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  • mysql_fetch_row() not a valid result resource

    - by user1717305
    I am confused, I don't know what's wrong. I'm about to transfer all data from my first table to the other. Here is my code: $getdata = mysql_query("SELECT Quantity, Description, Total FROM ordercart"); while($row = mysql_fetch_row($getdata)) { foreach($row as $cell){ $query1 = mysql_query("INSERT INTO ordermem (Quantity, Description, Total) VALUES ($cell)",$connect); } mysql_free_result($getdata); } I get the error: Warning: mysql_fetch_row(): 5 is not a valid MySQL result resource.

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  • Best way to use If() statement in My-Sql Query

    - by PHP-Prabhu
    Can any one please let me know the best way to use IF statement in mysql query to show if the "email" field is NULL then it should show as "no email"... Postcode Telephone Email ---------------------------------------------------------- BS20 0QN 1275373088 no email BS20 0QN 1275373088 no email PO9 4HG 023 92474208 [email protected] SO43 7DS 07801 715200 [email protected] ----------------------------------------------------------

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  • difference between cn.execute and rs.update?

    - by every_answer_gets_a_point
    i am connecting to mysql from excel using odbc. the following illustrates how i am updating the rs With rs .AddNew ' create a new record ' add values to each field in the record .Fields("datapath") = dpath .Fields("analysistime") = atime .Fields("reporttime") = rtime .Fields("lastcalib") = lcalib .Fields("analystname") = aname .Fields("reportname") = rname .Fields("batchstate") = "bstate" .Fields("instrument") = "NA" .Update ' stores the new record End With the question is why is there a need to run cn.execute after this? havent i already updated the rs with rs.update?

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  • manage user permissions in php

    - by user420528
    i am creating a marks management system using php & mysqlwhere the concerned faculty will be able to login and enter the marks of the students. i can go with a simple table but the problem is there are 288 different subjects for which marks must be entered. So creating a mysql table with so many subjects does not look good for me. please suggest me the best way to manage user permissions so that only the corresponding faculty will be able to enter marks

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  • Duplicate information from sql result

    - by puddleJumper
    I looked in about 18 other posts on here an most people are asking how to delete the records not just hide them. So my problem: I have a database with staff members who are associated with locations. Many of the staff members are associated with more than one location. What I want to do is to only display the first location listed in the mysql result and skip over the others. I have the sql query linking the tables together and it works aside from it showing the same information for those staff members that are in those other locations multiple times so example would be like this: This is the sql statement I have currently SELECT staff_tbl.staffID, staff_tbl.firstName, staff_tbl.middleInitial, staff_tbl.lastName, location_tbl.locationID, location_tbl.staffID, officelocations_tbl.locationID, officelocations_tbl.officeName, staff_title_tbl.title_ID, staff_title_tbl.staff_ID, titles_tbl.titleID, titles_tbl.titleName FROM staff_tbl INNER JOIN location_tbl ON location_tbl.staffID = staff_tbl.staffID INNER JOIN officelocations_tbl ON location_tbl.locationID = officelocations_tbl.locationID INNER JOIN staff_title_tbl ON staff_title_tbl.staff_ID = staff_tbl.staffID INNER JOIN titles_tbl ON staff_title_tbl.title_ID = titles_tbl.titleID and my php is <?php do { ?> <tr> <td><?php echo $row_rs_Staff_Info['firstName']; ?>&nbsp; <?php echo $row_rs_Staff_Info['lastName']; ?></td> <td><?php echo $row_rs_Staff_Info['titleName']; ?>&nbsp; </td> <td><?php echo $row_rs_Staff_Info['officeName']; ?>&nbsp; </td> </tr> <?php } while ($row_mysqlResult = mysql_fetch_assoc($rs_mysqlResult)); ?> What I would like to know is there a way using php to select only the first entry listed for each person and display that and just skip over the other two. I was thinking it could be done by possibly adding the staffID's to an array and if they are in there to skip over the next one listed in the staff_title_tbl but wasn't quite sure how to write it that way. Any help would be great thank you in advance.

