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  • matplotlib.pyplot, preserve aspect ratio of the plot

    - by Headcrab
    Assuming we have a polygon coordinates as polygon = [(x1, y1), (x2, y2), ...], the following code displays the polygon: import matplotlib.pyplot as plt plt.fill(*zip(*polygon)) plt.show() By default it is trying to adjust the aspect ratio so that the polygon (or whatever other diagram) fits inside the window, and automatically changing it so that it fits even after resizing. Which is great in many cases, except when you are trying to estimate visually if the image is distorted. How to fix the aspect ratio to be strictly 1:1? (Not sure if "aspect ratio" is the right term here, so in case it is not - I need both X and Y axes to have 1:1 scale, so that (0, 1) on both X and Y takes an exact same amount of screen space. And I need to keep it 1:1 no matter how I resize the window.)

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  • [Django] How to find out whether a model's column is a foreign key?

    - by codethief
    I'm dynamically storing information in the database depending on the request: // table, id and column are provided by the request table_obj = getattr(models, table) record = table_obj.objects.get(pk=id) setattr(record, column, request.POST['value']) The problem is that request.POST['value'] sometimes contains a foreign record's primary key (i.e. an integer) whereas Django expects the column's value to be an object of type ForeignModel: Cannot assign "u'122'": "ModelA.b" must be a "ModelB" instance. Now, is there an elegant way to dynamically check whether b is a column containing foreign keys and what model these keys are linked to? (So that I can load the foreign record by it's primary key and assign it to ModelA?) Or doesn't Django provide information like this to the programmer so I really have to get my hands dirty and use isinstance() on the foreign-key column?

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  • What is the Simplest Possible Payment Gateway to Implement? (using Django)

    - by b14ck
    I'm developing a web application that will require users to either make one time deposits of money into their account, or allow users to sign up for recurring billing each month for a certain amount of money. I've been looking at various payment gateways, but most (if not all) of them seem complex and difficult to get working. I also see no real active Django projects which offer simple views for making payments. Ideally, I'd like to use something like Amazon FPS, so that I can see online transaction logs, refund money, etc., but I'm open to other things. I just want the EASIEST possible payment gateway to integrate with my site. I'm not looking for anything fancy, whatever does the job, and requires < 10 hours to get working from start to finish would be perfect. I'll give answer points to whoever can point out a good one. Thanks!

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  • Error handling in the RequestHandler without embedding in URI

    - by hyn
    When a user sends a filled form, I want to print an error message in case there is an input error. One of the GAE sample codes does this by embedding the error message in the URI. Inside the form handler (get): self.redirect('/compose?error_message=%s' % message) and in the handler (get) of redirected URI, gets the message from request: values = { 'error_message': self.request.get('error_message'), ... Is there a way to accomplish the same without embedding the message in the URI?

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  • Sqlalchemy complex in_ clause

    - by lostlogic
    I'm trying to find a way to cause sqlalchemy to generate sql of the following form: select * from t where (a,b) in ((a1,b1),(a2,b2)); Is this possible? If not, any suggestions on a way to emulate it? Thanks kindly!

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  • Locating file path from a <InMemoryUploadedFile> Djnago object

    - by PirosB3
    Hi all I have a Django app which, submitting a package, should return values that are inside it.. Submitted the form to a view called "insert": request.FILES['file'] returns the file objects, but it is of kind < InMemoryUploadedFile. What i need is a way to get the absolute path of the uploaded file, so that i can feed it to a method that will return the values needed Anyone know how i can accomplish this? Thanks

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  • how to fill a part of a circle using PIL?

