Search Results

Search found 15224 results on 609 pages for 'parallel python'.

Page 419/609 | < Previous Page | 415 416 417 418 419 420 421 422 423 424 425 426  | Next Page >

  • How to include a dynamic page contents into a template ?

    - by Ankit
    Hi All, I have to include a dynamic page content into my template, Say I have a left panel which gets the data dynamically through a view. Now, I have to include this left panel into all my pages but I do not want to duplicate the code for all the pages. Is there any way, I can write a single script and include it in all my templates to display the left panel in all my pages? Thanks in advance.

    Read the article

  • Does Google appengine cache external requests?

    - by Andy Hume
    I have a very simple application running on appengine that requests a web page every five minutes and parses for a specific piece of data. Everything works fine except that the response I get back from the external request (using urllib2) doesn't reflect the latest changes to the page. Sometimes it takes a few minutes to get the latest, sometimes over an hour. Is there a transparent layer of caching that appengine puts in place? Or is there something else I am missing here? I've looked at the caching headers of the requested page and there is no Expires or LastModified's sent. Update: Sometimes, it will get the new version of the page for a number of requests and then randomly later get an old out of date version.

    Read the article

  • Connect to a DB with an encrypted password with Django?

    - by Liam
    My place of employment requires that all passwords must be encrypted, including the ones used to connect to a database. What's the best way of handling this? I'm using the development version of Django with MySQL at the moment, but I will be eventually migrating to Oracle. Is this a job for Django, or the database? Edit: The encrypted password should be stored in the settings.py file, or somewhere else in the filesystem. This is the password that will be used to connect to the database.

    Read the article

  • Django: Get bound IP address inside settings.py

    - by Silver Light
    Hello! I want to enable debug (DEBUG = True) For my Django project only if it runs on localhost. How can I get user IP address inside settings.py? I would like something like this to work: #Debugging only on localhost if user_ip = '127.0.0.1': DEBUG = True else: DEBUG = False How do I put user IP address in user_ip variable inside settings.py file?

    Read the article

  • What kind of data do I pass into a Django Model.save() method?

    - by poswald
    Lets say that we are getting POSTed a form like this in Django: rate=10 items= [23,12,31,52,83,34] The items are primary keys of an Item model. I have a bunch of business logic that will run and create more items based on this data, the results of some db lookups, and some business logic. I want to put that logic into a save signal or an overridden Model.save() method of another model (let's call it Inventory). The business logic will run when I create a new Inventory object using this form data. Inventory will look like this: class Inventory(models.Model): picked_items = models.ManyToManyField(Item, related_name="items_picked_set") calculated_items = models.ManyToManyField(Item, related_name="items_calculated_set") rate = models.DecimalField() ... other fields here ... New calculated_items will be created based on the passed in items which will be stored as picked_items. My question is this: is it better for the save() method on this model to accept: the request object (I don't really like this coupling) the form data as arguments or kwargs (a list of primary keys and the other form fields) a list of Items (The caller form or view will lookup the list of Items and create a list as well as pass in the other form fields) some other approach? I know this is a bit subjective, but I was wondering what the general idea is. I've looked through a lot of code but I'm having a hard time finding a pattern I like.

    Read the article

  • Updating a modul leve shared dictionary

    - by Vishal
    Hi, A module level dictionary 'd' and is accessed by different threads/requests in a django web application. I need to update 'd' every minute with a new data and the process takes about 5 seconds. What could be best solution where I want the users to get either the old value or the new value of d and nothing in between. I can think of a solution where a temp dictionary is constructed with a new data and assigned to 'd' but not sure how this works! Appreciate your ideas. Thanks

    Read the article

  • How would I make this faster? Parsing Word/sorting by heading [on hold]

    - by Doof12
    Currently it takes about 3 minutes to run through a single 53 page word document. Hopefully you all have some advice about speeding up the process. Code: import win32com.client as win32 from glob import glob import io import re from collections import namedtuple from collections import defaultdict import pprint raw_files = glob('*.docx') word = win32.gencache.EnsureDispatch('Word.Application') word.Visible = False oFile = io.open("rawsort.txt", "w+", encoding = "utf-8")#text dump doccat= list() for f in raw_files: word.Documents.Open(f) doc = word.ActiveDocument #whichever document is active at the time doc.ConvertNumbersToText() print doc.Paragraphs.Count for x in xrange(1, doc.Paragraphs.Count+1):#for loop to print through paragraphs oText = doc.Paragraphs(x) if not oText.Range.Tables.Count >0 : results = re.match('(?P<number>(([1-3]*[A-D]*[0-9]*)(.[1-3]*[0-9])+))', oText.Range.Text) stylematch = re.match('Heading \d', oText.Style.NameLocal) if results!= None and oText.Style != None and stylematch != None: doccat.append((oText.Style.NameLocal, oText.Range.Text[:len(results.group('number'))],oText.Range.Text[len(results.group('number')):])) style = oText.Style.NameLocal else: if oText.Range.Font.Bold == True : doccat.append(style, oText) oFile.write(unicode(doccat)) oFile.close() The for Paragraph loop obviously takes the most amount of time. Is there some way of identifying and appending it without going through every Paragraph?

