Search Results

Search found 13534 results on 542 pages for 'python 2 6'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 405/542 | < Previous Page | 401 402 403 404 405 406 407 408 409 410 411 412  | Next Page >

  • indexing for faster search of lists in a file??

    - by kaushik
    i have a file having around 1 lakh lists and have a another file with again a list of around an average of 50.. I want to compare 2nd item of list in second file with the 2nd element of 1st file and repeat this for each of the 50 lists in 2nd file and get the result of all the matching element. I have written the code for all this,but this is taking a lot of time as it need to check the whole the 1lakh list some 50 times..i want to improve the speed... please tell me how can i do this.... i cant not post my code as it is part of big code and will be difficult to infer anything from that... please tell what can be done to improve the speed?? thank u,

    Read the article

  • How to turn this simple 10 digit hex number back into 8 digits?

    - by Babil
    The algorithm to convert input 8 digit hex number into 10 digit are following: Given that the 8 digit number is: '12 34 56 78' x1 = 1 * 16^8 * 2^3 x2 = 2 * 16^7 * 2^2 x3 = 3 * 16^6 * 2^1 x4 = 4 * 16^4 * 2^4 x5 = 5 * 16^3 * 2^3 x6 = 6 * 16^2 * 2^2 x7 = 7 * 16^1 * 2^1 x8 = 8 * 16^0 * 2^0 Final 10 digit hex is: = x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = '08 86 42 98 E8' The problem is - how to go back to 8 digit hex from a given 10 digit hex (for example: 08 86 42 98 E8 to 12 34 56 78) Some sample input and output are following: input output 11 11 11 11 08 42 10 84 21 22 22 33 33 10 84 21 8C 63 AB CD 12 34 52 D8 D0 88 64 45 78 96 32 21 4E 84 98 62 FF FF FF FF 7B DE F7 BD EF

    Read the article

  • why my code show messy code ..

    - by zjm1126
    class sss(webapp.RequestHandler): def get(self): url = "http://www.google.com/" result = urlfetch.fetch(url) if result.status_code == 200: self.response.out.write(result.content) and this view show : when i change code to this: if result.status_code == 200: self.response.out.write(result.content.decode('utf-8').encode('gb2312')) it show : so ,what i should do ? thanks

    Read the article

  • Appengine backreferences - need composite index?

    - by davezor
    I have a query that is very recently starting to throw: "The built-in indices are not efficient enough for this query and your data. Please add a composite index for this query." I checked the line on which this exception is being thrown, and the problem query is this one: count = self.vote_set.filter("direction =", 1).count() This is literally a one-filter operation using appengine's built-in backreferences. I have no idea how to optimize this query...anyone have any suggestions? I tried to add this index: - kind: Vote properties: - name: direction direction: desc - kind: Vote properties: - name: direction And I got a message (obviously) saying this was an unnecessary index. Thanks for your help in advance.

    Read the article

  • MemoryError when running Numpy Meshgrid

    - by joaoc
    I have 8823 data points with x,y coordinates. I'm trying to follow the answer on how to get a scatter dataset to be represented as a heatmap but when I go through the X, Y = np.meshgrid(x, y) instruction with my data arrays I get MemoryError. I am new to numpy and matplotlib and am essentially trying to run this by adapting the examples I can find. Here's how I built my arrays from a file that has them stored: XY_File = open ('XY_Output.txt', 'r') XY = XY_File.readlines() XY_File.close() Xf=[] Yf=[] for line in XY: Xf.append(float(line.split('\t')[0])) Yf.append(float(line.split('\t')[1])) x=array(Xf) y=array(Yf) Is there a problem with my arrays? This same code worked when put into this example but I'm not too sure. Why am I getting this MemoryError and how can I fix this?

    Read the article

  • Google App Engine: Update model definitons?