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  • Socket operation on non-socket

    - by embedded
    I'm running mysql5 on Mac os x 10.5.8 and got this error. How do I solve this? The DB worked fine but stopped working after system update. I think its something related to the socket file which is /tmp/mysql.sock do I need to give it special permissions and owner? Thanks

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  • Summarize Data with SQL statement

    - by bugbug
    I have CMS table that contain CMS_STARTTIME and CMS_STOPTIME (attachment). I want to create report to summarize exist data by using Date, Time and Year as Parameter (attachment). I don't know how to create sql statement to meet this requirement. I'm using MySQL and MS-SQL. Does one can help? Thank you very much.

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  • how to change a while sql query loop into an array loop

    - by Mac Taylor
    hey guys i record number of queries of my website and in page the below script runs , 40 extra queries added to page . how can I change this sql connection into a propper and light one function tree_set($index) { //global $menu; Remove this. $q=mysql_query("select id,name,parent from cats where parent='$index'"); if(mysql_num_rows($q) === 0) { return; } // User $tree instead of the $menu global as this way there shouldn't be any data duplication $tree = $index > 0 ? '<ul>' : ''; // If we are on index 0 then we don't need the enclosing ul while($arr=mysql_fetch_assoc($q)) { $subFileCount=mysql_query("select id,name,parent from cats where parent='{$arr['id']}'"); if(mysql_num_rows($subFileCount) > 0) { $class = 'folder'; } else { $class = 'file'; } $tree .= '<li>'; $tree .= '<span class="'.$class.'">'.$arr['name'].'</span>'; $tree .=tree_set("".$arr['id'].""); $tree .= '</li>'."\n"; } $tree .= $index > 0 ? '</ul>' : ''; // If we are on index 0 then we don't need the enclosing ul return $tree; } i heard , this can be done by changing it into an array , but i don't know how to do so thanks in advance

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  • how to organize country data?

    - by fayer
    how do i organize country data (countries, states and cities etc) in mysql? cause every country has 3 tables: countries, states and cities. should i have each country in separate set of tables or should i have them all in these 3 tables? if i have all of them in same tables, im afraid that the amount of rows will be huge cause i tend to have a lot of countries! what is best practice for this?

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  • How can I add dynamic text from a different table where primary key is a foreign key to adynamic table being shown?

    - by Jethro Tamares Doble
    I have here a dynamic table named tb_user with column region_id and institute_id and both ids are primary key of another table tb_region (with column region_name and region_id) and tb_institute (column institute_id and institute_name). I wanted to see region_name and institute_name instead of the ids. I've used this php script <?php echo $row_institute['institution_name']; ?> and query to collect data for tb_institute mysql_select_db($database_connection_ched, $connection_ched); $query_institution = "SELECT institute_id, institute_name FROM tb_institute"; $institution = mysql_query($query_institution, $connection_ched) or die(mysql_error()); $row_institution = mysql_fetch_assoc($institution); $totalRows_institution = mysql_num_rows($institution); but it seems not to display the correct name of id. query i used to collect data: mysql_select_db($database_connection_ched, $connection_ched); $query_notification = sprintf("SELECT * FROM tb_user WHERE status = 'inactive' ORDER BY date_register ASC", GetSQLValueString($colname_notification, "text")); $query_limit_notification = sprintf("%s LIMIT %d, %d", $query_notification, $startRow_notification, $maxRows_notification); $notification = mysql_query($query_limit_notification, $connection_ched) or die(mysql_error()); $row_notification = mysql_fetch_assoc($notification); if (isset($_GET['totalRows_notification'])) { $totalRows_notification = $_GET['totalRows_notification']; } else { $all_notification = mysql_query($query_notification); $totalRows_notification = mysql_num_rows($all_notification); } $totalPages_notification = ceil($totalRows_notification/$maxRows_notification)-1;

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  • Compare two table and find matching columns

    - by Karthick
    Hi, I have two tables table1 and table2, i need to write a select query which will list me the columns that exist in both the tables.(mysql) I need to do for different tables (2 at a time) Is this possible? I tried using INFORMATION_SCHEMA.COLUMNS but am not able to get it right.

