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  • How to quickly parse a list of strings

    - by math
    If I want to split a list of words separated by a delimiter character, I can use >>> 'abc,foo,bar'.split(',') ['abc', 'foo', 'bar'] But how to easily and quickly do the same thing if I also want to handle quoted-strings which can contain the delimiter character ? In: 'abc,"a string, with a comma","another, one"' Out: ['abc', 'a string, with a comma', 'another, one'] Related question: How can i parse a comma delimited string into a list (caveat)?

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  • Dynamically customize django admin columns ?

    - by tomjerry
    Is it possible to let the users choose / change dynamically the columns displayed in a object list in Django administration ? Things can surely be implemented "from scratch" by modifying the 'change_list.html' template but I was wondering if somebody has already had the same problem and/or if any django-pluggin can do that. Thanks in advance,

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  • Is it possibile to modify a link value with Beautifulsoup without recreating the all link?

    - by systempuntoout
    Starting from an Html input like this: <p> <a href="http://www.foo.com" rel="nofollow">this is foo</a> <a href="http://www.bar.com" rel="nofollow">this is bar</a> </p> is it possible to modify the <a> node values ("this i foo" and "this is bar") adding the suffix "PARSED" to the value without recreating the all link? The result need to be like this: <p> <a href="http://www.foo.com" rel="nofollow">this is foo_PARSED</a> <a href="http://www.bar.com" rel="nofollow">this is bar_PARSED</a> </p> And code should be something like: from BeautifulSoup import BeautifulSoup soup = BeautifulSoup(html) for link_tag in soup.findAll('a'): link_tag.string = link_tag.string + '_PARSED' #This obviously does not work

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  • related to list and file handling?

    - by kaushik
    i have file with contents in list form such as [1,'ab','fgf','ssd'] [2,'eb','ghf','hhsd'] [3,'ag','rtf','ssfdd'] i want to read that file line by line using f.readline and assign thn to a list so as to use it is the prog as a list for using list properties tried like k=[ ] k=f.readline() print k[1] i xpected a result to show 2nd element in the list in first line but it showed the first bit and gave o/p as '1' how to get the xpected output.. please suggest

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  • How should I use try...except while defining a function?

    - by SpawnCxy
    Hi all, I find I've been confused by the problem that when I needn't to use try..except.For last few days it was used in almost every function I defined which I think maybe a bad practice.For example: class mongodb(object): def getRecords(self,tname,conditions=''): try: col = eval("self.db.%s" %tname) recs = col.find(condition) return recs except Exception,e: #here make some error log with e.message What I thought is ,exceptions may be raised everywhere and I have to use try to get them. And my question is,is it a good practice to use it everywhere when defining functions?If not are there any principles for it?Help would be appreciated! Regards

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  • Get parent function

    - by Morgoth
    Is there a way to find what function called the current function? So for example: def first(): second() def second(): # print out here what function called this one Any ideas?

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  • TypeError: object not callable when making instance

    - by TSM
    I've searched around other threads with similar questions, but I'm not finding the answer. Basically, I have a class: import Android_Class class Android_Revision(object): def __init__(self): # dict for storing the classes in this revision # (format {name : classObject}): self.Classes = {} self.WorkingClass = Android_Class() self.RevisionNumber = '' def __call__(self): print "Called" def make_Class(self, name): newClass = Android_Class(name) self.Classes.update({name : newClass}) self.WorkingClass = newClass def set_Class(self, name): if not(self.Classes.has_key(name)): newClass = Android_Class(name) self.Classes.update({name : newClass}) self.WorkingClass = self.Classes.get(name) I'm trying to make an instance of this class: Revision = Android_Revision() and that's when I'm getting the error. I'm confused because I have another situation where I'm doing almost the exact same thing, and it's working fine. I can't figure out what differences between the two would lead to this error. Thanks.

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  • Debugging (displaying) SQL command sent to the db by SQLAlchemy

    - by morpheous
    I have an ORM class called Person, which wraps around a person table: After setting up the connection to the db etc, I run the ff statement. people = session.query(Person).all() The person table does not contain any data (as yet), so when I print the variable people, I get an empty list. I renamed the table referred to in my ORM class People, to people_foo (which does not exist). I then run the script again. I was surprised that no exception was thrown when attempting to access a table that does not exist. I therefore have the following 2 questions: How may I setup SQLAlchemy so that it propagates db errors back to the script? How may I view (i.e. print) the SQL that is being sent to the db engine If it helps, I am using PostgreSQL as the db

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  • Converting Numpy Lstsq residual value to R^2

    - by whatnick
    I am performing a least squares regression as below (univariate). I would like to express the significance of the result in terms of R^2. Numpy returns a value of unscaled residual, what would be a sensible way of normalizing this. field_clean,back_clean = rid_zeros(backscatter,field_data) num_vals = len(field_clean) x = field_clean[:,row:row+1] y = 10*log10(back_clean) A = hstack([x, ones((num_vals,1))]) soln = lstsq(A, y ) m, c = soln [0] residues = soln [1] print residues

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  • Pickled my dictionary from ZODB but i got a less in size one?

