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  • Using "ocamlfind" to make the OCaml compiler and toplevel find (project specific) libraries

    - by CharlieP
    Hello, I'm trying to use ocamlfind with both the OCaml compiler and toplevel. From what I understood, I need to place the required libraries in the _tags file at the root of my project, so that the ocamlfind tool will take care of loading them - allowing me to open them in my modules like so : open Sdl open Sdlvideo open Str Currently, my _tags file looks like this : <*>: pkg_sdl,pkg_str I can apparently launch the ocamlfind command with the ocamlc or ocamlopt argument, provided I wan't to compile my project, but I did not see an option to launch the toplevel in the same manner. Is there any way to do this (something like "ocamlfind ocaml")? I also don't know how to place my project specific modules in the _tags file : imagine I have a module name Land. I am currently using the #use "land.ml" directive to open the file and load the module, but it has been suggested that this is not good practice. What syntax should I use in _tags to specify it should be loaded by ocamlfind (considering land.ml is not in the ocamlfind search path) ? Thank you, Charlie P. Edit : According to the first answer of this post, the _tags file is not to be used with ocamlfind. The questions above still stand, there is just a new one to the list : what is the correct way to specify the libraries to ocamlfind ?

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  • Testing performance of queries in mysl

    - by Unreason
    I am trying to setup a script that would test performance of queries on a development mysql server. Here are more details: I have root access I am the only user accessing the server Mostly interested in InnoDB performance The queries I am optimizing are mostly search queries (SELECT ... LIKE '%xy%') What I want to do is to create reliable testing environment for measuring the speed of a single query, free from dependencies on other variables. Till now I have been using SQL_NO_CACHE, but sometimes the results of such tests also show caching behaviour - taking much longer to execute on the first run and taking less time on subsequent runs. If someone can explain this behaviour in full detail I might stick to using SQL_NO_CACHE; I do believe that it might be due to file system cache and/or caching of indexes used to execute the query, as this post explains. It is not clear to me when Buffer Pool and Key Buffer get invalidated or how they might interfere with testing. So, short of restarting mysql server, how would you recommend to setup an environment that would be reliable in determining if one query performs better then the other?

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  • In PHP... best way to turn string representation of a folder structure into nested array

    - by Greg Frommer
    Hi everyone, I looked through the related questions for a similar question but I wasn't seeing quite what I need, pardon if this has already been answered already. In my database I have a list of records that I want represented to the user as files inside of a folder structure. So for each record I have a VARCHAR column called "FolderStructure" that I want to identify that records place in to the folder structure. The series of those flat FolderStructure string columns will create my tree structure with the folders being seperated by backslashes (naturally). I didn't want to add another table just to represent a folder structure... The 'file' name is stored in a separate column so that if the FolderStructure column is empty, the file is assumed to be at the root folder. What is the best way to turn a collection of these records into a series of HTML UL/LI tags... where each LI represents a file and each folder structure being an UL embedded inside it's parent?? So for example: file - folderStructure foo - bar - firstDir blue - firstDir/subdir would produce the following HTML: <ul> <li>foo</li> <ul> <li> bar </li> <ul> <li> blue </li> </ul> </ul> </ul> Thanks

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  • ClassNotFoundException com.mysql.jdbc.Driver

    - by Dusk
    This question might have asked here number of times . After doing some google search for the above error and doing some update, I can't understand why I'm still getting that error. I've already put my driver-- mysql-connector-java-5.1.5-bin in the classpath: Java_Home\jre\lib\ Java_Home\jre\lib\ext\ Java_Home\lib and the code which I'm using to connect to mysql database is: try{ Class.forName("com.mysql.jdbc.Driver"); Connection con=DriverManager.getConnection("jdbc:mysql://localhost:3306/mail","root",""); Statement stmt = con.createStatement(); ResultSet rs = stmt.executeQuery("select message_body from deadletter"); String dbtime; while (rs.next()) { dbtime = rs.getString(1); System.out.println(dbtime); } con.close(); } catch (SQLException e) { System.out.println("Connection Failed! Check output console"); e.printStackTrace(); } } and the complete stacktrace of the above exception is: java.lang.ClassNotFoundException: com.mysql.jdbc:Driver at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:307) at java.lang.ClassLoader.loadClass(ClassLoader.java:307) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301) at java.lang.ClassLoader.loadClass(ClassLoader.java:252) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:169) at mail.main(mail.java:114) Now, what's wrong I'm doing here?

