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  • How do I show TextView's in LinearLayout that layed on other Layout?

    - by gelassen
    Good day. I have three layouts: first is the root, second and third lie in first. I try add TextView object in third layout and objects had been added in third layout (I saw it in debage mode) but this objects didn't showed on screen. May be someone know where is the problem? <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="vertical"> <LinearLayout android:layout_width="fill_parent" android:layout_height="wrap_content" android:orientation="horizontal"> <Button android:id="@+id/addJokeButton" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="@string/app_name" /> <EditText android:id="@+id/newJokeEditText" android:layout_width="fill_parent" android:layout_height="wrap_content" /> </LinearLayout> <LinearLayout android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="vertical"> </LinearLayout> </LinearLayout> protected void initLayout() { setContentView(R.layout.advanced); LinearLayout linearLayout = (LinearLayout) getLayoutInflater().inflate( R.layout.advanced, null); m_vwJokeEditText = (EditText) findViewById(R.id.newJokeEditText); m_vwJokeButton = (Button) findViewById(R.id.addJokeButton); m_vwJokeLayout = (LinearLayout) linearLayout.getChildAt(1); } protected void addJoke(Joke joke) { m_arrJokeList.add(joke); LayoutParams lparams = new LayoutParams(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT); TextView textView = new TextView(this); setColor(textView); textView.setLayoutParams(lparams); textView.setText(joke.getJoke()); m_vwJokeLayout.addView(textView); }

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  • Java MySQL Query Problem MySQLSyntaxErrorException When Creating a Table

    - by Aqib Mushtaq
    I fairly new to MySQL with Java, but I have executed a few successful INSERT queries however cannot seem to get the CREATE TABLE query to execute without getting the 'MySQLSyntaxErrorException' exception. My code is as follows: import java.sql.*; Statement stmt; Class.forName("com.mysql.jdbc.Driver"); String url = "jdbc:mysql://localhost:3306/mysql"; Connection con = DriverManager.getConnection(url, "root", "password"); stmt = con.createStatement(); String tblSQL = "CREATE TABLE IF NOT EXISTS \'dev\'.\'testTable\' (\n" + " \'id\' int(11) NOT NULL AUTO_INCREMENT,\n" + " \'date\' smallint(6) NOT NULL\n" + ") ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;"; stmt.executeUpdate(tblSQL); stmt.close(); con.close(); And the error is as follows: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''dev'.'testTable' ( 'id' int(11) NOT NULL AUTO_INCREMENT, 'date' smallint(6) N' at line 1 I would appreciate it if anyone could spot the mistake in this query, as I've tried executing this within phpMyAdmin and it works as it should. Thanks in advance.

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  • jqGrid Sort or Search does not work with columns having json dot notation

    - by rsmoorthy
    I have this jqGrid: $("#report").jqGrid( { url: '/py/db?coll=report', datatype: 'json', height: 250, colNames: ['ACN', 'Status', 'Amount'], colModel: [ {name:'acn', sortable:true}, {name:'meta.status', sortable:true}, {name:amount} ], caption: 'Show Report', rownumbers: true, gridview: true, rowNum: 10, rowList: [10,20,30], pager: '#report_pager', viewrecords: true, sortname: 'acn', sortorder: "desc", altRows: true, loadonce: true, mtype: "GET", rowTotal: 1000, jsonReader: { root: "rows", page: "page", total: "total", records: "records", repeatitems: false, id: "acn" } }); Notice that the column 'meta.status' is in JSON dot notation and accordingly the data sent from the server is like this: {"page": "1", "total": "1", "records": "5", "rows": [ {"acn":1,"meta": {"status":"Confirmed"}, "amount": 50}, {"acn":2,"meta": {"status":"Started"}, "amount": 51}, {"acn":3,"meta": {"status":"Stopped"}, "amount": 52}, {"acn":4,"meta": {"status":"Working"}, "amount": 53}, {"acn":5,"meta": {"status":"Started"}, "amount": 54} ] } The problems are of two fold: Sorting does not work on columns with dot notation, here "meta.status". It does not even show the sortable icons on the column header, and nothing happens even if the header is clicked. Sorting does not work, whether loadonce is true or false. If I try Searching (after setting loadonce to true) for the column meta.status (other columns without dot notation is okay), then it throws up a javascript error like this. Any help? Thanks Moorthy

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  • Rewrite to support folders as domain aliases while hiding subfolders