    - by valya
    hello. I'm trying to use PIL for a task but the result is very dirty. What I'm doing is trying to fill a part of a piece of a circle, as you can see on the image. Here is my code: def gen_image(values): side = 568 margin = 47 image = Image.open(settings.MEDIA_ROOT + "/i/promo_circle.jpg") draw = ImageDraw.Draw(image) draw.ellipse((margin, margin, side-margin, side-margin), outline="white") center = side/2 r = side/2 - margin cnt = len(values) for n in xrange(cnt): angle = n*(360.0/cnt) - 90 next_angle = (n+1)*(360.0/cnt) - 90 nr = (r * values[n] / 5) max_r = r min_r = nr for cr in xrange(min_r*10, max_r*10): cr = cr/10.0 draw.arc((side/2-cr, side/2-cr, side/2+cr, side/2+cr), angle, next_angle, fill="white") return image

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  • Algorithm to match natural text in mail

    - by snøreven
    I need to separate natural, coherent text/sentences in emails from lists, signatures, greetings and so on before further processing. example: Hi tom, last monday we did bla bla, lore Lorem ipsum dolor sit amet, consectetur adipisici elit, sed eiusmod tempor incidunt ut labore et dolore magna aliqua. list item 2 list item 3 list item 3 Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquid x ea commodi consequat. Quis aute iure reprehenderit in voluptate velit regards, K. ---line-of-funny-characters-####### example inc. 33 evil street, london mobile: 00 234534/234345 Ideally the algorithm would match only the bold parts. Is there any recommended approach - or are there even existing algorithms for that problem? Should I try approximate regular expressions or more statistical stuff based on number of punctation marks, length and so on?

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  • SQLAlchemy declarative syntax with autoload in Pylons

    - by Juliusz Gonera
    I would like to use autoload to use an existings database. I know how to do it without declarative syntax (model/_init_.py): def init_model(engine): """Call me before using any of the tables or classes in the model""" t_events = Table('events', Base.metadata, schema='events', autoload=True, autoload_with=engine) orm.mapper(Event, t_events) Session.configure(bind=engine) class Event(object): pass This works fine, but I would like to use declarative syntax: class Event(Base): __tablename__ = 'events' __table_args__ = {'schema': 'events', 'autoload': True} Unfortunately, this way I get: sqlalchemy.exc.UnboundExecutionError: No engine is bound to this Table's MetaData. Pass an engine to the Table via autoload_with=<someengine>, or associate the MetaData with an engine via metadata.bind=<someengine> The problem here is that I don't know where to get the engine from (to use it in autoload_with) at the stage of importing the model (it's available in init_model()). I tried adding meta.Base.metadata.bind(engine) to environment.py but it doesn't work. Anyone has found some elegant solution?

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  • PyParsing: Not all tokens passed to setParseAction()

    - by Rosarch
    I'm parsing sentences like "CS 2110 or INFO 3300". I would like to output a format like: [[("CS" 2110)], [("INFO", 3300)]] To do this, I thought I could use setParseAction(). However, the print statements in statementParse() suggest that only the last tokens are actually passed: >>> statement.parseString("CS 2110 or INFO 3300") Match [{Suppress:("or") Re:('[A-Z]{2,}') Re:('[0-9]{4}')}] at loc 7(1,8) string CS 2110 or INFO 3300 loc: 7 tokens: ['INFO', 3300] Matched [{Suppress:("or") Re:('[A-Z]{2,}') Re:('[0-9]{4}')}] -> ['INFO', 3300] (['CS', 2110, 'INFO', 3300], {'Course': [(2110, 1), (3300, 3)], 'DeptCode': [('CS', 0), ('INFO', 2)]}) I expected all the tokens to be passed, but it's only ['INFO', 3300]. Am I doing something wrong? Or is there another way that I can produce the desired output? Here is the pyparsing code: from pyparsing import * def statementParse(str, location, tokens): print "string %s" % str print "loc: %s " % location print "tokens: %s" % tokens DEPT_CODE = Regex(r'[A-Z]{2,}').setResultsName("DeptCode") COURSE_NUMBER = Regex(r'[0-9]{4}').setResultsName("CourseNumber") OR_CONJ = Suppress("or") COURSE_NUMBER.setParseAction(lambda s, l, toks : int(toks[0])) course = DEPT_CODE + COURSE_NUMBER.setResultsName("Course") statement = course + Optional(OR_CONJ + course).setParseAction(statementParse).setDebug()