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  • Iphone: Problem with moving back and forth between two UIViewController

    - by Harry Pham
    Let me first describe the context of the problem. I have 2 UIViewController call AdminViewController and ButtonReorderViewController. AdminViewController contain 1 button. ButtonReorderViewController contains 1 button and 1 picture. Button in AdminViewController tie to an event call goToReorderButton. The content of goToReorderButton are below: ButtonReorderViewController *buttonReorder = [[ButtonReorderViewController alloc] initWithNibName:@"ButtonReorderViewController" bundle:[NSBundle mainBundle]]; UINavigationController *navController = [[UINavigationController alloc] initWithRootViewController:buttonReorder]; //Add a Navigation Controller to the root view [navController setNavigationBarHidden:TRUE]; buttonReorder = (ButtonReorderViewController *) navController; [[buttonReorder view] setFrame:CGRectMake(0, -20, 320, 470)]; [self.view addSubview:buttonReorder.view]; I use UINavigationController to allow me to swipe left and right.So I am in AdminViewController, and I click on goToReorderButton, it load ButtonReorderViewController. I am able to swipe left and right (awesome !!!) So I click the button in ButtonReorderViewController call goToAdmin, simply to go back to the AdminViewController -(void) goToAdmin{ [self.view removeFromSuperview]; } However, as soon as I go back to AdminViewController, I cant click anything at all. The program does not seg fault, it just that I cant click the button at all. if I remove the line buttonReorder = (ButtonReorderViewController *) navController; inside goToReorderButton, then everything work fine. Any idea how to fix this?

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  • Django - The included urlconf doesn't have any patterns in it

    - by unsorted
    My website, which was working before, suddenly started breaking with the error "ImproperlyConfigured at / The included urlconf resume.urls doesn't have any patterns in it" The project base is called resume. In settings.py I have set ROOT_URLCONF = 'resume.urls' Here's my resume.urls, which sits in the project root directory. from django.conf.urls.defaults import * # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Example: # (r'^resume/', include('resume.foo.urls')), # Uncomment the admin/doc line below and add 'django.contrib.admindocs' # to INSTALLED_APPS to enable admin documentation: (r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: (r'^admin/', include(admin.site.urls)), (r'^accounts/login/$', 'django.contrib.auth.views.login'), #(r'^employer/', include(students.urls)), (r'^ajax/', include('urls.ajax')), (r'^student/', include('students.urls')), (r'^club/(?P<object_id>\d+)/$', 'resume.students.views.club_detail'), (r'^company/(?P<object_id>\d+)/$', 'resume.students.views.company_detail'), (r'^program/(?P<object_id>\d+)/$', 'resume.students.views.program_detail'), (r'^course/(?P<object_id>\d+)/$', 'resume.students.views.course_detail'), (r'^career/(?P<object_id>\d+)/$', 'resume.students.views.career_detail'), (r'^site_media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': 'C:/code/django/resume/media'}), ) I have a folder called urls and a file ajax.py inside. (I also created a blank init.py in the same folder so that urls would be recognized.) This is ajax.py. from django.conf.urls.defaults import * urlpatterns = patterns('', (r'^star/(?P<object_id>\d+)$', 'resume.students.ajax-calls.star'), ) Anyone know what's wrong? This is driving me crazy. Thanks,

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  • How can I prevent default_environment variables from getting set by Capistrano's sudo action?

    - by Logan Koester
    My deploy.rb sets some environment variables to use the regular user's local Ruby rather than the system-wide one. set :default_environment, { :PATH => '/home/myapp/.rvm/bin:/home/myapp/.rvm/bin:/home/myapp/.rvm/rubies/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global/bin:/home/myapp/bin:/usr/bin:/opt/local/bin:/opt/local/sbin:/usr/local/bin:/usr/local/sbin:/usr/sbin:/sbin:/bin:/usr/games', :RUBY_VERSION => 'ruby-1.9.1-p378', :GEM_HOME => '/home/myapp/.rvm/gems/ruby-1.9.1-p378', :GEM_PATH => '/home/myapp/.rvm/gems/ruby-1.9.1-p378:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global' } Naturally, when a task is using sudo, I would expect the system-wide ruby to be used instead. But it seems the environment variables are being set anyway, which is obviously invalid for the root user and returns an error: executing "sudo -p 'sudo password: ' /etc/init.d/god stop" servers: ["myapp.com"] [myapp.com] executing command command finished failed: "env PATH=/home/myapp/.rvm/bin:/home/myapp/.rvm/bin:/home/myapp/.rvm/rubies/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global/bin:/home/myapp/bin:/usr/bin:/opt/local/bin:/opt/local/sbin:/usr/local/bin:/usr/local/sbin:/usr/sbin:/sbin:/bin:/usr/games RUBY_VERSION=ruby-1.9.1-p378 GEM_HOME=/home/myapp/.rvm/gems/ruby-1.9.1-p378 GEM_PATH=/home/myapp/.rvm/gems/ruby-1.9.1-p378:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global sh -c 'sudo -p '\\''sudo password: '\\'' /etc/init.d/god stop'" on myapp.com It makes no difference whether I use capistrano's sudo "system call" or the regular run "sudo system call". How can I avoid this?