    - by Someone Someoneelse
    I use ZODB and i want to copy my 'database_1.fs' file to another 'database_2.fs', so I opened the root dictionary of that 'database_1.fs' and I (pickle.dump) it in a text file. Then I (pickle.load) it in a dictionary-variable, in the end I update the root dictionary of the other 'database_2.fs' with the dictionary-variable. It works, but I wonder why the size of the 'database_1.fs' not equal to the size of the other 'database_2.fs'. They are still copies of each other. def openstorage(store): #opens the database data={} data['file']=filestorage data['db']=DB(data['file']) data['conn']=data['db'].open() data['root']=data['conn'].root() return data def getroot(dicty): return dicty['root'] def closestorage(dicty): #close the database after Saving transaction.commit() dicty['file'].close() dicty['db'].close() dicty['conn'].close() transaction.get().abort() then that's what i do:- import pickle loc1='G:\\database_1.fs' op1=openstorage(loc1) root1=getroot(op1) loc2='G:database_2.fs' op2=openstorage(loc2) root2=getroot(op2) >>> len(root1) 215 >>> len(root2) 0 pickle.dump( root1, open( "save.txt", "wb" )) item=pickle.load( open( "save.txt", "rb" ) ) #now item is a dictionary root2.update(item) closestorage(op1) closestorage(op2) #after I open both of the databases #I get the same keys in both databases #But `database_2.fs` is smaller that `database_2.fs` in size I mean. >>> len(root2)==len(root1)==215 #they have the same keys True Note: (1) there are persistent dictionaries and lists in the original database_1.fs (2) both of them have the same length and the same indexes.

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  • HTML5 video element non-seekable when using Django development server

    - by Ory Band
    Hey everyone. I've got a Django app serving a webpage with an HTML5 element. There's a wierd "feature", turning the video element to be non-seekable: video.seekable returns a timeRanges object with length=0, whereas it should be length=1. This means I can't edit the video. JavaScript can't do anything either. The thing is, when I upload the problematic webpage, statically - no Django, just plain HTML/JS/CSS - to my website for testing, it works fine - length=1. However, if I try to serve the same static page on my Django dev server still gives the same problem. I am using Django's static serving for dev/debug purposes - Do you have any idea what is causing this, or how can I fix it? Thanks.

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  • recursive cumulative sums

    - by user1816377
    I need to write a program that compute cumulative sums from a list of numbers with def but ONLY with recursion. I did it, but now I need to write the same program without using the method sum, but no success so far. Any idea? my code: def rec_cumsum(numbers): ''' Input: numbers - a list of numbers, Output: a list of cumulative sums of the numbers''' if len(numbers)==0: return numbers return rec_cumsum(numbers[:-1])+ [sum(numbers)] input: 1 [1,2,3] 2 [2, 2, 2, 3] output: 1 [1,3,6] 2 [2, 4, 6, 9]

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  • Is there any way to do this without using '__init__'?

    - by zjm1126
    class a(object): c=b()# how to call the b method d=4 def __init__(self): print self.c def b(self): return self.d+1 a() how to call the 'b' method not in the __init__ thanks the error is : Traceback (most recent call last): File "D:\zjm_code\a.py", line 12, in <module> class a(object): File "D:\zjm_code\a.py", line 13, in a c=b()# how to call the b method NameError: name 'b' is not defined

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  • sending the data from form to db in django

    - by BharatKrishna
    I have a form in which I can input text through text boxes. How do I make these data go into the db on clicking submit. this is the code of the form in the template. <form method="post" action="app/save_page"> <p> Title:<input type="text" name="title"/> </p> <p> Name:<input type="text" name="name"/> </p> <p> Phone:<input type="text" name="phone"/> </p> <p> Email:<input type="text" name="email"/> </p> <p> <textarea name="description" rows=20 cols=60> </textarea><br> </p> <input type="submit" value="Submit"/> </form> I have a function in the views.py for saving the data in the page. But I dont know how to impliment it properly: def save_page(request): title = request.POST["title"] name = request.POST["name"] phone = request.POST["phone"] email = request.POST["email"] description = request.POST["description"] Now how do I send these into the db? And what do I put in views.py so that those data goes into the db? so how do I open a database connection and put those into the db and save it? should I do something like : connection=sqlite3.connect('app.db') cursor= connection.cursor() ..... ..... connection.commit() connection.close() Thank you.