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  • mod_wsgi daemon mode vs threaded fastcgi

    - by t0ster
    Can someone explain the difference between apache mod_wsgi in daemon mode and django fastcgi in threaded mode. They both use threads for concurrency I think. Supposing that I'm using nginx as front end to apache mod_wsgi. UPDATE: I'm comparing django built in fastcgi(./manage.py method=threaded maxchildren=15) and mod_wsgi in 'daemon' mode(WSGIDaemonProcess example threads=15). They both use threads and acquire GIL, am I right?

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  • Accented characters in matplotlib

    - by OldJim
    Does anyone know a way to get matplotlib to render accented chars (é,ã,â,etc)? For instance i'm trying to use accented chars on set_yticklabels() and matplot renders squares instead, and when i use unicode() it renders the wrong chars. Is there a way to make this work? Thanks in advance, Jim.

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  • How to make Universal Feed Parser only parse feeds?

    - by piquadrat
    I'm trying to get content from external feeds on my Django web site with Universal Feed Parser. I want to have some user error handling, e.g. if the user supplies a URL that is not a feed. When I tried how feedparser responds to faulty input, I was surprised to see that feedparser does not throw any Exceptions at all. E.g. on HTML content, it tries to parse some information from the HTML code, and on non-existing domains, it returns a mostly empty dictionary: {'bozo': 1, 'bozo_exception': URLError(gaierror(-2, 'Name or service not known'),), 'encoding': 'utf-8', 'entries': [], 'feed': {}, 'version': None} Other faulty input manifest themselves in the status_code or the namespaces values in the returned dictionary. So, what's the best approach to have sane error checking without resorting to an endless cascade of if .. elif .. elif ...?

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  • Scrape zipcode table for different urls based on county

    - by Dr.Venkman
    I used lxml and ran into a wall as my new computer wont install lxml and the code doesnt work. I know this is simple - maybe some one can help with a beautiful soup script. this is my code: import codecs import lxml as lh from selenium import webdriver import time import re results = [] city = [ 'amador'] state = [ 'CA'] for state in states: for city in citys: browser = webdriver.Firefox() link2 = 'http://www.getzips.com/cgi-bin/ziplook.exe?What=3&County='+ city +'&State=' + state + '&Submit=Look+It+Up' browser.get(link2) bcontent = browser.page_source zipcode = bcontent[bcontent.find('<td width="15%"'):bcontent.find('<p>')+0] if len(zipcode) > 0: print zipcode else: print 'none' browser.quit() Thanks for the help

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  • Getting unpredictable data into a tabular format

    - by Acorn
    The situation: Each page I scrape has <input> elements with a title= and a value= I don't know what is going to be on the page. I want to have all my collected data in a single table at the end, with a column for each title. So basically, I need each row of data to line up with all the others, and if a row doesn't have a certain element, then it should be blank (but there must be something there to keep the alignment). eg. First page has: {animal: cat, colour: blue, fruit: lemon, day: monday} Second page has: {animal: fish, colour: green, day: saturday} Third page has: {animal: dog, number: 10, colour: yellow, fruit: mango, day: tuesday} Then my resulting table should be: animal | number | colour | fruit | day cat | none | blue | lemon | monday fish | none | green | none | saturday dog | 10 | yellow | mango | tuesday Although it would be good to keep the order of the title value pairs, which I know dictionaries wont do. So basically, I need to generate columns from all the titles (kept in order but somehow merged together) What would be the best way of going about this without knowing all the possible titles and explicitly specifying an order for the values to be put in?