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  • Record Disappeared from Mysql Table, How Can I Find Out What Happened?

    - by Jascha
    I got the fire alarm phone call, AIM messages and email today from a client stating "The site is down!, WTF happened?!" Well, after a little digging, it turns out one of the records in a table had been wiped clean, but without removing the row itself. So, I had the representation of data, but a bunch of empty fields. (needless to day I need to write into my code a catch for this.) What my real question is, where can I figure out what happened? I've got access to phpmyadmin and that's about it. I found some access logs on in the root directory of my server, but that just tells me the client was in the admin area I built editing that record, I'd like to know specifically what they did that made all of the data go away. (what query was run etc...) is it possible without real server admin access? is there a neat little php to mysql class that returns data like this? Thanks in advance. -Jascha

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  • How to create a log file in the folder which will be created at run time

    - by swati
    Hello Everyone, I new to apache logger.I am using apache log4j for my application. I am using the following configuration file configure the root logger log4j.rootLogger=INFO, STDOUT, DAILY configure the console appender log4j.appender.STDOUT=org.apache.log4j.ConsoleAppender log4j.appender.STDOUT.Target=System.out log4j.appender.STDOUT.layout=org.apache.log4j.PatternLayout log4j.appender.STDOUT.layout.conversionPattern=%d{yyyy-MM-dd HH:mm:ss.SSS} [%p] %c:%L - %m%n configure the daily rolling file appender log4j.appender.DAILY=org.apache.log4j.DailyRollingFileAppender log4j.appender.DAILY.File=log4jtest.log log4j.appender.DAILY.DatePattern='.'yyyy-MM-dd-HH-mm log4j.appender.DAILY.layout=org.apache.log4j.PatternLayout log4j.appender.DAILY.layout.conversionPattern=%d{yyyy-MM-dd HH:mm:ss.SSS} [%p] %c:%L - %m%n So when my application runs it creates a folder called somename_2010-04-09-23-09 . My log file has to be created inside of this somename_2010-04-09-23-09 folder.(Which created at run time..). Is there anyway to do that.. Is there anyway we can specify in the configuration file so that it will create at run time the log file inside of the folder somename_2010-04-09-23-03 folder..? I would really appreciate if some one can answer to my questions. Thanks, Swati

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  • Does pressing Back always cause Activity to finish()?

    - by stormin986
    I've heard that pressing the back button will essentially cause the current Activity to finish(). Is this always the case? Seems like it would be with the way it pops the Activity off the stack. The one situation I'm not so sure about is when the root Activity in a Task has back pressed. I'm currently experiencing a very weird effect, described as follows: On loading my application, the first Activity is for initialization, and once it finishes, it calls my main Activity (a TabActivity). This first init activity has android:noHistory="true" set in the Manifest so pressing Back from my main Activity won't go back to that. It goes to the Launcher. When I click on my App in the Launcher a second time, the initialization activity loads again, and loads the main Activity when done. Almost immediately after, it loads a second instance of my main Activity. But ONLY after the Application has already been run once, and was exited by pressing BACK from the main Activity. It does it every subsequent time until I force quit the app or load a new version from the IDE. Based on this, I am suspecting some kind of Activity instance is lying around and being reused, since it only happens on the second+ time I run the application (and exit with BACK -- using HOME just returns to the last state of the app, no big deal). Anyone have any thoughts??

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  • Network Authentication when running exe from WMI