    - by user1692328
    I am trying to use domain aliases to point to subfolders on my site where the subfolders name would be hidden from resulting url on rewrite. domain-alias1.com and domain-alias2.com are domain aliases to domain.com I have the following in my root: domain.com/ .htaccess (listed below) domain-alias1/ main/ .htaccess (contains only Options -Indexes) domain-alias2/ ... /.htaccess follows: RewriteEngine on RewriteBase / RewriteCond %{HTTP_HOST} ^domain-alias1\.com$ [NC,OR] RewriteCond %{HTTP_HOST} ^www\.domain-alias1\.com$ [NC] RewriteCond %{REQUEST_URI} !^/domain-alias1 RewriteRule ^(.*)$ domain-alias1/$1 [L] RewriteCond %{HTTP_HOST} ^domain-alias2\.com$ [NC,OR] RewriteCond %{HTTP_HOST} ^www\.domain-alias2\.com$ [NC] RewriteCond %{REQUEST_URI} !^/domain-alias2 RewriteRule ^(.*)$ domain-alias2/$1 [L] domain-alias1.com (yields) - Forbidden. You don't have permission to access /cogeco-gis/ on this server. (Which is what I want since .htaccess in domain.com/domain-alias1 contains Options -Indexes) domain-alias1.com/test (yields) - Not Found. The requested URL /domain-alias1/test was not found on this server. (Which is what I expect since test does not exist) domain-alias1.com/main (yields) - domain-alias1.com/domain-alias1/main/login_page.php I am expecting rewrite to yield : domain-alias1.com/main/login_page.php where subfolder domain-alias1 is hidden from resulting url) Any help on how to get expected results?

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  • Does pressing Back always cause Activity to finish()?

    - by stormin986
    I've heard that pressing the back button will essentially cause the current Activity to finish(). Is this always the case? Seems like it would be with the way it pops the Activity off the stack. The one situation I'm not so sure about is when the root Activity in a Task has back pressed. I'm currently experiencing a very weird effect, described as follows: On loading my application, the first Activity is for initialization, and once it finishes, it calls my main Activity (a TabActivity). This first init activity has android:noHistory="true" set in the Manifest so pressing Back from my main Activity won't go back to that. It goes to the Launcher. When I click on my App in the Launcher a second time, the initialization activity loads again, and loads the main Activity when done. Almost immediately after, it loads a second instance of my main Activity. But ONLY after the Application has already been run once, and was exited by pressing BACK from the main Activity. It does it every subsequent time until I force quit the app or load a new version from the IDE. Based on this, I am suspecting some kind of Activity instance is lying around and being reused, since it only happens on the second+ time I run the application (and exit with BACK -- using HOME just returns to the last state of the app, no big deal). Anyone have any thoughts??

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  • How can i zip files in Java and not include files paths

    - by Ignacio
    For example, i want to zip a file stored in /Users/me/Desktop/image.jpg I maded this method: public static Boolean generateZipFile(ArrayList<String> sourcesFilenames, String destinationDir, String zipFilename){ // Create a buffer for reading the files byte[] buf = new byte[1024]; try { // VER SI HAY QUE CREAR EL ROOT PATH boolean result = (new File(destinationDir)).mkdirs(); String zipFullFilename = destinationDir + "/" + zipFilename ; System.out.println(result); // Create the ZIP file ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFullFilename)); // Compress the files for (String filename: sourcesFilenames) { FileInputStream in = new FileInputStream(filename); // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(filename)); // Transfer bytes from the file to the ZIP file int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } // Complete the entry out.closeEntry(); in.close(); } // Complete the ZIP file out.close(); return true; } catch (IOException e) { return false; } } But when i extract the file, the unzipped files have the full path. I don't want the full path of each file in the zip i only want the filename. How can i made this?

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  • Host Primary Domain from a subfolder

    - by TandemAdam
    I am having a problem making a sub directory act as the public_html for my main domain, and getting a solution that works with that domains sub directories too. My hosting allows me to host multiple sites, which are all working great. I have set up a subfolder under my ~/public_html/ directory called /domains/, where I create a folder for each separate website. e.g. public_html domains websiteone websitetwo websitethree ... This keeps my sites nice and tidy. The only issue was getting my "main domain" to fit into this system. It seems my main domain, is somehow tied to my account (or to Apache, or something), so I can't change the "document root" of this domain. I can define the document roots for any other domains ("Addon Domains") that I add in cPanel no problem. But the main domain is different. I was told to edit the .htaccess file, to redirect the main domain to a subdirectory. This seemed to work great, and my site works fine on it's home/index page. The problem I'm having is that if I try to navigate my browser to say the images folder (just for example) of my main site, like this: www.yourmaindomain.com/images/ then it seems to ignore the redirect and shows the entire server directory in the url, like this: www.yourmaindomain.com/domains/yourmaindomain/images/ It still actually shows the correct "Index of /images" page, and show the list of all my images. Here is an example of my .htaccess file that I am using: RewriteEngine on RewriteCond %{HTTP_HOST} ^(www.)?yourmaindomain.com$ RewriteCond %{REQUEST_URI} !^/domains/yourmaindomain/ RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ /domains/yourmaindomain/$1 RewriteCond %{HTTP_HOST} ^(www.)?yourmaindomain.com$ RewriteRule ^(/)?$ domains/yourmaindomain/index.html [L] Does this htaccess file look correct? I just need to make it so my main domain behaves like an addon domain, and it's subdirectories adhere to the redirect rules.