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  • Performing non-blocking requests? - Django

    - by RadiantHex
    Hi folks, I have been playing with other frameworks, such as NodeJS, lately. I love the possibility to return a response, and still being able to do further operations. e.g. def view(request): do_something() return HttpResponse() do_more_stuff() #not possible!!! Maybe Django already offers a way to perform operations after returning a request, if that is the case that would be great. Help would be very much appreciated! =D

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  • Search for a String and replace it with a variable

    - by chrissygormley
    Hello, I am trying to use regular expression to search a document fo a UUID number and replace the end of it with a new number. The code I have so far is: read_file = open('test.txt', 'r+') write_file = open('test.txt', 'w') r = re.compile(r'(self.uid\s*=\s*5EFF837F-EFC2-4c32-A3D4\s*)(\S+)') for l in read_file: m1 = r.match(l) if m1: new=(str,m1.group(2)) new?????? This where I get stuck. The file test.txt has the below UUID stored in it: self.uid = '5EFF837F-EFC2-4c32-A3D4-D15C7F9E1F22' I want to replace the part D15C7F9E1F22. I have also tried this: r = re.compile(r'(self.uid\s*=\s*)(\S+)') for l in fp: m1 = r.match(l) new=map(int,m1.group(2).split("-") new[4]='RHUI5345JO' But I cannot seem to match the string. Thanks in advance for any help.

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  • socket.accept error 24: To many open files

    - by Creotiv
    I have a problem with open files under my Ubuntu 9.10 when running server in Python2.6 And main problem is that, that i don't know why it so.. I have set ulimit -n = 999999 net.core.somaxconn = 999999 fs.file-max = 999999 and lsof gives me about 12000 open files when server is running. And also i'm using epoll. But after some time it's start giving exeption: File "/usr/lib/python2.6/socket.py", line 195, in accept error: [Errno 24] Too many open files And i don't know how it can reach file limit when it isn't reached. Thanks for help)

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  • What could cause Django to start failing its own tests after an OS and Django reinstall?

    - by Macha
    I had to reinstall my OS, and so, I reinstalled django 1.1. Since reinstalling, when I run tests in my app, I get several failures from django.contrib.auth. Logs: http://dpaste.com/178153/ I asked on #django, and no one is too sure what the cause of the errors are. Some of my own code fails its tests, because it's not fully written yet, but that shouldn't cause django to fail it's core tests... I have included django.contrib.admin, which was mentioned as a possible cause.

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  • how to speed up the code??

    - by kaushik
    in my program i have a method which requires about 4 files to be open each time it is called,as i require to take some data.all this data from the file i have been storing in list for manupalation. I approximatily need to call this method about 10,000 times.which is making my program very slow? any method for handling this files in a better ways and is storing the whole data in list time consuming what is better alternatives for list? I can give some code,but my previous question was closed as that only confused everyone as it is a part of big program and need to be explained completely to understand,so i am not giving any code,please suggest ways thinking this as a general question... thanks in advance

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  • how to speed up the code??