    - by Andy
    Hi, I have a C# exe that needs to be run using WMI and access a network share. However, when I access the share I get an UnauthorizedAccessException. If I run the exe directly the share is accessible. I am using the same user account in both cases. There are two parts to my application, a GUI client that runs on a local PC and a backend process that runs on a remote PC. When the client needs to connect to the backend it first launches the remote process using WMI (code reproduced below). The remote process does a number of things including accessing a network share using Directory.GetDirectories() and reports back to the client. When the remote process is launched automatically by the client using WMI, it cannot access the network share. However, if I connect to the remote machine using Remote Desktop and manually launch the backend process, access to the network share succeeds. The user specifed in the WMI call and the user logged in for the Remote Desktop session are the same, so the permissions should be the same, shouldn't they? I see in the MSDN entry for Directory.Exists() it states "The Exists method does not perform network authentication. If you query an existing network share without being pre-authenticated, the Exists method will return false." I assume this is related? How can I ensure the user is authenticated correctly in a WMI session? ConnectionOptions opts = new ConnectionOptions(); opts.Username = username; opts.Password = password; ManagementPath path = new ManagementPath(string.Format("\\\\{0}\\root\\cimv2:Win32_Process", remoteHost)); ManagementScope scope = new ManagementScope(path, opts); scope.Connect(); ObjectGetOptions getOpts = new ObjectGetOptions(); using (ManagementClass mngClass = new ManagementClass(scope, path, getOpts)) { ManagementBaseObject inParams = mngClass.GetMethodParameters("Create"); inParams["CommandLine"] = commandLine; ManagementBaseObject outParams = mngClass.InvokeMethod("Create", inParams, null); }

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  • MS Query Analizer/Management Studio replacement?

    - by kprobst
    I've been using SQL Server since version 6.5 and I've always been a bit amazed at the fact that the tools seem to be targeted to DBAs rather than developers. I liked the simplicity and speed of the Query Analizer for example, but hated the built-in editor, which was really no better than a syntax coloring-capable Notepad. Now that we have Management Studio the management part seems a bit better but from a developer standpoint the tools is even worse. Visual Studio's excellent text editor... without a way to customize keyboard bindings!? Don't get me started on how unusable is the tree-based management hierarchy. Why can't I re-root the tree on a list of stored procs for example the way the Enterprise Manager used to allow? Now I have a treeview that needs to be scrolled horizontally, which makes it eminently useless. The SQL server support in Visual Studio is fantastic for working with stored procedures and functions, but it's terrible as a general ad hoc data query tool. I've tried various tools over the years but invariably they seem to focus on the management side and shortchange the developer in me. I just want something with basic admin capabilities, good keyboard support and requisite DDL functionality (ideally something like the Query Analyzer). At this point I'm seriously thinking of using vim+sqlcmd and a console... I'm that desperate :) Those of you who work day in and day out with SQL Server and Visual Studio... do you find the tools to be adequate? Have you ever wished they were better and if you have found something better, could you share please? Thanks!

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  • How do I use the sed command to remove all lines between 2 phrases (including the phrases themselves

    - by fzkl
    I am generating a log from which I want to remove X startup output which looks like this: X.Org X Server 1.7.6 Release Date: 2010-03-17 X Protocol Version 11, Revision 0 Build Operating System: Linux 2.6.31-607-imx51 armv7l Ubuntu Current Operating System: Linux nvidia 2.6.33.2 #1 SMP PREEMPT Mon May 31 21:38:29 PDT 2010 armv7l Kernel command line: mem=448M@0M nvmem=64M@448M mem=512M@512M chipuid=097c81c6425f70d7 vmalloc=320M video=tegrafb console=ttyS0,57600n8 usbcore.old_scheme_first=1 tegraboot=nand root=/dev/nfs ip=:::::usb0:on rw tegra_ehci_probe_delay=5000 smp dvfs tegrapart=recovery:1b80:a00:800,boot:2680:1000:800,environment:3780:40:800,system:38c0:2bc00:800,cache:2f5c0:4000:800,userdata:336c0:c840:800 envsector=3080 Build Date: 23 April 2010 05:19:26PM xorg-server 2:1.7.6-2ubuntu7 (Bryce Harrington <[email protected]>) Current version of pixman: 0.16.4 Before reporting problems, check http://wiki.x.org to make sure that you have the latest version. Markers: (--) probed, (**) from config file, (==) default setting, (++) from command line, (!!) notice, (II) informational, (WW) warning, (EE) error, (NI) not implemented, (??) unknown. (==) Log file: "/var/log/Xorg.0.log", Time: Wed Jun 16 19:52:00 2010 (==) Using config file: "/etc/X11/xorg.conf" (==) Using config directory: "/usr/lib/X11/xorg.conf.d" Is there any way to do this without manually checking pattern for each line?