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  • Access denied when trying to access my database.

    - by Sergio Tapia
    Here's my code: <html> <head> </head> <body> <?php $user = mysql_real_escape_string($_GET["u"]); $pass = mysql_real_escape_string($_GET["p"]); $query = "SELECT * FROM usario WHERE username = '$user' AND password = '$pass'"; mysql_connect(localhost, "root", ""); @mysql_select_db("multas") or die( "Unable to select database"); $result=mysql_query($query); if(mysql_numrows($result) > 0){ echo 'si'; } ?> </body> </html> And here's the error I get when I try to run it Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\useraccess.php on line 7 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in C:\xampp\htdocs\useraccess.php on line 7 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\xampp\htdocs\useraccess.php on line 8 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in C:\xampp\htdocs\useraccess.php on line 8 Warning: mysql_numrows() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\useraccess.php on line 16

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  • Problem with date_select when using :discard option. (Rails)

    - by MikeH
    I'm using a date_select with the option :discard_year => true If a user selects a date in the date select, and then he comes back and returns the select to the prompt values of Month and Day, Rails automatically sets the select values to January 1. I know this is the intended functionality if a month is selected and a day is left blank, but that's not the case here. In my example, the user sets both the month and day back to the prompt. By Rails forcing January 1, I'm getting bad results. I've tried every parameter available in the api. :default = nil, :include_blank = true. None of those change the behavior I'm describing. I've isolated the root of the problem, which is this: Because I'm discarding the :year parameter, when the user tries to return the month and day to the prompt values, Rails doesn't see an empty prompt select. It perhaps sees a year selected with empty month and day, which it then sets to January 1. This is the case because the :discard_year parameter does in fact set a date in the database, it just removes it from the view. How can I code around this problem?

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  • Cleaning up a sparsebundle with a script

    - by nickg
    I'm using time machine to backup some servers to a sparse disk image bundle and I'd like to have a script to clean up the old back ups and re-size the image once space has been freed up. I'm fairly certain the data is protected because if I delete the old backups by right clicking, I have to enter a password to be able to delete them. To allow my script to be able to delete them, I've been running it as root. For some reason, it just won't run and every file it tries to delete I get rm: /file/: Operation not permitted Here is what I have as my script: #!/bin/bash for server in servername; do /usr/bin/hdiutil attach -mountpoint /path/to/mountpoint /path/to/sparsebundle/$server.sparsebundle/; /bin/sleep 10; /usr/bin/find /path/to/mountpoint -type d -mtime +7 -exec /bin/rm -rf {} \; /usr/bin/hdiutil unmount /path/to/mountpoint; /bin/sleep 10; /usr/bin/hdiutil compact /path/to/sparsebundle/$server.sparsebundle/; done exit; One of the problems I thought was causing this was it needed to have a mountpoint specified since the default mount was to /Volumes/Time\ Machine\ Backups/ that's why I created a mountpoint. I also thought that it was trying to delete the files to quickly after mounting and it wasn't actually mounted yet, that's why I added the sleep. I've also tried using the -delete option for find instead of -exec, but it didn't make any difference. Any help on this would be greatly appreciated because I'm out of ideas as to why this won't work.