    - by kaushik
    i have very huge code about 600 lines plus. cant post the whole thing here. but a particular code snippet is taking so much time,leading to problems. here i post that part of code please tell me what to do speed up the processing.. please suggest the part which may be the reason and measure to improve them if this small part of code is understandable. using_data={} def join_cost(a , b): global using_data #print a #print b save_a=[] save_b=[] print 1 #for i in range(len(m)): #if str(m[i][0])==str(a): save_a=database_index[a] #for i in range(len(m)): # if str(m[i][0])==str(b): #print 'save_a',save_a #print 'save_b',save_b print 2 save_b=database_index[b] using_data[save_a[0]]=save_a s=str(save_a[1]).replace('phone','text') s=str(s)+'.pm' p=os.path.join("c:/begpython/wavnk/",s) x=open(p , 'r') print 3 for i in range(6): x.readline() k2='a' j=0 o=[] while k2 is not '': k2=x.readline() k2=k2.rstrip('\n') oj=k2.split(' ') o=o+[oj] #print o[j] j=j+1 #print j #print o[2][0] temp=long(1232332) end_time=save_a[4] #print end_time k=(j-1) for i in range(k): diff=float(o[i][0])-float(end_time) if diff<0: diff=diff*(-1) if temp>diff: temp=diff pm_row=i #print pm_row #print temp #print o[pm_row] #pm_row=3 q=[] print 4 l=str(p).replace('.pm','.mcep') z=open(l ,'r') for i in range(pm_row): z.readline() k3=z.readline() k3=k3.rstrip('\n') q=k3.split(' ') #print q print 5 s=str(save_b[1]).replace('phone','text') s=str(s)+'.pm' p=os.path.join("c:/begpython/wavnk/",s) x=open(p , 'r') for i in range(6): x.readline() k2='a' j=0 o=[] while k2 is not '': k2=x.readline() k2=k2.rstrip('\n') oj=k2.split(' ') o=o+[oj] #print o[j] j=j+1 #print j #print o[2][0] temp=long(1232332) strt_time=save_b[3] #print strt_time k=(j-1) for i in range(k): diff=float(o[i][0])-float(strt_time) if diff<0: diff=diff*(-1) if temp>diff: temp=diff pm_row=i #print pm_row #print temp #print o[pm_row] #pm_row=3 w=[] l=str(p).replace('.pm','.mcep') z=open(l ,'r') for i in range(pm_row): z.readline() k3=z.readline() k3=k3.rstrip('\n') w=k3.split(' ') #print w cost=0 for i in range(12): #print q[i] #print w[i] h=float(q[i])-float(w[i]) cost=cost+math.pow(h,2) j_cost=math.sqrt(cost) #print cost return j_cost def target_cost(a , b): a=(b+1)*3 b=(a+1)*2 t_cost=(a+b)*5/2 return t_cost r1='shht:ra_77' r2='grx_18' g=[] nodes=[] nodes=nodes+[[r1]] for i in range(len(y_in_db_format)): g=y_in_db_format[i] #print g #print g[0] g.remove(str(g[0])) nodes=nodes+[g] nodes=nodes+[[r2]] print nodes print "lenght of nodes",len(nodes) lists=[] #lists=lists+[r1] for i in range(len(nodes)): for j in range(len(nodes[i])): lists=lists+[nodes[i][j]] #lists=lists+[r2] print lists distance={} for i in range(len(lists)): if i==0: distance[str(lists[i])]=0 else: distance[str(lists[i])]=long(123231223) #print distance group_dist=[] infinity=long(123232323) for i in range(len(nodes)): distances=[] for j in range(len(nodes[i])): #distances=[] if i==0: distances=distances+[[nodes[i][j], 0]] else: distances=distances+[[nodes[i][j],infinity]] group_dist=group_dist+[distances] #print distances print "group_distances",group_dist #print "check",group_dist[0][0][1] #costs={} #for i in range(len(lists)): #if i==0: # costs[str(lists[i])]=1 #else: # costs[str(lists[i])]=get_selfcost(lists[i]) path=[] for i in range(len(nodes)): mini=[] if i!=(len(nodes)-1): #temp=long(123234324) #Now calculate the cost between the current node and each of its neighbour for k in range(len(nodes[(i+1)])): for j in range(len(nodes[i])): current=nodes[i][j] #print "current_node",current j_distance=join_cost( current , nodes[i+1][k]) #t_distance=target_cost( current , nodes[i+1][k]) t_distance=34 #print distance #print "distance between current and neighbours",distance total_distance=(.5*(float(group_dist[i][j][1])+float(j_distance))+.5*(float(t_distance))) #print "total distance between the intial_nodes and current neighbour",total_distance if int(group_dist[i+1][k][1]) > int(total_distance): group_dist[i+1][k][1]=total_distance #print "updated distance",group_dist[i+1][k][1] a=current #print "the neighbour",nodes[i+1][k],"updated the value",a mini=mini+[[str(nodes[i+1][k]),a]] print mini

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