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  • SQLAlchemy - loading user by username

    - by keithjgrant
    Just diving into pylons here, and am trying to get my head around the basics of SQLALchemy. I have figured out how to load a record by id: user_q = session.query(model.User) user = user_q.get(user_id) But how do I query by a specific field (i.e. username)? I assume there is a quick way to do it with the model rather than hand-building the query. I think it has something with the add_column() function on the query object, but I can't quite figure out how to use it. I've been trying stuff like this, but obviously it doesn't work: user_q = meta.Session.query(model.User).add_column('username'=user_name) user = user_q.get()

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  • text overlay for tray icon

    - by AnC
    I have a simple tray icon using PyGTK's gtk.StatusIcon: import pygtk pygtk.require('2.0') import gtk statusIcon = gtk.StatusIcon() statusIcon.set_from_stock(gtk.STOCK_EDIT) statusIcon.set_tooltip('Hello World') statusIcon.set_visible(True) gtk.main() How can I add a text label (one or two characters; basically, unread count) to the tooltip - without creating separate images for set_from_file?

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  • list in loop, Nonetype errors

    - by user2926755
    Here is my Code def printList(stringlist): empty = [] if stringlist is None: print empty else: print stringlist def add (stringlist, string): string = [] if string is None else string if stringlist is not None: stringlist.insert(0, string) else: stringlist.append(1) it somehow appears "AttributeError: 'NoneType' object has no attribute 'append'" I was originally looking for the code to be run like this: >>> myList = None >>> printList(myList) [] >>> for word in ['laundry','homework','cooking','cleaning']: myList = add(myList, word) printList(myList) [laundry] [homework, laundry] [cooking, homework, laundry] [cleaning, cooking, homework, laundry]

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  • How to calculate cointegrations of two lists?

    - by Damiano
    Hello everybody! Thank you in advance for your help! I have two lists with some stocks prices, example: a = [10.23, 11.65, 12.36, 12.96] b = [5.23, 6.10, 8.3, 4.98] I can calculate the correlation of these two lists, with: import scipy.stats scipy.stats.pearsonr(a, b)[0] But, I didn't found a method to calculate the co-integration of two lists. Could you give me some advices? Thank you very much!

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  • Indexing over the results returned by selenium

    - by Guy
    Hi I try to index over results returned by an xpath. For example: xpath = '//a[@id="someID"]' can return a few results. I want to get a list of them. I thought that doing: numOfResults = sel.get_xpath_count(xpath) l = [] for i in range(1,numOfResults+1): l.append(sel.get_text('(%s)[%d]'%(xpath, i))) would work because doing something similar with firefox's Xpath checker works: (//a[@id='someID'])[2] returns the 2nd result. Ideas why the behavior would be different and how to do such a thing with selenium Thanks

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  • Converting time period strings to value/unit pair

    - by randomtoor
    I need to parse the contents of a string that represents a time period. The format of the string is value/unit, e.g.: 1s, 60min, 24h. I would separate the actual value (an int) and unit (a str) to separated variables. At the moment I do it like this: def validate_time(time): binsize = time.strip() unit = re.sub('[0-9]','',binsize) if unit not in ['s','m','min','h','l']: print "Error: unit {0} is not valid".format(unit) sys.exit(2) tmp = re.sub('[^0-9]','',binsize) try: value = int(tmp) except ValueError: print "Error: {0} is not valid".format(time) sys.exit(2) return value,unit However, it is not ideal as things like 1m0 are also (wrongly) validated (value=10,unit=m). What is the best way to validate/parse this input?

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  • How do I assign functions in a dictionary?

    - by Ziv
    hi, I'm having a problem with a simple program I wrote, I want to perform a certain function according to the users input. I've already used a dictionary as a replacement for a switch to do assignment but when I try to assign functions to the dictionary it doesn't execute them... The code: def PrintValuesArea(): ## do this def PrintValuesLength(): ## do that def PrintValuesTime(): ## do third PrintTables={"a":PrintValuesArea,"l":PrintValuesLength,"t":PrintValuesTime} PrintTables.get(ans.lower()) ## ans is the user input what did I do wrong? It looks the same as all the examples I've seen....

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  • Do not match if word appears in regex

    - by David542
    I have a url, and I want it to NOT match if the word 'season' is contained in the url. Here are two examples: CONTAINS SEASON, DO NOT MATCH 'http://imdb.com/title/tt0285331/episodes?this=1&season=7&ref_=tt_eps_sn_7' DOES NOT CONTAIN SEASON, MATCH 'http://imdb.com/title/tt0285331/ Here is what I have so far, but I'm afraid the .+ will match everything until the end. What would be the correct regex to use here? r'http://imdb.com/title/tt(\d)+/.+^[season].+'

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  • What is considered bleeding edge in programming these days?

    - by iestyn
    What is "bleeding edge" these days? has it all been done before us, and we are just discovering new ways of implementing mathematical constructs within programming? Functional Programming seems to be making inroads in all areas, but is this just marketing to create interest in a programming arena where it appears that the state of the art has climaxed too soon. have the sales men got hold of the script, and selling ideas that can be sold, dumbing down the future? I see very old ideas making their way into the market place....what are the truly new things that should be considered fresh and new in 2010 onwards, and not some 1960-1980 idea being refocused.