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  • Eager loading OneToMany in Hibernate with JPA2

    - by pihentagy
    I have a simple @OneToMany between Person and Pet entities: @OneToMany(mappedBy="owner", cascade=CascadeType.ALL, fetch=FetchType.EAGER) public Set<Pet> getPets() { return pets; } I would like to load all Persons with associated Pets. So I came up with this (inside a test class): @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration public class AppTest { @Test @Rollback(false) @Transactional(readOnly = false) public void testApp() { CriteriaBuilder qb = em.getCriteriaBuilder(); CriteriaQuery<Person> c = qb.createQuery(Person.class); Root<Person> p1 = c.from(Person.class); SetJoin<Person, Pet> join = p1.join(Person_.pets); TypedQuery<Person> q = em.createQuery(c); List<Person> persons = q.getResultList(); for (Person p : persons) { System.out.println(p.getName()); for (Pet pet : p.getPets()) { System.out.println("\t" + pet.getNick()); } } However, turning the SQL logging on shows, that it executes 3 queries (having 2 Persons in the DB). Hibernate: select person0_.id as id0_, person0_.name as name0_, person0_.sex as sex0_ from Person person0_ inner join Pet pets1_ on person0_.id=pets1_.owner_id Hibernate: select pets0_.owner_id as owner3_0_1_, pets0_.id as id1_, pets0_.id as id1_0_, pets0_.nick as nick1_0_, pets0_.owner_id as owner3_1_0_ from Pet pets0_ where pets0_.owner_id=? Hibernate: select pets0_.owner_id as owner3_0_1_, pets0_.id as id1_, pets0_.id as id1_0_, pets0_.nick as nick1_0_, pets0_.owner_id as owner3_1_0_ from Pet pets0_ where pets0_.owner_id=? Any tips? Thanks Gergo

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  • .net 4.5 Asp Mvc -> Error 403.14- IIS 7 - Windows Server 2008 R2

    - by Boas Enkler
    When I want to deploy an MVC 4 (.net 4.5) application to my iis i got the 403.14 calling me that the content ist not browseable. This also occurs when i deploy the unchanged mvc 4 template. when using the mvc 4 template with .net 4.0 everything works. I checked the other posts but can't figure out the solution. ist set i ran aspnet_regiss -i which completed without any errors. the only strange thing is that .net 4.5 is installed in the .net 4.0 directory %windows%/microsoft.net/Framework64/4.0.30319 From this folder i also ran aspnet_regiis. to ensure that 4.5 is installed i restarted the .net 4.5 setup and it tells me taht it is installes Also the apppools show me 4.0.30319 as version. There is an other application targeting mvc with 4.5 which runs. but i don't know wether it was created with a 4.0 templated and retargeted to 4.5 Any hints? The app.config is the unchanged default from the mvc 4 template. I just tested to create a subfolder which i convert to an application. placing the site there makes it working. But why not on root folder?

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  • Forward slash problem in xsl and xsql

    - by Peter Kaleta
    Hi I have simple xsql <?xml version="1.0" encoding="utf-8"?> <?xml-stylesheet type="text/xsl" href="zad1.xsl" ?> <page xmlns:xsql="urn:oracle-xsql" connection="java:comp/env/jdbc/mondialDS"> <xsql:query max-rows="-1" null-indicator="no" tag-case="lower" rowset-element="continents"> select name as continent from mondial_user.Continent order by 1 </xsql:query> </page> which gives me a list of continents with "australia/oceania" among them i use XSL on above xsql : <?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <!-- Root template --> <res> <xsl:template match="/continents"> <xsl:for-each select="row"> <re> <xsl:value-of select="continent"/> </re> </xsl:for-each> </xsl:template> </res> </xsl:stylesheet> Firefox throws an error on "wrong formated xml document" with: AfricaAmericaAsiaAustralia/OceaniaEurope -----------------------------------^ Help appreciated.

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  • How to use function to connect to database and how to work with queries?

    - by Abhilash Shukla
    I am using functions to work with database.. Now the way i have defined the functions are as follows:- /** * Database definations */ define ('db_type', 'MYSQL'); define ('db_host', 'localhost'); define ('db_port', '3306'); define ('db_name', 'database'); define ('db_user', 'root'); define ('db_pass', 'password'); define ('db_table_prefix', ''); /** * Database Connect */ function db_connect($host = db_host, $port = db_port, $username = db_user, $password = db_pass, $database = db_name) { if(!$db = @mysql_connect($host.':'.$port, $username, $password)) { return FALSE; } if((strlen($database) > 0) AND (!@mysql_select_db($database, $db))) { return FALSE; } // set the correct charset encoding mysql_query('SET NAMES \'utf8\''); mysql_query('SET CHARACTER_SET \'utf8\''); return $db; } /** * Database Close */ function db_close($identifier) { return mysql_close($identifier); } /** * Database Query */ function db_query($query, $identifier) { return mysql_query($query, $identifier); } Now i want to know whether it is a good way to do this or not..... Also, while database connect i am using $host = db_host Is it ok? Secondly how i can use these functions, these all code is in my FUNCTIONS.php The Database Definitions and also the Database Connect... will it do the needful for me... Using these functions how will i be able to connect to database and using the query function... how will i able to execute a query? VERY IMPORTANT: How can i make mysql to mysqli, is it can be done by just adding an 'i' to mysql....Like:- @mysql_connect @mysqli_connect

