Search Results

Search found 16680 results on 668 pages for 'python datetime'.

Page 404/668 | < Previous Page | 400 401 402 403 404 405 406 407 408 409 410 411  | Next Page >

  • problem with pasting image over lines in wx DC

    - by Moayyad Yaghi
    hello .. i have the same code as wx Doodle pad in the wx demos i added a tool to paste images from the clipboard to the pad. using wx.DrawBitmap() function , but whenever i refresh the buffer .and call funtions ( drawSavedLines and drawSavedBitmap) it keeps putting bitmap above line no matter what i did even if i called draw bitmap first and then draw lines . is there anyway to put a line above the bitmap ? please inform me if i miss anything thanx in advance

    Read the article

  • redefine __and__ operator

    - by wiso
    Why I can't redefine the __and__ operator? class Cut(object): def __init__(self, cut): self.cut = cut def __and__(self, other): return Cut("(" + self.cut + ") && (" + other.cut + ")") a = Cut("a>0") b = cut("b>0") c = a and b print c.cut() I want (a>0) && (b>0), but I got b, that the usual behaviour of and

    Read the article

  • Raising events and object persistence in Django

    - by Mridang Agarwalla
    Hi, I have a tricky Django problem which didn't occur to me when I was developing it. My Django application allows a user to sign up and store his login credentials for a sites. The Django application basically allows the user to search this other site (by scraping content off it) and returns the result to the user. For each query, it does a couple of queries of the other site. This seemed to work fine but sometimes, the other site slaps me with a CAPTCHA. I've written the code to get the CAPTCHA image and I need to return this to the user so he can type it in but I don't know how. My search request (the query, the username and the password) in my Django application gets passed to a view which in turn calls the backend that does the scraping/search. When a CAPTCHA is detected, I'd like to raise a client side event or something on those lines and display the CAPTCHA to the user and wait for the user's input so that I can resume my search. I would somehow need to persist my backend object between calls. I've tried pickling it but it doesn't work because I get the Can't pickle 'lock' object error. I don't know to implement this though. Any help/ideas? Thanks a ton.

    Read the article

  • Url open encoding

    - by badc0re
    I have the following code for urllib and BeautifulSoup: getSite = urllib.urlopen(pageName) # open current site getSitesoup = BeautifulSoup(getSite.read()) # reading the site content print getSitesoup.originalEncoding for value in getSitesoup.find_all('link'): # extract all <a> tags defLinks.append(value.get('href')) The result of it: /usr/lib/python2.6/site-packages/bs4/dammit.py:231: UnicodeWarning: Some characters could not be decoded, and were replaced with REPLACEMENT CHARACTER. "Some characters could not be decoded, and were " And when i try to read the site i get: ?7?e????0*"I??G?H????F??????9-??????;??E?YÞBs????????????4i???)?????^W?????`w?Ke??%??*9?.'OQB???V??@?????]???(P??^??q?$?S5???tT*?Z

    Read the article

  • Prepopulate drop-box according to another drop-box choice in Django Admin

    - by onorua
    I have models like this: class User(models.Model): Switch = models.ForeignKey(Switch, related_name='SwitchUsers') Port = models.ForeignKey(Port) class Switch(models.Model): Name = models.CharField(max_length=50) class Port(models.Model): PortNum = models.PositiveIntegerField() Switch = models.ForeignKey(Switch, related_name = "Ports") When I'm in Admin interface and choose Switch from Switches available, I would like to have Port prepopulated accordingly with Ports from the related Switch. As far as I understand I need to create some JS script to prepopulate it. Unfortunately I don't have this experience, and I would like to keep things simple as it possible and don't rewrite all Django admin interface. Just add this functionality for one Field. Could you please help me with my problem? Thank you.

    Read the article

  • How can I draw a log-normalized imshow plot with a colorbar representing the raw data in matplotlib

    - by Adam Fraser
    I'm using matplotlib to plot log-normalized images but I would like the original raw image data to be represented in the colorbar rather than the [0-1] interval. I get the feeling there's a more matplotlib'y way of doing this by using some sort of normalization object and not transforming the data beforehand... in any case, there could be negative values in the raw image. import matplotlib.pyplot as plt import numpy as np def log_transform(im): '''returns log(image) scaled to the interval [0,1]''' try: (min, max) = (im[im > 0].min(), im.max()) if (max > min) and (max > 0): return (np.log(im.clip(min, max)) - np.log(min)) / (np.log(max) - np.log(min)) except: pass return im a = np.ones((100,100)) for i in range(100): a[i] = i f = plt.figure() ax = f.add_subplot(111) res = ax.imshow(log_transform(a)) # the colorbar drawn shows [0-1], but I want to see [0-99] cb = f.colorbar(res) I've tried using cb.set_array, but that didn't appear to do anything, and cb.set_clim, but that rescales the colors completely. Thanks in advance for any help :)

    Read the article

  • twisted reactor stops too early

    - by pygabriel
    I'm doing a batch script to connect to a tcp server and then exiting. My problem is that I can't stop the reactor, for example: cmd = raw_input("Command: ") # custom factory, the protocol just send a line reactor.connectTCP(HOST,PORT, CommandClientFactory(cmd) d = defer.Deferred() d.addCallback(lambda x: reactor.stop()) reactor.callWhenRunning(d.callback,None) reactor.run() In this code the reactor stops before that the tcp connection is done and the cmd is passed. How can I stop the reactor after that all the operation are finished?