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  • Displaying tree path of record in SQL Server 2005

    - by jskiles1
    An example of my tree table is: ([id] is an identity) [id], [parent_id], [path] 1, NULL, 1 2, 1, 1-2 3, 1, 1-3 4, 3, 1-3-4 My goal is to query quickly for multiple rows of this table and view the full path of the node from its root, through its superiors, down to itself. The ultimate question is, should I generate this path on inserts and maintain it in its own column or generate this path on query to save disk space? I guess it depends if this table is write heavy or read heavy. I've been contemplating several approaches to using the "path" characteristic of this parent/child relationship and I just can't seem to settle on one. This "path" is simply for display purposes and serves absolutely no purpose other than that. Here is what I have done to implement this "path." AFTER INSERT TRIGGER - requires passing a NULL path to the insert and updating the path for the record at the inserted rows identity INSTEAD OF INSERT TRIGGER - does not require insert to have NULL path passed, but does require the trigger to insert with a NULL path and updating the path for the record at SCOPE_IDENTITY() STORED PROCEDURE - requiring all inserts into this table to be done through the stored procedure implementing the trigger logic VIEW - requires building the path in the view 1 and 2 seem annoying if massive amounts of data are entered at once. 3 seems annoying because all inserts must go through the procedure in order to have a valid path populated. 1, 2, and 3 require maintaining a path column on the table. 4 removes all the limitations of the above but require the view to perform the path logic and requires use of the view if a path is to be displayed. I have successfully implemented all of the above approaches and I'm mainly looking for some advice. Am I way off the mark here or are any of the above acceptable? Each has it's advantages and disadvantages.

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  • Hadoop reduce task gets hung

    - by user806098
    I set up a hadoop cluster with 4 nodes, When running a map-reduce task, the map task finishes quickly, while the reduce task hangs at 27% percent. I checked the log, it's that the reduce task fails to fetch map output from map nodes. The job tracker log of master shows messages like this: 2011-06-27 19:55:14,748 INFO org.apache.hadoop.mapred.JobTracker: Adding task (REDUCE) 'attempt_201106271953_0001_r_000000_0' to tip task_201106271953_0001_r_000000, for tracker 'tracker_web30.bbn.com.cn:localhost/127.0.0.1:56476' And the name node log of master shows messages like this: 2011-06-27 14:00:52,898 INFO org.apache.hadoop.ipc.Server: IPC Server handler 4 on 54310, call register(DatanodeRegistration(202.106.199.39:50010, storageID=DS-1989397900-202.106.199.39-50010-1308723051262, infoPort=50075, ipcPort=50020)) from 192.168.225.19:16129: error: java.io.IOException: verifyNodeRegistration: unknown datanode 202.106.199.3 9:50010 However, neither the "web30.bbn.com.cn" or 202.106.199.39, 202.106.199.3 is the slave node. I think such ip/domains appear because hadoop fails to resolve a node(first in the Intranet DNS server), then it goes to a higher-level DNS server, later to the top, still fails, then the "junk" ip/domains are returned. But I checked my config, it goes like this: /etc/hosts: 127.0.0.1 localhost.localdomain localhost ::1 localhost6.localdomain6 localhost6 192.168.225.16 master 192.168.225.66 slave1 192.168.225.20 slave5 192.168.225.17 slave17 conf/core-site.xml: hadoop.tmp.dir /root/hadoop_tmp/hadoop_${user.name} fs.default.name hdfs://master:54310 io.sort.mb 1024 hdfs-site.xml: dfs.replication 3 masters: master slaves: master slave1 slave5 slave17 Also, all firewalls(iptables) are turned off, and ssh between each 2 nodes is ok. so I don't know where exact the error comes from. Please help. Thanks a lot.

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  • Eager loading OneToMany in Hibernate with JPA2

    - by pihentagy
    I have a simple @OneToMany between Person and Pet entities: @OneToMany(mappedBy="owner", cascade=CascadeType.ALL, fetch=FetchType.EAGER) public Set<Pet> getPets() { return pets; } I would like to load all Persons with associated Pets. So I came up with this (inside a test class): @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration public class AppTest { @Test @Rollback(false) @Transactional(readOnly = false) public void testApp() { CriteriaBuilder qb = em.getCriteriaBuilder(); CriteriaQuery<Person> c = qb.createQuery(Person.class); Root<Person> p1 = c.from(Person.class); SetJoin<Person, Pet> join = p1.join(Person_.pets); TypedQuery<Person> q = em.createQuery(c); List<Person> persons = q.getResultList(); for (Person p : persons) { System.out.println(p.getName()); for (Pet pet : p.getPets()) { System.out.println("\t" + pet.getNick()); } } However, turning the SQL logging on shows, that it executes 3 queries (having 2 Persons in the DB). Hibernate: select person0_.id as id0_, person0_.name as name0_, person0_.sex as sex0_ from Person person0_ inner join Pet pets1_ on person0_.id=pets1_.owner_id Hibernate: select pets0_.owner_id as owner3_0_1_, pets0_.id as id1_, pets0_.id as id1_0_, pets0_.nick as nick1_0_, pets0_.owner_id as owner3_1_0_ from Pet pets0_ where pets0_.owner_id=? Hibernate: select pets0_.owner_id as owner3_0_1_, pets0_.id as id1_, pets0_.id as id1_0_, pets0_.nick as nick1_0_, pets0_.owner_id as owner3_1_0_ from Pet pets0_ where pets0_.owner_id=? Any tips? Thanks Gergo