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  • Silverlight 3 data-binding child property doesn't update

    - by sonofpirate
    I have a Silverlight control that has my root ViewModel object as it's data source. The ViewModel exposes a list of Cards as well as a SelectedCard property which is bound to a drop-down list at the top of the view. I then have a form of sorts at the bottom that displays the properties of the SelectedCard. My XAML appears as (reduced for simplicity): <StackPanel Orientation="Vertical"> <ComboBox DisplayMemberPath="Name" ItemsSource="{Binding Path=Cards}" SelectedItem="{Binding Path=SelectedCard, Mode=TwoWay}" /> <TextBlock Text="{Binding Path=SelectedCard.Name}" /> <ListBox DisplayMemberPath="Name" ItemsSource="{Binding Path=SelectedCard.PendingTransactions}" /> </StackPanel> I would expect the TextBlock and ListBox to update whenever I select a new item in the ComboBox, but this is not the case. I'm sure it has to do with the fact that the TextBlock and ListBox are actually bound to properties of the SelectedCard so it is listening for property change notifications for the properties on that object. But, I would have thought that data-binding would be smart enough to recognize that the parent object in the binding expression had changed and update the entire binding. It bears noting that the PendingTransactions property (bound to the ListBox) is lazy-loaded. So, the first time I select an item in the ComboBox, I do make the async call and load the list and the UI updates to display the information corresponding to the selected item. However, when I reselect an item, the UI doesn't change! For example, if my original list contains three cards, I select the first card by default. Data-binding does attempt to access the PendingTransactions property on that Card object and updates the ListBox correctly. If I select the second card in the list, the same thing happens and I get the list of PendingTransactions for that card displayed. But, if I select the first card again, nothing changes in my UI! Setting a breakpoint, I am able to confirm that the SelectedCard property is being updated correctly. How can I make this work???

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  • Targeted Simplify in Mathematica

    - by Timo
    I generate very long and complex analytic expressions of the general form: (...something not so complex...)(...ditto...)(...ditto...)...lots... When I try to use Simplify, Mathematica grinds to a halt, I am assuming due to the fact that it tries to expand the brackets and or simplify across different brackets. The brackets, while containing long expressions, are easily simplified by Mathematica on their own. Is there some way I can limit the scope of Simplify to a single bracket at a time? Edit: Some additional info and progress. So using the advice from you guys I have now started using something in the vein of In[1]:= trouble = Log[(x + I y) (x - I y) + Sqrt[(a + I b) (a - I b)]]; In[2]:= Replace[trouble, form_ /; (Head[form] == Times) :> Simplify[form],{3}] Out[2]= Log[Sqrt[a^2 + b^2] + (x - I y) (x + I y)] Changing Times to an appropriate head like Plus or Power makes it possible to target the simplification quite accurately. The problem / question that remains, though, is the following: Simplify will still descend deeper than the level specified to Replace, e.g. In[3]:= Replace[trouble, form_ /; (Head[form] == Plus) :> Simplify[form], {1}] Out[3]= Log[Sqrt[a^2 + b^2] + x^2 + y^2] simplifies the square root as well. My plan was to iteratively use Replace from the bottom up one level at a time, but this clearly will result in vast amount of repeated work by Simplify and ultimately result in the exact same bogging down of Mathematica I experienced in the outset. Is there a way to restrict Simplify to a certain level(s)? I realize that this sort of restriction may not produce optimal results, but the idea here is getting something that is "good enough".

