e. books), then either of the above statements works. Are tables name supposed to have a lower case first name? Is this a setting or a feature or a bug? Am I missing something obvious?

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  • Default subclass objects in Sqlalchemy?

    - by Timmy
    im using the example from the pylons book orm.mapper(Comment, comment_table) orm.mapper(Tag, tag_table) orm.mapper(Nav, nav_table, polymorphic_on=nav_table.c.type, polymorphic_identity='nav') orm.mapper(Section, section_table, inherits=Nav, polymorphic_identity='section') orm.mapper(Page, page_table, inherits=Nav, polymorphic_identity='page', properties={ 'comments':orm.relation(Comment, backref='page', cascade='all'), 'tags':orm.relation(Tag, secondary=pagetag_table) }) i am mostly copying from this, but is there a simple way have a default Page that gets referenced, but if users requests a change, create a new Page object? thanks i want something similar to this class DefaultPage(Page): __init__(self): self.a = a self.b = b self.c = c orm.mapper(DefaultPage, None, inherits=Nav, yada yada )

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  • urllib open - how to control the number of retries

    - by user1641071
    how can i control the number of retries of the "opener.open"? for example, in the following code, it will send about 6 "GET" HTTP requests (i saw it in the Wireshark sniffer) before it goes to the " except urllib.error.URLError" success/no-success lines. password_mgr = urllib.request.HTTPPasswordMgrWithDefaultRealm() password_mgr.add_password(None,url, username, password) handler = urllib.request.HTTPBasicAuthHandler(password_mgr) opener = urllib.request.build_opener(handler) try: resp = opener.open(url,None,1) except urllib.error.URLError as e: print ("no success") else: print ("success!")

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  • get the list and input from one function and run them in different function

    - by rookie
    i have a programm that generate the list and then i ask them to tell me what they want to do from the menu and this is where my problem start i was able to get the input form the user to different function but when i try to use the if else condition it doesn't check, below are my code def menu(x,l): print (x) if x == 1: return make_table(l) if x == 2: y= input("enter a row (as a number) or a column (as an uppercase letter") if y in [ "1",'2','3']: print("Minmum is:",minimum(y,l)) if x== 3: print ('bye') def main(): bad_filename = True l =[] while bad_filename == True: try: filename = input("Enter the filename: ") fp = open(filename, "r") for f_line in fp: f_str=f_line.strip() f_str=f_str.split(',') for unit_str in f_str: unit=float(unit_str) l.append(unit) bad_filename = False except IOError: print("Error: The file was not found: ", filename) #print(l) condition=True while condition==True: print('1- open\n','2- maximum') x=input("Enter the choice") menu(x,l) main() from the bottom function i can get list and i can get the user input and i can get the data and move it in second function but it wont work after that.thank you

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