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  • Iphone: Problem with moving back and forth between two UIViewController

    - by Harry Pham
    Let me first describe the context of the problem. I have 2 UIViewController call AdminViewController and ButtonReorderViewController. AdminViewController contain 1 button. ButtonReorderViewController contains 1 button and 1 picture. Button in AdminViewController tie to an event call goToReorderButton. The content of goToReorderButton are below: ButtonReorderViewController *buttonReorder = [[ButtonReorderViewController alloc] initWithNibName:@"ButtonReorderViewController" bundle:[NSBundle mainBundle]]; UINavigationController *navController = [[UINavigationController alloc] initWithRootViewController:buttonReorder]; //Add a Navigation Controller to the root view [navController setNavigationBarHidden:TRUE]; buttonReorder = (ButtonReorderViewController *) navController; [[buttonReorder view] setFrame:CGRectMake(0, -20, 320, 470)]; [self.view addSubview:buttonReorder.view]; I use UINavigationController to allow me to swipe left and right.So I am in AdminViewController, and I click on goToReorderButton, it load ButtonReorderViewController. I am able to swipe left and right (awesome !!!) So I click the button in ButtonReorderViewController call goToAdmin, simply to go back to the AdminViewController -(void) goToAdmin{ [self.view removeFromSuperview]; } However, as soon as I go back to AdminViewController, I cant click anything at all. The program does not seg fault, it just that I cant click the button at all. if I remove the line buttonReorder = (ButtonReorderViewController *) navController; inside goToReorderButton, then everything work fine. Any idea how to fix this?

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  • Why are my Flex resource bundles not being loaded?

    - by Chris R
    I have an Actionscript module in the flex source folder filterModules, which is one of two additional source folders in my project (the main source folder is reports, but I'm not dealing with anything in there right now). Here's the MXML content that references the resources. ... This array is assigned to the dataProvider field of a ComboBox. It's not bound using the bindings, presumably for reasons that made sense to the original developer, and it'd be nontrivial to change the class to make that happen. I additionally have a resource property file in a folder resources/en_US and I have the source folder resources/{locale} in the project source settings. My additional compiler options are -locale en_US. The resource property file is resources/en_US/labels.properties (All paths are relative to the flash builder project root) and contains (amongst other things) these keys: metric.q3 = Overall Satisfaction metric.q5 = Personnel metric.q9a = Issue Resolution metric.q42 = Visit Duration Sat metric.q34 = Visit Duration I have written some FlexUnit tests that run in my local Flash Player that exercise these resources -- they check that every label is represented in the metrics array, for example, so I know that the resource file is loaded when run locally. However, when I copy the module .swf file over to my server, the combo box to which the array is assigned is empty. I copy the .swf like so, if it matters: rsync -rlDv --inplace -T /tmp ~/projects/flex_reports/bin-debug/rankingFilter.swf HOSTNAME:WEBROOT/flashPath/ Why is this? I am not able to debug the remote module because our surrounding site sets up a lot of context and makes some database calls to determine which module to load. I'm hoping to get some pointers on why resource bundles might not show up. I'd understand it if the array was present with wrong labels, but the array is instead completely empty, which is pretty odd.

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  • MS Query Analizer/Management Studio replacement?

    - by kprobst
    I've been using SQL Server since version 6.5 and I've always been a bit amazed at the fact that the tools seem to be targeted to DBAs rather than developers. I liked the simplicity and speed of the Query Analizer for example, but hated the built-in editor, which was really no better than a syntax coloring-capable Notepad. Now that we have Management Studio the management part seems a bit better but from a developer standpoint the tools is even worse. Visual Studio's excellent text editor... without a way to customize keyboard bindings!? Don't get me started on how unusable is the tree-based management hierarchy. Why can't I re-root the tree on a list of stored procs for example the way the Enterprise Manager used to allow? Now I have a treeview that needs to be scrolled horizontally, which makes it eminently useless. The SQL server support in Visual Studio is fantastic for working with stored procedures and functions, but it's terrible as a general ad hoc data query tool. I've tried various tools over the years but invariably they seem to focus on the management side and shortchange the developer in me. I just want something with basic admin capabilities, good keyboard support and requisite DDL functionality (ideally something like the Query Analyzer). At this point I'm seriously thinking of using vim+sqlcmd and a console... I'm that desperate :) Those of you who work day in and day out with SQL Server and Visual Studio... do you find the tools to be adequate? Have you ever wished they were better and if you have found something better, could you share please? Thanks!