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  • a function that returns a random number that is a multiple of 3 between 0 and the function's non-negative integer parameter n

    - by martin
    I need to write a function called multipleOf3 that returns a random number that is a multiple of 3 between 0 and the function's non-negative integer parameter n and here is the result i want [Note: No number returned can be greater than the value of the parameter n] Examples: multipleOf3(0) -- 0 multipleOf3(1) -- 0 multipleOf3(2) -- 0 multipleOf3(3) -- 0 or 3 multipleOf3(20) -- 0 or 3 or 6 or 9 or 12 or 15 or 18

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  • How do I attach event bindings to items on a canvas using Tkinter?

    - by Ian
    If I'm using a canvas to display data and I want the user to be able to click on various items on the canvas in order to get more information or interact with it in some way, whats the best way of going about this? Searching online I can find information about how to bind events to tags but that seems to be more indirect then what I want. I don't want to group items with tags, but rather have specific function calls when the user clicks specific items on the canvas.

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  • Django Find Out if User is Authenticated in Custom Tag

    - by greggory.hz
    I'm trying to create a custom tag. Inside this custom tag, I want to be able to have some logic that checks if the user is logged in, and then have the tag rendered accordingly. This is what I have: def user_actions(context): request = template.Variable('request').resolve(context) return { 'auth': request['user'].is_athenticated() } register.inclusion_tag('layout_elements/user_actions.html', takes_context=True)(user_actions) When I run this, I get this error: Caught VariableDoesNotExist while rendering: Failed lookup for key [request] in u'[{}]' The view that renders this ends like this: return render_to_response('start/home.html', {}, context_instance=RequestContext(request)) Why doesn't the tag get a RequestContext object instead of the Context object? How can I get the tag to receive the RequestContext instead of the Context? EDIT: Whether or not it's possible to get a RequestContext inside a custom tag, I'd still be interested to know the "correct" or best way to determine a user's authentication state from within the custom tag. If that's not possible, then perhaps that kind of logic belongs elsewhere? Where?

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  • How to use ';' in urls, using Google Appengine

    - by tonfa
    Using the local dev server, I can use ';' in urls, but as soon as I try the live version hosted by Google, it looks like the ';' and everything afterward is stripped (at least according to request.path_qs). (I would prefer not to encode them if possible, it's much less user friendly if the url cannot be constructed by copy-pasting, especially since other characters works fine, e.g. ':').

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  • nested list comprehension using intermediate result

    - by KentH
    I am trying to grok the output of a function which doesn't have the courtesy of setting a result code. I can tell it failed by the "error:" string which is mixed into the stderr stream, often in the middle of a different conversion status message. I have the following list comprehension which works, but scans for the "error:" string twice. Since it is only rescanning the actual error lines, it works fine, but it annoys me I can't figure out how to use a single scan. Here's the working code: errors = [e[e.find('error:'):] for e in err.splitlines() if 'error:' in e] The obvious (and wrong) way to simplify is to save the "find" result errors = [e[i:] for i in e.find('error:') if i != -1 for e in err.splitlines()] However, I get "UnboundLocalError: local variable 'e' referenced before assignment". Blindly reversing the 'for's in the comprehension also fails. How is this done? THanks. Kent

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  • Building a user subscription application

    - by Tristan O'Neil
    Hello, I'm trying to come up with the best way to handle user subscription and management for our magazine website. What I want to happen is a user purchases a subscription and they are granted online access of a certain membership role for a certain amount of time depending on how many years they subscribed for. I would also like the system to be able to send out emails when a subscription is almost up. I've seen some third party projects to help accomplish this but I'd prefer to write this from scratch as I want total control over how it works. Any suggestions would be helpful. The main thing I can't figure out is how to have an expiring membership. You must keep track of when the user signed up and how long until they should expire.

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  • Find all A^x in a given range

    - by Austin Henley
    I need to find all monomials in the form AX that when evaluated falls within a range from m to n. It is safe to say that the base A is greater than 1, the power X is greater than 2, and only integers need to be used. For example, in the range 50 to 100, the solutions would be: 2^6 3^4 4^3 My first attempt to solve this was to brute force all combinations of A and X that make "sense." However this becomes too slow when used for very large numbers in a big range since these solutions are used in part of much more intensive processing. Here is the code: def monoSearch(min, max): base = 2 power = 3 while 1: while base**power < max: if base**power > min: print "Found " + repr(base) + "^" + repr(power) + " = " + repr(base**power) power = power + 1 base = base + 1 power = 3 if base**power > max: break I could remove one base**power by saving the value in a temporary variable but I don't think that would make a drastic effect. I also wondered if using logarithms would be better or if there was a closed form expression for this. I am open to any optimizations or alternatives to finding the solutions.

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  • Actual SQL statement after bind variables specified

    - by bioffe
    I am trying to log every SQL statement executed from my scripts. However I contemplate one problem I can not overcome. Is there a way to compute actual SQL statement after bind variables were specified. In SQLite I had to compute the statement to be executed manually, using code below: def __sql_to_str__(self, value,args): for p in args: if type(p) is IntType or p is None: value = value.replace("?", str(p) ,1) else: value = value.replace("?",'\'' + p + '\'',1) return value It seems CX_Oracle has cursor.parse() facilities. But I can't figure out how to trick CX_Oracle to compute my query before its execution.

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