    Read the article

  • Time difference in seconds (as a floating point)

    - by pocoa
    >>> from datetime import datetime >>> t1 = datetime.now() >>> t2 = datetime.now() >>> delta = t2 - t1 >>> delta.seconds 7 >>> delta.microseconds 631000 Is there any way to get that as 7.631000 ? I can use time module, but I also need that t1 and t2 variables as DateTime objects. So if there is a way to do it with datettime, that would be great.

    Read the article

  • Change|Assign parent for the Model instance on Google App Engine Datastore

    - by Vladimir Prudnikov
    Is it possible to change or assign new parent to the Model instance that already in datastore? For example I need something like this task = db.get(db.Key(task_key)) project = db.get(db.Key(project_key)) task.parent = project task.put() but it doesn't works this way because task.parent is built-in method. I was thinking about creating a new Key instance for the task but there is no way to change key as well. Any thoughts?

    Read the article

  • Processing forms that generate many rows in DB

    - by Zack
    I'm wondering what the best approach to take here is. I've got a form that people use to register for a class and a lot of times the manager of a company will register multiple people for the class at the same time. Presently, they'd have to go through the registration process multiple times and resubmit the form once for every person they want to register. What I want to do is give the user a form that has a single <input/> for one person to register with, along with all the other fields they'll need to fill out (Email, phone number, etc); if they want to add more people, they'll be able to press a button and a new <input/> will be generated. This part I know how to do, but I'm including it to best describe what I'm aiming to do. The part I don't know how to approach is processing that data the form submits, I need some way of making a new row in the Registrant table for every <input/> that's added and include the same contact information (phone, email, etc) as the first row with that row. For the record, I'm using the Django framework for my back-end code. What's the best approach here? Should it just POST the form x times for x people, or is there a less "brute force" way of handling this?

    Read the article

  • Doing a count over a filter query efficiently in django

    - by apple_pie
    Hello, Django newbie here, I need to do a count over a certain filter in a django model. If I do it like so: my_model.objects.filter(...).count() I'm guessing it does the SQL query that retrieves all the rows and only afterwards does the count. To my knowledge it's much more efficient to do the count without retrieving those rows like so "SELECT COUNT(*) FROM ...". Is there a way to do so in django?

    Read the article

  • Sql Alchemy Duplicated Commit

    - by PythonWolf
    Good Morning i'm currently facing a problem in my Cherrypy application. Im my own custom session module , anyway when performing session.add() The exact same object gets updated Twice. cherrypy.request.SessionManager.user_data = user try: db_session.add(cherrypy.request.SessionManager) db_session.commit() Will Return 2011-06-21 09:16:48,991 INFO sqlalchemy.engine.base.Engine.0x...04cL BEGIN (implicit) 2011-06-21 09:16:49,015 INFO sqlalchemy.engine.base.Engine.0x...04cL SELECT ..... FROM "Clients_Users" WHERE "Clients_Users".username = %(username_1)s AND "Clients_Users".password = %(password_1)s LIMIT 1 OFFSET 0 2011-06-21 09:16:49,015 INFO sqlalchemy.engine.base.Engine.0x...04cL {'password_1': '123', 'username_1': u'1'} 2011-06-21 09:16:49,047 INFO sqlalchemy.engine.base.Engine.0x...04cL UPDATE "SYS_Sessions" SET user_data=%(user_data)s WHERE "SYS_Sessions".id = %(SYS_Sessions_id)s 2011-06-21 09:16:49,067 INFO sqlalchemy.engine.base.Engine.0x...04cL {'SYS_Sessions_id': 92L, 'user_data': } 2011-06-21 09:16:49,071 INFO sqlalchemy.engine.base.Engine.0x...04cL COMMIT 2011-06-21 09:16:49,093 INFO sqlalchemy.engine.base.Engine.0x...04cL BEGIN (implicit) 2011-06-21 09:16:49,095 INFO sqlalchemy.engine.base.Engine.0x...04cL UPDATE "SYS_Sessions" SET user_data=%(user_data)s WHERE "SYS_Sessions".id = %(SYS_Sessions_id)s 2011-06-21 09:16:49,095 INFO sqlalchemy.engine.base.Engine.0x...04cL {'SYS_Sessions_id': 92L, 'user_data': } 2011-06-21 09:16:49,108 INFO sqlalchemy.engine.base.Engine.0x...04cL COMMIT As Anyone seen this before ? P.S This doesn't happen in the rest of the modules i have made.