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  • Compile subversion on CentOs

    - by peter
    I have downloaded, compiled and installed so far: apr-1.3.9 apr-util-1.3.9 sqlite-3.6.23 zlib-1.2.4 libtool-2.2.6b Now after downloading subversion-1.6.9, the config works fine but compiling it will end with the following error: cd subversion/svn && /bin/sh /root/subversion-1.6.9/libtool --tag=CC --silent --mode=link gcc -g -O2 -g -O2 -pthread -rpath /usr/local/lib -o svn add-cmd.o blame-cmd.o cat-cmd.o changelist-cmd.o checkout-cmd.o cleanup-cmd.o commit-cmd.o conflict-callbacks.o copy-cmd.o delete-cmd.o diff-cmd.o export-cmd.o help-cmd.o import-cmd.o info-cmd.o list-cmd.o lock-cmd.o log-cmd.o main.o merge-cmd.o mergeinfo-cmd.o mkdir-cmd.o move-cmd.o notify.o propdel-cmd.o propedit-cmd.o propget-cmd.o proplist-cmd.o props.o propset-cmd.o resolve-cmd.o resolved-cmd.o revert-cmd.o status-cmd.o status.o switch-cmd.o tree-conflicts.o unlock-cmd.o update-cmd.o util.o ../../subversion/libsvn_client/libsvn_client-1.la ../../subversion/libsvn_wc/libsvn_wc-1.la ../../subversion/libsvn_ra/libsvn_ra-1.la ../../subversion/libsvn_delta/libsvn_delta-1.la ../../subversion/libsvn_diff/libsvn_diff-1.la ../../subversion/libsvn_subr/libsvn_subr-1.la /usr/local/apr/lib/libaprutil-1.la -lexpat /usr/local/apr/lib/libapr-1.la -lrt -lcrypt -lpthread -ldl /usr/bin/ld: cannot find -lexpat collect2: ld returned 1 exit status make: * [subversion/svn/svn] Error 1 The file at /usr/local/apr/lib/libapr-1.la exists and seems to be OK (from permission perspective What could be the problem here? Thanks Peter

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  • iPhone View Switching basics.

    - by Daniel Granger
    I am just trying to get my head around simple view switching for the iPhone and have created a simple app to try and help me understand it. I have included the code from my root controller used to switch the views. My app has a single toolbar with three buttons on it each linking to one view. Here is my code to do this but I think there most be a more efficient way to achieve this? Is there a way to find out / remove the current displayed view instead of having to do the if statements to see if either has a superclass? I know I could use a tab bar to create a similar effect but I am just using this method to help me practice a few of the techniques. -(IBAction)switchToDataInput:(id)sender{ if (self.dataInputVC.view.superview == nil) { if (dataInputVC == nil) { dataInputVC = [[DataInputViewController alloc] initWithNibName:@"DataInput" bundle:nil]; } if (self.UIElementsVC.view.superview != nil) { [UIElementsVC.view removeFromSuperview]; } else if (self.totalsVC.view.superview != nil) { [totalsVC.view removeFromSuperview]; } [self.view insertSubview:dataInputVC.view atIndex:0]; } } -(IBAction)switchToUIElements:(id)sender{ if (self.UIElementsVC.view.superview == nil) { if (UIElementsVC == nil) { UIElementsVC = [[UIElementsViewController alloc] initWithNibName:@"UIElements" bundle:nil]; } if (self.dataInputVC.view.superview != nil) { [dataInputVC.view removeFromSuperview]; } else if (self.totalsVC.view.superview != nil) { [totalsVC.view removeFromSuperview]; } [self.view insertSubview:UIElementsVC.view atIndex:0]; } } -(IBAction)switchToTotals:(id)sender{ if (self.totalsVC.view.superview == nil) { if (totalsVC == nil) { totalsVC = [[TotalsViewController alloc] initWithNibName:@"Totals" bundle:nil]; } if (self.dataInputVC.view.superview != nil) { [dataInputVC.view removeFromSuperview]; } else if (self.UIElementsVC.view.superview != nil) { [UIElementsVC.view removeFromSuperview]; } [self.view insertSubview:totalsVC.view atIndex:0]; } }

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  • T4MVC and duplicate controller names in different areas

    - by artvolk
    In my application I have controller named Snippets both in default area (in application root) and in my area called Manage. I use T4MVC and custom routes, like this: routes.MapRoute( "Feed", "feed/", MVC.Snippets.Rss() ); And I get this error: Multiple types were found that match the controller named 'snippets'. This can happen if the route that services this request ('{controller}/{action}/{id}/') does not specify namespaces to search for a controller that matches the request. If this is the case, register this route by calling an overload of the 'MapRoute' method that takes a 'namespaces' parameter. The request for 'snippets' has found the following matching controllers: Snippets.Controllers.SnippetsController Snippets.Areas.Manage.Controllers.SnippetsController I know that there are overloads for MapRoute that take namespaces argument, but there are no such overloads with T4MVC support. May be I'm missing something? The possible syntax can be: routes.MapRoute( "Feed", "feed/", MVC.Snippets.Rss(), new string[] {"Snippets.Controllers"} ); or, it seems quite good to me to have namespace as T4MVC property: routes.MapRoute( "Feed", "feed/", MVC.Snippets.Rss(), new string[] {MVC.Snippets.Namespace} ); Thanks in advance!

