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  • Object for storing strings geted from prints

    - by evg
    class MyWriter: def __init__(self, stdout): self.stdout = stdout self.dumps = [] def write(self, text): self.stdout.write(smart_unicode(text).encode('cp1251')) self.dumps.append(text) def close(self): self.stdout.close() writer = MyWriter(sys.stdout) save = sys.stdout sys.stdout = writer I use self.dumps list to store geted data from prints. Is it exists more convinient object for storing string lines in memory? ideally i want dump it to one big string. I can get it like this "\n".join(self.dumps) from code above. Mb it's better to just concat strings - self.dumps += text ?

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  • Mechanize Submit Form Error: Insufficient items with name '10427'

    - by maneh
    I'm trying to submit a form with Mechanize, I have tried different ways, but the problem persists. Can anyone help me on this. Thank you in advance! This is the form I want to submit: http://www.stpairways.st/ This is the code that I'm using: def stp_airways(url): import re import mechanize br = mechanize.Browser() br.open(url) print br.title() br.select_form(name = "frmbook") br.form['TypeTrajet'] = ["1"] br.form['id_depart'] = ["11967"] br.form['id_arrivee'] = ["10427"] br.form['txtDateAller'] = "5/7/2014" br.form['txtDateRetour'] = "12/7/2014" br.form['TypePassager1u1000r0b1'] = ["1"] br.form['TypePassager2u1000r0b1'] = ["0"] br.form['TypePassager3u1000r0b1'] = ["0"] br.form['CodeIsoDeviseClient'] = ["17,20,23,24,25,26,27,28,29,30,31,33,34,36,37,64,65,67,68,70,73,80,81,95,96,103,147,151,152,159,160,162,169,170TP1TPF"] br.form['CodeIsoDeviseClient'] = ["EUR"] # submit response1 = br.submit() print response1.read()

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  • Building a user subscription application

    - by Tristan O'Neil
    Hello, I'm trying to come up with the best way to handle user subscription and management for our magazine website. What I want to happen is a user purchases a subscription and they are granted online access of a certain membership role for a certain amount of time depending on how many years they subscribed for. I would also like the system to be able to send out emails when a subscription is almost up. I've seen some third party projects to help accomplish this but I'd prefer to write this from scratch as I want total control over how it works. Any suggestions would be helpful. The main thing I can't figure out is how to have an expiring membership. You must keep track of when the user signed up and how long until they should expire.

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  • Actual SQL statement after bind variables specified

    - by bioffe
    I am trying to log every SQL statement executed from my scripts. However I contemplate one problem I can not overcome. Is there a way to compute actual SQL statement after bind variables were specified. In SQLite I had to compute the statement to be executed manually, using code below: def __sql_to_str__(self, value,args): for p in args: if type(p) is IntType or p is None: value = value.replace("?", str(p) ,1) else: value = value.replace("?",'\'' + p + '\'',1) return value It seems CX_Oracle has cursor.parse() facilities. But I can't figure out how to trick CX_Oracle to compute my query before its execution.

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  • ValueError: setting an array element with a sequence.

    - by MedicalMath
    This code: import numpy as p def firstfunction(): UnFilteredDuringExSummaryOfMeansArray = [] MeanOutputHeader=['TestID','ConditionName','FilterType','RRMean','HRMean','dZdtMaxVoltageMean','BZMean','ZXMean' ,'LVETMean','Z0Mean','StrokeVolumeMean','CardiacOutputMean','VelocityIndexMean'] dataMatrix = BeatByBeatMatrixOfMatrices[column] roughTrimmedMatrix = p.array(dataMatrix[1:,1:17]) trimmedMatrix = p.array(roughTrimmedMatrix,dtype=p.float64) myMeans = p.mean(trimmedMatrix,axis=0,dtype=p.float64) conditionMeansArray = [TestID,testCondition,'UnfilteredBefore',myMeans[3], myMeans[4], myMeans[6], myMeans[9] , myMeans[10], myMeans[11], myMeans[12], myMeans[13], myMeans[14], myMeans[15]] UnFilteredDuringExSummaryOfMeansArray.append(conditionMeansArray) secondfunction(UnFilteredDuringExSummaryOfMeansArray) return def secondfunction(UnFilteredDuringExSummaryOfMeansArray): RRDuringArray = p.array(UnFilteredDuringExSummaryOfMeansArray,dtype=p.float64)[1:,3] return firstfunction() Throws this error message: File "mypath\mypythonscript.py", line 3484, in secondfunction RRDuringArray = p.array(UnFilteredDuringExSummaryOfMeansArray,dtype=p.float64)[1:,3] ValueError: setting an array element with a sequence. However, this code works: import numpy as p a=range(24) b = p.reshape(a,(6,4)) c=p.array(b,dtype=p.float64)[:,2] I re-arranged the code a bit to put it into a cogent posting, but it should more or less have the same result. Can anyone show me what to do to fix the problem in the broken code above so that it stops throwing an error message?