    Read the article

  • How to build a Django form which requires a delay to be re-submitted ?

    - by pierre-guillaume-degans
    Hey, In order to avoid spamming, I would like to add a waiting time to re-submit a form (i.e. the user should wait a few seconds to submit the form, except the first time that this form is submitted). To do that, I added a timestamp to my form (and a security_hash field containing the timestamp plus the settings.SECRET_KEY which ensures that the timestamp is not fiddled with). This look like: class MyForm(forms.Form): timestamp = forms.IntegerField(widget=forms.HiddenInput) security_hash = forms.CharField(min_length=40, max_length=40, widget=forms.HiddenInput) # + some other fields.. # + methods to build the hash and to clean the timestamp... # (it is based on django.contrib.comments.forms.CommentSecurityForm) def clean_timestamp(self): """Make sure the delay is over (5 seconds).""" ts = self.cleaned_data["timestamp"] if not time.time() - ts > 5: raise forms.ValidationError("Timestamp check failed") return ts # etc... This works fine. However there is still an issue: the timestamp is checked the first time the form is submitted by the user, and I need to avoid this. Any idea to fix it ? Thank you ! :-)

    Read the article

  • csrf error in django

    - by niklasfi
    Hello, I want to realize a login for my site. I basically copied and pasted the following bits from the Django Book together. However I still get an error (CSRF verification failed. Request aborted.), when submitting my registration form. Can somebody tell my what raised this error and how to fix it? Here is my code: views.py: # Create your views here. from django import forms from django.contrib.auth.forms import UserCreationForm from django.http import HttpResponseRedirect from django.shortcuts import render_to_response def register(request): if request.method == 'POST': form = UserCreationForm(request.POST) if form.is_valid(): new_user = form.save() return HttpResponseRedirect("/books/") else: form = UserCreationForm() return render_to_response("registration/register.html", { 'form': form, }) register.html: <html> <body> {% block title %}Create an account{% endblock %} {% block content %} <h1>Create an account</h1> <form action="" method="post">{% csrf_token %} {{ form.as_p }} <input type="submit" value="Create the account"> </form> {% endblock %} </body> </html>

    Read the article

  • Removing specific ticks from matplotlib plot

    - by Jsg91
    I'm trying to remove the origin ticks from my plot below to stop them overlapping, alternatively just moving them away from each other would also be great I tried this: xticks = ax.xaxis.get_major_ticks() xticks[0].label1.set_visible(False) yticks = ax.yaxis.get_major_ticks() yticks[0].label1.set_visible(False) However this removed the first and last ticks from the y axis like so: Does anyone have an idea about how to do this? Any help would be greatly appreciated.

    Read the article

  • How to reset Scrapy parameters? (always running under same parameters)

    - by Jean Ventura
    I've been running my Scrapy project with a couple of accounts (the project scrapes a especific site that requieres login credentials), but no matter the parameters I set, it always runs with the same ones (same credentials). I'm running under virtualenv. Is there a variable or setting I'm missing? Edit: It seems that this problem is Twisted related. Even when I run: scrapy crawl -a user='user' -a password='pass' -o items.json -t json SpiderName I still get an error saying: ERROR: twisted.internet.error.ReactorNotRestartable And all the information I get, is the last 'succesful' run of the spider.

    Read the article

  • Django says the "id may not be NULL" but why is it?

    - by Oli
    I'm going crazy today. I just tried to insert a new record and it threw back a "post_blogpost.id may not be NULL" error. Here's my model: class BlogPost(models.Model): title = models.CharField(max_length=100) slug = models.SlugField(max_length=100) who = models.ForeignKey(User, default=1) when = models.DateTimeField() intro = models.TextField(blank=True, null=True) content = models.TextField(blank=True, null=True) counter = models.PositiveIntegerField(default=0) published = models.BooleanField(default=False) css = models.TextField(blank=True, null=True) class Meta: ordering = ('-when', 'id') There are a number of functions beneath the model too but I won't include them in full here. Their names are: content_cache_key, clear_cache, __unicode__, reads, read, processed_content. I'm adding through the admin... And I'm running out of hair.