    - by Rosarch
    I recently updated one of my models by adding a db.ListProperty(): class DependencyArcTail(db.Model): courses = db.ListProperty(db.Key) ''' newly added ''' forwardLinks = db.ListProperty(db.Key) However, I can't seem to get this to be reflected in the SDK dashboard. I cleared the datastore and reloaded it. Then I ran the procedures that create the DependencyArcTail objects. However, forwardLinks still doesn't show up as an attribute in the SDK dashboard. What's happening?

    Read the article

  • Decorator that can take both init args and call args?

    - by digitala
    Is it possible to create a decorator which can be __init__'d with a set of arguments, then later have methods called with other arguments? For instance: from foo import MyDecorator bar = MyDecorator(debug=True) @bar.myfunc(a=100) def spam(): pass @bar.myotherfunc(x=False) def eggs(): pass If this is possible, can you provide a working example?

    Read the article

  • efficiently convert string (or tuple) to ctypes array

    - by Mu Mind
    I've got code that takes a PIL image and converts it to a ctypes array to pass out to a C function: w_px, h_px = img.size pixels = struct.unpack('%dI'%(w_px*h_px), img.convert('RGBA').tostring()) pixels_array = (ctypes.c_int * len(pixels))(*pixels) But I'm dealing with big images, and unpacking that many items into function arguments seems to be noticeably slow. What's the simplest thing I can do to get a reasonable speedup? I'm only converting to a tuple as an intermediate step, so if it's unnecessary, all the better.

    Read the article

  • I need to change a zip code into a series of dots and dashes (a barcode), but I can't figure out how

    - by Maggie
    Here's what I've got so far: def encodeFive(zip): zero = "||:::" one = ":::||" two = "::|:|" three = "::||:" four = ":|::|" five = ":|:|:" six = ":||::" seven = "|:::|" eight = "|::|:" nine = "|:|::" codeList = [zero,one,two,three,four,five,six,seven,eight,nine] allCodes = zero+one+two+three+four+five+six+seven+eight+nine code = "" digits = str(zip) for i in digits: code = code + i return code With this I'll get the original zip code in a string, but none of the numbers are encoded into the barcode. I've figured out how to encode one number, but it wont work the same way with five numbers.

    Read the article

  • pyplot.scatter changes the data limits of the axis

    - by Erotemic
    I have some code which plots some points. I substituted ax.scatter for ax.plot so I could control the color of each point individually. However when I make this change the axis x and y ranges seem to increase. I can't pinpoint why this is happening. The only thing I've changed is plot to scatter. This code makes an axis that is too big ax.scatter(x, y, c=color_list, s=pts_size, marker='o', edgecolor='none') #ax.plot(x, y, linestyle='None', marker='o', markerfacecolor=pts_color, markersize=pts_size, markeredgewidth=0) This code does the right thing (but I can't control the color) #ax.scatter(x, y, c=color_list, s=pts_size, marker='o', edgecolor='none') ax.plot(x, y, linestyle='None', marker='o', markerfacecolor=pts_color, markersize=pts_size, markeredgewidth=0) Is there a way I can call scatter such that it doesn't mess with my current axis limits?

    Read the article

  • How can I load an MP3 or similar music file for display and anaysis in wxWdigets?

    - by Jon Cage
    I'm developing a GUI in wxPython which allows a user to generate sequences of colours for some toys I'm building. Part of the program needs to load an MP3 (and potentially other formats further down the line) and display it to the user. That shuold be sufficient to get started but later I'd like to add features like identifying beats and some crude frequency analysis. Is there any simple way of loading / understanding an MP3's contents to display a plot of it's amplitudes to the screen using wxWidgets? I later intend to port to C++/wxWidgets for speed and to avoid having to distribute wxPython.

    Read the article

  • Error 400 in urllib2 when using cookies

    - by Hempage
    I've had some success using a different method to load cookies, but now I'm wanting to use the cookielib.MozillaCookieJar method to open a cookies.txt file. Here's the snippet of code that does this. cookieJar=MozillaCookieJar() cookieJar.load(argv[2]) After creating an HTTPCookieProcessor opener, and installing it, whenever I use urlopen, I get an HTTP 400 error. However, if I don't use a CookieJar, the urlopen method succeeds (though the response doesn't contain the data I need). I'm not sure whether the cookies.txt file is malformed, or whether there's something else going on.