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  • How to calculate cointegrations of two lists?

    - by Damiano
    Hello everybody! Thank you in advance for your help! I have two lists with some stocks prices, example: a = [10.23, 11.65, 12.36, 12.96] b = [5.23, 6.10, 8.3, 4.98] I can calculate the correlation of these two lists, with: import scipy.stats scipy.stats.pearsonr(a, b)[0] But, I didn't found a method to calculate the co-integration of two lists. Could you give me some advices? Thank you very much!

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  • list in loop, Nonetype errors

    - by user2926755
    Here is my Code def printList(stringlist): empty = [] if stringlist is None: print empty else: print stringlist def add (stringlist, string): string = [] if string is None else string if stringlist is not None: stringlist.insert(0, string) else: stringlist.append(1) it somehow appears "AttributeError: 'NoneType' object has no attribute 'append'" I was originally looking for the code to be run like this: >>> myList = None >>> printList(myList) [] >>> for word in ['laundry','homework','cooking','cleaning']: myList = add(myList, word) printList(myList) [laundry] [homework, laundry] [cooking, homework, laundry] [cleaning, cooking, homework, laundry]

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  • Django Find Out if User is Authenticated in Custom Tag

    - by greggory.hz
    I'm trying to create a custom tag. Inside this custom tag, I want to be able to have some logic that checks if the user is logged in, and then have the tag rendered accordingly. This is what I have: def user_actions(context): request = template.Variable('request').resolve(context) return { 'auth': request['user'].is_athenticated() } register.inclusion_tag('layout_elements/user_actions.html', takes_context=True)(user_actions) When I run this, I get this error: Caught VariableDoesNotExist while rendering: Failed lookup for key [request] in u'[{}]' The view that renders this ends like this: return render_to_response('start/home.html', {}, context_instance=RequestContext(request)) Why doesn't the tag get a RequestContext object instead of the Context object? How can I get the tag to receive the RequestContext instead of the Context? EDIT: Whether or not it's possible to get a RequestContext inside a custom tag, I'd still be interested to know the "correct" or best way to determine a user's authentication state from within the custom tag. If that's not possible, then perhaps that kind of logic belongs elsewhere? Where?

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  • index error:list out of range

    - by kaushik
    from string import Template from string import Formatter import pickle f=open("C:/begpython/text2.txt",'r') p='C:/begpython/text2.txt' f1=open("C:/begpython/text3.txt",'w') m=[] i=0 k='a' while k is not '': k=f.readline() mi=k.split(' ') m=m+[mi] i=i+1 print m[1] f1.write(str(m[3])) f1.write(str(m[4])) x=[] j=0 while j<i: k=j-1 l=j+1 if j==0 or j==i: j=j+1 else: xj=[] xj=xj+[j] xj=xj+[m[j][2]] xj=xj+[m[k][2]] xj=xj+[m[l][2]] xj=xj+[p] x=x+[xj] j=j+1 f1.write(','.join(x)) f.close() f1.close() It say line 33,xj=xj+m[l][2] has index error,list out of range please help thanks in advance

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  • Find all A^x in a given range

    - by Austin Henley
    I need to find all monomials in the form AX that when evaluated falls within a range from m to n. It is safe to say that the base A is greater than 1, the power X is greater than 2, and only integers need to be used. For example, in the range 50 to 100, the solutions would be: 2^6 3^4 4^3 My first attempt to solve this was to brute force all combinations of A and X that make "sense." However this becomes too slow when used for very large numbers in a big range since these solutions are used in part of much more intensive processing. Here is the code: def monoSearch(min, max): base = 2 power = 3 while 1: while base**power < max: if base**power > min: print "Found " + repr(base) + "^" + repr(power) + " = " + repr(base**power) power = power + 1 base = base + 1 power = 3 if base**power > max: break I could remove one base**power by saving the value in a temporary variable but I don't think that would make a drastic effect. I also wondered if using logarithms would be better or if there was a closed form expression for this. I am open to any optimizations or alternatives to finding the solutions.

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  • nested list comprehension using intermediate result

    - by KentH
    I am trying to grok the output of a function which doesn't have the courtesy of setting a result code. I can tell it failed by the "error:" string which is mixed into the stderr stream, often in the middle of a different conversion status message. I have the following list comprehension which works, but scans for the "error:" string twice. Since it is only rescanning the actual error lines, it works fine, but it annoys me I can't figure out how to use a single scan. Here's the working code: errors = [e[e.find('error:'):] for e in err.splitlines() if 'error:' in e] The obvious (and wrong) way to simplify is to save the "find" result errors = [e[i:] for i in e.find('error:') if i != -1 for e in err.splitlines()] However, I get "UnboundLocalError: local variable 'e' referenced before assignment". Blindly reversing the 'for's in the comprehension also fails. How is this done? THanks. Kent

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  • Preventing a security breach

    - by Wiz
    I am creating a website where you "post", and the form content is saved in a MySql database, and upon loading the page, is retrieved, similar to facebook. I construct all the posts and insert raw html into a template. The thing is, as I was testing, I noticed that I could write javascript or other HTML into the form and submit it, and upon reloading, the html or JS would treated as source code, not a post. I figured that some simple encoding would do the trick, but using is not working. Is there an efficient way to prevent this type of security hole?