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  • TypeError: init_animals() takes 1 positional arguments but 2 were given

    - by libra
    I know this title look familiar to some old questions, but i've looked at every single one of them, none of them solves. And here is my codes: class Island (object):E,W,R,P def __init__(self, x, y): self.init_animals(y) def init_animals(y): pass isle = Island(x,y) However, i got the following error: Traceback (most recent call last): File "<stdin>", line 1, in <module> File "<stdin>", line 3, in __init__ TypeError: init_animals() takes 1 positional arguments but 2 were given Please tell me if i got any mistakes, im so confused by this. Best regards

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  • [SOLVED]Django - Passing variables to template based on db

    - by George 'Griffin
    I am trying to add a feature to my app that would allow me to enable/disable the "Call Me" button based on whether or not I am at [home|the office]. I created a model in the database called setting, it looks like this: class setting(models.Model): key = models.CharField(max_length=200) value = models.CharField(max_length=200) Pretty simple. There is currently one row, available, the value of it is the string True. I want to be able to transparently pass variables to the templates like this: {% if available %} <!-- Display button --> {% else %} <!-- Display grayed out button --> {% endif %} Now, I could add logic to every view that would check the database, and pass the variable to the template, but I am trying to stay DRY. What is the best way to do this? UPDATE I created a context processor, and added it's path to the TEMPLATE_CONTEXT_PROCESSORS, but it is not being passed to the template def available(request): available = Setting.objects.get(key="available") if open.value == "True": return {"available":True} else: return {} UPDATE TWO If you are using the shortcut render_to_response, you need to pass an instance of RequestContext to the function. from the django documentation: If you're using Django's render_to_response() shortcut to populate a template with the contents of a dictionary, your template will be passed a Context instance by default (not a RequestContext). To use a RequestContext in your template rendering, pass an optional third argument to render_to_response(): a RequestContext instance. Your code might look like this: def some_view(request): # ... return render_to_response('my_template.html', my_data_dictionary, context_instance=RequestContext(request)) Many thanks for all the help!

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  • Common elements comparison between 2 lists.

    - by Daniel
    def common_elements(list1, list2): """ Return a list containing the elements which are in both list1 and list2 >>> common_elements([1,2,3,4,5,6], [3,5,7,9]) [3, 5] >>> common_elements(['this','this','n','that'],['this','not','that','that']) ['this', 'that'] """ for element in list1: if element in list2: return list(element) Got that so far, but can't seem to get it to work! Thanks

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  • I want to select the distict value from models field and then update them (django)

    - by qulzam
    I have models... class Item(models.Model): name = models.CharField('Item Name', max_length = 30) item_code = models.CharField(max_length = 10) color = models.CharField(max_length = 150, null = True, blank = True) size = models.CharField(max_length = 30, null = True, blank = True) fabric_code = models.CharField(max_length = 30, null = True, blank = True) I have values in Item. in Item model name field has the similar values..(but the other values of record are change). I want to select the name field values distinctly(ie similar values select only ones). in one box(like combo box). What kind of form or views i use??

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  • How to check if a file is a textfile?

    - by daniels
    I have a folder full of files and i want to search some string inside them. The issue is that some files may be zip,exe,ogg,etc. Can i check somehow what kind of file is it so i only open and search through txt, php, etc files. I can't rely on the file extension.

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  • Twisted: how-to bind a server to a specified IP address? (solved)

    - by daccle
    I want to have a twisted service (started via twistd) which listens to TCP/POST request on a specified port on a specified IP address. By now I have a twisted application which listens to port 8040 on localhost. It is running fine, but I want it to only listen to a certain IP address, say 10.0.0.78. How-to manage that? This is a snippet of my code: application = service.Application('SMS_Inbound') smsInbound = resource.Resource() smsInbound.putChild('75sms_inbound',ReceiveSMS(application)) smsInboundServer = internet.TCPServer(8001, webserver.Site(smsInbound)) smsInboundServer.setName("SMS Handling") smsInboundServer.setServiceParent(application)

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