    Read the article

  • urllib open - how to control the number of retries

    - by user1641071
    how can i control the number of retries of the "opener.open"? for example, in the following code, it will send about 6 "GET" HTTP requests (i saw it in the Wireshark sniffer) before it goes to the " except urllib.error.URLError" success/no-success lines. password_mgr = urllib.request.HTTPPasswordMgrWithDefaultRealm() password_mgr.add_password(None,url, username, password) handler = urllib.request.HTTPBasicAuthHandler(password_mgr) opener = urllib.request.build_opener(handler) try: resp = opener.open(url,None,1) except urllib.error.URLError as e: print ("no success") else: print ("success!")

    Read the article

  • PHP CURL sending POST to Django app issue

    - by Felipe Pelá
    This code in PHP sends a HTTP POST to a Django app using CURL lib. I need that this code sends POST but redirect to the page in the same submit. Like a simple form does. The PHP Code: $c = curl_init(); curl_setopt($c, CURLOPT_FOLLOWLOCATION, true); curl_setopt($c, CURLOPT_URL, "http://www.xxx.com"); curl_setopt($c, CURLOPT_POST, true); curl_setopt($c, CURLOPT_POSTFIELDS, 'Var='.$var); curl_exec($c); curl_close ($c); In this case, the PHP is sending the HTTP POST, but is not redirecting to the page. He is printing the result. My URL still .php and not a django/url/ I need be redirected to the django URL with the Post like a simple form in HTML does. Any Idea? Thanks.

    Read the article

  • How do I check for Existence of a Record in GAE

    - by VDev
    I am trying to create a simple view in Django & GAE, which will check if the user has a profile entity and prints a different message for each case. I have the program below, but somehow GAE always seem to return a object. My program is below import datetime from django.http import HttpResponse, HttpResponseRedirect from google.appengine.api import users from google.appengine.ext import db from models import Profile import logging #from accounts.views import profile # Create your views here. def login_view(request): user = users.get_current_user() profile = db.GqlQuery("SELECT * FROM Profile WHERE account = :1", users.get_current_user()) logging.info(profile) logging.info(user) if profile: return HttpResponse("Congratulations Your profile is already created.") else: return HttpResponse("Sorry Your profile is NOT created.") My model object is Profile defined as follows: class Profile(db.Model): first_name = db.StringProperty() last_name = db.StringProperty() gender = db.StringProperty(choices=set(["Male", "Female"])) account = db.UserProperty(required = True) friends = db.ListProperty(item_type=users.User) last_login = db.DateTimeProperty(required=True) Thanks for the help.

    Read the article

  • how to download data which upload to gae ,

    - by zjm1126
    this is my code : import os from google.appengine.ext import webapp from google.appengine.ext.webapp import template from google.appengine.ext.webapp.util import run_wsgi_app from google.appengine.ext import db #from login import htmlPrefix,get_current_user class MyModel(db.Model): blob = db.BlobProperty() class BaseRequestHandler(webapp.RequestHandler): def render_template(self, filename, template_args=None): if not template_args: template_args = {} path = os.path.join(os.path.dirname(__file__), 'templates', filename) self.response.out.write(template.render(path, template_args)) class upload(BaseRequestHandler): def get(self): self.render_template('index.html',) def post(self): file=self.request.get('file') obj = MyModel() obj.blob = db.Blob(file.encode('utf8')) obj.put() self.response.out.write('upload ok') class download(BaseRequestHandler): def get(self): #id=self.request.get('id') o = MyModel.all().get() #self.response.out.write(''.join('%s: %s <br/>' % (a, getattr(o, a)) for a in dir(o))) self.response.out.write(o) application = webapp.WSGIApplication( [ ('/?', upload), ('/download',download), ], debug=True ) def main(): run_wsgi_app(application) if __name__ == "__main__": main() my index.html is : <form action="/" method="post"> <input type="file" name="file" /> <input type="submit" /> </form> and it show : <__main__.MyModel object at 0x02506830> but ,i don't want to see this , i want to download it , how to change my code to run, thanks

    Read the article

  • Can Django be used for web services?

    - by alex
    My friend said, "Pylons is so much better for web services." My other friend said, "You can modify Django in a way to do exactly whatever you like." In Django, what is necessary to be modified (urls.py? models classes? settings?) in order to do "web services" with APIs and REST and versioning, etc etc.?

    Read the article

< Previous Page | 415 416 417 418 419 420 421 422 423 424 425 426  | Next Page >