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  • Defining the hash of an object as the sum of hashes of its members

    - by Space_C0wb0y
    I have a class that represents undirected edges in a graph. Every edge has two members vertex1 and vertex2 representing the vertices it connects. The problem is, that an edge can be specified two directions. My idea was now to define the hash of an edge as the sum of the hashes of its vertices. This way, the direction plays no role anymore, the hash would be the same. Are there any pitfalls with that?

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  • does webapp has 'elseif' or 'elif' in template tags..

    - by zjm1126
    my code is : Hello!~~~ {% if user %} <p>Logged in as {{ user.first_name }} {{ user.last_name }}.</p> {% elif openid_user%} <p>Hello, {{openid_user.nickname}}! Do you want to <a href="{{openid_logout_url}}">Log out?</p> {% else %} <p><a href="/login?redirect={{ current_url }}">google Log in</a>.</p> <p><a href="/twitter">twitter Log in</a>.</p> <p><a href="/facebook">facebook Log in</a>.</p> <p><a href="{{openid_login_url}}">openid Log in</a>.</p> <iframe src="/_openid/login?continue=/"></iframe> {% endif %} the error is : TemplateSyntaxError: Invalid block tag: 'elif' does not webapp has a 'else if ' ? thanks

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  • Writing a unique identifier to script?

    - by dannycab
    I'd like to write a subscript that adds a unique identifier (machine time) to a script everytime that it runs. However, each time I edit the script (in IDLE) the indetifiers are over-written. Is there a elegant way of doing this. The script that I wrote appears below. import os, time f = open('sys_time_append.py','r') lines = f.readlines() f.close() fout = open('sys_time_append.py','w') for thisline in lines: fout.write(thisline) fout.write('\n#'+str(time.time())+' s r\n') fout.close() Thanks for any help.

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  • Conditional CellRenderCombo in pyGTK TreeView

    - by Präriewolf
    I have a two column TreeView attached to a ListStore. Both columns are CellRenderCombo combo boxes. When the user selects an entry in the first box, I need to dynamically load a set of options in the second. For example, the behavior I want is: On row 0, the user selects "Alphabet" in the first column box. The second column box is populated with the letters "A-Z". On row 1, the user selects "Numbers" in the first column box. The second column box is populated with the numbers "0-9". On row 2, the user selects "Alphabet" in the first column box. The second column box is populated with the letters "A-Z". etc. Does anyone know how to do this, or seen any open source pygtk or gtk projects that have similar behavior which I can analyze?

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  • How to pickle and unpickle objects with self-references and from a class with slots?

    - by EOL
    Is it possible to pickle an object from a class with slots, when this object references itself through one of its attributes? Here is a simple example: import weakref import pickle class my_class(object): __slots__ = ('an_int', 'ref_to_self', '__weakref__') def __init__(self): self.an_int = 42 self.ref_to_self = weakref.WeakKeyDictionary({self: 1}) # __getstate__ and __setstate__ not defined: how should this be done? if __name__ == '__main__': obj = my_class() # How to make the following work? obj_pickled = pickle.dumps(obj) obj_unpickled = pickle.loads(obj_pickled) # Self-references should be kept: print "OK?", obj_unpickled == obj_unpickled.ref_to_self.keys()[0]

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  • problem with list return type??

    - by kaushik
    my list has value such as m=[['na','1','2']['ka','31','45']['ra','3','5'] d=0 r=2 t=m[d][r] print t # this is givin number i.e 2 Now when I use this value u=[] u=m[t] I am getting an err msg saying type error list does take str values... i want to use like this how can i convert that t into a integer?? please suggest.. thanks..

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  • delete common dictionaries in list based on a value

    - by pythoonatic
    How would I delete all corresponding dictionaries in a list of dictionaries based on one of the dictionaries having a character in it. data = [ { 'x' : 'a', 'y' : '1' }, { 'x' : 'a', 'y' : '1/1' }, { 'x' : 'a', 'y' : '2' }, { 'x' : 'b', 'y' : '1' }, { 'x' : 'b', 'y' : '1' }, { 'x' : 'b', 'y' : '1' }, ] For example, how would I delete all of the x = a due to one of the y in the x=a having a / in it? Based on the example data above, here is where I would like to get to: cleaneddata = [ { 'x' : 'b', 'y' : '1' }, { 'x' : 'b', 'y' : '1' }, { 'x' : 'b', 'y' : '1' }, ]

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