    Read the article

  • How to differentiate between method and function in a decorator?

    - by defnull
    I want to write a decorator that acts differently depending on whether it is applied to a function or to a method. def some_decorator(func): if the_magic_happens_here(func): # <---- Point of interest print 'Yay, found a method ^_^ (unbound jet)' else: print 'Meh, just an ordinary function :/' return func class MyClass(object): @some_decorator def method(self): pass @some_decorator def function(): pass I tried inspect.ismethod(), inspect.ismethoddescriptor() and inspect.isfunction() but no luck. The problem is that a method actually is neither a bound nor an unbound method but an ordinary function as long as it is accessed from within the class body. What I really want to do is to delay the actions of the decorator to the point the class is actually instantiated because I need the methods to be callable in their instance scope. For this, I want to mark methods with an attribute and later search for these attributes when the .__new__() method of MyClass is called. The classes for which this decorator should work are required to inherit from a class that is under my control. You can use that fact for your solution. In the case of a normal function the delay is not necessary and the decorator should take action immediately. That is why I wand to differentiate these two cases.

    Read the article

  • Connect to a DB with an encrypted password with Django?

    - by Liam
    My place of employment requires that all passwords must be encrypted, including the ones used to connect to a database. What's the best way of handling this? I'm using the development version of Django with MySQL at the moment, but I will be eventually migrating to Oracle. Is this a job for Django, or the database? Edit: The encrypted password should be stored in the settings.py file, or somewhere else in the filesystem. This is the password that will be used to connect to the database.

    Read the article

  • muti user dungeon help

    - by mudman
    ive created a single user dungeon which i would like to create into a multi user dungoen so at least two plays can play how would i do that what code do i need to add can anyone help? i would show coding but if i do then everyone would see it and all my work will be copied as i know other students do use this site to so plz understand my situation and yes this is a homework/assignment work.

    Read the article

  • rearranging a list of months

    - by MacUsers
    How can I list the numbers 01 to 12 (one for each of the 12 months) in such a way so that the current month always comes last where the oldest one is first. In other words, if the number is grater than the current month, it's from the previous year. e.g. 02 is Feb, 2011 (the current month right now), 03 is March, 2010 and 09 is Sep, 2010 but 01 is Jan, 2011. In this case, I'd like to have [09, 03, 01, 02]. This is what I'm doing to determine the year: for inFile in os.listdir('.'): if inFile.isdigit(): month = months[int(inFile)] if int(inFile) <= int(strftime("%m")): year = strftime("%Y") else: year = int(strftime("%Y"))-1 mnYear = month + ", " + str(year) I don't have a clue what to do next. What should I do here?

    Read the article

  • Updating a module level shared dictionary

    - by Vishal
    Hi, A module level dictionary 'd' and is accessed by different threads/requests in a django web application. I need to update 'd' every minute with a new data and the process takes about 5 seconds. What could be best solution where I want the users to get either the old value or the new value of d and nothing in between. I can think of a solution where a temp dictionary is constructed with a new data and assigned to 'd' but not sure how this works! Appreciate your ideas. Thanks

    Read the article

  • Get parent function

    - by Morgoth
    Is there a way to find what function called the current function? So for example: def first(): second() def second(): # print out here what function called this one Any ideas?

    Read the article

  • How to parse json data in jquery ajax success?

    - by samarh.k
    info = {'phone_number': '123456', 'personal_detail': {'foo':foo, 'bar':bar}, 'is_active': 1, 'document_detail': {'baz':baz, 'saz':saz}, 'is_admin': 1, 'email': '[email protected]'} return HttpResponse(simplejson.dumps({'success':'True', 'result':info}), mimetype='application/javascript') if(data["success"] === "True") { alert(data[**here I want to display personal_detail and document_details**]); } How can I do this?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 401 402 403 404 405 406 407 408 409 410 411 412  | Next Page >