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  • limiting a query to a specific item

    - by Dev-Ria
    I have a db with thousands of domains and data. I want to list only 100 rows of each domain. i can't use LIMIT 100 cause that only limits 100 records but I want dom1 to list 100 dom2 to list 100 dom3 to list 100 all in one query. This is what I have so far. SELECT domain COUNT(Key) AS DomCount FROM table_domain GROUP BY user,location ORDER BY domain,DomCount DESC Could I use a CASE?

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  • How to first get different related values from diferent SQL tables (PHP)

    - by Ole Jak
    I am triig to fill options list. I have 2 tables USERS and STREAMS I vant to get all streams and get names of users assigned to that streams. Users consists of username and id Streams consists of id, userID, streamID I try such code: <?php global $connection; $query = "SELECT * FROM streams "; $streams_set = mysql_query($query, $connection); confirm_query($streams_set); $streams_count = mysql_num_rows($streams_set); while ($row = mysql_fetch_array($streams_set)){ $userid = $row['userID']; global $connection; $query2 = "SELECT email, username "; $query2 .= "FROM users "; $query2 .= "WHERE id = '{$userid}' "; $qs = mysql_query($query2, $connection); confirm_query($qs); $found_user = mysql_fetch_array($qs); echo ' <option value="'.$row['streamID'].'">'.$row['userID'].$found_user.'</option> '; } ?> But it does not return USER names from DB=( So what shall I do to this code to see usernames as "options" text?

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  • Odd PHP Error Message

    - by John
    When I run some php code I've written, I get the following message: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'condition, price, name, email) VALUES('Fake Title', 'Fake Subhead', 'Fake Author' at line 1 I do not see anything wrong with my syntax, however, which is like: mysql_query("INSERT INTO table (x1, x2, x3) VALUES('$y1', '$y2', '$y3')"); Any ideas?

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  • User monthly payment system

    - by SomCollection
    I want to create a monthly payment system for community members, at this point I have figured out that I need the following tables in my mysql database. Edited Users table user_id, first_name, last_name Payment table payment_id,user_id,amount,due_date,payment_date,total What I need to display list of users who did not pay 6th of every month. How do I do this? And once the last day of the month is reached, how do I move to the next month?

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  • Allow users to pull temporary data then delete table data (headers remain)?

    - by JM4
    I don't know the best way to title this question but am trying to accomplish the following goal: When a client logs into their profile, they are presented with a link to download data from an existing database in CSV format. The process works, however, I would like for this data to be 'fresh' each time they click the link so my plan was - once a user has clicked the link and downloaded the CSV file, the database table would 'erase' all of its data and start fresh (be empty) until the next set of data populated it. My EXISTING CSV creation code: <?php $host = 'localhost'; $user = 'username'; $pass = 'password'; $db = 'database'; $table = 'tablename'; $file = 'export'; $link = mysql_connect($host, $user, $pass) or die("Can not connect." . mysql_error()); mysql_select_db($db) or die("Can not connect."); $result = mysql_query("SHOW COLUMNS FROM ".$table.""); $i = 0; if (mysql_num_rows($result) > 0) { while ($row = mysql_fetch_assoc($result)) { $csv_output .= $row['Field'].", "; $i++; } } $csv_output .= "\n"; $values = mysql_query("SELECT * FROM ".$table.""); while ($rowr = mysql_fetch_row($values)) { for ($j=0;$j<$i;$j++) { $csv_output .= '"'.$rowr[$j].'",'; } $csv_output .= "\n"; } $filename = $file."_".date("Y-m-d",time()); header("Content-type: application/vnd.ms-excel"); header("Content-disposition: csv" . date("Y-m-d") . ".csv"); header( "Content-disposition: filename=".$filename.".csv"); print $csv_output; exit; ?> any ideas?

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