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  • What is the most efficient/elegant way to parse a flat table into a tree?

    - by Tomalak
    Assume you have a flat table that stores an ordered tree hierarchy: Id Name ParentId Order 1 'Node 1' 0 10 2 'Node 1.1' 1 10 3 'Node 2' 0 20 4 'Node 1.1.1' 2 10 5 'Node 2.1' 3 10 6 'Node 1.2' 1 20 What minimalistic approach would you use to output that to HTML (or text, for that matter) as a correctly ordered, correctly intended tree? Assume further you only have basic data structures (arrays and hashmaps), no fancy objects with parent/children references, no ORM, no framework, just your two hands. The table is represented as a result set, which can be accessed randomly. Pseudo code or plain English is okay, this is purely a conceptional question. Bonus question: Is there a fundamentally better way to store a tree structure like this in a RDBMS? EDITS AND ADDITIONS To answer one commenter's (Mark Bessey's) question: A root node is not necessary, because it is never going to be displayed anyway. ParentId = 0 is the convention to express "these are top level". The Order column defines how nodes with the same parent are going to be sorted. The "result set" I spoke of can be pictured as an array of hashmaps (to stay in that terminology). For my example was meant to be already there. Some answers go the extra mile and construct it first, but thats okay. The tree can be arbitrarily deep. Each node can have N children. I did not exactly have a "millions of entries" tree in mind, though. Don't mistake my choice of node naming ('Node 1.1.1') for something to rely on. The nodes could equally well be called 'Frank' or 'Bob', no naming structure is implied, this was merely to make it readable. I have posted my own solution so you guys can pull it to pieces.

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  • facebook javascript api

    - by ngreenwood6
    I am trying to get my status from facebook using the javascript api. I have the following code: <div id="fb-root"></div> <div id="data"></div> <script src="http://connect.facebook.net/en_US/all.js"></script> <script type="text/javascript"> (function(){ FB.init({ appId : 'SOME ID', status : true, // check login status cookie : true, // enable cookies to allow the server to access the session xfbml : true // parse XFBML }); }); getData(); function getData(){ var query = FB.Data.query('SELECT message FROM status WHERE uid=12345 LIMIT 10'); query.wait(function(rows) { for(i=0;i<rows.length;i++){ document.getElementById('data').innerHTML += 'Your status is ' + rows[i].message + '<br />'; } }); } </script> When i try to get my name it works fine but the status is not working. Can someone please tell me what I am doing wrong because the documentation for this is horrible. And yes I replaced the uid with a fake one and yes i put in my app id because like i said when i try to get my name it works fine. Any help is appreciated.

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  • How can I get back my privilege to create a new database in MySQL?

    - by Steven
    I can not use MySQL. MySQL is on my local computer. Currently I added skip-grant-tables in My.ini so I can use MySQL. But I have no privilege to create a new database. My problem is tough, although I asked related questions on SO, but no answer can resolve my problem. I almost give up. So I lower my expectation. I am developing a website, so I need to create database, tables and operate tables. You don't have to consider security. Is there a simple solution that can give me privilege to create a new database? Maybe by adding some command in my.ini or something? You won't need to completely resolve my problem. Maybe after the development, I will upload the database and tables to another server(The current database server is my personal computer, windows XP) so I can uninstall and reinstall MySQL. The root of problem is that I lack privileges.

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  • Zend Framework: Zend_DB Error