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  • jqGrid Sort or Search does not work with columns having json dot notation

    - by rsmoorthy
    I have this jqGrid: $("#report").jqGrid( { url: '/py/db?coll=report', datatype: 'json', height: 250, colNames: ['ACN', 'Status', 'Amount'], colModel: [ {name:'acn', sortable:true}, {name:'meta.status', sortable:true}, {name:amount} ], caption: 'Show Report', rownumbers: true, gridview: true, rowNum: 10, rowList: [10,20,30], pager: '#report_pager', viewrecords: true, sortname: 'acn', sortorder: "desc", altRows: true, loadonce: true, mtype: "GET", rowTotal: 1000, jsonReader: { root: "rows", page: "page", total: "total", records: "records", repeatitems: false, id: "acn" } }); Notice that the column 'meta.status' is in JSON dot notation and accordingly the data sent from the server is like this: {"page": "1", "total": "1", "records": "5", "rows": [ {"acn":1,"meta": {"status":"Confirmed"}, "amount": 50}, {"acn":2,"meta": {"status":"Started"}, "amount": 51}, {"acn":3,"meta": {"status":"Stopped"}, "amount": 52}, {"acn":4,"meta": {"status":"Working"}, "amount": 53}, {"acn":5,"meta": {"status":"Started"}, "amount": 54} ] } The problems are of two fold: Sorting does not work on columns with dot notation, here "meta.status". It does not even show the sortable icons on the column header, and nothing happens even if the header is clicked. Sorting does not work, whether loadonce is true or false. If I try Searching (after setting loadonce to true) for the column meta.status (other columns without dot notation is okay), then it throws up a javascript error like this. Any help? Thanks Moorthy

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  • How can i zip files in Java and not include files paths

    - by Ignacio
    For example, i want to zip a file stored in /Users/me/Desktop/image.jpg I maded this method: public static Boolean generateZipFile(ArrayList<String> sourcesFilenames, String destinationDir, String zipFilename){ // Create a buffer for reading the files byte[] buf = new byte[1024]; try { // VER SI HAY QUE CREAR EL ROOT PATH boolean result = (new File(destinationDir)).mkdirs(); String zipFullFilename = destinationDir + "/" + zipFilename ; System.out.println(result); // Create the ZIP file ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFullFilename)); // Compress the files for (String filename: sourcesFilenames) { FileInputStream in = new FileInputStream(filename); // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(filename)); // Transfer bytes from the file to the ZIP file int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } // Complete the entry out.closeEntry(); in.close(); } // Complete the ZIP file out.close(); return true; } catch (IOException e) { return false; } } But when i extract the file, the unzipped files have the full path. I don't want the full path of each file in the zip i only want the filename. How can i made this?

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  • Host Primary Domain from a subfolder

    - by TandemAdam
    I am having a problem making a sub directory act as the public_html for my main domain, and getting a solution that works with that domains sub directories too. My hosting allows me to host multiple sites, which are all working great. I have set up a subfolder under my ~/public_html/ directory called /domains/, where I create a folder for each separate website. e.g. public_html domains websiteone websitetwo websitethree ... This keeps my sites nice and tidy. The only issue was getting my "main domain" to fit into this system. It seems my main domain, is somehow tied to my account (or to Apache, or something), so I can't change the "document root" of this domain. I can define the document roots for any other domains ("Addon Domains") that I add in cPanel no problem. But the main domain is different. I was told to edit the .htaccess file, to redirect the main domain to a subdirectory. This seemed to work great, and my site works fine on it's home/index page. The problem I'm having is that if I try to navigate my browser to say the images folder (just for example) of my main site, like this: www.yourmaindomain.com/images/ then it seems to ignore the redirect and shows the entire server directory in the url, like this: www.yourmaindomain.com/domains/yourmaindomain/images/ It still actually shows the correct "Index of /images" page, and show the list of all my images. Here is an example of my .htaccess file that I am using: RewriteEngine on RewriteCond %{HTTP_HOST} ^(www.)?yourmaindomain.com$ RewriteCond %{REQUEST_URI} !^/domains/yourmaindomain/ RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ /domains/yourmaindomain/$1 RewriteCond %{HTTP_HOST} ^(www.)?yourmaindomain.com$ RewriteRule ^(/)?$ domains/yourmaindomain/index.html [L] Does this htaccess file look correct? I just need to make it so my main domain behaves like an addon domain, and it's subdirectories adhere to the redirect rules.

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