    Read the article

  • Tkinter Packing Strangeness: Buttons packed above others

    - by Parand
    I'm sure I'm doing something obvious wrong here, but I can't see it. I end up with the "Should be on top" label packed at the bottom instead of at the top. What am I doing wrong? from Tkinter import * class SelectAction(Frame): buttons = {} def callback(self): print "Callback" def createWidgets(self): logo_label = Label(text="Should be on top").pack(fill=X) for name, text, callback in ( ('setup_account', 'Account Settings', self.callback), ('do_action', 'Do Something', self.callback), ): self.buttons[name] = Button(self, text=text, command=callback).pack(fill=X) def __init__(self, master=None): Frame.__init__(self, master) self.pack() self.createWidgets() if __name__ == "__main__": root = Tk() app = SelectAction(master=root) app.mainloop() root.destroy()

    Read the article

  • In Django, why is user.is_authenticated a method and not a member variable like is_staff

    - by luc
    Hello all, I've lost some time with a bug in my app due to user authentication. I think that it's a bit confusing but maybe someone can explain the reason and it will appear to me very logical. The user.is_staff is a member variable while user.is_authenticated is a method. However is_authenticated only returns True or False depending if the class is User or AnonymousUser (see http://docs.djangoproject.com/en/dev/topics/auth/) Is there a reason for that? Why user.is_authenticated is a method? Thanks in advance

    Read the article

  • Simple pygtk and threads example please.

    - by wtzolt
    Hello, Can someone give me a simple example involving threads in this manner, please. Problem with my code is that when I click button One, GUI freezes until its finished. I want buttons to stay responsive when def is being executed. How can i fix that? class fun: wTree = None def __init__( self ): self.wTree = gtk.glade.XML( "ui.glade" ) dic = { "on_buttonOne" : self.one, "on_buttonTwo" : self.two, } self.wTree.signal_autoconnect( dic ) gtk.main() def sone(self, widget): time.sleep(1) print "1" time.sleep(1) print "2" time.sleep(1) print "3" def stwo(self, widget): time.sleep(1) print "4" time.sleep(1) print "5" time.sleep(1) print "6" do=fun() Pretty please, help me.

    Read the article

  • grabbing a substring while scraping with Python2.6

    - by Diego
    Hey can someone help with the following? I'm trying to scrape a site that has the following information.. I need to pull just the number after the </strong> tag.. [<li><strong>ISBN-13:</strong> 9780375853401</li>, <li><strong>Pub. Date: </strong> 05/11/2010</li>] [<li><strong>UPC:</strong> 490355000372</li>, <li><strong>Catalog No:</strong> 15024/25</li>, <li><strong>Label:</strong> CAMERATA</li>] here's a piece of the code I've been using to grab the above data using mechanize and BeautifulSoup. I'm stuck here as it won't let me use the find() function for a list br_results = mechanize.urlopen(br_results) html = br_results.read() soup = BeautifulSoup(html) local_links = soup.findAll("a", {"class" : "down-arrow csa"}) upc_code = soup.findAll("ul", {"class" : "bc-meta3"}) for upc in upc_code: upc_text = upc.contents.contents print upc_text

    Read the article

  • Preserving the dimensions of a slice from a Numpy 3d array

    - by Brendan
    I have a 3d array, a, of shape say a.shape = (10, 10, 10) When slicing, the dimensions are squeezed automatically i.e. a[:,:,5].shape = (10, 10) I'd like to preserve the number of dimensions but also ensure that the dimension that was squeezed is the one that shows 1 i.e. a[:,:,5].shape = (10, 10, 1) I have thought of re-casting the array and passing ndmin but that just adds the extra dimensions to the start of the shape tuple regardless of where the slice came from in the array a.

    Read the article

  • split twice in the same expression?

    - by UcanDoIt
    Imagine I have the following: inFile = "/adda/adas/sdas/hello.txt" # that instruction give me hello.txt Name = inFile.name.split("/") [-1] # that one give me the name I want - just hello Name1 = Name.split(".") [0] Is there any chance to simplify that doing the same job in just one expression?

    Read the article

  • Filter zipcodes by proximity in Django with the Spherical Law of Cosines

    - by spiffytech
    I'm trying to handle proximity search for a basic store locater in Django. Rather than haul PostGIS around with my app just so I can use GeoDjango's distance filter, I'd like to use the Spherical Law of Cosines distance formula in a model query. I'd like all of the calculations to be done in the database in one query, for efficiency. An example MySQL query from The Internet implementing the Spherical Law of Cosines like this: SELECT id, ( 3959 * acos( cos( radians(37) ) * cos( radians( lat ) ) * cos( radians( lng ) - radians(-122) ) + sin( radians(37) ) * sin( radians( lat ) ) ) ) AS distance FROM stores HAVING distance < 25 ORDER BY distance LIMIT 0 , 20; The query needs to reference the Zipcode ForeignKey for each store's lat/lng values. How can I make all of this work in a Django model query?

    Read the article

< Previous Page | 400 401 402 403 404 405 406 407 408 409 410 411  | Next Page >