    - by Sergio E.
    I'm trying to learn ZF, but got strange error after 20 minutes :) Fatal error: Uncaught exception 'Zend_Db_Adapter_Exception' with message 'Configuration array must have a key for 'dbname' that names the database instance' What does this error mean? I got DB information in my config file: resources.db.adapter=pdo_mysql resources.db.host=localhost resources.db.username=name resources.db.password=pass resources.db.dbname=name Any suggestions? EDIT: This is my model file /app/models/DbTable/Bands.php: class Model_DbTable_Bands extends Zend_Db_Table_Abstract { protected $_name = 'zend_bands'; } Index controller action: public function indexAction() { $albums = new Model_DbTable_Bands(); $this->view->albums = $albums->fetchAll(); } EDIT All codes: bootstrap.php protected function _initAutoload() { $autoloader = new Zend_Application_Module_Autoloader(array( 'namespace' => '', 'basePath' => dirname(__FILE__), )); return $autoloader; } protected function _initDoctype() { $this->bootstrap('view'); $view = $this->getResource('view'); $view->doctype('XHTML1_STRICT'); } public static function setupDatabase() { $config = self::$registry->configuration; $db = Zend_Db::factory($config->db); $db->query("SET NAMES 'utf8'"); self::$registry->database = $db; Zend_Db_Table::setDefaultAdapter($db); Zend_Db_Table_Abstract::setDefaultAdapter($db); } IndexController.php class IndexController extends Zend_Controller_Action { public function init() { /* Initialize action controller here */ } public function indexAction() { $albums = new Model_DbTable_Bands(); $this->view->albums = $albums->fetchAll(); } } configs/application.ini, changed database and provided password: [development : production] phpSettings.display_startup_errors = 1 phpSettings.display_errors = 1 db.adapter = PDO_MYSQL db.params.host = localhost db.params.username = root db.params.password = pedro db.params.dbname = test models/DbTable/Bands.php class Model_DbTable_Bands extends Zend_Db_Table_Abstract { protected $_name = 'cakephp_bands'; public function getAlbum($id) { $id = (int)$id; $row = $this->fetchRow('id = ' . $id); if (!$row) { throw new Exception("Count not find row $id"); } return $row->toArray(); } }

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  • Stubbing an ActsAs Rails Plugin

    - by Rabbott
    I need to create a plugin much like Authlogic (or even just add on to Authlogic), but due to requirements beyond my control I need my plugin to authenticate using SOAP. Basically the plugin would require that anyone accessing the controller (before_filter would be fine) would have to authenticate first. I have ZERO control over the login page, or the SOAP server, I am simply a client attempting to authenticate to the providers SOAP Web Service. Here is what happens.. before_filter realizes that no session[:credential] is set, and forwards the user to the url on the providers servers. The user enters their credentials, and once authenticated, the web service forwards the user to a URL that has been entered by their sysadmins, attaching a token to the url on its way back. I need to take that token, append it to some parameters stored in a local YAML file, and make the SOAP call to the providers server. If all goes as planned, I need to set session[:credential] to the result of the SOAP call, and forward the user to the root page. Subsequent calls to the before_filter will not make the SOAP call, because session[:credential] is set. Ideally I think this would be awesome to slap on top of Authlogic, but I'm not sure how to do this, So I started to create my own acts_as_soap_authentic plugin, which isn't causing errors, but doesn't do anything.. Anyone have any pointers, or tips as to how I can get the ball rolling here? It seems simple, but is proving not to be..

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  • Silverlight 3 data-binding child property doesn't update

    - by sonofpirate
    I have a Silverlight control that has my root ViewModel object as it's data source. The ViewModel exposes a list of Cards as well as a SelectedCard property which is bound to a drop-down list at the top of the view. I then have a form of sorts at the bottom that displays the properties of the SelectedCard. My XAML appears as (reduced for simplicity): <StackPanel Orientation="Vertical"> <ComboBox DisplayMemberPath="Name" ItemsSource="{Binding Path=Cards}" SelectedItem="{Binding Path=SelectedCard, Mode=TwoWay}" /> <TextBlock Text="{Binding Path=SelectedCard.Name}" /> <ListBox DisplayMemberPath="Name" ItemsSource="{Binding Path=SelectedCard.PendingTransactions}" /> </StackPanel> I would expect the TextBlock and ListBox to update whenever I select a new item in the ComboBox, but this is not the case. I'm sure it has to do with the fact that the TextBlock and ListBox are actually bound to properties of the SelectedCard so it is listening for property change notifications for the properties on that object. But, I would have thought that data-binding would be smart enough to recognize that the parent object in the binding expression had changed and update the entire binding. It bears noting that the PendingTransactions property (bound to the ListBox) is lazy-loaded. So, the first time I select an item in the ComboBox, I do make the async call and load the list and the UI updates to display the information corresponding to the selected item. However, when I reselect an item, the UI doesn't change! For example, if my original list contains three cards, I select the first card by default. Data-binding does attempt to access the PendingTransactions property on that Card object and updates the ListBox correctly. If I select the second card in the list, the same thing happens and I get the list of PendingTransactions for that card displayed. But, if I select the first card again, nothing changes in my UI! Setting a breakpoint, I am able to confirm that the SelectedCard property is being updated correctly. How can I make this work???

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  • ASP.Net MVC ActionLink's and Shared Hosting Aliased Domains

    - by Peter Meyer
    So, I've read this and I've got a similar issue: I have a shared hosting account (with GoDaddy, though that's not exactly relevant, I believe) and I've got an MVC (RC1) site deployed to a sub-folder which where I have another domain name mapped (or aliased). The sub-folder is also setup as an application root as well. The site works without issue, the problem is that I don't like the links that are being generated using Html.ActionLink and Ajax.ActionLink. It's inserting the sub folder name as part of the URL as described in this other question. Thing is, the site works fine, but I'd like to make the links generated relative to the domain name. To use an example: http://my.abc.com "primary" domain; maps to \ on file system http://my.xyz.com setup to map to \_xyz.com folder on file system My generated links on xyz.com look like this: Intended Generated -------- --------- http://my.xyz.com/Ctrller/Action/52 http://my.xyz.com/_xyz.com/Ctrller/Action/52 and, FWIW, the site works. So, the question: Is there something I can do to get rid of that folder name in the links being generated? I have a couple of brute force ideas, but they aren't too elegant.

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  • iPhone View Switching basics.

    - by Daniel Granger
    I am just trying to get my head around simple view switching for the iPhone and have created a simple app to try and help me understand it. I have included the code from my root controller used to switch the views. My app has a single toolbar with three buttons on it each linking to one view. Here is my code to do this but I think there most be a more efficient way to achieve this? Is there a way to find out / remove the current displayed view instead of having to do the if statements to see if either has a superclass? I know I could use a tab bar to create a similar effect but I am just using this method to help me practice a few of the techniques. -(IBAction)switchToDataInput:(id)sender{ if (self.dataInputVC.view.superview == nil) { if (dataInputVC == nil) { dataInputVC = [[DataInputViewController alloc] initWithNibName:@"DataInput" bundle:nil]; } if (self.UIElementsVC.view.superview != nil) { [UIElementsVC.view removeFromSuperview]; } else if (self.totalsVC.view.superview != nil) { [totalsVC.view removeFromSuperview]; } [self.view insertSubview:dataInputVC.view atIndex:0]; } } -(IBAction)switchToUIElements:(id)sender{ if (self.UIElementsVC.view.superview == nil) { if (UIElementsVC == nil) { UIElementsVC = [[UIElementsViewController alloc] initWithNibName:@"UIElements" bundle:nil]; } if (self.dataInputVC.view.superview != nil) { [dataInputVC.view removeFromSuperview]; } else if (self.totalsVC.view.superview != nil) { [totalsVC.view removeFromSuperview]; } [self.view insertSubview:UIElementsVC.view atIndex:0]; } } -(IBAction)switchToTotals:(id)sender{ if (self.totalsVC.view.superview == nil) { if (totalsVC == nil) { totalsVC = [[TotalsViewController alloc] initWithNibName:@"Totals" bundle:nil]; } if (self.dataInputVC.view.superview != nil) { [dataInputVC.view removeFromSuperview]; } else if (self.UIElementsVC.view.superview != nil) { [UIElementsVC.view removeFromSuperview]; } [self.view insertSubview:totalsVC.view atIndex:0]; } }

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  • Webfaction apache + mod_wsgi + django configuration issue

    - by Dmitry Guyvoronsky
    A problem that I stumbled upon recently, and, even though I solved it, I would like to hear your opinion of what correct/simple/adopted solution would be. I'm developing website using Django + python. When I run it on local machine with "python manage.py runserver", local address is http://127.0.0.1:8000/ by default. However, on production server my app has other url, with path - like "http://server.name/myproj/" I need to generate and use permanent urls. If I'm using {% url view params %}, I'm getting paths that are relative to / , since my urls.py contains this urlpatterns = patterns('', (r'^(\d+)?$', 'myproj.myapp.views.index'), (r'^img/(.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT + '/img' }), (r'^css/(.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT + '/css' }), ) So far, I see 2 solutions: modify urls.py, include '/myproj/' in case of production run use request.build_absolute_uri() for creating link in views.py or pass some variable with 'hostname:port/path' in templates Are there prettier ways to deal with this problem? Thank you. Update: Well, the problem seems to be not in django, but in webfaction way to configure wsgi. Apache configuration for application with URL "hostname.com/myapp" contains the following line WSGIScriptAlias / /home/dreamiurg/webapps/pinfont/myproject.wsgi So, SCRIPT_NAME is empty, and the only solution I see is to get to mod_python or serve my application from root. Any ideas?

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